{"id":662,"date":"2015-05-12T17:00:16","date_gmt":"2015-05-12T17:00:16","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=662"},"modified":"2024-09-03T13:21:34","modified_gmt":"2024-09-03T13:21:34","slug":"exercicios-resolvidos-ucs-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-ucs-2015\/","title":{"rendered":"Exercicios Resolvidos UCS 2015"},"content":{"rendered":"<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_6274b724.png\" alt=\"\" width=\"167\" height=\"114\" name=\"Imagem 41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Viner Hand ITC,serif;\"><span style=\"font-size: large;\"><b>A\u00a0Universidade de Caxias do Sul\u00a0(UCS) \u00e9 uma\u00a0institui\u00e7\u00e3o\u00a0de\u00a0ensino superior\u00a0da\u00a0regi\u00e3o nordeste\u00a0do\u00a0Rio Grande do Sul,\u00a0Brasil. \u00c9 a maior em n\u00famero de alunos do\u00a0estado\u00a0do Rio Grande do Sul.\u00a0Conta com unidades nas cidades de\u00a0Caxias do Sul,\u00a0Bento Gon\u00e7alves, Vacaria,\u00a0Canela,\u00a0Farroupilha,\u00a0Guapor\u00e9,\u00a0Nova Prata,\u00a0Veran\u00f3polis\u00a0e\u00a0S\u00e3o Sebasti\u00e3o do Ca\u00ed. Tendo sido considerada recentemente a segunda melhor universidade particular do Brasil, superada apenas pela\u00a0PUC-SP.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Viner Hand ITC,serif;\"><span style=\"font-size: large;\"><b>Hoje, a Universidade de Caxias do Sul j\u00e1 \u00e9 parte essencial do projeto de desenvolvimento regional e busca, atrav\u00e9s da qualifica\u00e7\u00e3o cont\u00ednua e do incentivo aos universit\u00e1rios, crescer e consolidar sua presen\u00e7a no panorama universit\u00e1rio nacional e internacional.<img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_fcb873fc.png\" alt=\"\" width=\"775\" height=\"179\" name=\"Imagem 1\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_4e5a4b73.jpg\" alt=\"\" width=\"536\" height=\"149\" name=\"Imagem 2\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Quando um motorista vai ao posto de gasolina para\u00a0colocar ar nos pneus do carro, \u00e9 comum<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_2e45369d.png\" alt=\"\" width=\"261\" height=\"154\" name=\"Imagem 3\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>encontrar o valor de\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>press\u00e3o fornecido pela bomba de ar expresso na unidade Psi (pound per square inch)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, que\u00a0n\u00e3o \u00e9 uma unidade\u00a0do\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sistema Internacional de Unidades<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Se, por exemplo, o manual do usu\u00e1rio do ve\u00edculo determinar o\u00a0valor para calibra\u00e7\u00e3o dos pneus em\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>30 Psi,\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>sendo que\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1 Psi = 6,895. 10<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0Pa<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, significa que o\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>motorista deve aplicar<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 30 N de for\u00e7a do ar em toda a \u00e1rea interna do pneu.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 2,07.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N de for\u00e7a, aproximadamente, em cada m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2\u00a0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da \u00e1rea interna do pneu.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 4,35.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0N de for\u00e7a, aproximadamente, em cada m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2\u00a0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da \u00e1rea interna do pneu.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 30 quilogramas de massa de ar em cada m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3\u00a0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da \u00e1rea interna do pneu.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) uma quantidade de ar \u00e0 temperatura de 30 \u00b0C.<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_7747824f.jpg\" alt=\"\" width=\"678\" height=\"142\" name=\"Imagem 4\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Tendo chegado atrasado ao casamento, um convidado conseguiu pegar uma \u00faltima fatia de bolo e concluiu que experimentara o melhor glac\u00ea de toda a sua vida. Ouvindo falar que na cozinha havia mais um bolo, mas que seria cortado apenas em outra festa, ele foi at\u00e9 l\u00e1. Viu o bolo em cima de uma mesa perto da porta. Por\u00e9m, percebeu que havia tamb\u00e9m uma cozinheira de costas para o bolo e para ele. Querendo passar o dedo no bolo sem ser pego pela cozinheira e conseguir pegar a maior quantidade de glac\u00ea poss\u00edvel, o convidado deduziu que, se passasse muito r\u00e1pido, o dedo pegaria pouco glac\u00ea; mas, se passasse muito lentamente, corria o risco de ser descoberto. Supondo,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ent\u00e3o, que\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ele tenha 3 segundos\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>para roubar o glac\u00ea sem ser notado e que a melhor t\u00e9cnica para<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_cdbf295.png\" alt=\"\" width=\"278\" height=\"170\" name=\"Imagem 5\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>conseguir a maior quantidade seja\u00a0passar o dedo\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>por 40,5 cm de bolo em MRU<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>V, partindo do repouso, qual\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>acelera\u00e7\u00e3o\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>teria o dedo no intervalo de tempo do roubo do glac\u00ea?