{"id":3249,"date":"2017-09-27T22:31:35","date_gmt":"2017-09-27T22:31:35","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3249"},"modified":"2024-06-29T23:49:45","modified_gmt":"2024-06-29T23:49:45","slug":"vestibulares-recentes-por-assunto-2014-e-2013","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/vestibulares-recentes\/mecanica\/vestibulares-recentes-por-assunto-2014-e-2013\/","title":{"rendered":"Din\u00e2mica &#8211;  2014 e 2013"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: x-large;\">Exerc\u00edcios &#8211; Vestibulares Recentes por assunto<\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: x-large;\"><b>2014 e 2013<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: x-large;\"><b>As tr\u00eas leis de Newton<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>01-(FMJ-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_c88184be.png\" alt=\"\" width=\"581\" height=\"162\" name=\"Imagem 434\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um avi\u00e3o, de massa\u00a0m,\u00a0est\u00e1 decolando\u00a0inclinado de um\u00a0\u00e2ngulo \u03b1com a horizontal, com\u00a0velocidade<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_fb5493a.png\" alt=\"\" width=\"463\" height=\"177\" name=\"Imagem 435\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>constante\u00a0e acelera\u00e7\u00e3o da gravidade local igual a\u00a0g. Para\u00a0continuar subindo nessas condi\u00e7\u00f5es,a for\u00e7a resultante\u00a0sobre o avi\u00e3o dever\u00e1 ter intensidade igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) m.g.sen\u03b1. (B) m.g.tg\u03b1. (C) m.g.cos\u03b1. (D) zero. (E) m.g.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-(IFPE-PE-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_14ef823f.png\" alt=\"\" width=\"719\" height=\"158\" name=\"Imagem 436\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um bloco desliza sobre um piso horizontal liso (sem atrito) com\u00a0velocidade de 20 m\/s\u00a0quando atinge<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>uma regi\u00e3o\u00a0\u00e1spera\u00a0muito extensa, cujo\u00a0coeficiente de atrito cin\u00e9tico vale \u03bc = 0,4\u00a0(ver figura).<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b65ae69c.png\" alt=\"\" width=\"506\" height=\"125\" name=\"Imagem 437\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0dist\u00e2ncia percorrida pelo bloco sobre o piso com atrito,\u00a0at\u00e9 ele parar, vale em metros: (Adote g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 10 b) 20 c) 30 d) 40 e) 50<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03-(FATEC-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1e09810c.jpg\" alt=\"\" width=\"761\" height=\"157\" name=\"Imagem 438\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Os avi\u00f5es\u00a0voam\u00a0porque o perfil aerodin\u00e2mico de suas asas faz com que o\u00a0ar\u00a0que\u00a0passa por cima\u00a0e\u00a0por baixo\u00a0delas ocasione uma\u00a0diferen\u00e7a de press\u00e3o que gera o empuxo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Esta for\u00e7a de\u00a0empuxo\u00a0\u00e9 que\u00a0permite ao avi\u00e3o se sustentar\u00a0no ar. Logo, para que\u00a0o avi\u00e3o voe, as\u00a0h\u00e9lices ou\u00a0turbinas do avi\u00e3o \u00e9 que empurram o ar para tr\u00e1s, e o ar reage impulsionando a aeronave para a frente. Desta forma, podemos dizer que o avi\u00e3o se sustenta no ar sob a a\u00e7\u00e3o de\u00a04 for\u00e7as:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_a4d31519.png\" alt=\"\" width=\"595\" height=\"270\" name=\"Imagem 439\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&#8211; a motora ou propuls\u00e3o;<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&#8211; de resist\u00eancia do ar ou arrasto;<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&#8211; a peso;<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&#8211; a de empuxo ou sustenta\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Caso um\u00a0avi\u00e3o voe em velocidade constante\u00a0e permane\u00e7a\u00a0\u00e0 mesma altitude, \u00e9 correto afirmar que a somat\u00f3ria das<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) for\u00e7as verticais \u00e9 nula e a das horizontais, n\u00e3o nula.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(B) for\u00e7as horizontais \u00e9 nula e a das verticais, n\u00e3o nula.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(C) for\u00e7as horizontais e verticais \u00e9 nula.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(D) for\u00e7as positivas \u00e9 nula.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(E) for\u00e7as negativas \u00e9 nula<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>04<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>&#8211;<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>(UERJ-RJ-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9beace6.jpg\" alt=\"\" width=\"649\" height=\"149\" name=\"Imagem 440\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A imagem abaixo ilustra uma bola de ferro ap\u00f3s ser disparada por um canh\u00e3o antigo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_8aedee4d.png\" alt=\"\" width=\"380\" height=\"179\" name=\"Imagem 441\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desprezando-se a resist\u00eancia do ar, o esquema que melhor representa as for\u00e7as que atuam sobre a bola de ferro \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_39d736e6.png\" alt=\"\" width=\"771\" height=\"91\" name=\"Imagem 442\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>05-(EsPCEx-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1f8014df.jpg\" alt=\"\" width=\"709\" height=\"147\" name=\"Imagem 443\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0port\u00e3o maci\u00e7o e homog\u00eaneo\u00a0de\u00a01,60m de largura e 1,80m de comprimento,\u00a0pesando 800N\u00a0est\u00e1 fixado em um muro por meio das\u00a0dobradi\u00e7as &#8220;A&#8221;, situada\u00a0a 0,10m\u00a0abaixo do topo do port\u00e3o, e\u00a0&#8220;B&#8221;,\u00a0situada a 0,10 m\u00a0de sua parte inferior. A\u00a0dist\u00e2ncia entre as dobradi\u00e7as \u00e9 de 1,60m\u00a0conforme o desenho abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1810f7d3.png\" alt=\"\" width=\"479\" height=\"249\" name=\"Imagem 444\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Elas t\u00eam peso e dimens\u00f5es desprez\u00edveis, e\u00a0cada dobradi\u00e7a suporta uma for\u00e7a cujo m\u00f3dulo da componente vertical \u00e9 metade do peso do port\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando que o port\u00e3o est\u00e1 em\u00a0equil\u00edbrio, e que o seu\u00a0centro de gravidade\u00a0est\u00e1 localizado em\u00a0seu centro geom\u00e9trico, o\u00a0m\u00f3dulo da componente horizontal da for\u00e7a em cada dobradi\u00e7a &#8220;A&#8221; e &#8220;B&#8221;<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>vale, respectivamente:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 130 N e 135 N b) 135 N e 135 N c) 400 N e 400 N d) 450 N e 450 N e) 600 N e 65ON<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>06-(UERJ-RJ-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_5576f497.jpg\" alt=\"\" width=\"529\" height=\"151\" name=\"Imagem 445\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O corpo de um\u00a0aspirador de p\u00f3\u00a0tem massa igual a\u00a02,0 kg. Ao utiliz\u00e1-lo, durante um dado\u00a0intervalo de tempo, uma pessoa faz um esfor\u00e7o sobre o\u00a0tubo 1\u00a0que resulta em uma\u00a0for\u00e7a de intensidade constante igual a 4,0 N\u00a0aplicada ao corpo do aspirador. A\u00a0dire\u00e7\u00e3o dessa for\u00e7a \u00e9 paralela ao tubo 2,\u00a0cuja inclina\u00e7\u00e3o em rela\u00e7\u00e3o ao solo \u00e9 igual a 60\u00ba, e puxa o corpo do aspirador para perto da pessoa.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d6f76f61.png\" alt=\"\" width=\"469\" height=\"210\" name=\"Imagem 446\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere\u00a0sen 60\u00ba = 0,87, cos 60\u00ba = 0,5\u00a0e tamb\u00e9m que o corpo do aspirador se move\u00a0sem atrito.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Durante esse\u00a0intervalo de tempo, a acelera\u00e7\u00e3o do corpo do aspirador, em m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,\u00a0equivale a:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(A) 0,5 (B) 1,0 (C) 1,5 (D) 2,0<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>07-(UNESP-SP-013)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_694b4244.png\" alt=\"\" width=\"763\" height=\"155\" name=\"Imagem 447\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>bungeejump<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e9 um esporte radical no qual uma pessoa salta no ar amarrada pelos tornozelos ou pela cintura a uma corda el\u00e1stica.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d7246472.png\" alt=\"\" width=\"403\" height=\"223\" name=\"Imagem 448\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere que a corda el\u00e1stica tenha comprimento natural (n\u00e3o deformada) de 10 m. Depois de saltar, no instante em que a pessoa passa pela posi\u00e7\u00e3o A, a corda est\u00e1 totalmente na vertical e com seu comprimento natural. A partir da\u00ed, a corda \u00e9 alongada, isto \u00e9, tem seu comprimento crescente at\u00e9 que a pessoa atinja a posi\u00e7\u00e3o B, onde para instantaneamente, com a corda deformada ao m\u00e1ximo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6c188a34.png\" alt=\"\" width=\"583\" height=\"421\" name=\"Imagem 449\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desprezando a resist\u00eancia do ar, \u00e9 correto afirmar que, enquanto a pessoa est\u00e1 descendo pela primeira vez depois de saltar, ela<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) atinge sua m\u00e1xima velocidade escalar quando passa pela posi\u00e7\u00e3o A.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(B) desenvolve um movimento retardado desde a posi\u00e7\u00e3o A at\u00e9 a posi\u00e7\u00e3o B.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(C) movimenta-se entre A e B com acelera\u00e7\u00e3o, em m\u00f3dulo, igual \u00e0 da gravidade local.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(D) tem acelera\u00e7\u00e3o nula na posi\u00e7\u00e3o B.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(E) atinge sua m\u00e1xima velocidade escalar numa posi\u00e7\u00e3o entre A e B<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>08-(UNESP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6f6ba745.jpg\" alt=\"\" width=\"753\" height=\"151\" name=\"Imagem 450\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ao tentar\u00a0arrastar\u00a0um m\u00f3vel de\u00a0120 kg\u00a0sobre uma\u00a0superf\u00edcie plana e horizontal,\u00a0Dona Elvira\u00a0percebeu que, mesmo exercendo sua\u00a0m\u00e1xima for\u00e7a sobre ele, n\u00e3o conseguiria mov\u00ea-lo, devido \u00e0\u00a0for\u00e7a de atrito entre o m\u00f3vel e a superf\u00edcie do solo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Chamou, ent\u00e3o,\u00a0Dona Dolores,\u00a0para ajud\u00e1-la.\u00a0Empurrando juntas, elas conseguiram arrastar\u00a0o m\u00f3vel<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ab35dda8.png\" alt=\"\" width=\"329\" height=\"287\" name=\"Imagem 451\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>em linha reta, com\u00a0acelera\u00e7\u00e3o escalar constante de m\u00f3dulo 0,2 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabendo que as for\u00e7as aplicadas pelas duas senhoras tinham\u00a0a mesma dire\u00e7\u00e3o e o mesmo sentido\u00a0do\u00a0movimento do m\u00f3vel, que\u00a0Dona Elvira aplicou uma for\u00e7a de m\u00f3dulo igual ao dobro da aplicada por Dona Dolores\u00a0e que\u00a0durante o movimento\u00a0atuou sobre o m\u00f3vel uma\u00a0for\u00e7a de atrito de intensidade<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>constante e igual a 240 N, \u00e9 correto afirmar que o\u00a0m\u00f3dulo da for\u00e7a aplicada por Dona Elvira, em newtons, foi igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 340. (B) 60. (C) 256. (D) 176. (E) 120.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>09-(ACAFE-SC-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1012f73f.jpg\" alt=\"\" width=\"434\" height=\"149\" name=\"Imagem 452\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O tratamento de\u00a0tra\u00e7\u00e3o\u00a0\u00e9 a\u00a0aplica\u00e7\u00e3o de uma for\u00e7a de tra\u00e7\u00e3o sobre uma parte do corpo. A tra\u00e7\u00e3o<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ainda \u00e9 usada principalmente como uma prescri\u00e7\u00e3o em curto prazo at\u00e9 que outras modalidades,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>como a fixa\u00e7\u00e3o externa ou interna, sejam poss\u00edveis. Isso reduz o risco da s\u00edndrome do desuso.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Seja um paciente de\u00a0massa 50 kg\u00a0submetido a um tratamento\u00a0de tra\u00e7\u00e3o como na figura abaixo, que<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>est\u00e1 deitado em uma cama onde o\u00a0coeficiente de atrito\u00a0entre a mesma e o paciente \u00e9\u00a0\u03bc=0,26.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b47ac1ee.png\" alt=\"\" width=\"407\" height=\"179\" name=\"Imagem 453\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabendo-se que o\u00a0\u00e2ngulo\u00a0entre a for\u00e7a\u00a0de tra\u00e7\u00e3o e a horizontal \u00e9 30<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, a alternativa\u00a0correta\u00a0que<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>apresenta a\u00a0m\u00e1xima massa, em\u00a0kg,\u00a0que deve ser\u00a0utilizada para produzir tal for\u00e7a de tra\u00e7\u00e3o sem que<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o paciente se desloque em cima da cama \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A)\u00a025\u00a0B)\u00a013\u00a0C)\u00a010\u00a0D)\u00a050<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>10-(CEDERJ-RJ-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_678513ec.jpg\" alt=\"\" width=\"564\" height=\"150\" name=\"Imagem 454\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um pequeno bloco de madeira \u00e9 lan\u00e7ado com velocidade inicial\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6d20852d.png\" alt=\"\" width=\"14\" height=\"18\" name=\"Imagem 455\" align=\"BOTTOM\" border=\"0\" \/>\u00a0sobre uma superf\u00edcie horizontal,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6461ded6.png\" alt=\"\" width=\"457\" height=\"159\" name=\"Imagem 456\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>conforme ilustra a figura. O bloco desliza sobre esta superf\u00edcie, parando depois de percorrer uma determinada\u00a0dist\u00e2ncia sob a\u00e7\u00e3o de uma for\u00e7a de atrito constante<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_cd5e4eb4.png\" alt=\"\" width=\"775\" height=\"154\" name=\"Imagem 457\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>11-(CEFET-MG-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9797a45e.jpg\" alt=\"\" width=\"745\" height=\"177\" name=\"Imagem 458\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma caixa,\u00a0inicialmente em repouso, sobre uma superf\u00edcie horizontal e plana, \u00e9 puxada por um oper\u00e1rio que aplica\u00a0uma for\u00e7a variando linearmente com o tempo. Sabendo-se que\u00a0h\u00e1 atrito\u00a0entre a caixa e a superf\u00edcie, e que a rugosidade entre as \u00e1reas em contato \u00e9 sempre a mesma,\u00a0a for\u00e7a de atrito, no decorrer do tempo, est\u00e1 corretamente representada pelo gr\u00e1fico<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d1dccc81.png\" alt=\"\" width=\"765\" height=\"157\" name=\"Imagem 459\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>12-(MACKENZIE-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_87b0e17c.jpg\" alt=\"\" width=\"589\" height=\"152\" name=\"Imagem 460\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ao montar o experimento abaixo no laborat\u00f3rio de F\u00edsica, observa-se\u00a0que\u00a0o\u00a0bloco A, de massa 3 kg, <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_4a238275.png\" alt=\"\" width=\"731\" height=\"366\" name=\"Imagem 461\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cai com<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>acelera\u00e7\u00e3o de 2,4 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,\u00a0e que a mola\u00a0ideal, de\u00a0constante el\u00e1stica 1240 N\/m,\u00a0que suspende o bloco C, est\u00e1\u00a0distendida\u00a0de 2 cm. O coeficiente de atrito entre o\u00a0bloco B e o plano inclinado \u00e9 0,4. Um\u00a0aluno determina acertadamente a\u00a0massa\u00a0do bloco B\u00a0como sendo<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>a) 1,0 kg b) 2,0 kg c) 2,5 kg d) 4,0 kg e) 5,0 kg<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>13-(PUC-MG-014)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_c1de245f.jpg\" alt=\"\" width=\"653\" height=\"159\" name=\"Imagem 462\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0pequeno bloco desce um plano inclinado\u00a0com velocidade constante. Sobre essa situa\u00e7\u00e3o, \u00e9 CORRETO<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6a3493d7.jpg\" alt=\"\" width=\"409\" height=\"187\" name=\"Imagem 463\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>afirmar:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) A for\u00e7a resultante que age sobre o bloco \u00e9 nula.