{"id":902,"date":"2015-06-29T00:04:30","date_gmt":"2015-06-29T00:04:30","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=902"},"modified":"2024-09-02T17:37:27","modified_gmt":"2024-09-02T17:37:27","slug":"resolucao-comentada-da-uece","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-da-uece\/resolucao-comentada-da-uece\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada da UECE"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span>Trata- se de uma <\/b><\/span><\/span><\/span>transforma\u00e7\u00e3o isom\u00e9trica (volume constante<\/b><\/span><\/span><\/span>) e, nela, <\/b><\/span><\/span><\/span>P\/T = constante<\/b><\/span><\/span><\/span> o que significa que a <\/b><\/span><\/span><\/span>press\u00e3o P \u00e9 diretamente proporcional \u00e0 temperatura T.<\/b><\/span><\/span><\/span><\/b><\/p>\n

Se a <\/b><\/span><\/span><\/span>temperatura T aumenta<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span><\/span>energia t\u00e9rmica<\/b><\/span><\/span><\/span> do g\u00e1s pressurizado <\/b><\/span><\/span><\/span>tamb\u00e9m aumenta<\/b><\/span><\/span><\/span> o que implica tamb\u00e9m num <\/b><\/span><\/span><\/span>aumento da press\u00e3o.<\/b><\/span><\/span><\/span><\/b><\/p>\n

R- B<\/b><\/span><\/span><\/p>\n

02- <\/span><\/span><\/span>Irradia\u00e7\u00e3o<\/b><\/span><\/span><\/span> \"\" \u00c9 o fen\u00f4meno pelo qual a <\/b><\/span><\/span><\/span>energia emitida pelo Sol chega at\u00e9 a Terra atrav\u00e9s do v\u00e1cuo.<\/b><\/span><\/span><\/span><\/b><\/p>\n

\"\"<\/p>\n

Realiza-se atrav\u00e9s de <\/b><\/span><\/span><\/span>ondas eletromagn\u00e9ticas<\/b><\/span><\/span><\/span> que s\u00e3o compostas por diversas ondas de freq\u00fc\u00eancias diferentes (raios c\u00f3smicos, raios X, raios ultravioleta, luz vis\u00edvel, raios infravermelhos, etc.) e <\/b><\/span><\/span><\/span>f\u00f3tons<\/b><\/span><\/span><\/span> oriundos da luz solar.<\/b><\/span><\/span><\/span><\/p>\n

R – D<\/b><\/span><\/span><\/p>\n

03- <\/span><\/span><\/span>O <\/b><\/span><\/span><\/span>\u00fanico caso<\/b><\/span><\/span><\/span> em que a <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o seria nula<\/b><\/span><\/span><\/span> ocorreria se essas for\u00e7as tivessem <\/b><\/span><\/span><\/span>m\u00f3dulos iguais,<\/b><\/span><\/span><\/span> mesma dire\u00e7\u00e3o e sentidos contr\u00e1rios, fazendo com que <\/b><\/span><\/span><\/span>\u2206V fosse nula e, consequentemente, a = \u2206V\/\u2206t = 0\/\u2206t = 0.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/p>\n

04- <\/span><\/span><\/span>P = U<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/R<\/b><\/span><\/span><\/span> = 10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/10 \"\" <\/b><\/span><\/span><\/span>P = 10 W<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

P = W\/<\/b><\/span><\/span><\/span>\u2206t \"\" <\/b><\/span><\/span><\/span>10 = W\/10<\/b><\/span><\/span><\/span> \"\" W = 100 J.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

05- <\/span><\/span><\/span>Sendo a mola a mesma, a <\/b><\/span><\/span><\/span>constante el\u00e1stica k<\/b><\/span><\/span><\/span>, tanto na <\/b><\/span><\/span><\/span>compress\u00e3o de x<\/b><\/span><\/span><\/span> quanto na <\/b><\/span><\/span><\/span>distens\u00e3o<\/b><\/span><\/span><\/span><\/b><\/p>\n

\"\"<\/p>\n

tamb\u00e9m de x ser\u00e1 a mesma<\/b><\/span><\/span><\/span>, pois <\/b><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> =kx<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2<\/b><\/span><\/span><\/span>. Como <\/b><\/span><\/span><\/span>k e x s\u00e3o os mesmos E<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> ser\u00e1 a mesma nos dois casos.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/p>\n

06- <\/span><\/span><\/span>Os <\/b><\/span><\/span><\/span>dois g\u00eameos possuem mesma massa<\/b><\/span><\/span><\/span> e, claro, mesmo peso \"\" <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>C <\/b><\/span><\/span><\/sub><\/span>= P<\/b><\/span><\/span><\/span>D<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Colocando o <\/b><\/span><\/span><\/span>p\u00f3lo O<\/b><\/span><\/span><\/span> (eixo de rota\u00e7\u00e3o) no <\/b><\/span><\/span><\/span>ponto central<\/b><\/span><\/span><\/span> da gangorra e estabelecendo o sentido<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

hor\u00e1rio de rota\u00e7\u00e3o em torno de O como positivo<\/b><\/span><\/span><\/span>, no <\/b><\/span><\/span><\/span>equil\u00edbrio de rota\u00e7\u00e3o<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span><\/span>soma dos torques (momentos) de cada for\u00e7a em rela\u00e7\u00e3o ao p\u00f3lo deve ser nula.<\/b><\/span><\/span><\/span><\/p>\n