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,03 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 0,04 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 0,09 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 1,05 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 2 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>03-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_665eafe1.jpg\" alt=\"\" width=\"673\" height=\"144\" name=\"Imagem 6\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O\u00a0centro de massa\u00a0(ponto que se comporta como se toda a massa de um corpo estivesse concentrada nele) de uma pessoa de\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>80 kg\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>se encontra exatamente na\u00a0altura do umbigo\u00a0quando ela\u00a0est\u00e1 em p\u00e9 sobre o ch\u00e3o, com a postura ereta. Suponha que a pessoa, para comemorar a aprova\u00e7\u00e3o<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_a4a2a101.png\" alt=\"\" width=\"137\" height=\"219\" name=\"Imagem 7\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>no vestibular,\u00a0usou a energia que adquiriu no almo\u00e7o para executar um pulo na vertical, utilizando como impulso apenas as pernas. Nesse pulo, durante a subida,\u00a0seu umbigo, a partir da posi\u00e7\u00e3o inicial mencionada, variou sua posi\u00e7\u00e3o\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>para cima em 40 cm<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Se em\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cada 100 g do almo\u00e7o ela recebe 100 calorias<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, quantos gramas de almo\u00e7o, no m\u00ednimo, ela ingeriu para\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ter energia para dar esse<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pulo?<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0Considere, para fins de simplifica\u00e7\u00e3o,\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1 cal = 4,2 J, a acelera\u00e7\u00e3o da gravidade como g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, que a massa adquirida no almo\u00e7o j\u00e1 est\u00e1 inclu\u00edda nos 80 kg e que a\u00a0energia do almo\u00e7o \u00e9 toda convertida em energia potencial gravitacional.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 40,3 g <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 55,5 g <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 76,2 g <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 100 g <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 200 g<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_7a1ee6af.jpg\" alt=\"\" width=\"697\" height=\"154\" name=\"Imagem 8\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Tentando inovar no show de inaugura\u00e7\u00e3o de um santu\u00e1rio de animais, um bi\u00f3logo\u00a0resolveu apagar as luzes do palco e substitu\u00ed-las por vaga-lumes libertados de uma caixa. Supondo que\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>um vaga<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&#8211;<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_49e881c4.png\" alt=\"\" width=\"260\" height=\"153\" name=\"Imagem 9\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>lume consiga gerar luz a 0,5 Joules por segundo, se a ilumina\u00e7\u00e3o artificial liberava energia luminosa na taxa de 300 W, quantos vaga-lumes precisar\u00e3o ser soltos para gerar esse mesmo efeito luminoso?\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para fins de simplifica\u00e7\u00e3o, desconsidere quaisquer outras caracter\u00edsticas que venham a diferenciar a luz dos vaga-lumes da luz de ilumina\u00e7\u00e3o artificial.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 200 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 300 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 500 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 600 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 80005<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>05-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_f94460a.jpg\" alt=\"\" width=\"683\" height=\"149\" name=\"Imagem 10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Projeta-se um futuro em que\u00a0as roupas vir\u00e3o com circuitos eletr\u00f4nicos embutidos\u00a0para desempenhar\u00a0fun\u00e7\u00f5es como regula\u00e7\u00e3o de temperatura, celulares, sensores de presen\u00e7a, entre outros.\u00a0Mas, como qualquer\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>equipamento el\u00e9trico<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, uma necessidade fundamental \u00e9 a\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>alimenta\u00e7\u00e3o de energia<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Suponha um cientista que criou uma roupa el\u00e9trica para\u00a0praticantes de luta. A\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>bateria<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0dessa roupa \u00e9 ligada a um\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>tecido repleto de transdutores piezoel\u00e9tricos<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, que s\u00e3o dispositivos que, basicamente,\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>convertem<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_57719a7e.png\" alt=\"\" width=\"174\" height=\"172\" name=\"Imagem 11\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>energia mec\u00e2nica em energia el\u00e9trica<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Supondo que a\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pancada aplica na roupa um trabalho de 0,5 Joules, em 0,5 segundos, totalmente convertido em energia el\u00e9trica<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, e que a\u00a0bateria \u00e9 carregada com uma\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>corrente el\u00e9trica de 4 mA,\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>qual \u00e9 a\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>tens\u00e3o el\u00e9trica gerada pela pancada no circuito\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>formado pela<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>roupa e pela bateria?