{"id":3997,"date":"2018-06-25T04:54:05","date_gmt":"2018-06-25T04:54:05","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3997"},"modified":"2024-08-22T12:59:52","modified_gmt":"2024-08-22T12:59:52","slug":"dinamica-5-peso-e-massa","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/formulario\/dinamica-5-peso-e-massa\/","title":{"rendered":"Din\u00e2mica 5 – Peso e Massa"},"content":{"rendered":"

Formul\u00e1rio completo de F\u00edsica com informa\u00e7\u00f5es \u00fateis <\/b><\/span><\/span><\/span><\/p>\n

(dicas para vestibulares)<\/b><\/span><\/span><\/span><\/p>\n

Din\u00e2mica 5<\/b><\/span><\/span><\/span><\/p>\n

Peso e Massa\u00a0<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

Massa<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

A <\/b><\/span><\/span>massa uma\u00a0grandeza escalar, positiva\u00a0e\u00a0invari\u00e1vel para cada corpo n\u00e3o dependendo do lugar onde ele se\u00a0encontra.<\/b><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

Peso<\/b><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

<\/p>\n

Em\u00a0pontos <\/b><\/span><\/span><\/span>pr\u00f3ximos \u00e0 superf\u00edcie da Terra,<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>desprezando-se a resist\u00eancia do ar<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>os corpos caem <\/b><\/span><\/span><\/span>com\u00a0<\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o vari\u00e1vel pr\u00f3xima de 9,8m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0<\/b><\/span><\/span><\/span>que, quando\u00a0<\/b><\/span><\/span><\/span>n\u00e3o for especi<\/b><\/span><\/span><\/span>ficada podemos considerar como sendo de\u00a0<\/b><\/span><\/span><\/span>10m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

Apoio horizontal m\u00f3vel\u00a0<\/b><\/span><\/span><\/span>(peso aparente, elevadores)<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

Observa\u00e7\u00f5es:<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

\u00a0<\/span><\/p>\n

<\/p>\n

\u00a0<\/span>Lembre-se<\/b><\/span><\/span><\/span>\u00a0de que, se o\u00a0<\/b><\/span><\/span><\/span>cabo do elevador quebrar<\/b><\/span><\/span><\/span>, tanto\u00a0<\/b><\/span><\/span><\/span>ele como o homem\u00a0<\/b><\/span><\/span><\/span>caem em queda livre,<\/b><\/span><\/span><\/span>\u00a0com a\u00a0<\/b><\/span><\/span><\/span>mesma acelera\u00e7\u00e3o g<\/b><\/span><\/span><\/span>\u00a0e consequentemente com a\u00a0<\/b><\/span><\/span><\/span>mesma velocidade em cada instante, e a balan\u00e7a indicar\u00e1 zero (N = 0).<\/b><\/span><\/span><\/span><\/p>\n

<\/p>\n

Informa\u00e7\u00f5es \u00fateis <\/b><\/span><\/span><\/span><\/span>(dicas de vestibulares)<\/b><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

<\/p>\n

Dinam\u00f4metro<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>\u00a0\u00a0<\/b><\/span><\/span>Instrumento que mede a\u00a0<\/b><\/span><\/span>intensidade do peso de um corpo.<\/b><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

Um\u00a0<\/b><\/span><\/span><\/span>quilograma-for\u00e7a<\/b><\/span><\/span><\/span> \u00e9 o peso de um corpo de massa 1kg,<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>num local em que <\/b><\/span><\/span><\/span>aacelera\u00e7\u00e3o da<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>gravidade vale\u00a09,806m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0que podemos\u00a0arredondar para 10m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\u00c9 a <\/b><\/span><\/span><\/span>unidade de intensidade de for\u00e7a <\/b><\/span><\/span><\/span>no\u00a0<\/b><\/span><\/span><\/span>sistema t\u00e9cnico de unidades<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n

<\/p>\n

A\u00a0<\/b><\/span><\/span><\/span>intensidade da for\u00e7a peso\u00a0diminui <\/b><\/span><\/span><\/span>com a\u00a0<\/b><\/span><\/span><\/span>altitude na Terra ou em qualquer outro planeta.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

Desprezando-se a resist\u00eancia do ar<\/b><\/span><\/span><\/span>, dois corpos\u00a0<\/b><\/span><\/span><\/span>abandonados de uma mesma altura da superf\u00edcie da Terra, tem a mesma acelera\u00e7\u00e3o da gravidade (g) e consequentemente chegam juntos ao solo, independente de suas massas.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

Uma\u00a0<\/b><\/span><\/span>formiga de massa m<\/b><\/span><\/span>f<\/b><\/span><\/sub><\/span>\u00a0<\/b><\/span><\/span>e um\u00a0<\/b><\/span><\/span>elefante de massa M<\/b><\/span><\/span>e<\/b><\/span><\/sub><\/span>, em queda livre, sem ar:<\/b><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

Assim,\u00a0<\/b><\/span><\/span>desprezando-se a\u00a0<\/b><\/span><\/span>resist\u00eancia do ar<\/b><\/span><\/span>, um\u00a0<\/b><\/span><\/span>elefante e uma formiga<\/b><\/span><\/span>, quando abandonados da\u00a0<\/b><\/span><\/span>mesma altura, chegam ao solo ao mesmo tempo e, claro que com a mesma velocidade.<\/b><\/span><\/span><\/span><\/span><\/p>\n

<\/p>\n

<\/p>\n","protected":false},"excerpt":{"rendered":"

Formul\u00e1rio completo de F\u00edsica com informa\u00e7\u00f5es \u00fateis (dicas para vestibulares) Din\u00e2mica 5 Peso e Massa\u00a0 Massa A massa uma\u00a0grandeza escalar, positiva\u00a0e\u00a0invari\u00e1vel para cada corpo n\u00e3o dependendo do lugar onde ele se\u00a0encontra. Peso Em\u00a0pontos pr\u00f3ximos \u00e0 superf\u00edcie da Terra,\u00a0desprezando-se a resist\u00eancia do ar, os corpos caem com\u00a0acelera\u00e7\u00e3o vari\u00e1vel pr\u00f3xima de 9,8m\/s2\u00a0que, quando\u00a0n\u00e3o for especificada podemos considerar como sendo de\u00a010m\/s2. Apoio horizontal<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3987,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3997","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3997","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3997"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3997\/revisions"}],"predecessor-version":[{"id":3998,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3997\/revisions\/3998"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3987"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3997"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}