{"id":3357,"date":"2017-11-05T19:03:26","date_gmt":"2017-11-05T19:03:26","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3357"},"modified":"2024-09-04T12:45:18","modified_gmt":"2024-09-04T12:45:18","slug":"resolucao-comentada-das-questoes-de-fisica-da-ufpr-2018","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2018\/ufpr-2018\/resolucao-comentada-das-questoes-de-fisica-da-ufpr-2018\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da UFPR \u2013 2018"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da <\/b><\/span><\/span><\/span><\/p>\n

UFPR \u2013 2018<\/b><\/span><\/span><\/span><\/p>\n

01- <\/b><\/span><\/span><\/span>1. Correta<\/b><\/span><\/span><\/span> \"\"<\/span><\/span><\/span> Uma \u00a0<\/b><\/span><\/span><\/span>associa\u00e7\u00e3o s\u00e9rie\u00a0<\/b><\/span><\/span><\/span>\u00e9 aquela em que os\u00a0<\/b><\/span><\/span><\/span>resistores est\u00e3o associados um em seguida do outro<\/b><\/span><\/span><\/span> de modo que a <\/b><\/span><\/span><\/span>corrente em cada um seja a mesma.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

C\u00e1lculo<\/b><\/span><\/span><\/span> da resist\u00eancia <\/b><\/span><\/span><\/span>(R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span> do <\/b><\/span><\/span><\/span>resistor equivalente\u00a0na associa\u00e7\u00e3o s\u00e9rie\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0a resist\u00eancia\u00a0do\u00a0<\/b><\/span><\/span><\/span>resistor<\/b><\/span><\/span><\/span> equivalente entre A e B\u00a0\u00e9 fornecida pela\u00a0soma das resist\u00eancias de cada resistor.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Portanto, numa <\/b><\/span><\/span><\/span>associa\u00e7\u00e3o de resistores em s\u00e9rie, <\/b><\/span><\/span><\/span>o <\/b><\/span><\/span><\/span>resistor equivalente <\/b><\/span><\/span><\/span>sempre tem <\/b><\/span><\/span><\/span>resist\u00eancia maior <\/b><\/span><\/span><\/span>que <\/b><\/span><\/span><\/span>qualquer uma das resist\u00eancias <\/b><\/span><\/span><\/span>dos resistores que <\/b><\/span><\/span><\/span>formam a associa\u00e7\u00e3o. <\/b><\/span><\/span><\/span><\/p>\n

02. Falsa<\/b><\/span><\/span> \"\" A tens\u00e3o U \u00e9 a mesma para todos os capacitores. Veja informa\u00e7\u00e3o abaixo:<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

03. Correta \"\" <\/span><\/span>Veja as informa\u00e7\u00f5es abaixo:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

No\u00a0<\/b><\/span><\/span><\/span>processo de carga,<\/b><\/span><\/span><\/span>\u00a0quando os\u00a0<\/b><\/span><\/span><\/span>capacitores em s\u00e9rie\u00a0estiverem ligados ao\u00a0gerador de tens\u00e3o U<\/b><\/span><\/span><\/span>, as <\/b><\/span><\/span><\/span>cargas <\/b><\/span><\/span><\/span>que\u00a0<\/b><\/span><\/span><\/span>saem de uma armadura ser\u00e3o deslocadas para a seguinte <\/b><\/span><\/span><\/span>at\u00e9 que as\u00a0<\/b><\/span><\/span><\/span>cargas de todas as armaduras tenham o mesmo m\u00f3dulo, ou seja, Q<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0= Q<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0= Q<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>\u00a0= Q, que \u00e9 igual \u00e0 carga do capacitor equivalente.<\/b><\/span><\/span><\/span><\/p>\n

Observe que,\u00a0se as\u00a0<\/b><\/span><\/span><\/span>cargas s\u00e3o iguais\u00a0e as\u00a0capacit\u00e2ncias s\u00e3o diferentes, <\/b><\/span><\/span><\/span>a <\/b><\/span><\/span><\/span>diferen\u00e7a de potencial (tens\u00e3o) tamb\u00e9m ser\u00e1 diferente.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

Voc\u00ea tamb\u00e9m pode\u00a0<\/b><\/span><\/span><\/span>calcular o capacitor equivalente\u00a0<\/b><\/span><\/span><\/span>como\u00a0<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span>\u00a0= produto\/soma tomados dois a dois.<\/b><\/span><\/span><\/span><\/p>\n

