{"id":920,"date":"2015-06-29T00:26:37","date_gmt":"2015-06-29T00:26:37","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=920"},"modified":"2024-09-02T17:44:45","modified_gmt":"2024-09-02T17:44:45","slug":"resolucao-comentada-da-uespi-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-da-uespi-2015\/resolucao-comentada-da-uespi-2015\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada da UESPI 2015"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span>Primeiro trecho<\/b><\/span><\/span><\/span> \"\" V<\/b><\/span><\/span><\/span>m1<\/b><\/span><\/span><\/sub><\/span> = \u2206S<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\/\u2206t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> \"\" 100 = \u2206S<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\/2 \"\" <\/b><\/span><\/span><\/span>\u2206S<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 200 km<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Segundo trecho<\/b><\/span><\/span><\/span> \"\" V<\/b><\/span><\/span><\/span>m2<\/b><\/span><\/span><\/sub><\/span> = \u2206S<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\/\u2206t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> \"\" 76 = \u2206S<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\/3 \"\" <\/b><\/span><\/span><\/span>\u2206S<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 228 km<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\u2206S<\/b><\/span><\/span><\/span>total <\/b><\/span><\/span><\/sub><\/span>= 200 + 228 = 428 km.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

02- <\/span><\/span><\/span>Nos <\/b><\/span><\/span><\/span>0,5 s at\u00e9 pisar no freio com V = 90\/3,6 = 25 m\/s, ele percorreu<\/b><\/span><\/span><\/span> \"\" 25 = \u2206S<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\/0,5 \"\" <\/b><\/span><\/span><\/span>\u2206S<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> =<\/b><\/span><\/span><\/span><\/p>\n

12,5 m<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Com os <\/b><\/span><\/span><\/span>freios acionados, sua velocidade varia de V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 25 m\/s at\u00e9 V = 18\/3,6 = 5 m\/s em 5s<\/b><\/span><\/span><\/span> \"\" a = (V \u2013 V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)\/\u2206t = (5 \u2013 25)\/5 \"\" <\/b><\/span><\/span><\/span>a <\/b><\/span><\/span><\/span>= 20\/5 <\/b><\/span><\/span><\/span>= – 4 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\u2206S<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span> = V<\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sub><\/span>t + at<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/2<\/b><\/span><\/span><\/span><\/span> <\/b>= 25.5 \u2013 4.5<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/2 = 125 \u2013 50 \"\" <\/b><\/span><\/span><\/span><\/span>\u2206S<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span> = 75 m.<\/b><\/span><\/span><\/span><\/span><\/p>\n

\u2206S <\/b><\/span><\/span><\/span><\/span>= 12,5 + 75 <\/b><\/span><\/span><\/span><\/span>= 87,5 m<\/b><\/span><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

03- <\/span><\/span><\/span>a = (V \u2013 V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)\/(t \u2013 t<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span> = (12 \u2013 3)\/3 = 9\/3 \"\"<\/b><\/span><\/span><\/span> a = 3 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

F<\/b><\/span><\/span><\/span> = ma =2.3 <\/b><\/span><\/span><\/span>= 6 N<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/p>\n

04- <\/span><\/span><\/span>W = F.d.cos60<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span> = 7.4.0,5 \"\" <\/b><\/span><\/span><\/span>W = 14 J<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

05- <\/span><\/span><\/span>Fun\u00e7\u00e3o hor\u00e1ria da elonga\u00e7\u00e3o x de um MHS.<\/b><\/span><\/span><\/span><\/p>\n

X = A.cos(\u03c6<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> + Wt)<\/b><\/span><\/span><\/span><\/p>\n

Elonga\u00e7\u00e3o (x)<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u2013 posi\u00e7\u00e3o (localiza\u00e7\u00e3o) da part\u00edcula em MHS sobre o eixo x em rela\u00e7\u00e3o \u00e0 origem 0, ou seja, mostra a que dist\u00e2ncia de 0 a part\u00edcula se encontra em determinado instante.<\/b><\/span><\/span><\/span><\/p>\n

Amplitude (A)<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u2013 em m\u00f3dulo \u00e9 a elonga\u00e7\u00e3o m\u00e1xima do MHS e corresponde ao raio da circunfer\u00eancia do MCU (R=A). Fun\u00e7\u00e3o hor\u00e1ria da elonga\u00e7\u00e3o x de um MHS.<\/b><\/span><\/span><\/span><\/p>\n

