{"id":821,"date":"2015-05-14T17:02:47","date_gmt":"2015-05-14T17:02:47","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=821"},"modified":"2024-09-02T17:40:37","modified_gmt":"2024-09-02T17:40:37","slug":"resolucao-comentada-da-uem-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-da-uem-2015\/resolucao-comentada-da-uem-2015\/","title":{"rendered":"Resolu\u00e7\u00e3o Comentada da UEM 2015"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/b><\/span><\/span><\/span><\/p>\n

01- <\/b><\/span><\/span><\/span>01)<\/b><\/span><\/span><\/span> Press\u00e3o \u00e9 uma grandeza vetorial, portanto tem m\u00f3dulo, dire\u00e7\u00e3o e sentido definidos<\/b><\/span><\/span><\/span><\/p>\n

01. Falsa<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> <\/b>Se a for\u00e7a\u00a0\"\"\u00a0estiver inclinada de um <\/b><\/span><\/span><\/span>\u00e2ngulo \u03b2<\/b><\/span><\/span><\/span> em rela\u00e7\u00e3o \u00e0 horizontal, a parcela dessa <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

for\u00e7a <\/b><\/span><\/span><\/span>que exerce a press\u00e3o \u00e9 a <\/b><\/span><\/span><\/span>componente vertical de\u00a0\"\", ou seja, \u00e9 Fsen\u03b2, conforme a figura acima.<\/b><\/span><\/span><\/span><\/p>\n

A press\u00e3o sempre vai estar relacionada ao <\/b><\/span><\/span><\/span>m\u00f3dulo da for\u00e7a que age perpendicularmente<\/b><\/span><\/span><\/span> <\/b>\u00e0 superf\u00edcie<\/b><\/span><\/span><\/span>. Ent\u00e3o <\/b><\/span><\/span><\/span>n\u00e3o importa a dire\u00e7\u00e3o<\/b><\/span><\/span><\/span> que a for\u00e7a \u00e9 aplicada, ela <\/b><\/span><\/span><\/span>n\u00e3o muda a dire\u00e7\u00e3o da press\u00e3o<\/b><\/span><\/span><\/span>, que \u00e9 sempre <\/b><\/span><\/span><\/span>perpendicular a superf\u00edcie<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>
\n<\/b><\/span><\/span><\/span>S\u00f3 <\/b><\/span><\/span><\/span>o que leva em conta na press\u00e3o, portanto, \u00e9 a <\/b><\/span><\/span><\/span>intensidade.<\/b><\/span><\/span><\/span><\/p>\n

02)<\/b><\/span><\/span><\/span> A diferen\u00e7a de press\u00e3o entre dois pontos no interior de um l\u00edquido homog\u00eaneo e em equil\u00edbrio \u00e9<\/b><\/span><\/span><\/span><\/p>\n

proporcional \u00e0 diferen\u00e7a de profundidade entre esses dois pontos.<\/b><\/span><\/span><\/span><\/p>\n

02. Correta \"\" <\/b><\/span><\/span><\/span>Teorema de Stevin<\/b><\/span><\/span><\/span> \"\" Observe a figura abaixo onde, quem varia \u00e9 <\/b><\/span><\/span><\/span>apenas a press\u00e3o<\/b><\/span><\/span><\/span> <\/b>vertical<\/b><\/span><\/span><\/span>, onde o l\u00edquido que \u00e9 homog\u00eaneo e incompress\u00edvel est\u00e1 em equil\u00edbrio.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Na superf\u00edcie livre superior (A) desse l\u00edquido age a press\u00e3o atmosf\u00e9rica (P<\/b><\/span><\/span><\/span>atm<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span>,\u00a0<\/b><\/span><\/span><\/sub><\/span>exercida pela coluna de ar que est\u00e1 sobre ele. Num ponto qualquer <\/b><\/span><\/span><\/span>B do interior do l\u00edquido<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span><\/span>press\u00e3o (P<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span> que age \u00e9 a <\/b><\/span><\/span><\/span>soma da press\u00e3o atmosf\u00e9rica com a press\u00e3o exercida pela coluna l\u00edquida acima dele, devido \u00e0 seu peso.<\/b><\/span><\/span><\/span><\/p>\n

P<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>=P<\/b><\/span><\/span><\/span>atm<\/b><\/span><\/span><\/sub><\/span>\u00a0+ P<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 P<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>=P<\/b><\/span><\/span><\/span>atm\u00a0<\/b><\/span><\/span><\/sub><\/span>+ F\/S\u00a0 —\u00a0 P<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>= P<\/b><\/span><\/span><\/span>atm\u00a0<\/b><\/span><\/span><\/sub><\/span>+ peso do l\u00edquido\/S\u00a0 —\u00a0 P<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>=P<\/b><\/span><\/span><\/span>atm<\/b><\/span><\/span><\/sub><\/span>\u00a0+ (m<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>.g)\/S\u00a0 —\u00a0 d<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>=m<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>\/V<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 d<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>=m<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>\/S.h<\/b><\/span><\/span><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00a0\u00a0—\u00a0 m<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>=d<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>.S.h\u00a0 — \u00a0P<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>=P<\/b><\/span><\/span><\/span>atm<\/b><\/span><\/span><\/sub><\/span>\u00a0+ (d<\/b><\/span><\/span><\/span>l\u00edquido<\/b><\/span><\/span><\/sub><\/span>.S.h)\/S\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>=P<\/b><\/span><\/span><\/span>atm<\/b><\/span><\/span><\/sub><\/span>+ d<\/b><\/span><\/span><\/span>l\u00edquido.<\/b><\/span><\/span><\/sub><\/span>g.h\u00a0 —<\/b><\/span><\/span><\/span>\u00a0 esta express\u00e3o \u00e9 chamada de Teorema Fundamental da Hidrost\u00e1tica ou de Teorema de Stevin<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

