{"id":4782,"date":"2019-11-07T03:03:00","date_gmt":"2019-11-07T03:03:00","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=4782"},"modified":"2024-07-04T03:40:06","modified_gmt":"2024-07-04T03:40:06","slug":"termomecanica-meio-do-ano-2019-2020","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2019\/termomecanica-meio-do-ano-2019-2020\/","title":{"rendered":"Termomec\u00e2nica \u2013 meio do ano \u2013 2019\/2020"},"content":{"rendered":"

Termomec\u00e2nica \u2013 meio do ano \u2013 2019\/2020 <\/b><\/span><\/span><\/span><\/p>\n

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Faculdade de Tecnologia Termomecanica<\/b><\/span><\/span><\/span><\/p>\n

Na Faculdade de Tecnologia Termomecanica, o aluno recebe gratuitamente um curso que corresponde a um investimento financeiro anual por aluno de quase R$ 25 mil. Al\u00e9m do modelo de educa\u00e7\u00e3o inovador e gratuito, que inclui forma\u00e7\u00e3o humanista, todos os universit\u00e1rios recebem gratuitamente uniformes e alimenta\u00e7\u00e3o balanceada. A FTT ainda possui\u00a0parceria com mais de 130 empresas nacionais e multinacionais e 11 agentes de integra\u00e7\u00e3o de est\u00e1gio. Em 12 anos, a institui\u00e7\u00e3o j\u00e1\u00a0preparou quase 1,3 mil profissionais\u00a0para o mercado de trabalho e\u00a0conquistou \u00edndice de 86,7% de empregabilidade.<\/b><\/span><\/span><\/span><\/p>\n

A grade curricular dos quatro cursos superiores oferecidos pela Faculdade de Tecnologia Termomecanica \u2013 Administra\u00e7\u00e3o, Engenharia de Alimentos, Engenharia de Computa\u00e7\u00e3o e Engenharia de Controle e Automa\u00e7\u00e3o \u2013 possui tamb\u00e9m aulas de empreendedorismo, libras, recupera\u00e7\u00e3o e nivelamento. Al\u00e9m disso, cursos de extens\u00e3o s\u00e3o oferecidos gratuitamente aos alunos.<\/b><\/span><\/span><\/span><\/p>\n

A Faculdade de Tecnologia Termomec\u00e2nica est\u00e1 localizada no Centro Educacional da Funda\u00e7\u00e3o Salvador Arena, no munic\u00edpio de S\u00e3o Bernardo do Campo, na Grande S\u00e3o Paulo. O complexo educacional de 131 mil m\u00b2 recebeu\u00a0investimentos de mais de R$ 350 milh\u00f5es\u00a0em educa\u00e7\u00e3o nos \u00faltimos 15 anos e, al\u00e9m de laborat\u00f3rios com equipamentos de \u00faltima gera\u00e7\u00e3o, possui gin\u00e1sios e quadras poliesportivos, conjunto aqu\u00e1tico, est\u00e1dio ol\u00edmpico, uma rede de bibliotecas interativas e um dos teatros mais modernos do Brasil, com capacidade para 600 pessoas.<\/b><\/span><\/span><\/span><\/p>\n

Em nota divulgada em 17 de novembro de 2016, pelo Minist\u00e9rio da Educa\u00e7\u00e3o, a Faculdade de Tecnologia Termomec\u00e2nica obteve\u00a0nota quatro no IGC\u00a0\u2013 \u00cdndice Geral de Cursos. O IGC \u00e9 uma das medidas usadas pelo Inep para avaliar as institui\u00e7\u00f5es de educa\u00e7\u00e3o superior, p\u00fablicas e privadas, classificando-as com notas de um a cinco.<\/b><\/span><\/span><\/span><\/p>\n

