{"id":4730,"date":"2019-09-10T10:57:07","date_gmt":"2019-09-10T10:57:07","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=4730"},"modified":"2024-07-11T03:02:22","modified_gmt":"2024-07-11T03:02:22","slug":"etec-sp-2019","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2019\/etec-sp-2019\/","title":{"rendered":"ETEC SP 2019"},"content":{"rendered":"

ETEC-SP-2019<\/span><\/span><\/span><\/p>\n

<\/a> <\/p>\n

As\u00a0<\/b><\/span><\/span><\/span>Escolas T\u00e9cnicas Estaduais<\/b><\/span><\/span><\/span>\u00a0(<\/b><\/span><\/span><\/span>ETECs<\/b><\/span><\/span><\/span>) s\u00e3o\u00a0institui\u00e7\u00f5es<\/a>\u00a0de ensinos t\u00e9cnico, m\u00e9dio e t\u00e9cnico integrado ao m\u00e9dio (ETIM), pertencentes ao\u00a0Centro Estadual de Educa\u00e7\u00e3o Tecnol\u00f3gica Paula Souza<\/a>\u00a0(CEETEPS), autarquia da\u00a0Secretaria de Desenvolvimento Econ\u00f4mico, Ci\u00eancia e Tecnologia<\/a>\u00a0(SDECTI) do estado de\u00a0S\u00e3o Paulo<\/a>.<\/b><\/span><\/span><\/span><\/p>\n

O Centro Paula Souza mant\u00e9m uma parceria com a Secretaria de Educa\u00e7\u00e3o e prefeituras dos munic\u00edpios paulistas para oferecer cursos t\u00e9cnicos em salas de aulas que n\u00e3o est\u00e3o em uso em Escolas Estaduais e Escolas Municipais no per\u00edodo noturno.<\/b><\/span><\/span><\/span><\/p>\n

Para ingressar numa Etec, o candidato deve passar por um\u00a0<\/b><\/span><\/span><\/span>vestibulinho<\/b><\/i><\/span><\/span><\/span>, processo seletivo aplicado para quem pretende estudar em Escolas T\u00e9cnicas Estaduais. As Etecs possuem o “Sistema de Pontua\u00e7\u00e3o Acrescida”, no qual os candidatos que se declararem afro\u2013descendentes recebem 3% de b\u00f4nus sobre a nota, e aqueles que cursaram o ensino fundamental integralmente em escola p\u00fablica ganham 10%, percentuais que s\u00e3o cumulativos.<\/b><\/span><\/span><\/span>[2]<\/b><\/span><\/span><\/sup><\/span><\/a><\/p>\n

Das 50 escolas estaduais mais bem classificadas no ENEM no Estado de S\u00e3o Paulo, 44 s\u00e3o Etecs. A Etec de S\u00e3o Paulo (Etesp) \u00e9 a melhor escola estadual paulista. No ranking nacional, \u00e9 a 2\u00aa entre as estaduais e na capital, est\u00e1 em 17\u00ba lugar entre p\u00fablicas e privadas, \u00e0 frente de col\u00e9gios particulares tradicionais.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

CURSOS T\u00c9CNICOS<\/span><\/span><\/span><\/p>\n

01- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

O <\/b><\/span><\/span><\/span>Electrophorus electricus<\/b><\/i><\/span><\/span><\/span>, popularmente conhecido por poraqu\u00ea ou treme-treme, <\/b><\/span><\/span><\/span>\u00e9 um <\/b><\/span><\/span><\/span>peixe carn\u00edvoro de agua doce encontrado na Bacia Amaz\u00f4nica.<\/b><\/span><\/span><\/span><\/p>\n

Esse peixe <\/b><\/span><\/span><\/span>\u00e9 capaz de liberar uma forte descarga el\u00e9trica, imobilizando e at\u00e9 matando suas presas ou agressores.<\/b><\/span><\/span><\/span> Isso \u00e9 poss\u00edvel porque, <\/b><\/span><\/span><\/span>logo apos sua cabe\u00e7a, estende-se uma serie de c\u00e9lulas, conectadas entre si, ate a cauda. <\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Essa <\/b><\/span><\/span><\/span>serie de c\u00e9lulas permite que a cabe\u00e7a desse peixe tenha carga positiva enquanto a extremidade de sua cauda tenha carga negativa.<\/b><\/span><\/span><\/span><\/p>\n

Assinale a <\/b><\/span><\/span><\/span>alternativa que apresenta um objeto do cotidiano que tem caracter\u00edsticas compar\u00e1veis as desse peixe.<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>Autofalante<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>Motor el\u00e9trico<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>Bateria de carro<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>Ferro de passar roupas<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>L\u00e2mpada incandescente<\/b><\/span><\/span><\/span><\/p>\n

02- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Os <\/b><\/span><\/span><\/span>estudos de hidrost\u00e1tica <\/b><\/span><\/span><\/span>de Arquimedes (288\u2013212 a.C.) o <\/b><\/span><\/span><\/span>levaram a conclus\u00e3o de que corpos imersos em um liquido, total ou parcialmente, sofrem a a\u00e7\u00e3o de uma forca vertical, voltada para cima, denominada empuxo. <\/b><\/span><\/span><\/span><\/p>\n

Devido <\/b><\/span><\/span><\/span>\u00e0s caracter\u00edsticas dessa forca, o empuxo op\u00f5e-se a a\u00e7\u00e3o do peso, que atua sobre todos os corpos.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Quando um <\/b><\/span><\/span><\/span>corpo se encontra totalmente submerso, a rela\u00e7\u00e3o entre a forca peso e a forca de empuxo reduz-se a um confronto entre densidades: a do corpo e a do liquido no qual ele se encontra submerso.<\/b><\/span><\/span><\/span><\/p>\n

Para obter o empuxo necess\u00e1rio, alguns peixes \u00f3sseos possuem um \u00f3rg\u00e3o denominado bexiga natat\u00f3ria que os auxilia no controle de sua flutua\u00e7\u00e3o sem o auxilio de suas nadadeiras, devido a presen\u00e7a de g\u00e1s em seu interior. <\/b><\/span><\/span><\/span><\/p>\n

