{"id":3697,"date":"2018-02-13T16:45:25","date_gmt":"2018-02-13T16:45:25","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3697"},"modified":"2024-08-20T23:24:31","modified_gmt":"2024-08-20T23:24:31","slug":"resolucao-comentada-hidrostatica-densidade-e-pressao","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/enem\/hidrostatica-densidade-e-pressao\/resolucao-comentada-hidrostatica-densidade-e-pressao\/","title":{"rendered":"Hidrost\u00e1tica – Densidade e Press\u00e3o – Resolu\u00e7\u00e3o"},"content":{"rendered":"

\u00a0<\/span>Resolu\u00e7\u00e3o Comentada<\/b><\/span><\/span><\/span> <\/b><\/p>\n

Hidrost\u00e1tica<\/b><\/span><\/span><\/span><\/p>\n

Densidade e Press\u00e3o<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

01-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>I- Na hora mais quente, o volume aumenta e, num mesmo volume haveria menos massa\u00a0 —\u00a0\u00a0 voc\u00ea levaria preju\u00edzo\u00a0 — Falsa<\/b><\/span><\/span><\/span><\/p>\n

II- Com temperatura mais baixa, o volume diminui e, num mesmo volume haveria mais massa\u00a0 —\u00a0 voc\u00ea levaria vantagem\u00a0 —\u00a0 correta<\/b><\/span><\/span><\/span><\/p>\n

III- Correta\u00a0 —\u00a0 voc\u00ea estaria comprando o que realmente interessa, que \u00e9 a massa.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

02-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Em cada litro de \u00e1lcool hidratado t\u00eam-se\u00a0 —\u00a0 0,96L de \u00e1lcool (96%) e 0,04L de \u00e1gua (4%)\u00a0 —\u00a0 c\u00e1lculo da massa de \u00e1lcool\u00a0 —\u00a0 d<\/b><\/span><\/span><\/span>\u00e1lcool<\/b><\/span><\/span><\/sub><\/span>=m<\/b><\/span><\/span><\/span>\u00e1lcool<\/b><\/span><\/span><\/sub><\/span>\/V<\/b><\/span><\/span><\/span>\u00e1lcool<\/b><\/span><\/span><\/sub><\/span>\u00a0 — 800g\/L=m<\/b><\/span><\/span><\/span>\u00e1lcool<\/b><\/span><\/span><\/sub><\/span>\/0,96L\u00a0 —\u00a0m<\/b><\/span><\/span><\/span>\u00e1lcool<\/b><\/span><\/span><\/sub><\/span>=768g\u00a0 —\u00a0 massa de \u00e1gua\u00a0 —\u00a0 d<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span>=m<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span>\/V<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 1.000g\/L=m<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span>\/0,04L\u00a0 —\u00a0m<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span>=40g\u00a0 —\u00a0 d<\/b><\/span><\/span><\/span>mistura<\/b><\/span><\/span><\/sub><\/span>=(m<\/b><\/span><\/span><\/span>\u00e1lcool<\/b><\/span><\/span><\/sub><\/span>\u00a0+ m<\/b><\/span><\/span><\/span>\u00e1gua<\/b><\/span><\/span><\/sub><\/span>)\/V<\/b><\/span><\/span><\/span>mistura<\/b><\/span><\/span><\/sub><\/span>=(768 + 40)\/1\u00a0 —\u00a0 d<\/b><\/span><\/span><\/span>mistura<\/b><\/span><\/span><\/sub><\/span>=808g\/L\u00a0 —<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>R- E<\/b><\/span><\/span><\/span><\/p>\n

03-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Quando o corpo estiver na imin\u00eancia de flutuar, a densidade do corpo \u00e9 igual \u00e0 do l\u00edquido (mistura)\u00a0 —\u00a0 d<\/b><\/span><\/span><\/span>mistura<\/b><\/span><\/span><\/sub><\/span>=d<\/b><\/span><\/span><\/span>corpo<\/b><\/span><\/span><\/sub><\/span>=m\/V d<\/b><\/span><\/span><\/span>corpo<\/b><\/span><\/span><\/sub><\/span>=90\/100\u00a0 —\u00a0 d=0,9g\/cm<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>R- A\u00a0<\/b><\/span><\/span><\/span><\/p>\n

04-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u03c1<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>=m<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>\/V<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>=80\/10=8g\/cm<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u03c1<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>=m<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>\/V<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>=0,8g\/cm<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u03c1<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>\/\u03c1<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>=8\/0,8=10\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>R- C<\/b><\/span><\/span><\/span><\/p>\n

05-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Se a massa \u00e9 a mesma, a massa espec\u00edfica \u00e9 inversamente proporcional ao volume (\u03c1=m\/V), assim, o cone circular reto \u00e9 o que tem menor volume e dever\u00e1 ter maior massa espec\u00edfica\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>R- D<\/b><\/span><\/span><\/span><\/p>\n

06-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Sendo o tijolo o mesmo, sua massa, seu volume e\u00a0 seu peso (que \u00e9 a for\u00e7a que ele exerce sobre o tampo) s\u00e3o os mesmos\u00a0 —\u00a0 P=F\/S\u00a0 —como a for\u00e7a (que \u00e9 o peso) \u00e9 a mesma nos dois casos\u00a0 —\u00a0 F<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>=F<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>=p\u00a0 —\u00a0 quanto menor a \u00e1rea, maior a press\u00e3o\u00a0 —\u00a0 P<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>>P<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>R- B<\/b><\/span><\/span><\/span><\/p>\n

