{"id":4736,"date":"2019-09-10T11:06:52","date_gmt":"2019-09-10T11:06:52","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=4736"},"modified":"2024-07-11T11:50:49","modified_gmt":"2024-07-11T11:50:49","slug":"utfpr-2019","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2019\/utfpr-2019\/","title":{"rendered":"UTFPR 2019"},"content":{"rendered":"

UTFPR-PR-2019<\/span><\/span><\/span><\/p>\n

<\/p>\n

A\u00a0<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0(<\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span>) \u00e9 uma\u00a0universidade p\u00fablica<\/a>\u00a0mantida pelo governo federal e sua sede esta localizada na cidade de\u00a0Curitiba<\/a>, capital do estado\u00a0brasileiro<\/a>\u00a0do\u00a0Paran\u00e1<\/a>. As bases da institui\u00e7\u00e3o decorrem do antigo\u00a0<\/b><\/span><\/span><\/span>Centro Federal de Educa\u00e7\u00e3o Tecnol\u00f3gica do Paran\u00e1<\/b><\/i><\/span><\/span><\/span>\u00a0(CEFET-PR).<\/b><\/span><\/span><\/span><\/p>\n

A institui\u00e7\u00e3o abrange cursos t\u00e9cnicos integrados e o ensino superior, oferecendo diversos cursos: Bacharelados, Licenciaturas e Tecnol\u00f3gicos, no qual muitos acad\u00eamicos podem estender sua forma\u00e7\u00e3o para Mestrados e Doutorados em diversas \u00e1reas de conhecimento.\u00a0\u00a0Obteve a melhor avalia\u00e7\u00e3o dentre as institui\u00e7\u00f5es federais de ensino superior do Paran\u00e1 segundo o IGC divulgado em 2013 e 2014, este consistindo em um indicador de qualidade criado pelo MEC que avalia as institui\u00e7\u00f5es com base na m\u00e9dia ponderada das notas dos cursos de gradua\u00e7\u00e3o e p\u00f3s-gradua\u00e7\u00e3o de cada institui\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

A UTFPR conta com treze c\u00e2mpus no Estado do Paran\u00e1, nas cidades de:\u00a0Apucarana<\/a>,\u00a0Campo Mour\u00e3o<\/a>,\u00a0Corn\u00e9lio Proc\u00f3pio<\/a>,\u00a0Curitiba<\/a>\u00a0(dividido nas sedes Centro e Ecoville),\u00a0Dois Vizinhos<\/a>,\u00a0Francisco Beltr\u00e3o<\/a>,\u00a0Guarapuava<\/a>,\u00a0Londrina<\/a>,\u00a0Medianeira<\/a>,\u00a0Ponta Grossa<\/a>,\u00a0Pato Branco<\/a>,\u00a0Toledo<\/a>\u00a0e\u00a0Santa Helena<\/a>.<\/b><\/span><\/span><\/span><\/p>\n

01- (<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Toda grandeza f\u00edsica pode ser expressa matematicamente, em fun\u00e7\u00e3o de outras grandezas f\u00edsicas,<\/b><\/span><\/span><\/span> atrav\u00e9s da <\/b><\/span><\/span><\/span>f\u00f3rmula dimensional. <\/b><\/span><\/span><\/span>Utilizando-se dos <\/b><\/span><\/span><\/span>s\u00edmbolos dimensionais das grandezas fundamentais do S.I., determine a f\u00f3rmula dimensional da grandeza f\u00edsica pot\u00eancia.<\/b><\/span><\/span><\/span><\/p>\n

A <\/b><\/span><\/span><\/span>alternativa correta \u00e9:<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span><\/span>M.L.T<\/b><\/span><\/span><\/span><\/span>\u2013 1<\/b><\/span><\/span><\/span><\/sup><\/span><\/p>\n

B) <\/b><\/span><\/span><\/span><\/span>M.L<\/b><\/span><\/span><\/span><\/span>\u20132<\/b><\/span><\/span><\/span><\/sup><\/span>.T<\/b><\/span><\/span><\/span><\/span>\u2013 3<\/b><\/span><\/span><\/span><\/sup><\/span><\/p>\n