Quando um <\/b><\/span><\/span><\/span>peixe desse tipo apresenta problemas na bexiga natat\u00f3ria <\/b><\/span><\/span><\/span>e <\/b><\/span><\/span><\/span>n\u00e3o consegue manter o g\u00e1s aprisionado,<\/b><\/span><\/span><\/span> <\/b>ter\u00e1 dificuldades em manter-se a uma mesma profundidade <\/b><\/span><\/span><\/span>e tamb\u00e9m em <\/b><\/span><\/span><\/span>aproximar-se da superf\u00edcie, tendendo a ficar no fundo.<\/b><\/span><\/span><\/span><\/p>\n

Para o peixe, nessas condi\u00e7\u00f5es, podemos concluir corretamente <\/b><\/span><\/span><\/span>que o<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>seu peso e nulo.<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>empuxo e nulo.<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>empuxo e maior que seu peso.<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>empuxo e igual ao seu peso.<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>empuxo e menor que seu peso.<\/b><\/span><\/span><\/span><\/p>\n

03- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

\u00c9 surpreendente como a vida pode ocorrer mesmo em locais in\u00f3spitos<\/b><\/span><\/span><\/span> como, por exemplo, nas <\/b><\/span><\/span><\/span>fossas das Marianas, grande depress\u00e3o oce\u00e2nica localizada na fronteira entre as placas tect\u00f4nicas do Pacifico e das Filipinas. <\/b><\/span><\/span><\/span><\/p>\n

Nesse local, o leito oce\u00e2nico atinge cerca de 11 000 metros de profundidade. <\/b><\/span><\/span><\/span><\/p>\n

A <\/b><\/span><\/span><\/span>press\u00e3o e t\u00e3o grande que os seres que l\u00e1 habitam tiveram de desenvolver condi\u00e7\u00f5es especiais<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

para sua sobreviv\u00eancia, o que torna imposs\u00edvel traze-los vivos para a superf\u00edcie.<\/b><\/span><\/span><\/span><\/p>\n

Considerando que para cada 10 metros de profundidade sob a agua, a press\u00e3o e acrescida de 1 atm, <\/b><\/span><\/span><\/span>e <\/b><\/span><\/span><\/span>correto afirmar que a press\u00e3o total suportada pelos seres que vivem no fundo das fossas das Marianas equivale a <\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

(A) <\/b><\/span><\/span><\/span>110 atm. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>111 atm. (C) 1 100 atm. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>1 101 atm. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>1 110 atm.<\/b><\/span><\/span><\/span><\/p>\n

04- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

O <\/b><\/span><\/span><\/span>acidente nuclear de Chernobyl foi respons\u00e1vel por uma serie de modifica\u00e7\u00f5es na biodiversidade<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

local, quando espalhou pela regi\u00e3o grandes quantidades de material radioativo, <\/b><\/span><\/span><\/span>cuja <\/b><\/span><\/span><\/span>principal emiss\u00e3o consiste em ondas eletromagn\u00e9ticas com os menores comprimentos de onda e, portanto, maiores energias.<\/b><\/span><\/span><\/span> <\/b><\/p>\n

Uma das <\/b><\/span><\/span><\/span>modifica\u00e7\u00f5es da biodiversidade que chamou a aten\u00e7\u00e3o de pesquisadores foi a diminui\u00e7\u00e3o de muitas esp\u00e9cies de insetos.<\/b><\/span><\/span><\/span><\/p>\n

Ha <\/b><\/span><\/span><\/span>estudos<\/b><\/span><\/span><\/span> sobre <\/b><\/span><\/span><\/span>a esteriliza\u00e7\u00e3o de insetos machos do <\/b><\/span><\/span><\/span>Aedes aegypti <\/b><\/i><\/span><\/span><\/span>na esperan\u00e7a de atacar diretamente esse mosquito.<\/b><\/span><\/span><\/span><\/p>\n

Mosquitos machos s\u00e3o expostos a radia\u00e7\u00f5es semelhantes \u00e0s de Chernobyl, sofrendo modifica\u00e7\u00f5es criticas em seu material gen\u00e9tico, que inibem sua prolifera\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

A <\/b><\/span><\/span><\/span>figura apresenta o espectro das ondas eletromagn\u00e9ticas <\/b><\/span><\/span><\/span>e logo abaixo <\/b><\/span><\/span><\/span>a ordem de grandeza de seus comprimentos de onda em metros.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

De acordo com o texto, o tipo de radia\u00e7\u00e3o potencialmente capaz de combater o mosquito citado e<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>micro-ondas.<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>infravermelho.<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>ultravioleta.<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>raios X.<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>raios gama.<\/b><\/span><\/span><\/span><\/p>\n

05- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

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Segundo pesquisas, <\/b><\/span><\/span><\/span>na <\/b><\/span><\/span><\/span>historia do planeta Terra, <\/b><\/span><\/span><\/span>houve <\/b><\/span><\/span><\/span>cinco grandes eventos cujos impactos sobre a biodiversidade foram t\u00e3o devastadores que acarretaram extin\u00e7\u00f5es em massa, como a dos dinossauros.<\/b><\/span><\/span><\/span><\/p>\n

Suponha que <\/b><\/span><\/span><\/span>um desses epis\u00f3dios foi causado por um impacto com um asteroide de 15 km de di\u00e2metro, o que deixou em nosso planeta uma cratera de 200 km de di\u00e2metro.<\/b><\/span><\/span><\/span><\/p>\n

Considere que a <\/b><\/span><\/span><\/span>energia liberada pelo impacto de um asteroide \u00e9<\/b><\/span><\/span><\/span> <\/b>diretamente proporcional apenas ao cubo do di\u00e2metro da cratera formada.<\/b><\/span><\/span><\/span><\/p>\n

Assinale a express\u00e3o que relaciona corretamente a energia liberada E, no fen\u00f4meno descrito, <\/b><\/span><\/span><\/span>com o <\/b><\/span><\/span><\/span>di\u00e2metro do asteroide, na qual k representa a constante de proporcionalidade.<\/b><\/span><\/span><\/span><\/p>\n

(A) E = k \u2219 15<\/b><\/span><\/span><\/span><\/p>\n

(B) E = k \u2219 200<\/b><\/span><\/span><\/span><\/p>\n

(C) E = k \u2219 3 000<\/b><\/span><\/span><\/span><\/p>\n

(D) E = k \u2219 3 3750<\/b><\/span><\/span><\/span><\/p>\n

(E) E = k \u2219 8 000 000<\/b><\/span><\/span><\/span><\/p>\n

Especializa\u00e7\u00e3o – T\u00e9cnico em Mecatr\u00f4nica<\/b><\/span><\/span><\/span><\/p>\n

06- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

No <\/b><\/span><\/span><\/span>estudo da eletricidade, iniciam-se os estudos, considerando a condi\u00e7\u00e3o ideal para depois estudar<\/b><\/span><\/span><\/span><\/p>\n

a condi\u00e7\u00e3o real.<\/b><\/span><\/span><\/span> A <\/b><\/span><\/span><\/span>reta da curva caracter\u00edstica de um gerador el\u00e9trico real pode ser desenhada<\/b><\/span><\/span><\/span><\/p>\n

utilizando-se os pontos<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>A for\u00e7a eletromotriz (F<\/b><\/span><\/span><\/span>em<\/b><\/span><\/span><\/sub><\/span>) em Volts e a corrente de curto circuito (i<\/b><\/span><\/span><\/span>cc<\/b><\/span><\/span><\/sub><\/span>) em Amperes<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>A for\u00e7a eletromotriz (F<\/b><\/span><\/span><\/span>em<\/b><\/span><\/span><\/sub><\/span>) em Volts e a resist\u00eancia interna (r.i.) em Ohms<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>Resist\u00eancia interna (r.i.) em Ohms e a corrente de curto circuito (i<\/b><\/span><\/span><\/span>cc<\/b><\/span><\/span><\/sub><\/span>) em Amperes<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>Tens\u00e3o \u00fatil do gerador e a resist\u00eancia interna (r.i.) em Ohms<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>A corrente de curto circuito (i<\/b><\/span><\/span><\/span>cc<\/b><\/span><\/span><\/sub><\/span>) em Amperes e a pot\u00eancia total em Watts<\/b><\/span><\/span><\/span><\/p>\n

07- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Um <\/b><\/span><\/span><\/span>corpo neutro foi eletrizado com 1 Coulomb. Para que isso fosse poss\u00edvel, <\/b><\/span><\/span><\/span>a <\/b><\/span><\/span><\/span>quantidade de el\u00e9trons que foram retirados do corpo foi: <\/b><\/span><\/span><\/span>Dado:<\/b><\/span><\/span><\/span> e = – 1,6.10<\/b><\/span><\/span><\/span>-19<\/b><\/span><\/span><\/sup><\/span> C.<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>1,6.10<\/b><\/span><\/span><\/span>18<\/b><\/span><\/span><\/sup><\/span> <\/b>(B) <\/b><\/span><\/span><\/span>1,6.10<\/b><\/span><\/span><\/span>\u201319<\/b><\/span><\/span><\/sup><\/span> <\/b>(C) <\/b><\/span><\/span><\/span>6,25.10<\/b><\/span><\/span><\/span>18<\/b><\/span><\/span><\/sup><\/span> <\/b>(D) <\/b><\/span><\/span><\/span>6,25.10<\/b><\/span><\/span><\/span>\u201319 <\/b><\/span><\/span><\/sup><\/span>(E) 1.10<\/b><\/span><\/span><\/span>\u201319<\/b><\/span><\/span><\/sup><\/span><\/p>\n

08- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

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Em uma <\/b><\/span><\/span><\/span>aula de laborat\u00f3rio de eletricidade, <\/b><\/span><\/span><\/span>um aluno <\/b><\/span><\/span><\/span>realizou a seguinte experi\u00eancia:<\/b><\/span><\/span><\/span><\/p>\n

– <\/b><\/span><\/span><\/span>Separou 5 esferas id\u00eanticas e eletricamente neutras; <\/b><\/span><\/span><\/span><\/p>\n

– <\/b><\/span><\/span><\/span>Eletrizou uma delas com uma carga de valor Q; <\/b><\/span><\/span><\/span><\/p>\n

– <\/b><\/span><\/span><\/span>Separadamente, colocou a esfera eletrizada em contato com cada uma das outras esferas.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Assim, <\/b><\/span><\/span><\/span>a esfera que foi, inicialmente, carregada com carga Q, ter\u00e1 sua carga final de valor:<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>1Q\/7 <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>1Q\/16 <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>2Q\/16 <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>1Q\/32 <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>1Q\/64<\/b><\/span><\/span><\/span><\/p>\n

09- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Por um condutor, que leva energia el\u00e9trica at\u00e9 uma m\u00e1quina de uma empresa, passaram 6,25 \u00d710<\/b><\/span><\/span><\/span>18<\/b><\/span><\/span><\/sup><\/span> el\u00e9trons em um \u00fanico segundo.<\/b><\/span><\/span><\/span> <\/b><\/p>\n

<\/p>\n

Pode-se dizer que a <\/b><\/span><\/span><\/span>Intensidade da corrente el\u00e9trica nesse condutor, durante esse \u00fanico segundo foi: Considere e <\/b><\/span><\/span><\/span>= – 1,6.10<\/b><\/span><\/span><\/span>-19<\/b><\/span><\/span><\/sup><\/span> C<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>1,6 \u00d710 <\/b><\/span><\/span><\/span>\u201319<\/b><\/span><\/span><\/sup><\/span> Amperes <\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>1,6 Amperes <\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>6,25 Amperes <\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>2 Amperes <\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>1 Ampere<\/b><\/span><\/span><\/span><\/p>\n

10- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

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Um <\/b><\/span><\/span><\/span>aluno de uma ETEC,<\/b><\/span><\/span><\/span> durante um <\/b><\/span><\/span><\/span>experimento em laborat\u00f3rio na escola, analisa um circuito<\/b><\/span><\/span><\/span><\/p>\n

que possui um conjunto de cinco resistores de 100 ohms associados em paralelo<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span><\/span>ligados em<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

um gerador de 24 volts que tamb\u00e9m est\u00e1 em paralelo com os resistores.<\/b><\/span><\/span><\/span><\/p>\n

Ao <\/b><\/span><\/span><\/span>medir a tens\u00e3o no terceiro resistor, o valor <\/b><\/span><\/span><\/span>ser\u00e1 de:<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>100 volts. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>300 volts. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>24 volts. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>14,2 volts. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>12 volts.<\/b><\/span><\/span><\/span><\/p>\n

11- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Um <\/b><\/span><\/span><\/span>chuveiro el\u00e9trico possui uma pot\u00eancia de 6000 W em 127 V. <\/b><\/span><\/span><\/span>Conforme a <\/b><\/span><\/span><\/span>NBR\u20135410, norma<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

de instala\u00e7\u00e3o el\u00e9trica de baixa tens\u00e3o, esse chuveiro ser\u00e1 ligado em uma:<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>Tomada de uso gera, pois trabalha com tens\u00e3o 127 V<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>Tomada de uso geral, pois ter\u00e1 uma corrente de, aproximadamente, 47,2 A<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>Tomada de uso espec\u00edfico mesmo trabalhando com 127 V<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>Tomada de uso geral pelo fato de ser um tipo de eletrodom\u00e9stico<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>Tomada de uso espec\u00edfico se a tens\u00e3o de opera\u00e7\u00e3o do chuveiro for alterada para 220 V<\/b><\/span><\/span><\/span><\/p>\n

12- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Em uma <\/b><\/span><\/span><\/span>instala\u00e7\u00e3o el\u00e9trica, a fun\u00e7\u00e3o dos interruptores do tipo paralelo <\/b><\/span><\/span><\/span>\u00e9:<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>Ligar e desligar duas l\u00e2mpadas, a partir de dois interruptores localizados no mesmo espelho,<\/b><\/span><\/span><\/span><\/p>\n

por possu\u00edrem duas se\u00e7\u00f5es.<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>Ligar e desligar uma l\u00e2mpada, a partir de um interruptor por possuir uma se\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>Exatamente a mesma fun\u00e7\u00e3o de um interruptor intermedi\u00e1rio.<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>Exatamente a mesma fun\u00e7\u00e3o de um interruptor simples.<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>Ligar e desligar uma l\u00e2mpada, a partir de dois interruptores localizados em pontos diferentes.<\/b><\/span><\/span><\/span><\/p>\n

13- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Em <\/b><\/span><\/span><\/span>uma ind\u00fastria, um t\u00e9cnico nota, com o uso de um amper\u00edmetro, <\/b><\/span><\/span><\/span>que o <\/b><\/span><\/span><\/span>consumo de Intensidade de corrente em uma de suas m\u00e1quinas est\u00e1 aumentando diariamente, provavelmente, devido a algum<\/b><\/span><\/span><\/span><\/p>\n

defeito na parte el\u00e9trica da m\u00e1quina. <\/b><\/span><\/span><\/span><\/p>\n

O t\u00e9cnico, a princ\u00edpio, n\u00e3o se preocupa pelo fato de a m\u00e1quina possuir disjuntores de prote\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Sabendo que o <\/b><\/span><\/span><\/span>amper\u00edmetro utilizado s\u00f3 indica intensidade de corrente em miliamperes <\/b><\/span><\/span><\/span>e que os <\/b><\/span><\/span><\/span>disjuntores s\u00e3o de 10 Amperes,<\/b><\/span><\/span><\/span> no <\/b><\/span><\/span><\/span>momento em que os disjuntores desarmarem, a indica\u00e7\u00e3o no amper\u00edmetro, provavelmente, ser\u00e1 de, <\/b><\/span><\/span><\/span>aproximadamente:<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>10 mA.<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>1000 mA.<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>10000 mA.<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>100000 mA.<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>1000000 mA.<\/b><\/span><\/span><\/span><\/p>\n

14- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Sabe-se que em <\/b><\/span><\/span><\/span>uma tomada residencial, sua infraestrutura<\/b><\/span><\/span><\/span> (fios condutores, disjuntores, condu\u00edtes, etc) <\/b><\/span><\/span><\/span>est\u00e1 preparada para receber um equipamento que consuma, no m\u00e1ximo,<\/b><\/span><\/span><\/span> <\/b>20 amperes.<\/b><\/span><\/span><\/span> <\/b><\/p>\n

Sabendo que essa tomada opera com uma tens\u00e3o de 127 volts, a pot\u00eancia m\u00e1xima do equipamento dever\u00e1 ser, aproximadamente, <\/b><\/span><\/span><\/span>de:<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span><\/span>20 watts.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span><\/span>127 watts.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span><\/span>1270 watts.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>2540 watts.<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>4400 watts.<\/b><\/span><\/span><\/span><\/p>\n

Especializa\u00e7\u00e3o – T\u00e9cnico em Eletr\u00f4nica<\/b><\/span><\/span><\/span><\/p>\n

15- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

A <\/b><\/span><\/span><\/span>resistencia el\u00e9trica e a capacidade de oposi\u00e7\u00e3o <\/b><\/span><\/span><\/span>que um <\/b><\/span><\/span><\/span>material oferece ao fluxo de corrente eletrica.<\/b><\/span><\/span><\/span><\/p>\n

A 2<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sup><\/span> Lei de Ohm, com a qual podemos calcular o valor dessa resist\u00eancia el\u00e9trica, diz:<\/b><\/span><\/span><\/span><\/p>\n

\u201cA resist\u00eancia el\u00e9trica de um condutor de se\u00e7\u00e3o transversal constante \u00e9 diretamente proporcional ao seu comprimento e inversamente proporcional a \u00e1rea da sua se\u00e7\u00e3o transversal e depende do material desse condutor\u201d.<\/b><\/span><\/span><\/span><\/p>\n

Sua f\u00f3rmula \u00e9:<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

onde:<\/b><\/span><\/span><\/span><\/p>\n

R = <\/b><\/span><\/span><\/span>Resistencia el\u00e9trica <\/b><\/span><\/span><\/span>(\u03a9)<\/b><\/span><\/span><\/span><\/p>\n

\u03c1 = <\/b><\/span><\/span><\/span>Resistividade do material <\/b><\/span><\/span><\/span>(\u03a9 .m)<\/b><\/span><\/span><\/span><\/p>\n

L = <\/b><\/span><\/span><\/span>Comprimento <\/b><\/span><\/span><\/span>(m)<\/b><\/span><\/span><\/span><\/p>\n

A = <\/b><\/span><\/span><\/span>Se\u00e7\u00e3o <\/b><\/span><\/span><\/span>(m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span><\/p>\n

Um <\/b><\/span><\/span><\/span>fio com \u03c1 = 2,8.10<\/b><\/span><\/span><\/span>\u20138<\/b><\/span><\/span><\/sup><\/span> \u03a9.m, comprimento de 1000 m e se\u00e7\u00e3o transversal de 2 mm<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> tem uma<\/b><\/span><\/span><\/span><\/p>\n

resist\u00eancia el\u00e9trica com<\/b><\/span><\/span><\/span> valor de<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>1 \u03a9. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>2 \u03a9. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>7 \u03a9. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>14 \u03a9. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>28 \u03a9.<\/b><\/span><\/span><\/span><\/p>\n

16- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

A seguir, temos a figura de um circuito que recebe o nome de divisor de tens\u00e3o, pois a soma das tens\u00f5es sobre os resistores R<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span> e R<\/b><\/span><\/span><\/span>b<\/b><\/span><\/span><\/sub><\/span> \u00e9 igual a tens\u00e3o da fonte V<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span> . <\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Analisando esse circuito, podemos afirmar que a tens\u00e3o no volt\u00edmetro V <\/b><\/span><\/span><\/span>\u00e9 de:<\/b><\/span><\/span><\/span><\/p>\n

A) <\/b><\/span><\/span><\/span>1 V. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>5 V. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>10 V. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>12 V. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>14 V.<\/b><\/span><\/span><\/span><\/p>\n

17- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

A <\/b><\/span><\/span><\/span>Lei de Coulomb afirma que a intensidade da forca eletrica de interacao entre cargas puntiformes<\/b><\/span><\/span><\/span><\/p>\n

e diretamente proporcional ao produto dos m\u00f3dulos de cada carga e inversamente proporcional<\/b><\/span><\/span><\/span><\/p>\n

ao quadrado da distancia que os separ<\/b><\/span><\/span><\/span>a e <\/b><\/span><\/span><\/span>tamb\u00e9m depende do meio onde as cargas se encontram.<\/b><\/span><\/span><\/span><\/p>\n

Portanto<\/b><\/span><\/span><\/span>, essa forca pode ser calculada, utilizando-se a seguinte f\u00f3rmula:<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Duas cargas Q<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 20 \u03bcC e Q<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = 10 \u03bcC est\u00e3o no v\u00e1cuo, onde K = 9,19.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> N m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> \/C<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> e distantes<\/b><\/span><\/span><\/span><\/p>\n

1 m uma da outra.<\/b><\/span><\/span><\/span> A <\/b><\/span><\/span><\/span>for\u00e7a entre essas cargas e de, <\/b><\/span><\/span><\/span>aproximadamente<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>1,84 N. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>2,76 N. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>5,39 N<\/b><\/span><\/span><\/span> (D) <\/b><\/span><\/span><\/span>9,24 N<\/b><\/span><\/span><\/span>. (E) <\/b><\/span><\/span><\/span>18,20 N.<\/b><\/span><\/span><\/span><\/p>\n

18- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Na <\/b><\/span><\/span><\/span>representa\u00e7\u00e3o de instala\u00e7\u00f5es el\u00e9tricas, <\/b><\/span><\/span><\/span>utilizamos <\/b><\/span><\/span><\/span>diagramas el\u00e9tricos.<\/b><\/span><\/span><\/span> <\/b><\/p>\n

Um desses diagramas \u00e9 o diagrama unifilar <\/b><\/span><\/span><\/span>no qual <\/b><\/span><\/span><\/span>todos os condutores de um eletroduto s\u00e3o representados sobre um \u00fanico tra\u00e7o.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

A <\/b><\/span><\/span><\/span>figura a seguir mostra um diagrama unifilar com um eletroduto e dois condutores.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Os <\/b><\/span><\/span><\/span>dois condutores representados<\/b><\/span><\/span><\/span> s\u00e3o <\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>Fase e Terra.<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>Fase e Retorno.<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>Neutro e Terra<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>Neutro e Retorno. <\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>Retorno e Terra.<\/b><\/span><\/span><\/span><\/p>\n

19- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

LED (<\/b><\/span><\/span><\/span>Light Emitting Diode<\/b><\/i><\/span><\/span><\/span>) <\/b><\/span><\/span><\/span>\u00e9 um <\/b><\/span><\/span><\/span>diodo que emite luz. <\/b><\/span><\/span><\/span>Ele tem um <\/b><\/span><\/span><\/span>baixo consumo de energia el\u00e9trica,<\/b><\/span><\/span><\/span><\/p>\n

alto rendimento e vida \u00fatil longa.<\/b><\/span><\/span><\/span><\/p>\n

O <\/b><\/span><\/span><\/span>circuito a seguir mostra um LED sendo alimentado por uma bateria com um resistor ligado em s\u00e9rie.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Qual deve ser o valor \u00f4hmico do resistor R para que a tens\u00e3o sobre o LED seja de 3 V <\/b><\/span><\/span><\/span>e a <\/b><\/span><\/span><\/span>corrente el\u00e9trica do circuito seja de 30 mA?<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>50 \u03a9. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>60 \u03a9. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>100 \u03a9. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>500 \u03a9. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>600 \u03a9.<\/b><\/span><\/span><\/span><\/p>\n

20- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

O <\/b><\/span><\/span><\/span>circuito a seguir apresenta tr\u00eas resistores associados em serie entre os pontos A e B.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Qual o valor do resistor equivalente a essa associa\u00e7\u00e3o?<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>330 \u03a9. <\/b><\/span><\/span><\/span>(B) <\/b><\/span><\/span><\/span>360 \u03a9. <\/b><\/span><\/span><\/span>(C) <\/b><\/span><\/span><\/span>390 \u03a9. <\/b><\/span><\/span><\/span>(D) <\/b><\/span><\/span><\/span>950 \u03a9. <\/b><\/span><\/span><\/span>(E) <\/b><\/span><\/span><\/span>1080 \u03a9.<\/b><\/span><\/span><\/span><\/p>\n

21- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Um <\/b><\/span><\/span><\/span>mult\u00edmetro e um instrumento utilizado para fazer diferentes leituras em um circuito el\u00e9trico.<\/b><\/span><\/span><\/span><\/p>\n

Para que <\/b><\/span><\/span><\/span>n\u00e3o tenhamos problemas na hora de efetuarmos uma leitura, <\/b><\/span><\/span><\/span>devemos <\/b><\/span><\/span><\/span>selecionar a<\/b><\/span><\/span><\/span><\/p>\n

escala certa e ligarmos os terminais do mult\u00edmetro de forma correta. <\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Fabio <\/b><\/span><\/span><\/span>utilizou, de maneira correta, um mult\u00edmetro para medir a corrente e, depois, a tens\u00e3o em um componente de um circuito.<\/b><\/span><\/span><\/span><\/p>\n