Lembre-se de que o\u00a0<\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00e9 sempre menor que a capacit\u00e2ncia de cada um dos capacitores associados.<\/b><\/span><\/span><\/span><\/p>\n

R- E <\/b><\/span><\/span><\/span><\/p>\n

02- <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

(F)<\/b><\/span><\/span><\/span> <\/b>Pelo gr\u00e1fico o <\/b><\/span><\/span><\/span>material Y se contrai <\/b><\/span><\/span><\/span>(volume diminui) quando a temperatura aumenta <\/b><\/span><\/span><\/span>at\u00e9 5 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C<\/b><\/span><\/span><\/span>, e<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

somente a <\/b><\/span><\/span><\/span>partir dessa temperatura passa a dilatar-se (volume aumentando).<\/b><\/span><\/span><\/span> <\/b><\/p>\n

(V)<\/b><\/span><\/span><\/span> Veja no <\/b><\/span><\/span><\/span>gr\u00e1fico<\/b><\/span><\/span><\/span> que em <\/b><\/span><\/span><\/span>T = 5 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C o volume de Y (V<\/b><\/span><\/span><\/span>Y<\/b><\/span><\/span><\/sub><\/span>) \u00e9 menor que o de X (V<\/b><\/span><\/span><\/span>X<\/b><\/span><\/span><\/sub><\/span>).<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

03- <\/b><\/span><\/span><\/span>Em <\/b><\/span><\/span><\/span>eletromagnetismo <\/b><\/span><\/span><\/span>a unidade bastante comum \u00e9 a de <\/b><\/span><\/span><\/span>carga el\u00e9trica medida em coulomb = amp\u00e8re.segundo \"\" 1C = 1A.1s.<\/b><\/span><\/span><\/span><\/p>\n

Em <\/b><\/span><\/span><\/span>Termodin\u00e2mica <\/b><\/span><\/span><\/span>a temperatura expressa \u00e9 a <\/b><\/span><\/span><\/span>absoluta medida em kelvin (K).<\/b><\/span><\/span><\/span><\/p>\n

Em <\/b><\/span><\/span><\/span>Mec\u00e2nica<\/b><\/span><\/span><\/span> \u00e9 a unidade de for\u00e7a, o <\/b><\/span><\/span><\/span>newton (N) \"\" 1N = 1kg.m\/s <\/b><\/span><\/span><\/span>e em <\/b><\/span><\/span><\/span>Ondulat\u00f3ria, a unidade de frequ\u00eancia que \u00e9 o hertz (Hz).<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

04- <\/b><\/span><\/span><\/span> (V)<\/b><\/span><\/span><\/span> <\/b>Veja <\/b><\/span><\/span><\/span>informa\u00e7\u00e3o abaixo:<\/b><\/span><\/span><\/span><\/p>\n

Transforma\u00e7\u00e3o isoc\u00f3rica, isom\u00e9trica ou isovolum\u00e9trica<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

\u00a0Ocorre a\u00a0<\/b><\/span><\/span><\/span>volume constante\u00a0\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\u00a0= V\u00a0\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0 \u0394V = 0\u00a0\u00a0\"\"\u00a0\u00a0<\/b><\/span><\/span><\/span>W = P.\u0394V\u00a0\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0 W = P.0\u00a0\u00a0\"\"\u00a0\u00a0<\/b><\/span><\/span><\/span>W = 0\u00a0\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u0394U = Q \u2013 W\u00a0 \"\"<\/b><\/span><\/span><\/span>\u00a0 \u0394U = Q \u2013 0\u00a0\u00a0\"\"\u00a0\u00a0<\/b><\/span><\/span><\/span>\u0394U = Q<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

(F)<\/b><\/span><\/span><\/span> <\/b>A <\/b><\/span><\/span><\/span>energia interna (\u2206U) <\/b><\/span><\/span><\/span>do g\u00e1s \u00e9 igual ao <\/b><\/span><\/span><\/span>trabalho (W) realizado, com sinal invertido.<\/b><\/span><\/span><\/span><\/p>\n

Veja <\/b><\/span><\/span><\/span>informa\u00e7\u00e3o abaixo:<\/b><\/span><\/span><\/span><\/p>\n

