{"id":570,"date":"2015-03-05T18:03:07","date_gmt":"2015-03-05T18:03:07","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=570"},"modified":"2024-09-03T13:01:54","modified_gmt":"2024-09-03T13:01:54","slug":"resolucao-comentada-da-unicesumar-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-da-unicesumar-2015\/resolucao-comentada-da-unicesumar-2015\/","title":{"rendered":"Resolu\u00e7\u00e3o Comentada da UniCesumar 2015"},"content":{"rendered":"

RESOLU\u00c7\u00d5ES<\/b><\/span><\/span><\/span><\/p>\n

01<\/span><\/span><\/span>– <\/span><\/span>A <\/b><\/span><\/span><\/span>corrente el\u00e9trica total i= 4 A<\/b><\/span><\/span><\/span> que passa <\/b><\/span><\/span><\/span>pelo fus\u00edvel<\/b><\/span><\/span><\/span> \u00e9 dividida <\/b><\/span><\/span><\/span>em n correntes<\/b><\/span><\/span><\/span>, cada uma <\/b><\/span><\/span><\/span>valendo i\u2019, que passam por cada l\u00e2mpada — 4 = n.i\u2019.<\/b><\/span><\/span><\/span><\/p>\n

Como as l\u00e2mpadas est\u00e3o associadas em <\/b><\/span><\/span><\/span>paralelo,<\/b><\/span><\/span><\/span> <\/b>tens\u00e3o U \u00e9 a mesma em cada uma, valendo U = 12<\/b><\/span><\/span><\/span> <\/b>V<\/b><\/span><\/span><\/span> e funcionando normalmente, dissipando uma <\/b><\/span><\/span><\/span>pot\u00eancia de P = 6 W.<\/b><\/span><\/span><\/span><\/p>\n

Corrente em cada l\u00e2mpada<\/b><\/span><\/span><\/span> para que funcionem <\/b><\/span><\/span><\/span>normalmente, percorridas por i\u2019<\/b><\/span><\/span><\/span>, tal que, P = i\u2019.U —<\/b><\/span><\/span><\/span><\/p>\n

6 = i\u2019.12 — i\u2019 = 6\/12 — <\/b><\/span><\/span><\/span>i\u2019 = 0,5 A.<\/b><\/span><\/span><\/span><\/p>\n

Ent\u00e3o, a <\/b><\/span><\/span><\/span>corrente total no fus\u00edvel<\/b><\/span><\/span><\/span> deve valer <\/b><\/span><\/span><\/span>i =n.i\u2019<\/b><\/span><\/span><\/span> — 4 = n.0,5 — i=n = 4\/0,5 <\/b><\/span><\/span><\/span>— n = 8 l\u00e2mpadas<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

02- <\/span><\/span><\/span>Sendo os tri\u00e2ngulos hachurados da figura baixo semelhantes, voc\u00ea ter\u00e1 — h\/P = (3h\/4)\/d —<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

P = (4\/3)d<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

03- <\/span><\/span><\/span>PV = nRT<\/b><\/span><\/span><\/span> — 1,23.V = 5.0,082.(27 + 273) — V = 123\/1,23 — <\/b><\/span><\/span><\/span>V = 100 L.<\/b><\/span><\/span><\/span><\/p>\n

R – A<\/b><\/span><\/span><\/span><\/p>\n

04- <\/span><\/span><\/span>Fun\u00e7\u00e3o hor\u00e1ria do espa\u00e7o — <\/b><\/span><\/span><\/span>S = S<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> + Vt<\/b><\/span><\/span><\/span>, que, comparada com <\/b><\/span><\/span><\/span>S = 5 + 10t<\/b><\/span><\/span><\/span>, fornece — <\/b><\/span><\/span><\/span>S<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>= 5m e V=10m\/s.<\/b><\/span><\/span><\/span><\/p>\n

V = 2<\/b><\/span><\/span><\/span><\/span>\u03c0<\/b><\/span><\/span><\/span>R\/T<\/b><\/span><\/span><\/span><\/span> — 10 = 2.3.2,5\/T — T = 15\/10 — <\/b><\/span><\/span><\/span><\/span>T = 1,5 s (T = 6\/4 s).<\/b><\/span><\/span><\/span><\/span><\/p>\n

f = 1\/T<\/b><\/span><\/span><\/span> — <\/b><\/span><\/span><\/span>f = 1\/1,5 Hz (f = 4\/6 Hz).<\/b><\/span><\/span><\/span><\/p>\n

a<\/b><\/span><\/span><\/span>cp<\/b><\/span><\/span><\/sub><\/span> = V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/R<\/b><\/span><\/span><\/span> =10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2,5 = 100\/2,5 — <\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/span>cp<\/b><\/span><\/span><\/sub><\/span> = 40m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 40 m.s<\/b><\/span><\/span><\/span>-1<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

05- \"\"<\/span><\/span><\/span><\/p>\n

R = 2,5 + 7,5 — <\/b><\/span><\/span><\/span>R = 10 \u2126<\/b><\/span><\/span><\/span> — R = U\/i — 10 = 15\/i — <\/b><\/span><\/span><\/span>i = 1,5 A<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

B = 4.3.10<\/b><\/span><\/span><\/span>-7<\/b><\/span><\/span><\/sup><\/span>.800.1,5\/0,3<\/b><\/span><\/span><\/span> = 48 000.10<\/b><\/span><\/span><\/span>-7<\/b><\/span><\/span><\/sup><\/span> — <\/b><\/span><\/span><\/span>B = 0,0048 T.<\/b><\/span><\/span><\/span><\/p>\n

R – A<\/b><\/span><\/span><\/span><\/p>\n

Voltar para os Exerc\u00edcios<\/span><\/a><\/h3>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

RESOLU\u00c7\u00d5ES 01– A corrente el\u00e9trica total i= 4 A que passa pelo fus\u00edvel \u00e9 dividida em n correntes, cada uma valendo i\u2019, que passam por cada l\u00e2mpada — 4 = n.i\u2019. Como as l\u00e2mpadas est\u00e3o associadas em paralelo, tens\u00e3o U \u00e9 a mesma em cada uma, valendo U = 12 V e funcionando normalmente, dissipando uma pot\u00eancia de P =<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":568,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-570","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/570","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=570"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/570\/revisions"}],"predecessor-version":[{"id":571,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/570\/revisions\/571"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/568"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=570"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}