Qual das alternativas a seguir apresenta, em sequencia correta, as maneiras como os terminais foram ligados no componente?<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>Serie e Paralelo.<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>Paralelo e Serie.<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>Serie e Serie.<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>Paralelo e Paralelo.<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>Antiparalelo e Antiparalelo.<\/b><\/span><\/span><\/span><\/p>\n

22- (ESCOLA T\u00c9CNICA ESTADUAL \u2013 ETEC \u2013 SP \u2013 019)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

O <\/b><\/span><\/span><\/span>oscilosc\u00f3pio e um aparelho eletr\u00f4nico<\/b><\/span><\/span><\/span> por meio do qual <\/b><\/span><\/span><\/span>\u00e9 poss\u00edvel visualizar a forma de uma tens\u00e3o, atrav\u00e9s da sua tela que, geralmente, e formada por 8 divis\u00f5es no eixo vertical e 10 divis\u00f5es no eixo horizontal. <\/b><\/span><\/span><\/span><\/p>\n

O <\/b><\/span><\/span><\/span>eixo vertical representa a tens\u00e3o e o eixo horizontal representa o tempo.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

A <\/b><\/span><\/span><\/span>tela a seguir e de um oscilosc\u00f3pio que foi ajustado em sua escala de tens\u00e3o em 0,1 V\/Div.<\/b><\/span><\/span><\/span> e em <\/b><\/span><\/span><\/span>sua<\/b><\/span><\/span><\/span><\/p>\n

escala de Tempo em 5 ms\/Div.<\/b><\/span><\/span><\/span><\/p>\n

Com essas informa\u00e7\u00f5es, podemos afirmar que a tens\u00e3o de pico e a frequ\u00eancia desse sinal<\/b><\/span><\/span><\/span> valem<\/b><\/span><\/span><\/span><\/p>\n

(A) <\/b><\/span><\/span><\/span>V = 0,1 V e f = 20 Hz.<\/b><\/span><\/span><\/span><\/p>\n

(B) <\/b><\/span><\/span><\/span>V = 0,1 V e f = 50 Hz.<\/b><\/span><\/span><\/span><\/p>\n

(C) <\/b><\/span><\/span><\/span>V = 0,3 V e f = 20 Hz.<\/b><\/span><\/span><\/span><\/p>\n

(D) <\/b><\/span><\/span><\/span>V = 0,3 V e f = 50 Hz.<\/b><\/span><\/span><\/span><\/p>\n

(E) <\/b><\/span><\/span><\/span>V = 0,5 V e f = 60 Hz.<\/b><\/span><\/span><\/span><\/p>\n

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00edsica da ETEC \u2013 SP \u2013 2019<\/span><\/span><\/span><\/p>\n

01-<\/span><\/span><\/span><\/p>\n

Toda bateria possui um polo positivo e um polo negativo, caracter\u00edsticas semelhantes <\/b><\/span><\/span><\/span>\u00e0s <\/b><\/span><\/span><\/span>desse peixe, onde o polo positivo seria a cabe\u00e7a e o negativo a cauda.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Esses dois polos originam uma diferen\u00e7a de potencial <\/b><\/span><\/span><\/span>(tens\u00e3o ou voltagem) que <\/b><\/span><\/span><\/span>originam<\/b><\/span><\/span><\/span> a movimenta\u00e7\u00e3o de <\/b><\/span><\/span><\/span>corrente el\u00e9trica, <\/b><\/span><\/span><\/span>que no caso do peixe, quando tocado, pode <\/b><\/span><\/span><\/span>liberar uma forte descarga el\u00e9trica, imobilizando e at\u00e9 matando suas presas ou agressores.<\/b><\/span><\/span><\/span> <\/b><\/p>\n

R- C<\/span><\/span><\/span><\/p>\n

02-<\/b><\/span><\/span><\/span><\/p>\n

Se voc\u00ea n\u00e3o domina a teoria, ela est\u00e1 a seguir.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

03-<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

No <\/b><\/span><\/span><\/span>caso do exerc\u00edcio voc\u00ea ter\u00e1 P<\/b><\/span><\/span><\/span>fundo<\/b><\/span><\/span><\/sub><\/span> = 11 000\/10 + 1 atm <\/b><\/span><\/span><\/span>= 1 101 atm.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

04-<\/b><\/span><\/span><\/span><\/p>\n

Pelo enunciado <\/b><\/span><\/span><\/span>voc\u00ea deve escolher <\/b><\/span><\/span><\/span>ondas eletromagn\u00e9ticas com os menores comprimentos de onda e, portanto, maiores energias que s\u00e3o os raios gama.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

05-<\/b><\/span><\/span><\/span><\/p>\n

Pelo enunciado a energia liberada pelo impacto de um asteroide \u00e9<\/b><\/span><\/span><\/span> <\/b>diretamente proporcional apenas ao cubo do di\u00e2metro da cratera formada, que possui 200 km = 2.10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(2.10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span> <\/b>= 2<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span> <\/b>= 8 000 000.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

06-<\/b><\/span><\/span><\/span><\/p>\n

Curva caracter\u00edstica de um gerador<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

E = for\u00e7a eletromotriz<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span><\/span>i<\/b><\/span><\/span><\/span>cc<\/b><\/span><\/span><\/sub><\/span> = corrente de curto circuito<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

07-<\/b><\/span><\/span><\/span><\/p>\n

Corpos eletrizados<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

Q = n.e <\/b><\/span><\/span><\/span> 1 = n.1,6.10<\/b><\/span><\/span><\/span>-19<\/b><\/span><\/span><\/sup><\/span> <\/b><\/span><\/span><\/span>n<\/b><\/span><\/span><\/span> = 1\/1,6.10<\/b><\/span><\/span><\/span>-19<\/b><\/span><\/span><\/sup><\/span> = 0,625.10<\/b><\/span><\/span><\/span>19<\/b><\/span><\/span><\/sup><\/span> <\/b>= 6,25.10<\/b><\/span><\/span><\/span>18<\/b><\/span><\/span><\/sup><\/span> el\u00e9trons.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/span><\/span><\/span><\/p>\n

