{"id":3915,"date":"2018-04-30T15:50:58","date_gmt":"2018-04-30T15:50:58","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3915"},"modified":"2024-09-04T12:38:24","modified_gmt":"2024-09-04T12:38:24","slug":"resolucao-comentada-das-questoes-de-fisica-da-universidade-do-estado-do-rio-de-janeiro-uerj-2018","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2018\/resolucao-comentada-das-questoes-de-fisica-da-universidade-do-estado-do-rio-de-janeiro-uerj-2018\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da Universidade do Estado do Rio de Janeiro (UERJ) \u2013 2018"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da <\/span><\/span><\/span><\/p>\n

Universidade do Estado do Rio de Janeiro (UERJ) \u2013 2018<\/span><\/span><\/span><\/p>\n

01-<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

02-<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

03-<\/span><\/span><\/span><\/p>\n

O <\/b><\/span><\/span><\/span>foco dessa lente convergente est\u00e1 a 60 cm de seu centro \u00f3ptico<\/b><\/span><\/span><\/span> (f= 60 cm), pois <\/b><\/span><\/span><\/span>todo raio de luz que incide na lente paralelamente ao eixo principal (proveniente de uma dist\u00e2ncia muito grande,<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

como do Sol)<\/b><\/span><\/span><\/span>, atinge a lente se <\/b><\/span><\/span><\/span>refratando e passando pelo foco.<\/b><\/span><\/span><\/span><\/p>\n

Assim, os <\/b><\/span><\/span><\/span>infinitos raios de luz provenientes do Sol, convergem sobre f = 60 cm.<\/b><\/span><\/span><\/span><\/p>\n


\nEqua\u00e7\u00e3o de Gauss<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

04-<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

05-<\/span><\/span><\/span><\/p>\n

Breve teoria<\/b><\/span><\/span><\/span><\/p>\n

Rela\u00e7\u00e3o entre pot\u00eancia m\u00e9dia (P<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span>) e velocidade m\u00e9dia (V<\/b><\/span><\/span><\/span>m<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span><\/p>\n

Considere uma\u00a0<\/b><\/span><\/span><\/span>for\u00e7a constante de intensidade F<\/b><\/span><\/span><\/span>\u00a0realizando um\u00a0<\/b><\/span><\/span><\/span>trabalho W<\/b><\/span><\/span><\/span>\u00a0num\u00a0<\/b><\/span><\/span><\/span>deslocamento d,<\/b><\/span><\/span><\/span>\u00a0de modo que a\u00a0<\/b><\/span><\/span><\/span>dire\u00e7\u00e3o de\u00a0F\u00a0forme um \u00e2ngulo\u00a0\u03b1<\/b><\/span><\/span><\/span>\u00a0com a\u00a0<\/b><\/span><\/span><\/span>dire\u00e7\u00e3o do deslocamento.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

06-<\/span><\/span><\/span><\/p>\n

Veja na <\/b><\/span><\/span><\/span>figura abaixo: V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 10 m\/s; V = 25 m\/s; t = 5s.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

C\u00e1lculo da acelera\u00e7\u00e3o \"\" V = V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> + a.t<\/b><\/span><\/span><\/span> \"\" 25 = 10 + a.5 \"\" a = \"\"<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>a = 3 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Determinando<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span><\/span>dist\u00e2ncia \u2206S que ele percorre <\/b><\/span><\/span><\/span>com <\/b><\/span><\/span><\/span>esses valores <\/b><\/span><\/span><\/span>pela <\/b><\/span><\/span><\/span>equa\u00e7\u00e3o de Torricelli \"\"<\/b><\/span><\/span><\/span> <\/b>V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> =<\/b><\/span><\/span><\/span><\/p>\n

V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span> + 2.a.\u2206S<\/b><\/span><\/span><\/span> \"\" 25<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> + 2.3.\u2206S \"\" 625 = 100 + 6.\u2206S \"\" \u2206S = 525\/6 \"\" <\/b><\/span><\/span><\/span>\u2206S = 87,5 m<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Como ele n\u00e3o ultrapassou a dist\u00e2ncia de 120 m, n\u00e3o ser\u00e1 multado.<\/b><\/span><\/span><\/span><\/p>\n

07-<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

08-<\/span><\/span><\/span><\/p>\n

Lei de Coulomb<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

A <\/b><\/span><\/span>express\u00e3o matem\u00e1tica <\/b><\/span><\/span>acima \u00e9 <\/b><\/span><\/span>denominada lei de Coulomb e de enunciado:<\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

09-<\/span><\/span><\/span><\/p>\n

Se voc\u00ea n\u00e3o domina a teoria ela est\u00e1 a seguir:<\/b><\/span><\/span><\/span><\/p>\n

Velocidade orbital (de transla\u00e7\u00e3o) de um sat\u00e9lite<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

10-<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

<\/a><\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da Universidade do Estado do Rio de Janeiro (UERJ) \u2013 2018 01- 02- 03- O foco dessa lente convergente est\u00e1 a 60 cm de seu centro \u00f3ptico (f= 60 cm), pois todo raio de luz que incide na lente paralelamente ao eixo principal (proveniente de uma dist\u00e2ncia muito grande, como do Sol), atinge a<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3353,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3915","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3915","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3915"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3915\/revisions"}],"predecessor-version":[{"id":3916,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3915\/revisions\/3916"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3353"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3915"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}