{"id":757,"date":"2015-05-13T14:52:39","date_gmt":"2015-05-13T14:52:39","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=757"},"modified":"2024-09-02T17:23:15","modified_gmt":"2024-09-02T17:23:15","slug":"resolucao-comentada-da-iff-rs","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-da-iff-rs-2015\/resolucao-comentada-da-iff-rs\/","title":{"rendered":"Resolu\u00e7\u00e3o Comentada da IFF-RS 2015"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/b><\/span><\/span><\/span><\/p>\n

01- <\/b><\/span><\/span><\/span>I. Correta<\/b><\/span><\/span> \"\" <\/b><\/span>\u00a0<\/span><\/span><\/span>ABS<\/b><\/span><\/span><\/span> (Anti-lock Braking System) \u00e9 um <\/b><\/span><\/span>sistema de frenagem<\/b><\/span><\/span><\/span> que evita que a <\/b><\/span><\/span>roda bloqueie<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span>entre em derrapagem<\/b><\/span><\/span><\/span> quando o pedal do freio \u00e9 pisado fortemente, evitando que a roda n\u00e3o trave,e o carro comece a <\/b><\/span><\/span>derrapar.<\/b><\/span><\/span><\/span><\/p>\n

Isso ocorre porque <\/b><\/span><\/span>atrito entre o pneu e o pavimento \u00e9 o atrito est\u00e1tico que \u00e9 <\/b><\/span><\/span><\/span>maior<\/b><\/span><\/span><\/span> que o cin\u00e9tico.<\/b><\/span><\/span><\/span><\/p>\n

II. Falsa<\/b><\/span><\/span><\/span> \"\" veja I.<\/b><\/span><\/span><\/p>\n

III. Falsa<\/b><\/span><\/span><\/span> \"\" V<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sup> = V<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sub>2<\/b><\/span><\/span><\/sup> \u2013 2.a.d \"\" 0<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sup> = 30<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sup> \u2013 2.a.60 \"\" a = 900\/120 \"\" a = 7,7 m\/s<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sup>.<\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

F<\/b><\/span><\/span>R<\/b><\/span><\/span><\/sub> = ma e F<\/b><\/span><\/span>R<\/b><\/span><\/span><\/sub> = F<\/b><\/span><\/span>at \"\" <\/b><\/span><\/span><\/sub>ma = \u03bcmg \"\" 7,7 = \u03bc.10 \"\" <\/b><\/span><\/span>\u03bc = 0,77.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

02- <\/b><\/span><\/span><\/span>A <\/b><\/span><\/span>massa de ar no interior do bal\u00e3o \u00e9 a mesma<\/b><\/span><\/span><\/span> e, consequentemente seu peso, vertical e para baixo <\/b><\/span><\/span>tamb\u00e9m \u00e9 o mesmo<\/b><\/span><\/span><\/span>. Quem varia \u00e9 a for\u00e7a do <\/b><\/span><\/span>empuxo <\/b><\/span><\/span><\/span>(vertical e para cima) devido \u00e0 <\/b><\/span><\/span>varia\u00e7\u00e3o <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

de volume do g\u00e1s ao ser aquecido (V aumenta) ou resfriado (V diminui). <\/b><\/span><\/span><\/span><\/p>\n

R – A<\/b><\/span><\/span><\/span><\/p>\n

03- <\/b><\/span><\/span><\/span>Q = mc(\u03b8 \u2013 \u03b8<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span> \"\" 960.10<\/b><\/span><\/span>3<\/b><\/span><\/span><\/sup> = m.1.(37 \u2013 5) \"\" m = 960.10<\/b><\/span><\/span>3<\/b><\/span><\/span><\/sup>\/32 \"\" <\/b><\/span><\/span>m = 30.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span> g = 30 kg.<\/b><\/span><\/span><\/span><\/p>\n

d<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span> = 1 g\/cm<\/b><\/span><\/span>3<\/b><\/span><\/span><\/sup> = 10<\/b><\/span><\/span>3<\/b><\/span><\/span><\/sup>kg\/m<\/b><\/span><\/span>3<\/b><\/span><\/span><\/sup> = 1 kg\/dm<\/b><\/span><\/span>3<\/b><\/span><\/span><\/sup> \"\" <\/b><\/span><\/span>d<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span> = 1kg\/L.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

04- <\/b><\/span><\/span><\/span>Quando voc\u00ea <\/b><\/span><\/span>diminui <\/b><\/span><\/span><\/span>o comprimento do filamento interno met\u00e1lico do chuveiro, voc\u00ea est\u00e1 <\/b><\/span><\/span>diminuindo o valor da resist\u00eancia interna do chuveiro<\/b><\/span><\/span><\/span> e, consequentemente <\/b><\/span><\/span>aumentando sua<\/b><\/span><\/span><\/span> <\/b>pot\u00eancia el\u00e9trica<\/b><\/span><\/span><\/span>, pois P = U<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sup>\/R e, como U \u00e9 a mesma R \u00e9 inversamente proporcional \u00e0 P.<\/b><\/span><\/span><\/p>\n

R- C <\/b><\/span><\/span><\/span><\/p>\n

05- <\/b><\/span><\/span><\/span>As tr\u00eas est\u00e3o corretas.<\/b><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

<\/h2>\n

Voltar para exerc\u00edcios.<\/span><\/a><\/h2>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01- I. Correta \u00a0ABS (Anti-lock Braking System) \u00e9 um sistema de frenagem que evita que a roda bloqueie e entre em derrapagem quando o pedal do freio \u00e9 pisado fortemente, evitando que a roda n\u00e3o trave,e o carro comece a derrapar. Isso ocorre porque atrito entre o pneu e o pavimento \u00e9 o atrito est\u00e1tico que \u00e9 maior que<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":755,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-757","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/757","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=757"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/757\/revisions"}],"predecessor-version":[{"id":760,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/757\/revisions\/760"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/755"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=757"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}