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,01 V <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 0,5 V <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 5,0 V <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 250 V <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 1 000 V<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>06-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_33938054.jpg\" alt=\"\" width=\"700\" height=\"150\" name=\"Imagem 12\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dois rinocerontes machos, na disputa por uma f\u00eamea,\u00a0colidiram de frente\u00a0um com o outro. O\u00a0maior tinha\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1200 kg<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e estava a uma\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade de 36 km\/h<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.\u00a0O outro, com\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1000 kg<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, estava a uma\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade de 20 m\/s.\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Qual a\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>energia cin\u00e9tica total envolvida na colis\u00e3o?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 53.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 17,8.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 154.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 260.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 827.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>07-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_c6fecc9f.jpg\" alt=\"\" width=\"700\" height=\"144\" name=\"Imagem 13\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma\u00a0ferramenta de corte\u00a0a raio laser consegue cortar\u00a0v\u00e1rios materiais, como\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a\u00e7o carbono, a\u00e7o<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_d7a5b6e.png\" alt=\"\" width=\"250\" height=\"132\" name=\"Imagem 14\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>inoxid\u00e1vel, alum\u00ednio, tit\u00e2nio, pl\u00e1sticos, etc<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Supondo, numa situa\u00e7\u00e3o idealizada para fins de simplifica\u00e7\u00e3o, que o\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>material s\u00f3lido a ser cortado estava exatamente na sua temperatura de transi\u00e7\u00e3o do estado s\u00f3lido para o l\u00edquido;\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>al\u00e9m disso, que o<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>laser foi aplicado e liquefez o material nos trechos em que esteve em contato com ele<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, por\u00e9m,\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>sem aumentar a temperatura do material nesses trechos<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Pode-se dizer que o\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>laser transferiu para o material uma quantidade de energia associada diretamente<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) ao calor espec\u00edfico do material.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) ao calor latente de fus\u00e3o do material.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) \u00e0 capacidade t\u00e9rmica do material. <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) ao m\u00f3dulo de compressibilidade do material.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) ao n\u00famero de moles do material.<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_6bbd426a.jpg\" alt=\"\" width=\"685\" height=\"139\" name=\"Imagem 15\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Alfredo Moser, um mec\u00e2nico mineiro, desenvolveu um\u00a0sistema de ilumina\u00e7\u00e3o\u00a0baseado em garrafas\u00a0pet de\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dois litros<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>preenchidas com uma solu\u00e7\u00e3o de\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e1gua e cloro.\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Capaz de iluminar ambientes fechados durante o dia, a l\u00e2mpada de Moser j\u00e1 \u00e9 usada em diversos pa\u00edses. Sua instala\u00e7\u00e3o exige que<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_1bf2d839.png\" alt=\"\" width=\"240\" height=\"134\" name=\"Imagem 16\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ela seja\u00a0adaptada no teto de forma que metade do seu corpo fique para fora da casa e metade para dentro.\u00a0A inten\u00e7\u00e3o \u00e9 que a<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>luz do sol incida na parte da garrafa que fica acima do telhado e seja desviada pelo l\u00edquido dentro da garrafa para o interior da resid\u00eancia.\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma ideia simples e eficiente\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>que est\u00e1 baseada na propriedade da luz conhecida como<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) indu\u00e7\u00e3o.