04)<\/b><\/span><\/span><\/span> No sistema internacional de medidas (SI) a unidade de press\u00e3o \u00e9 o Pascal (Pa).<\/b><\/span><\/span><\/span><\/p>\n

04. Correta \"\" <\/b><\/span><\/span><\/span>Pa = N\/m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

08)<\/b><\/span><\/span><\/span> Quando um dado ponto de um l\u00edquido em equil\u00edbrio no interior de um recipiente sofre uma varia\u00e7\u00e3o de press\u00e3o, essa varia\u00e7\u00e3o de press\u00e3o \u00e9 transmitida a todos os pontos do l\u00edquido e das paredes do recipiente.<\/b><\/span><\/span><\/span><\/p>\n

08. Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>Considere um <\/b><\/span><\/span><\/span>fluido<\/b><\/span><\/span><\/span> (l\u00edquidos e gases que fluem para as regi\u00f5es inferiores de um recipiente at\u00e9 preench\u00ea-los totalmente) em <\/b><\/span><\/span><\/span>equil\u00edbrio (vertical e horizontal)<\/b><\/span><\/span><\/span> no interior de um recipiente.<\/b><\/span><\/span><\/span><\/p>\n

Esse l\u00edquido exerce sobre as paredes do recipiente que o contem for\u00e7as que se tornam de maior intensidade \u00e0 medida que a profundidade aumenta.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Observe que as <\/b><\/span><\/span><\/span>for\u00e7as, na mesma horizontal, em ambos os extremos, tem a mesma intensidade, pois o l\u00edquido est\u00e1 em equil\u00edbrio horizontal, caso contr\u00e1rio, ele se moveria nessa dire\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

16)<\/b><\/span><\/span><\/span> Estando um l\u00edquido em um recipiente aberto, a press\u00e3o na superf\u00edcie do l\u00edquido \u00e9 nula.<\/b><\/span><\/span><\/span><\/p>\n

16. Falsa<\/b><\/span><\/span><\/span> \"\" veja 02.<\/b><\/span><\/span><\/span><\/p>\n

R- (02 + 04 + 08) = 14<\/b><\/span><\/span><\/span><\/p>\n

02- <\/b><\/span><\/span><\/span>Toda a teoria que envolve as f\u00f3rmulas fornecidas encontram-se em fisicaevestibular.com.br \u2013 Mec\u00e2nica \u2013 Din\u00e2mica \u2013 MHS \u2013 Sistema massa-mola.<\/b><\/span><\/span><\/span><\/p>\n

01)<\/b><\/span><\/span><\/span> A amplitude m\u00e1xima de oscila\u00e7\u00e3o do sistema massa-mola \u00e9 de 20 cm.<\/b><\/span><\/span><\/span><\/p>\n

01. Falsa<\/b><\/span><\/span><\/span> \"\" a <\/b><\/span><\/span><\/span>amplitude A<\/b><\/span><\/span><\/span> \u00e9 fornecida pelo enunciado \"\" Quando o <\/b><\/span><\/span><\/span>sistema <\/b><\/span><\/span><\/span>\u00e9 trazido para a <\/b><\/span><\/span><\/span>posi\u00e7\u00e3o +10 cm em rela\u00e7\u00e3o \u00e0 posi\u00e7\u00e3o de equil\u00edbrio \"\" A = 10 cm.<\/b><\/span><\/span><\/span><\/p>\n

02)<\/b><\/span><\/span><\/span> A velocidade angular de oscila\u00e7\u00e3o do sistema massa-mola \u00e9 de 20 rad\/s.<\/b><\/span><\/span><\/span><\/p>\n

02. Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>W = \u221a(k\/m<\/b><\/span><\/span><\/span> = \u221a(80\/0,2) = \u221a400 \"\" <\/b><\/span><\/span><\/span>W = 20 rad\/s.<\/b><\/span><\/span><\/span><\/p>\n

04)<\/b><\/span><\/span><\/span> O per\u00edodo de oscila\u00e7\u00e3o do sistema massa-mola \u00e9 de \u03c0\/10 s.<\/b><\/span><\/span><\/span><\/p>\n

04. Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>T=2\u03c0\u221a(m\/k)<\/b><\/span><\/span><\/span> = 2\u03c0\u221a(0,2\/80) = 2\u03c0\u221a(0,2\/80) = 2\u03c0\u221a(0,0025) \"\" <\/b><\/span><\/span><\/span>T <\/b><\/span><\/span><\/span>= 2\u03c0(0,05) = \u03c0.0,01 = <\/b><\/span><\/span><\/span>\u03c0\/10 s.<\/b><\/span><\/span><\/span><\/p>\n

08)<\/b><\/span><\/span><\/span> A acelera\u00e7\u00e3o do bloco quando ele passa sobre o ponto x = -0,2 cm \u00e9 de 2 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