Transforma\u00e7\u00e3o adiab\u00e1tica<\/b><\/span><\/span><\/span><\/p>\n

\u00a0Nela, o\u00a0<\/b><\/span><\/span><\/span>sistema n\u00e3o troca calor com o meio externo (Q = 0) e isso ocorre porque o g\u00e1s est\u00e1 termicamente isolado ou porque a transforma\u00e7\u00e3o \u00e9 muito r\u00e1pida de modo que qualquer troca de calor com possa ser considerada.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0Se Q = 0\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/span>\u0394U = Q \u2013 W\u00a0\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0 \u0394U = 0 \u2013 W\u00a0\u00a0\"\"\u00a0\u00a0<\/b><\/span><\/span><\/span>\u0394U =<\/b><\/span><\/span><\/span> \u2013 W.<\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

(F)<\/b><\/span><\/span><\/span> <\/b>H\u00e1 trocas de calor, <\/b><\/span><\/span><\/span>que \u00e9 distribu\u00eddo <\/b><\/span><\/span><\/span>conforme as<\/b><\/span><\/span><\/span> <\/b>informa\u00e7\u00f5es abaixo:<\/b><\/span><\/span><\/span><\/p>\n

Transforma\u00e7\u00e3o isob\u00e1rica<\/b><\/span><\/span><\/span><\/p>\n

Ocorre <\/b><\/span><\/span><\/span>\u00e0 press\u00e3o constante.\u00a0<\/b><\/span><\/span><\/span>A\u00a0<\/b><\/span><\/span><\/span>varia\u00e7\u00e3o de temperatura (\u0394T) <\/b><\/span><\/span><\/span>provoca uma <\/b><\/span><\/span><\/span>varia\u00e7\u00e3o de energia interna (\u0394U) <\/b><\/span><\/span><\/span>do<\/b><\/span><\/span><\/span> sistema <\/b><\/span><\/span><\/span>e a <\/b><\/span><\/span><\/span>varia\u00e7\u00e3o de volume (\u0394V) produz trabalho.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Parte<\/b><\/span><\/span><\/span>\u00a0do calor (Q) recebido pelo sistema\u00a0<\/b><\/span><\/span><\/span>\u00e9\u00a0<\/b><\/span><\/span><\/span>armazenada sob forma de energia interna\u00a0<\/b><\/span><\/span><\/span>e parte<\/b><\/span><\/span><\/span>\u00a0\u00e9 transformada em trabalho, de modo que \u0394U = Q \u2013 W.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

(F)<\/b><\/span><\/span><\/span> Isot\u00e9rmica <\/b><\/span><\/span><\/span>ocorre \u00e0 <\/b><\/span><\/span><\/span>temperatura constante.<\/b><\/span><\/span><\/span><\/p>\n

Veja <\/b><\/span><\/span><\/span>informa\u00e7\u00e3o abaixo:<\/b><\/span><\/span><\/span><\/p>\n

Transforma\u00e7\u00e3o isot\u00e9rmica<\/b><\/span><\/span><\/span><\/p>\n

Como a\u00a0<\/b><\/span><\/span><\/span>temperatura (T) e a energia interna (U) de um sistema\u00a0<\/b><\/span><\/span><\/span>est\u00e3o associadas \u00e0\u00a0<\/b><\/span><\/span><\/span>energia cin\u00e9tica das mol\u00e9culas,\u00a0<\/b><\/span><\/span><\/span>se a\u00a0<\/b><\/span><\/span><\/span>temperatura for constante (transforma\u00e7\u00e3o isot\u00e9rmica),<\/b><\/span><\/span><\/span> a energia interna (U) do sistema tamb\u00e9m ser\u00e1 constante.<\/b><\/span><\/span><\/span><\/p>\n

Assim, a\u00a0<\/b><\/span><\/span><\/span>varia\u00e7\u00e3o de energia interna (\u0394U) do sistema ser\u00e1 nula.<\/b><\/span><\/span><\/span><\/p>\n

Transforma\u00e7\u00e3o isot\u00e9rmica\u00a0\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/span>\u0394U = 0\u00a0\"\"<\/b><\/span><\/span><\/span>\u00a0 \u0394U = Q \u2013 W\u00a0\u00a0\"\"\u00a0 0 = Q \u2013 W\u00a0\u00a0\"\"\u00a0\u00a0<\/b><\/span><\/span><\/span>Q = W.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Q = W<\/b><\/span><\/span><\/span>\u00a0\"\"\u00a0Portanto, numa\u00a0<\/b><\/span><\/span><\/span>transforma\u00e7\u00e3o isot\u00e9rmica\u00a0<\/b><\/span><\/span><\/span>(temperatura constante)<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>todo calor Q recebido pelo sistema \u00e9 totalmente transformado em trabalho.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

