{"id":719,"date":"2015-05-12T19:16:58","date_gmt":"2015-05-12T19:16:58","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=719"},"modified":"2024-09-03T13:09:17","modified_gmt":"2024-09-03T13:09:17","slug":"resolucao-comentada-da-unipar-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-da-unipar-2015\/resolucao-comentada-da-unipar-2015\/","title":{"rendered":"Resolu\u00e7\u00e3o Comentada da UNIPAR 2015"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span>Dilata\u00e7\u00e3o superficial \"\" \u2206S = S<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.\u03b2.\u2206t \"\"<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span>diminui\u00e7\u00e3o de \u00e1rea ser\u00e1 a mesma para os dois<\/b><\/span><\/span><\/span>, pois s\u00e3o do <\/b><\/span><\/span>mesmo material<\/b><\/span><\/span><\/span> (mesmo coeficiente de dilata\u00e7\u00e3o superficial \u03b2), possuem <\/b><\/span><\/span>mesma \u00e1rea inicial<\/b><\/span><\/span><\/span> (S<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sub>) e sofrem a <\/b><\/span><\/span>mesma varia\u00e7\u00e3o de temperatura<\/b><\/span><\/span><\/span> (\u2206t). <\/b><\/span><\/span>Assim, tanto o disco quanto o anel continuam encaixando-se no orif\u00edcio na placa.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

02- <\/span><\/span><\/span>Q = m.c.\u2206\u03b8<\/b><\/span><\/span><\/span> = 200.1.(100 \u2013 30) = <\/b><\/span><\/span>14000 cal \"\" P = Q\/\u2206 t \"\"<\/b><\/span><\/span><\/span> 250 = 14000\/\u2206t \"\" \u2206t = 14000\/250 <\/b><\/span><\/span>= <\/b><\/span><\/span><\/span><\/p>\n

56 s.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

03- <\/span><\/span><\/span>Tempo <\/b><\/span><\/span><\/span>que demora para percorrer a <\/b><\/span><\/span>primeira metade \u2206S = 100 km com V<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span> = 60 km\/h \"\" V<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span> = \u2206S\/\u2206t\"\"<\/b><\/span><\/span><\/span> 60 = 100\/\u2206t \"\" <\/b><\/span><\/span>\u2206t<\/b><\/span><\/span><\/span> = 100\/60 <\/b><\/span><\/span>= 5\/3 h.<\/b><\/span><\/span><\/span><\/p>\n

O <\/b><\/span><\/span>tempo da primeira etapa que deve incluir os 20 min = 20\/60 = 1\/3 h de parada \"\" \u2206t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 5\/3 + 1\/3 = <\/b><\/span><\/span>2h.<\/b><\/span><\/span><\/span><\/p>\n

Para percorrer a <\/b><\/span><\/span>segunda metade (100km), faltam \u2206t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = 3 \u2013 2 = 1h \"\"<\/b><\/span><\/span><\/span> V<\/b><\/span><\/span>m2<\/b><\/span><\/span><\/sub> = 100\/1 \"\" <\/b><\/span><\/span>V<\/b><\/span><\/span><\/span>m2<\/b><\/span><\/span><\/sub><\/span> = 100 km\/h.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

04- <\/span><\/span><\/span>Velocidade do barco em rela\u00e7\u00e3o \u00e0s margens \"\" V<\/b><\/span><\/span><\/span>bm<\/b><\/span><\/span><\/sub><\/span> = 14 + 4 = 18\/3,6 <\/b><\/span><\/span><\/span>= 5 m\/s \"\"<\/b><\/span><\/span><\/span> para atravessar totalmente a ponte o <\/b><\/span><\/span><\/span>barco percorre \u2206S = L + D = 80 + 25 = 105m \"\" V<\/b><\/span><\/span><\/span>bm<\/b><\/span><\/span><\/sub><\/span> = \u2206S\/\u2206t \"\"<\/b><\/span><\/span><\/span> 5 = 105\/\u2206t \"\"<\/b><\/span><\/span><\/span><\/p>\n

\u2206t = 21 s.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

05- <\/span><\/span><\/span>Observe na figura abaixo que as <\/b><\/span><\/span>regi\u00f5es I e III recebem apenas parte da luz<\/b><\/span><\/span><\/span> emitida pela fonte <\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

extensa <\/b><\/span><\/span>(penumbras)<\/b><\/span><\/span><\/span> enquanto que a <\/b><\/span><\/span>regi\u00e3o II n\u00e3o recebe nenhuma luz emitida pela fonte extensa (sombra).<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

<\/h2>\n

Voltar para exerc\u00edcios.<\/span><\/a><\/h2>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01- Dilata\u00e7\u00e3o superficial \u2206S = So.\u03b2.\u2206t a diminui\u00e7\u00e3o de \u00e1rea ser\u00e1 a mesma para os dois, pois s\u00e3o do mesmo material (mesmo coeficiente de dilata\u00e7\u00e3o superficial \u03b2), possuem mesma \u00e1rea inicial (So) e sofrem a mesma varia\u00e7\u00e3o de temperatura (\u2206t). Assim, tanto o disco quanto o anel continuam encaixando-se no orif\u00edcio na placa. R- B 02- Q = m.c.\u2206\u03b8<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":717,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-719","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/719","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=719"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/719\/revisions"}],"predecessor-version":[{"id":720,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/719\/revisions\/720"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/717"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=719"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}