{"id":619,"date":"2015-04-12T13:52:47","date_gmt":"2015-04-12T13:52:47","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=619"},"modified":"2024-09-02T17:11:59","modified_gmt":"2024-09-02T17:11:59","slug":"resolucao-comentada-da-uss","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-da-uss-2015\/resolucao-comentada-da-uss\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada da USS"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span>Partiu<\/b><\/span><\/span><\/span> de uma esta\u00e7\u00e3o <\/b><\/span><\/span><\/span>quando t=0 e chegou \u00e0 outra quando t=120s<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Em todo gr\u00e1fico <\/b><\/span><\/span><\/span>Vxt<\/b><\/span><\/span><\/span> o deslocamento <\/b><\/span><\/span><\/span>d <\/b><\/span><\/span><\/span>\u00e9 numericamente igual \u00e0 \u00e1rea, no caso, de um trap\u00e9zio:<\/b><\/span><\/span><\/span><\/p>\n

d = (B + b).h\/2<\/b><\/span><\/span><\/span> = (120 + 50).15\/2 = 2550\/2 \"\" <\/b><\/span><\/span><\/span>d = 1275m.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

02- <\/b><\/span><\/span><\/span>W=Q=2,6.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>kJ = 2,6.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span>J \"\" m = 10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span> kg \"\" \u03b8<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 20<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C \"\" c = 4 kJ.kg<\/b><\/span><\/span><\/span>-1<\/b><\/span><\/span><\/sup><\/span>.\u00b0C<\/b><\/span><\/span><\/span>-1<\/b><\/span><\/span><\/sup><\/span> = 4.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span> kJ.kg<\/b><\/span><\/span><\/span>-1<\/b><\/span><\/span><\/sup><\/span>.\u00b0C<\/b><\/span><\/span><\/span>-1<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

W = Q = m.c.(\u03b8 \u2013 \u03b8<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>) \"\" 2,6.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> = 10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>.4.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>.(\u03b8 \u2013 20) \"\" 2,6.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span>\/4.10<\/b><\/span><\/span><\/span>7<\/b><\/span><\/span><\/sup><\/span> = \u03b8 \u2013 20 \"\" 0,65.10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = \u03b8 \u2013 20<\/b><\/span><\/span><\/span><\/p>\n

\u03b8 = 65 + 20 \"\" <\/b><\/span><\/span><\/span>\u03b8 = 85<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

03- <\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = U<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>\/i<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = 50\/10 \"\" <\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = 5 \u2126<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = U<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span>\/i<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = 120\/48 \"\" <\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = 2,5 \u2126.<\/b><\/span><\/span><\/span><\/p>\n

Associados em s\u00e9rie <\/b><\/span><\/span><\/span>\"\" <\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = R<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> + R<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = 5 + 2,5 \"\" <\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = 7,5 \u2126.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

04- <\/b><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span>=E<\/b><\/span><\/span><\/span>c<\/b><\/span><\/span><\/sub><\/span> + E<\/b><\/span><\/span><\/span>pg<\/b><\/span><\/span><\/sub><\/span> = mV<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + m.g.h <\/b><\/span><\/span><\/span>= 8000.250<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + 8000.10.11000 \"\" E<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span> = 250 000 000 + 880 000 000 \"\"<\/b><\/span><\/span><\/span><\/p>\n

E<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span> = 250.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span> + 88.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span> = 1130.10<\/b><\/span><\/span><\/span>7<\/b><\/span><\/span><\/sup><\/span> \"\" <\/b><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span> = 11,3.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> J.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

05- <\/b><\/span><\/span><\/span>Bloco1 <\/b><\/span><\/span><\/span>\"\" quando <\/b><\/span><\/span><\/span>a trava \u00e9 retirada o bloco 1<\/b><\/span><\/span><\/span> se move com acelera\u00e7\u00e3o <\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/span> percorrendo <\/b><\/span><\/span><\/span>\u2206S <\/b><\/span><\/span><\/span>= 90cm<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

= 0,9m,<\/b><\/span><\/span><\/span> partindo do repouso <\/b><\/span><\/span><\/span>(V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 0)<\/b><\/span><\/span><\/span> durante <\/b><\/span><\/span><\/span>t = 3s, puxado por F<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span> = T:<\/b><\/span><\/span><\/span>
\n<\/b><\/span><\/span><\/span>\u2206S = V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>t + at<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2<\/b><\/span><\/span><\/span> \"\" 0,9 = 0.3 + a.3<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 \"\" a = 0,9\/4,5 \"\" <\/b><\/span><\/span><\/span>a = 0,2 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

F<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span> = <\/b><\/span><\/span><\/span>T = m<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>.a<\/b><\/span><\/span><\/span> \"\" T = m<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>.0,2 \"\" <\/b><\/span><\/span><\/span>T = 0,2m<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span><\/p>\n

Bloco 2<\/b><\/span><\/span><\/span> \"\" est\u00e1 <\/b><\/span><\/span><\/span>caindo<\/b><\/span><\/span><\/span> com acelera\u00e7\u00e3o <\/b><\/span><\/span><\/span>a = 0,2 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> tal que \"\" <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> \u2013 T = m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.a<\/b><\/span><\/span><\/span> \"\" m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>g \u2013 T = m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.a<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

10m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> \u2013 0,2m<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 0,2m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> \"\" 9,8m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = 0,2m<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> \"\" <\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\/m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = 9,8\/0,2 <\/b><\/span><\/span><\/span>= 49.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os Exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01- Partiu de uma esta\u00e7\u00e3o quando t=0 e chegou \u00e0 outra quando t=120s. Em todo gr\u00e1fico Vxt o deslocamento d \u00e9 numericamente igual \u00e0 \u00e1rea, no caso, de um trap\u00e9zio: d = (B + b).h\/2 = (120 + 50).15\/2 = 2550\/2 d = 1275m. R- C 02- W=Q=2,6.106kJ = 2,6.109J m = 104 kg \u03b8o = 20oC c =<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":617,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-619","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/619","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=619"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/619\/revisions"}],"predecessor-version":[{"id":621,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/619\/revisions\/621"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/617"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=619"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}