{"id":3242,"date":"2017-09-27T22:22:09","date_gmt":"2017-09-27T22:22:09","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3242"},"modified":"2024-06-29T23:48:38","modified_gmt":"2024-06-29T23:48:38","slug":"cinematica-2013-2014","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/vestibulares-recentes\/mecanica\/cinematica-2013-2014\/","title":{"rendered":"Cinem\u00e1tica &#8211; 2013 &#8211; 2014"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\">2013 &#8211; 2014<\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: x-large;\">Cinem\u00e1tica<\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\">MOVIMENTO UNIFORME<\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\">01-(UEL-PR-014)<\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_5db0f1b5.png\" alt=\"\" width=\"613\" height=\"153\" name=\"Imagem 467\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Analise a figura a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_9c83c9cd.png\" alt=\"\" width=\"629\" height=\"213\" name=\"Imagem 468\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Os habitantes de\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>metr\u00f3poles<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0convivem com o problema dos\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>congestionamentos de autom\u00f3veis<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, que geram estresse, acidentes, polui\u00e7\u00e3o sonora, entre outras consequ\u00eancias. Uma solu\u00e7\u00e3o para o problema de mobilidade urbana \u00e9 o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>transporte coletivo por linhas de metr\u00f4.\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>figura<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0mostra a regi\u00e3o central da cidade de Bras\u00edlia. Considere que um indiv\u00edduo se\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>desloca diariamente de carro da posi\u00e7\u00e3o A, onde mora, at\u00e9 a posi\u00e7\u00e3o B, onde trabalha, em um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>percurso de 12 km\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>representado pela\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>linha tracejada<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. No hor\u00e1rio de\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>rush,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_8f49fee6.png\" alt=\"\" width=\"480\" height=\"149\" name=\"Imagem 469\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade m\u00e9dia dos autom\u00f3veis \u00e9 de 12 km<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\/h e,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>fora desse hor\u00e1rio, \u00e9 de 42 km\/h<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Se houvesse em Bras\u00edlia uma linha de\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>metr\u00f4 de A at\u00e9 B, como representado pela linha ponto-tracejada, ela teria 20 km<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Supondo que a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade m\u00e9dia do metr\u00f4 seja de 60 km\/h<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, considere as afirmativas a seguir<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I.\u00a0No hor\u00e1rio de rush, o tempo de deslocamento de carro de A at\u00e9 B \u00e9 maior do que o tempo de deslocamento por metr\u00f4 em 1 hora.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II.\u00a0No hor\u00e1rio de rush, o tempo de deslocamento de A at\u00e9 B por metr\u00f4 \u00e9 1\/3 do tempo de deslocamento<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>por carro.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III.\u00a0Fora do hor\u00e1rio de rush, \u00e9 mais r\u00e1pido fazer o percurso de A para B de carro.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>IV.\u00a0Fora do hor\u00e1rio de rush, considerando que o sistema de metr\u00f4 tenha melhorado e que sua velocidade<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>m\u00e9dia passe a ser de 70 km\/h, ent\u00e3o o tempo de deslocamento de A at\u00e9 B tanto por carro quanto por metr\u00f4 \u00e9 igual.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa correta.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Somente as afirmativas I e II s\u00e3o corretas.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Somente as afirmativas I e IV s\u00e3o corretas.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Somente as afirmativas III e IV s\u00e3o corretas.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Somente as afirmativas I, II e III s\u00e3o corretas.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) Somente as afirmativas II, III e IV s\u00e3o corretas.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02-(PUC-RJ-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_4ac03064.jpg\" alt=\"\" width=\"767\" height=\"141\" name=\"Imagem 470\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>passageiro<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0do metr\u00f4 no Rio de Janeiro deseja fazer uma viagem da esta\u00e7\u00e3o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Botafogo\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>at\u00e9 a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_747f9050.png\" alt=\"\" width=\"414\" height=\"203\" name=\"Imagem 471\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>esta\u00e7\u00e3o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Cinel\u00e2ndia<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dist\u00e2ncia e o tempo estimado\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de viagem entre cada uma das esta\u00e7\u00f5es da linha do metr\u00f4 \u00e9 apresentado na tabela abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_a4a1bed7.png\" alt=\"\" width=\"476\" height=\"233\" name=\"Imagem 472\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade escalar m\u00e9dia\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do passageiro em seu trajeto, em\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>metros por segundo<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 7,8 (B) 8,0 (C) 48,0 (D) 474,7 (E) 480,0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>03-(UNICAMP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_6c998e42.jpg\" alt=\"\" width=\"672\" height=\"159\" name=\"Imagem 473\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Andar de bondinho no complexo do\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>P\u00e3o de A\u00e7\u00facar no Rio de Janeiro<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00e9 um dos passeios a\u00e9reos urbanos mais famosos do mundo. Marca registrada da cidade, o Morro do P\u00e3o de A\u00e7\u00facar \u00e9 constitu\u00eddo de um \u00fanico<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>bloco de granito, despido de vegeta\u00e7\u00e3o em sua quase totalidade e tem mais de 600 milh\u00f5es de anos.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_95dfdb78.png\" alt=\"\" width=\"484\" height=\"198\" name=\"Imagem 474\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O passeio completo no complexo do P\u00e3o de A\u00e7\u00facar inclui um trecho de bondinho de aproximadamente\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>540 m, da Praia Vermelha ao Morro da Urca<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>caminhada at\u00e9 a segunda esta\u00e7\u00e3o no Morro da Urca<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, e um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>segundo trecho de bondinho de cerca de 720 m, do Morro da Urca ao P\u00e3o de A\u00e7\u00facar<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. A velocidade escalar m\u00e9dia do bondinho no primeiro trecho \u00e9\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>V<\/b><\/span><\/span><\/span><span style=\"color: #0000ff;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 10,8 km\/h e, no segundo, V<\/b><\/span><\/span><\/span><span style=\"color: #0000ff;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 14,4 km\/h.<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0Supondo que, em certo dia, o tempo gasto na caminhada no Morro da Urca somado ao tempo de espera nas esta\u00e7\u00f5es \u00e9 de\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000ff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>30 minutos<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>tempo total do passeio completo<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0da Praia Vermelha at\u00e9 o P\u00e3o de A\u00e7\u00facar ser\u00e1 igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>a) 33 min. b) 42 min. c) 50 min.