{"id":3676,"date":"2018-02-13T14:11:30","date_gmt":"2018-02-13T14:11:30","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3676"},"modified":"2024-08-20T23:31:26","modified_gmt":"2024-08-20T23:31:26","slug":"resolucao-comentada-gravitacao-universal","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/enem\/gravitacao-universal-lei-da-gravitacao-universal-e-satelites-em-orbitas\/resolucao-comentada-gravitacao-universal\/","title":{"rendered":"Gravita\u00e7\u00e3o Universal – Resolu\u00e7\u00e3o"},"content":{"rendered":"

Resolu\u00e7\u00e3o Comentada<\/b><\/span><\/span><\/span> <\/b><\/p>\n

Gravita\u00e7\u00e3o Universal<\/b><\/span><\/span><\/span><\/p>\n

Lei da Gravita\u00e7\u00e3o Universal e Sat\u00e9lites em \u00d3rbitas<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

\u00a0<\/span><\/p>\n

\u00a0<\/span>01-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Leia com aten\u00e7\u00e3o essas informa\u00e7\u00f5es\u00a0 —\u00a0 as mar\u00e9s (movimentos de fluxos e refluxos da \u00e1gua <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

dos mares) ocorrem devido \u00e0 for\u00e7a de atra\u00e7\u00e3o que a Lua (figura 1) e secundariamente o Sol (figura 2) exercem sobre os oceanos\u00a0 —\u00a0 \u00a0amplitude das mar\u00e9s ser\u00e1 m\u00e1xima quando Sol e Lua estiverem alinhados em rela\u00e7\u00e3o \u00e0 Terra (Lua Cheia e Lua Nova) e durante um intervalo de tempo de 24 horas ocorrem duas mar\u00e9s altas e duas mar\u00e9s baixas,ou seja, as mar\u00e9s altas e baixas ocorrem num intervalo de aproximadamente 24\/4=6 horas\u00a0 —\u00a0 \u00a0influ\u00eancia da Lua \u00e9 maior do que a do Sol, pois, embora a sua massa seja muito menor do que a do Sol, esse fato \u00e9 compensado pela menor dist\u00e2ncia \u00e0 Terra, pois a for\u00e7a gravitacional \u00e9 inversamente proporcional ao quadrado da dist\u00e2ncia\u00a0 —\u00a0 a mar\u00e9 cheia \u00e9 vista por um observador quando ele e a Lua est\u00e3o alinhados, ou seja, quando a Lua passa por cima dele ou por baixo dele\u00a0 —\u00a0 a alternativa falsa \u00e9 a D pois, realmente as massas de \u00e1gua que est\u00e3o mais pr\u00f3ximas da Lua ou do Sol sofrem atra\u00e7\u00e3o maior do que as massas de \u00e1gua que est\u00e3o mais afastadas, mas isso n\u00e3o ocorre devido \u00e0 rota\u00e7\u00e3o da Terra mas sim, apenas devido \u00e0 a\u00e7\u00e3o das for\u00e7as gravitacionais\u00a0<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

02-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>I. Correta\u00a0 — \u00a0A sali\u00eancia no\u00a0lado\u00a0da\u00a0Lua \u00e9 causada\u00a0porque\u00a0a\u00a0Lua\u00a0puxa a \u00e1gua em dire\u00e7\u00e3o a ela distanciando-a da massa s\u00f3lida\u00a0 —\u00a0 a sali\u00eancia no\u00a0lado oposto\u00a0\u00e9 causada\u00a0porque a massa s\u00f3lida \u00e9 <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

atra\u00edda em dire\u00e7\u00e3o \u00e0 Lua e se distancia da massa l\u00edquida do lado oposto\u00a0 —\u00a0 a \u00e1gua que se encontra nos p\u00f3los sofre uma atra\u00e7\u00e3o menor, por ser quase tangencial a superf\u00edcie do oceano n\u00e3o precisa vencer o seu peso nestes locais\u00a0 —\u00a0 assim, essa \u00e1gua deslizar\u00e1 tamb\u00e9m, em dire\u00e7\u00e3o ao lado esquerdo, \u00e9 como<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>se as \u00e1guas fossem “espremidas” nos p\u00f3los\u00a0 —\u00a0 ent\u00e3o, como a \u00e1gua flui muito facilmente, ela se “empilha” nos\u00a0dois\u00a0lados\u00a0da\u00a0Terra, que fica com um bojo de \u00e1gua na dire\u00e7\u00e3o da Lua e outro na dire\u00e7\u00e3o contr\u00e1ria.<\/b><\/span><\/span><\/span><\/p>\n