08. Falsa \"\" a= -k\/m.x<\/b><\/span><\/span><\/span> = – 80\/0,2.(-0,02) \"\" <\/b><\/span><\/span><\/span>a = 8 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

16)<\/b><\/span><\/span><\/span> A frequ\u00eancia de oscila\u00e7\u00e3o do sistema massa-mola \u00e9 de aproximadamente 6,28 Hz.<\/b><\/span><\/span><\/span><\/p>\n

16. Falsa \"\" f = 1\/T = <\/b><\/span><\/span><\/span>1\/(\u03c0\/10)<\/b><\/span><\/span><\/span> \"\" f <\/b><\/span><\/span><\/span>=<\/b><\/span><\/span><\/span> <\/b>10\/\u03c0 = 10\/3,14<\/b><\/span><\/span><\/span> = 3,184 Hz.<\/b><\/span><\/span><\/span><\/p>\n

R- (02 + 04) = 06<\/b><\/span><\/span><\/span><\/p>\n

03- <\/b><\/span><\/span><\/span>01)<\/b><\/span><\/span><\/span> A varia\u00e7\u00e3o da energia interna de um sistema f\u00edsico \u00e9 dada pela diferen\u00e7a entre o calor trocado com o meio externo ao sistema e o trabalho realizado no processo termodin\u00e2mico.<\/b><\/span><\/span><\/span><\/p>\n

01. Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>O <\/b><\/span><\/span><\/span>Primeiro Princ\u00edpio da Termodin\u00e2mica<\/b><\/span><\/span><\/span> (Princ\u00edpio da Conserva\u00e7\u00e3o da Energia) afirma que: \u201cA energia n\u00e3o pode ser criada nem destru\u00edda, mas apenas transformada\u201d<\/b><\/span><\/span><\/span><\/p>\n

Suponha que um sistema isolado receba 300J de calor. Se, por exemplo, 50J dessa energia forem absorvidos pelo sistema, ent\u00e3o a parte restante, 250J, ser\u00e1 fornecida ao ambiente sob a forma de trabalho.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Ent\u00e3o, Q= W + \u0394U ou,<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

A express\u00e3o acima \u00e9 a representa\u00e7\u00e3o matem\u00e1tica do primeiro princ\u00edpio da termodin\u00e2mica.<\/b><\/span><\/span><\/span><\/p>\n

02)<\/b><\/span><\/span><\/span> A energia interna de uma dada quantidade de g\u00e1s perfeito \u00e9 fun\u00e7\u00e3o exclusiva da temperatura desse g\u00e1s.<\/b><\/span><\/span><\/span><\/p>\n

02. Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>Energia interna de um g\u00e1s perfeito<\/b><\/span><\/span><\/span><\/p>\n

A energia interna (U) de um g\u00e1s perfeito monoat\u00f4mico corresponde a soma das energias cin\u00e9ticas m\u00e9dias (E<\/b><\/span><\/span><\/span>c<\/b><\/span><\/span><\/sub><\/span>) de todas as suas mol\u00e9culas e, pela lei de Joule \u00e9 fornecida por:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

\u00a0A afirma\u00e7\u00e3o acima indica que a temperatura de um g\u00e1s \u00e9 a medida da energia cin\u00e9tica m\u00e9dia de suas mol\u00e9culas.<\/b><\/span><\/span><\/span><\/p>\n

04)<\/b><\/span><\/span><\/span> As transforma\u00e7\u00f5es termodin\u00e2micas naturais sempre levam \u00e0 conserva\u00e7\u00e3o da quantidade de movimento e da entropia do Universo.<\/b><\/span><\/span><\/span><\/p>\n

04. Falsa<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

08<\/b><\/span><\/span><\/span>) Dois corpos, em equil\u00edbrio t\u00e9rmico, possuem a mesma temperatura e, nessa condi\u00e7\u00e3o, n\u00e3o h\u00e1 troca de calor entre eles.<\/b><\/span><\/span><\/span><\/p>\n

08. Correta \"\" <\/b><\/span><\/span><\/span>s\u00f3 existe troca de calor entre dois corpos quando eles estiverem <\/b><\/span><\/span><\/span>\u00e0 temperaturas diferentes e essa transfer\u00eancia ocorre sempre do corpo de maior para o de menor temperatura.<\/b><\/span><\/span><\/span><\/p>\n

16)<\/b><\/span><\/span><\/span> Se dois ou mais corpos trocam calor entre si at\u00e9 atingirem o equil\u00edbrio termodin\u00e2mico, a soma<\/b><\/span><\/span><\/span><\/p>\n

alg\u00e9brica das quantidades de calor trocada \u00e9 sempre positiva e ser\u00e1 tanto maior quanto maior a<\/b><\/span><\/span><\/span><\/p>\n

temperatura inicial desses corpos.<\/b><\/span><\/span><\/span><\/p>\n

16. Falsa<\/b><\/span><\/span><\/span> \"\" a quantidade de calor <\/b><\/span><\/span><\/span>\u00e9 negativa para o corpo que cede calor<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span><\/span>positiva para o que recebe calor.<\/b><\/span><\/span><\/span><\/p>\n