De acordo com esse levantamento, a Faculdade de Tecnologia Termomecanica ocupa o 1\u00ba lugar entre as institui\u00e7\u00f5es de ensino superior das tr\u00eas principais cidades do ABC, a 7\u00aa no Estado de S\u00e3o Paulo e a 33\u00aa, entre todas as faculdades do Brasil. A coloca\u00e7\u00e3o \u00e9 um orgulho para uma faculdade que iniciou suas atividades h\u00e1 menos de uma d\u00e9cada e que se equipara a institui\u00e7\u00f5es j\u00e1 consagradas de nosso Pa\u00eds.<\/b><\/span><\/span><\/span><\/p>\n

01 \u2013 (Faculdade de Tecnologia Termomec\u00e2nica \u2013 SP- meio do ano \u2013 019\/020)<\/b><\/span><\/span><\/span><\/p>\n

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O <\/b><\/span><\/span><\/span>gr\u00e1fico mostra como varia a posi\u00e7\u00e3o s de um m\u00f3vel <\/b><\/span><\/span><\/span>que se <\/b><\/span><\/span><\/span>desloca em linha reta, em fun\u00e7\u00e3o do tempo t.<\/b><\/span><\/span><\/span><\/p>\n

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A <\/b><\/span><\/span><\/span>respeito desse movimento, \u00e9 correto afirmar <\/b><\/span><\/span><\/span>que<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>a acelera\u00e7\u00e3o \u00e9 nula no intervalo 0 < t < t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>a acelera\u00e7\u00e3o \u00e9 positiva no intervalo 0 < t < t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> e negativa no intervalo t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> < t < t<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(C)<\/b><\/span><\/span><\/span> a velocidade \u00e9 positiva no intervalo t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> < t < t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>o movimento \u00e9 retr\u00f3grado no intervalo t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> < t < t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>a \u00e1rea do gr\u00e1fico fornece numericamente o deslocamento total do movimento.<\/b><\/span><\/span><\/span><\/p>\n

02\u2013(Faculdade de Tecnologia Termomec\u00e2nica \u2013 SP- meio do ano \u2013 019\/020)<\/b><\/span><\/span><\/span><\/p>\n

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Um <\/b><\/span><\/span><\/span>bloco de 50 kg est\u00e1 apoiado e em equil\u00edbrio sobre o piso de um elevador, <\/b><\/span><\/span><\/span>que <\/b><\/span><\/span><\/span>desce com velocidade constante, como mostra a figura.<\/b><\/span><\/span><\/span><\/p>\n

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Num <\/b><\/span><\/span><\/span>dado momento, o elevador desacelera na raz\u00e3o de 1,5 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>,<\/b><\/span><\/span><\/span> <\/b>mantendo esse valor constante at\u00e9 o elevador parar no andar t\u00e9rreo.<\/b><\/span><\/span><\/span> <\/b><\/p>\n

Sendo <\/b><\/span><\/span><\/span>a acelera\u00e7\u00e3o da gravidade igual a 10 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>, F<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> o valor da for\u00e7a de contato entre o bloco e o piso do elevador antes da frenagem, <\/b><\/span><\/span><\/span>e <\/b><\/span><\/span><\/span>F<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> o valor dessa for\u00e7a durante a frenagem, a diferen\u00e7a F<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> \u2013 F<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> \u00e9<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>0. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>15 N. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>30 N. <\/b><\/span><\/span><\/span>() <\/b><\/span><\/span><\/span>50 N. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>75 N.<\/b><\/span><\/span><\/span><\/p>\n

03\u2013(Faculdade de Tecnologia Termomec\u00e2nica \u2013 SP- meio do ano \u2013 019\/020)<\/b><\/span><\/span><\/span><\/p>\n

UEST\u00c3O<\/b><\/span><\/span><\/span><\/p>\n

Um <\/b><\/span><\/span><\/span>bloco de 5 kg \u00e9 lan\u00e7ado verticalmente para cima, a partir do repouso, por uma mola cujo gr\u00e1fico da for\u00e7a nela aplicada pela elonga\u00e7\u00e3o<\/b><\/span><\/span><\/span> (ou compress\u00e3o) <\/b><\/span><\/span><\/span>correspondente \u00e9 dado a seguir.<\/b><\/span><\/span><\/span><\/p>\n