05-<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

2. Verdadeira<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> pelo <\/b><\/span><\/span><\/span>gr\u00e1fico,<\/b><\/span><\/span><\/span> quando <\/b><\/span><\/span><\/span>t = 15 s<\/b><\/span><\/span><\/span> e em <\/b><\/span><\/span><\/span>qualquer instante entre 10 s e 20 s<\/b><\/span><\/span><\/span> o <\/b><\/span><\/span><\/span>objeto<\/b><\/span><\/span><\/span> est\u00e1 <\/b><\/span><\/span><\/span>parado na posi\u00e7\u00e3o x = – 20 m, <\/b><\/span><\/span><\/span>sua <\/b><\/span><\/span><\/span>velocidade \u00e9 nula <\/b><\/span><\/span><\/span>e, consequentemente a <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o a tamb\u00e9m ser\u00e1 nula (a = 0).<\/b><\/span><\/span><\/span><\/p>\n

Pela lei fundamental da din\u00e2mica <\/b><\/span><\/span><\/span>F<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span> = m.a \"\"<\/b><\/span><\/span><\/span> F<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span> = m.0 \"\" <\/b><\/span><\/span><\/span>F<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span> = 0. <\/b><\/span><\/span><\/span><\/p>\n

3. Falsa<\/b><\/span><\/span><\/span><\/p>\n

\"\" entre 0 s e 10 s \"\" \u2206x = <\/b><\/span><\/span><\/span>x \u2013 x<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> <\/b>= -20 \u2013 0 = – 20m (retr\u00f3grado). <\/b><\/span><\/span><\/span><\/p>\n

\"\" entre 10 s e 20 s \"\" \u2206x = 0 \"\" parado na posi\u00e7\u00e3o x = – 20m.<\/b><\/span><\/span><\/span><\/p>\n

\"\" entre 20 s e 30 s \"\" \u2206x = <\/b><\/span><\/span><\/span>x \u2013 x<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> <\/b>= 20 \u2013 (-20) = 40m (progressivo). <\/b><\/span><\/span><\/span><\/p>\n

\"\" entre 30 s e 40 s \"\" \u2206x = 0 \"\" parado na posi\u00e7\u00e3o x = 20m.<\/b><\/span><\/span><\/span><\/p>\n

\u2206x<\/b><\/span><\/span><\/span>total<\/b><\/span><\/span><\/sub><\/span> = <\/b><\/span><\/span><\/span>-20 + 40 <\/b><\/span><\/span><\/span>= + 20 m (progressivo) <\/b><\/span><\/span><\/span>ou <\/b><\/span><\/span><\/span>\u2206x<\/b><\/span><\/span><\/span>total<\/b><\/span><\/span><\/sub><\/span> = x \u2013 x<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> <\/b>= 20 \u2013 0 <\/b><\/span><\/span><\/span>= + 20m (progressivo).<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

06- <\/b><\/span><\/span><\/span>Como \u00e9 pedida a <\/b><\/span><\/span><\/span>maior pot\u00eancia el\u00e9trica <\/b><\/span><\/span><\/span>voc\u00ea deve selecionar a <\/b><\/span><\/span><\/span>maior corrente el\u00e9trica fornecida pelo gr\u00e1fico, que \u00e9 de i<\/b><\/span><\/span><\/span>m\u00e1x<\/b><\/span><\/span><\/sub><\/span> = 60 A<\/b><\/span><\/span><\/span> e, se a <\/b><\/span><\/span><\/span>tens\u00e3o \u00e9 constante U = 110 V<\/b><\/span><\/span><\/span>, basta voc\u00ea utilizar a <\/b><\/span><\/span><\/span>express\u00e3o P<\/b><\/span><\/span><\/span>m\u00e1x<\/b><\/span><\/span><\/sub><\/span> = i<\/b><\/span><\/span><\/span>m\u00e1x<\/b><\/span><\/span><\/sub><\/span>.U <\/b><\/span><\/span><\/span>= 60.110 \"\" <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>m\u00e1x<\/b><\/span><\/span><\/sub><\/span> = 6600 W = 6,6 kW.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

07- <\/b><\/span><\/span><\/span><\/p>\n

Veja um <\/b><\/span><\/span><\/span>resumo da teoria abaixo:<\/b><\/span><\/span><\/span><\/p>\n

Comprimentos de onda e frequ\u00eancias para um tubo aberto nas duas extremidades<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

