{"id":884,"date":"2015-06-28T23:48:19","date_gmt":"2015-06-28T23:48:19","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=884"},"modified":"2024-09-03T13:02:56","modified_gmt":"2024-09-03T13:02:56","slug":"resolucao-comentada-da-uniceub-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-da-uniceub-2015\/resolucao-comentada-da-uniceub-2015\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada da UniCEUB 2015"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/b><\/span><\/span><\/span><\/p>\n

01-<\/b><\/span><\/span><\/span> Correta \"\" <\/b><\/span><\/span><\/span>Entre 6h e 8h<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span>velocidade<\/b><\/span><\/span><\/span> do ve\u00edculo \u00e9 <\/b><\/span><\/span>constante <\/b><\/span><\/span><\/span>e em qualquer instante (inclusive t = 7h) vale <\/b><\/span><\/span>V =(S \u2013 S<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)\/(t \u2013 t<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span> = (200 \u2013 100)\/(8 \u2013 6) = 100\/2 <\/b><\/span><\/span>= 50 km\/h.<\/b><\/span><\/span><\/span><\/p>\n

02- <\/b><\/span><\/span><\/span>Correta \"\" <\/b><\/span><\/span><\/span>Entre 0 e 10h<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span>V<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span> = (S \u2013 S<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)\/(t \u2013 t<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span> = (200 \u2013 0)\/(10 \u2013 0) = 200\/10 <\/b><\/span><\/span>= 20 km\/h.<\/b><\/span><\/span><\/span><\/p>\n

03-<\/b><\/span><\/span><\/span>Errada<\/b><\/span><\/span><\/span> \"\" observe que a primeira lei afirma que o <\/b><\/span><\/span>Sol deve ocupar <\/b><\/span><\/span><\/span>um <\/b><\/span><\/span><\/span>dos focos da elipse.<\/b><\/span><\/span><\/span><\/p>\n

04- <\/b><\/span><\/span><\/span>04- Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span>observe a figura abaixo:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Pela express\u00e3o acima, <\/b><\/span><\/span><\/span>quando A<\/b><\/span><\/span><\/span>1 <\/b><\/span><\/span><\/sub><\/span>= A<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>,<\/b><\/span><\/span><\/span> \u00a0<\/b><\/span><\/span><\/sub><\/span>\u2206t<\/b><\/span><\/span><\/span>1 <\/b><\/span><\/span><\/sub><\/span>=\u00a0\u2206t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>,<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/sub><\/span>ou seja, <\/b><\/span><\/span><\/span>para o arco maior 34, ser percorrido no<\/b><\/span><\/span><\/span> <\/b>mesmo intervalo<\/b><\/span><\/span><\/span> <\/b>de tempo<\/b><\/span><\/span><\/span> <\/b>que o arco menor12, a velocidade em 3,4<\/b><\/span><\/span><\/span> (mais perto do Sol –\u00a0peri\u00e9lio) <\/b><\/span><\/span><\/span>deve ser maior que a velocidade em 1,2<\/b><\/span><\/span><\/span> (mais afastado do Sol \u2013\u00a0af\u00e9lio).<\/b><\/span><\/span><\/span><\/p>\n

Portanto\u00a0os planetas aceleram do af\u00e9lio para o peri\u00e9lio e retardam do peri\u00e9lio para o af\u00e9lio. Ainda, de acordo com essa lei, se as \u00f3rbitas forem circulares a velocidade de transla\u00e7\u00e3o ser\u00e1 constante.\u00a0<\/b><\/span><\/span><\/span><\/p>\n

05- <\/b><\/span><\/span><\/span>05- Errada<\/b><\/span><\/span><\/span> \"\" foi fornecido que a <\/b><\/span><\/span>distancia media da Terra ao Sol \u00e9 1 unidade astron\u00f4mica (1 U.A.) e que o per\u00edodo de revolu\u00e7\u00e3o da Terra ao redor do Sol corresponde a 1 ano.<\/b><\/span><\/span><\/span><\/p>\n