A <\/b><\/span><\/span><\/span>ilustra\u00e7\u00e3o seguinte mostra o bloco comprimindo a mola no instante inicial, quando se encontra em repouso.<\/b><\/span><\/span><\/span><\/p>\n

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(<\/b><\/span><\/span><\/span>Ap\u00f3s ser lan\u00e7ado, <\/b><\/span><\/span><\/span>verifica-se que o <\/b><\/span><\/span><\/span>bloco sobe verticalmente, at\u00e9 parar na altura de 5 metros,<\/b><\/span><\/span><\/span><\/p>\n

contados desde o ponto em que estava em repouso. <\/b><\/span><\/span><\/span><\/p>\n

Sendo a <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o da gravidade igual a 10 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> e n\u00e3o havendo resist\u00eancia do ar, a compress\u00e3o<\/b><\/span><\/span><\/span><\/p>\n

inicial sofrida pela mola \u00e9 igual<\/b><\/span><\/span><\/span> a<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>50 cm. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>45 cm. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>40 cm. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>35 cm. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>30 cm.<\/b><\/span><\/span><\/span><\/p>\n

04\u2013(Faculdade de Tecnologia Termomec\u00e2nica \u2013 SP- meio do ano \u2013 019\/020)<\/b><\/span><\/span><\/span><\/p>\n

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O <\/b><\/span><\/span><\/span>gr\u00e1fico mostra como varia a press\u00e3o num l\u00edquido X <\/b><\/span><\/span><\/span>(linha vermelha) e <\/b><\/span><\/span><\/span>na \u00e1gua <\/b><\/span><\/span><\/span>(linha azul), <\/b><\/span><\/span><\/span>ambos<\/b><\/span><\/span><\/span><\/p>\n

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em equil\u00edbrio e em fun\u00e7\u00e3o da profundidade, a partir de sua superf\u00edcie livre.<\/b><\/span><\/span><\/span><\/p>\n

\u00c9 correto afirmar que a densidade do l\u00edquido X, relativamente \u00e0 da \u00e1gua, \u00e9 igual <\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>0,4. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>0,5. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>0,6. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>0,8. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>0,9<\/b><\/span><\/span><\/span><\/p>\n

QUEST\u00c3O 05<\/b><\/span><\/span><\/span><\/p>\n

05\u2013(Faculdade de Tecnologia Termomec\u00e2nica \u2013 SP- meio do ano \u2013 019\/020)<\/b><\/span><\/span><\/span><\/p>\n

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Num <\/b><\/span><\/span><\/span>recipiente termicamente isolado, \u00e1gua e gelo s\u00e3o misturados, <\/b><\/span><\/span><\/span>e os <\/b><\/span><\/span><\/span>dados iniciais s\u00e3o mostrados na tabela.<\/b><\/span><\/span><\/span><\/p>\n

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Considerando que a troca de calor s\u00f3 ocorre entre o gelo e a \u00e1gua,<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span><\/span>sendo o calor latente de fus\u00e3o do gelo igual a 80 cal\/g,<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span><\/span>temperatura de equil\u00edbrio t\u00e9rmico dessa mistura <\/b><\/span><\/span><\/span>ser\u00e1<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>\u2013 2,0 \u00baC. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>0 \u00baC. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>2,5 \u00baC. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>5,0 \u00baC. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>7,5 \u00baC.<\/b><\/span><\/span><\/span><\/p>\n

06\u2013(Faculdade de Tecnologia Termomec\u00e2nica \u2013 SP- meio do ano \u2013 019\/020)<\/b><\/span><\/span><\/span><\/p>\n

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A <\/b><\/span><\/span><\/span>figura mostra um gato observando um peixe dentro de um aqu\u00e1rio contendo \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n

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O <\/b><\/span><\/span><\/span>\u00edndice de refra\u00e7\u00e3o do ar onde est\u00e1 o gato \u00e9 igual a 1,0 <\/b><\/span><\/span><\/span>e o <\/b><\/span><\/span><\/span>\u00edndice de refra\u00e7\u00e3o da \u00e1gua onde est\u00e1 o peixe \u00e9 igual a 1,5.<\/b><\/span><\/span><\/span><\/p>\n