II. Falsa\u00a0 —\u00a0 veja justificativa anterior.<\/b><\/span><\/span><\/span><\/p>\n

III. Correta\u00a0 —\u00a0 veja resolu\u00e7\u00e3o do exerc\u00edcio 1.<\/b><\/span><\/span><\/span><\/p>\n

R-E<\/b><\/span><\/span><\/span><\/p>\n

03-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Observe que, se a \u00f3rbita fosse circular o gr\u00e1fico F x t seria uma reta paralela ao eixo, pois F seria constante —\u00a0 ent\u00e3o, a \u00f3rbita \u00e9 el\u00edptica, a for\u00e7a \u00e9 vari\u00e1vel e o movimento do cometa \u00e9 peri\u00f3dico\u00a0 —\u00a0 assim, a dist\u00e2ncia do Sol ao cometa \u00e9 vari\u00e1vel \u00a0—\u00a0 \u00a0for\u00e7a gravitacional sobre o cometa \u00e9 dada pela lei de Newton da gravita\u00e7\u00e3o\u00a0 —\u00a0 F=GM<\/b><\/span><\/span><\/span>Sol<\/b><\/span><\/span><\/sub><\/span>.m<\/b><\/span><\/span><\/span>cometa<\/b><\/span><\/span><\/sub><\/span>\/d<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 como a dist\u00e2ncia entre eles varia, a for\u00e7a gravitacional tamb\u00e9m variar\u00e1 e ter\u00e1 intensidade m\u00ednima quando o cometa passa pelo seu af\u00e9lio e intensidade<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\u00a0m\u00e1xima quando passa pelo seu peri\u00e9lio conforme voc\u00ea pode observar na figura acima.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0R- A<\/b><\/span><\/span><\/span><\/p>\n

04-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Pelo gr\u00e1fico, quando F<\/b><\/span><\/span><\/span>G<\/b><\/span><\/span><\/sub><\/span>=4,0.10<\/b><\/span><\/span><\/span>19<\/b><\/span><\/span><\/sup><\/span>N, a dist\u00e2ncia \u00a0r ser\u00e1 igual a r=1,6.10<\/b><\/span><\/span><\/span>20<\/b><\/span><\/span><\/sup><\/span>m\u00a0 —\u00a0 F<\/b><\/span><\/span><\/span>G<\/b><\/span><\/span><\/sub><\/span>=G.M.m\/r<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 4.10<\/b><\/span><\/span><\/span>19<\/b><\/span><\/span><\/sup><\/span>=6,7.10<\/b><\/span><\/span><\/span>-11<\/b><\/span><\/span><\/sup><\/span>.M.10<\/b><\/span><\/span><\/span>30<\/b><\/span><\/span><\/sup><\/span>\/(1,6.10<\/b><\/span><\/span><\/span>20<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 M= 4.10<\/b><\/span><\/span><\/span>19<\/b><\/span><\/span><\/sup><\/span>.2,56.10<\/b><\/span><\/span><\/span>40<\/b><\/span><\/span><\/sup><\/span>\/6,7.10<\/b><\/span><\/span><\/span>19<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 M=1,528.10<\/b><\/span><\/span><\/span>40<\/b><\/span><\/span><\/sup><\/span>\u00a0kg\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>R- C<\/b><\/span><\/span><\/span><\/p>\n