\u00a0<\/b><\/span><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 36 min<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04-(UEFS-BA-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_fea8b49a.png\" alt=\"\" width=\"643\" height=\"162\" name=\"Imagem 475\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma corrida\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de 100 metros rasos,<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>vencedor<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0completou o percurso, desenvolvendo\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_4f9697a7.png\" alt=\"\" width=\"353\" height=\"206\" name=\"Imagem 476\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>escalar m\u00e9dia de 32km\/h<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, enquanto o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>segundo colocado\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>desenvolveu\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade escalar m\u00e9dia de 30km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>No\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>final da corrida<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dist\u00e2ncia que separava o vencedor do segundo colocado<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>em metros,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>era de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 5,50 B) 5,75 C) 6,00 D) 6,25 E) 7,802<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>05-(UFRN-RN-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_54d0e7d9.jpg\" alt=\"\" width=\"531\" height=\"146\" name=\"Imagem 477\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dois amigos, um residente em Natal (I) e outro em Parnamirim (II), combinaram de ir, cada um no seu autom\u00f3vel, a um evento na cidade de Goianinha, a 64,0 km de Natal. Apesar de sa\u00edrem de lugares diferentes, eles pretendiam chegar a Goianinha no mesmo instante. O que mora em Parnamirim, a 8,0 km do ponto de partida do amigo, resolveu sair\u00a0 6 minutos ap\u00f3s o hor\u00e1rio combinado para a partida. O gr\u00e1fico abaixo mostra a posi\u00e7\u00e3o em fun\u00e7\u00e3o do tempo para os<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ve\u00edculos I e II, dirigidos, respectivamente, pelos amigos oriundos de Natal e Parnamirim.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_57b9080.jpg\" alt=\"\" width=\"768\" height=\"269\" name=\"Imagem 478\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nessas condi\u00e7\u00f5es,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) os ve\u00edculos pararam durante a viagem? Eles chegaram ao mesmo tempo na cidade? Justifique suas respostas.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B) determine qual dos dois ve\u00edculos fez o percurso com maior velocidade escalar m\u00e9dia.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Justifique sua resposta.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C) considerando que a velocidade m\u00e1xima permitida no percurso entre Natal e Goianinha \u00e9 de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>100 Km\/h, determine se eles cometeram excesso de velocidade durante a viagem. Justifique<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>sua resposta.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>06-(PUCCAMP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_88a436a.jpg\" alt=\"\" width=\"768\" height=\"143\" name=\"Imagem 479\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Carlos pratica caminhada. Segundo ele, sua velocidade \u00e9 de 3500 m\/h, velocidade aferida com um rel\u00f3gio que adianta exatos um minuto e 40 segundos por hora. Julieta, amiga de Carlos, tamb\u00e9m pratica a caminhada e diz que sua<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_b4fe2307.jpg\" alt=\"\" width=\"313\" height=\"154\" name=\"Imagem 480\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade \u00e9 de 3330 m\/h, velocidade medida com um rel\u00f3gio que atrasa exatos um minuto e 40 segundos por hora. Os dois amigos resolveram caminhar partindo juntos do mesmo local, na mesma dire\u00e7\u00e3o e sentido. Cada um manteve a sua velocidade costumeira. Ap\u00f3s uma hora, marcada em um rel\u00f3gio preciso, Julieta estar\u00e1<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) atr\u00e1s de Carlos em 360 metros. \u00a0\u00a0\u00a0\u00a0\u00a0(B) atr\u00e1s de Carlos em 240 metros. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(C) junto com Carlos.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(D) adiante de Carlos em 240 metros. \u00a0\u00a0\u00a0\u00a0(E) adiante de Carlos em 360 metros.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>07-(PUCCAMP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_29b55915.jpg\" alt=\"\" width=\"690\" height=\"139\" name=\"Imagem 481\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura indica um avi\u00e3o supers\u00f4nico voando de A para C a 12 km de altitude e com velocidade constante de 1872 km\/h.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_a3e37d6d.jpg\" alt=\"\" width=\"517\" height=\"214\" name=\"Imagem 482\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desprezando-se a curvatura da Terra e adotando no c\u00e1lculo final\u00a0 \u221a3 =1,7 , o tempo que esse avi\u00e3o leva para ir de B at\u00e9 C, em segundos, \u00e9 igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A)\u00a0\u00a0 6. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(B) 8\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(C) 10 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(D) 12\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E) 14<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08-(PUC-RJ-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_17ba2043.jpg\" alt=\"\" width=\"720\" height=\"134\" name=\"Imagem 483\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O gr\u00e1fico da figura mostra a posi\u00e7\u00e3o em fun\u00e7\u00e3o do tempo<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_c1e797a0.jpg\" alt=\"\" width=\"626\" height=\"208\" name=\"Imagem 484\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de uma pessoa que passeia em um parque. Calcule a velocidade m\u00e9dia em m\/s desta pessoa durante \u00a0todo o passeio, expressando o resultado com o n\u00famero de algarismos significativos apropriados.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 0,50\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) 1,25\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (C) 1,50\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D) 1,70\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E) 4,00<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>09-(ENEM-MEC-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\">\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_30fb0b32.jpg\" alt=\"\" width=\"222\" height=\"110\" name=\"Imagem 485\" align=\"BOTTOM\" border=\"0\" \/>\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma empresa de transportes precisa efetuar a entrega de uma encomenda o mais breve poss\u00edvel.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_4f8a9dca.jpg\" alt=\"\" width=\"427\" height=\"153\" name=\"Imagem 486\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para tanto, a equipe de log\u00edstica analisa o trajeto desde a empresa at\u00e9 o local de entrega. Ela verifica que o trajeto apresenta dois trechos de dist\u00e2ncias diferentes e velocidades m\u00e1ximas permitidas diferentes. No primeiro trecho, a velocidade m\u00e1xima permitida \u00e9 de 80 km\/h e a dist\u00e2ncia a ser percorrida \u00e9 de 80 km. No segundo trecho, cujo comprimento vale 60 km, a velocidade m\u00e1xima permitida \u00e9 de 120 km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Supondo que as condi\u00e7\u00f5es de tr\u00e2nsito sejam favor\u00e1veis para que o veiculo da empresa permitida, qual ser\u00e1 o tempo necess\u00e1rio, em horas, para a realiza\u00e7\u00e3o da entrega?