C) <\/b><\/span><\/span><\/span><\/span>M<\/b><\/span><\/span><\/span><\/span>\u20131<\/b><\/span><\/span><\/span><\/sup><\/span>.L<\/b><\/span><\/span><\/span><\/span>3<\/b><\/span><\/span><\/span><\/sup><\/span>.T<\/b><\/span><\/span><\/span><\/span>\u2013 2<\/b><\/span><\/span><\/span><\/sup><\/span><\/p>\n

D) <\/b><\/span><\/span><\/span>M.L<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.T<\/b><\/span><\/span><\/span>\u2013 3<\/b><\/span><\/span><\/sup><\/span><\/p>\n

E) <\/b><\/span><\/span><\/span>M.L.T<\/b><\/span><\/span><\/span>\u2013 2<\/b><\/span><\/span><\/sup><\/span><\/p>\n

02- (<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Um <\/b><\/span><\/span><\/span>ladr\u00e3o tenta fugir carregando uma mala cheia de barras de ouro.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Considerando a <\/b><\/span><\/span><\/span>densidade do ouro aproximadamente igual a 20 g\/cm<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>, g = 10 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> e o <\/b><\/span><\/span><\/span>volume ocupado pelas barras de ouro igual a 48 dm<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>, o peso, em N, da mala teria um valor num\u00e9rico <\/b><\/span><\/span><\/span>pr\u00f3ximo de:<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span>24.000. <\/b><\/span><\/span><\/span>B) <\/b><\/span><\/span><\/span>960. <\/b><\/span><\/span><\/span>C) <\/b><\/span><\/span><\/span>9.600.<\/b><\/span><\/span><\/span> <\/b>D) <\/b><\/span><\/span><\/span>96.000. <\/b><\/span><\/span><\/span>E) <\/b><\/span><\/span><\/span>2.400.<\/b><\/span><\/span><\/span><\/p>\n

03- (<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Um jogador de futebol chuta uma bola de 400 g, inicialmente em repouso<\/b><\/span><\/span><\/span>, e ela <\/b><\/span><\/span><\/span>sai com uma <\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

velocidade de 72 km\/h.<\/b><\/span><\/span><\/span> O <\/b><\/span><\/span><\/span>tempo de contato entre o p\u00e9 do jogador e a bola \u00e9 de 0,02 s. Calcule a for\u00e7a m\u00e9dia aplicada pelo p\u00e9 do jogador sobre a bola.<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span>10 kgf <\/b><\/span><\/span><\/span>B) <\/b><\/span><\/span><\/span>400 N<\/b><\/span><\/span><\/span> <\/b>C) <\/b><\/span><\/span><\/span>20 kgf <\/b><\/span><\/span><\/span>D) <\/b><\/span><\/span><\/span>144 N <\/b><\/span><\/span><\/span>E) <\/b><\/span><\/span><\/span>28.8 N<\/b><\/span><\/span><\/span><\/p>\n

04- (<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Uma <\/b><\/span><\/span><\/span>crian\u00e7a de 30 kg brinca de patins com seu pai de 70 kg<\/b><\/span><\/span><\/span>. O <\/b><\/span><\/span><\/span>pai est\u00e1 patinando com uma velocidade 0,50 m\/s e a crian\u00e7a com 2,0 m\/s, um em dire\u00e7\u00e3o ao outro. <\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Ao <\/b><\/span><\/span><\/span>encontrar a crian\u00e7a, o pai a segura.<\/b><\/span><\/span><\/span> O que <\/b><\/span><\/span><\/span>acontece fisicamente com os dois logo depois do abra\u00e7o, supondo que o pai continue segurando a crian\u00e7a nos bra\u00e7os e que mantenha o equil\u00edbrio. (Desconsidere o atrito).<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span>Os dois adquirem uma velocidade de 0,35 m\/s no mesmo sentido da velocidade da crian\u00e7a antes da colis\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

B) <\/b><\/span><\/span><\/span>Os dois adquirem uma velocidade de 0,95 m\/s no mesmo sentido da velocidade do pai antes da colis\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

C) <\/b><\/span><\/span><\/span>Os dois adquirem uma velocidade de 1,4 m\/s no mesmo sentido da velocidade do pai antes da colis\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

D) <\/b><\/span><\/span><\/span>Os dois adquirem uma velocidade de 3,2 m\/s no mesmo sentido da velocidade da crian\u00e7a antes da colis\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

E) <\/b><\/span><\/span><\/span>Os dois adquirem uma velocidade de 0,25 m\/s no mesmo sentido da velocidade da crian\u00e7a antes da colis\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

