{"id":4499,"date":"2019-06-30T23:56:44","date_gmt":"2019-06-30T23:56:44","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=4499"},"modified":"2024-07-11T02:50:26","modified_gmt":"2024-07-11T02:50:26","slug":"insper-2019","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2019\/insper-2019\/","title":{"rendered":"Insper 2019"},"content":{"rendered":"

Vestibular<\/b><\/span><\/span><\/span><\/em>\u00a0Insper <\/b><\/span><\/span><\/span>2019<\/b><\/span><\/span><\/span><\/em>\u00a0<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

O\u00a0Insper\u00a0\u00e9 uma institui\u00e7\u00e3o de\u00a0<\/b><\/span><\/span><\/span>ensino superior<\/b><\/span><\/span><\/span><\/a>\u00a0<\/b><\/span><\/span><\/span>brasileira<\/b><\/span><\/span><\/span><\/a>\u00a0que atua nas \u00e1reas de\u00a0<\/b><\/span><\/span><\/span>neg\u00f3cios<\/b><\/span><\/span><\/span><\/a>,\u00a0<\/b><\/span><\/span><\/span>economia<\/b><\/span><\/span><\/span><\/a>,\u00a0<\/b><\/span><\/span><\/span>direito<\/b><\/span><\/span><\/span><\/a>,\u00a0<\/b><\/span><\/span><\/span>engenharia mec\u00e2nica<\/b><\/span><\/span><\/span><\/a>,\u00a0<\/b><\/span><\/span><\/span>engenharia mecatr\u00f4nica<\/b><\/span><\/span><\/span><\/a>\u00a0e\u00a0<\/b><\/span><\/span><\/span>engenharia da computa\u00e7\u00e3o<\/b><\/span><\/span><\/span><\/a>. Est\u00e1 localizada em S\u00e3o Paulo (capital<\/b><\/span><\/span><\/span><\/p>\n

Somos\u00a0uma institui\u00e7\u00e3o de\u00a0<\/b><\/span><\/span><\/span>ensino superior<\/b><\/span><\/span><\/span><\/a>\u00a0e de\u00a0<\/b><\/span><\/span><\/span>pesquisa<\/b><\/span><\/span><\/span><\/a>\u00a0sem fins lucrativos que reverte todo o resultado operacional para a realiza\u00e7\u00e3o de nossa\u00a0miss\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

O Programa de Bolsas de Estudo foi criado para garantir o acesso ao Insper aos jovens aprovados no processo seletivo e que necessitem de apoio financeiro para serem alunos da Gradua\u00e7\u00e3o nos cursos de Administra\u00e7\u00e3o, Economia e Engenharia. Hoje, 12% dos nossos alunos s\u00e3o contemplados com algum tipo de bolsa de estudo.<\/b><\/span><\/span><\/span><\/p>\n

O Insper torna p\u00fablico o Edital para o Processo Seletivo referente ao 1\u00ba semestre letivo de 2018 para os cursos de Gradua\u00e7\u00e3o em Administra\u00e7\u00e3o, Ci\u00eancias Econ\u00f4micas, Engenharia de Computa\u00e7\u00e3o, Engenharia Mec\u00e2nica e Engenharia Mecatr\u00f4nica. A sele\u00e7\u00e3o ser\u00e1 realizada em duas fases, a primeira por meio do Exame Vestibular ou dos resultados no Exame Nacional do Ensino M\u00e9dio (ENEM), com vagas para a segunda fase especificamente destinadas a cada uma dessas op\u00e7\u00f5es; e a segunda fase por meio de exame oral.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