Se o <\/b><\/span><\/span><\/span>gato v\u00ea a imagem do peixe a 20 cm abaixo da superf\u00edcie da \u00e1gua, a alternativa que assinala a profundidade real do peixe, em rela\u00e7\u00e3o a essa superf\u00edcie,<\/b><\/span><\/span><\/span> \u00e9<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>5 cm. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>10 cm. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>15 cm. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>25 cm. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>30 cm.<\/b><\/span><\/span><\/span><\/p>\n

07\u2013(Faculdade de Tecnologia Termomec\u00e2nica \u2013 SP- meio do ano \u2013 019\/020)<\/b><\/span><\/span><\/span><\/p>\n

U<\/b><\/span><\/span><\/span><\/p>\n

Uma carga el\u00e9trica com massa m e carga q est\u00e1 em repouso, <\/b><\/span><\/span><\/span>submetida a <\/b><\/span><\/span><\/span>apenas duas for\u00e7as: peso e for\u00e7a el\u00e9trica.<\/b><\/span><\/span><\/span><\/p>\n

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Sendo <\/b><\/span><\/span><\/span>g a acelera\u00e7\u00e3o da gravidade, a alternativa que fornece a op\u00e7\u00e3o correta para a intensidade do campo el\u00e9trico, na regi\u00e3o em que se encontra a carga,<\/b><\/span><\/span><\/span> \u00e9<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>mg <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>mgq <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>mg\/q <\/b><\/span><\/span><\/span> (D) <\/b><\/span><\/span><\/span>mg\/2q <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>2mg\/q<\/b><\/span><\/span><\/span><\/p>\n

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00edsica do vestibular do meio do ano da <\/b><\/span><\/span><\/span>Faculdade de Tecnologia Termomec\u00e2nica \u2013 SP- meio do ano \u2013 019\/020<\/b><\/span><\/span><\/span><\/p>\n

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01-<\/span><\/span><\/span><\/p>\n

A. Correta <\/b><\/span><\/span><\/span>entre <\/b><\/span><\/span><\/span>0 e t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> <\/b>o gr\u00e1fico \u00e9 uma <\/b><\/span><\/span><\/span>reta ascendente com o espa\u00e7o S aumentando de maneira uniforme com o tempo<\/b><\/span><\/span><\/span> (<\/b><\/span><\/span><\/span>movimento progressivo<\/b><\/span><\/span><\/span> <\/b>e <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o nula,<\/b><\/span><\/span><\/span> ou seja um movimento uniforme progressivo com velocidade constante). Entre <\/b><\/span><\/span><\/span>t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> e t<\/b><\/span><\/span><\/span>2 <\/b><\/span><\/span><\/sub><\/span>ele est\u00e1 rem repouso com acelera\u00e7\u00e3o nula.<\/b><\/span><\/span><\/span><\/p>\n

B. Falsa Veja (A).<\/b><\/span><\/span><\/span>. Falsa QUEST\u00c3O 02<\/b><\/span><\/span><\/span><\/p>\n

C. Falsa Veja (A).<\/b><\/span><\/span><\/span>. Falsa QUEST\u00c3O 02<\/b><\/span><\/span><\/span><\/p>\n

D. Falsa Veja (A).<\/b><\/span><\/span><\/span>. Falsa QUEST\u00c3O 02<\/b><\/span><\/span><\/span><\/p>\n

E. Falsa <\/b><\/span><\/span><\/span>a \u00e1rea do gr\u00e1fico <\/b><\/span><\/span><\/span>forneceria numericamente o deslocamento total <\/b><\/span><\/span><\/span>do movimento se o gr\u00e1fico fosse <\/b><\/span><\/span><\/span>vxt.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

02-<\/span><\/span><\/span><\/p>\n

Veja o formul\u00e1rio abaixo:<\/b><\/span><\/span><\/span><\/p>\n

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Antes da freagem com o elevador descendo com velocidade constante N = P <\/b><\/span><\/span><\/span> N = m.g = 50.10<\/b><\/span><\/span><\/span><\/p>\n