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,7\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 1,4\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 1,5\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 2,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 3,0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10-(ENEM-MEC-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_a5d84aa.jpg\" alt=\"\" width=\"203\" height=\"125\" name=\"Imagem 487\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para melhorar a mobilidade urbana na rede metrovi\u00e1ria \u00e9 necess\u00e1ria minimizar o tempo entre esta\u00e7\u00f5es. Para isso a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_79e1e831.jpg\" alt=\"\" width=\"342\" height=\"157\" name=\"Imagem 488\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>administra\u00e7\u00e3o do metr\u00f4 de uma grande cidade adotou o seguinte procedimento entre duas esta\u00e7\u00f5es: a locomotiva parte<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do repouso com acelera\u00e7\u00e3o constante por um ter\u00e7o do tempo de percurso, mant\u00e9m a velocidade constante por outro ter\u00e7o e reduz sua velocidade com desacelera\u00e7\u00e3o constante no trecho final, at\u00e9 parar.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Qual \u00e9 o gr\u00e1fico de posi\u00e7\u00e3o (eixo vertical) em fun\u00e7\u00e3o do tempo (eixo horizontal) que representa o movimento desse trem?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_9282e5f2.jpg\" alt=\"\" width=\"767\" height=\"159\" name=\"Imagem 489\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>11-(UNICAMP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_6c998e42.jpg\" alt=\"\" width=\"647\" height=\"153\" name=\"Imagem 490\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para fins de registros de recordes mundiais, nas provas de 100 metros rasos n\u00e3o s\u00e3o consideradas<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_c3d1f83a.jpg\" alt=\"\" width=\"157\" height=\"196\" name=\"Imagem 491\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>as marcas em competi\u00e7\u00f5es em que houver vento favor\u00e1vel (mesmo sentido do corredor) com velocidade superior a 2m\/s. Sabe-se que, com vento favor\u00e1vel de 2m\/s, o tempo necess\u00e1rio para a conclus\u00e3o da prova \u00e9 reduzido em 0,1s. Se um velocista realiza a prova em 10s sem vento, qual seria sua velocidade se o vento fosse favor\u00e1vel com velocidade de 2m\/s?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 8,0m\/s.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0b) 9,9m\/s.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0c) 10,1m\/s.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0d) 12,0m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Movimento Uniformemente variado (MUV)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01-(UFJF-MG-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_21d38763.jpg\" alt=\"\" width=\"519\" height=\"156\" name=\"Imagem 492\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A velocidade de um objeto em fun\u00e7\u00e3o do tempo \u00e9 registrada em um gr\u00e1fico.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_669a27b3.jpg\" alt=\"\" width=\"741\" height=\"212\" name=\"Imagem 493\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Analisando o gr\u00e1fico ao lado, determine o m\u00f3dulo da velocidade inicial v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, o m\u00f3dulo da acelera\u00e7\u00e3o a e a dist\u00e2ncia percorrida d entre os instantes t = 3 s e 5 s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 4m\/s; a = 4m\/s\u00b2; d = 4m.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 4m\/s; a = 0m\/s\u00b2; d = 8m.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 0m\/s; a = 4m\/s\u00b2; d = 32m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 0m\/s; a = 0m\/s\u00b2; d = 8m.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) v<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 4m\/s; a = 4m\/s\u00b2; d = 32m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02-(UEL-PR-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_b88caa11.png\" alt=\"\" width=\"742\" height=\"161\" name=\"Imagem 494\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O desrespeito \u00e0s leis de tr\u00e2nsito, principalmente \u00e0quelas relacionadas \u00e0 velocidade permitida nas vias<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>p\u00fablicas, levou os \u00f3rg\u00e3os regulamentares a utilizarem meios eletr\u00f4nicos de fiscaliza\u00e7\u00e3o: os radares capazes de aferir a velocidade de um ve\u00edculo e capturar sua imagem, comprovando a infra\u00e7\u00e3o ao C\u00f3digo de Tr\u00e2nsito Brasileiro.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Suponha que um motorista trafegue com seu carro \u00e0 velocidade constante de 30 m\/s em uma avenida cuja<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_118a24bc.png\" alt=\"\" width=\"497\" height=\"243\" name=\"Imagem 495\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade regulamentar seja de 60 km\/h. A uma dist\u00e2ncia de 50 m, o motorista percebe a exist\u00eancia de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>um radar fotogr\u00e1fico e, bruscamente, inicia a frenagem com uma desacelera\u00e7\u00e3o de 5 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sobre a a\u00e7\u00e3o do condutor, \u00e9 correto afirmar que o ve\u00edculo<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) n\u00e3o ter\u00e1 sua imagem capturada, pois passa pelo radar com velocidade de 50 km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) n\u00e3o ter\u00e1 sua imagem capturada, pois passa pelo radar com velocidade de 60 km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) ter\u00e1 sua imagem capturada, pois passa pelo radar com velocidade de 64 km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) ter\u00e1 sua imagem capturada, pois passa pelo radar com velocidade de 66 km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) ter\u00e1 sua imagem capturada, pois passa pelo radar com velocidade de 72 km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>03-(FGV-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_451823f2.png\" alt=\"\" width=\"479\" height=\"180\" name=\"Imagem 496\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em alguns pa\u00edses da Europa, os radares fotogr\u00e1ficos das rodovias, al\u00e9m de detectarem a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_f737a56d.png\" alt=\"\" width=\"469\" height=\"185\" name=\"Imagem 497\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade instant\u00e2nea dos ve\u00edculos, s\u00e3o capazes de determinar a velocidade m\u00e9dia desenvolvida pelos ve\u00edculos entre dois radares consecutivos.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere dois desses radares instalados em uma rodovia retil\u00ednea e horizontal. A velocidade instant\u00e2nea de certo autom\u00f3vel, de 1 500 kg de massa, registrada pelo primeiro radar foi de 72 km\/h. Um minuto depois, o radar seguinte acusou 90 km\/h para o mesmo autom\u00f3vel.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com a velocidade crescendo de modo constante, em fun\u00e7\u00e3o do tempo, \u00e9 correto afirmar que a dist\u00e2ncia<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_bd19ff54.png\" alt=\"\" width=\"493\" height=\"212\" name=\"Imagem 498\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>entre os dois radares \u00e9 de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 450 m. (B) 675 m. (C) 925 m. (D) 1,075 km. (E) 1,350 km.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04-(FGV-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_1d20e37e.png\" alt=\"\" width=\"415\" height=\"155\" name=\"Imagem 499\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Na fun\u00e7\u00e3o hor\u00e1ria\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>S = B\u00b7t<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0+ A<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, em que\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #660066;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>S<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0representa as\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #660066;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>posi\u00e7\u00f5es<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0ocupadas por um m\u00f3vel sobre uma trajet\u00f3ria retil\u00ednea em fun\u00e7\u00e3o do\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #660066;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>tempo t,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>as\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #660066;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>constantes A e B\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>t\u00eam, respectivamente, unidades de medida de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) velocidade final e acelera\u00e7\u00e3o. (B) posi\u00e7\u00e3o inicial e acelera\u00e7\u00e3o. (C) posi\u00e7\u00e3o inicial e velocidade final.