01\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Existem cidades no mundo cujo tra\u00e7ado visto de cima assemelha-se a um tabuleiro de xadrez. Considere um <\/b><\/span><\/span><\/span>ciclista trafegando<\/b><\/span><\/span><\/span> por uma dessas cidades, <\/b><\/span><\/span><\/span>percorrendo<\/b><\/span><\/span><\/span>, inicialmente, <\/b><\/span><\/span><\/span>2,0 km no sentido leste<\/b><\/span><\/span><\/span>, seguindo por <\/b><\/span><\/span><\/span>mais<\/b><\/span><\/span><\/span> <\/b>3,0 km no sentido norte<\/b><\/span><\/span><\/span>. A seguir, <\/b><\/span><\/span><\/span>ele passa a se movimentar no sentido leste, percorrendo, novamente, 1,0 km<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span><\/span>finalizando com mais 3,0 km no sentido norte<\/b><\/span><\/span><\/span>. Todo esse <\/b><\/span><\/span><\/span>percurso \u00e9 realizado em 18 minutos<\/b><\/span><\/span><\/span>. A <\/b><\/span><\/span><\/span>rela\u00e7\u00e3o percentual <\/b><\/span><\/span><\/span>entre o <\/b><\/span><\/span><\/span>m\u00f3dulo da velocidade vetorial<\/b><\/span><\/span><\/span> <\/b>m\u00e9dia<\/b><\/span><\/span><\/span> desenvolvida pelo ciclista e a respectiva <\/b><\/span><\/span><\/span>velocidade escalar m\u00e9dia<\/b><\/span><\/span><\/span> deve ter sido mais pr\u00f3xima de:<\/b><\/span><\/span><\/span><\/p>\n

(A) 72%.<\/b><\/span><\/span><\/span><\/p>\n

(B) 74%.<\/b><\/span><\/span><\/span><\/p>\n

(C) 77%.<\/b><\/span><\/span><\/span><\/p>\n

(D) 76%.<\/b><\/span><\/span><\/span><\/p>\n

(E) 70%.<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

02\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

A figura mostra uma r\u00e9plica do Benz Patent Motorwagen, de 1885, carro de dois lugares e tr\u00eas rodas. O <\/b><\/span><\/span><\/span>di\u00e2metro da roda dianteira mede 60 cm, e o das rodas traseiras mede 80 cm<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/a><\/p>\n

Em um teste rec\u00e9m-realizado, o ve\u00edculo <\/b><\/span><\/span><\/span>percorreu<\/b><\/span><\/span><\/span>, em linha reta, <\/b><\/span><\/span><\/span>7,2 km em 12 minutos<\/b><\/span><\/span><\/span>, mantendo sua <\/b><\/span><\/span><\/span>velocidade praticamente constante<\/b><\/span><\/span><\/span>. Assim, considerando <\/b><\/span><\/span><\/span>\u03c0 = 3<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span><\/span>frequ\u00eancia de giro das rodas dianteira e traseiras deve ter sido<\/b><\/span><\/span><\/span>, em <\/b><\/span><\/span><\/span>Hz<\/b><\/span><\/span><\/span>, aproximada e respectivamente, de<\/b><\/span><\/span><\/span><\/p>\n

(A) 5,5 e 4,2.<\/b><\/span><\/span><\/span><\/p>\n

(B) 5,5 e 4,4.<\/b><\/span><\/span><\/span><\/p>\n

(C) 5,6 e 4,2.<\/b><\/span><\/span><\/span><\/p>\n

(D) 5,6 e 4,4.<\/b><\/span><\/span><\/span><\/p>\n

(E) 5,8 e 4,5.<\/b><\/span><\/span><\/span><\/p>\n

03\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Uma pessoa est\u00e1 segurando um livro no interior de um elevador em <\/b><\/span><\/span><\/span>movimento vertical, uniforme e descendente<\/b><\/span><\/span><\/span>. Em determinado instante, rompe-se o cabo de sustenta\u00e7\u00e3o do elevador e ele passa a <\/b><\/span><\/span><\/span>cair em queda livre<\/b><\/span><\/span><\/span>. De susto, a pessoa solta o livro. A <\/b><\/span><\/span><\/span>a\u00e7\u00e3o dissipativa do ar ou de outro tipo de atrito \u00e9 desprez\u00edvel<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

<\/b>A partir do momento em que \u00e9 abandonado, e enquanto o elevador n\u00e3o tocar o ch\u00e3o, o livro<\/b><\/span><\/span><\/span><\/p>\n

(A) cair\u00e1, atingindo o piso rapidamente, com acelera\u00e7\u00e3o maior que a do elevador, para um observador em referencial n\u00e3o inercial, dentro do elevador.<\/b><\/span><\/span><\/span><\/p>\n