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) reverbera\u00e7\u00e3o. <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) interfer\u00eancia. <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) condu\u00e7\u00e3o el\u00e9trica. <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) refra\u00e7\u00e3o<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>09-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_3f395f3.jpg\" alt=\"\" width=\"628\" height=\"150\" name=\"Imagem 17\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Assumindo que o\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>calor espec\u00edfico da \u00e1gua vale 1 cal\/g \u00b0C,\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>considere que\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>100 g de \u00e1gua a 60 \u00b0C\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>foram<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_5ee8ea88.png\" alt=\"\" width=\"182\" height=\"158\" name=\"Imagem 18\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>depositadas em uma\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cuia de chimarr\u00e3o que j\u00e1 possu\u00eda erva-mate e bomba<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Suponha que\u00a0ap\u00f3s um r\u00e1pido intervalo de tempo a \u00e1gua\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>transmitiu 100 calorias para a bomba, 100 calorias para a erva e 30 calorias para a cuia<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.\u00a0Qual a\u00a0temperatura da \u00e1gua no instante exato ap\u00f3s terem ocorrido essas transmiss\u00f5es de calor?\u00a0Para fins de simplifica\u00e7\u00e3o, ignore qualquer outro evento de perda de energia interna da \u00e1gua que n\u00e3o esteja entre os citados acima.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 57,7 \u00b0C <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 52,3 \u00b0C<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 45,0 \u00b0C <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 28,2 \u00b0C <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 23 \u00b0C<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10-(UCS-RS-015)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_ecacad13.jpg\" alt=\"\" width=\"725\" height=\"147\" name=\"Imagem 19\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um importante componente para um filme \u00e9 sua\u00a0trilha sonora. Alguns sons, inclusive, j\u00e1 est\u00e3o associados a certas\u00a0emo\u00e7\u00f5esque se desejam passar ao espectador em\u00a0uma cena.\u00a0Por exemplo, em<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/universidades-2015\/ucs\/i_6e0a691e8fc30d4c_html_365b74ae.png\" alt=\"\" width=\"576\" height=\"144\" name=\"Imagem 20\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>filmes de terror e mist\u00e9rio, \u00e9 comum o som de fundo da cena ser\u00a0mais grave (embora haja exce\u00e7\u00f5es).\u00a0Imagine-se uma pessoa<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cuja percep\u00e7\u00e3o sonora a permite distinguir os sons graves e agudos emitidos por um instrumento musical.\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Se ela receber do<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>mesmo aparelho de som em sequ\u00eancia<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, e sem que ocorra nenhuma mudan\u00e7a no meio de propaga\u00e7\u00e3o da onda,\u00a0<\/b><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>primeiro uma onda sonora que ela classifica como de som grave, e depois uma onda sonora que ela classifica como de som agudo,<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>significa que ela recebeu, respectivamente,<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) duas ondas mec\u00e2nicas, sendo a primeira com frequ\u00eancia menor do que a segunda.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) uma onda eletromagn\u00e9tica de pequeno comprimento de onda e uma onda mec\u00e2nica de grande comprimento de onda.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) duas ondas eletromagn\u00e9ticas com iguais frequ\u00eancias e diferentes comprimentos de onda.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) duas ondas mec\u00e2nicas com iguais comprimentos de onda e diferentes frequ\u00eancias.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) duas ondas mec\u00e2nicas com iguais frequ\u00eancias, iguais comprimentos de onda, mas diferentes amplitudes.<\/b><\/span><\/span><\/p>\n<h2><span style=\"color: #000080;\"><a style=\"color: #000080;\" title=\"Resolucao da UCS 2015\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-ucs-2015\/resolucao-da-ucs-2015\/\">Confira a resolu\u00e7\u00e3o comentada<\/a><\/span><\/h2>\n","protected":false},"excerpt":{"rendered":"<p>A\u00a0Universidade de Caxias do Sul\u00a0(UCS) \u00e9 uma\u00a0institui\u00e7\u00e3o\u00a0de\u00a0ensino superior\u00a0da\u00a0regi\u00e3o nordeste\u00a0do\u00a0Rio Grande do Sul,\u00a0Brasil. \u00c9 a maior em n\u00famero de alunos do\u00a0estado\u00a0do Rio Grande do Sul.\u00a0Conta com unidades nas cidades de\u00a0Caxias do Sul,\u00a0Bento Gon\u00e7alves, Vacaria,\u00a0Canela,\u00a0Farroupilha,\u00a0Guapor\u00e9,\u00a0Nova Prata,\u00a0Veran\u00f3polis\u00a0e\u00a0S\u00e3o Sebasti\u00e3o do Ca\u00ed. Tendo sido considerada recentemente a segunda melhor universidade particular do Brasil, superada apenas pela\u00a0PUC-SP. Hoje, a Universidade de Caxias do Sul j\u00e1 \u00e9<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":5,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-662","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/662","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=662"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/662\/revisions"}],"predecessor-version":[{"id":668,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/662\/revisions\/668"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/5"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=662"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}