N = F<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 500 N.<\/b><\/span><\/span><\/span><\/p>\n

Quando <\/b><\/span><\/span><\/span>o elevador desce freando N > P F<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span> = m.a N \u2013 P = m.a <\/b><\/span><\/span><\/span> N \u2013 m.g = m.a <\/b><\/span><\/span><\/span><\/p>\n

N \u2013 50.10 = 50.1,5 N = 500 + 75 <\/b><\/span><\/span><\/span>N = F<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = 575 N.<\/b><\/span><\/span><\/span><\/p>\n

Diferen\u00e7a pedida F<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> \u2013 F<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> <\/b>= 575 \u2013 500 <\/b><\/span><\/span><\/span>= 75 N.<\/b><\/span><\/span><\/span><\/p>\n

R – E<\/b><\/span><\/span><\/span><\/p>\n

03-<\/span><\/span><\/span><\/p>\n

Se voc\u00ea n\u00e3o domina a teoria sobre a lei de Hooke ela est\u00e1 a seguir:<\/b><\/span><\/span><\/span><\/p>\n

For\u00e7a el\u00e1stica \u2013 Lei de Hooke<\/b><\/span><\/span><\/span><\/p>\n

Considere uma\u00a0<\/b><\/span><\/span><\/span>mola\u00a0<\/b><\/span><\/span><\/span>(ou um corpo el\u00e1stico qualquer<\/b><\/span><\/span><\/span>,\u00a0<\/b><\/span><\/span><\/span>corda de borracha, el\u00e1stico etc.<\/b><\/span><\/span><\/span>) sujeita a uma\u00a0<\/b><\/span><\/span><\/span>deforma\u00e7\u00e3o x<\/b><\/span><\/span><\/span>, devido \u00e0\u00a0<\/b><\/span><\/span><\/span>aplica\u00e7\u00e3o de uma for\u00e7a externa\u00a0.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

F<\/b><\/span><\/span><\/span>\u00a0 \u2014\u00a0\u00a0<\/b><\/span><\/span><\/span>intensidade da<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>for\u00e7a externa deformadora\u00a0<\/b><\/span><\/span><\/span>(que comprime ou distende a mola)<\/b><\/span><\/span><\/span><\/p>\n

Fe<\/b><\/span><\/span><\/span>\u00a0 \u2014\u00a0\u00a0<\/b><\/span><\/span><\/span>intensidade da<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>for\u00e7a el\u00e1stica<\/b><\/span><\/span><\/span>\u00a0que\u00a0<\/b><\/span><\/span><\/span>tende a fazer com que a mola retorne \u00e0 posi\u00e7\u00e3o normal<\/b><\/span><\/span><\/span><\/p>\n

x\u00a0<\/b><\/span><\/span><\/span>\u2014\u00a0\u00a0<\/b><\/span><\/span><\/span>deforma\u00e7\u00e3o da mola em rela\u00e7\u00e3o \u00e0 posi\u00e7\u00e3o normal<\/b><\/span><\/span><\/span><\/p>\n

K\u00a0<\/b><\/span><\/span><\/span>\u00a0\u2014\u00a0 constante\u00a0<\/b><\/span><\/span><\/span>el\u00e1stica da mola\u00a0<\/b><\/span><\/span><\/span>medida no SI em N\/m<\/b><\/span><\/span><\/span>, que \u00e9\u00a0<\/b><\/span><\/span><\/span>caracter\u00edstica de cada mola<\/b><\/span><\/span><\/span>\u00a0e que depende do material de que a mesma \u00e9 feita, do\u00a0n\u00famero de espiras, das dimens\u00f5es, etc.<\/b><\/span><\/span><\/span><\/p>\n

