{"id":3531,"date":"2018-01-19T03:20:50","date_gmt":"2018-01-19T03:20:50","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3531"},"modified":"2024-09-04T12:31:04","modified_gmt":"2024-09-04T12:31:04","slug":"resolucao-comentada-das-questoes-de-fisica-da-fmabc-2018","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2018\/fmabc\/resolucao-comentada-das-questoes-de-fisica-da-fmabc-2018\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da FAMERP- 2018"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da <\/span><\/span><\/span><\/p>\n

FMABC \u2013 2018<\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span><\/p>\n

Caracter\u00edsticas de uma lente delgada e convergente que fornece uma imagem direita e maior que o objeto:<\/b><\/span><\/span><\/span><\/span><\/p>\n

Objeto O entre f<\/b><\/span><\/span>o<\/b><\/span><\/sub><\/span> (foco objeto)\u00a0e O (centro \u00f3ptico da lente)<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Natureza\u00a0\"\"<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>Virtual<\/b><\/span><\/span>\u00a0(obtida no\u00a0<\/b><\/span><\/span>cruzamento dos prolongamentos<\/b><\/span><\/span>\u00a0dos raios luminosos).<\/b><\/span><\/span><\/span><\/span><\/p>\n

Localiza\u00e7\u00e3o\u00a0\"\"\u00a0Antes de f<\/b><\/span><\/span>o<\/b><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Tamanho e orienta\u00e7\u00e3o\u00a0\"\"\u00a0maior\u00a0que o objeto e\u00a0direita\u00a0em rela\u00e7\u00e3o a ele.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Utilidade<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

A <\/b><\/span><\/span><\/span>verg\u00eancia<\/b><\/span><\/span><\/span> \u201cgrau\u201d <\/b><\/span><\/span><\/span>V da lente <\/b><\/span><\/span><\/span>que \u00e9 de <\/b><\/span><\/span><\/span>5 dioptrias (di) <\/b><\/span><\/span><\/span>corresponde ao <\/b><\/span><\/span><\/span>inverso <\/b><\/span><\/span><\/span>de sua <\/b><\/span><\/span><\/span>dist\u00e2ncia focal f medida em metros (m).<\/b><\/span><\/span><\/span><\/p>\n

V = 5 di<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>V = \"\"<\/b><\/span><\/span><\/span> \"\" 5 = \"\" \"\" f = \"\" \"\" <\/b><\/span><\/span><\/span>f <\/b><\/span><\/span><\/span>= 0,2 m <\/b><\/span><\/span><\/span>= 20 cm.<\/b><\/span><\/span><\/span><\/p>\n

Equa\u00e7\u00e3o de Gauss<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Imagem direita i e 4 vezes maior que o objeto O \"\"<\/b><\/span><\/span><\/span> <\/b>i = 4.O \"\"<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> = – \"\" \"\"<\/b><\/span><\/span><\/span> \"\" = – \"\" \"\" <\/b><\/span><\/span><\/span>P\u2019 = – 4P.<\/b><\/span><\/span><\/span><\/p>\n

\"\" =<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>+<\/b><\/span><\/span><\/span> \"\" \"\"<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>=<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>+<\/b><\/span><\/span><\/span> \"\" \"\" \"\" <\/b><\/span><\/span><\/span>=<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>–<\/b><\/span><\/span><\/span> \"\" \"\" \"\" <\/b><\/span><\/span><\/span>=<\/b><\/span><\/span><\/span> \"\" \"\" \"\" <\/b><\/span><\/span><\/span>=<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> \"\" 4P = 60 \"\" P = \"\" \"\" <\/b><\/span><\/span><\/span><\/p>\n

P = 15 cm<\/b><\/span><\/span><\/span> (dist\u00e2ncia entre o olho da boneca \u201cobjeto\u201d e o centro \u00f3ptico da lente)<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

02- <\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

03- <\/span><\/span><\/span><\/p>\n

Localizando os m\u00f3veis no plano cartesiano:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

04- <\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

05- <\/span><\/span><\/span><\/p>\n

Express\u00e3o matem\u00e1tica da lei da Gravita\u00e7\u00e3o Universal<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

