{"id":3283,"date":"2017-10-01T00:12:03","date_gmt":"2017-10-01T00:12:03","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3283"},"modified":"2024-06-29T23:46:40","modified_gmt":"2024-06-29T23:46:40","slug":"estatica-2017-2016-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/vestibulares-recentes\/mecanica\/estatica-2017-2016-2015\/","title":{"rendered":"EST\u00c1TICA \u2013 2017 \u2013 2016 – 2015"},"content":{"rendered":"

Est\u00e1tica<\/span><\/span><\/span><\/p>\n

EST\u00c1TICA \u2013 2017 \u2013 2016 – 2015<\/b><\/span><\/span><\/span><\/p>\n

Est\u00e1tica de um ponto material<\/b><\/span><\/span><\/span><\/p>\n

01-(FMJ-SP-017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Considere um objeto,\u00a0<\/b><\/span><\/span>cuja massa n\u00e3o varia<\/b><\/span><\/span>, se\u00a0<\/b><\/span><\/span>deslocando em uma trajet\u00f3ria retil\u00ednea com velocidade constante<\/b><\/span><\/span>. \u00c9\u00a0<\/b><\/span><\/span>correto afirmar\u00a0<\/b><\/span><\/span>que necessariamente<\/b><\/span><\/span><\/span><\/span><\/p>\n

(A) a\u00a0<\/b><\/span><\/span>resultante das for\u00e7as<\/b><\/span><\/span>\u00a0sobre esse objeto\u00a0<\/b><\/span><\/span>tem dire\u00e7\u00e3o perpendicular \u00e0 da velocidade<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(B) a\u00a0<\/b><\/span><\/span>resultante das for\u00e7as\u00a0<\/b><\/span><\/span>sobre esse objeto \u00e9\u00a0<\/b><\/span><\/span>igual a seu peso<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(C) a\u00a0<\/b><\/span><\/span>resultante das for\u00e7as\u00a0<\/b><\/span><\/span>sobre esse objeto tem\u00a0<\/b><\/span><\/span>dire\u00e7\u00e3o e sentido iguais aos da velocidade<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(D) a\u00a0<\/b><\/span><\/span>resultante das for\u00e7as\u00a0<\/b><\/span><\/span>sobre esse objeto\u00a0<\/b><\/span><\/span>\u00e9 nula<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

(E)\u00a0<\/b><\/span><\/span>n\u00e3o h\u00e1 for\u00e7as agindo sobre esse objeto<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

02-(FAMERP-SP-017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

03-(UERJ-RJ\/017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

No\u00a0<\/b><\/span><\/span>esquema,<\/b><\/span><\/span>\u00a0est\u00e1\u00a0<\/b><\/span><\/span>representado u<\/b><\/span>m\u00a0<\/b><\/span><\/span>bloco de massa igual a 100 kg\u00a0<\/b><\/span><\/span>em <\/b><\/span><\/span>equil\u00edbrio est\u00e1tico.<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Determine,\u00a0<\/b><\/span><\/span>em\u00a0<\/b><\/span><\/span>newtons,<\/b><\/span><\/span>\u00a0a\u00a0<\/b><\/span><\/span>tra\u00e7\u00e3o no fio ideal AB.<\/b><\/span><\/span><\/span><\/span><\/p>\n

 <\/p>\n

04-(ACAFE-SC-017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Um homem queria derrubar uma \u00e1rvore que estava inclinada e oferecia perigo de cair em cima de sua casa. Para isso, com a ajuda de um amigo, <\/b><\/span><\/span>preparou um sistema de roldanas<\/b><\/span><\/span>\u00a0preso a outra \u00e1rvore para segurar a \u00e1rvore que seria derrubada, a fim de pux\u00e1-la para o lado oposto de sua suposta queda, conforme figura.<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Sabendo que\u00a0<\/b><\/span><\/span>para segurar a \u00e1rvore em sua posi\u00e7\u00e3o o homem fez uma <\/b><\/span><\/span>for\u00e7a de 1000 N<\/b><\/span><\/span>\u00a0sobre a corda, a for\u00e7a aplicada pela corda na \u00e1rvore que seria derrubada \u00e9:<\/b><\/span><\/span><\/span><\/span><\/p>\n

a)\u00a0<\/b><\/span><\/span>2000 N<\/b><\/span><\/span><\/span><\/span><\/p>\n

b)\u00a0<\/b><\/span><\/span>1000 N<\/b><\/span><\/span><\/span><\/span><\/p>\n

c)\u00a0<\/b><\/span><\/span>500 N<\/b><\/span><\/span><\/span><\/span><\/p>\n

d)\u00a0<\/b><\/span><\/span>4000 N<\/b><\/span><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Est\u00e1tica de um ponto material 2017 \u2013 2016 \u2013 2015<\/span><\/span><\/span><\/p>\n