08-<\/b><\/span><\/span><\/span><\/p>\n

Eletriza\u00e7\u00e3o por contato<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Se os dois corpos\u00a0<\/b><\/span><\/span>forem\u00a0id\u00eanticos<\/b><\/span><\/span>\u00a0e estiverem\u00a0<\/b><\/span><\/span>inicialmente eletrizados com cargas\u00a0Q<\/b><\/span><\/span>A<\/b><\/span><\/sub><\/span>\u00a0e Q<\/b><\/span><\/span>B<\/b><\/span><\/sub><\/span>,<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>ap\u00f3s\u00a0<\/b><\/span><\/span>o contato eles ter\u00e3o cargas id\u00eanticas Q\u2019 tal que\u00a0<\/b><\/span><\/span>Q\u2019= (Q<\/b><\/span><\/span>A<\/b><\/span><\/sub><\/span>\u00a0+ Q<\/b><\/span><\/span>B<\/b><\/span><\/sub><\/span>)\/2.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Esfera de carga Q em contato com a primeira, neutra<\/b><\/span><\/span><\/span> Q\u2019<\/b><\/span><\/span><\/span> <\/b>=(Q + 0)\/2 <\/b><\/span><\/span><\/span>Q\u2019<\/b><\/span><\/span><\/span> <\/b>= Q\/2.<\/b><\/span><\/span><\/span><\/p>\n

Esfera de carga Q\u2019 em contato com a segunda, neutra <\/b><\/span><\/span><\/span> Q\u2019\u2019<\/b><\/span><\/span><\/span> <\/b>=(Q\/2 + 0)\/2 <\/b><\/span><\/span><\/span>Q\u2019\u2019<\/b><\/span><\/span><\/span> <\/b>= Q\/4.<\/b><\/span><\/span><\/span><\/p>\n

Esfera de carga Q\u2019\u2019 em contato com a terceira, neutra <\/b><\/span><\/span><\/span> Q\u2019\u2019\u2019<\/b><\/span><\/span><\/span> <\/b>=(Q\/4 + 0)\/2 <\/b><\/span><\/span><\/span>Q\u2019\u2019\u2019<\/b><\/span><\/span><\/span> <\/b>= Q\/8.<\/b><\/span><\/span><\/span><\/p>\n

Esfera de carga Q\u2019\u2019\u2019 em contato com a quarta, neutra <\/b><\/span><\/span><\/span> Q\u2019\u2019\u2019\u2019<\/b><\/span><\/span><\/span> <\/b>=(Q\/8 + 0)\/2 <\/b><\/span><\/span><\/span>Q\u2019\u2019\u2019\u2019<\/b><\/span><\/span><\/span> <\/b>= Q\/16.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/span><\/span><\/span><\/p>\n

09-<\/span><\/span><\/span><\/p>\n

<\/p>\n

Q = n.e <\/b><\/span><\/span><\/span>= 6,25.10<\/b><\/span><\/span><\/span>18<\/b><\/span><\/span><\/sup><\/span>.1,6.10<\/b><\/span><\/span><\/span>-19 <\/b><\/span><\/span><\/sup><\/span>= 10.10<\/b><\/span><\/span><\/span>-1<\/b><\/span><\/span><\/sup><\/span> =10<\/b><\/span><\/span><\/span>0<\/b><\/span><\/span><\/sup><\/span> <\/b><\/span><\/span><\/span>Q = 1 C em t = 1s.<\/b><\/span><\/span><\/span><\/p>\n

i = Q\/t <\/b><\/span><\/span><\/span>= 1\/1 <\/b><\/span><\/span><\/span>i = 1 A<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

10-<\/b><\/span><\/span><\/span><\/p>\n

Caracter\u00edsticas da associa\u00e7\u00e3o paralelo<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Veja teoria acima.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

11-<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

12-<\/b><\/span><\/span><\/span><\/p>\n

Uma\u00a0<\/b><\/span><\/span><\/span>situa\u00e7\u00e3o pr\u00e1tica<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>bastante comum<\/b><\/span><\/span><\/span>\u00a0nas\u00a0<\/b><\/span><\/span><\/span>resid\u00eancias<\/b><\/span><\/span><\/span>\u00a0e\u00a0<\/b><\/span><\/span><\/span>nos hot\u00e9is<\/b><\/span><\/span><\/span>\u00a0\u00e9 o chamado<\/b><\/span><\/span><\/span><\/p>\n

\u201cinterruptor paralelo\u201d,<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>onde,\u00a0<\/b><\/span><\/span><\/span>na\u00a0realidade a liga\u00e7\u00e3o \u00e9 em s\u00e9rie<\/b><\/span><\/span><\/span>,\u00a0na qual\u00a0<\/b><\/span><\/span><\/span>\u00e9\u00a0poss\u00edvel ligar ou desligar uma determinada l\u00e2mpada, de forma independente, estando no ponto mais alto ou mais baixo de uma escada, da maneira indicada nas sequ\u00eancias abaixo.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

13-<\/b><\/span><\/span><\/span><\/p>\n

1 mA = 10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span> A <\/b><\/span><\/span><\/span> assim, <\/b><\/span><\/span><\/span>10 000 mA <\/b><\/span><\/span><\/span>= 10 000×10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span> A <\/b><\/span><\/span><\/span>= 10 A.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

14-<\/b><\/span><\/span><\/span><\/p>\n

S\u00e3o dados: i <\/b><\/span><\/span><\/span>= 20 A e <\/b><\/span><\/span><\/span>U <\/b><\/span><\/span><\/span>= 127 V.<\/b><\/span><\/span><\/span><\/p>\n

P = i.U <\/b><\/span><\/span><\/span>= 20×127 <\/b><\/span><\/span><\/span>P = 2 540 W.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

15-<\/b><\/span><\/span><\/span><\/p>\n

S\u00e3o <\/b><\/span><\/span><\/span>dado<\/b><\/span><\/span><\/span>s: <\/b><\/span><\/span><\/span>\u03c1 = 2,8.10<\/b><\/span><\/span><\/span>\u20138<\/b><\/span><\/span><\/sup><\/span> \u03a9; L = 1000 m = 10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span> m; A = 2 mm<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 2.10<\/b><\/span><\/span><\/span>-6 <\/b><\/span><\/span><\/sup><\/span>m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R = \u03c1.L\/A <\/b><\/span><\/span><\/span>= 2,8.10<\/b><\/span><\/span><\/span>-8<\/b><\/span><\/span><\/sup><\/span>.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\/2.10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span> = 1,4.10<\/b><\/span><\/span><\/span>-5<\/b><\/span><\/span><\/sup><\/span>\/10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span> = 1,4.10 <\/b><\/span><\/span><\/span> R = 14 \u2126<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