Hooke\u00a0<\/b><\/span><\/span><\/span>determinou\u00a0<\/b><\/span><\/span><\/span>experimentalmente que\u00a0<\/b><\/span><\/span><\/span>\u201cem regime de deforma\u00e7\u00e3o el\u00e1stica, a intensidade da for\u00e7a el\u00e1stica Fe\u00a0\u00e9 diretamente proporcional \u00e0 deforma\u00e7\u00e3o x\u201d,<\/b><\/span><\/span><\/span>\u00a0ou seja,<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Representando\u00a0<\/b><\/span><\/span><\/span>graficamente<\/b><\/span><\/span><\/span>\u00a0a express\u00e3o acima:<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

C\u00e1lculo da constante el\u00e1stica da mola utilizando quando x = 3 cm = 3.10<\/b><\/span><\/span><\/span>-2<\/b><\/span><\/span><\/sup><\/span> m, F = 60 N <\/b><\/span><\/span><\/span> <\/b><\/span><\/span><\/span>k = F\/x <\/b><\/span><\/span><\/span>=<\/b><\/span><\/span><\/span><\/p>\n

60\/3.10<\/b><\/span><\/span><\/span>-2<\/b><\/span><\/span><\/sup><\/span> = 20.10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> <\/b><\/span><\/span><\/span>k = 2000 N\/m.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Colocando o n\u00edvel zero de altura na posi\u00e7\u00e3o inicial,<\/b><\/span><\/span><\/span> com a <\/b><\/span><\/span><\/span>mola comprimida de x, a energia mec\u00e2nica (total) na posi\u00e7\u00e3o inicial ser\u00e1 E<\/b><\/span><\/span><\/span>mi<\/b><\/span><\/span><\/sub><\/span> = E<\/b><\/span><\/span><\/span>pgravitacional <\/b><\/span><\/span><\/sub><\/span>+ E<\/b><\/span><\/span><\/span>cin\u00e9tica<\/b><\/span><\/span><\/sub><\/span> + E<\/b><\/span><\/span><\/span>pel\u00e1stica<\/b><\/span><\/span><\/sub><\/span> <\/b>= m.g.h + mV<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + kx<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 = m.g.0 + m0<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 + kx<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 E<\/b><\/span><\/span><\/span>mi<\/b><\/span><\/span><\/sub><\/span> = 0 + 0 + kx<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 = 2000x<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 <\/b><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span>mi<\/b><\/span><\/span><\/sub><\/span> = 1000x<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Na <\/b><\/span><\/span><\/span>altura m\u00e1xima h = 5 m n\u00e3o existe mais energia potencial el\u00e1stica, a energia cin\u00e9tica \u00e9 zero (V = 0), e s\u00f3 existindo energia potencial gravitacional <\/b><\/span><\/span><\/span>e, a\u00ed a <\/b><\/span><\/span><\/span>energia mec\u00e2nica final ser\u00e1 E<\/b><\/span><\/span><\/span>mf<\/b><\/span><\/span><\/sub><\/span> = m.g.h<\/b><\/span><\/span><\/span> = 5.10.5 <\/b><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span>mf<\/b><\/span><\/span><\/sub><\/span> = 250 J.<\/b><\/span><\/span><\/span><\/p>\n

Pelo <\/b><\/span><\/span><\/span>teorema da conserva\u00e7\u00e3o da energia mec\u00e2nica E<\/b><\/span><\/span><\/span>mi<\/b><\/span><\/span><\/sub><\/span> = E<\/b><\/span><\/span><\/span>mf<\/b><\/span><\/span><\/sub><\/span> <\/b><\/span><\/span><\/span> 1000x<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 250 x<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 250\/1000 =<\/b><\/span><\/span><\/span><\/p>\n

0,25 x = <\/b><\/span><\/span><\/span> <\/b><\/span><\/span><\/span>x = 0,5 m = 50 cm.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

04-<\/span><\/span><\/span><\/p>\n

Gr\u00e1fico do Teorema de Stevin<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

\u00c1gua P<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = P<\/b><\/span><\/span><\/span>atm<\/b><\/span><\/span><\/sub><\/span> + d<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>.g.h<\/b><\/span><\/span><\/span> 1,5.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span> = 1.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span> + d<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span>.10.5 d<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = 0,5.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span>\/50 = 50.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\/50 <\/b><\/span><\/span><\/span><\/p>\n

d<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = 10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span> kg\/m<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