S\u00e3o dados:<\/b><\/span><\/span><\/span><\/p>\n

Comprimento do tubo<\/b><\/span><\/span><\/span> (flauta) \"\" <\/b><\/span><\/span><\/span>L <\/b><\/span><\/span><\/span>= 34 cm <\/b><\/span><\/span><\/span>= 0,34 m<\/b><\/span><\/span><\/span><\/p>\n

Velocidade do som \"\" V<\/b><\/span><\/span><\/span>s<\/b><\/span><\/span><\/sub><\/span> = 340 m\/s<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

08-<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

<\/a> 09- <\/b><\/span><\/span><\/span><\/p>\n

Veja abaixo um resumo da teoria:<\/b><\/span><\/span><\/span><\/p>\n

Lan\u00e7amento vertical para cima \u2013\u00a0Equa\u00e7\u00f5es<\/b><\/span><\/span><\/span><\/p>\n

Considere um corpo<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>lan\u00e7ado verticalmente para cima<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>a partir de um ponto A (origem), com\u00a0<\/b><\/span><\/span><\/span>velocidade escalar inicial\u00a0<\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\" No <\/b><\/span><\/span><\/span>ponto mais alto da trajet\u00f3ria <\/b><\/span><\/span><\/span>a <\/b><\/span><\/span><\/span>velocidade do corpo \u00e9 nula, <\/b><\/span><\/span><\/span>mas <\/b><\/span><\/span><\/span>nesse ponto, <\/b><\/span><\/span><\/span>como em <\/b><\/span><\/span><\/span>todos os pontos da trajet\u00f3ria o corpo est\u00e1 sujeito \u00e0 for\u00e7a peso <\/b><\/span><\/span><\/span>e, consequentemente <\/b><\/span><\/span><\/span>\u00e0 acelera\u00e7\u00e3o da gravidade sempre vertical e para baixo.<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0O de\u00a0<\/b><\/span><\/span><\/span>tempo subida \u00e9 igual ao tempo de descida.<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0A\u00a0<\/b><\/span><\/span><\/span>velocidade (V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)\u00a0de lan\u00e7amento\u00a0<\/b><\/span><\/span><\/span>na origem<\/b><\/span><\/span><\/span>\u00a0\u00e9 igual \u00e0\u00a0<\/b><\/span><\/span><\/span>mesma velocidade de<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>chegada \u00e0 origem,<\/b><\/span><\/span><\/span>\u00a0mas de sinal contr\u00e1rio (-V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>).<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0Em\u00a0<\/b><\/span><\/span><\/span>qualquer ponto da trajet\u00f3ria<\/b><\/span><\/span><\/span>\u00a0o corpo tem duas velocidades de <\/b><\/span><\/span><\/span>mesmo m\u00f3dulo, uma positiva na subida e uma negativa na descida.<\/b><\/span><\/span><\/span><\/p>\n

1. Falsa<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> A <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o no ponto mais alto da trajet\u00f3ria<\/b><\/span><\/span><\/span>, que fica a uma altura H do ch\u00e3o, \u00e9 a <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o da gravidade g.<\/b><\/span><\/span><\/span><\/p>\n

2. Falsa<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> \u00c9 a <\/b><\/span><\/span><\/span>dist\u00e2ncia efetivamente percorrida que vale 2H, <\/b><\/span><\/span><\/span>o <\/b><\/span><\/span><\/span>deslocamento total \u00e9 nulo d<\/b><\/span><\/span><\/span>total<\/b><\/span><\/span><\/sub><\/span> <\/b>= + H (subida) \u2013 H (descida) = 0, <\/b><\/span><\/span><\/span>\u00e9 nulo.<\/b><\/span><\/span><\/span><\/p>\n

3. Correta<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> <\/b>Veja teoria acima.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da UFPR \u2013 2018 01- 1. Correta Uma \u00a0associa\u00e7\u00e3o s\u00e9rie\u00a0\u00e9 aquela em que os\u00a0resistores est\u00e3o associados um em seguida do outro de modo que a corrente em cada um seja a mesma. C\u00e1lculo da resist\u00eancia (Req) do resistor equivalente\u00a0na associa\u00e7\u00e3o s\u00e9rie\u00a0\u00a0a resist\u00eancia\u00a0do\u00a0resistor equivalente entre A e B\u00a0\u00e9 fornecida pela\u00a0soma das resist\u00eancias de cada resistor.<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3355,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3357","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3357","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3357"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3357\/revisions"}],"predecessor-version":[{"id":3359,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3357\/revisions\/3359"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3355"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3357"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}