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(D) acelera\u00e7\u00e3o e velocidade inicial. (E) posi\u00e7\u00e3o e velocidade iniciais.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>05-(UNESP-SP-014)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_332e7a00.jpg\" alt=\"\" width=\"744\" height=\"144\" name=\"Imagem 500\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um motorista dirigia por uma estrada plana e retil\u00ednea quando, por causa de obras, foi obrigado a desacelerar seu ve\u00edculo, reduzindo sua velocidade de 90 km\/h (25 m\/s) para 54 km\/h (15 m\/s). Depois de passado o trecho em obras, retornou \u00e0 velocidade inicial de 90 km\/h. O gr\u00e1fico representa como variou a velocidade escalar do ve\u00edculo em fun\u00e7\u00e3o do tempo, enquanto ele passou por esse trecho da rodovia.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_9a40b6c5.png\" alt=\"\" width=\"774\" height=\"201\" name=\"Imagem 501\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Caso n\u00e3o tivesse reduzido a velocidade devido \u00e0s obras, mas mantido sua velocidade constante de 90 km\/h durante os 80 s representados no gr\u00e1fico, a dist\u00e2ncia adicional que teria percorrido nessa estrada seria, em metros, de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 1 650. (B) 800. (C) 950. (D) 1 250. (E) 350.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>06-(UNIOESTE-PR-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_b1645da5.jpg\" alt=\"\" width=\"570\" height=\"158\" name=\"Imagem 502\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>comboio ferrovi\u00e1rio \u00e9 composto por uma locomotiva e v\u00e1rios vag\u00f5e<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>s. Tanto a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>locomotiva como os vag\u00f5es possuem\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>24 m de comprimento cada um<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. A\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>locomotiva demora 4,0 s para passar diante\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>observador parado\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pr\u00f3ximo aos trilhos e o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>primeiro vag\u00e3o demora 2,0 s para passar diante do mesmo observador<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Supondo a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>acelera\u00e7\u00e3o constante<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, assinale a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>alternativa CORRETA.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_9db26a2e.png\" alt=\"\" width=\"677\" height=\"155\" name=\"Imagem 503\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A. A acelera\u00e7\u00e3o do comboio \u00e9 igual a 0,50 m.s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B. A velocidade da locomotiva, quando come\u00e7a a passar diante do observador, \u00e9 igual a 4,0 m.s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C. O segundo vag\u00e3o demora 1,0 s para passar diante do observador.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>D. Quando o primeiro vag\u00e3o come\u00e7a a passar diante do observador, a velocidade do comboio \u00e9 igual a 36 km.h<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>E. Quando o segundo vag\u00e3o come\u00e7a a passar diante do observador, a velocidade do comboio \u00e9 igual a 54 km.h<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>07-(UNIMONTES-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_42b99b13.jpg\" alt=\"\" width=\"454\" height=\"151\" name=\"Imagem 504\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #555555;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dois carros iniciam, a partir do repouso, uma competi\u00e7\u00e3o em uma pista de corrida retil\u00ednea. O carro 1 arranca 50m \u00e0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_157afcf9.jpg\" alt=\"\" width=\"394\" height=\"177\" name=\"Imagem 505\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>frente do carro 2; ambos se movem com acelera\u00e7\u00e3o constante. Se a acelera\u00e7\u00e3o mantida pelo carro 2 \u00e9 duas vezes maior que a do carro 1 (a<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 2 a<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>), ele alcan\u00e7ar\u00e1 o carro 1 ap\u00f3s percorrer\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 200m. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B) 150m. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C) 100m. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D) 50m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08-(UFRN-RN-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_15fd031e.jpg\" alt=\"\" width=\"521\" height=\"145\" name=\"Imagem 506\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ap\u00f3s ser conscientizado por uma campanha da Pol\u00edcia Rodovi\u00e1ria Federal, um motorista deseja saber qual a dist\u00e2ncia m\u00ednima que ele deveria manter de um ve\u00edculo que trafegasse a sua frente, na mesma dire\u00e7\u00e3o e sentido, para\u00a0 evitar uma poss\u00edvel colis\u00e3o caso esse ve\u00edculo freasse repentinamente, obrigando-o a tamb\u00e9m frear bruscamente.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pesquisando na internet, ele encontrou o valor de 0,6 segundos para o tempo de rea\u00e7\u00e3o de um motorista, isto \u00e9, o intervalo de tempo entre ele perceber que o ve\u00edculo a sua frente freou e o instante em que ele aciona os freios. A figura a seguir ilustra uma situa\u00e7\u00e3o em que dois ve\u00edculos de passeio trafegam na mesma dire\u00e7\u00e3o e sentido.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_40939c5c.jpg\" alt=\"\" width=\"619\" height=\"129\" name=\"Imagem 507\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere que: os dois ve\u00edculos\u00a0 est\u00e3o\u00a0 a 72 km\/h (20 m\/s);\u00a0 o motorista do ve\u00edculo I acionou os freios quando o veiculo II se encontrava a uma dist\u00e2ncia d; e,\u00a0 durante a frenagem, os ve\u00edculos percorrem a mesma dist\u00e2ncia. Nessa situa\u00e7\u00e3o, \u00e9 correto afirmar:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) a dist\u00e2ncia m\u00ednima, d, entre os ve\u00edculos, para que n\u00e3o ocorra colis\u00e3o, deve ser 20m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B) a dist\u00e2ncia m\u00ednima, d, entre os ve\u00edculos, para que n\u00e3o ocorra colis\u00e3o, deve ser 10m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C) a dist\u00e2ncia m\u00ednima, d, entre os ve\u00edculos, para que n\u00e3o ocorra colis\u00e3o, deve ser 24m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>D) a\u00a0 dist\u00e2ncia m\u00ednima, d, entre os ve\u00edculos, para que n\u00e3o ocorra colis\u00e3o, deve ser 12m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>09-(ESPCEX-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_ab45b56d.jpg\" alt=\"\" width=\"409\" height=\"127\" name=\"Imagem 508\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um carro est\u00e1 desenvolvendo uma velocidade constante de 72 km\/h em uma rodovia federal. Ele passa por um trecho da rodovia que est\u00e1 em obras, onde a velocidade m\u00e1xima permitida \u00e9 de 60 km\/h. Ap\u00f3s 5 s de passagem do carro, uma viatura policial inicial uma persegui\u00e7\u00e3o partindo do repouso e desenvolvendo uma acelera\u00e7\u00e3o constante. A<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_16a1dd41.jpg\" alt=\"\" width=\"550\" height=\"160\" name=\"Imagem 509\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>viatura se desloca 2,1 km at\u00e9 alcan\u00e7ar o carro do infrator. Nesse momento, a viatura policial atinge a velocidade de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 20 m\/s\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b) 24 m\/s\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0c) 30 m\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d) 38 m\/s\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e) 42 m\/s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10-(UNESP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_47059f46.jpg\" alt=\"\" width=\"685\" height=\"137\" name=\"Imagem 510\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dois autom\u00f3veis est\u00e3o parados em um sem\u00e1foro para pedestres localizado em uma rua plana e retil\u00ednea. Considere o eixo x paralelo \u00e0 rua e orientado para direita, que os pontos A e B da figura representam esses autom\u00f3veis e que as coordenadas x<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(0) = 0 e x<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(0) = 3,<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>em metros, indicam as posi\u00e7\u00f5es iniciais dos autom\u00f3veis.