Per\u00edodo (T)<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u2013 corresponde ao tempo que o MCU demora \u00a0para efetuar uma volta completa ou ao tempo que o MHS demora para efetuar um \u201cvai e vem\u201d completo sobre a reta x.<\/b><\/span><\/span><\/span><\/p>\n

Freq\u00fc\u00eancia (f)<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u2013 n\u00famero de voltas completas (MCU) ou n\u00famero de idas e voltas completas (MHS), na unidade de tempo.<\/b><\/span><\/span><\/span><\/p>\n

\u00c2ngulo de fase (<\/b><\/span><\/span><\/span>\u03c6<\/b><\/span><\/span><\/span>)<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u2013 posi\u00e7\u00e3o (localiza\u00e7\u00e3o) angular no MCU, ou seja, localiza angularmente o corpo em MCU.<\/b><\/span><\/span><\/span><\/p>\n

Fase inicial (<\/b><\/span><\/span><\/span>\u03c6<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u2013 indica, no instante t=0, o \u00e2ngulo de fase inicial do MCU.<\/b><\/span><\/span><\/span><\/p>\n

O \u00e2ngulo de fase (j) e a Fase inicial (j<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>) s\u00e3o medidos em radianos (rad).<\/b><\/span><\/span><\/span><\/p>\n

Compare a equa\u00e7\u00e3o fornecida x = (6,0m)cos(4\u03c0t + 3\u03c0\/2) com <\/b><\/span><\/span><\/span>X = A.cos(\u03c6<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> + Wt) <\/b><\/span><\/span><\/span>e verifique que<\/b><\/span><\/span><\/span><\/b><\/p>\n

A = <\/b><\/span><\/span><\/span>6 m<\/b><\/span><\/span><\/span>; \u03c6<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = <\/b><\/span><\/span><\/span>3\u03c0\/2 rad e <\/b><\/span><\/span><\/span>W =<\/b><\/span><\/span><\/span> 4\u03c0 rad\/s.<\/b><\/span><\/span><\/span><\/p>\n

W = 2<\/b><\/span><\/span><\/span>\u03c0f \"\" 4\u03c0 = 2\u03c0f \"\" <\/b><\/span><\/span><\/span>f = 2 H<\/b><\/span><\/span><\/span>z<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

06- <\/span><\/span><\/span>Observe na express\u00e3o <\/b><\/span><\/span><\/span>\u2206V = V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.\u03b3.\u2206\u03b8<\/b><\/span><\/span><\/span> que a varia\u00e7\u00e3o de volume <\/b><\/span><\/span><\/span>\u2206V<\/b><\/span><\/span><\/span> do s\u00f3lido \u00e9 <\/b><\/span><\/span><\/span>diretamente <\/b><\/span><\/span><\/span>proporcional ao volume inicial V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>, \u00e0 varia\u00e7\u00e3o de temperatura \u2206\u03b8 e ao coeficiente de dilata\u00e7\u00e3o volum\u00e9trica \u03b3.<\/b><\/span><\/span><\/span><\/p>\n

R \u2013 B<\/b><\/span><\/span><\/p>\n

07- <\/span><\/span><\/span>P = i.U<\/b><\/span><\/span><\/span> = 2.14 <\/b><\/span><\/span><\/span>= 28 W.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/p>\n

Voltar para os Exerc\u00edcios<\/span><\/a><\/h2>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01- Primeiro trecho Vm1 = \u2206S1\/\u2206t1 100 = \u2206S1\/2 \u2206S1 = 200 km. Segundo trecho Vm2 = \u2206S2\/\u2206t2 76 = \u2206S2\/3 \u2206S1 = 228 km. \u2206Stotal = 200 + 228 = 428 km. R- C 02- Nos 0,5 s at\u00e9 pisar no freio com V = 90\/3,6 = 25 m\/s, ele percorreu 25 = \u2206S1\/0,5 \u2206S1 = 12,5 m.<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":918,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-920","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/920","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=920"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/920\/revisions"}],"predecessor-version":[{"id":921,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/920\/revisions\/921"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/918"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=920"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}