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) A for\u00e7a de atrito entre o bloco e a superf\u00edcie do plano \u00e9 desprez\u00edvel.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) O peso do bloco interfere na velocidade com que ele desce pelo plano inclinado.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Na realidade \u00e9 imposs\u00edvel que um bloco des\u00e7a um plano inclinado com velocidade constante devido \u00e0<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>acelera\u00e7\u00e3o da gravidade<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>For\u00e7as no MCU<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>01-(UNESP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_332e7a00.jpg\" alt=\"\" width=\"769\" height=\"151\" name=\"Imagem 464\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>show\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de patina\u00e7\u00e3o no gelo, duas garotas de\u00a0massas iguais\u00a0giram em\u00a0movimento circular uniforme\u00a0em torno de uma haste vertical fixa, perpendicular ao plano horizontal.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Duas fitas,\u00a0F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, inextens\u00edveis, de massas desprez\u00edveis e mantidas na horizontal, ligam uma garota \u00e0 outra, e uma delas \u00e0 haste. Enquanto as garotas patinam, as fitas, a haste e os centros de massa das garotas mant\u00eam-se num mesmo plano perpendicular ao piso plano e horizontal.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_234ead46.png\" alt=\"\" width=\"593\" height=\"291\" name=\"Imagem 465\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando as informa\u00e7\u00f5es indicadas na figura, que o m\u00f3dulo da for\u00e7a de tra\u00e7\u00e3o na fita\u00a0F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00e9 igual a\u00a0120 N\u00a0e desprezando o atrito e a resist\u00eancia do ar, \u00e9 correto afirmar que o\u00a0m\u00f3dulo da for\u00e7a de tra\u00e7\u00e3o,\u00a0em newtons, na\u00a0fita F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00e9 igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 120. (B) 240. (C) 60. (D) 210. (E) 180.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-(FUVEST-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_5379627b.png\" alt=\"\" width=\"668\" height=\"175\" name=\"Imagem 466\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para passar de uma margem a outra de um rio, uma pessoa se pendura na extremidade de um cip\u00f3<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1d8d5d00.png\" alt=\"\" width=\"425\" height=\"210\" name=\"Imagem 467\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>esticado, formando um \u00e2ngulo de 30\u00b0com a vertical, e inicia, com velocidade nula, um movimento pendular. Do outro lado do rio, a pessoa se solta do cip\u00f3 no instante em que sua velocidade fica novamente igual a zero. Imediatamente antes de se soltar, sua acelera\u00e7\u00e3o tem<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) valor nulo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) dire\u00e7\u00e3o que forma um \u00e2ngulo de 30\u00b0com a vertical e m\u00f3dulo 9 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) dire\u00e7\u00e3o que forma um \u00e2ngulo de 30\u00b0com a vertical e m\u00f3dulo 5m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) dire\u00e7\u00e3o que forma um \u00e2ngulo de 60\u00b0com a vertical e m\u00f3dulo 9m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) dire\u00e7\u00e3o que forma um \u00e2ngulo de 60\u00b0com a vertical e m\u00f3dulo 5m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_63ca7e18.png\" alt=\"\" width=\"527\" height=\"150\" name=\"Imagem 468\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03-(AFA-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_2305759.png\" alt=\"\" width=\"533\" height=\"159\" name=\"Imagem 469\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um motociclista, pilotando sua motocicleta, move-se com velocidade constante durante a realiza\u00e7\u00e3o do looping da figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_23dbf7df.png\" alt=\"\" width=\"428\" height=\"209\" name=\"Imagem 470\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Quando est\u00e1 passando pelo ponto mais alto dessa trajet\u00f3riacircular, o motociclista lan\u00e7a, para tr\u00e1s, um objeto de massa<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>desprez\u00edvel, comparada \u00e0 massa de todo o conjunto motocicleta-motociclista. Dessa forma, o objeto cai, em rela\u00e7\u00e3o \u00e0 superf\u00edcie da Terra, como se tivesse sido abandonado em A, percorrendo uma trajet\u00f3ria retil\u00ednea at\u00e9 B. Ao passar, ap\u00f3s esse lan\u00e7amento, em B, o motociclista consegue recuperar o objeto imediatamente antes dele tocar o solo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desprezando a resist\u00eancia do ar e as dimens\u00f5es do conjunto motocicleta-motociclista, e considerando \u03c0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 10, a raz\u00e3o entre a normal (N), que age sobre a motocicleta no instante em que passa no ponto A, e o peso (P) do conjunto<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>motocicleta-motociclista, (N\/P), ser\u00e1 igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,5 b) 1,0 c) 1,5 d) 3,5<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>04-(CEDERJ-RJ-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6a32be92.jpg\" alt=\"\" width=\"743\" height=\"159\" name=\"Imagem 471\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0p\u00eandulo\u00a0\u00e9 constitu\u00eddo por um pequeno corpo de\u00a0massa\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>preso a um fio inextens\u00edvel, de\u00a0comprimento\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>d\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e de massa desprez\u00edvel. Esse p\u00eandulo oscila em um plano vertical em torno do ponto\u00a0P\u00a0ao qual o fio est\u00e1 preso. As\u00a0posi\u00e7\u00f5es I e II\u00a0especificam, respectivamente, os\u00a0pontos mais alto e<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_981ae81.png\" alt=\"\" width=\"416\" height=\"288\" name=\"Imagem 472\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>mais baixo da trajet\u00f3ria\u00a0do pequeno corpo. Sabendo que a\u00a0altura m\u00e1xima\u00a0que o corpo atinge em\u00a0rela\u00e7\u00e3o ao ponto II \u00e9\u00a0h, calcule (em fun\u00e7\u00e3o\u00a0de\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>d<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>h\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e do valor\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>g\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da acelera\u00e7\u00e3o da gravidade):<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a\u00a0velocidade\u00a0do corpo ao passar\u00a0pelo ponto II.\u00a0Sugest\u00e3o: Utilize a\u00a0conserva\u00e7\u00e3o da energia mec\u00e2nica;<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a\u00a0tens\u00e3o\u00a0T\u00a0no fio do p\u00eandulo ao\u00a0passar pelo ponto II.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Trabalho- Energia<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>01-(UFSCAR-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_be9975be.png\" alt=\"\" width=\"765\" height=\"143\" name=\"Imagem 473\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para realizar uma reforma na laje de um edif\u00edcio, uma empreiteira instalou um pequeno guindaste a uma<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9e77c0f1.png\" alt=\"\" width=\"493\" height=\"240\" name=\"Imagem 474\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>altura de 15 m do ch\u00e3o. Ao\u00a0descer\u00a0uma carga de entulho, o guindaste necessita de\u00a060 s\u00a0e emprega<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>uma\u00a0pot\u00eancia de 900 W, fazendo com que a\u00a0velocidade\u00a0de descida seja\u00a0constante. Sabendo que a acelera\u00e7\u00e3o da gravidade \u00e9\u00a010 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e supondo que toda a pot\u00eancia seja empregada para realizar o movimento da carga, a\u00a0massa\u00a0de entulho, em kg, \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 120. (B) 180. (C) 300. (D) 360. (E) 540.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-(UERJ-RJ-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_923f1ed7.jpg\" alt=\"\" width=\"553\" height=\"157\" name=\"Imagem 475\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em um experimento, s\u00e3o produzidos\u00a0feixes de \u00e1tomos de hidrog\u00eanio, de h\u00e9lio, de prata e de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_e5f8c318.png\" alt=\"\" width=\"244\" height=\"167\" name=\"Imagem 476\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>chumbo. Estes \u00e1tomos\u00a0deslocam-se paralelamente com velocidades de\u00a0mesma magnitude.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Suas\u00a0energias cin\u00e9ticas\u00a0valem, respectivamente, E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>H<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>He<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ag<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pb<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0rela\u00e7\u00e3o\u00a0entre essas energias \u00e9 dada por:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>He<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>H<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pb<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ag<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0B) E\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ag<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pb<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>H<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>He<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C) E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>H<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>He<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ag<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pb<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0D) E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pb<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ag<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>He<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt; E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>H<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03-(UNICAMP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_85522f49.jpg\" alt=\"\" width=\"779\" height=\"159\" name=\"Imagem 477\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Andar de bondinho no complexo do\u00a0P\u00e3o de A\u00e7\u00facar no Rio de Janeiro\u00a0\u00e9 um dos passeios a\u00e9reos urbanos mais famosos do mundo. Marca registrada da cidade, o Morro do P\u00e3o de A\u00e7\u00facar \u00e9 constitu\u00eddo de um \u00fanico<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>bloco de granito, despido de vegeta\u00e7\u00e3o em sua quase totalidade e tem mais de 600 milh\u00f5es de anos.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A altura do Morro da Urca \u00e9 de\u00a0220 m\u00a0e a altura do P\u00e3o de A\u00e7\u00facar \u00e9 de cerca de\u00a0400 m,\u00a0ambas em rela\u00e7\u00e3o<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_fbae4249.png\" alt=\"\" width=\"472\" height=\"220\" name=\"Imagem 478\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ao solo. A\u00a0varia\u00e7\u00e3o da energia potencial gravitacional\u00a0do bondinho com passageiros de\u00a0massa total M =\u00a05000 kg,\u00a0no segundo trecho do passeio, \u00e9 (Use g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 9.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>6\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J. b) 11.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>6<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J c) 20.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>6<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J d) 31.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>6<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>04-(UNICAMP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_a40809d5.png\" alt=\"\" width=\"771\" height=\"158\" name=\"Imagem 479\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O\u00a0ar atmosf\u00e9rico\u00a0oferece uma\u00a0resist\u00eancia significativa\u00a0ao movimento dos autom\u00f3veis. Suponha que<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b9b0307c.png\" alt=\"\" width=\"403\" height=\"161\" name=\"Imagem 480\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>um determinado autom\u00f3vel movido a gasolina, trafegando em\u00a0linha reta\u00a0a uma\u00a0velocidade constante de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>V=72km\/h\u00a0com rela\u00e7\u00e3o ao ar, seja submetido a uma\u00a0for\u00e7a de atrito de F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 380 N.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma viagem de\u00a0uma hora, aproximadamente\u00a0quantos litros de gasolina ser\u00e3o consumidos\u00a0somente para\u00a0\u201cvencer\u201d o atrito imposto pelo ar?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dados: calor de combust\u00e3o da gasolina: 35 MJ\/\u2113 . Rendimento do motor a gasolina: 30%.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>05-(FUVEST-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_92da8aa7.png\" alt=\"\" width=\"773\" height=\"175\" name=\"Imagem 481\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma competi\u00e7\u00e3o de salto em dist\u00e2ncia, um atletade70kgtem,\u00a0imediatamente antes\u00a0do salto, uma<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_48327bce.png\" alt=\"\" width=\"531\" height=\"183\" name=\"Imagem 482\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade na\u00a0dire\u00e7\u00e3o horizontal de m\u00f3dulo10m\/s.\u00a0Aosaltar, o atleta usa seus m\u00fasculos para empurrar o ch\u00e3o na\u00a0dire\u00e7\u00e3o vertical, produzindo uma\u00a0energia de 500J,\u00a0sendo 70%\u00a0desse valornaformadeenergia cin\u00e9tica.Imediatamenteap\u00f3sseseparardoch\u00e3o,om\u00f3dulodavelocidadedoatleta \u00e9 maispr\u00f3ximode<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 10,0m\/s b) 10,5m\/s c) 12,2m\/s d) 13,2m\/s e) 13,8m\/s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>06-(FGV-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_451823f2.png\" alt=\"\" width=\"459\" height=\"150\" name=\"Imagem 483\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com a velocidade crescendo de modo constante, em fun\u00e7\u00e3o do tempo, \u00e9 correto afirmar que a <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_bd19ff54.png\" alt=\"\" width=\"541\" height=\"212\" name=\"Imagem 484\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dist\u00e2ncia entre os dois radares \u00e9 de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 450 m. (B) 675 m. (C) 925 m. (D) 1,075 km. (E) 1,350 km.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>07-(FGV-SP-014)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_cb1f3890.png\" alt=\"\" width=\"538\" height=\"164\" name=\"Imagem 485\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O trabalho realizado pela resultante das for\u00e7as agentes sobre o autom\u00f3vel foi, em joules, mais pr\u00f3ximo de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 1,5\u00b710<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. (B) 5,2\u00b710<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. (C) 7,5\u00b710<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. (D) 1,7\u00b710<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. (E) 3,2\u00b710<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>08-(AFA-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1b025ca8.png\" alt=\"\" width=\"515\" height=\"145\" name=\"Imagem 486\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um bloco, de massa 2 kg, desliza sobre um plano inclinado, conforme a figura 1. O gr\u00e1fico v x t, figura 2, representa a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ddea61e1.png\" alt=\"\" width=\"641\" height=\"210\" name=\"Imagem 487\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade desse bloco em fun\u00e7\u00e3o do tempo, durante sua subida, desde o ponto A at\u00e9 o ponto B.