(B) manter\u00e1 um movimento uniforme de queda em rela\u00e7\u00e3o \u00e0 pessoa, que est\u00e1 em referencial n\u00e3o inercial, podendo at\u00e9 atingir seu piso.<\/b><\/span><\/span><\/span><\/p>\n

(C) cair\u00e1 em queda livre tamb\u00e9m, com acelera\u00e7\u00e3o igual \u00e0 do elevador, e n\u00e3o ir\u00e1 atingir seu piso, para qualquer observador em referencial inercial.<\/b><\/span><\/span><\/span><\/p>\n

(D) dever\u00e1 subir em rela\u00e7\u00e3o aos olhos da pessoa, que est\u00e1 em um referencial n\u00e3o inercial, pois sua acelera\u00e7\u00e3o ser\u00e1 menor que a do elevador.<\/b><\/span><\/span><\/span><\/p>\n

(E) manter\u00e1 um movimento uniforme de subida em rela\u00e7\u00e3o aos olhos da pessoa, que est\u00e1 em referencial n\u00e3o inercial, podendo at\u00e9 atingir seu teto.<\/b><\/span><\/span><\/span><\/p>\n

04\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Sobre uma pista retil\u00ednea, lisa e horizontal, <\/b><\/span><\/span><\/span>dois m\u00f3veis, A e B, de massas m<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/sub><\/span> = 100 kg e m<\/b><\/span><\/span><\/span>B<\/b><\/span><\/span><\/sub><\/span> = 60 kg, s\u00e3o lan\u00e7ados em sentidos opostos<\/b><\/span><\/span><\/span>, indo colidir frontalmente. O <\/b><\/span><\/span><\/span>gr\u00e1fico hor\u00e1rio (1) mostra as posi\u00e7\u00f5es que A e B ocupam sobre a pista at\u00e9 colidirem no instante t = 4,0 s<\/b><\/span><\/span><\/span>. <\/b><\/span><\/span><\/span>O gr\u00e1fico (2) mostra as posi\u00e7\u00f5es ocupadas pelo m\u00f3vel A ap\u00f3s a colis\u00e3o e cinco poss\u00edveis percursos para o m\u00f3vel B<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/a><\/p>\n

O percurso correto \u00e9 o<\/b><\/span><\/span><\/span><\/p>\n

(A) B<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(B) B<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(C) B<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(D) B<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

(E) B<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

05\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

As <\/b><\/span><\/span><\/span>leis da gravita\u00e7\u00e3o universal<\/b><\/span><\/span><\/span>, aplicadas ao movimento de planetas e sat\u00e9lites em \u00f3rbita est\u00e1vel, permitem concluir que <\/b><\/span><\/span><\/span>a energia cin\u00e9tica desses corpos depende de sua massa, da massa do centro de for\u00e7as em torno do qual orbitam e da dist\u00e2ncia m\u00fatua entre eles <\/b><\/span><\/span><\/span>(raio orbital). Assim, o <\/b><\/span><\/span><\/span>gr\u00e1fico que melhor representa qualitativamente a energia cin\u00e9tica (Ec) de planeta ou sat\u00e9lite em \u00f3rbita est\u00e1vel, em fun\u00e7\u00e3o do raio orbital (r), <\/b><\/span><\/span><\/span>\u00e9 o ilustrado em:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/a><\/span><\/span><\/span><\/p>\n

06\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

No circuito ideal esquematizado na figura, o gerador fornece uma<\/b><\/span><\/span><\/span> tens\u00e3o cont\u00ednua de 200 V<\/b><\/span><\/span><\/span>. As resist\u00eancias dos resistores \u00f4hmicos<\/b><\/span><\/span><\/span> s\u00e3o R<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = R<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span> = 20 \u03a9, R<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = 60 \u03a9 e a capacit\u00e2ncia do capacitor \u00e9 C = 2,0.10<\/b><\/span><\/span><\/span>-6 <\/b><\/span><\/span><\/sup><\/span>F<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/a><\/p>\n