Resolu\u00e7\u00f5es<\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span>Nesse caso o objeto tem uma\u00a0<\/b><\/span><\/span>velocidade constante<\/b><\/span><\/span>, logo\u00a0<\/b><\/span><\/span>sua acelera\u00e7\u00e3o \u00e9 0<\/b><\/span><\/span>. Como sua acelera\u00e7\u00e3o \u00e9 0,\u00a0<\/b><\/span><\/span>a for\u00e7a resultante tamb\u00e9m s\u00f3 pode ser 0<\/b><\/span><\/span>, com isso\u00a0<\/b><\/span><\/span>a alternativa correta \u00e9 a D<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Vamos analisar as outras, tamb\u00e9m:<\/b><\/span><\/span><\/span><\/span><\/p>\n

A\u00a0<\/b><\/span><\/span>velocidade tem sempre a mesma dire\u00e7\u00e3o e sentido da for\u00e7a resultante<\/b><\/span><\/span>, pois\u00a0<\/b><\/span><\/span>ela \u00e9 uma consequ\u00eancia da acelera\u00e7\u00e3o<\/b><\/span><\/span>\u00a0que vai ser exercida por essa for\u00e7a.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Se\u00a0<\/b><\/span><\/span>a resultante fosse igual ao peso, o objeto estaria em queda livre<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

A alternativa C pode causar confus\u00e3o, porque\u00a0<\/b><\/span><\/span>realmente ela \u00e9 verdadeira, mas no caso aonde h\u00e1 uma for\u00e7a resultante<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Sempre\u00a0<\/b><\/span><\/span>h\u00e1 for\u00e7as agindo<\/b><\/span><\/span>, por\u00e9m\u00a0<\/b><\/span><\/span>a soma delas vai ser igual a 0<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

R \u2013 D<\/b><\/span><\/span><\/span><\/span><\/p>\n

02- <\/span><\/span><\/span>Peso do conjunto A\u00a0\"\"\u00a0<\/b><\/span><\/span>PA\u00a0= 4mg\u00a0\"\"<\/b><\/span><\/span>\u00a0peso do conjunto B\u00a0\"\"\u00a0<\/b><\/span><\/span>PB\u00a0= 2mg.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Chamando a\u00a0<\/b><\/span><\/span>dist\u00e2ncia entre cada marca consecutiva de d\u00a0<\/b><\/span><\/span>e de\u00a0<\/b><\/span><\/span>Y a dist\u00e2ncia de P at\u00e9 onde se deve colocar o peso PB\u00a0voc\u00ea obter\u00e1 o esquema da figura abaixo:<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Adotando o\u00a0<\/b><\/span><\/span>ponto P como polo 0\u00a0<\/b><\/span><\/span>(eixo de rota\u00e7\u00e3o) e o\u00a0<\/b><\/span><\/span>sentido hor\u00e1rio de rota\u00e7\u00e3o como positivo\u00a0<\/b><\/span><\/span>e\u00a0<\/b><\/span><\/span>anti hor\u00e1rio como negativo,\u00a0<\/b><\/span><\/span>vamos\u00a0<\/b><\/span><\/span>calcular<\/b><\/span><\/span>\u00a0o <\/b><\/span><\/span>momento de cada for\u00e7a em rela\u00e7\u00e3o ao polo.<\/b><\/span><\/span><\/span><\/span><\/p>\n

M<\/b><\/span><\/span>PA<\/b><\/span><\/sub><\/span>\u00a0= \u2013 F.d<\/b><\/span><\/span>PA<\/b><\/span><\/sub><\/span> P\u00a0= \u2013 P<\/b><\/span><\/span>A<\/b><\/span><\/sub><\/span>.2d\u00a0\"\"<\/b><\/span><\/span>\u00a0M<\/b><\/span><\/span>PA<\/b><\/span><\/sub><\/span>\u00a0= \u2013 4mg2d\u00a0\"\"\u00a0<\/b><\/span><\/span>MPA\u00a0= \u2013 8mgd\u00a0\"\"<\/b><\/span><\/span>\u00a0(sinal negativo, pois tende a girar no sentido anti\u00a0<\/b><\/span><\/span>hor\u00e1rio)<\/b><\/span><\/span><\/span><\/span><\/p>\n