16-<\/b><\/span><\/span><\/span><\/p>\n

Considerando o volt\u00edmetro ideal,<\/b><\/span><\/span><\/span> voc\u00ea pode tir\u00e1-lo do circuito e verificar que os <\/b><\/span><\/span><\/span>resistores R<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span> e R<\/b><\/span><\/span><\/span>b<\/b><\/span><\/span><\/sub><\/span> est\u00e3o em s\u00e9rie fornecendo um \u00fanico resistor de R\u2019<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = 100 + 140 = 240 \u2126 submetido \u00e0 tens\u00e3o de U = 12 V.<\/b><\/span><\/span><\/span><\/p>\n

R\u2019<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> = U\/i <\/b><\/span><\/span><\/span> 240 = 12\/i <\/b><\/span><\/span><\/span>i <\/b><\/span><\/span><\/span>= 12\/240 <\/b><\/span><\/span><\/span>= 0,05 A <\/b><\/span><\/span><\/span>(corrente que circula por R<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span> e por R<\/b><\/span><\/span><\/span>b<\/b><\/span><\/span><\/sub><\/span> pois est\u00e3o em s\u00e9rie).<\/b><\/span><\/span><\/span><\/p>\n

Como o <\/b><\/span><\/span><\/span>volt\u00edmetro est\u00e1 ligado apenas ao resistor de R<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span> = 100 \u2126 percorrido por i = 0,05 A ele indicar\u00e1 R<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span> = V\/i <\/b><\/span><\/span><\/span> 100 = V\/0,05 V = 100.0,05 <\/b><\/span><\/span><\/span>V = 5 V.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

17-<\/b><\/span><\/span><\/span><\/p>\n

F = K.Q<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>.Q<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\/d<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 9,19.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span>.20.10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span>.10.10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span>\/1<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 1838.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span> <\/b><\/span><\/span><\/span>F = 1,838 N.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

18-<\/b><\/span><\/span><\/span><\/p>\n

Representa\u00e7\u00e3o simb\u00f3lica<\/span><\/span><\/span><\/p>\n

<\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

19-<\/b><\/span><\/span><\/span><\/p>\n

Se o <\/b><\/span><\/span><\/span>LED est\u00e1 submetido \u00e0 tens\u00e3o de 3 V <\/b><\/span><\/span><\/span>e, <\/b><\/span><\/span><\/span>ele e R est\u00e3o associados em s\u00e9rie ser\u00e3o percorridos pela mesma corrente el\u00e9trica de i <\/b><\/span><\/span><\/span>= 30 mA <\/b><\/span><\/span><\/span>= 30.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span> A <\/b><\/span><\/span><\/span>e <\/b><\/span><\/span><\/span>R estar\u00e1 submetido \u00e0 tens\u00e3o de U <\/b><\/span><\/span><\/span>= 18 \u2013 3 <\/b><\/span><\/span><\/span>= 15 V <\/b><\/span><\/span><\/span>(caracter\u00edsticas da associa\u00e7\u00e3o s\u00e9rie, i \u00e9 a mesma e a tens\u00e3o total U \u00e9 a soma das tens\u00f5es parciais).<\/b><\/span><\/span><\/span><\/p>\n

R = U\/i <\/b><\/span><\/span><\/span>= 15\/30.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span> = 0,5.10<\/b><\/span><\/span><\/span>3 <\/b><\/span><\/span><\/sup><\/span> <\/b>R = 500 \u2126.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

20-<\/b><\/span><\/span><\/span><\/p>\n

Caracter\u00edstica da associa\u00e7\u00e3o s\u00e9rie R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span> <\/b>= 330 + 360 + 390 <\/b><\/span><\/span><\/span>= 1080 \u03a9<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

21-<\/b><\/span><\/span><\/span><\/p>\n

Se voc\u00ea n\u00e3o domina a teoria, ela est\u00e1 a seguir:<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

22-<\/b><\/span><\/span><\/span><\/p>\n

Observe no esquema abaixo <\/b><\/span><\/span><\/span>que a <\/b><\/span><\/span><\/span>tens\u00e3o de pico corresponde a 3xcada divis\u00e3o de 0,1 V = 0,3 V.<\/b><\/span><\/span><\/span><\/p>\n

\"ETEC\"<\/p>\n

Sendo o <\/b><\/span><\/span><\/span>per\u00edodo o tempo que demora para efetuar uma oscila\u00e7\u00e3o completa <\/b><\/span><\/span><\/span>( dist\u00e2ncia entre duas cristas, por exemplo), no caso <\/b><\/span><\/span><\/span>T = 4x5divis\u00f5es de 5 ms <\/b><\/span><\/span><\/span>= 20 ms <\/b><\/span><\/span><\/span>= 20.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span> s.<\/b><\/span><\/span><\/span><\/p>\n

Como a <\/b><\/span><\/span><\/span>frequ\u00eancia \u00e9 o inverso do per\u00edodo f = 1\/T <\/b><\/span><\/span><\/span>= 1\/20.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span> = 0,05.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span> <\/b><\/span><\/span><\/span> f = 50 Hz.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Clique aqui para ver sobre o tema!<\/a><\/p>\n

Confira as v\u00eddeo aulas!<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

ETEC-SP-2019 As\u00a0Escolas T\u00e9cnicas Estaduais\u00a0(ETECs) s\u00e3o\u00a0institui\u00e7\u00f5es\u00a0de ensinos t\u00e9cnico, m\u00e9dio e t\u00e9cnico integrado ao m\u00e9dio (ETIM), pertencentes ao\u00a0Centro Estadual de Educa\u00e7\u00e3o Tecnol\u00f3gica Paula Souza\u00a0(CEETEPS), autarquia da\u00a0Secretaria de Desenvolvimento Econ\u00f4mico, Ci\u00eancia e Tecnologia\u00a0(SDECTI) do estado de\u00a0S\u00e3o Paulo. O Centro Paula Souza mant\u00e9m uma parceria com a Secretaria de Educa\u00e7\u00e3o e prefeituras dos munic\u00edpios paulistas para oferecer cursos t\u00e9cnicos em salas de aulas que<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":4337,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-4730","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4730","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=4730"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4730\/revisions"}],"predecessor-version":[{"id":10271,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4730\/revisions\/10271"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4337"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=4730"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}