{"id":752,"date":"2015-05-12T20:44:14","date_gmt":"2015-05-12T20:44:14","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=752"},"modified":"2024-09-02T17:16:07","modified_gmt":"2024-09-02T17:16:07","slug":"resolucao-comentada-acafe-medicina-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-acafe-medicina-2015\/resolucao-comentada-acafe-medicina-2015\/","title":{"rendered":"Resolu\u00e7\u00e3o Comentada ACAFE – medicina 2015"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/b><\/span><\/span><\/span><\/p>\n

01- <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

02- <\/b><\/span><\/span><\/span>I. Correta<\/b><\/span><\/span><\/span> \"\" todos os pontos do tubo \u201cvarrem\u201d o <\/b><\/span><\/span><\/span>mesmo \u00e2ngulo no mesmo intervalo de tempo<\/b><\/span><\/span><\/span>, portanto possuem a mesma velocidade angular.<\/b><\/span><\/span><\/span><\/p>\n

II. Falsa<\/b><\/span><\/span><\/span> \"\" veja I<\/b><\/span><\/span><\/span><\/p>\n

III. Correta<\/b><\/span><\/span><\/span> \"\" quanto <\/b><\/span><\/span><\/span>mais densa<\/b><\/span><\/span><\/span>, mais pesada, <\/b><\/span><\/span><\/span>mais afastada<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

IV. Falsa<\/b><\/span><\/span><\/span> \"\" veja III.<\/b><\/span><\/span><\/span><\/p>\n

V. Correta<\/b><\/span><\/span><\/span> \"\" se a <\/b><\/span><\/span><\/span>velocidade \u00e9 alta<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span><\/span>freq\u00fc\u00eancia<\/b><\/span><\/span><\/span> (n\u00famero de voltas por segundo) <\/b><\/span><\/span><\/span>\u00e9 maior que o<\/b><\/span><\/span><\/span> <\/b>per\u00edodo<\/b><\/span><\/span><\/span> (tempo que demora para efetuar uma volta completa).<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

03- <\/b><\/span><\/span><\/span>Teorema de Stevin<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>m\u00e1xima<\/b><\/span><\/span><\/sub><\/span> = d<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span>.g.h<\/b><\/span><\/span><\/span> \"\" 14000 = 10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>.10.h \"\" h = 14000\/10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span> = 14.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span> = 14.10<\/b><\/span><\/span><\/span>-1<\/b><\/span><\/span><\/sup><\/span><\/p>\n

h = 1,4 m (altura do bra\u00e7o at\u00e9 a bolsa do soro).<\/b><\/span><\/span><\/span><\/p>\n

h\u2019 = 1,4 + 0,7 = 2,1 m (altura da bolsa de soro at\u00e9 o solo)<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

04- <\/b><\/span><\/span><\/span>A energia \u00e9 a cin\u00e9tica:<\/b><\/span><\/span><\/span><\/p>\n

BA<\/b><\/span><\/span><\/span><\/span> \"\" m=100g = 0,1 kg \"\" V<\/b><\/span><\/span><\/span><\/span>1<\/b><\/span><\/span><\/span><\/sub><\/span> = 20 cm\/s = 0,2 m\/s \"\" <\/b><\/span><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span><\/span>c1<\/b><\/span><\/span><\/span><\/sub><\/span> =mV<\/b><\/span><\/span><\/span><\/span>1<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/2<\/b><\/span><\/span><\/span><\/span> = 0,1.0,2<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/2 = 0,1.0,04\/2 \"\" <\/b><\/span><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span><\/span>c1<\/b><\/span><\/span><\/span><\/sub><\/span> =<\/b><\/span><\/span><\/span><\/span> <\/b>0,002 J.<\/b><\/span><\/span><\/span><\/span> <\/b><\/p>\n

\"\"<\/p>\n

AA<\/b><\/span><\/span><\/span><\/span> \"\" m=100g = 0,1 kg \"\" V<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span> = 60 cm\/s = 0,6 m\/s \"\" <\/b><\/span><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span><\/span>c2<\/b><\/span><\/span><\/span><\/sub><\/span> =mV<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/2<\/b><\/span><\/span><\/span><\/span> = 0,1.0,6<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/2 = 0,1.0,36\/2 \"\" <\/b><\/span><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span><\/span>c2 <\/b><\/span><\/span><\/span><\/sub><\/span>=<\/b><\/span><\/span><\/span><\/span> <\/b>0,018 J.<\/b><\/span><\/span><\/span><\/span> <\/b><\/p>\n