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere a exist\u00eancia de atrito entre o bloco e o plano inclinado e despreze quaisquer outras formas de resist\u00eancia<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ao movimento. Sabendo que o bloco retorna ao ponto A, a velocidade com que ele passa por esse ponto, na descida,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>em m\/s, vale<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 4 b) 2\u221a2 c) 2 d) \u221a3<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>09-(ACAFE-SC-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d777c932.jpg\" alt=\"\" width=\"509\" height=\"165\" name=\"Imagem 488\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sem prote\u00e7\u00e3o adequada, uma queda com skate pode causar s\u00e9rias les\u00f5es, dependendo da\u00a0velocidade\u00a0que ocorre a queda. Um menino\u00a0em repouso\u00a0no seu skate encontra-se no\u00a0ponto mais alto<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_84865abc.png\" alt=\"\" width=\"367\" height=\"212\" name=\"Imagem 489\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de uma rampa e\u00a0come\u00e7a a descer, chegando ao ponto mais baixo com velocidade de m\u00f3dulo 2,0 m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em seguida, o menino se\u00a0lan\u00e7a para baixo com o mesmo skate desse ponto mais alto com uma velocidade inicial de m\u00f3dulo 1,5 m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabendo que, em\u00a0ambas as situa\u00e7\u00f5es, ap\u00f3s iniciado o movimento, o\u00a0menino n\u00e3o toca mais os p\u00e9s no solo, a alternativa\u00a0correta\u00a0que indica o m\u00f3dulo da velocidade, em\u00a0m\/s, com que o menino no skate chega ao ponto mais baixo na segunda situa\u00e7\u00e3o,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A)\u00a00,5 B) 3,5\u00a0C)\u00a02,1\u00a0D) 1,2<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>10-(IFMT-MT-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_41db97f4.jpg\" alt=\"\" width=\"680\" height=\"157\" name=\"Imagem 490\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0corpo de 2 kg \u00e9 jogado de baixo para cima, a partir da\u00a0base de um plano inclinado de\u00a08 m de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9f553ba9.png\" alt=\"\" width=\"385\" height=\"173\" name=\"Imagem 491\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>comprimento. Ele\u00a0para exatamente no ponto mais alto do plano\u00a0e, em seguida,\u00a0retorna \u00e0 base.\u00a0Considerando\u00a0g = 10 m\/s2<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e sabendo que o\u00a0\u00e2ngulo\u00a0que o plano forma com a\u00a0horizontal \u00e9 de 30\u00b0,\u00a0assinale o\u00a0trabalho do peso do corpo em Joule (J), na subida e na descida\u00a0respectivamente. Dados:\u00a0cos30\u00b0 = 0,866 e sen30\u00ba= 0,500.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) &#8211; 40 e 40 b) 40 e \u2013 40 c) &#8211; 80 e 80 d) -160 e 160 e) 160 e 160<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Din\u00e2mica Impulsiva<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>01-(FMJ-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f16a3464.png\" alt=\"\" width=\"675\" height=\"154\" name=\"Imagem 492\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Suponha dois corpos celestes viajando no espa\u00e7o sideral. Suasmassas s\u00e3o\u00a0M<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e M<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Em rela\u00e7\u00e3o a um referencial inercial, o primeiro se desloca a uma velocidade\u00a0v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e o segundo a uma velocidadev<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><a name=\"_GoBack\"><\/a> <span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>perpendicular a v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Considere que ocorra uma\u00a0colis\u00e3o totalmente inel\u00e1stica\u00a0entre eles. A\u00a0quantidade de movimento do sistema, logo ap\u00f3s a colis\u00e3o,\u00a0ser\u00e1 expressa por<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ae23528.png\" alt=\"\" width=\"774\" height=\"45\" name=\"Imagem 493\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-(EsPCEx-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ab45b56d.jpg\" alt=\"\" width=\"628\" height=\"160\" name=\"Imagem 494\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um bloco de\u00a0massa M=180g\u00a0est\u00e1 sobre uma superf\u00edcie horizontal sem atrito, e prende-se \u00e0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>extremidade de uma\u00a0mola ideal\u00a0de massa desprez\u00edvel e\u00a0constante el\u00e1stica igual a 2.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0N\/m. A outra<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>extremidade da mola est\u00e1 presa a um suporte fixo, conforme mostra o desenho.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_a76b9caa.png\" alt=\"\" width=\"474\" height=\"139\" name=\"Imagem 495\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Inicialmente o bloco se encontra\u00a0em repouso e a mola no seu comprimento natural, isto \u00e9, sem deforma\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um proj\u00e9til de\u00a0massa m=20g\u00a0\u00e9 disparado horizontalmente contra o bloco, que \u00e9 de f\u00e1cil penetra\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ele\u00a0atinge o bloco\u00a0no centro de sua face, com velocidade de\u00a0v=200m\/s. Devido ao choque,\u00a0o proj\u00e9til<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>aloja-se no interior do bloco. Desprezando a resist\u00eancia do ar, a\u00a0compress\u00e3o m\u00e1xima da mola\u00a0\u00e9 de:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 10,0 cm b) 12,0 cm c) 15,0 cm d) 20,0 cm e) 30,0 cm<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03-(FGV-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_7f88da1e.png\" alt=\"\" width=\"585\" height=\"157\" name=\"Imagem 496\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Na loja de um supermercado, uma cliente lan\u00e7a seu carrinho com compras, de massa total 30 kg, em <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_48aad0a8.png\" alt=\"\" width=\"375\" height=\"198\" name=\"Imagem 497\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>outro carrinho vazio, parado e de massa 20 kg. Ocorre o engate entre ambos e, como consequ\u00eancia do engate, o conjunto dos carrinhos percorre 6,0 m em 4,0 s, perdendo velocidade de modo uniforme at\u00e9 parar. O sistema de carrinhos \u00e9 considerado isolado durante o engate. A velocidade do carrinho com compras imediatamente antes do engate era, em m\/s, de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 5,0. (B) 5,5. (C) 6,0. (D) 6,5. (E) 7,0.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>04-(UNICAMP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_41d1f8fe.png\" alt=\"\" width=\"654\" height=\"148\" name=\"Imagem 498\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Existem in\u00fameros tipos de extintores de inc\u00eandio que devem ser utilizados de acordo com a classe do<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>fogo a se extinguir. No caso de inc\u00eandio envolvendo\u00a0l\u00edquidos inflam\u00e1veis, classe B, os extintores \u00e0 base<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_8bc833f5.png\" alt=\"\" width=\"391\" height=\"206\" name=\"Imagem 499\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de\u00a0p\u00f3 qu\u00edmico ou de di\u00f3xido de carbono (CO<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>)\u00a0s\u00e3o recomendados, enquanto extintores de \u00e1gua devem ser evitados, pois podem espalhar o fogo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Suponha que um extintor de\u00a0CO<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0completamente\u00a0carregado, isolado e inicialmente em repouso, lance um jato de CO<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0de\u00a0massa\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m=<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Symbol,serif;\"><span style=\"font-size: medium;\"><b>\uf020<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>50 g com velocidade v=20 m\/s\u00a0. Estime a\u00a0massa total\u00a0do extintor\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>M<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>ext<\/b><\/i><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e calcule a sua\u00a0velocidade de recuoprovocada pelo lan\u00e7amento do g\u00e1s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Despreze a varia\u00e7\u00e3o da massa total do cilindro decorrente do lan\u00e7amento do jato.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>05-(UPF-RS-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_4349473f.png\" alt=\"\" width=\"637\" height=\"161\" name=\"Imagem 500\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma\u00a0mesa de sinuca, uma bola \u00e9 lan\u00e7ada\u00a0frontalmente contra outra bola\u00a0em repouso.\u00a0Ap\u00f3s a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d8efccf.png\" alt=\"\" width=\"369\" height=\"206\" name=\"Imagem 501\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>colis\u00e3o, a bola incidente\u00a0para e a bola alvo (bola atingida)\u00a0passa a se mover na\u00a0mesma dire\u00e7\u00e3o do movimento da bola incidente.\u00a0Supondo que as bolas\u00a0tenham massas id\u00eanticas, que o choque seja el\u00e1stico\u00a0e que a\u00a0velocidade da bola incidente seja de 2 m\/s, qual ser\u00e1,\u00a0em m\/s, a velocidade inicial da bola alvo ap\u00f3s a colis\u00e3o?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,5 b) 1 c) 2 d) 4 e) 8<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>06-(UNESP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_a86da273.jpg\" alt=\"\" width=\"773\" height=\"162\" name=\"Imagem 502\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0garoto de 50 kg\u00a0est\u00e1\u00a0parado dentro de um barco de 150 kg\u00a0nas proximidades da plataforma de um ancoradouro. Nessa situa\u00e7\u00e3o, o\u00a0barco flutua em repouso, conforme a figura 1.\u00a0Em um\u00a0determinado instante, o garoto\u00a0salta para o ancoradouro, de modo que, quando abandona o barco, a\u00a0componente horizontal de sua\u00a0velocidade tem m\u00f3dulo igual a 0,9 m\/s\u00a0em rela\u00e7\u00e3o<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e0s \u00e1guas paradas, de acordo com a figura 2.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f1d60278.png\" alt=\"\" width=\"789\" height=\"224\" name=\"Imagem 503\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabendo que a\u00a0densidade da \u00e1gua \u00e9 igual a 10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0kg\/m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, adotando g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e\u00a0desprezando a resist\u00eancia da \u00e1gua ao movimento do barco, calcule o\u00a0volume de \u00e1gua, em m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, que a parte submersa do barco desloca quando o garoto est\u00e1 em repouso dentro dele, antes de saltar para o ancoradouro, e o\u00a0m\u00f3dulo da velocidade horizontal de recuo (Vrec) do barco em rela\u00e7\u00e3o\u00a0\u00e0s \u00e1guas, em m\/s,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>imediatamente depois que o garoto salta para sair dele<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>07-(FUVEST-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_687cb0e0.jpg\" alt=\"\" width=\"662\" height=\"173\" name=\"Imagem 504\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um n\u00facleo de pol\u00f4nio-204(<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>204<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>P<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>), em repouso, transmuta-se em um n\u00facleo de chumbo-200(<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>200<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>P<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>), emitindo<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6786a54e.png\" alt=\"\" width=\"390\" height=\"179\" name=\"Imagem 505\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>uma part\u00edcula alfa(\u03b1) com energia cin\u00e9tica E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u03b1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nesta rea\u00e7\u00e3o, a energia cin\u00e9tica do n\u00facleo de chumbo \u00e9 igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_2d32391e.png\" alt=\"\" width=\"353\" height=\"175\" name=\"Imagem 506\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ebaacd61.png\" alt=\"\" width=\"676\" height=\"42\" name=\"Imagem 507\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>08-(UNIFESP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f667bda2.png\" alt=\"\" width=\"779\" height=\"143\" name=\"Imagem 508\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma empresa de demoli\u00e7\u00e3o utiliza um guindaste, extremamente massivo, que se mant\u00e9m\u00a0em repouso\u00a0e em\u00a0equil\u00edbrio est\u00e1vel no solo\u00a0durante todo o processo. Ao bra\u00e7o superior fixo da treli\u00e7a do guindaste,\u00a0ponto O, prende-se um cabo, de massa desprez\u00edvel e inextens\u00edvel,\u00a0de 10 m de comprimento. A outra extremidade do cabo \u00e9 presa a uma\u00a0bola de 300 kg que parte do repouso, com o cabo esticado, do ponto A.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_195d694a.png\" alt=\"\" width=\"642\" height=\"252\" name=\"Imagem 509\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabe-se que a trajet\u00f3ria da bola, contida em um plano vertical, do\u00a0ponto A at\u00e9 o ponto B, \u00e9 um\u00a0arco de circunfer\u00eancia\u00a0com centro no ponto O; que o m\u00f3dulo da\u00a0velocidade da bola\u00a0no ponto B, imediatamente antes de atingir a estrutura do pr\u00e9dio,\u00a0\u00e9 de 2 m\/s; que o choque frontal da bola com o pr\u00e9dio\u00a0dura 0,02 s; e que depois desse intervalo de tempo a\u00a0bola para instantaneamente. Desprezando a resist\u00eancia do ar e adotando g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, calcule, em newtons:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0o m\u00f3dulo da for\u00e7a resultante m\u00e9dia que atua na bola no intervalo de tempo de dura\u00e7\u00e3o do choque.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b)\u00a0o m\u00f3dulo da for\u00e7a de tra\u00e7\u00e3o no cabo no instante em que a bola \u00e9 abandonada do repouso no ponto A.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>09-(UNIFESP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_3b7460e7.png\" alt=\"\" width=\"775\" height=\"158\" name=\"Imagem 510\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma bancada horizontal da linha de produ\u00e7\u00e3o de uma ind\u00fastria, um\u00a0amortecedor fixo\u00a0na bancada tem a fun\u00e7\u00e3o de\u00a0reduzir a zero a\u00a0velocidade de uma caixa,\u00a0para que um trabalhador possa peg\u00e1-la. Esse amortecedor cont\u00e9m uma mola horizontal de\u00a0constante el\u00e1stica K = 180 N\/m\u00a0e um pino acoplado a ela tendo esse conjunto massa desprez\u00edvel.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_22c203d9.png\" alt=\"\" width=\"743\" height=\"169\" name=\"Imagem 511\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A caixa tem massa\u00a0m = 3 kg\u00a0e escorrega em linha reta sobre a bancada, quando toca o pino do\u00a0amortecedor com velocidade V<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabendo que o\u00a0coeficiente de atrito\u00a0entre as superf\u00edcies da caixa e da bancada \u00e9\u00a00,4,\u00a0que a\u00a0compress\u00e3o\u00a0m\u00e1xima sofrida pela mola quando a caixa para \u00e9 de 20 cm\u00a0e adotando\u00a0g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, calcule:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0o trabalho, em joules, realizado pela for\u00e7a de atrito que atua sobre a caixa\u00a0desde o instante em que ela toca o amortecedor at\u00e9 o instante em que ela para.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b)\u00a0o\u00a0m\u00f3dulo da velocidade\u00a0V<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0da caixa, em m\/s, no\u00a0instante em que ela toca\u00a0o amortecedor.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>10-(UEL-PR-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_96cdb02f.jpg\" alt=\"\" width=\"779\" height=\"165\" name=\"Imagem 512\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Analise as figuras a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma part\u00edcula\u00a01\u00a0com\u00a0massa\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>M<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, inicialmente em repouso, que est\u00e1 a uma altura\u00a0de\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>h\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 1<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>,\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>25\u00a0m, desliza\u00a0sem atrito por uma calha,\u00a0como esquematizado na Figura 1. Essa part\u00edcula\u00a0colide elasticamente\u00a0com<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_12ade64a.png\" alt=\"\" width=\"743\" height=\"165\" name=\"Imagem 513\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a part\u00edcula\u00a02\u00a0com\u00a0massa\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, inicialmente em repouso.