Nessas condi\u00e7\u00f5es, a <\/b><\/span><\/span><\/span>quantidade de carga acumulada no capacitor ser\u00e1<\/b><\/span><\/span><\/span>, em C, igual a<\/b><\/span><\/span><\/span><\/p>\n

(A) 2,4.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span><\/p>\n

(B) 2,4.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span><\/p>\n

(C) 1,2.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span><\/p>\n

(D) 1,2.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span><\/p>\n

(E) 2,0.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span><\/p>\n

07\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Jos\u00e9 M\u00e1rio \u00e9 um homem que mant\u00e9m sua condi\u00e7\u00e3o f\u00edsica fazendo caminhadas em torno do condom\u00ednio em que reside. Em dias de chuva, ele compensa subindo a escadaria do pr\u00e9dio, a partir do t\u00e9rreo at\u00e9 o seu apartamento, no <\/b><\/span><\/span><\/span>10\u00ba andar<\/b><\/span><\/span><\/span>. <\/b><\/span><\/span><\/span>O desn\u00edvel entre 2 andares consecutivos \u00e9 de 3,0 m. <\/b><\/span><\/span><\/span>Jos\u00e9 M\u00e1rio <\/b><\/span><\/span><\/span>pesa 800 N<\/b><\/span><\/span><\/span>. <\/b><\/span><\/span><\/span>Se<\/b><\/span><\/span><\/span> <\/b>fosse poss\u00edvel converter toda a energia potencial acumulada nessa subida em energia el\u00e9trica para acender um circuito de 10 l\u00e2mpadas de LED, de 5 W cada, o circuito permaneceria aceso, ininterruptamente, por<\/b><\/span><\/span><\/span><\/p>\n

<\/b>(A) 8,0 min.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(B) 4,2 min.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(C) 6,0 min.<\/b><\/span><\/span><\/span><\/span><\/p>\n

<\/b>(D) 2,4 min.<\/b><\/span><\/span><\/span><\/p>\n

(E) 7,2 min.<\/b><\/span><\/span><\/span><\/p>\n

08\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

O esquema da figura ilustra o perfil de uma cuba de ondas de profundidade espraiada, cheia de \u00e1gua. \u00c9 uma simula\u00e7\u00e3o do que acontece na realidade em uma praia marinha.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/a><\/p>\n

Uma fonte vibrat\u00f3ria F, localizada na parte profunda da cuba, produz frentes de onda retas, paralelas \u00e0 \u201cpraia\u201d, com frequ\u00eancia f. Sabe-se que <\/b><\/span><\/span><\/span>ondas mec\u00e2nicas na \u00e1gua sofrem mais refring\u00eancia com a diminui\u00e7\u00e3o da profundidade<\/b><\/span><\/span><\/span>. Considerando as velocidades v<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> e v<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> de propaga\u00e7\u00e3o das frentes de onda nas profundidades h<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> e h<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>, respectivamente, assim como os comprimentos de onda \u03bb<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> e \u03bb<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> e frequ\u00eancias de oscila\u00e7\u00e3o f<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> e f<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>, <\/b><\/span><\/span><\/span>s\u00e3o corretas as rela\u00e7\u00f5es de ordem:<\/b><\/span><\/span><\/span><\/p>\n

(A) v<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > v<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>, \u03bb<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = \u03bb<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> e f<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > f<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span><\/p>\n

(B) v<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > v<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>, \u03bb<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > \u03bb<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> e f<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = f<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span><\/p>\n

(C) v<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > v<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>, \u03bb<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > \u03bb<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> e f<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > f<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span><\/p>\n

(D) v<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = v<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>, \u03bb<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > \u03bb<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> e f<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > f<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span><\/p>\n

(E) v<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> > v<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>, \u03bb<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = \u03bb<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> e f<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = f<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span><\/p>\n

09\u2013 Insper \u2013 SP – 2019<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