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_c2001bf9.jpg\" alt=\"\" width=\"771\" height=\"208\" name=\"Imagem 511\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Os carros partem simultaneamente em sentidos opostos e suas velocidades escalares variam em fun\u00e7\u00e3o do tempo, conforme representado no gr\u00e1fico.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando que os autom\u00f3veis se mantenham em trajet\u00f3rias retil\u00edneas e paralelas, calcule o m\u00f3dulo do deslocamento sofrido pelo carro A entre os instantes 0 e 15 s e o instante t, em segundos, em que a diferen\u00e7a entre as coordenadas x<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e x<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, dos pontos A e B, ser\u00e1 igual a 332 m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Movimentos verticais<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01-(UFPR-PR-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_9fadba56.jpg\" alt=\"\" width=\"479\" height=\"147\" name=\"Imagem 512\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere um edif\u00edcio em constru\u00e7\u00e3o, constitu\u00eddo\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #548dd4;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pelo andar t\u00e9rreo e mais dez andares<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Um servente de pedreiro deixou\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #548dd4;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cair um martelo cuja\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>massa \u00e9 0,5 kg\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #548dd4;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a partir de uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>altura do piso do<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_4cf36514.png\" alt=\"\" width=\"274\" height=\"240\" name=\"Imagem 513\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d\u00e9cimo andar.\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Suponha que\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cada andar\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>tem uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>altura de 2,5 m\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e que o martelo caiu verticalmente em queda livre\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>partindo do repouso<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Considere a acelera\u00e7\u00e3o da gravidade igual a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10 m\/s\u00b2\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e o martelo como uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>part\u00edcula.<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Despreze a resist\u00eancia do ar, a a\u00e7\u00e3o do vento e a espessura de cada piso.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Levando em conta\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #548dd4;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>as informa\u00e7\u00f5es dadas, analise as seguintes afirmativas:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1. A velocidade do martelo ao passar pelo teto do 1\u2070\u00a0andar era 20 m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2. A energia cin\u00e9tica do martelo ao passar pelo piso do 5\u2070\u00a0andar era maior que 100 J.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3. Se a massa do martelo fosse o dobro, o tempo de queda at\u00e9 o ch\u00e3o diminuiria pela metade.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa correta.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Somente a afirmativa 1 \u00e9 verdadeira. b) Somente a afirmativa 2 \u00e9 verdadeira.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Somente as afirmativas 1 e 2 s\u00e3o verdadeiras. d) Somente as afirmativas 2 e 3 s\u00e3o verdadeiras.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) As afirmativas 1, 2 e 3 s\u00e3o verdadeiras.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02-(UDESC-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_2ac3ecd8.png\" alt=\"\" width=\"745\" height=\"164\" name=\"Imagem 514\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma pessoa do alto de um pr\u00e9dio solta uma bola e mede o m\u00f3dulo da posi\u00e7\u00e3o da bola em fun\u00e7\u00e3o do tempo. A Figura, abaixo, mostra o esbo\u00e7o do gr\u00e1fico da posi\u00e7\u00e3o em rela\u00e7\u00e3o ao tempo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_4f377936.png\" alt=\"\" width=\"668\" height=\"225\" name=\"Imagem 515\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa que representa o esbo\u00e7o dos gr\u00e1ficos em rela\u00e7\u00e3o \u00e0 velocidade \u00d7 tempo e<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e0 acelera\u00e7\u00e3o \u00d7 tempo, respectivamente.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_68928158.png\" alt=\"\" width=\"765\" height=\"275\" name=\"Imagem 516\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>03-(UFSCAR-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_b30447f0.png\" alt=\"\" width=\"675\" height=\"142\" name=\"Imagem 517\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para decidir a posse da bola no in\u00edcio de um jogo de futebol, o juiz lan\u00e7a uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #7030a0;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>moeda verticalmente<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_3eb00ea7.png\" alt=\"\" width=\"313\" height=\"192\" name=\"Imagem 518\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #7030a0;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>para cima<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e aguarda seu retorno para a palma de sua m\u00e3o. Dos esbo\u00e7os gr\u00e1ficos abaixo, aquele que pode representar a varia\u00e7\u00e3o da\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade escalar\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do centro de massa\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da moeda em fun\u00e7\u00e3o do tempo<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, supondo\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #7030a0;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>desprez\u00edvel a resist\u00eancia\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do ar, \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_11abaffc.png\" alt=\"\" width=\"765\" height=\"139\" name=\"Imagem 519\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04-(UNESP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_4af372a7.jpg\" alt=\"\" width=\"581\" height=\"119\" name=\"Imagem 520\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em um dia de calmaria, um garoto sobre uma ponte deixa cair, verticalmente e a partir do repouso, uma bola no instante t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=0. A bola atinge, no instante t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, um ponto localizado no n\u00edvel das \u00e1guas do rio e \u00e0 dist\u00e2ncia h do ponto de lan\u00e7amento. A figura apresenta, fora de escala, cinco posi\u00e7\u00f5es da bola, relativas aos instantes t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabe-se que entre os instantes t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e t<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0a bola percorre 6,25 m e que g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_98550b6b.jpg\" alt=\"\" width=\"419\" height=\"288\" name=\"Imagem 521\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desprezando a resist\u00eancia do ar e sabendo que o intervalo de tempo entre duas posi\u00e7\u00f5es consecutivas apresentadas na figura \u00e9 sempre o mesmo, pode-se afirmar que a dist\u00e2ncia h, em metros, \u00e9 igual a<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 25.