E<\/b><\/span><\/span><\/span>c2<\/b><\/span><\/span><\/sub><\/span>\/E<\/b><\/span><\/span><\/span>c1<\/b><\/span><\/span><\/sub><\/span> = 0,018\/0,002 <\/b><\/span><\/span><\/span>= 9.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

05- <\/b><\/span><\/span><\/span>A. Correta<\/b><\/span><\/span><\/span> \"\" no interior da membrana o <\/b><\/span><\/span><\/span>campo el\u00e9trico<\/b><\/span><\/span><\/span> se <\/b><\/span><\/span><\/span>afasta das cargas positivas e se aproxima das negativas, \u00e9 uniforme e diferente de zero.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

B. Falsa<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>na <\/b><\/span><\/span><\/span>regi\u00e3o entre a parede externa e interna<\/b><\/span><\/span><\/span> (no interior da membrana celular) <\/b><\/span><\/span><\/span>o potencial <\/b><\/span><\/span><\/span>\u00e9 uniforme e diferente de zero<\/b><\/span><\/span><\/span><\/p>\n

C. Falsa \"\" <\/b><\/span><\/span><\/span>placas <\/b><\/span><\/span><\/span>positivas<\/b><\/span><\/span><\/span> possuem <\/b><\/span><\/span><\/span>maior potencial<\/b><\/span><\/span><\/span><\/p>\n

D. Falsa<\/b><\/span><\/span><\/span> \"\"\u00a0 <\/b><\/span><\/span><\/span>veja A<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

06- <\/b><\/span><\/span><\/span>Observe que a <\/b><\/span><\/span><\/span>for\u00e7a <\/b><\/span><\/span><\/span>\u00e9 aplicada na \u00e1rea do <\/b><\/span><\/span><\/span>\u00eambolo<\/b><\/span><\/span><\/span> (<\/b><\/span><\/span><\/span>S<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> <\/b>= 3,0 cm<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> <\/b>= 3.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span> m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>) \"\" P = F\/S \"\" 1800 = <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

F\/3.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span> \"\" F =1800.3.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span> \"\" F = 5400.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span> = 0,54 N.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

07- <\/b><\/span><\/span><\/span>A <\/b><\/span><\/span><\/span>escolha do material de blindagem<\/b><\/span><\/span><\/span> depende do <\/b><\/span><\/span><\/span>tipo da radia\u00e7\u00e3o<\/b><\/span><\/span><\/span>, atividade da fonte e da taxa de dose que \u00e9 aceit\u00e1vel fora do material de blindagem.<\/b><\/span><\/span><\/span><\/p>\n

\u00c9 <\/b><\/span><\/span><\/span>qualquer anteparo colocado entre o feixe e o indiv\u00edduo<\/b><\/span><\/span><\/span>. A <\/b><\/span><\/span><\/span>blindagem<\/b><\/span><\/span><\/span> serve para atenuar o <\/b><\/span><\/span><\/span>feixe de<\/b><\/span><\/span><\/span> <\/b>radia\u00e7\u00e3o<\/b><\/span><\/span><\/span>. Ex.: Aventais de chumbo, biombos de chumbo, paredes baritadas das salas dos equipamentos de radiodiagn\u00f3stico e radioterapia,etc.<\/b><\/span><\/span><\/span><\/p>\n

Portanto<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>as <\/b><\/span><\/span><\/span>blindagens<\/b><\/span><\/span><\/span> para <\/b><\/span><\/span><\/span>cada um<\/b><\/span><\/span><\/span> desses tipos de radia\u00e7\u00f5es devem ser <\/b><\/span><\/span><\/span>constitu\u00eddas de<\/b><\/span><\/span><\/span> <\/b><\/p>\n

\"\"<\/p>\n

diferentes materiais e diferentes espessuras<\/b><\/span><\/span><\/span> para fins de <\/b><\/span><\/span><\/span>radioprote\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

<\/h2>\n

Voltar para exerc\u00edcios.<\/span><\/a><\/h2>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01- 02- I. Correta todos os pontos do tubo \u201cvarrem\u201d o mesmo \u00e2ngulo no mesmo intervalo de tempo, portanto possuem a mesma velocidade angular. II. Falsa veja I III. Correta quanto mais densa, mais pesada, mais afastada. IV. Falsa veja III. V. Correta se a velocidade \u00e9 alta, a freq\u00fc\u00eancia (n\u00famero de voltas por segundo) \u00e9 maior que o<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":750,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-752","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/752","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=752"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/752\/revisions"}],"predecessor-version":[{"id":753,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/752\/revisions\/753"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/750"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=752"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}