R- (01 + 02 + 08) = 11<\/b><\/span><\/span><\/span><\/p>\n

04- <\/b><\/span><\/span><\/span>01)<\/b><\/span><\/span><\/span> Condutores el\u00e9tricos paralelos percorridos por correntes el\u00e9tricas que fluem no mesmo sentido<\/b><\/span><\/span><\/span><\/p>\n

repelem-se.<\/b><\/span><\/span><\/span><\/p>\n

01. Falsa<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>For\u00e7a de intera\u00e7\u00e3o entre dois fios condutores paralelos<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0Considere dois <\/b><\/span><\/span><\/span>condutores retil\u00edneos 1 e 2<\/b><\/span><\/span><\/span> percorridos, respectivamente por correntes el\u00e9tricas i<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0e i<\/b><\/span><\/span><\/span>2,\u00a0<\/b><\/span><\/span><\/sub><\/span>e separados por uma dist\u00e2ncia \u00a0d. Tem-se duas situa\u00e7\u00f5es:<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0<\/span>As correntes el\u00e9tricas tem mesmo sentido<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Utilizando a regra da m\u00e3o direita, voc\u00ea determina\u00a0\"\"\u00a0que \u00e9 o vetor indu\u00e7\u00e3o magn\u00e9tica que o condutor 1 produz onde est\u00e1 o condutor 2.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

O condutor 2, imerso no campo magn\u00e9tico de\u00a0\"\"\u00a0ficar\u00e1 sujeito a uma for\u00e7a magn\u00e9tica\u00a0\"\", fornecida pela regra da m\u00e3o esquerda.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Assim, o condutor 2 fica sujeito a uma for\u00e7a magn\u00e9tica\u00a0\"\"\u00a0vertical e para cima.<\/b><\/span><\/span><\/span><\/p>\n

Analogamente, o condutor 2 origina, onde est\u00e1 o condutor 1, um campo magn\u00e9tico\u00a0\"\"<\/b><\/span><\/span><\/span>,\u00a0<\/b><\/span><\/span><\/sub><\/span>que, fornecido pela regra da m\u00e3o direita estar\u00e1 saindo da folha de papel. <\/b><\/span><\/span><\/span>Ent\u00e3o surgir\u00e1 sobre o condutor 1 uma for\u00e7a vertical e para baixo, fornecida pela regra da m\u00e3o esquerda.<\/b><\/span><\/span><\/span><\/p>\n

Situa\u00e7\u00e3o final:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Dois fios condutores retil\u00edneos, paralelos e pr\u00f3ximos um do outro, sofrem for\u00e7as de atra\u00e7\u00e3o se as correntes que os percorrem tiverem mesmo sentido.<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0Se as correntes el\u00e9tricas tiverem <\/b><\/span><\/span><\/span>sentidos contr\u00e1rios<\/b><\/span><\/span><\/span>, procedendo da mesma forma que no item anterior, voc\u00ea observar\u00e1 que os dois fios sofrem for\u00e7a de repuls\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Dois fios condutores retil\u00edneos, paralelos e pr\u00f3ximos um do outro, sofrem for\u00e7as de repuls\u00e3o se as correntes que os percorrem tiverem sentidos contr\u00e1rios.<\/b><\/span><\/span><\/span><\/p>\n

02)<\/b><\/span><\/span><\/span> A for\u00e7a eletromotriz induzida em uma espira condutora \u00e9 diretamente proporcional \u00e0 varia\u00e7\u00e3o<\/b><\/span><\/span><\/span><\/p>\n

temporal do fluxo magn\u00e9tico que atravessa essa espira.<\/b><\/span><\/span><\/span><\/p>\n

02. Correta \"\" <\/b><\/span><\/span><\/span>\u201c O m\u00f3dulo da for\u00e7a eletromotriz induzida num circuito \u00e9 igual \u00e0 raz\u00e3o entre a varia\u00e7\u00e3o do fluxo magn\u00e9tico nesse circuito, pelo intervalo de tempo em que essa varia\u00e7\u00e3o ocorre\u201d<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Eventualmente, devido \u00e0 lei de Lenz, que afirma que a for\u00e7a eletromotriz induzida se op\u00f5e \u00e0 varia\u00e7\u00e3o de fluxo, costuma-se escrever a lei de Lenz da seguinte forma:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

04)<\/b><\/span><\/span><\/span> A for\u00e7a eletromotriz induzida em uma espira condutora \u00e9 inversamente proporcional ao intervalo<\/b><\/span><\/span><\/span><\/p>\n

de tempo em que ocorre a varia\u00e7\u00e3o do fluxo magn\u00e9tico que atravessa a espira.<\/b><\/span><\/span><\/span><\/p>\n

04. Correta<\/b><\/span><\/span><\/span> \"\" observe na express\u00e3o <\/b><\/span><\/span><\/span>\u03b5 = \u2206\u0424\/\u2206t<\/b><\/span><\/span><\/span> que <\/b><\/span><\/span><\/span>\u03b5 \u00e9 inversamente proporcional a \u2206t.<\/b><\/span><\/span><\/span><\/p>\n

08)<\/b><\/span><\/span><\/span> A corrente el\u00e9trica induzida em um circuito el\u00e9trico produz um campo magn\u00e9tico que permite o aumento do fluxo magn\u00e9tico que a induz.<\/b><\/span><\/span><\/span><\/p>\n