\u00a0Ap\u00f3s a colis\u00e3o, a\u00a0velocidade horizontal final\u00a0da\u00a0part\u00edcula 1 \u00e9\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>V<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>1f<\/b><\/i><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=\u00a04,5 m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Utilizando a\u00a0acelera\u00e7\u00e3o da gravidade\u00a0g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, calcule<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a\u00a0velocidade horizontal da part\u00edcula\u00a01 antes da colis\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a\u00a0velocidade horizontal da part\u00edcula\u00a02 ap\u00f3s a colis\u00e3o e a altura m\u00e1xima que ela atinge.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Primeira lei de Newton<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>29-(UDESC-SC-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_fa997f0e.jpg\" alt=\"\" width=\"759\" height=\"155\" name=\"Imagem 514\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere o movimento de um objeto sujeito \u00e0 a\u00e7\u00e3o de v\u00e1rias for\u00e7as, de modo que a resultante delas seja nula em todos os instantes.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Analise as proposi\u00e7\u00f5es em rela\u00e7\u00e3o \u00e0 informa\u00e7\u00e3o acima.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I. Se o objeto estiver inicialmente em movimento, ele n\u00e3o poder\u00e1 atingir o repouso em algum instante de tempo posterior ao inicial.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II. Se o objeto estiver inicialmente em movimento, ele poder\u00e1 atingir o repouso em algum instante de tempo posterior ao inicial.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III. Se o objeto estiver inicialmente em repouso, ele poder\u00e1 entrar em movimento em algum instante de tempo posterior ao inicial.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa correta.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A. ( ) Somente a afirmativa III \u00e9 verdadeira.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. ( ) Somente a afirmativa II \u00e9 verdadeira.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C. ( ) Somente a afirmativa I \u00e9 verdadeira.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. ( ) Somente as afirmativas II e III s\u00e3o verdadeiras.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>E. ( ) Somente as afirmativas I e III s\u00e3o verdadeiras.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>30-(UFRN-RN-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_418a0930.jpg\" alt=\"\" width=\"610\" height=\"142\" name=\"Imagem 515\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um dos esportes ol\u00edmpicos mais tradicionais \u00e9 o salto\u00a0 ornamental em piscina. Nele, o atleta salta do alto de um trampolim visando executar uma trajet\u00f3ria parab\u00f3lica at\u00e9 atingir a \u00e1gua. Aliado a esse movimento, ele\u00a0 tem\u00a0 de executar outros movimentos, pontuados pelos ju\u00edzes,\u00a0 como o de encolher momentaneamente bra\u00e7os e pernas de modo que, al\u00e9m da trajet\u00f3ria parab\u00f3lica de seu centro de massa, ele passe tamb\u00e9m a girar seu corpo em torno do\u00a0 seu centro de massa. No final do salto, ele estica novamente os bra\u00e7os e\u00a0 as pernas visando cair de cabe\u00e7a na \u00e1gua. Essa<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>sequ\u00eancia de movimentos\u00a0 est\u00e1 representada na figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_813ba899.jpg\" alt=\"\" width=\"507\" height=\"236\" name=\"Imagem 516\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Comparando\u00a0 o movimento inicial feito pelo atleta com bra\u00e7os e pernas estendidos ao movimento realizado com esses membros dobrados\u00a0 junto ao tronco, a lei de conserva\u00e7\u00e3o do momento angular permite afirmar que<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) h\u00e1 uma diminui\u00e7\u00e3o do momento de in\u00e9rcia do atleta e, portanto, uma diminui\u00e7\u00e3o na sua velocidade de rota\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B) h\u00e1 uma diminui\u00e7\u00e3o do momento de in\u00e9rcia do atleta e, portanto, um aumento na sua velocidade de rota\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C) h\u00e1 um aumento do momento de in\u00e9rcia do atleta e, portanto, um aumento na sua velocidade de rota\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>D) h\u00e1 um aumento do momento de in\u00e9rcia do atleta e, portanto, uma diminui\u00e7\u00e3o na sua velocidade de rota\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>31-(PUC-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_af4fb137.jpg\" alt=\"\" width=\"691\" height=\"153\" name=\"graphics46\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>FOR\u00c7A ESTRANHA<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com a Terra girando a quase 1700 km\/h no equador, seria de se esperar que todos fic\u00e1ssemos enjoados, certo? Errado. N\u00e3o \u00e9 a velocidade que nos afeta, \u00e9 a acelera\u00e7\u00e3o, como qualquer piloto de corridas pode confirmar. O giro \u201cvagaroso\u201d<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_e86323d9.jpg\" alt=\"\" width=\"161\" height=\"170\" name=\"graphics47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da Terra produz uma acelera\u00e7\u00e3o 100 vezes menor do que a experimentada num carrossel de um parque de divers\u00f5es. Ainda assim, a rota\u00e7\u00e3o da Terra pode se fazer notar por seus habitantes, por meio do fen\u00f4meno chamado For\u00e7a de Coriolis, que ganhou esse nome em homenagem ao f\u00edsico e matem\u00e1tico Gaspard-Gustave Coriolis. Coriolis determinou que qualquer coisa que se mova em conjunto com um objeto em rota\u00e7\u00e3o vai perceber a realidade como se tivesse sido retirada do seu curso natural por uma for\u00e7a vinda sabe-se-l\u00e1 de onde. <\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Por exemplo, uma pessoa num carrossel girando que tente jogar uma bola numa cesta fixa do outro lado do carrossel, vai achar que a bola sempre \u00e9 desviada do alvo por alguma \u201cfor\u00e7a estranha\u201d. Essa tal \u201cfor\u00e7a estranha\u201d n\u00e3o existe de fato.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Qualquer um que olhe a cena de fora do carrossel vai perceber que o fen\u00f4meno \u00e9 simplesmente o resultado do movimento da cesta, que se moveu em sua rota\u00e7\u00e3o enquanto a bola est\u00e1 no ar. Mas, para os que est\u00e3o no carrossel, a for\u00e7a \u00e9 bem real. Por isso, ela precisa ser levada em conta quando calculamos os percursos de objetos t\u00e3o distintos como m\u00edsseis e furac\u00f5es.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Adaptado do texto Robert Matthews. Revista Conhecer \u2013 N\u00ba 33, mar\u00e7o de 2012.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>(PUC-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_36f88af1.jpg\" alt=\"\" width=\"641\" height=\"152\" name=\"graphics48\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando-se a velocidade de rota\u00e7\u00e3o da Terra informada no texto, uma pessoa na superf\u00edcie n\u00e3o sente o efeito:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) porque a velocidade relativa \u00e9 praticamente zero, devido \u00e0 in\u00e9rcia.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) porque a for\u00e7a centr\u00edpeta \u00e9 igual \u00e0 for\u00e7a centr\u00edfuga.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) porque n\u00e3o h\u00e1 for\u00e7a centr\u00edpeta.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) devido \u00e0 for\u00e7a da gravidade.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Segunda lei de Newton<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>34-(CEDERJ-RJ-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6a32be92.jpg\" alt=\"\" width=\"753\" height=\"142\" name=\"graphics49\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma caixa \u00e9 arrastada em trajet\u00f3ria retil\u00ednea sobre a superf\u00edcie horizontal de uma mesa, puxada por um fio (F) paralelo \u00e0 superf\u00edcie. Existe atrito (<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ecca7ea2.jpg\" alt=\"\" width=\"16\" height=\"17\" name=\"graphics50\" align=\"BOTTOM\" border=\"0\" \/>) entre a mesa e a caixa. A figura a seguir ilustra a situa\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_a691e16f.jpg\" alt=\"\" width=\"559\" height=\"193\" name=\"graphics51\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Quando o arrasto se d\u00e1 a uma velocidade constante, o valor da tens\u00e3o no fio \u00e9 de 1N, n\u00e3o importando qual \u00e9 o valor da velocidade. Quando o arrasto se d\u00e1 com acelera\u00e7\u00e3o constante, a tens\u00e3o no fio cresce linearmente com a acelera\u00e7\u00e3o. O gr\u00e1fico abaixo mostra esse comportamento.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9d94666e.jpg\" alt=\"\" width=\"540\" height=\"200\" name=\"graphics52\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Justifique , com base nessas informa\u00e7\u00f5es, porque o valor da for\u00e7a de atrito entre a caixa e a superf\u00edcie da mesa \u00e9 de 1N.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Qual a massa da caixa?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>35-(UEPG-PR-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6aec473d.jpg\" alt=\"\" width=\"751\" height=\"146\" name=\"graphics53\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Analisando a a\u00e7\u00e3o do sistema de for\u00e7as que age no corpo, conforme figura abaixo, assinale o que for correto.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f8e7e268.jpg\" alt=\"\" width=\"493\" height=\"222\" name=\"graphics54\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01) A resultante das for\u00e7as sobre o eixo X ser\u00e1 conhecida por R<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>x<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cos\u03b1 \u2013 \u03bcN \u2013 F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>sen\u03b2.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02) A resultante de todo o sistema \u00e9 conhecida pela soma dos vetores R<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>x<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e R<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>y<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04) Se a resultante do sistema for igual a zero, ent\u00e3o o corpo est\u00e1 em repouso absoluto.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08) A resultante das for\u00e7as sobre o eixo Y ser\u00e1 conhecida por R<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>y<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cos\u03b1 + F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cos\u03b2 &#8211; P.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>16) A for\u00e7a de atrito mostrada na figura est\u00e1 fora do eixo X e n\u00e3o pode ser computada como for\u00e7a atuante no sistema.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Terceira lei de Newton<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>20-(UEG-GO-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_82c921f8.jpg\" alt=\"\" width=\"421\" height=\"149\" name=\"Imagem 526\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>No reino animal, existem seres que t\u00eam a capacidade de realizar diferentes tipos de v\u00f4os. O v\u00f4o pode ser dividido em<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9763f9bf.jpg\" alt=\"\" width=\"534\" height=\"150\" name=\"Imagem 527\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>tr\u00eas grupos: o paraquedismo, o planeio e o voo propulsionado. Com rela\u00e7\u00e3o aos tipos de voo, considera-se o seguinte:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) no animal planador, a facilidade do voo depende da forma e da dimens\u00e3o das asas, sendo o movimento no ar ascendente e sem realiza\u00e7\u00e3o de trabalho.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) no paraquedismo, a for\u00e7a de resist\u00eancia do ar no animal equilibra-se com o seu peso, fazendo-o cair com velocidade constante.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) nos voos propulsionados, os animais exercem a movimenta\u00e7\u00e3o de seus m\u00fasculos para impulsionarem o deslocamento vertical.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) o paraquedismo e o planeio baseiam-se em princ\u00edpios f\u00edsicos iguais, pois as for\u00e7as de resist\u00eancia e peso s\u00e3o um par de a\u00e7\u00e3o e rea\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios sobre conceitos das tr\u00eas leis de Newton<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>57-(UENP-PR-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_5c1ad09e.jpg\" alt=\"\" width=\"553\" height=\"151\" name=\"Imagem 528\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0\u00a0\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um autom\u00f3vel de massa 1200kg se desloca sobre uma rodovia com velocidade de 108 km\/h, quando avista uma<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_54ba376e.jpg\" alt=\"\" width=\"701\" height=\"170\" name=\"graphics55\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>fiscaliza\u00e7\u00e3o policial e aciona os freios at\u00e9 parar. Sabendo-se que a dist\u00e2ncia percorrida nesse intervalo de tempo em que os freios foram acionados \u00e9 de 200m, calcule o m\u00f3dulo da acelera\u00e7\u00e3o e o m\u00f3dulo do trabalho realizado pelos freios do ve\u00edculo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 1,00 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>; 5,9.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 2,25 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>; 5,4.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 2,50 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>; 2,8.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 2,25 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>; 3,7.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 1,00 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>; zero<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>58-(UCS-RS-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_665eafe1.jpg\" alt=\"\" width=\"763\" height=\"162\" name=\"graphics56\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Na luta de sum\u00f4, em que dois lutadores se enfrentam dentro de uma \u00e1rea circular, para vencer \u00e9 necess\u00e1rio, utilizando o<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_a251a3e1.jpg\" alt=\"\" width=\"373\" height=\"201\" name=\"graphics57\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>corpo e os bra\u00e7os, empurrar o oponente para fora do c\u00edrculo. Suponha que dois oponentes, de 200 kg cada, colidam exatamente no centro do c\u00edrculo e que um dos lutadores consiga aplicar uma for\u00e7a de 1.000 N permanentemente sobre o outro, o qual, por sua vez, aplica uma for\u00e7a de 950 N permanentemente sobre o primeiro. Ambas as for\u00e7as t\u00eam dire\u00e7\u00e3o paralela ao ch\u00e3o e sentidos opostos. Se o c\u00edrculo possui 2,0 m de raio, quanto tempo aproximadamente levar\u00e1 para a luta acabar? Para fins de simplifica\u00e7\u00e3o, ignore o volume do corpo dos lutadores, e considere que, no momento exato da colis\u00e3o, eles ficam em breve repouso.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,5 s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 1,0 s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 2,0 s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 3,0 s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 4,0 s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Tipos de for\u00e7a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>39-(FATEC-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_89c8ca5c.jpg\" alt=\"\" width=\"703\" height=\"118\" name=\"Imagem 59\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um carro em um ve\u00edculo do tipo \u201ccegonha\u201d (que transporta v\u00e1rios carros) tem cada uma de suas rodas travada por uma cinta, cujos extremos est\u00e3o presos sobre a plataforma em que se ap\u00f3ia o carro. A cinta abra\u00e7a parcialmente o pneu, e a regulagem de sua tens\u00e3o garante a seguran\u00e7a para o transporte, j\u00e1 que aumenta a intensidade da for\u00e7a de contato entre cada pneu e a plataforma.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_7a71989a.jpg\" alt=\"\" width=\"651\" height=\"252\" name=\"Imagem 60\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Se o \u00e2ngulo formado entre a plataforma e a cinta, de ambos os lados do pneu, \u00e9 de 60<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, admitindo que cada extremo da cinta se encontre sob uma tra\u00e7\u00e3o de intensidade T, o acr\u00e9scimo da for\u00e7a de contato de intensidade F entre cada pneu e a plataforma, devido ao uso desse dispositivo, \u00e9 dado por<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(A) F=T\/2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) F=(\u221a3\/2)T\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (C) F=T\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D) F=\u221a3.T\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E) F=4(\u221a3\/3).T<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>40-(ENEM-MEC-012)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_c14c4c7.jpg\" alt=\"\" width=\"224\" height=\"123\" name=\"graphics58\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O mecanismo que permite articular uma porta (de um m\u00f3vel ou de acesso) \u00e9 a dobradi\u00e7a. Normalmente, s\u00e3o necess\u00e1rias<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d6bf46ee.jpg\" alt=\"\" width=\"240\" height=\"196\" name=\"graphics59\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>duas ou mais dobradi\u00e7as para que a porta seja fixada no m\u00f3vel ou no portal, permanecendo em equil\u00edbrio e podendo ser articulada com facilidade.