05- (<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

O <\/b><\/span><\/span><\/span>diagrama a seguir representa a transforma\u00e7\u00e3o c\u00edclica termodin\u00e2mica sofrida por uma massa gasosa:<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

De acordo com o digrama \u00e9 correto afirmar que:<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span>se o ciclo for percorrido em sentido hor\u00e1rio, h\u00e1 convers\u00e3o de calor em trabalho.<\/b><\/span><\/span><\/span><\/p>\n

B) <\/b><\/span><\/span><\/span>ao passar de D para A, o trabalho realizado pelo g\u00e1s \u00e9 positivo.<\/b><\/span><\/span><\/span><\/p>\n

C) <\/b><\/span><\/span><\/span>ao passar de B para C, o trabalho realizado pelo g\u00e1s \u00e9 positivo.<\/b><\/span><\/span><\/span><\/p>\n

D) <\/b><\/span><\/span><\/span>a quantidade de calor recebida pelo g\u00e1s \u00e9 numericamente igual \u00e0 \u00e1rea do quadril\u00e1tero ABCD.<\/b><\/span><\/span><\/span><\/p>\n

E) <\/b><\/span><\/span><\/span>se o ciclo for percorrido em sentido hor\u00e1rio, o sistema realiza trabalho sobre o g\u00e1s.<\/b><\/span><\/span><\/span><\/p>\n

06- (<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Um <\/b><\/span><\/span><\/span>oscilador massa-mola executa um movimento harm\u00f4nico simples com amplitude de 10,0 cm e energia mec\u00e2nica representada por E.<\/b><\/span><\/span><\/span> <\/b><\/p>\n

<\/p>\n

Quando<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span><\/span>elonga\u00e7\u00e3o do movimento for igual a 8,0 cm<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span><\/span>energia cin\u00e9tica do movimento<\/b><\/span><\/span><\/span> ser\u00e1 igual a:<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span>20% de E.<\/b><\/span><\/span><\/span><\/p>\n

B) <\/b><\/span><\/span><\/span>28% de E.<\/b><\/span><\/span><\/span><\/p>\n

C) <\/b><\/span><\/span><\/span>36% de E.<\/b><\/span><\/span><\/span><\/p>\n

D) <\/b><\/span><\/span><\/span>72% de E.<\/b><\/span><\/span><\/span><\/p>\n

E) <\/b><\/span><\/span><\/span>64% de E.<\/b><\/span><\/span><\/span><\/p>\n

07- (<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Ao <\/b><\/span><\/span><\/span>montar uma loja de roupas, um comerciante deseja colocar um espelho plano que tenha a menor altura poss\u00edvel, mas que seja capaz de fornecer uma imagem por inteiro da maioria de seus clientes<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Supondo que <\/b><\/span><\/span><\/span>seus clientes possuam uma altura m\u00e9dia de 1,70 m<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>o mais indicado para o comerciante \u00e9 comprar um espelho que tenha uma altura, em m, <\/b><\/span><\/span><\/span>igual a:<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span>0,90. <\/b><\/span><\/span><\/span>B) <\/b><\/span><\/span><\/span>0,80.<\/b><\/span><\/span><\/span> <\/b>C) <\/b><\/span><\/span><\/span>1,70.<\/b><\/span><\/span><\/span> <\/b>D) <\/b><\/span><\/span><\/span>0,75.<\/b><\/span><\/span><\/span> <\/b>E) <\/b><\/span><\/span><\/span>0,60.<\/b><\/span><\/span><\/span><\/p>\n

08- (<\/b><\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Tr\u00eas l\u00e2mpadas id\u00eanticas s\u00e3o instaladas em s\u00e9rie conforme figura abaixo:<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Sobre esta associa\u00e7\u00e3o \u00e9 correto afirmar que:<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span>a pot\u00eancia dissipada em cada l\u00e2mpada \u00e9 a mesma, consequentemente o brilho de cada l\u00e2mpada seria o mesmo se ela estivesse sozinha no circuito.<\/b><\/span><\/span><\/span><\/p>\n

B) <\/b><\/span><\/span><\/span>a l\u00e2mpada 1 apresenta uma queda de tens\u00e3o maior do que a l\u00e2mpada 3.<\/b><\/span><\/span><\/span><\/p>\n