O gr\u00e1fico da figura ilustra qualitativamente <\/b><\/span><\/span><\/span>a varia\u00e7\u00e3o da press\u00e3o (p)<\/b><\/span><\/span><\/span> exercida pelo combust\u00edvel\/g\u00e1s de um pist\u00e3o do motor de um ve\u00edculo, <\/b><\/span><\/span><\/span>em fun\u00e7\u00e3o do volume (V) <\/b><\/span><\/span><\/span>ocupado pelo combust\u00edvel\/ g\u00e1s no interior da c\u00e2mara de combust\u00e3o, durante um ciclo. <\/b><\/span><\/span><\/span>O rendimento do motor \u00e9 de 40%<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/a><\/p>\n

O <\/b><\/span><\/span><\/span>calor fornecido a esse sistema pela fonte quente durante um ciclo<\/b><\/span><\/span><\/span>, em fun\u00e7\u00e3o dos dados, est\u00e1 corretamente expresso por:<\/b><\/span><\/span><\/span><\/p>\n

<\/b>(A) 2,5.(V<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span>\u2013V<\/b><\/span><\/span><\/span><\/span>1<\/b><\/span><\/span><\/span><\/sub><\/span>).(p<\/b><\/span><\/span><\/span><\/span>3<\/b><\/span><\/span><\/span><\/sub><\/span>\u2013p<\/b><\/span><\/span><\/span><\/span>1<\/b><\/span><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span><\/span><\/p>\n

(B) 2,5.(V<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span>\u2013V<\/b><\/span><\/span><\/span><\/span>1<\/b><\/span><\/span><\/span><\/sub><\/span>).(p<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span>\u2013p<\/b><\/span><\/span><\/span><\/span>1<\/b><\/span><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span><\/span><\/p>\n

(C) 0,4.(V<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span>\u2013V<\/b><\/span><\/span><\/span><\/span>1<\/b><\/span><\/span><\/span><\/sub><\/span>).(p<\/b><\/span><\/span><\/span><\/span>3<\/b><\/span><\/span><\/span><\/sub><\/span>\u2013p<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span><\/span><\/p>\n

(D) 2,5.(V<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span>\u2013V<\/b><\/span><\/span><\/span><\/span>1<\/b><\/span><\/span><\/span><\/sub><\/span>).(p<\/b><\/span><\/span><\/span><\/span>3<\/b><\/span><\/span><\/span><\/sub><\/span>\u2013p<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span><\/span><\/p>\n

<\/b>(E) 0,4.(V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u2013V<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>).(p<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>\u2013p<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span><\/p>\n

Resolu\u00e7\u00e3o Comentada<\/b><\/span><\/span><\/span><\/p>\n

<\/b>01) <\/b><\/span><\/span><\/span><\/p>\n

Vamos fazer um esbo\u00e7o com base no enunciado:<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

<\/p>\n

<\/b><\/p>\n

03- <\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

<\/p>\n

04-<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

\"\"<\/a><\/p>\n

<\/p>\n

\"\"<\/a><\/p>\n

<\/p>\n

    \n
  1. \n

    Para :<\/b><\/span><\/span><\/span><\/p>\n<\/li>\n

  2. <\/li>\n<\/ol>\n

    <\/p>\n

    05-<\/b><\/span><\/span><\/span><\/p>\n

    <\/p>\n

    <\/p>\n

    <\/p>\n

    \"\"<\/a><\/p>\n

    <\/b>Logo, a <\/b><\/span><\/span><\/span>alternativa correta \u00e9 a E<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

    <\/b>06-<\/b><\/span><\/span><\/span><\/p>\n

    O <\/b><\/span><\/span><\/span>diagrama das tens\u00f5es no circuito \u00e9 esbo\u00e7ado na figura abaixo<\/b><\/span><\/span><\/span>:<\/b><\/span><\/span><\/span><\/p>\n

    <\/p>\n

    Repare que <\/b><\/span><\/span><\/span>n\u00e3o h\u00e1 corrente fluindo no n\u00f3 do capacitor<\/b><\/span><\/span><\/span>, isto acontece porque o <\/b><\/span><\/span><\/span>mesmo est\u00e1 carregado<\/b><\/span><\/span><\/span>, impedindo que flua corrente neste trecho do circuito. Embora n\u00e3o exista corrente, o <\/b><\/span><\/span><\/span>capacitor ainda est\u00e1 sujeito \u00e0 uma diferen\u00e7a de potencial<\/b><\/span><\/span><\/span>, que \u00e9 <\/b><\/span><\/span><\/span>igual \u00e0 do segundo resistor<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>visto que est\u00e3o ligados em paralelo<\/b><\/span><\/span><\/span>. A <\/b><\/span><\/span><\/span>equa\u00e7\u00e3o da malha <\/b><\/span><\/span><\/span>\u00e9 a seguinte:<\/b><\/span><\/span><\/span><\/p>\n