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>No plano, o diagrama vetorial das for\u00e7as que as dobradi\u00e7as exercem na porta est\u00e1 representado em<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ac83a641.jpg\" alt=\"\" width=\"776\" height=\"173\" name=\"Imagem 536\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Peso e massa<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>33-(PUC-RJ-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d0afc780.jpg\" alt=\"\" width=\"643\" height=\"154\" name=\"graphics60\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um objeto de 3,10 kg \u00e9 liberado por um astronauta, a partir do repouso, e cai em dire\u00e7\u00e3o \u00e0 superf\u00edcie do planeta<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_172c448e.jpg\" alt=\"\" width=\"269\" height=\"175\" name=\"graphics61\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Marte. \u00a0Calcule a for\u00e7a peso em Newtons atuando sobre o objeto, expressando o resultado com o n\u00famero de algarismos significativos apropriado.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere a acelera\u00e7\u00e3o da gravidade g<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Marte<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 3,69 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 31,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) 11,439\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (C) 11,44\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D) 11,4\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E) 6,79<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>34-(UNIMONTES-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_4ce1c51f.jpg\" alt=\"\" width=\"691\" height=\"159\" name=\"Imagem 539\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um conjunto de molas sustenta o peso de um carro. Com 2 pessoas de 60kg em seu interior, o carro abaixa 2cm. Com 4<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6d43bd9c.jpg\" alt=\"\" width=\"341\" height=\"148\" name=\"Imagem 540\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pessoas de 70kg, o carro vai abaixar, aproximadamente: g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2.<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 3,0cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B) 3,5cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C) 4,0cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D) 4,7cm.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Leis de Newton do MUV<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>48-(UEL-PR-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6c791db8.jpg\" alt=\"\" width=\"762\" height=\"147\" name=\"Imagem 541\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere a \ufb01gura a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_319c8dbe.jpg\" alt=\"\" width=\"593\" height=\"152\" name=\"graphics62\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Despreze qualquer tipo de atrito.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) O m\u00f3vel de massa M = 1200 kg \u00e9 uniformemente acelerado (com acelera\u00e7\u00e3o a) a partir do repouso em t = 0 segundos, atingindo B, em t = 10 segundos, com a velocidade de 108 km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule a for\u00e7a resultante que atua no m\u00f3vel de A at\u00e9 B.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) No ponto B, a acelera\u00e7\u00e3o a do m\u00f3vel deixa de existir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule a dist\u00e2ncia BC percorrida pelo m\u00f3vel, sabendo-se que ele alcan\u00e7a C no instante t = 15 segundos.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, determine a energia mec\u00e2nica total do m\u00f3vel em C.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Apresente os c\u00e1lculos realizados na resolu\u00e7\u00e3o deste item<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Plano inclinado sem atrito<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>25-(FMABC-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b36421b0.jpg\" alt=\"\" width=\"627\" height=\"141\" name=\"graphics63\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere um escorregador radical constitu\u00eddo de uma mega rampa de 31,25m de altura e que forma com o plano<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_dfe753b1.jpg\" alt=\"\" width=\"445\" height=\"165\" name=\"graphics64\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>horizontal 30<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Para escorregar, a partir do repouso, as pessoas devem vestir roupas especialmente desenvolvidas com materiais revolucion\u00e1rios que reduzem o atrito com a plataforma da rampa e com o ar a valores desprez\u00edveis. Qual o intervalo de tempo gasto para as pessoas escorregarem do topo at\u00e9 a base da rampa?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Adote para o m\u00f3dulo da acelera\u00e7\u00e3o da gravidade o valor de 10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A)\u00a0 5,0s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B)\u00a0 4,0s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(C)\u00a0 3,5s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D)\u00a0 3,0s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E)\u00a0 2,5s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>26-(UERJ-RJ-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_5576f497.jpg\" alt=\"\" width=\"635\" height=\"139\" name=\"graphics65\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma pequena caixa \u00e9 lan\u00e7ada em dire\u00e7\u00e3o ao solo, sobre um plano inclinado, com velocidade igual a 3,0 m\/s. A altura do ponto de lan\u00e7amento da caixa, em rela\u00e7\u00e3o ao solo, \u00e9 igual a 0,8 m (adote g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9b82fc53.jpg\" alt=\"\" width=\"447\" height=\"217\" name=\"graphics66\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando que a caixa desliza sem atrito, estime a sua velocidade ao atingir o solo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>27-(PUC-GO-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_24684ee.jpg\" alt=\"\" width=\"632\" height=\"143\" name=\"Imagem 547\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nos versos \u201cA hirta cena de uma dif\u00edcil f\u00f3rmula\/ ganhadora na velocidade da grafia\/ Sem estuprar o tempo\/ invento mandingas com a caneta\/ de fazer inveja a qualquer Ferrari\/ fa\u00e7o curvas com as letras\/ manobro perigosas ideias sem capacete\u201d, aparecem as palavras velocidade e tempo. Acrescentando a estas os conceitos de acelera\u00e7\u00e3o e de peso de um corpo, analise as afirmativas abaixo:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I- Quando uma bola em repouso est\u00e1 pendurada por uma corda vertical, a tens\u00e3o na corda \u00e9 mg. Se a bola \u00e9 colocada a se mover formando um c\u00edrculo na horizontal de tal forma que a corda descreve um cone, a tens\u00e3o na corda \u00e9 superior a mg.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II- Se um bloco desce um plano inclinado, sem atrito, nele a for\u00e7a normal (a for\u00e7a perpendicular ao plano) \u00e9 inferior a mg.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III- Duas pedras, uma de massa maior que a outra, em queda livre (resist\u00eancia do ar nula), t\u00eam a mesma acelera\u00e7\u00e3o. A raz\u00e3o pela qual a pedra de maior massa n\u00e3o apresenta uma maior acelera\u00e7\u00e3o \u00e9 a de que a propor\u00e7\u00e3o da for\u00e7a pela massa \u00e9 a mesma.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>De acordo com os itens analisados, marque a alternativa que contenha apenas proposi\u00e7\u00e3o(\u00f5es) correta(s):<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A ( ) I\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B ( ) I e II\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C ( ) I, II e III\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D ( ) III\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Lei de Hooke<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>28-(UNIMONTES-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_4ce1c51f.jpg\" alt=\"\" width=\"603\" height=\"159\" name=\"Imagem 548\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um conjunto de molas sustenta o peso de um carro. Com 2 pessoas de 60kg em seu interior, o carro abaixa 2cm. Com 4<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6d43bd9c.jpg\" alt=\"\" width=\"399\" height=\"159\" name=\"Imagem 549\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pessoas de 70kg, o carro vai abaixar, aproximadamente: g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2.<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 3,0cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B) 3,5cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C) 4,0cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D) 4,7cm.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>29-(MACKENZIE-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b9bad8a0.jpg\" alt=\"\" width=\"663\" height=\"155\" name=\"Imagem 57\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma experi\u00eancia de laborat\u00f3rio, um estudante utilizou os dados do gr\u00e1fico da figura 1, que se referiam \u00e0 intensidade da for\u00e7a aplicada a uma mola helicoidal, em fun\u00e7\u00e3o de sua deforma\u00e7\u00e3o (F=kx). Com esses dados e uma montagem<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>semelhante \u00e0 da figura 2, determinou a massa (m) do corpo suspenso.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d885854c.jpg\" alt=\"\" width=\"711\" height=\"193\" name=\"Imagem 58\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando que as massas da mola e dos fios (inextens\u00edveis) s\u00e3o desprez\u00edveis, que\u00a0 g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e que, na posi\u00e7\u00e3o de equil\u00edbrio, a mola est\u00e1 deformada de 6,4 cm, a massa (m) do corpo suspenso \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 12 kg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 8,0 kg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 4,0 kg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 3,2 kg \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e) 2,0 kg<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Movimento Harm\u00f4nico Simples (MHS)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>20-(UNICENTRO-PR-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d1ffdbc9.jpg\" alt=\"\" width=\"691\" height=\"159\" name=\"graphics67\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma mola se encontra sobre um plano horizontal sem atrito. Um alongamento de 10 cm \u00e9 obtido com uma for\u00e7a de 10 N.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_70d35905.jpg\" alt=\"\" width=\"593\" height=\"185\" name=\"graphics68\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Adicionamos uma massa de 0,25 kg \u00e0 mola e produziu-se um alongamento de 20 cm. Abandonamos o sistema. Nestas condi\u00e7\u00f5es, assinale a alternativa correta.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) A constante da for\u00e7a da mola ser\u00e1 1,0.103 N\/m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(B) O per\u00edodo ser\u00e1 de 31s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(C) A velocidade m\u00e1xima ser\u00e1 de 4,0 m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(D) A acelera\u00e7\u00e3o m\u00e1xima ser\u00e1 de 8,0 m\/s2.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(E) A energia mec\u00e2nica total do sistema ser\u00e1 20,0 J.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>21-(ESCOLA NAVAL-012-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_955309a8.jpg\" alt=\"\" width=\"547\" height=\"162\" name=\"graphics69\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um bloco de massa m=1,00kg executa, preso a uma mola de constante k=100N\/m, um MHS de amplitude A cm ao longo do plano inclinado mostrado na figura. N\u00e3o h\u00e1 atrito em qualquer parte do sistema. Na posi\u00e7\u00e3o de altura m\u00e1xima,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9d55ba9d.jpg\" alt=\"\" width=\"346\" height=\"223\" name=\"graphics70\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a mola est\u00e1 comprimida e exerce sobre o bloco uma for\u00e7a el\u00e1stica de m\u00f3dulo igual a 3,00N. A velocidade do bloco, em m\/s, ao passar pela posi\u00e7\u00e3o de equil\u00edbrio \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 1,10\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 0,800\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 0,500\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 0,300\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 0,200<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>15-(AFA-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b8dfc8aa.jpg\" alt=\"\" width=\"591\" height=\"161\" name=\"Imagem 556\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Num local onde a acelera\u00e7\u00e3o da gravidade \u00e9 constante, um corpo de massa m, com dimens\u00f5es desprez\u00edveis, \u00e9 posto a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>oscilar, unido a uma mola ideal de constante el\u00e1stica k, em um plano fixo e inclinado de um \u00e2ngulo\u00a0 \u03b8, como mostra a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_456266fa.jpg\" alt=\"\" width=\"431\" height=\"205\" name=\"graphics71\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nessas condi\u00e7\u00f5es, o sistema massa-mola executa um movimento harm\u00f4nico simples de per\u00edodo T.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Colocando-se o mesmo sistema massa-mola para oscilar na vertical, tamb\u00e9m em movimento harm\u00f4nico simples, o\u00a0 seu<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>novo per\u00edodo passa a ser T\u2019.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nessas condi\u00e7\u00f5es, a raz\u00e3o T\u2019\/T \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 1\/sen\u03b8\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) sen\u03b8\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 1\/2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d) 1<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>16-(ESPCEX-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_7d952794.jpg\" alt=\"\" width=\"567\" height=\"156\" name=\"Imagem 558\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma mola ideal est\u00e1 suspensa verticalmente, presa a um ponto fixo no teto de uma sala, por uma de suas extremidades. Um corpo de massa 80 g \u00e9 preso \u00e0 extremidade livre da mola e verifica-se que a mola desloca-se para uma nova posi\u00e7\u00e3o de equil\u00edbrio. O corpo \u00e9 puxado verticalmente para baixo e abandonado de modo que o sistema<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_736dd21f.jpg\" alt=\"\" width=\"202\" height=\"187\" name=\"Imagem 559\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>massa-mola passa a executar um movimento harm\u00f4nico simples. Desprezando s for\u00e7as dissipativas, sabendo que a constante el\u00e1stica da mola vale 0,5 N\/m e considerando\u00a0 \u03c0 = 3,14, o per\u00edodo do<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>movimento executado pelo corpo \u00e9 de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0 1,256 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b)\u00a0 2,512 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0c)\u00a0 6,369 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d)\u00a0 7,850 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e)\u00a0 15,700 s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>For\u00e7a de resist\u00eancia no ar<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>36-(UNICAMP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_5e9c1131.jpg\" alt=\"\" width=\"588\" height=\"141\" name=\"graphics72\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em agosto de 2012, a NASA anunciou o pouso da sonda Curiosity na superf\u00edcie de Marte. A sonda, de massa m=1000<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_cc4c2bbd.jpg\" alt=\"\" width=\"307\" height=\"168\" name=\"graphics73\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>kg , entrou na atmosfera marciana a uma velocidade\u00a0 v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=6000 m\/s .<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) A sonda atingiu o repouso, na superf\u00edcie de Marte, 7 minutos ap\u00f3s a sua entrada na atmosfera. Calcule o m\u00f3dulo da for\u00e7a resultante m\u00e9dia de desacelera\u00e7\u00e3o da sonda durante sua descida.