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(B) 28.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0(C) 22.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0(D) 30.\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(E) 20.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Lan\u00e7amento obliquo<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01-(FGV-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_8ccd867a.png\" alt=\"\" width=\"349\" height=\"153\" name=\"Imagem 522\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dist\u00e2ncia horizontal percorrida por um dardo, denotada por\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e dada em metros<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, pode ser calculada aproximadamente pela\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>f\u00f3rmula d=V<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #c00000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.sen(2\u03b1)\/10, sendo V<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0a velocidade inicial do dardo, em metros por segundo, e \u03b1 o \u00e2ngulo do lan\u00e7amento.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_4c82b083.png\" alt=\"\" width=\"232\" height=\"269\" name=\"Imagem 523\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #004f6d;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule a velocidade inicial (em m\/s) de lan\u00e7amento de um dardo que atingiu a dist\u00e2ncia de 80 <\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>metros ao ser lan\u00e7ado sob um \u00e2ngulo de 15\u00ba.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b)\u00a0O recorde mundial masculino da prova de lan\u00e7amento do dardo foi estabelecido em 1996 por Jan Zelezny, com a marca de 98,48 m. Admitindo-se que o lan\u00e7amento tenha sido feito com o melhor \u00e2ngulo poss\u00edvel, e usando 98 m nos c\u00e1lculos, determine a velocidade inicial do dardo de Jan Zelezny no lan\u00e7amento. Entregue o resultado em km\/h.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Pelo enunciado, o\u00a0melhor \u00e2ngulo poss\u00edvel\u00a0ocorre quando o\u00a0alcance \u00e9 m\u00e1ximo\u00a0e, o\u00a0maior valor para sen (2\u03b1) o<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_a3dcb7c5.png\" alt=\"\" width=\"744\" height=\"99\" name=\"Imagem 524\" align=\"BOTTOM\" border=\"0\" \/>corre quando \u03b1=45<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, pois sen(2\u03b1)=sen(2.45<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>)=sen90<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1\u00a0&#8212; 98=V<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.1 10 &#8212; V<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=\u221a980\u224831msx3,6 &#8212;<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>V<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u2248 111km\/h<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02-(FGV-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_2f3ea2c.png\" alt=\"\" width=\"396\" height=\"143\" name=\"Imagem 525\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Na superf\u00edcie lunar, uma pequena bola lan\u00e7ada a partir do solo com velocidade inicial inclinada de 45<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0com a horizontal voltou ao solo 8,0 m adiante do ponto de lan\u00e7amento. A velocidade inicial, em metros por segundo, e o tempo de perman\u00eancia dela em movimento, em segundos, foram, respectivamente,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_42cc8525.png\" alt=\"\" width=\"765\" height=\"43\" name=\"Imagem 526\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>03-(UEFS-BA-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_21d3c613.png\" alt=\"\" width=\"518\" height=\"163\" name=\"Imagem 527\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>goleiro chuta uma bola,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>que se encontra parada no gramado,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>para um jogador situado a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>57,0m\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_d1d84196.png\" alt=\"\" width=\"775\" height=\"207\" name=\"Imagem 528\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>posi\u00e7\u00e3o do goleiro.\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>bola \u00e9 lan\u00e7ada com velocidade\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de 20,0m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, fazendo um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e2ngulo de 45\u00b0\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>com o plano horizontal.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desprezando-se a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>resist\u00eancia do ar<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, considerando-se o m\u00f3dulo da\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>acelera\u00e7\u00e3o da gravidade local igual a 10,0m\/s<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e sabendo-se que\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>sen45\u00b0 = cos45\u00b0 = \u221a2\/2<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>m\u00f3dulo<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da velocidade<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0do jogador para\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>alcan\u00e7ar a bola<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>no instante em que ela toca o gramado,<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>em m\/s,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>deve ser de, aproximadamente,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 4,0 B) 5,0 C) 6,0 D) 7,0 E) 8,0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04-(UPF-RS-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_282b887c.png\" alt=\"\" width=\"589\" height=\"169\" name=\"Imagem 529\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>Quest\u00e3o 50 &#8211;\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #008000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>vag\u00e3o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>deslocando-se em uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>trajet\u00f3ria retil\u00ednea com velocidade constante e igual a 5 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>observador, A,<\/b><\/span><\/span><\/span><span style=\"color: #008000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0dentro dele, lan\u00e7a uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pedra verticalmente para cima<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Um outro\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>observador, B, do lado de fora do vag\u00e3o e em repouso\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #008000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>em rela\u00e7\u00e3o \u00e0 Terra, observa o vag\u00e3o passar<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Sendo V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0, respectivamente, as\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidades da pedra no ponto mais alto de sua trajet\u00f3ria em rela\u00e7\u00e3o a cada observador, pode-se concluir que:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 0 e V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 0 b) V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 0 e V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 5 m\/s c) V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 5 m\/s e V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 0 d) V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 5 m\/s e V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 5m\/s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 0 e V<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 10 m\/s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>05-(UFAM-AM-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_2a9791c2.png\" alt=\"\" width=\"740\" height=\"168\" name=\"Imagem 530\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>bola de futebol com 450\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>g\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de massa<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>inicialmente em repouso<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, \u00e9 chutada obliquamente para cima com\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade inicial de 20<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m\/s<\/b><\/i><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. A bola atinge\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>altura m\u00e1xima de 10<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e atinge uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>parede<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_27c1878.png\" alt=\"\" width=\"478\" height=\"205\" name=\"Imagem 531\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>vertical 2<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>s\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ap\u00f3s o chute.