07-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u0394P=(1,0 \u2013 0,6)=0,4atm=0,4.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span>N\/m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394P=4.10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>N\/m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394P=F\/S=F\/(0,5.0,25)\u00a0 —\u00a0 4.10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>=F\/0,125\u00a0 —\u00a0 F=0,5.10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 F=5.000N\u00a0 —\u00a0 F=p=mg\u00a0 —\u00a0 5.000=m.10\u00a0 —\u00a0 m=500kg\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>R- D<\/b><\/span><\/span><\/span><\/p>\n

08-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Massa da plataforma\u00a0 —\u00a0 m<\/b><\/span><\/span><\/span>plat.<\/b><\/span><\/span><\/sub><\/span>=90t=90.000kg=9.10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>kg\u00a0 —\u00a0 o terreno suporta\u00a0 —\u00a0 P<\/b><\/span><\/span><\/span>terr.,<\/b><\/span><\/span><\/sub><\/span>=F\/S<\/b><\/span><\/span><\/span>terr.<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 0,15t\/cm<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=m<\/b><\/span><\/span><\/span>plat.<\/b><\/span><\/span><\/sub><\/span>\/S<\/b><\/span><\/span><\/span>plat.<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 0,15.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>=90.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\/S<\/b><\/span><\/span><\/span>plat.<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 S<\/b><\/span><\/span><\/span>plat.<\/b><\/span><\/span><\/sub><\/span>=90\/0,15\u00a0 —\u00a0 S<\/b><\/span><\/span><\/span>plat.<\/b><\/span><\/span><\/sub><\/span>=600cm<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 cada estaca tem \u00e1rea de base\u00a0 —\u00a0 S<\/b><\/span><\/span><\/span>est.<\/b><\/span><\/span><\/sub><\/span>=10cm.10cm=100cm<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 n\u00famero de estacas\u00a0 —\u00a0 n=600\/100\u00a0 —\u00a0 n=6 estacas\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>R- D<\/b><\/span><\/span><\/span><\/p>\n

09-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Press\u00e3o\u00a0 —\u00a0\u00a0P<\/b><\/span><\/span><\/span>r<\/b><\/span><\/span><\/sub><\/span>\u00a0= 140 atm\u00a0 —\u00a0 P<\/b><\/span><\/span><\/span>r<\/b><\/span><\/span><\/sub><\/span>\u00a0= 140.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span>N\/m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0\u00a0\u00a0\u00a0—\u00a0 \u00e1rea=1,0mm.200mm\u00a0 —\u00a0 S=200mm<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=200.10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span>m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 S=2.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span>m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0—\u00a0\u00a0 g=10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>\u00a0mm\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 peso\u00a0 —\u00a0 P=mg=m.10\u00a0 —\u00a0 P=10m\u00a0 —\u00a0 press\u00e3o\u00a0 —\u00a0 P<\/b><\/span><\/span><\/span>r<\/b><\/span><\/span><\/sub><\/span>=F=P\/S\u00a0 —\u00a0 140.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span>=10m\/2.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 m=140.10<\/b><\/span><\/span><\/span>5<\/b><\/span><\/span><\/sup><\/span>.2.10<\/b><\/span><\/span><\/span>-4<\/b><\/span><\/span><\/sup><\/span>\/10\u00a0 —\u00a0 m=280kg\u00a0 —\u00a0 \u00e9 muito improv\u00e1vel um patinador ter massa de 280kg ou seja, um peso de 2.800N\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>R- E<\/b><\/span><\/span><\/span><\/p>\n

10-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>O ato de sugar implica em aumentar o volume dos pulm\u00f5es e, consequentemente, diminuir a press\u00e3o interna da boca e do canudinho, tornando-a menor que a press\u00e3o atmosf\u00e9rica local na superf\u00edcie livre do l\u00edquido\u00a0 —\u00a0 essa diferen\u00e7a de press\u00e3o provoca uma for\u00e7a que empurra o l\u00edquido para cima, na tend\u00eancia de um novo equil\u00edbrio de press\u00f5es\u00a0 —<\/b><\/span><\/span><\/span>–\u00a0<\/b><\/span><\/span><\/span>R- D<\/b><\/span><\/span><\/span><\/p>\n

<\/a>11-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Em grandes altitudes a press\u00e3o atmosf\u00e9rica diminui, o ar \u00e9 mais rarefeito, tornando-se mais dif\u00edcil a capta\u00e7\u00e3o de oxig\u00eanio pelo organismo\u00a0 —\u00a0 para se adaptar a essa baixa press\u00e3o atmosf\u00e9rica o corpo se autoregula, aumentando a frequ\u00eancia respirat\u00f3ria\u00a0 —\u00a0 isso acarreta sintomas como dores de cabe\u00e7a, n\u00e1useas, lentid\u00e3o de racioc\u00ednio, dores musculares, fadiga e taquicardia.\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

\u00a0Resolu\u00e7\u00e3o Comentada Hidrost\u00e1tica Densidade e Press\u00e3o \u00a0 01-\u00a0\u00a0I- Na hora mais quente, o volume aumenta e, num mesmo volume haveria menos massa\u00a0 —\u00a0\u00a0 voc\u00ea levaria preju\u00edzo\u00a0 — Falsa II- Com temperatura mais baixa, o volume diminui e, num mesmo volume haveria mais massa\u00a0 —\u00a0 voc\u00ea levaria vantagem\u00a0 —\u00a0 correta III- Correta\u00a0 —\u00a0 voc\u00ea estaria comprando o que realmente interessa, que<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3695,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3697","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3697","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3697"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3697\/revisions"}],"predecessor-version":[{"id":10672,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3697\/revisions\/10672"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3695"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3697"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}