{"id":4085,"date":"2018-07-20T17:53:39","date_gmt":"2018-07-20T17:53:39","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=4085"},"modified":"2024-08-21T17:19:13","modified_gmt":"2024-08-21T17:19:13","slug":"cinematica-10-lancamento-obliquo","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/formulario\/cinematica-10-lancamento-obliquo\/","title":{"rendered":"Cinem\u00e1tica 10 – LAN\u00c7AMENTO OBL\u00cdQUO"},"content":{"rendered":"

Formul\u00e1rio completo de F\u00edsica com informa\u00e7\u00f5es \u00fateis <\/b><\/span><\/span><\/span><\/p>\n

(dicas para vestibulares)<\/b><\/span><\/span><\/span><\/p>\n

Cinem\u00e1tica 10<\/b><\/span><\/span><\/span><\/p>\n

LAN\u00c7AMENTO OBL\u00cdQUO<\/b><\/span><\/span><\/span><\/p>\n

Decomposi\u00e7\u00e3o do movimento obl\u00edquo<\/b><\/span><\/span><\/span><\/p>\n

O\u00a0<\/b><\/span><\/span><\/span>movimento obl\u00edquo<\/b><\/span><\/span><\/span>\u00a0\u00e9\u00a0<\/b><\/span><\/span><\/span>decomposto<\/b><\/span><\/span><\/span>\u00a0num movimento segundo a\u00a0<\/b><\/span><\/span><\/span>dire\u00e7\u00e3o horizontal (eixo X<\/b><\/span><\/span><\/span>) e\u00a0<\/b><\/span><\/span><\/span>outro segundo a dire\u00e7\u00e3o vertical (eixo Y).<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

\u00a0Assim, na <\/b><\/span><\/span><\/span>dire\u00e7\u00e3o\u00a0vertica<\/b><\/span><\/span><\/span>l<\/b><\/span><\/span><\/span>, voc\u00ea tem um\u00a0<\/b><\/span><\/span><\/span>lan\u00e7amento vertical para cima<\/b><\/span><\/span><\/span>, com acelera\u00e7\u00e3o igual \u00e0\u00a0<\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o da gravidade\u00a0<\/b><\/span><\/span><\/span>\u00a0e\u00a0<\/b><\/span><\/span><\/span>velocidade inicial de lan\u00e7amento\u00a0<\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>oy<\/b><\/span><\/span><\/sub><\/span>, tal que\u00a0<\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>oy<\/b><\/span><\/span><\/sub><\/span>=V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.sen\u03b1, onde \u03b1 \u00e9 o \u00e2ngulo de lan\u00e7amento.<\/b><\/span><\/span><\/span><\/p>\n

Equa\u00e7\u00f5es do movimento na dire\u00e7\u00e3o vertical<\/b><\/span><\/span><\/span><\/p>\n

Movimento parcial na dire\u00e7\u00e3o horizontal (eixo X)<\/b><\/span><\/span><\/span><\/p>\n

Sendo o\u00a0<\/b><\/span><\/span><\/span>movimento apenas na horizontal,<\/b><\/span><\/span><\/span>\u00a0a\u00a0<\/b><\/span><\/span><\/span>proje\u00e7\u00e3o do vetor acelera\u00e7\u00e3o da gravidade (<\/b><\/span><\/span><\/span>) no eixo X \u00e9 nula, ou seja, na dire\u00e7\u00e3o horizontal do lan\u00e7amento obl\u00edquo n\u00e3o existe acelera\u00e7\u00e3o\u00a0<\/b><\/span><\/span><\/span>e, nesse caso o\u00a0<\/b><\/span><\/span><\/span>movimento \u00e9 <\/b><\/span><\/span><\/span>uniforme (MU)<\/b><\/span><\/span><\/span>\u00a0com velocidade constante\u00a0<\/b><\/span><\/span><\/span>Vox\u00a0= Vocos\u03b1.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Informa\u00e7\u00f5es \u00fateis (dicas)<\/b><\/span><\/span><\/span><\/p>\n