T<\/b><\/span><\/span>Terra<\/b><\/span><\/span><\/sub> = <\/b><\/span><\/span>T<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span> = 1 ano<\/b><\/span><\/span><\/span> \"\" a<\/b><\/span><\/span>Terra-Sol\u00ad<\/b><\/span><\/span><\/sub> = <\/b><\/span><\/span>a<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span> = 1 U.A.<\/b><\/span><\/span><\/span><\/p>\n

T<\/b><\/span><\/span>planeta<\/b><\/span><\/span><\/sub> = <\/b><\/span><\/span>T<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span> = ?<\/b><\/span><\/span><\/span> \"\" a<\/b><\/span><\/span>planeta-Sol <\/b><\/span><\/span><\/sub>= <\/b><\/span><\/span>a<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span> = 3 U.A.<\/b><\/span><\/span><\/span><\/p>\n

T<\/b><\/span><\/span><\/span><\/span>T<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/a<\/b><\/span><\/span><\/span><\/span>T<\/b><\/span><\/span><\/span><\/sub><\/span>3<\/b><\/span><\/span><\/span><\/sup><\/span> = T<\/b><\/span><\/span><\/span><\/span>p<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/a<\/b><\/span><\/span><\/span><\/span>p<\/b><\/span><\/span><\/span><\/sub><\/span>3<\/b><\/span><\/span><\/span><\/sup><\/span> \"\" 1<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup>\/1<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/span><\/sup> = T<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/span><\/sub>2<\/b><\/span><\/span><\/span><\/sup>\/3<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/span><\/sup> \"\" 1\/1 = T<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/span><\/sub>2<\/b><\/span><\/span><\/span><\/sup>\/27 \"\" <\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/span><\/span>p<\/b><\/span><\/span><\/span><\/sub><\/span> = \u221a(27) \u22485,2 anos.<\/b><\/span><\/span><\/span><\/span><\/p>\n

06- <\/b><\/span><\/span><\/span>Correta<\/b><\/span><\/span><\/span> \"\" cada <\/b><\/span><\/span>varia\u00e7\u00e3o de 5<\/b><\/span><\/span><\/span>o <\/b><\/span><\/span><\/sup><\/span>na escala Celsius corresponde uma varia\u00e7\u00e3o de 9<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span> na escala<\/b><\/span><\/span><\/span> <\/b>Fahrenhei<\/b><\/span><\/span><\/span>t \"\" <\/b><\/span><\/span>\u2206\u03b8 =5<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C \"\" m = 100 kg \"\" c = 3.500 J\/(kg\u00d7<\/b><\/span><\/span><\/span>O<\/b><\/span><\/span><\/sup><\/span>C).<\/b><\/span><\/span><\/span><\/p>\n

Q = W = mc\u2206\u03b8<\/b><\/span><\/span><\/span> = 100.3500.5 = 1 750 000 J <\/b><\/span><\/span>= 1,75×10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span> J.<\/b><\/span><\/span><\/span><\/p>\n

07- <\/b><\/span><\/span><\/span>Errada \"\" <\/b><\/span><\/span><\/span>Quando a <\/b><\/span><\/span>escala T marca 10<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>T a Celsius marca 0<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C<\/b><\/span><\/span><\/span> e quando a <\/b><\/span><\/span>escala T marca 60<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>T a<\/b><\/span><\/span><\/span> <\/b>Celsius marca 50<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C<\/b><\/span><\/span><\/span> \"\" \u00e9 pedido o ponto de <\/b><\/span><\/span>ebuli\u00e7\u00e3o da \u00e1gua<\/b><\/span><\/span><\/span>na <\/b><\/span><\/span>escala T<\/b><\/span><\/span><\/span>, sabendo que <\/b><\/span><\/span>na Celsius ela vale C = 100 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

(100 \u2013 0)\/(50 \u2013 0) = (T \u2013 10)\/(60 \u2013 10)<\/b><\/span><\/span><\/span><\/span> \"\" 100\/50 = (T \u2013 10)\/50 \"\" 100 = T \u2013 10 \"\" <\/b><\/span><\/span><\/span>T = 110 <\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sup><\/span>T<\/b><\/span><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