08. Falsa<\/b><\/span><\/span><\/span> \"\" Poe produzir tamb\u00e9m uma <\/b><\/span><\/span><\/span>diminui\u00e7\u00e3o do fluxo magn\u00e9tico.<\/b><\/span><\/span><\/span><\/p>\n

16)<\/b><\/span><\/span><\/span> A varia\u00e7\u00e3o temporal do campo magn\u00e9tico em uma determinada regi\u00e3o do espa\u00e7o provoca o<\/b><\/span><\/span><\/span><\/p>\n

aparecimento de um campo el\u00e9trico vari\u00e1vel nessa mesma regi\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

16. Correta <\/b><\/span><\/span><\/span><\/p>\n

R- (02 + 04 + 16) = 22<\/b><\/span><\/span><\/span><\/p>\n

05- <\/b><\/span><\/span><\/span>01)<\/b><\/span><\/span><\/span> No gr\u00e1fico da intensidade da for\u00e7a em fun\u00e7\u00e3o do tempo, a \u00e1rea sob a curva \u00e9 numericamente igual ao impulso da for\u00e7a.<\/b><\/span><\/span><\/span><\/p>\n

01. Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>Em todo gr\u00e1fico <\/b><\/span><\/span><\/span>for\u00e7a X tempo<\/b><\/span><\/span><\/span>, a intensidade do <\/b><\/span><\/span><\/span>impulso<\/b><\/span><\/span><\/span> \u00e9 fornecida pela \u00e1rea <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

compreendida entre a reta representativa e o eixo do tempo, no intervalo pedido.<\/b><\/span><\/span><\/span><\/p>\n

02)<\/b><\/span><\/span><\/span> A varia\u00e7\u00e3o do momento linear de um ponto material \u00e9 igual ao impulso da for\u00e7a resultante que atua sobre ele<\/b><\/span><\/span><\/span><\/p>\n

02. Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>Teorema do Impulso<\/b><\/span><\/span><\/span> <\/b>“O <\/b><\/span><\/span><\/span>impulso da for\u00e7a resultante<\/b><\/span><\/span><\/span> de um <\/b><\/span><\/span><\/span>sistema de for\u00e7as<\/b><\/span><\/span><\/span> que age <\/b><\/span><\/span><\/span><\/p>\n

\"\"\"\"\"\"\"\"<\/p>\n

sobre um corpo <\/b><\/span><\/span><\/span>\u00e9 igual \u00e0 varia\u00e7\u00e3o da quantidade de movimento do corpo”<\/b><\/span><\/span><\/span><\/p>\n

04)<\/b><\/span><\/span><\/span> Em um sistema isolado, no qual a resultante das for\u00e7as que atuam sobre esse sistema \u00e9 nula, o<\/b><\/span><\/span><\/span><\/p>\n

momento linear permanece constante.<\/b><\/span><\/span><\/span><\/p>\n

04. Correta<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>Quando um sistema \u00e9 <\/b><\/span><\/span><\/span>isolado de for\u00e7as externas<\/b><\/span><\/span><\/span>, sua <\/b><\/span><\/span><\/span>for\u00e7a resultante<\/b><\/span><\/span><\/span> tem intensidade <\/b><\/span><\/span><\/span>nula <\/b><\/span><\/span><\/span>e consequentemente o <\/b><\/span><\/span><\/span>impulso dessa for\u00e7a \u00e9 nulo<\/b><\/span><\/span><\/span>, pois I=F<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span>.\u2206t=0.\u00a0\u2206t=0. Como I = Q<\/b><\/span><\/span><\/span>depois<\/b><\/span><\/span><\/sub><\/span>\u00a0\u2013 Q<\/b><\/span><\/span><\/span>antes<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 0= Q<\/b><\/span><\/span><\/span>depois<\/b><\/span><\/span><\/sub><\/span>\u00a0\u2013 Q<\/b><\/span><\/span><\/span>antes<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 Q<\/b><\/span><\/span><\/span>antes<\/b><\/span><\/span><\/sub><\/span>\u00a0= Q<\/b><\/span><\/span><\/span>depois<\/b><\/span><\/span><\/sub><\/span>. Sendo a quantidade de movimento grandeza vetorial, a rela\u00e7\u00e3o abaixo representa o\u00a0<\/b><\/span><\/span><\/span>princ\u00edpio da conserva\u00e7\u00e3o da quantidade de movimento (momento linear)<\/b><\/span><\/span><\/span>:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

08)<\/b><\/span><\/span><\/span> Quando dois autom\u00f3veis colidem e se deslocam juntos ap\u00f3s a colis\u00e3o, temos uma colis\u00e3o<\/b><\/span><\/span><\/span><\/p>\n

perfeitamente el\u00e1stica na qual o momento linear total diminui.<\/b><\/span><\/span><\/span><\/p>\n

08. Falsa<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>Independente do tipo de choque<\/b><\/span><\/span><\/span>, a quantidade de movimento <\/b><\/span><\/span><\/span>(momento linear)<\/b><\/span><\/span><\/span> sempre <\/b><\/span><\/span><\/span>se conserva em m\u00f3dulo, dire\u00e7\u00e3o e sentido.<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span><\/p>\n

16)<\/b><\/span><\/span><\/span> Em qualquer tipo de colis\u00e3o, o momento linear \u00e9 conservado, mantendo-se constantes seu m\u00f3dulo, sua dire\u00e7\u00e3o e seu sentido.<\/b><\/span><\/span><\/span><\/p>\n