\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desprezando a resist\u00eancia do ar,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>podemos afirmar que a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dist\u00e2ncia do ponto de lan\u00e7amento da bola at\u00e9 a parede\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e9 aproximadamente igual a:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 40<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 28<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 20<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 10<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 14<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>m<\/b><\/i><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>06-(PUC-RJ-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_b05792af.jpg\" alt=\"\" width=\"611\" height=\"133\" name=\"Imagem 532\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um proj\u00e9til \u00e9 lan\u00e7ado com uma velocidade escalar inicial de 20 m\/s com uma inclina\u00e7\u00e3o de 30<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0com a horizontal,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_3770c8d4.jpg\" alt=\"\" width=\"469\" height=\"200\" name=\"Imagem 533\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>estando inicialmente a uma altura de 5,0 m em rela\u00e7\u00e3o ao solo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A altura m\u00e1xima que o proj\u00e9til atinge, em rela\u00e7\u00e3o ao solo, medida em metros, \u00e9: Considere a acelera\u00e7\u00e3o da gravidade g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 5,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) 10\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (C) 15\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D) 20\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E) 25<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>07-(UNIFESP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_12249908.jpg\" alt=\"\" width=\"528\" height=\"118\" name=\"Imagem 534\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O atleta h\u00fangaro KrisztianPars conquistou medalha de ouro na olimp\u00edada de Londres no lan\u00e7amento de martelo. Ap\u00f3s girar sobre si pr\u00f3prio, o atleta lan\u00e7a a bola a 0,50 m acima do solo, com velocidade linear inicial que forma um \u00e2ngulo de 45\u00ba com a horizontal. A bola toca o solo ap\u00f3s percorrer a dist\u00e2ncia horizontal de 80 m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_ccdbfadf.jpg\" alt=\"\" width=\"297\" height=\"191\" name=\"Imagem 535\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nas condi\u00e7\u00f5es descritas do movimento parab\u00f3lico da bola, considerando a acelera\u00e7\u00e3o da gravidade no local igual a 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, \u221a2 igual a 1,4 e desprezando-se as perdas de energia mec\u00e2nica durante o v\u00f4o da bola, determine,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>aproximadamente:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) o m\u00f3dulo da velocidade de lan\u00e7amento da bola, em m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a altura m\u00e1xima, em metros, atingida pela bola.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08-(MACKENZIE-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_2481025a.jpg\" alt=\"\" width=\"578\" height=\"125\" name=\"Imagem 536\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma bola de futebol, ao ser chutada por um garoto, sai do solo com velocidade de 30,0 m\/s, formando um \u00e2ngulo de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_22f5b32a.jpg\" alt=\"\" width=\"257\" height=\"182\" name=\"Imagem 537\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>60\u00ba acima da horizontal. Desprezando a resist\u00eancia do ar, a velocidade da bola no ponto mais alto da trajet\u00f3ria ser\u00e1 de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_278a157d.jpg\" alt=\"\" width=\"519\" height=\"51\" name=\"Imagem 538\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0 11,1 m\/s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b)\u00a0 15,0 m\/s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0c)\u00a0 18,0 m\/s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d)\u00a0 26,1 m\/s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e)\u00a0 30,2 m\/s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>09-(PUC-RS-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_89cd3b69.jpg\" alt=\"\" width=\"467\" height=\"129\" name=\"Imagem 539\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma esteira horizontal despeja min\u00e9rio dentro de um vag\u00e3o. As pedras de min\u00e9rio saem da esteira com velocidade<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_68a9b842.jpg\" alt=\"\" width=\"215\" height=\"134\" name=\"Imagem 540\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>horizontal de 8,0m\/s e levam 0,60s numa trajet\u00f3ria parab\u00f3lica at\u00e9 o centro do vag\u00e3o. Considerando o peso como for\u00e7a resultante atuando em cada pedra e a acelera\u00e7\u00e3o da gravidade como 10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, os m\u00f3dulos dos deslocamentos horizontal e vertical, bem como o da velocidade das pedras quando chegam ao vag\u00e3o s\u00e3o, respectivamente,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) 6,0m; 6,0m e14m\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B) 6,0m; 4,8m e 14m\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C) 4,8m; 3,6m e 10m\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D) 4,8m; 1,8m e 10m\/s \u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>E) 4,8m; 1,8m e 6,0m\/s<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10-(UNIOESTE-PR-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_fcdd71e2.jpg\" alt=\"\" width=\"509\" height=\"136\" name=\"Imagem 541\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um canh\u00e3o atira proj\u00e9teis com velocidade de 100 m.s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0num local plano e horizontal onde a acelera\u00e7\u00e3o da<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>gravidade \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_750331af.jpg\" alt=\"\" width=\"430\" height=\"144\" name=\"Imagem 542\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>igual a 10 m.s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Se o \u00e2ngulo \u03b8 de lan\u00e7amento, com a horizontal, \u00e9 tal que sen\u03b8=0,6 e desprezando a<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>resist\u00eancia do ar, assinale a alternativa correta.