MT<\/b><\/span><\/span>\u00a0<\/b><\/span>= T.0\u00a0\"\"\u00a0MT\u00a0= 0<\/b><\/span><\/span><\/span><\/span><\/p>\n

MPB\u00a0= + F.dPPB\u00a0= + P<\/b><\/span><\/span>B<\/b><\/span><\/sub><\/span> .Y\u00a0\"\"\u00a0M<\/b><\/span><\/span>PB<\/b><\/span><\/sub><\/span>\u00a0= + 2mgY\u00a0\"\"<\/b><\/span><\/span>\u00a0(sinal positivo, pois tende a girar no sentido hor\u00e1rio)<\/b><\/span><\/span><\/span><\/span><\/p>\n

A\u00a0<\/b><\/span><\/span>condi\u00e7\u00e3o<\/b><\/span><\/span>\u00a0de\u00a0<\/b><\/span><\/span>equil\u00edbrio de rota\u00e7\u00e3o\u00a0<\/b><\/span><\/span>\u00e9 que a\u00a0<\/b><\/span><\/span>soma dos momentos de cada for\u00e7a em rela\u00e7\u00e3o ao polo deve ser nula\u00a0\"\"<\/b><\/span><\/span>\u00a0<\/b><\/span>MPA\u00a0+ MT\u00a0+ MPB\u00a0= 0\u00a0\"\"<\/b><\/span><\/span>\u00a0\u2013 8mgd + 0 + 2mgY = 0\u00a0\"\"\u00a0Y =\u00a0\"\"<\/b><\/span><\/span>\u00a0\"\"\u00a0<\/b><\/span><\/span>Y = 4<\/b><\/span><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/span><\/p>\n

03- <\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Figura 2<\/b><\/span><\/span>\u00a0\"\"\u00a0<\/b><\/span><\/span>TCBh\u00a0= TCB.cos30o<\/b><\/span><\/span>\u00a0<\/b><\/span>=\u00a0\"\"TCB)\/2\u00a0\"\"\u00a0<\/b><\/span><\/span>TCBv<\/b><\/span><\/span>\u00a0<\/b><\/span>= TCB.sen30o<\/b><\/span><\/span>\u00a0<\/b><\/span>=TCB\/2.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Figura 3<\/b><\/span><\/span>\u00a0\"\"\u00a0<\/b><\/span><\/span>equil\u00edbrio na vertical\u00a0\"\"<\/b><\/span><\/span>\u00a0<\/b><\/span>TCBv\u00a0= P\u00a0\"\"<\/b><\/span><\/span>\u00a0TCB\/2 = mg = 100.10\u00a0\"\"TCB\/2 = 1000\u00a0\"\"\u00a0<\/b><\/span><\/span>TCB\u00a0= 2000N.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Figura 3\u00a0\"\"\u00a0equil\u00edbrio na horizontal\u00a0\"\"\u00a0TCBh\u00a0= TAB\u00a0\"\"<\/b><\/span><\/span>\u00a0\"\"TCB)\/2 =\u00a0TAB\u00a0\"\"\u00a0\"\")\/2 =\u00a0TAB\u00a0\"\"<\/b><\/span><\/span><\/span><\/span><\/p>\n

TAB\u00a0= 1000\"\"<\/b><\/span><\/span><\/span><\/span><\/p>\n

04- <\/b><\/span><\/span><\/span>Vamos analisar as polias:<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

No caso do exerc\u00edcio n\u00f3s\u00a0<\/b><\/span><\/span>temos duas polias m\u00f3veis e uma for\u00e7a de 1000 N,\u00a0<\/b><\/span><\/span>ent\u00e3o s\u00f3\u00a0<\/b><\/span><\/span>precisamos dobrar duas vezes a for\u00e7a inicial, sendo assim a for\u00e7a aplicada \u00e9 de 4000 N. Alternativa D.<\/b><\/span><\/span><\/span><\/span><\/p>\n