16. Correta<\/b><\/span><\/span><\/span> \"\" veja 08.<\/b><\/span><\/span><\/span><\/p>\n

R- (01 + 02 + 04 + 16) = 23<\/b><\/span><\/span><\/span><\/p>\n

06- <\/b><\/span><\/span><\/span>01)<\/b><\/span><\/span><\/span> Os resistores equivalentes nos dois ramos do circuito possuem, respectivamente, resist\u00eancia el\u00e9trica de 30 \u2126 e de 5 \u2126.<\/b><\/span><\/span><\/span><\/p>\n

01. Correta<\/b><\/span><\/span><\/span> \"\" <\/span><\/span>ramo A \"\" s\u00e9rie \"\" R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = 10 + 10 + 10 = 30 \u2126 \"\" ramo B \"\" paralelo \"\" R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = 10.10\/(10 + 10) = 100\/20 \"\" R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = 5 \u2126.<\/b><\/span><\/span><\/span><\/p>\n

02)<\/b><\/span><\/span><\/span> A corrente el\u00e9trica que flui no ramo <\/b><\/span><\/span><\/span>A <\/b><\/i><\/span><\/span><\/span>\u00e9 de 2 A.<\/b><\/span><\/span><\/span><\/p>\n

02. Falsa \"\" R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = U\/i \"\" <\/b><\/span><\/span><\/span>30\/7 = 10\/i <\/b><\/span><\/span><\/span> \"\" i = 2,33 A \"\" i<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> <\/b>= 10\/30<\/b><\/span><\/span><\/span> = 0,33 A \"\" i<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> <\/b>= 10\/5<\/b><\/span><\/span><\/span> = 2 A.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Veja acima que<\/b><\/span><\/span><\/span> i<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = 0,33 A.<\/b><\/span><\/span><\/span><\/p>\n

04)<\/b><\/span><\/span><\/span> A pot\u00eancia dissipada no ramo <\/b><\/span><\/span><\/span>B <\/b><\/i><\/span><\/span><\/span>\u00e9 de 20 W.<\/b><\/span><\/span><\/span><\/p>\n

04. Correta \"\" P = R.i<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span> <\/b>= 5.2<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 20 W.<\/b><\/span><\/span><\/span><\/p>\n

08)<\/b><\/span><\/span><\/span> A pot\u00eancia dissipada e a corrente el\u00e9trica no ramo <\/b><\/span><\/span><\/span>B <\/b><\/i><\/span><\/span><\/span>s\u00e3o maiores que as observadas no ramo <\/b><\/span><\/span><\/span>A<\/b><\/i><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

08. Correta<\/b><\/span><\/span><\/span> \"\" de 04, <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = 20W<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = R.i<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 30.0,33 <\/b><\/span><\/span><\/span>= 9,9 W.<\/b><\/span><\/span><\/span><\/p>\n

16)<\/b><\/span><\/span><\/span> A diferen\u00e7a de potencial entre os terminais do segundo resistor do ramo <\/b><\/span><\/span><\/span>A <\/b><\/i><\/span><\/span><\/span>\u00e9 de aproximadamente 3,3<\/b><\/span><\/span><\/span> V<\/span><\/p>\n

16. Correta \"\" R = U\/i<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> \"\" <\/b><\/span><\/span><\/span>10 = U\/0,33<\/b><\/span><\/span><\/span> \"\" U = 3,3 V.<\/b><\/span><\/span><\/span><\/p>\n

R- (01 + 04 + 08 + 16) = 29<\/b><\/span><\/span><\/span><\/p>\n

07- <\/b><\/span><\/span><\/span>01)<\/b><\/span><\/span><\/span> A velocidade com que o bloco percorre a superf\u00edcie delgada, plana e horizontal \u00e9 A \u221a(2gh<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>) , sendo g a acelera\u00e7\u00e3o da gravidade.<\/b><\/span><\/span><\/span><\/p>\n

01. Correta<\/b><\/span><\/span><\/span> \"\" c\u00e1lculo da <\/b><\/span><\/span><\/span>velocidade com que o bloco chega \u00e0 base C<\/b><\/span><\/span><\/span> pela conserva\u00e7\u00e3o da energia mec\u00e2nica j\u00e1 que n\u00e3o existe atrito e o sistema \u00e9 conservativo.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

E<\/b><\/span><\/span><\/span>mA<\/b><\/span><\/span><\/sub><\/span> = MV<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + Mgh<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = M.0<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + Mgh <\/b><\/span><\/span><\/span>= Mgh.<\/b><\/span><\/span><\/span><\/p>\n

E<\/b><\/span><\/span><\/span>mC<\/b><\/span><\/span><\/sub><\/span> = MV<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + Mgh<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span> = M.V<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + Mg.0 <\/b><\/span><\/span><\/span>= MV<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2.<\/b><\/span><\/span><\/span><\/p>\n