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Considere que, ap\u00f3s a entrada na atmosfera a uma altitude \u00a0h<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=125 km, a for\u00e7a de atrito reduziu a velocidade da sonda para v= 4000 m\/s quando a altitude atingiu h=100 km. A partir da varia\u00e7\u00e3o da energia mec\u00e2nica, calcule o trabalho realizado pela for\u00e7a de atrito neste trecho. Considere a acelera\u00e7\u00e3o da gravidade de Marte, neste trecho, constante e igual a g<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Marte<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=4 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>37-(UNICAMP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_e2df49cd.jpg\" alt=\"\" width=\"629\" height=\"147\" name=\"graphics74\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As nuvens s\u00e3o formadas por got\u00edculas de \u00e1gua que s\u00e3o facilmente arrastadas pelo vento. Em determinadas situa\u00e7\u00f5es,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_3ef663a7.jpg\" alt=\"\" width=\"472\" height=\"176\" name=\"graphics75\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>v\u00e1rias got\u00edculas se juntam para formar uma gota maior, que cai, produzindo a chuva. De forma simplificada, a queda da gota ocorre quando a for\u00e7a gravitacional que age sobre ela fica maior que a for\u00e7a do vento ascendente. A densidade da \u00e1gua \u00e9 \u03c1<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e1gua<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1,0.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>kg\/m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) O m\u00f3dulo da for\u00e7a, que \u00e9 vertical e para cima, que certo vento aplica sobre uma gota esf\u00e9rica de raio r pode ser aproximado por F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>vento<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=b.r, com b=1,6.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N\/m. Calcule o raio m\u00ednimo da gota para que ela comece a cair.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) O volume de chuva e a velocidade com que as gotas atingem o solo s\u00e3o fatores importantes na eros\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O volume \u00e9 usualmente expresso pelo \u00edndice pluviom\u00e9trico, que corresponde \u00e0 altura do n\u00edvel da \u00e1gua da chuva acumulada em um recipiente aberto e disposto horizontalmente. Calcule o impulso transferido pelas gotas da chuva para cada metro quadrado de solo horizontal, se a velocidade m\u00e9dia das gotas ao chegar ao solo \u00e9 de 2,5 m\/s e o \u00edndice pluviom\u00e9trico \u00e9 igual a 20 mm. Considere a colis\u00e3o como perfeitamente inel\u00e1stica.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>For\u00e7a de atrito<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>66-(UCS-RS-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6bbd426a.jpg\" alt=\"\" width=\"686\" height=\"154\" name=\"graphics76\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Numa festa junina, uma das brincadeiras mais tradicionais \u00e9 a escalada de um poste de madeira, vertical e besuntado de graxa, conhecido como pau de sebo. Numa dessas ocasi\u00f5es, o \u00fanico <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_3e56e9d4.jpg\" alt=\"\" width=\"241\" height=\"299\" name=\"graphics77\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>candidato que conseguiu escalar o pau de sebo possu\u00eda 60 kg. Em certo momento da escalada, ele parou para descansar. Por\u00e9m, a fim de n\u00e3o escorregar de volta ao ch\u00e3o, ele precisou aplicar no poste um abra\u00e7o, com os bra\u00e7os e pernas, utilizando uma for\u00e7a total, perpendicular ao poste, de 800N, de forma ininterrupta, pois percebeu que, se aplicasse uma for\u00e7a um pouco menor, escorregaria. Qual foi o coeficiente de atrito est\u00e1tico entre o candidato e a superf\u00edcie do pau de sebo? Ignore detalhes do contato entre o candidato e o pau de sebo e considere a acelera\u00e7\u00e3o da gravidade como 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,048\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 0,48\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 0,75\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 1,04\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 1,33<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>67-(PUC-RJ-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_8dda6db4.jpg\" alt=\"\" width=\"551\" height=\"149\" name=\"graphics78\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sobre uma superf\u00edcie sem atrito, h\u00e1 um bloco de massa m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 4,0 kg sobre o qual est\u00e1 apoiado um bloco menor de massa m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 1,0 kg. Uma corda puxa o bloco menor com uma for\u00e7a horizontal F de m\u00f3dulo 10 N, como mostrado na figura abaixo, e observa-se que nesta situa\u00e7\u00e3o os dois blocos movem-se juntos.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_2cfe4de8.jpg\" alt=\"\" width=\"307\" height=\"197\" name=\"graphics79\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A for\u00e7a de atrito existente entre as superf\u00edcies dos blocos vale em Newtons:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 10\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) 2,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (C) 40\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D) 13\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E) 8,0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>68-(UNESP-SP-2013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_4af372a7.jpg\" alt=\"\" width=\"724\" height=\"157\" name=\"graphics80\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um gar\u00e7om deve levar um copo com \u00e1gua apoiado em uma bandeja plana e mantida na horizontal, sem deixar que o copo escorregue em rela\u00e7\u00e3o \u00e0 bandeja e sem que a \u00e1gua transborde do copo. O copo, com massa total de 0,4 kg, parte do repouso e descreve um movimento retil\u00edneo e acelerado em rela\u00e7\u00e3o ao solo, em um plano horizontal e com acelera\u00e7\u00e3o constante.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_31f8abc6.jpg\" alt=\"\" width=\"367\" height=\"230\" name=\"graphics81\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em um intervalo de tempo de 0,8 s, o gar\u00e7om move o copo por uma dist\u00e2ncia de 1,6 m. Desprezando a resist\u00eancia do ar, o m\u00f3dulo da for\u00e7a de atrito devido \u00e0 intera\u00e7\u00e3o com a bandeja, em \u00a0newtons, que atua sobre o copo nesse intervalo de tempo \u00e9 igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 2.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) 3.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (C) 5.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D) 1.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E) 4<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>69-(MACKENZIE-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b78f6300.jpg\" alt=\"\" width=\"619\" height=\"158\" name=\"Imagem 570\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um aluno observa em certo instante um bloco com velocidade de 5 m\/s sobre uma superf\u00edcie plana e horizontal. <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_dec3665b.jpg\" alt=\"\" width=\"380\" height=\"207\" name=\"graphics82\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Esse bloco desliza sobre essa superf\u00edcie e p\u00e1ra ap\u00f3s percorrer 5 m. Sendo g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, o coeficiente de atrito cin\u00e9tico entre o bloco e a superf\u00edcie \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0 0,75\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b)\u00a0 0,60\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c)\u00a0 0,45\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d)\u00a0 0,37\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 0,25<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>70-(ENEM-MEC-012)\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_3756ec1a.jpg\" alt=\"\" width=\"276\" height=\"135\" name=\"Imagem 572\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Os freios ABS s\u00e3o uma importante medida de seguran\u00e7a no tr\u00e2nsito, os quais funcionam para impedir o travamento das rodas do carro quando o sistema de freios \u00e9 acionado, liberando as rodas quando est\u00e3o no limiar do deslizamento. Quando as rodas travam, a for\u00e7a de frenagem \u00e9 governada pelo atrito cin\u00e9tico.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As representa\u00e7\u00f5es esquem\u00e1ticas da for\u00e7a de atrito f<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>at<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0entre os pneus e a pista, em fun\u00e7\u00e3o da press\u00e3o p aplicada no pedal de freio, para carros sem ABS e com ABS, respectivamente, s\u00e3o<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_2dd6156b.jpg\" alt=\"\" width=\"768\" height=\"242\" name=\"Imagem 573\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Plano inclinado com atrito<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>32-(PUC-PR-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9158f3bb.jpg\" alt=\"\" width=\"540\" height=\"120\" name=\"graphics83\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um bloco de 10 kg encontra-se em repouso sobre um plano inclinado, conforme figura a seguir. Sabe-se que os coeficientes de atrito est\u00e1tico e din\u00e2mico entre o corpo e a superf\u00edcie s\u00e3o, respectivamente, 0,75 e 0,70. Para esse plano tamb\u00e9m considere sen\u03b8 = 0,6 e cos \u03b8 = 0,8.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f62516b8.jpg\" alt=\"\" width=\"412\" height=\"191\" name=\"graphics84\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A partir do exposto, pode-se marcar como CORRETA qual das alternativas a seguir? (Adote g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) O corpo desce acelerado. O m\u00f3dulo da acelera\u00e7\u00e3o \u00e9 de 6 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B) Faltam dados para calcular a situa\u00e7\u00e3o em que o corpo se encontra.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C) O corpo desce em movimento uniforme. As for\u00e7as que atuam no corpo se anulam.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>D) A for\u00e7a de atrito torna-se superior \u00e0 intensidade do componente tangencial ao plano da for\u00e7aPeso. Sendo assim, mesmo que muito lentamente, o corpo ir\u00e1 subir o plano.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>E) O corpo permanece em repouso. A situa\u00e7\u00e3o ser\u00e1 de imin\u00eancia de movimento.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>33-(MACKENZIE-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_8ce492b2.jpg\" alt=\"\" width=\"550\" height=\"157\" name=\"Imagem 63\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Certo menino encontra-se sentado sobre uma prancha plana e desce por uma rampa inclinada, conforme ilustra\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_a8296e90.jpg\" alt=\"\" width=\"504\" height=\"217\" name=\"graphics85\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O coeficiente de atrito cin\u00e9tico entre a prancha e a rampa \u00e9\u00a0 \u03bc<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=0,25, cos\u03b8=0,8, sen\u03b8=0,6 e g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Sabe-se que o conjunto, menino e prancha, possui massa de 50 kg e que ao passar pelo ponto A, sua velocidade era 1,0 m\/s. A varia\u00e7\u00e3o de quantidade de movimento sofrida por esse conjunto entre os pontos A e B foi<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 100 N.s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 200 N.s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 300 N.s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 400 N.s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 500 N.s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>For\u00e7as no movimento circular<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>49-(UNESP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_3cd8e2c9.jpg\" alt=\"\" width=\"772\" height=\"157\" name=\"graphics86\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura representa, de forma simplificada, o aut\u00f3dromo de Tarum\u00e3, localizado na cidade de Viam\u00e3o, na Grande Porto Alegre. Em um evento comemorativo, tr\u00eas ve\u00edculos de diferentes categorias do automobilismo, um kart (K), um f\u00f3rmula 1 (F) e um stock-car (S), passam por diferentes curvas do circuito, com velocidades escalares iguais e constantes.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_2111a178.jpg\" alt=\"\" width=\"757\" height=\"265\" name=\"graphics87\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As tabelas 1 e 2 indicam, respectivamente e de forma comparativa, as massas de cada ve\u00edculo e os raios de curvatura das curvas representadas na figura, nas posi\u00e7\u00f5es onde se encontram os ve\u00edculos.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sendo F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>K<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>S<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0os m\u00f3dulos das for\u00e7as resultantes centr\u00edpetas que atuam em cada um dos ve\u00edculos nas posi\u00e7\u00f5es em que eles se encontram na figura, \u00e9 correto afirmar que<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(A) F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>S<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>K<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>F<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>K<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>S<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>F<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>.\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0(C) F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>K<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>F<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>S<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>.\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0(D) F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>F<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>S<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>K<\/b><\/span><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(E) F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>S<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&lt; F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0&lt; F<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>K<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>50-(FUVEST-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9d403dca.jpg\" alt=\"\" width=\"597\" height=\"161\" name=\"graphics88\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O p\u00eandulo de um rel\u00f3gio \u00e9 constitu\u00eddo por uma haste r\u00edgida com um disco de metal preso em uma de suas extremidades. O disco oscila entre as posi\u00e7\u00f5es A e C, enquanto a outra extremidade da haste permanece im\u00f3vel no ponto P. A figura abaixo ilustra o sistema.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_3506097a.jpg\" alt=\"\" width=\"245\" height=\"227\" name=\"graphics89\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A for\u00e7a resultante que atua no disco quando ele passa por B, com a haste na dire\u00e7\u00e3o vertical, \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_bf40b46b.jpg\" alt=\"\" width=\"230\" height=\"51\" name=\"graphics90\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) nula. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b) vertical, com sentido para cima. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0c) vertical, com sentido para baixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) horizontal, com sentido para a direita. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e) horizontal, com sentido para a esquerda.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Trabalho<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0\u00a0<\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>48-(UCS-RS-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ecacad13.jpg\" alt=\"\" width=\"588\" height=\"108\" name=\"Imagem 583\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma mo\u00e7a comprou um par de brincos, de 50 gramas cada um, e os usou durante o per\u00edodo em que <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_5031f2ae.jpg\" alt=\"\" width=\"279\" height=\"161\" name=\"Imagem 584\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>esteve num anivers\u00e1rio. Considerando que o evento aconteceu em lugar plano e que, portanto, os deslocamentos da mo\u00e7a ocorreram sempre em dire\u00e7\u00f5es paralelas ao ch\u00e3o, qual foi o trabalho realizado pela for\u00e7a peso dos brincos, durante o tempo em que a mo\u00e7a esteve no anivers\u00e1rio?