C) <\/b><\/span><\/span><\/span>as tr\u00eas l\u00e2mpadas est\u00e3o associadas em s\u00e9rie. Este tipo de associa\u00e7\u00e3o \u00e9 utilizado para as l\u00e2mpadas das instala\u00e7\u00f5es residenciais.<\/b><\/span><\/span><\/span><\/p>\n

D) <\/b><\/span><\/span><\/span>a corrente el\u00e9trica da l\u00e2mpada 3 \u00e9 maior que a da l\u00e2mpada 2.<\/b><\/span><\/span><\/span><\/p>\n

E) <\/b><\/span><\/span><\/span>como a tens\u00e3o em cada l\u00e2mpada \u00e9 <\/b><\/span><\/span><\/span>sempre menor que a dos terminais<\/b><\/span><\/span><\/span> da associa\u00e7\u00e3o, o brilho de cada l\u00e2mpada \u00e9 menor do que se ela estivesse sozinha no circuito.<\/b><\/span><\/span><\/span><\/p>\n

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00edsica da <\/span><\/span><\/span>Universidade Tecnol\u00f3gica Federal do Paran\u00e1<\/b><\/span><\/span><\/span>\u00a0\u2013 <\/b><\/span><\/span><\/span>UTFPR<\/b><\/span><\/span><\/span> \u2013 2019<\/b><\/span><\/span><\/span><\/p>\n

01-<\/span><\/span><\/span><\/p>\n

<\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

02-<\/span><\/span><\/span><\/p>\n

<\/p>\n

R \u2013 C<\/b><\/span><\/span><\/span><\/p>\n

03-<\/span><\/span><\/span><\/p>\n

<\/p>\n

S\u00e3o dados: m <\/b><\/span><\/span><\/span>= 400 g <\/b><\/span><\/span><\/span>= 0,4 kg<\/b><\/span><\/span><\/span>; <\/b><\/span><\/span><\/span>V <\/b><\/span><\/span><\/span>= 72 km\/h\/3,6 <\/b><\/span><\/span><\/span>= 20 m\/s<\/b><\/span><\/span><\/span>; <\/b><\/span><\/span><\/span>\u2206t = 0,02 s e F = ?<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

04-<\/span><\/span><\/span><\/p>\n

Trata-se de <\/b><\/span><\/span><\/span>uma colis\u00e3o e deve-se utilizar o princ\u00edpio da conserva\u00e7\u00e3o da quantidade de movimento<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Observe que <\/b><\/span><\/span><\/span>o m\u00f3dulo da quantidade de movimento do filho antes da colis\u00e3o \u00e9 maior que a do pai <\/b><\/span><\/span><\/span> <\/b>Q<\/b><\/span><\/span><\/span>pai<\/b><\/span><\/span><\/sub><\/span> <\/b>= m<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>V<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span> = 70.0,5 <\/b><\/span><\/span><\/span>= 35 kg.m\/s <\/b><\/span><\/span><\/span>e <\/b><\/span><\/span><\/span>Q<\/b><\/span><\/span><\/span>filho<\/b><\/span><\/span><\/sub><\/span> = m<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>.V<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span> = 30.2 <\/b><\/span><\/span><\/span>= 60 kg.m\/s<\/b><\/span><\/span><\/span>. e, assim o <\/b><\/span><\/span><\/span>movimento depois da colis\u00e3o \u00e9 no sentido da velocidade do filho, para a esquerda (figura abaixo)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Q<\/b><\/span><\/span><\/span>sap<\/b><\/span><\/span><\/sub><\/span> = m<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>V<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span> <\/b>= 70.0,5 <\/b><\/span><\/span><\/span>= 35 kg.m\/s <\/b><\/span><\/span><\/span> <\/b>Q<\/b><\/span><\/span><\/span>saf<\/b><\/span><\/span><\/sub><\/span> = m<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>.V<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span> <\/b>= 30.(-2) <\/b><\/span><\/span><\/span>= – 60 kg.m\/s.<\/b><\/span><\/span><\/span><\/p>\n

Quantidade de movimento do sistema antes da colis\u00e3o Q<\/b><\/span><\/span><\/span>sa<\/b><\/span><\/span><\/sub><\/span> <\/b>= 35 \u2013 60 <\/b><\/span><\/span><\/span>= – 25 kg.m\/s. <\/b><\/span><\/span><\/span><\/p>\n

