{"id":3900,"date":"2018-04-30T14:50:37","date_gmt":"2018-04-30T14:50:37","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3900"},"modified":"2024-09-04T12:50:33","modified_gmt":"2024-09-04T12:50:33","slug":"resolucao-comentada-das-questoes-de-fisica-da-universidade-de-fortaleza-unifor-2018","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2018\/unifor-2018\/resolucao-comentada-das-questoes-de-fisica-da-universidade-de-fortaleza-unifor-2018\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da Universidade de Fortaleza \u2013 UNIFOR – 2018"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da <\/b><\/span><\/span><\/span><\/p>\n

Universidade de Fortaleza \u2013 UNIFOR – 2018<\/b><\/span><\/span><\/span><\/p>\n

01-<\/b><\/span><\/span><\/span><\/p>\n

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02-<\/b><\/span><\/span><\/span><\/p>\n

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03-<\/b><\/span><\/span><\/span><\/p>\n

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04-<\/b><\/span><\/span><\/span><\/p>\n

O <\/b><\/span><\/span><\/span>comprimento de onda <\/b><\/span><\/span><\/span>\u0001<\/b><\/span><\/span><\/span> <\/b>corresponde \u00e0 <\/b><\/span><\/span><\/span>dist\u00e2ncia entre duas cristas sucessivas e vale <\/b><\/span><\/span><\/span>\u0001<\/b><\/span><\/span><\/span> = 3 cm.<\/b><\/span><\/span><\/span><\/p>\n

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A <\/b><\/span><\/span><\/span>amplitude A <\/b><\/span><\/span><\/span>equivale \u00e0 <\/b><\/span><\/span><\/span>dist\u00e2ncia entre o ponto m\u00e9dio 0 e \u00e0 altura m\u00e1xima ou \u00e0 altura m\u00ednima verticais e vale A = 1,1 cm.<\/b><\/span><\/span><\/span><\/p>\n

C\u00e1lculo do <\/b><\/span><\/span><\/span>per\u00edodo T <\/b><\/span><\/span><\/span>pela <\/b><\/span><\/span><\/span>equa\u00e7\u00e3o fundamental da ondulat\u00f3ria V = <\/b><\/span><\/span><\/span>\u0001<\/b><\/span><\/span><\/span>.f \"\"<\/b><\/span><\/span><\/span> 150 = 3.10<\/b><\/span><\/span><\/span>-2<\/b><\/span><\/span><\/sup><\/span>.f \"\" f = 150\/0,03 \"\" <\/b><\/span><\/span><\/span>f = 5 000 Hz \"\"<\/b><\/span><\/span><\/span> <\/b>T = 1\/f <\/b><\/span><\/span><\/span>= 1\/5000 \"\" <\/b><\/span><\/span><\/span>T =<\/b><\/span><\/span><\/span> 0,0002 <\/b><\/span><\/span><\/span>= 2.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span> s.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

05-<\/b><\/span><\/span><\/span><\/p>\n

Embaixo est\u00e1 um resumo.<\/b><\/span><\/span> Se estiver interessado, a teoria completa encontra-se em fisicaevestibular.com.br \u2013 Eletricidade \u2013 Eletromagnetismo – <\/b><\/span><\/span>Campo magn\u00e9tico originado por um condutor retil\u00edneo extenso percorrido por corrente el\u00e9trica<\/b><\/span><\/span><\/span><\/span><\/p>\n

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 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da Universidade de Fortaleza \u2013 UNIFOR – 2018 01- 02- 03- 04- O comprimento de onda \u0001 corresponde \u00e0 dist\u00e2ncia entre duas cristas sucessivas e vale \u0001 = 3 cm. A amplitude A equivale \u00e0 dist\u00e2ncia entre o ponto m\u00e9dio 0 e \u00e0 altura m\u00e1xima ou \u00e0 altura m\u00ednima verticais e vale A =<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3898,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3900","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3900","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3900"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3900\/revisions"}],"predecessor-version":[{"id":3902,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3900\/revisions\/3902"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3898"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3900"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}