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,05 J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 0,025 J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 1,00 J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 0,1 J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) zero<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>49-(UEL-PR-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_3ba64291.jpg\" alt=\"\" width=\"733\" height=\"143\" name=\"graphics91\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Suponha que o conjunto formado pelo sat\u00e9lite e pelo foguete lan\u00e7ador possua massa de 1,0.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0toneladas e seja impulsionado por uma for\u00e7a propulsora de aproximadamente 5,0.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>7<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N, sendo o sentido de lan\u00e7amento desse foguete perpendicular ao solo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desconsiderando a resist\u00eancia do ar e a perda de massa devido \u00e0 queima de combust\u00edvel, assinale a alternativa que apresenta, corretamente, o trabalho realizado, em joules, pela for\u00e7a resultante aplicada ao conjunto nos primeiros 2,0 km de sua decolagem. Considere a acelera\u00e7\u00e3o da gravidade g = 10, 0 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0em todo o percurso descrito.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 4,0.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>7<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 8,0.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>7<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 4,0.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 &#8212; d)\u00a0 8,0.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 10,0.10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Pot\u00eancia<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>51-(UniFOA-RJ-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f8eed8b.jpg\" alt=\"\" width=\"486\" height=\"163\" name=\"Imagem 586\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um ciclista que far\u00e1 uma prova de &#8220;bike indoor&#8221; nas olimp\u00edadas do Rio de Janeiro, em 2016, est\u00e1 sujeito a um rigoroso<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_e98efdfe.jpg\" alt=\"\" width=\"377\" height=\"225\" name=\"Imagem 587\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>treino de prepara\u00e7\u00e3o. Seu treinador importou dos Estados Unidos uma bicicleta eletr\u00f4nica est\u00e1tica que faz uma an\u00e1lise completa do atleta em prepara\u00e7\u00e3o. Considerando que o ciclista tenha uma massa de 70kg e parta do repouso, qual a pot\u00eancia necess\u00e1ria que desenvolver\u00e1 para atingir a velocidade de 72km\/h em 2 minutos?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>a) 117W\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b) 10.080W\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 181.440W\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d) 1.512W\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e) 14.000W<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>52-(UFSC-SC-013)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_bf7f3faf.jpg\" alt=\"\" width=\"679\" height=\"153\" name=\"graphics92\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em Santa Catarina, existe uma das maiores torres de queda livre do mundo, com 100 m de altura. A viagem come\u00e7a com uma subida de 40 s com velocidade considerada constante, em uma das quatro g\u00f4ndolas de 500 kg, impulsionadas por motores de 90 kW. Ap\u00f3s alguns instantes de suspense, os passageiros caem em queda livre, alcan\u00e7ando a velocidade m\u00e1xima de 122,4 km\/h, quando os freios magn\u00e9ticos s\u00e3o acionados. Em um tempo de 8,4 s depois de iniciar a descida, os passageiros est\u00e3o de volta na base da torre em total seguran\u00e7a. Considere a g\u00f4ndola carregada com uma carga de 240 kg.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1f4f9d02.jpg\" alt=\"\" width=\"677\" height=\"171\" name=\"graphics93\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dispon\u00edvel em: &lt;http:\/\/www.cbmr.com.br\/index.php\/parques\/20-pqatracoes\/275-bigtower&gt;. Acesso em: 5 set. 2012.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com base nas informa\u00e7\u00f5es acima, assinale a(s) proposi\u00e7\u00e3o(\u00f5es) CORRETA(S).<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01. A pot\u00eancia m\u00e9dia desenvolvida pela for\u00e7a aplicada pelo motor durante a subida de uma g\u00f4ndola carregada \u00e9 de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>18500 W.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02.O m\u00f3dulo da for\u00e7a m\u00e9dia sobre a g\u00f4ndola carregada durante a frenagem na descida \u00e9 de 5032 N.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04. O tempo total de queda livre \u00e9 de aproximadamente 4,47 s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08. A dist\u00e2ncia percorrida pela g\u00f4ndola carregada durante a queda livre \u00e9 de 57,8 m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>16. A acelera\u00e7\u00e3o da g\u00f4ndola carregada durante todo o percurso \u00e9 igual a g.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Energia<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>26-(UFRN-RN-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ca343572.jpg\" alt=\"\" width=\"615\" height=\"153\" name=\"graphics94\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O Sol irradia energia para o espa\u00e7o sideral. Essa energia tem origem na sua autocontra\u00e7\u00e3o gravitacional. Nesse<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_59f1a887.jpg\" alt=\"\" width=\"384\" height=\"179\" name=\"graphics95\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>processo, os \u00edons de hidrog\u00eanio (pr\u00f3tons) contidos no seu interior adquirem \u00a0velocidades muito altas, o que os leva a atingirem temperaturas da ordem de milh\u00f5es de graus.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com isso, t\u00eam in\u00edcio rea\u00e7\u00f5es exot\u00e9rmicas de fus\u00e3o nuclear, nas quais n\u00facleos de hidrog\u00eanio s\u00e3o fundidos, gerando n\u00facleos de H<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0(H\u00e9lio) e propiciando a produ\u00e7\u00e3o da radia\u00e7\u00e3o, que \u00e9 emitida para o espa\u00e7o. Parte dessa radia\u00e7\u00e3o atinge a Terra e \u00e9 a principal fonte de toda a energia que utilizamos.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nesse contexto, a sequ\u00eancia de formas de energias que culmina com a emiss\u00e3o da radia\u00e7\u00e3o solar que atinge a terra \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b37686b.jpg\" alt=\"\" width=\"560\" height=\"73\" name=\"graphics96\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>27-(UNICAMP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_4e61fd1d.jpg\" alt=\"\" width=\"657\" height=\"150\" name=\"graphics97\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Alguns t\u00eanis esportivos modernos possuem um sensor na sola que permite o monitoramento do desempenho do usu\u00e1rio<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_ab0a4279.jpg\" alt=\"\" width=\"179\" height=\"215\" name=\"graphics98\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>durante as corridas. O monitoramento pode ser feito atrav\u00e9s de rel\u00f3gios ou telefones celulares que recebem as informa\u00e7\u00f5es do sensor durante os exerc\u00edcios. Considere um atleta de massa m=70 kg que usa um t\u00eanis com sensor durante uma s\u00e9rie de tr\u00eas corridas.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) O gr\u00e1fico 1) abaixo mostra a dist\u00e2ncia percorrida pelo atleta e a dura\u00e7\u00e3o em horas das tr\u00eas corridas realizadas em velocidades constantes distintas. Considere que, para essa s\u00e9rie de corridas, o consumo de energia do corredor pode ser aproximado por E=C<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>MET<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.m.t, onde m \u00e9 a massa do corredor, t \u00e9 a dura\u00e7\u00e3o da corrida e C<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>MET<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00e9 uma constante que depende da velocidade do corredor e \u00e9 expressa em unidade de (kJ\/kg.h).<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Usando o gr\u00e1fico 2) abaixo, que expressa C<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>MET<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0em fun\u00e7\u00e3o da velocidade do corredor, calcule a quantidade de energia que o atleta gastou na terceira corrida.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_3853e6a.jpg\" alt=\"\" width=\"690\" height=\"216\" name=\"graphics99\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) O sensor detecta o contato da sola do t\u00eanis com o solo pela varia\u00e7\u00e3o da press\u00e3o. Estime a \u00e1rea de contato entre o t\u00eanis e o solo e calcule a press\u00e3o aplicada no solo quando o atleta est\u00e1 em repouso e apoiado sobre um \u00fanico p\u00e9.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Tipos de energia \u2013 Trabalho<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>39-(ENEM-MEC-012)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_6f72c73.jpg\" alt=\"\" width=\"323\" height=\"125\" name=\"graphics100\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Os carrinhos de brinquedo podem ser de v\u00e1rios tipos. Dentre eles, h\u00e1 os movidos \u00e0 corda, em que uma mola em seu<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9a16ffc2.jpg\" alt=\"\" width=\"267\" height=\"160\" name=\"graphics101\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>interior \u00e9 comprimida quando a crian\u00e7a puxa o carrinho para tr\u00e1s. Ao ser solto, o carrinho entra em movimento enquanto a mola volta \u00e0 sua forma inicial.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O processo de convers\u00e3o de energia que ocorre no carrinho descrito tamb\u00e9m \u00e9 verificado em<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) um d\u00ednamo.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) um freio de autom\u00f3vel.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) um motor a combust\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) uma usina hidrel\u00e9trica.<br \/>\ne) uma atiradeira (estilingue)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Energia mec\u00e2nica<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>72-(PUC-RS-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_2a0a61d2.jpg\" alt=\"\" width=\"643\" height=\"156\" name=\"graphics102\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Num salto em altura com vara, um atleta atinge a velocidade de 11m\/s imediatamente antes de fincar a vara no ch\u00e3o<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_dc88cd16.jpg\" alt=\"\" width=\"531\" height=\"189\" name=\"graphics103\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>para subir. Considerando que o atleta consiga converter 80% da sua energia cin\u00e9tica em energia potencial gravitacional e que a acelera\u00e7\u00e3o da gravidade no local seja 10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, a altura m\u00e1xima que o seu centro de massa pode atingir \u00e9, em metros, aproximadamente,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 6,2 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B) 6,0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C) 5,6 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D) 5,2 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0E) 4,8<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>73-(PUC-RJ-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_45d1a631.jpg\" alt=\"\" width=\"743\" height=\"162\" name=\"graphics104\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Na figura abaixo, o bloco 1, de massa m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1,0 kg, havendo partido do repouso, alcan\u00e7ou uma velocidade de 10 m\/s ap\u00f3s descer uma dist\u00e2ncia d no plano inclinado de 30<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Ele ent\u00e3o colide com o bloco 2, inicialmente em repouso, de massa m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 3,0 kg. O bloco 2 adquire uma velocidade de 4,0 m\/s ap\u00f3s a colis\u00e3o e segue a trajet\u00f3ria semicircular mostrada, cujo raio \u00e9 de 0,6 m. Em todo o percurso, n\u00e3o h\u00e1 atrito entre a superf\u00edcie e os blocos. Considere g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_dff00ea1.jpg\" alt=\"\" width=\"692\" height=\"159\" name=\"graphics105\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Ao longo da trajet\u00f3ria no plano inclinado, fa\u00e7a o diagrama de corpo livre do bloco 1 e encontre o m\u00f3dulo da for\u00e7a normal sobre ele.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Determine a dist\u00e2ncia d percorrida pelo bloco 1 ao longo da rampa.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Determine a velocidade do bloco 1 ap\u00f3s colidir com o bloco 2.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Ache o m\u00f3dulo da for\u00e7a normal sobre o bloco 2 no ponto mais alto da trajet\u00f3ria semicircular.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>74-(PUC-SP-013)\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_89d5291d.jpg\" alt=\"\" width=\"715\" height=\"176\" name=\"Imagem 602\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um canh\u00e3o \u00e9 fixado sobre uma plataforma retangular\u00a0 de madeira, constituindo um conjunto que se <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9e3b4c44.jpg\" alt=\"\" width=\"331\" height=\"187\" name=\"Imagem 603\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>encontra inicialmente em repouso apoiado sobre um terreno plano e horizontal. Num dia de demonstra\u00e7\u00e3o para os recrutas \u00e9 disparado um proj\u00e9til de massa m com velocidade horizontal\u00a0 v. Ap\u00f3s o disparo constata-se que o conjunto (canh\u00e3o + plataforma de madeira) sofre um recuo horizontal\u00a0 d em rela\u00e7\u00e3o \u00e0 sua posi\u00e7\u00e3o inicial. Considerando que o conjunto tem uma massa M (M&gt;&gt;m) e adotando para o m\u00f3dulo da acelera\u00e7\u00e3o da gravidade o valor\u00a0 g, podemos afirmar que o coeficiente de atrito cin\u00e9tico (\u03bc) entre a superf\u00edcie inferior da plataforma de madeira e o solo pode ser obtido atrav\u00e9s da express\u00e3o:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_69f67b60.jpg\" alt=\"\" width=\"768\" height=\"53\" name=\"Imagem 604\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>75-(UNESP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_47059f46.jpg\" alt=\"\" width=\"666\" height=\"137\" name=\"Imagem 605\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um brinquedo \u00e9 constitu\u00eddo por dois carrinhos id\u00eanticos, A e B, de massas iguais a 3 kg e por uma mola de massa desprez\u00edvel, comprimida entre eles e presa apenas ao carrinho A. Um pequeno dispositivo, tamb\u00e9m de massa desprez\u00edvel, controla um gatilho que, quando acionado, permite que a mola se distenda.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f7e16d31.jpg\" alt=\"\" width=\"718\" height=\"187\" name=\"Imagem 606\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Antes de o gatilho ser acionado, os carrinhos e a mola moviam-se juntos, sobre uma superf\u00edcie plana horizontal sem atrito, com energia mec\u00e2nica de 3,75 J e velocidade de 1 m\/s, em rela\u00e7\u00e3o \u00e0 superf\u00edcie. Ap\u00f3s o disparo do gatilho, e no instante em que a mola est\u00e1 totalmente distendida, o carrinho B perde contato com ela e sua velocidade passa a ser de 1,5 m\/s, tamb\u00e9m em rela\u00e7\u00e3o a essa mesma superf\u00edcie.