\u0001<\/span>C<\/b><\/span><\/span><\/sub><\/span> + <\/b><\/span><\/span><\/span>\u0001<\/b><\/span><\/span><\/span>D<\/b><\/span><\/span><\/sub><\/span> = 0<\/b><\/span><\/span><\/span> \"\" + P<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span>.d – P<\/b><\/span><\/span><\/span>D<\/b><\/span><\/span><\/sub><\/span>.d = 0 \"\" P<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span>.d = P<\/b><\/span><\/span><\/span>D<\/b><\/span><\/span><\/sub><\/span>.d \"\" <\/b><\/span><\/span><\/span>\u0001<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span> = <\/b><\/span><\/span><\/span>\u0001<\/b><\/span><\/span><\/span>D<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/p>\n

07- \"\"<\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/p>\n

08- <\/span><\/span><\/span>Momento linear (quantidade de movimento)<\/b><\/span><\/span><\/span> do sistema <\/b><\/span><\/span><\/span>antes <\/b><\/span><\/span><\/span>da colis\u00e3o \"\" <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>sa<\/b><\/span><\/span><\/sub><\/span> = m<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>.V<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span> +<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

m<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span>.V<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span> = mV<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> + m.0 \"\" <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>sa<\/b><\/span><\/span><\/sub><\/span> = mV<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Momento linear (quantidade de movimento)<\/b><\/span><\/span><\/span> do sistema <\/b><\/span><\/span><\/span>depois<\/b><\/span><\/span><\/span> da colis\u00e3o \"\" <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>sd<\/b><\/span><\/span><\/sub><\/span> = m<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>.V<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span> + m<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span>.V<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span> =<\/b><\/span><\/span><\/span><\/p>\n

mV + mV \"\" <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>sd<\/b><\/span><\/span><\/sub><\/span> = 2mV.<\/b><\/span><\/span><\/span><\/p>\n

Q<\/b><\/span><\/span><\/span>sa<\/b><\/span><\/span><\/sub><\/span> = Q<\/b><\/span><\/span><\/span>sd<\/b><\/span><\/span><\/sub><\/span> \"\" mV<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 2mV \"\" <\/b><\/span><\/span><\/span>V = V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/2<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

09- <\/b><\/span><\/span><\/span>Se propagam como <\/b><\/span><\/span><\/span>ondas eletromagn\u00e9ticas<\/b><\/span><\/span><\/span> e, em cada meio, possuem a <\/b><\/span><\/span><\/span>mesma velocidade de propaga\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/p>\n

10- <\/b><\/span><\/span><\/span>Independente do referencial, <\/b><\/span><\/span><\/span>quanto <\/b><\/span><\/span><\/span>mais alto a \u00e1gua estiver<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>mais energia ela deve receber<\/b><\/span><\/span><\/span> para chegar ali.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/p>\n

11- <\/b><\/span><\/span><\/span>Parte da energia t\u00e9rmica<\/b><\/span><\/span><\/span> contida nos gases imediatamente ap\u00f3s a combust\u00e3o \u00e9 <\/b><\/span><\/span><\/span>transferida para<\/b><\/span><\/span><\/span><\/b><\/p>\n

\"\"<\/p>\n

o<\/b><\/span><\/span><\/span> <\/b>ambiente sob forma de calor<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span><\/span>parte transformada em trabalho<\/b><\/span><\/span><\/span> realizado pelo movimento do pist\u00e3o como varia\u00e7\u00e3o de energia cin\u00e9tica.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

12- <\/b><\/span><\/span><\/span>\u03bb = 60 cm \"\" 2\u03bb\/\/2 = 60 \"\"\u03bb = 60cm.<\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- B<\/b><\/span><\/span><\/p>\n

Voltar para os Exerc\u00edcios<\/a>\u00a0<\/span><\/h2>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01- Trata- se de uma transforma\u00e7\u00e3o isom\u00e9trica (volume constante) e, nela, P\/T = constante o que significa que a press\u00e3o P \u00e9 diretamente proporcional \u00e0 temperatura T. Se a temperatura T aumenta, a energia t\u00e9rmica do g\u00e1s pressurizado tamb\u00e9m aumenta o que implica tamb\u00e9m num aumento da press\u00e3o. R- B 02- Irradia\u00e7\u00e3o \u00c9 o fen\u00f4meno pelo qual a energia<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":900,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-902","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/902","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=902"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/902\/revisions"}],"predecessor-version":[{"id":10996,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/902\/revisions\/10996"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/900"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=902"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}