E<\/b><\/span><\/span><\/span>mA<\/b><\/span><\/span><\/sub><\/span> = E<\/b><\/span><\/span><\/span>mC<\/b><\/span><\/span><\/sub><\/span> \"\" Mgh<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = MV<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 \"\" <\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span> =\u221a(2gh<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>). <\/b><\/span><\/span><\/span>Essa \u00e9 a <\/b><\/span><\/span><\/span>velocidade <\/b><\/span><\/span><\/span>com que ele chega \u00e0 <\/b><\/span><\/span><\/span>base do plano<\/b><\/span><\/span><\/span> i<\/b><\/span><\/span><\/span>nclinado<\/b><\/span><\/span><\/span> e, como <\/b><\/span><\/span><\/span>n\u00e3o existe atrito, \u00e9 a mesma com que ele percorre o plano horizontal.<\/b><\/span><\/span><\/span><\/p>\n

02)<\/b><\/span><\/span><\/span> O trabalho realizado pela for\u00e7a peso sobre o bloco, durante seu movimento na superf\u00edcie do plano inclinado <\/b><\/span><\/span><\/span>A<\/b><\/i><\/span><\/span><\/span>, \u00e9 A mgh .<\/b><\/span><\/span><\/span><\/p>\n

02. Correta \"\" W<\/b><\/span><\/span><\/span>peso<\/b><\/span><\/span><\/sub><\/span> = P.d.cos90<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span> <\/b>= P.d.0<\/b><\/span><\/span><\/span> = 0<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

04)<\/b><\/span><\/span><\/span> O trabalho realizado pela for\u00e7a peso sobre o bloco, durante seu movimento na superf\u00edcie do plano inclinado <\/b><\/span><\/span><\/span>B<\/b><\/i><\/span><\/span><\/span>, \u00e9 B mgh<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

04. Falsa \"\" E<\/b><\/span><\/span><\/span>mC<\/b><\/span><\/span><\/sub><\/span> = MVc<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + Mgh<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/sub><\/span> <\/b>= M.(\u221a(2gh<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + M.g.0<\/b><\/span><\/span><\/span> = Mgh<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

E<\/b><\/span><\/span><\/span>mB<\/b><\/span><\/span><\/sub><\/span> = MV<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + Mgh<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = <\/b><\/span><\/span><\/span>M.0<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + Mgh<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = Mgh<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

W<\/b><\/span><\/span><\/span>CB<\/b><\/span><\/span><\/sub><\/span> = E<\/b><\/span><\/span><\/span>mB<\/b><\/span><\/span><\/sub><\/span> \u2013 E<\/b><\/span><\/span><\/span>mC<\/b><\/span><\/span><\/sub><\/span> = <\/b><\/span><\/span><\/span>Mgh<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> \u2013 Mgh<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = Mg(h<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> \u2013 h<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span><\/p>\n

08)<\/b><\/span><\/span><\/span> A quantidade de movimento do bloco \u00e9 conservada somente quando o bloco se movimenta na superf\u00edcie horizontal, onde a somat\u00f3ria de for\u00e7as sobre o mesmo \u00e9 nula.<\/b><\/span><\/span><\/span><\/p>\n

08. Correta \"\" Q = M.V<\/b><\/span><\/span><\/span> e, como <\/b><\/span><\/span><\/span>M e V nesse trecho s\u00e3o os mesmos<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span><\/span>quantidade de movimento Q tamb\u00e9m \u00e9 a mesma.<\/b><\/span><\/span><\/span><\/p>\n

16)<\/b><\/span><\/span><\/span> O trabalho l\u00edquido realizado pela somat\u00f3ria de for\u00e7as que agem sobre o bloco durante seu deslocamento sobre o plano inclinado <\/b><\/span><\/span><\/span>B <\/b><\/i><\/span><\/span><\/span>\u00e9 \u2013d<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>.(F<\/b><\/span><\/span><\/span>atB<\/b><\/span><\/span><\/sub><\/span> + Mgsen\u03b8), sendo \u03b8 o \u00e2ngulo de inclina\u00e7\u00e3o do plano inclinado <\/b><\/span><\/span><\/span>B<\/b><\/i><\/span><\/span><\/span>, g a acelera\u00e7\u00e3o da gravidade e F<\/b><\/span><\/span><\/span>atB<\/b><\/span><\/span><\/sub><\/span> a for\u00e7a de atrito entre a superf\u00edcie do bloco e a<\/b><\/span><\/span><\/span><\/p>\n

superf\u00edcie do plano inclinado <\/b><\/span><\/span><\/span>B<\/b><\/i><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

16. Correta <\/b><\/span><\/span><\/span><\/p>\n

R- (01 + 02 + 08 + 16) = 27<\/b><\/span><\/span><\/span><\/p>\n

08- <\/b><\/span><\/span><\/span>01)<\/b><\/span><\/span><\/span> No instante t = 3 s, a velocidade do m\u00f3vel <\/b><\/span><\/span><\/span>B <\/b><\/i><\/span><\/span><\/span>\u00e9 nula.<\/b><\/span><\/span><\/span><\/p>\n

01. Correta \"\" equa\u00e7\u00e3o da velocidade do m\u00f3vel B<\/b><\/span><\/span><\/span> \"\" V<\/b><\/span><\/span><\/span>oB<\/b><\/span><\/span><\/sub><\/span> = 12 m\/s e a<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = – 4 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> \"\" <\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> <\/b>= V<\/b><\/span><\/span><\/span>oB<\/b><\/span><\/span><\/sub><\/span> + a<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>t <\/b><\/span><\/span><\/span>= 12<\/b><\/span><\/span><\/span> <\/b>\u2013 4t<\/b><\/span><\/span><\/span> \"\" quando <\/b><\/span><\/span><\/span>t = 3 s<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = 12 \u2013 4.3 = 12 \u2013 12 <\/b><\/span><\/span><\/span>= 0.<\/b><\/span><\/span><\/span><\/p>\n