08- <\/b><\/span><\/span><\/span><\/span>Errada<\/b><\/span><\/span><\/span><\/span> \"\" C\/5 = (F \u2013 32)\/9<\/b><\/span><\/span><\/span><\/span> \"\" 50\/5 = (F \u2013 32)\/9 \"\" 90 = F \u2013 32 \"\" <\/b><\/span><\/span><\/span>F = 112 <\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sup><\/span>F.<\/b><\/span><\/span><\/span><\/span><\/p>\n

09- <\/b><\/span><\/span><\/span>Correta \"\"<\/b><\/span><\/span><\/span> Se <\/b><\/span><\/span>um deles<\/b><\/span><\/span><\/span> se danificar, <\/b><\/span><\/span>todo o circuito el\u00e9trico<\/b><\/span><\/span><\/span> compreendido entre <\/b><\/span><\/span>A e B ficar\u00e1<\/b><\/span><\/span><\/span> <\/b>inutilizado<\/b><\/span><\/span><\/span>, e ent\u00e3o voc\u00ea <\/b><\/span><\/span>pode substituir os tr\u00eas resistores sem prejudicar o funcionamento do equipamento por um \u00fanico resistor (resistor equivalente), calculado conforme o esquema abaixo:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = 150 k\u2126.<\/b><\/span><\/span><\/span><\/p>\n

10- <\/b><\/span><\/span><\/span>Errada<\/b><\/span><\/span><\/span> \"\" Pelo enunciado, uma <\/b><\/span><\/span>corrente el\u00e9trica<\/b><\/span><\/span><\/span> <\/b>superior a 0,3 A, ser\u00e1 fatal para a maioria dos seres humanos e, <\/b><\/span><\/span><\/span>para que isso ocorra a resist\u00eancia el\u00e9trica do corpo deve valer<\/b><\/span><\/span> \"\" R = U\/i <\/b><\/span><\/span><\/span>= 220\/0,3<\/b><\/span><\/span><\/span> = 733,3 \u2126. <\/b><\/span><\/span><\/span>Portanto,<\/b><\/span><\/span> depende da resist\u00eancia el\u00e9trica <\/b><\/span><\/span><\/span>do corpo humano.<\/b><\/span><\/span><\/p>\n

11- <\/b><\/span><\/span><\/span>Errada \"\" R = U\/i \"\" <\/b><\/span><\/span><\/span>100000 = 220\/i<\/b><\/span><\/span> \"\" i <\/b><\/span><\/span><\/span>= 220\/100000<\/b><\/span><\/span><\/span> = 0,0022 A. N\u00e3o ser\u00e1 fatal, pois<\/b><\/span><\/span><\/span><\/p>\n

i < 0,03 A.<\/b><\/span><\/span><\/span><\/p>\n

12- <\/b><\/span><\/span><\/span>Nesse caso, a <\/b><\/span><\/span>pot\u00eancia el\u00e9trica<\/b><\/span><\/span><\/span> que deve ser <\/b><\/span><\/span>fornecida para o paciente \u00e9 igual a 100 kW.<\/b><\/span><\/span><\/span><\/p>\n

Correta<\/b><\/span><\/span><\/span><\/span> \"\" W = 200 J \"\" \u2206t = 0,002s \"\" <\/b><\/span><\/span><\/span>P = W\/\u2206t <\/b><\/span><\/span><\/span><\/span>= 200\/0,002 = 100000 W <\/b><\/span><\/span><\/span>= 100 kW.<\/b><\/span><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os Exerc\u00edcios<\/a><\/span><\/h2>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01- Correta Entre 6h e 8h a velocidade do ve\u00edculo \u00e9 constante e em qualquer instante (inclusive t = 7h) vale V =(S \u2013 So)\/(t \u2013 to) = (200 \u2013 100)\/(8 \u2013 6) = 100\/2 = 50 km\/h. 02- Correta Entre 0 e 10h Vm = (S \u2013 So)\/(t \u2013 to) = (200 \u2013 0)\/(10 \u2013 0) = 200\/10<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":882,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-884","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/884","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=884"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/884\/revisions"}],"predecessor-version":[{"id":887,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/884\/revisions\/887"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/882"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=884"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}