06- <\/span><\/span><\/span><\/p>\n

O\u00a0<\/b><\/span><\/span><\/span>f\u00f3ton,\u00a0<\/b><\/span><\/span><\/span>como qualquer part\u00edcula, possui <\/b><\/span><\/span><\/span>certa energia (W),\u00a0<\/b><\/span><\/span><\/span>e a <\/b><\/span><\/span><\/span>rela\u00e7\u00e3o energia (W)<\/b><\/span><\/span><\/span>\u00a0e\u00a0<\/b><\/span><\/span><\/span>frequ\u00eancia (f),\u00a0\u00e9 proporcional<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>e est\u00e1\u00a0<\/b><\/span><\/span><\/span>relacionada por uma constante, a\u00a0constante de Planck\u00a0(h).<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

07- <\/span><\/span><\/span><\/p>\n

For\u00e7a el\u00e1stica \u2013 Lei de Hooke<\/b><\/span><\/span><\/span><\/p>\n

Hooke\u00a0<\/b><\/span><\/span><\/span>determinou\u00a0<\/b><\/span><\/span><\/span>experimentalmente que\u00a0<\/b><\/span><\/span><\/span>\u201cem regime de deforma\u00e7\u00e3o el\u00e1stica, a intensidade da <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

for\u00e7a el\u00e1stica F<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00e9 diretamente proporcional \u00e0 deforma\u00e7\u00e3o x\u201d,<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>com <\/b><\/span><\/span><\/span>k sendo<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span><\/span>constante el\u00e1stica da mola.<\/b><\/span><\/span><\/span><\/p>\n

Em <\/b><\/span><\/span><\/span>todo movimento circular<\/b><\/span><\/span><\/span> surge <\/b><\/span><\/span><\/span>sobre o m\u00f3vel <\/b><\/span><\/span><\/span>uma <\/b><\/span><\/span><\/span>for\u00e7a <\/b><\/span><\/span><\/span>chamada <\/b><\/span><\/span><\/span>For\u00e7a Resultante Centr\u00edpeta com as seguintes caracter\u00edsticas<\/b><\/span><\/span><\/span>:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

08- <\/span><\/span><\/span><\/p>\n

Devido \u00e0s\u00a0<\/b><\/span><\/span><\/span>configura\u00e7\u00f5es (simetria) das ondas em seu interior<\/b><\/span><\/span><\/span>,\u00a0<\/b><\/span><\/span><\/span>tubos abertos\u00a0<\/b><\/span><\/span><\/span>s\u00f3 fornecem\u00a0<\/b><\/span><\/span><\/span>harm\u00f4nicos impares.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Express\u00f5es gen\u00e9ricas para n harm\u00f4nicos:<\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

Trata-se da <\/b><\/span><\/span><\/span>frequ\u00eancia fundamental <\/b><\/span><\/span><\/span>de resson\u00e2ncia conforme a <\/b><\/span><\/span><\/span>primeira figura acima <\/b><\/span><\/span><\/span> onde <\/b><\/span><\/span><\/span>\u0001<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 4L <\/b><\/span><\/span><\/span>= 4.6 \"\" <\/b><\/span><\/span><\/span>\u0001<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 24,0 mm.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

09- <\/span><\/span><\/span><\/p>\n

290 mg tomados 3 vezes ao dia <\/b><\/span><\/span><\/span>corresponde a 290×3 = <\/b><\/span><\/span><\/span>870 mg ao dia.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- D<\/span><\/span><\/span><\/p>\n

10- <\/span><\/span><\/span><\/p>\n

For\u00e7a magn\u00e9tica sobre uma carga m\u00f3vel imersa num campo magn\u00e9tico<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da FMABC \u2013 2018 01- Caracter\u00edsticas de uma lente delgada e convergente que fornece uma imagem direita e maior que o objeto: Objeto O entre fo (foco objeto)\u00a0e O (centro \u00f3ptico da lente) Natureza\u00a0\u00a0Virtual\u00a0(obtida no\u00a0cruzamento dos prolongamentos\u00a0dos raios luminosos). Localiza\u00e7\u00e3o\u00a0\u00a0Antes de fo. Tamanho e orienta\u00e7\u00e3o\u00a0\u00a0maior\u00a0que o objeto e\u00a0direita\u00a0em rela\u00e7\u00e3o a ele. Utilidade A verg\u00eancia<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3529,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3531","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3531","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3531"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3531\/revisions"}],"predecessor-version":[{"id":11062,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3531\/revisions\/11062"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3529"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3531"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}