L\u00edquido P<\/b><\/span><\/span><\/span>L<\/b><\/span><\/span><\/sub><\/span> = P<\/b><\/span><\/span><\/span>atm<\/b><\/span><\/span><\/sub><\/span> + d<\/b><\/span><\/span><\/span>L<\/b><\/span><\/span><\/sub><\/span>.g.h <\/b><\/span><\/span><\/span> 1,4.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span> = 1.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span> + d<\/b><\/span><\/span><\/span>L<\/b><\/span><\/span><\/sub><\/span>.10.5 d<\/b><\/span><\/span><\/span>L<\/b><\/span><\/span><\/sub><\/span> = 0,4.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span>\/50 = 40.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\/50 <\/b><\/span><\/span><\/span><\/p>\n

d<\/b><\/span><\/span><\/span>L<\/b><\/span><\/span><\/sub><\/span> = 0,8.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span> kg\/m<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

d<\/b><\/span><\/span><\/span>L<\/b><\/span><\/span><\/sub><\/span>\/d<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> <\/b>= 0,8.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\/1.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span> <\/b><\/span><\/span><\/span>d<\/b><\/span><\/span><\/span>L<\/b><\/span><\/span><\/sub><\/span>\/d<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = 0,8.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

05-<\/span><\/span><\/span><\/p>\n

De gelo a \u2013 10 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 \u00e1gua a 0<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span> C <\/b><\/span><\/span><\/span> <\/b>quantidade de calor recebido pelo gelo de massa m<\/b><\/span><\/span><\/span>g<\/b><\/span><\/span><\/sub><\/span> = 200g para passar de – 10<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 0 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C<\/b><\/span><\/span><\/span> <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = m.c.(t \u2013 t<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span> = 200.0,5.(0 \u2013 ( -10)) = 100.10 <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 1000 cal.<\/b><\/span><\/span><\/span><\/p>\n

Fundindo gelo a 0<\/b><\/span><\/span><\/span> o<\/b><\/span><\/span><\/sup><\/span>C <\/b><\/span><\/span><\/span>(de gelo a 0 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 \u00e1gua a 0 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C) <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = m.L <\/b><\/span><\/span><\/span>= 200.80 <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = 16000 cal.<\/b><\/span><\/span><\/span><\/p>\n

De \u00e1gua a 0 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 \u00e1gua a t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> Q<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span> = m.c.(t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> \u2013 t<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>) <\/b><\/span><\/span><\/span>= 200.1.(t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> \u2013 0) <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span> = 200t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Quantidade de calor recebido pelo gelo para passar de – 10 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 \u00e1gua a t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> Q\u2019<\/b><\/span><\/span><\/span> <\/b>= 1000 + 16000 + 200t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> <\/b><\/span><\/span><\/span>Q\u2019 = 17000 + 200t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Calor retirado de m = 1000 g de \u00e1gua para passar de 20 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> Q\u2019\u2019 = m.c.(t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> \u2013 t<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>) = 1000.1.(t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> \u2013 20) <\/b><\/span><\/span><\/span>Q\u2019\u2019 = 1000t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> \u2013 20000. <\/b><\/span><\/span><\/span><\/p>\n

Pelo princ\u00edpio da conserva\u00e7\u00e3o da quantidade de calor Q\u2019 + Q\u2019\u2019 = 0 <\/b><\/span><\/span><\/span>17000 + 200t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> + 1000t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> \u2013 20000 = 0 1200t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> = 3000 t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> = 3000\/1200 <\/b><\/span><\/span><\/span> t<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> = 2,5 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