    <\/b>Logo, a alternativa correta \u00e9 a A<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

    <\/b>8)<\/b><\/span><\/span><\/span><\/p>\n

    <\/b>Para uma onda<\/b><\/span><\/span><\/span>, temos que:<\/b><\/span><\/span><\/span><\/p>\n

    Em que <\/b><\/span><\/span><\/span> \u00e9 o \u00edndice de refra\u00e7\u00e3o<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span> \u00e9 a velocidade da onda no meio<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span><\/span> \u00e9 a velocidade da onda em algum meio utilizado como par\u00e2metro<\/b><\/span><\/span><\/span> (<\/b><\/span><\/span><\/span>neste exerc\u00edcio o valor quantitativo deste par\u00e2metro n\u00e3o \u00e9 essencial, mas na \u00f3ptica, por exemplo, \u00e9 utilizada a velocidade da luz<\/b><\/span><\/span><\/span>).<\/b><\/span><\/span><\/span><\/p>\n

    Outro ponto importante para a resolu\u00e7\u00e3o do exerc\u00edcio \u00e9 que a <\/b><\/span><\/span><\/span>frequ\u00eancia depende exclusivamente da fonte<\/b><\/span><\/span><\/span>, e n\u00e3o do meio ao qual incide.<\/b><\/span><\/span><\/span><\/p>\n

    <\/b>Podemos reescrever as velocidades e utilizando o \u00edndice de refra\u00e7\u00e3o<\/b><\/span><\/span><\/span>:<\/b><\/span><\/span><\/span><\/p>\n

    <\/b>Em que \u00e9 o trabalho entregue pelo g\u00e1s e \u00e9 o calor entregue ao g\u00e1s pelo reservat\u00f3rio de calor<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

    <\/b>O trabalho entregue pelo g\u00e1s pode ser obtido calculando-se a \u00e1rea resultante abaixo da curva em um diagrama PxV, visto que<\/b><\/span><\/span><\/span>:<\/b><\/span><\/span><\/span><\/p>\n

    <\/a> <\/b>A \u00e1rea abaixo da curva \u00e9 esbo\u00e7ada na figura <\/b><\/span><\/span><\/span>abaixo:<\/b><\/span><\/span><\/span><\/p>\n

    \"Insper\"<\/p>\n

    <\/b><\/p>\n

    \n

    Clique aqui para ver sobre o tema!<\/a><\/p>\n

    Confira as v\u00eddeo aulas!<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

    Vestibular\u00a0Insper 2019\u00a0 O\u00a0Insper\u00a0\u00e9 uma institui\u00e7\u00e3o de\u00a0ensino superior\u00a0brasileira\u00a0que atua nas \u00e1reas de\u00a0neg\u00f3cios,\u00a0economia,\u00a0direito,\u00a0engenharia mec\u00e2nica,\u00a0engenharia mecatr\u00f4nica\u00a0e\u00a0engenharia da computa\u00e7\u00e3o. Est\u00e1 localizada em S\u00e3o Paulo (capital Somos\u00a0uma institui\u00e7\u00e3o de\u00a0ensino superior\u00a0e de\u00a0pesquisa\u00a0sem fins lucrativos que reverte todo o resultado operacional para a realiza\u00e7\u00e3o de nossa\u00a0miss\u00e3o. O Programa de Bolsas de Estudo foi criado para garantir o acesso ao Insper aos jovens aprovados no processo seletivo e<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":4337,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-4499","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4499","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=4499"}],"version-history":[{"count":5,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4499\/revisions"}],"predecessor-version":[{"id":10258,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4499\/revisions\/10258"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4337"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=4499"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}