Quantidade de movimento do sistema depois da colis\u00e3o quando ambos de massa M <\/b><\/span><\/span><\/span>= 70 + 30 = <\/b><\/span><\/span><\/span>100 kg se movem juntos para a esquerda com velocidade V\u2019 Q<\/b><\/span><\/span><\/span>sd<\/b><\/span><\/span><\/sub><\/span> = M.(-V\u2019) <\/b><\/span><\/span><\/span>= -100V\u2019.<\/b><\/span><\/span><\/span><\/p>\n

Q<\/b><\/span><\/span><\/span>sa<\/b><\/span><\/span><\/sub><\/span> = Q<\/b><\/span><\/span><\/span>sd<\/b><\/span><\/span><\/sub><\/span> <\/b><\/span><\/span><\/span> -25 = – 100V\u2019 <\/b><\/span><\/span><\/span>V\u2019 = 25\/100 = 0,25 m\/s (para a esquerda).<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

05-<\/span><\/span><\/span><\/p>\n

Primeiro princ\u00edpio da termodin\u00e2mica aplicado numa\u00a0<\/b><\/span><\/span><\/span>transforma\u00e7\u00e3o C\u00edclica<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

A <\/b><\/span><\/span>alternativa correta \u00e9 a (A) <\/b><\/span><\/span>conforme <\/b><\/span><\/span>as informa\u00e7\u00f5es acima<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

06-<\/span><\/span><\/span><\/p>\n

Energia no MHS no plano horizontal<\/span><\/span><\/span><\/p>\n

<\/p>\n

C\u00e1lculo da energia mec\u00e2nica que \u00e9 constante quando a elonga\u00e7\u00e3o \u00e9 m\u00e1xima A <\/b><\/span><\/span><\/span>= 10 cm = 10.10<\/b><\/span><\/span><\/span>-2<\/b><\/span><\/span><\/sup><\/span> = <\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

07-<\/span><\/span><\/span><\/p>\n

Se voc\u00ea n\u00e3o domina a teoria, ela est\u00e1 a seguir:<\/b><\/span><\/span><\/span><\/p>\n

C\u00e1lculo da altura de um espelho plano vertical para que, a partir do ch\u00e3o, uma pessoa possa ver-se de corpo inteiro, desde a cabe\u00e7a at\u00e9 os p\u00e9s.<\/b><\/span><\/span><\/span><\/p>\n

Localizar a imagem\u00a0<\/b><\/span><\/span><\/span>da pessoa que fica\u00a0<\/b><\/span><\/span><\/span>atr\u00e1s do espelho pelos seus pontos extremos AA\u2019<\/b><\/span><\/span><\/span>(superior) e<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

BB\u2019<\/b><\/span><\/span><\/span>\u00a0(inferior).<\/b><\/span><\/span><\/span><\/p>\n

Em seguida\u00a0<\/b><\/span><\/span><\/span>ligar, com linha pontilhada, A\u2019 e B\u2019 ao olho da pessoa objeto<\/b><\/span><\/span><\/span>, que\u00a0<\/b><\/span><\/span><\/span>interceptam<\/b><\/span><\/span><\/span>o espelho<\/b><\/span><\/span><\/span><\/p>\n

nos\u00a0<\/b><\/span><\/span><\/span>pontos M<\/b><\/span><\/span><\/span>\u00a0(inferior) e\u00a0<\/b><\/span><\/span><\/span>N\u00a0<\/b><\/span><\/span><\/span>(superior), que\u00a0<\/b><\/span><\/span><\/span>delimitam o tamanho m\u00ednimo do espelho\u00a0<\/b><\/span><\/span><\/span>para que a\u00a0<\/b><\/span><\/span><\/span>pessoa possa ver-se de corpo inteiro no mesmo.<\/b><\/span><\/span><\/span>\"UTFPR\"<\/p>\n

Observe que os\u00a0<\/b><\/span><\/span><\/span>tri\u00e2ngulos OMN e OB\u2019A\u2019\u00a0<\/b><\/span><\/span><\/span>s\u00e3o\u00a0<\/b><\/span><\/span><\/span>semelhantes<\/b><\/span><\/span><\/span>\u00a0e\u00a0<\/b><\/span><\/span><\/span>dessa semelhan\u00e7a tiramos o <\/b><\/span><\/span><\/span>tamanho m\u00ednimo do espelho MN\u00a0\u00a0<\/b><\/span><\/span><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/span>H\/MN = 2d\/d\u00a0\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>MN = H\/2\u00a0<\/b><\/span><\/span><\/span>\u00a0(o\u00a0<\/b><\/span><\/span><\/span>tamanho m\u00ednimo do espelho\u00a0<\/b><\/span><\/span><\/span>para que a\u00a0<\/b><\/span><\/span><\/span>pessoa se veja de corpo inteiro deve ter a metade da altura da pessoa).<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span><\/p>\n