05-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Leia com aten\u00e7\u00e3o as informa\u00e7\u00f5es a seguir\u00a0 —\u00a0 \u00a0sat\u00e9lites geoestacion\u00e1rios\u00a0 ou geosincr\u00f4nicos\u00a0 (sincronizados com o movimento de rota\u00e7\u00e3o da Terra)\u00a0 —\u00a0 a maioria dos sat\u00e9lites de telecomunica\u00e7\u00f5es s\u00e3o sat\u00e9lites geoestacion\u00e1rios pois se encontram parados em<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\u00a0rela\u00e7\u00e3o a um ponto fixo sobre a Terra\u00a0 —\u00a0 seu per\u00edodo \u00e9 o mesmo que o da Terra (24h),\u00a0o raio de sua \u00f3rbita \u00e9 de, aproximadamente 36.000km, tem a mesma velocidade angular (W) que a Terra e se encontram em \u00f3rbitas sobre a linha do equador, ou seja, devem manter-se num plano que contenha a linha do equador\u00a0 —\u00a0 acima da altura aproximada de 36.000km o per\u00edodo do sat\u00e9lite aumenta e abaixo desse valor, diminui\u00a0 —\u00a0 considere um sat\u00e9lite geoestacion\u00e1rio de massa m<\/b><\/span><\/span><\/span>sat\u00e9lite<\/b><\/span><\/span><\/sub><\/span>\u00a0orbitando a Terra\u00a0 de massa M<\/b><\/span><\/span><\/span>Terra\u00a0<\/b><\/span><\/span><\/sub><\/span>a uma dist\u00e2ncia r do centro da Terra\u00a0 —\u00a0 a intensidade da for\u00e7a de atra\u00e7\u00e3o <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

gravitacional (\"\") entre a Terra e o sat\u00e9lite, que atua no sat\u00e9lite, \u00e9 a for\u00e7a resultante centr\u00edpeta(\u00a0\"\")necess\u00e1ria para manter o sat\u00e9lite em \u00f3rbita, ou seja\u00a0 —\u00a0 F<\/b><\/span><\/span><\/span>G-Terra-sat\u00e9lite<\/b><\/span><\/span><\/sub><\/span>= F<\/b><\/span><\/span><\/span>c-sat\u00e9lite<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 GM<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>m<\/b><\/span><\/span><\/span>sat\u00e9lite<\/b><\/span><\/span><\/sub><\/span>\/r<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0= m<\/b><\/span><\/span><\/span>sat\u00e9lite<\/b><\/span><\/span><\/sub><\/span>.V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/rV<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0=GM<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>\/r\u00a0 —\u00a0 V =\u221a(GM<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>\/r)\u00a0 —\u00a0 observe nessa express\u00e3o que a velocidade escalar e consequentemente a angular do sat\u00e9lite em \u00f3rbita estacion\u00e1ria, independe da massa do sat\u00e9lite\u00a0 —\u00a0 portanto esses sat\u00e9lites podem ter massas diferentes desde que possuam o mesmo per\u00edodo (24h), a mesma velocidade angular e e a mesma dist\u00e2ncia r do centro da Terra.<\/b><\/span><\/span><\/span><\/p>\n

R- C\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n

06-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Dados\u00a0 —\u00a0 R = 6,4.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>\u00a0m\u00a0 — \u00a0(GM\/4\u03c0<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\/3=2,2.10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>\u00a0m.s<\/b><\/span><\/span><\/span>2\/3<\/b><\/span><\/span><\/sup><\/span>\u00a0 — \u00a0T = 24 h = (24×3.600)s=(24×3.600 s)<\/b><\/span><\/span><\/span>2\/3<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 T=2,2×10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>s<\/b><\/span><\/span><\/span>2\/3<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 a for\u00e7a gravitacional (F<\/b><\/span><\/span><\/span>G<\/b><\/span><\/span><\/sub><\/span>) sobre o sat\u00e9lite \u00e9 a for\u00e7a resultante centr\u00edpeta (F<\/b><\/span><\/span><\/span>c<\/b><\/span><\/span><\/sub><\/span>)\u00a0 —\u00a0 GMm\/r<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=mV<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/r\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=GM\/r (I)\u00a0 —\u00a0 para efetuar uma volta completa ele percorre \u0394S=2\u03c0r no intervalo de tempo \u0394t=T (per\u00edodo)\u00a0 —\u00a0 V=2\u03c0r\/T\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=4\u03c0<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>r<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/T<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0(II)\u00a0 —\u00a0 I = II\u00a0 —\u00a0<\/b><\/span><\/span><\/span><\/p>\n