 <\/p>\n

EST\u00c1TICA \u2013 2017 \u2013 2016 – 2015<\/b><\/span><\/span><\/span><\/p>\n

Est\u00e1tica de um corpo extenso <\/b><\/span><\/span><\/span><\/p>\n

01- (UNESP-SP-017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Tr\u00eas\u00a0<\/b><\/span><\/span>cubos laranja id\u00eanticos<\/b><\/span><\/span>\u00a0e\u00a0<\/b><\/span><\/span>tr\u00eas cubos azuis id\u00eanticos\u00a0<\/b><\/span><\/span>est\u00e3o <\/b><\/span><\/span>equilibrados em duas balan\u00e7as\u00a0<\/b><\/span><\/span>de\u00a0<\/b><\/span><\/span>pratos, tamb\u00e9m id\u00eanticas,\u00a0<\/b><\/span><\/span>conforme <\/b><\/span><\/span>indicam as figuras.<\/b><\/span><\/span><\/span><\/span>\"\"<\/p>\n

A\u00a0<\/b><\/span><\/span>massa de um cubo laranja supera a de um cubo azul\u00a0<\/b><\/span><\/span>em exato<\/b><\/span><\/span><\/span><\/span><\/p>\n

(A)\u00a0<\/b><\/span><\/span><\/span>1,3 kg.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

(B)\u00a0<\/b><\/span><\/span><\/span>1,5 kg.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

(C)\u00a0<\/b><\/span><\/span><\/span>1,2 kg.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

(D)\u00a0<\/b><\/span><\/span><\/span>1,4 kg.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

(E)\u00a0<\/b><\/span><\/span>1,6 kg.<\/b><\/span><\/span><\/span><\/span><\/p>\n

02-(EsPCEx- AMAN \u2013 SP- RJ \u2013 2016\/17)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

O\u00a0<\/b><\/span><\/span>desenho abaixo<\/b><\/span><\/span>\u00a0representa um\u00a0<\/b><\/span><\/span>sistema composto por duas barras r\u00edgidas I e II, homog\u00eaneas\u00a0<\/b><\/span><\/span>e de\u00a0<\/b><\/span><\/span>massas desprez\u00edveis na posi\u00e7\u00e3o horizontal, <\/b><\/span><\/span>dentro de uma sala. O\u00a0<\/b><\/span><\/span>sistema<\/b><\/span><\/span>\u00a0est\u00e1 em\u00a0<\/b><\/span><\/span>equil\u00edbrio est\u00e1tico.<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

No\u00a0<\/b><\/span><\/span>ponto M da barra II,<\/b><\/span><\/span>\u00a0\u00e9 colocado um\u00a0<\/b><\/span><\/span>peso de 200 N suspenso por um cabo de massa desprez\u00edvel.<\/b><\/span><\/span><\/span><\/span><\/p>\n

A\u00a0<\/b><\/span><\/span>barra I est\u00e1 apoiada no ponto N\u00a0<\/b><\/span><\/span>no\u00a0<\/b><\/span><\/span>v\u00e9rtice de um cone fixo no piso.<\/b><\/span><\/span><\/span><\/span><\/p>\n

O\u00a0<\/b><\/span><\/span>ponto A da barra I toca o v\u00e9rtice de um cone fixo no teto.<\/b><\/span><\/span><\/span><\/span><\/p>\n

O\u00a0<\/b><\/span><\/span>ponto B da barra I toca o ponto C,\u00a0<\/b><\/span><\/span>na\u00a0<\/b><\/span><\/span>extremidade da barra II.<\/b><\/span><\/span><\/span><\/span><\/p>\n

O\u00a0<\/b><\/span><\/span>ponto D, localizado na outra extremidade da barra II, est\u00e1 apoiado no v\u00e9rtice de um cone fixo no piso.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Os\u00a0<\/b><\/span><\/span>m\u00f3dulos das for\u00e7as de contato sobre a barra I, nos pontos A e N,<\/b><\/span><\/span>\u00a0s\u00e3o respectivamente:<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

03-(AFA \u2013 016\/017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

 <\/p>\n

04-(UFES \u2013 ES \u2013 017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