Importante:<\/b><\/span><\/span><\/span>\u00a0Observe que a\u00a0<\/b><\/span><\/span><\/span>altura m\u00ednima do espelho \u00e9 sempre a mesma independente do fato de a pessoa estar a uma dist\u00e2ncia d, 2d, 3d, etc. do espelho<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Assim, a\u00a0<\/b><\/span><\/span><\/span>imagem da pessoa encontra-se ajustada ao tamanho do espelho independente da dist\u00e2ncia a que ela se encontra do mesmo<\/b><\/span><\/span><\/span>, mas, \u00e0\u00a0<\/b><\/span><\/span><\/span>medida que a pessoa se afasta do espelho<\/b><\/span><\/span><\/span>, sua <\/b><\/span><\/span><\/span>imagem<\/b><\/span><\/span><\/span><\/p>\n

tamb\u00e9m se afasta dando a impress\u00e3o<\/b><\/span><\/span><\/span>, devido ao\u00a0<\/b><\/span><\/span><\/span>\u00e2ngulo visual, que ela parece menor, mas continua sempre ajustada ao tamanho do espelho.<\/b><\/span><\/span><\/span><\/p>\n

No caso do exerc\u00edcio h<\/b><\/span><\/span><\/span> = 1,70\/2 <\/b><\/span><\/span><\/span>= 0,85 m<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

08-<\/span><\/span><\/span><\/p>\n

A. Falsa <\/b><\/span><\/span><\/span> a <\/b><\/span><\/span><\/span>pot\u00eancia \u00e9 fun\u00e7\u00e3o do valor da resist\u00eancia el\u00e9tr<\/b><\/span><\/span><\/span>ica e, <\/b><\/span><\/span><\/span>como a corrente i \u00e9 a mesma<\/b><\/span><\/span><\/span>, para <\/b><\/span><\/span><\/span>uma l\u00e2mpada a pot\u00eancia ser\u00e1 P<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = R.i<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> <\/b>e <\/b><\/span><\/span><\/span>para as tr\u00eas P<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span> = 3Ri<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>. <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span> > P<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

B. Falsa veja (A).<\/b><\/span><\/span><\/span><\/p>\n

C. Falsa nas instala\u00e7\u00f5es residenciais a associa\u00e7\u00e3o utilizada \u00e9 a paralelo (mesma tens\u00e3o, ddp ou voltagem U).<\/b><\/span><\/span><\/span><\/p>\n

D. Falsa uma das caracter\u00edsticas da associa\u00e7\u00e3o s\u00e9rie \u00e9 de que a corrente i \u00e9 a mesma.<\/b><\/span><\/span><\/span><\/p>\n

E. Correta;<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Clique aqui para ver sobre o tema!<\/a><\/p>\n

Confira as v\u00eddeo aulas!<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

UTFPR-PR-2019 A\u00a0Universidade Tecnol\u00f3gica Federal do Paran\u00e1\u00a0(UTFPR) \u00e9 uma\u00a0universidade p\u00fablica\u00a0mantida pelo governo federal e sua sede esta localizada na cidade de\u00a0Curitiba, capital do estado\u00a0brasileiro\u00a0do\u00a0Paran\u00e1. As bases da institui\u00e7\u00e3o decorrem do antigo\u00a0Centro Federal de Educa\u00e7\u00e3o Tecnol\u00f3gica do Paran\u00e1\u00a0(CEFET-PR). A institui\u00e7\u00e3o abrange cursos t\u00e9cnicos integrados e o ensino superior, oferecendo diversos cursos: Bacharelados, Licenciaturas e Tecnol\u00f3gicos, no qual muitos acad\u00eamicos podem estender sua<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":4337,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-4736","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4736","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=4736"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4736\/revisions"}],"predecessor-version":[{"id":10293,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4736\/revisions\/10293"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4337"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=4736"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}