02)<\/b><\/span><\/span><\/span> No instante t = 4 s, os dois m\u00f3veis se encontram<\/b><\/span><\/span><\/span><\/p>\n

02. Correta \"\" <\/b><\/span><\/span><\/span>no encontro X<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = X<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> \"\" <\/b><\/span><\/span><\/span>25 \u2013 3t + 3t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 45 + 12t \u2013 2t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> \"\" <\/b><\/span><\/span><\/span>5t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> – 15t \u2013 20 = 0<\/b><\/span><\/span><\/span> \"\" \u2206 = 225 \u2013 4.5.(-20) \"\" \u2206 = 625 \"\" \u221a\u2206 = 25 \"\" t = 15 \u00b1 25\/10 \"\" <\/b><\/span><\/span><\/span>t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 40\/10 = 4s<\/b><\/span><\/span><\/span> e t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> < 0.<\/b><\/span><\/span><\/span><\/p>\n

04)<\/b><\/span><\/span><\/span> A dist\u00e2ncia percorrida pelo m\u00f3vel <\/b><\/span><\/span><\/span>B<\/b><\/i><\/span><\/span><\/span>, do instante t = 0 s at\u00e9 quando ele se encontra com o m\u00f3vel <\/b><\/span><\/span><\/span>A<\/b><\/i><\/span><\/span><\/span>, \u00e9 de 25 m<\/b><\/span><\/span><\/span><\/p>\n

04. Falsa \"\" <\/b><\/span><\/span><\/span>substituindo <\/b><\/span><\/span><\/span>t = 4s<\/b><\/span><\/span><\/span> em <\/b><\/span><\/span><\/span>X<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> <\/b>= 45 + 12.3 + 2.16 = 113 m \"\" <\/b><\/span><\/span><\/span>\u2206X<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = 113 \u2013 45 = <\/b><\/span><\/span><\/span>68 m<\/b><\/span><\/span><\/span><\/p>\n

08)<\/b><\/span><\/span><\/span> Entre os instantes t = 0 s at\u00e9 quando o m\u00f3vel <\/b><\/span><\/span><\/span>B <\/b><\/i><\/span><\/span><\/span>se encontra com o m\u00f3vel <\/b><\/span><\/span><\/span>A<\/b><\/i><\/span><\/span><\/span>, a velocidade m\u00e9dia desse m\u00f3vel \u00e9 de 4 m\/s.<\/b><\/span><\/span><\/span><\/p>\n

08. Correta <\/b><\/span><\/span><\/span><\/p>\n

16)<\/b><\/span><\/span><\/span> A fun\u00e7\u00e3o hor\u00e1ria da velocidade relativa entre os m\u00f3veis <\/b><\/span><\/span><\/span>A <\/b><\/i><\/span><\/span><\/span>e <\/b><\/span><\/span><\/span>B <\/b><\/i><\/span><\/span><\/span>\u00e9 dada por V<\/b><\/span><\/span><\/span>AB<\/b><\/span><\/span><\/sub><\/span> (t) = – 15 + 10t , em que V<\/b><\/span><\/span><\/span>AB<\/b><\/span><\/span><\/sub><\/span> = V<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> – V<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>, sendo V<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> e V<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> as velocidades dos<\/b><\/span><\/span><\/span> <\/b>m\u00f3veis <\/b><\/span><\/span><\/span>A <\/b><\/i><\/span><\/span><\/span>e <\/b><\/span><\/span><\/span>B<\/b><\/i><\/span><\/span><\/span>, respectivamente<\/b><\/span><\/span><\/span>.<\/span><\/p>\n

16. Correta \"\" V<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = – 3 + 6t \"\" V<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = 12 + 4t \"\" <\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>AB<\/b><\/span><\/span><\/sub><\/span> = V<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> \u2013 V<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = -3 + 6t \u2013 12 + <\/b><\/span><\/span><\/span>4t = -15 + 10t.<\/b><\/span><\/span><\/span><\/p>\n

R- (01 + 02 + 08 + 16) = 27<\/b><\/span><\/span><\/span><\/p>\n

<\/h2>\n

Voltar para os exerc\u00edcios.<\/span><\/a><\/h2>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01- 01) Press\u00e3o \u00e9 uma grandeza vetorial, portanto tem m\u00f3dulo, dire\u00e7\u00e3o e sentido definidos 01. Falsa Se a for\u00e7a\u00a0\u00a0estiver inclinada de um \u00e2ngulo \u03b2 em rela\u00e7\u00e3o \u00e0 horizontal, a parcela dessa for\u00e7a que exerce a press\u00e3o \u00e9 a componente vertical de\u00a0, ou seja, \u00e9 Fsen\u03b2, conforme a figura acima. A press\u00e3o sempre vai estar relacionada ao m\u00f3dulo da for\u00e7a<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":819,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-821","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/821","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=821"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/821\/revisions"}],"predecessor-version":[{"id":822,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/821\/revisions\/822"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/819"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=821"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}