06-<\/span><\/span><\/span><\/p>\n

Como utilizar a equa\u00e7\u00e3o do dioptro-plano<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Sendo:<\/b><\/span><\/span><\/span><\/p>\n

d<\/b><\/span><\/span><\/span>i<\/b><\/span><\/span><\/sub><\/span>\u00a0<\/b><\/span><\/span><\/sub><\/span>\u00a0<\/b><\/span><\/span><\/span>dist\u00e2ncia vertical da imagem \u00e0 superf\u00edcie de separa\u00e7\u00e3o<\/b><\/span><\/span><\/span>\u00a0dos meios A e B\u00a0<\/b><\/span><\/span><\/span>(dist\u00e2ncia aparente, em que o observador enxerga a imagem)<\/b><\/span><\/span><\/span><\/p>\n

d<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/span>dist\u00e2ncia vertical do objeto, at\u00e9 a superf\u00edcie de separa\u00e7\u00e3o\u00a0<\/b><\/span><\/span><\/span>dos meios A e B.<\/b><\/span><\/span><\/span><\/p>\n

n<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/span>\u00edndice de refra\u00e7\u00e3o do meio onde est\u00e1 o observador\u00a0<\/b><\/span><\/span><\/span>(no caso, meio A)<\/b><\/span><\/span><\/span><\/p>\n

n<\/b><\/span><\/span><\/span>i<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/span>\u00edndice de refra\u00e7\u00e3o do meio onde est\u00e1 o objeto e a imagem<\/b><\/span><\/span><\/span>\u00a0(no caso, meio B)<\/b><\/span><\/span><\/span><\/p>\n

No caso do exerc\u00edcio:<\/b><\/span><\/span><\/span> <\/b>d<\/b><\/span><\/span><\/span>i<\/b><\/span><\/span><\/sub><\/span> = <\/b><\/span><\/span><\/span>20 cm; <\/b><\/span><\/span><\/span>n<\/b><\/span><\/span><\/span>i<\/b><\/span><\/span><\/sub><\/span> =<\/b><\/span><\/span><\/span> 1,5; <\/b><\/span><\/span><\/span>n<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> =<\/b><\/span><\/span><\/span> 1 e <\/b><\/span><\/span><\/span>d<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> =<\/b><\/span><\/span><\/span> ?<\/b><\/span><\/span><\/span><\/p>\n

d<\/b><\/span><\/span><\/span>i<\/b><\/span><\/span><\/sub><\/span>.n<\/b><\/span><\/span><\/span>i<\/b><\/span><\/span><\/sub><\/span> = d<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.n<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> <\/b><\/span><\/span><\/span> 20.1,5 = d<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.1 <\/b><\/span><\/span><\/span>d<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 30 cm.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

07-<\/span><\/span><\/span><\/p>\n

Caracter\u00edsticas do Vetor Campo El\u00e9trico<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Como as <\/b><\/span><\/span><\/span>for\u00e7as que agem sobre ela s\u00e3o seu peso de intensidade P = mg <\/b><\/span><\/span><\/span>(vertical e para baixo), <\/b><\/span><\/span><\/span>para que a carga sujeita apenas \u00e0 for\u00e7a el\u00e9trica fique em repouso essa for\u00e7a el\u00e9trica de intensidade F<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> = qE deve obrigatoriamente ter <\/b><\/span><\/span><\/span>dire\u00e7\u00e3o vertical e sentido para cima.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

F<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> = P qE = mg E = mg\/q.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

<\/a><\/p>\n

Clique aqui para ver sobre o tema!<\/a><\/p>\n

Confira as v\u00eddeo aulas!<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Termomec\u00e2nica \u2013 meio do ano \u2013 2019\/2020 Faculdade de Tecnologia Termomecanica Na Faculdade de Tecnologia Termomecanica, o aluno recebe gratuitamente um curso que corresponde a um investimento financeiro anual por aluno de quase R$ 25 mil. Al\u00e9m do modelo de educa\u00e7\u00e3o inovador e gratuito, que inclui forma\u00e7\u00e3o humanista, todos os universit\u00e1rios recebem gratuitamente uniformes e alimenta\u00e7\u00e3o balanceada. A FTT ainda<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":4337,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-4782","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4782","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=4782"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4782\/revisions"}],"predecessor-version":[{"id":10088,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4782\/revisions\/10088"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4337"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=4782"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}