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nas condi\u00e7\u00f5es descritas, calcule a energia potencial el\u00e1stica inicialmente armazenada na mola antes de o gatilho ser disparado e a velocidade do carrinho A, em rela\u00e7\u00e3o \u00e0 superf\u00edcie, assim que B perde contato com a mola, depois de o gatilho ser disparado<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>76-(FUVEST-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_c0fa919a.jpg\" alt=\"\" width=\"584\" height=\"145\" name=\"graphics106\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma das hip\u00f3teses para explicar a extin\u00e7\u00e3o dos dinossauros, ocorrida h\u00e1 cerca de 60 milh\u00f5es de anos, foi a colis\u00e3o de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_63a27b1b.jpg\" alt=\"\" width=\"300\" height=\"134\" name=\"graphics107\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>um grande meteoro com a Terra. Estimativas indicam que o meteoro tinha massa igual a 10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>16<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0kg e velocidade de 30 km\/s, imediatamente antes da colis\u00e3o. Supondo que esse meteoro estivesse se aproximando da Terra, numa dire\u00e7\u00e3o radial em rela\u00e7\u00e3o \u00e0 \u00f3rbita desse planeta em torno do Sol, para uma colis\u00e3o frontal, determine<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a quantidade de movimento P<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>i<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0do meteoro imediatamente antes da colis\u00e3o;<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a energia cin\u00e9tica E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0do meteoro imediatamente antes da colis\u00e3o;<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) a componente radial da velocidade da Terra, V<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>r<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, pouco depois da colis\u00e3o;<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) a energia E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, em megatons, dissipada na colis\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_44a75307.jpg\" alt=\"\" width=\"614\" height=\"114\" name=\"graphics108\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Impulso e quantidade de movimento<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>39-(PUC-SP-013)\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_89d5291d.jpg\" alt=\"\" width=\"685\" height=\"160\" name=\"graphics109\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um canh\u00e3o \u00e9 fixado sobre uma plataforma retangular\u00a0 de madeira, constituindo um conjunto que se <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_9e3b4c44.jpg\" alt=\"\" width=\"339\" height=\"190\" name=\"graphics110\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>encontra inicialmente em repouso apoiado sobre um terreno plano e horizontal. Num dia de demonstra\u00e7\u00e3o para os recrutas \u00e9 disparado um proj\u00e9til de massa m com velocidade horizontal\u00a0 v. Ap\u00f3s o disparo constata-se que o conjunto (canh\u00e3o + plataforma de madeira) sofre um recuo horizontal\u00a0 d em rela\u00e7\u00e3o \u00e0 sua posi\u00e7\u00e3o inicial. Considerando que o conjunto tem uma massa M (M&gt;&gt;m) e adotando para o m\u00f3dulo da acelera\u00e7\u00e3o da gravidade o valor\u00a0 g, podemos afirmar que o coeficiente de atrito cin\u00e9tico (\u03bc) entre a superf\u00edcie inferior da plataforma de madeira e o solo pode ser obtido atrav\u00e9s da express\u00e3o:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_69f67b60.jpg\" alt=\"\" width=\"780\" height=\"81\" name=\"graphics111\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>40-(MACKENZIE-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_757236ef.jpg\" alt=\"\" width=\"616\" height=\"147\" name=\"graphics112\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma competi\u00e7\u00e3o de t\u00eanis, a raquete do jogador \u00e9 atingida por uma bola de massa 60 g, com velocidade horizontal<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de 40 m\/s. A bola \u00e9 rebatida na mesma dire\u00e7\u00e3o e sentido contr\u00e1rio com velocidade de 30 m\/s. Se o tempo de contato<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_caf90245.jpg\" alt=\"\" width=\"395\" height=\"191\" name=\"Imagem 42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da bola com a raquete \u00e9 de 0,01 s, a intensidade da for\u00e7a aplicada pela raquete \u00e0 bola \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 60 N\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 120 N\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 240 N\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 420 N\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 640 N<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>41-(UNICAMP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_593fcd14.jpg\" alt=\"\" width=\"717\" height=\"163\" name=\"Imagem 615\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Muitos carros possuem um sistema de seguran\u00e7a para os passageiros chamado airbag. Este sistema consiste em uma<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_2512f4f1.jpg\" alt=\"\" width=\"323\" height=\"176\" name=\"Imagem 616\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>bolsa de pl\u00e1stico que \u00e9 rapidamente inflada quando o carro sofre desacelera\u00e7\u00e3o brusca, interpondo-se entre o passageiro e o painel do ve\u00edculo. Em uma colis\u00e3o, a fun\u00e7\u00e3o do airbag \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) aumentar o intervalo de\u00a0 tempo de colis\u00e3o entre o passageiro e o carro, reduzindo assim a for\u00e7a recebida pelo passageiro.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) aumentar a varia\u00e7\u00e3o de momento linear do passageiro durante a colis\u00e3o, reduzindo assim a for\u00e7a recebida pelo passageiro.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) diminuir o intervalo de\u00a0 tempo de colis\u00e3o entre o passageiro e o carro, reduzindo assim a for\u00e7a recebida pelo passageiro.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) diminuir o impulso recebido pelo passageiro devido ao choque, reduzindo assim a for\u00e7a recebida pelo passageiro<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>42-(FUVEST-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_fac4ccbf.jpg\" alt=\"\" width=\"743\" height=\"163\" name=\"graphics113\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um f\u00f3ton, com quantidade de movimento na dire\u00e7\u00e3o e sentido do eixo x, colide com um el\u00e9tron em repouso.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Depois da colis\u00e3o, o el\u00e9tron passa a se mover com quantidade de movimento p<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, no plano xy, como ilustra a figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b91804c2.jpg\" alt=\"\" width=\"257\" height=\"178\" name=\"graphics114\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dos vetores\u00a0 p<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>f<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 abaixo, o \u00fanico que poderia representar a dire\u00e7\u00e3o e sentido da quantidade de movimento do f\u00f3ton, ap\u00f3s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a colis\u00e3o, \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1a4bb93d.jpg\" alt=\"\" width=\"482\" height=\"101\" name=\"graphics115\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_b791fc7d.jpg\" alt=\"\" width=\"776\" height=\"142\" name=\"graphics116\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>43-(UNESP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_47059f46.jpg\" alt=\"\" width=\"776\" height=\"160\" name=\"graphics117\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um brinquedo \u00e9 constitu\u00eddo por dois carrinhos id\u00eanticos, A e B, de massas iguais a 3 kg e por uma mola de massa desprez\u00edvel, comprimida entre eles e presa apenas ao carrinho A. Um pequeno dispositivo, tamb\u00e9m de massa desprez\u00edvel, controla um gatilho que, quando acionado, permite que a mola se distenda.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f7e16d31.jpg\" alt=\"\" width=\"758\" height=\"187\" name=\"graphics118\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Antes de o gatilho ser acionado, os carrinhos e a mola moviam-se juntos, sobre uma superf\u00edcie plana horizontal sem atrito, com energia mec\u00e2nica de 3,75 J e velocidade de 1 m\/s, em rela\u00e7\u00e3o \u00e0 superf\u00edcie. Ap\u00f3s o disparo do gatilho, e no instante em que a mola est\u00e1 totalmente distendida, o carrinho B perde contato com ela e sua velocidade passa a ser de 1,5 m\/s, tamb\u00e9m em rela\u00e7\u00e3o a essa mesma superf\u00edcie.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nas condi\u00e7\u00f5es descritas, calcule a energia potencial el\u00e1stica inicialmente armazenada na mola antes de o gatilho ser disparado e a velocidade do carrinho A, em rela\u00e7\u00e3o \u00e0 superf\u00edcie, assim que B perde contato com a mola, depois de o gatilho ser disparado<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Colis\u00f5es mec\u00e2nicas<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>49-(FUVEST-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_dd140f54.jpg\" alt=\"\" width=\"477\" height=\"140\" name=\"graphics119\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Compare as colis\u00f5es de uma bola de v\u00f4lei e de uma bola de golfe com o t\u00f3rax de uma pessoa, parada e em p\u00e9. A bola<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_a1d0c8b3.jpg\" alt=\"\" width=\"404\" height=\"173\" name=\"graphics120\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de v\u00f4lei, com massa de 270 g, tem velocidade de 30 m\/s quando atinge a pessoa, e a de golfe, com 45 g, tem velocidade de 60 m\/s ao atingir a mesma pessoa, nas mesmas condi\u00e7\u00f5es. Considere ambas as colis\u00f5es totalmente inel\u00e1sticas. \u00c9 correto apenas o que se afirma em:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_65046a63.jpg\" alt=\"\" width=\"467\" height=\"177\" name=\"graphics121\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Antes das colis\u00f5es, a quantidade de movimento da bola de golfe \u00e9 maior que a da bola de v\u00f4lei.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Antes das colis\u00f5es, a energia cin\u00e9tica da bola de golfe \u00e9 maior que a da bola de v\u00f4lei.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Ap\u00f3s as colis\u00f5es, a velocidade da bola de golfe \u00e9 maior que a da bola de v\u00f4lei.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Durante as colis\u00f5es, a for\u00e7a m\u00e9dia exercida pela bola de golfe sobre o t\u00f3rax da pessoa \u00e9 maior que a exercida pela bola de v\u00f4lei.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) Durante as colis\u00f5es, a press\u00e3o m\u00e9dia exercida pela bola de golfe sobre o t\u00f3rax da pessoa \u00e9 maior que a exercida pela bola de v\u00f4lei.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>50-(UNESP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_cfdcb71f.jpg\" alt=\"\" width=\"781\" height=\"172\" name=\"graphics122\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em um jogo de sinuca, a bola A \u00e9 lan\u00e7ada com velocidade\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_f5c85d4.jpg\" alt=\"\" width=\"12\" height=\"18\" name=\"graphics123\" align=\"BOTTOM\" border=\"0\" \/>\u00a0de m\u00f3dulo constante e igual a 2 m\/s em uma dire\u00e7\u00e3o paralela \u00e0s tabelas (laterais) maiores da mesa, conforme representado na figura 1. Ela choca-se de forma perfeitamente el\u00e1stica com a bola B, inicialmente em repouso, e, ap\u00f3s a colis\u00e3o, elas se movem em dire\u00e7\u00f5es distintas, conforme a figura<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_788f5601.jpg\" alt=\"\" width=\"781\" height=\"233\" name=\"graphics124\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2. Sabe-se que as duas bolas s\u00e3o de mesmo material e id\u00eanticas em massa e volume. A bola A tem, imediatamente depois da colis\u00e3o, velocidade<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_e1f1d6f8.jpg\" alt=\"\" width=\"16\" height=\"18\" name=\"Imagem 629\" align=\"BOTTOM\" border=\"0\" \/>\u00a0de m\u00f3dulo igual a 1 m\/s. Desprezando os atritos e sendo E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u2019 a energia cin\u00e9tica da bola B imediatamente depois da colis\u00e3o e E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0a energia cin\u00e9tica da bola A antes da colis\u00e3o, a raz\u00e3o<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>E&#8217;<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\/E<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00e9 igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 1\/2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) 4\/5\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (C) 3\/4\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D) 1\/5\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0(E) 2\/3<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>51-(PUC-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_76b1b6bb.jpg\" alt=\"\" width=\"750\" height=\"165\" name=\"Imagem 233\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma bola de borracha \u00e9 solta de uma altura de 5 m e cai livremente, chocando-se diversas vezes com um piso r\u00edgido.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_d476a022.jpg\" alt=\"\" width=\"149\" height=\"171\" name=\"Imagem 234\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Observa-se que, ap\u00f3s cada colis\u00e3o, a bola sobe e atinge uma altura que corresponde a 80% da altura anterior. Ap\u00f3s a terceira colis\u00e3o, com o piso r\u00edgido, a bola atinge uma altura aproximadamente, em metros, de:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 4,0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b) 3,2 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0c) 2,5 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d) 1,0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>52-(PUC-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_990e9144.jpg\" alt=\"\" width=\"771\" height=\"155\" name=\"Imagem 235\" align=\"BOTTOM\" border=\"0\" \/><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando-se, por exemplo, a primeira colis\u00e3o da quest\u00e3o de n\u00famero 51, \u00e9 CORRETO afirmar:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) A velocidade com que a bola atinge o solo \u00e9 igual \u00e0 velocidade com que ela abandona o solo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) A velocidade com que a bola se solta do solo \u00e9 80% da velocidade com que ela atinge o solo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) A velocidade com que a bola se solta do solo \u00e9 menor que 80% da velocidade com que ela atinge o solo, j\u00e1 que a energia cin\u00e9tica depende da velocidade ao quadrado.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) A velocidade com que a bola se solta do solo \u00e9 maior que 80% da velocidade com que ela atinge o solo, j\u00e1 que a energia cin\u00e9tica depende da velocidade ao quadrado.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>53-(UNIMONTES-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_24dc45c5.jpg\" alt=\"\" width=\"717\" height=\"162\" name=\"graphics125\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Duas bolas de gude, com massas m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, sendo m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 3 m<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, movimentam-se ao longo de uma mesma reta, mas em<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/dinamica\/Dina_mica-_por_assunto-Exerci_cios-com_tudo_html_1a1e206c.jpg\" alt=\"Din\u00e2mica\" width=\"482\" height=\"147\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>sentidos contr\u00e1rios. Num determinado instante, elas colidem. A colis\u00e3o dura um intervalo de tempo muito curto. Durante esse intervalo, a bola 1 fica sujeita a uma acelera\u00e7\u00e3o de m\u00f3dulo igual a 3m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Nesse \u00a0mesmo intervalo de tempo, o m\u00f3dulo da acelera\u00e7\u00e3o a que fica sujeita a bola 2 \u00e9 igual a (considere g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 3m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B) 9m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C) 18m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D) 27m\/s<\/b><\/span><\/span><\/span><\/p>\n<h3 align=\"JUSTIFY\"><a title=\"Resolu\u00e7\u00f5es Din\u00e2mica \u2013 2014 \u2013 2013\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/resolucoes-dinamica-2014-2013\/\"><span style=\"color: #000080;\">Confira as resolu\u00e7\u00f5es comentadas<\/span><\/a><\/h3>\n<p>&nbsp;<\/p>\n<p><a href=\"https:\/\/fisicaevestibular.com.br\/novo\/vestibulares-recentes\/mecanica\/\">Clique aqui para ver sobre o tema!<\/a><\/p>\n<p><a href=\"https:\/\/www.youtube.com\/user\/fisicaevestibular\/playlists\">Confira as v\u00eddeo aulas!<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios &#8211; Vestibulares Recentes por assunto 2014 e 2013 As tr\u00eas leis de Newton 01-(FMJ-SP-014) Um avi\u00e3o, de massa\u00a0m,\u00a0est\u00e1 decolando\u00a0inclinado de um\u00a0\u00e2ngulo \u03b1com a horizontal, com\u00a0velocidade constante\u00a0e acelera\u00e7\u00e3o da gravidade local igual a\u00a0g. Para\u00a0continuar subindo nessas condi\u00e7\u00f5es,a for\u00e7a resultante\u00a0sobre o avi\u00e3o dever\u00e1 ter intensidade igual a (A) m.g.sen\u03b1. (B) m.g.tg\u03b1. (C) m.g.cos\u03b1. (D) zero. (E) m.g. 02-(IFPE-PE-014) Um bloco desliza<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3123,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3249","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3249","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3249"}],"version-history":[{"count":6,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3249\/revisions"}],"predecessor-version":[{"id":9885,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3249\/revisions\/9885"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3123"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3249"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}