Movimento parcial na <\/b><\/span><\/span><\/span>Vertical (eixo Y)<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span>Na<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>subida<\/b><\/span><\/span><\/span>, o\u00a0<\/b><\/span><\/span><\/span>movimento \u00e9 progressivo,<\/b><\/span><\/span><\/span>\u00a0pois o\u00a0<\/b><\/span><\/span><\/span>deslocamento<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>ocorre no<\/b><\/span><\/span><\/span> <\/b>sentido crescente da trajet\u00f3ria, e retardado, pois o m\u00f3dulo da velocidade est\u00e1 diminuindo.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span>Na<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>descida<\/b><\/span><\/span><\/span>, o\u00a0<\/b><\/span><\/span><\/span>movimento \u00e9 retr\u00f3grado,<\/b><\/span><\/span><\/span>\u00a0pois o\u00a0<\/b><\/span><\/span><\/span>deslocamento<\/b><\/span><\/span><\/span>\u00a0ocorre no<\/b><\/span><\/span><\/span>sentido decrescente da trajet\u00f3ria, e acelerado, pois o m\u00f3dulo da velocidade est\u00e1 aumentando.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span>No\u00a0<\/b><\/span><\/span><\/span>ponto mais alto da trajet\u00f3ria,<\/b><\/span><\/span><\/span>\u00a0a\u00a0<\/b><\/span><\/span><\/span>velocidade do corpo se anula\u00a0<\/b><\/span><\/span><\/span>(V<\/b><\/span><\/span><\/span>y<\/b><\/span><\/span><\/sub><\/span>\u00a0= 0)<\/b><\/span><\/span><\/span>, pois \u00e9 o\u00a0<\/b><\/span><\/span><\/span>ponto em que o corpo inverte o sentido de seu movimento e nesse ponto a altura atingida pelo corpo \u00e9 m\u00e1xima.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0O\u00a0<\/b><\/span><\/span><\/span>tempo de\u00a0<\/b><\/span><\/span><\/span>subida<\/b><\/span><\/span><\/span>\u00a0\u00e9 igual ao tempo de\u00a0<\/b><\/span><\/span><\/span>descida.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0A\u00a0<\/b><\/span><\/span><\/span>velocidade\u00a0<\/b><\/span><\/span><\/span>(V<\/b><\/span><\/span><\/span>oy<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span>\u00a0de\u00a0<\/b><\/span><\/span><\/span>lan\u00e7amento na origem\u00a0<\/b><\/span><\/span><\/span>\u00e9 igual \u00e0\u00a0<\/b><\/span><\/span><\/span>mesma velocidade de chegada \u00e0 origem,<\/b><\/span><\/span><\/span>\u00a0mas de sinal contr\u00e1rio\u00a0<\/b><\/span><\/span><\/span>(-V<\/b><\/span><\/span><\/span>oy<\/b><\/span><\/span><\/sub><\/span>).<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span>Em\u00a0<\/b><\/span><\/span><\/span>qualquer<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>ponto da trajet\u00f3ria o corpo tem\u00a0<\/b><\/span><\/span><\/span>duas velocidades de <\/b><\/span><\/span><\/span>mesmo m\u00f3dulo<\/b><\/span><\/span><\/span>,<\/b><\/span><\/span><\/span>\u00a0uma\u00a0<\/b><\/span><\/span><\/span>positiva na subida e uma negativa na descida.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Representa\u00e7\u00e3o gr\u00e1fica do movimento na vertical<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Movimento parcial na dire\u00e7\u00e3o horizontal (eixo X)<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

<\/p>\n

\u00a0O\u00a0<\/b><\/span><\/span><\/span>alcance \u00e9 m\u00e1ximo<\/b><\/span><\/span><\/span> quando \u03b1 = 45<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>\u00a0e nesse caso o alcance X<\/b><\/span><\/span><\/span>m\u00e1x<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00e9 <\/b><\/span><\/span><\/span>quatro vezes maior<\/b><\/span><\/span><\/span> que a <\/b><\/span><\/span><\/span>altura m\u00e1xima alcan\u00e7ada (h<\/b><\/span><\/span><\/span>m\u00e1x<\/b><\/span><\/span><\/sub><\/span>)\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00a0 X<\/b><\/span><\/span><\/span>m\u00e1x <\/b><\/span><\/span><\/sub><\/span>= 4<\/b><\/span><\/span><\/span>hm\u00e1x<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span>\u00a0<\/span><\/p>\n

<\/p>\n

<\/p>\n

\u00a0Se os\u00a0<\/b><\/span><\/span><\/span>dois \u00e2ngulos de lan\u00e7amento forem\u00a0<\/b><\/span><\/span><\/span>complementares entre si <\/b><\/span><\/span><\/span>(\u03b1<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0+ \u03b1<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0= 90<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>e a\u00a0<\/b><\/span><\/span><\/span>velocidade inicial for a mesma,<\/b><\/span><\/span><\/span> o <\/b><\/span><\/span><\/span>alcance horizontal \u00e9 o mesmo.<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

\u00a0Exemplo <\/b><\/span><\/span><\/span>na figura acima.<\/b><\/span><\/span><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

Formul\u00e1rio completo de F\u00edsica com informa\u00e7\u00f5es \u00fateis (dicas para vestibulares) Cinem\u00e1tica 10 LAN\u00c7AMENTO OBL\u00cdQUO Decomposi\u00e7\u00e3o do movimento obl\u00edquo O\u00a0movimento obl\u00edquo\u00a0\u00e9\u00a0decomposto\u00a0num movimento segundo a\u00a0dire\u00e7\u00e3o horizontal (eixo X) e\u00a0outro segundo a dire\u00e7\u00e3o vertical (eixo Y). \u00a0Assim, na dire\u00e7\u00e3o\u00a0vertical, voc\u00ea tem um\u00a0lan\u00e7amento vertical para cima, com acelera\u00e7\u00e3o igual \u00e0\u00a0acelera\u00e7\u00e3o da gravidade\u00a0\u00a0e\u00a0velocidade inicial de lan\u00e7amento\u00a0Voy, tal que\u00a0Voy=Vo.sen\u03b1, onde \u03b1 \u00e9 o \u00e2ngulo de lan\u00e7amento.<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3987,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-4085","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4085","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=4085"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4085\/revisions"}],"predecessor-version":[{"id":10762,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/4085\/revisions\/10762"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3987"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=4085"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}