 <\/p>\n

05-(ACAFE-SC-017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Para cortar galhos de \u00e1rvores um jardineiro usa uma tesoura de podar, como\u00a0<\/b><\/span><\/span>mostra a figura 1. Por\u00e9m,\u00a0<\/b><\/span><\/span>alguns galhos ficam na copa das \u00e1rvores e como ele n\u00e3o queria subir nas mesmas, resolveu improvisar,\u00a0<\/b><\/span><\/span>acoplando \u00e0 tesoura cabos maiores, conforme figura 2.<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Assim,\u00a0<\/b><\/span><\/span>assinale a alternativa\u00a0correta\u00a0que completa as lacunas da frase a seguir.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Utilizando a tesoura da ________ o rapaz teria que fazer uma for\u00e7a ________ a for\u00e7a aplicada na tesoura da ______ para produzir o mesmo torque.<\/b><\/i><\/span><\/span><\/span><\/span><\/p>\n

a)<\/b><\/span><\/span>\u00a0figura 2 \u2013 menor do que \u2013 figura 1<\/b><\/span><\/span><\/span><\/span><\/p>\n

b)\u00a0<\/b><\/span><\/span>figura 2 \u2013 maior do que \u2013 figura 1<\/b><\/span><\/span><\/span><\/span><\/p>\n

c)\u00a0<\/b><\/span><\/span>figura 1 \u2013 menor do que \u2013 figura 2<\/b><\/span><\/span><\/span><\/span><\/p>\n

d)\u00a0<\/b><\/span><\/span>figura 1 \u2013 igual \u2013 figura 2<\/b><\/span><\/span><\/span><\/span><\/p>\n

 <\/p>\n

06-(PUC-GO-017)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Nos fragmentos do\u00a0<\/b><\/span><\/span>Texto 3<\/b><\/span><\/span>\u00a0<\/b><\/span>\u201cTentava acompanhar os passos de meu pai. [\u2026] dizer-lhe que parasse.\u201d\u00a0<\/b><\/span><\/span>Temos\u00a0<\/b><\/span><\/span>refer\u00eancia\u00a0<\/b><\/span><\/span>a\u00a0<\/b><\/span><\/span>movimento e a repouso.<\/b><\/span><\/span><\/span><\/span><\/p>\n

O\u00a0<\/b><\/span><\/span>movimento de um corpo pode ser de transla\u00e7\u00e3o e\/ou rota\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Para que um\u00a0<\/b><\/span><\/span>corpo permane\u00e7a em repouso, \u00e9 necess\u00e1rio que esteja em equil\u00edbrio de transla\u00e7\u00e3o\u00a0<\/b><\/span><\/span>e\u00a0<\/b><\/span><\/span>rota\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Considere uma\u00a0<\/b><\/span><\/span>gangorra constru\u00edda com uma t\u00e1bua r\u00edgida, homog\u00eanea<\/b><\/span><\/span>, de<\/b><\/span><\/span>massa igual a 10 kg,<\/b><\/span><\/span>\u00a0com\u00a0<\/b><\/span><\/span>espessura e largura desprez\u00edveis<\/b><\/span><\/span>\u00a0em rela\u00e7\u00e3o a<\/b><\/span><\/span>seu comprimento, que \u00e9 de 8 m.<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

A\u00a0<\/b><\/span><\/span>t\u00e1bua pode girar em torno de um eixo de rota\u00e7\u00e3o colocado perpendicularmente<\/b><\/span><\/span>\u00a0ao seu\u00a0<\/b><\/span><\/span>comprimento, a 4 m de cada uma das extremidades.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Duas pessoas, uma de massa m1\u00a0= 85 kg e outra de massa m2\u00a0= 40 kg,<\/b><\/span><\/span>est\u00e3o\u00a0<\/b><\/span><\/span>sentadas<\/b><\/span><\/span>\u00a0em\u00a0<\/b><\/span><\/span>cada uma\u00a0<\/b><\/span><\/span>das\u00a0<\/b><\/span><\/span>extremidades da t\u00e1bua.<\/b><\/span><\/span><\/span><\/span><\/p>\n

Para que a\u00a0<\/b><\/span><\/span>t\u00e1bua fique em equil\u00edbrio horizontal,\u00a0<\/b><\/span><\/span>uma\u00a0<\/b><\/span><\/span>terceira pessoa\u00a0<\/b><\/span><\/span>\u00e9 colocada entre o\u00a0<\/b><\/span><\/span>eixo de rota\u00e7\u00e3o e a pessoa mais leve, a uma dist\u00e2ncia de 1,5 m desse eixo.<\/b><\/span><\/span><\/span><\/span><\/p>\n