GM\/ = 4\u03c0<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>r<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/T<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 r<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>=GMT<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/4\u03c0<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 r = [GM\/4\u03c0<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>]<\/b><\/span><\/span><\/span>1\/3<\/b><\/span><\/span><\/sup><\/span>.[T<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>]<\/b><\/span><\/span><\/span>2\/3<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 substituindo os dados fornecidos\u00a0 —\u00a0 r = (2,2.10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>).(2.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>) = 4,4.10<\/b><\/span><\/span><\/span>7<\/b><\/span><\/span><\/sup><\/span>\u00a0m = 44.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>\u00a0m\u00a0 —\u00a0 observe na figura que\u00a0 —\u00a0 r=R + h\u00a0 —\u00a0 h=r \u2013 R\u00a0 —<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

44.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>\u00a0\u2013 6,4.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 h=37,6.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>m\u00a0 —\u00a0\u00a0h=37,6.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>=37.600km\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0R- A<\/b><\/span><\/span><\/span><\/p>\n

07-\u00a0<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>=2R<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>=\u221a(GM<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\/R<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>)\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>=\u221a(GM<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\/R<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>) —\u00a0 V<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>\/V<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>=\u221a(GM<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>)\/\u221a(2R<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>) X \u221a(R<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>)\/\u221a(GM<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>)\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>\/V<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>=1\/\u221a2\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/sub><\/span>=V<\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/sub><\/span>\/\u221a2\u00a0 —<\/b><\/span><\/span><\/span><\/p>\n

R-B<\/b><\/span><\/span><\/span><\/p>\n

08-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Como T<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span>\/R<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span>=T<\/b><\/span><\/span><\/span>S<\/b><\/span><\/span><\/sub><\/span>\/R<\/b><\/span><\/span><\/span>S<\/b><\/span><\/span><\/sub><\/span>\u00a0e os raios s\u00e3o iguais, conclu\u00edmos que T<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span>=T<\/b><\/span><\/span><\/span>S<\/b><\/span><\/span><\/sub><\/span>e pela express\u00e3o V=2\u03c0R\/T, conclu\u00edmos tamb\u00e9m que as velocidades s\u00e3o iguais\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>R-C<\/b><\/span><\/span><\/span><\/p>\n

09-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>A for\u00e7a que age sobre a estrela \u00e9 a for\u00e7a resultante centr\u00edpeta de intensidade igual \u00e0 da for\u00e7a gravitacional\u00a0 —\u00a0 F=mV<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/r\u00a0 —\u00a0 da tabela, quando F=4,0.10<\/b><\/span><\/span><\/span>19<\/b><\/span><\/span><\/sup><\/span>N, r=1,6.10<\/b><\/span><\/span><\/span>20<\/b><\/span><\/span><\/sup><\/span>m\u00a0 —\u00a0 4,0.10<\/b><\/span><\/span><\/span>19<\/b><\/span><\/span><\/sup><\/span>=10<\/b><\/span><\/span><\/span>30<\/b><\/span><\/span><\/sup><\/span>.V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/1,6.10<\/b><\/span><\/span><\/span>20<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=(4,0.10<\/b><\/span><\/span><\/span>19<\/b><\/span><\/span><\/sup><\/span>.1,6.10<\/b><\/span><\/span><\/span>20<\/b><\/span><\/span><\/sup><\/span>)\/10<\/b><\/span><\/span><\/span>30<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=64.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0\u00a0\u00a0 V=8,0.10<\/b><\/span><\/span><\/span>4<\/b><\/span><\/span><\/sup><\/span>m\/s\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>R- A<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o Comentada Gravita\u00e7\u00e3o Universal Lei da Gravita\u00e7\u00e3o Universal e Sat\u00e9lites em \u00d3rbitas \u00a0 \u00a0 \u00a001-\u00a0Leia com aten\u00e7\u00e3o essas informa\u00e7\u00f5es\u00a0 —\u00a0 as mar\u00e9s (movimentos de fluxos e refluxos da \u00e1gua dos mares) ocorrem devido \u00e0 for\u00e7a de atra\u00e7\u00e3o que a Lua (figura 1) e secundariamente o Sol (figura 2) exercem sobre os oceanos\u00a0 —\u00a0 \u00a0amplitude das mar\u00e9s ser\u00e1 m\u00e1xima quando Sol<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3674,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3676","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3676","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3676"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3676\/revisions"}],"predecessor-version":[{"id":10677,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3676\/revisions\/10677"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3674"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3676"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}