A\u00a0<\/b><\/span><\/span>massa da terceira pessoa \u00e9\u00a0<\/b><\/span><\/span>de (assinale a\u00a0<\/b><\/span><\/span>resposta correta<\/b><\/span><\/span>):<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

 <\/p>\n

07-(ENEM-MEC-015)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

08-(Medicina \u2013 USCS-SP-016)<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Um\u00a0<\/b><\/span><\/span>cilindro de 600 g de massa e 200 cm<\/b><\/span><\/span>3<\/b><\/span><\/sup><\/span>\u00a0<\/b><\/span>de volume<\/b><\/span><\/span>\u00a0\u00e9\u00a0<\/b><\/span><\/span>totalmente imerso em \u00e1gua, de densidade 1,0 g\/cm<\/b><\/span><\/span>3<\/b><\/span><\/sup><\/span>\u00a0= 10<\/b><\/span><\/span>3<\/b><\/span><\/sup><\/span>\u00a0kg\/m<\/b><\/span><\/span>3<\/b><\/span><\/sup><\/span>, e suspenso por um\u00a0<\/b><\/span><\/span>fio ideal <\/b><\/span><\/span>atado a uma das\u00a0<\/b><\/span><\/span>extremidades de uma barra r\u00edgida de peso desprez\u00edvel<\/b><\/span><\/span>.<\/b><\/span><\/span><\/span><\/span><\/p>\n

A barra<\/b><\/span><\/span>\u00a0\u00e9 apoiada em um\u00a0<\/b><\/span><\/span>ponto O, distante 30 cm da extremidade em que se encontra suspenso o<\/b><\/span><\/span>\u00a0<\/b><\/span>cilindro e distante 10 cm da outra extremidade <\/b><\/span><\/span>em que h\u00e1 uma\u00a0<\/b><\/span><\/span>esfera de peso P<\/b><\/span><\/span>e<\/b><\/span><\/sub><\/span>\u00a0, mantendo o\u00a0<\/b><\/span><\/span>sistema em equil\u00edbrio.<\/b><\/span><\/span>\u00a0A <\/b><\/span><\/span>figura<\/b><\/span><\/span>\u00a0ilustra a\u00a0<\/b><\/span><\/span>situa\u00e7\u00e3o descrita.<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"EST\u00c1TICA\"<\/p>\n

Considerando a\u00a0<\/b><\/span><\/span>acelera\u00e7\u00e3o da gravidade igual a 10 m\/s<\/b><\/span><\/span>2<\/b><\/span><\/sup><\/span>,<\/b><\/span><\/span>\u00a0a\u00a0<\/b><\/span><\/span>intensidade do peso P<\/b><\/span><\/span>e<\/b><\/span><\/sub><\/span>\u00a0,\u00a0<\/b><\/span><\/span>em N<\/b><\/span><\/span>, deve ser igual a<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

 <\/p>\n

Confira as resolu\u00e7\u00f5es comentadas<\/span><\/a><\/h3>\n

 <\/p>\n

Clique aqui para ver sobre o tema!<\/a><\/p>\n

Confira as v\u00eddeo aulas!<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Est\u00e1tica EST\u00c1TICA \u2013 2017 \u2013 2016 – 2015 Est\u00e1tica de um ponto material 01-(FMJ-SP-017) Considere um objeto,\u00a0cuja massa n\u00e3o varia, se\u00a0deslocando em uma trajet\u00f3ria retil\u00ednea com velocidade constante. \u00c9\u00a0correto afirmar\u00a0que necessariamente (A) a\u00a0resultante das for\u00e7as\u00a0sobre esse objeto\u00a0tem dire\u00e7\u00e3o perpendicular \u00e0 da velocidade. (B) a\u00a0resultante das for\u00e7as\u00a0sobre esse objeto \u00e9\u00a0igual a seu peso. (C) a\u00a0resultante das for\u00e7as\u00a0sobre esse objeto tem\u00a0dire\u00e7\u00e3o e<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3123,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3283","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3283","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3283"}],"version-history":[{"count":4,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3283\/revisions"}],"predecessor-version":[{"id":9854,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3283\/revisions\/9854"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3123"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3283"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}