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A. A componente horizontal da velocidade dos proj\u00e9teis \u00e9 igual a 60 m.s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B. A componente vertical da velocidade do proj\u00e9til \u00e9 igual a 80 m.s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C. Os proj\u00e9teis atingem o ch\u00e3o num ponto localizado a 480 m do canh\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>D. Os proj\u00e9teis atingem uma altura m\u00e1xima igual a 360 m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>E. Os proj\u00e9teis permanecem no ar durante 12 s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>MOVIMENTO CIRCULAR<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01-(UNICAMP-SP-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_6d5729e8.png\" alt=\"\" width=\"486\" height=\"167\" name=\"Imagem 543\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As m\u00e1quinas cortadeiras e colheitadeiras de cana-de-a\u00e7\u00facar podem substituir dezenas de trabalhadores\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_8e2a7389.png\" alt=\"\" width=\"765\" height=\"158\" name=\"Imagem 544\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>rurais, o que pode alterar de forma significativa a rela\u00e7\u00e3o de trabalho nas lavouras de cana-de-a\u00e7\u00facar. A p\u00e1<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cortadeira da m\u00e1quina ilustrada na figura abaixo\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0033cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>gira em movimento circular uniforme<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0a uma\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>frequ\u00eancia de 300 rpm.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_8e3fdf6a.png\" alt=\"\" width=\"385\" height=\"320\" name=\"Imagem 545\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #003399;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0de um ponto extremo P da p\u00e1 vale (Considere\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_566d73be.gif\" alt=\"\" width=\"17\" height=\"18\" name=\"Imagem 546\" align=\"BOTTOM\" border=\"0\" \/>\u00a0=3)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 9 m\/s. b) 18 m\/s. c) 15 m\/s. d) 60 m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02-(UERJ-RJ-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_bf609f13.jpg\" alt=\"\" width=\"553\" height=\"143\" name=\"Imagem 547\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma m\u00e1quina possui duas engrenagens circulares, sendo a dist\u00e2ncia entre seus centros A e B igual<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a 11 cm, como mostra o esquema:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_39bcdb60.png\" alt=\"\" width=\"252\" height=\"212\" name=\"Imagem 548\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabe-se que a engrenagem menor d\u00e1 1000 voltas no mesmo tempo em que a maior d\u00e1 375 voltas, e que os comprimentos dos dentes de ambas t\u00eam valores desprez\u00edveis.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A medida, em cent\u00edmetros, do raio da engrenagem menor equivale a:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 2,5 (B) 3,0 (C) 3,5 (D) 4,0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>03-(UEM-PR-014)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_30ab5a54.jpg\" alt=\"\" width=\"578\" height=\"152\" name=\"Imagem 549\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #ffffff;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>32<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>modelo padr\u00e3o<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0para dar movimento a uma bicicleta consiste em\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>duas polias conectadas por uma<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_57e2b602.png\" alt=\"\" width=\"329\" height=\"202\" name=\"Imagem 550\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>corrente.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma das polias, chamada de\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>coroa<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, fica\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>conectada aos pedais<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, enquanto a outra polia, chamada de\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>catraca<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, fica acoplada \u00e0 roda\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>traseira da bicicleta<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Cada pedalada, isto \u00e9, cada giro completo dos<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pedais<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, corresponde a um\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>giro completo da coroa, enquanto cada volta completa da catraca corresponde a uma volta completa da roda \u00e0 qual est\u00e1 acoplada.\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabe-se, ainda, que o\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>n\u00famero de<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>voltas da catraca \u00e9 proporcional ao n\u00famero de voltas da coroa<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, com\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>raz\u00e3o de propor\u00e7\u00e3o igual \u00e0 raz\u00e3o entre os raios da coroa (<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>R<\/b><\/i><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>) e da catraca (<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>r<\/b><\/i><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>).\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #555555;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando que a bicicleta, a partir do modelo<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0apresentado,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>desloca-se em linha reta em uma superf\u00edcie plana\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e que n\u00e3o haja deslizamento entre as rodas da bicicleta e a superf\u00edcie,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>assinale o que for\u00a0correto.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01) Se os raios da coroa e da catraca s\u00e3o, respectivamente,\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>R\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>r<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, ent\u00e3o cada volta completa da<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>coroa corresponde a\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>R\/r\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>voltas da catraca.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02) Para um dado\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>R\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>fixo, quanto menor for o raio da catraca, maior ser\u00e1 o deslocamento da bicicleta por pedalada realizada.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04) As velocidades angulares da coroa e da catraca s\u00e3o sempre iguais, independentemente do valor de seus raios.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08) Se a coroa de uma bicicleta tem raio igual a 15 cm, e a catraca tem raio igual a 1\/5 do raio da roda e 1\/4 do raio da coroa, ent\u00e3o cada pedalada corresponde a um deslocamento de 1,5 m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>16) Se as rodas de uma bicicleta t\u00eam raio igual a 50 cm e se o raio da coroa \u00e9 o dobro do raio da catraca, ent\u00e3o um ciclista que realiza duas pedaladas por segundo nessa bicicleta movimenta-se a 4\u03c0<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Symbol,serif;\"><span style=\"font-size: medium;\"><b>\uf020<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04-(ENEM-MEC-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_55b7870f.png\" alt=\"\" width=\"209\" height=\"99\" name=\"Imagem 551\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para serrar ossos e carnes congeladas, um a\u00e7ougueiro utiliza uma serra de fita que possui tr\u00eas polias e um<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>motor. O equipamento pode ser montado de duas formas diferentes, P e Q. Por quest\u00e3o de seguran\u00e7a, \u00e9 necess\u00e1rio que a serra possua menor velocidade linear.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_d12547ec.png\" alt=\"\" width=\"526\" height=\"200\" name=\"Imagem 552\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Por qual montagem o a\u00e7ougueiro deve optar e qual a justificativa desta op\u00e7\u00e3o?<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A) Q, pois as polias 1 e 3 giram com velocidades lineares iguais em pontos perif\u00e9ricos e a que tiver maior raio ter\u00e1 menor frequ\u00eancia.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B) Q, pois as polias 1 e 3 giram com frequ\u00eancias iguais e a que tiver maior raio ter\u00e1 menor velocidade linear<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>em um ponto perif\u00e9rico.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C) P, pois as polias 2 e 3 giram com frequ\u00eancias diferentes e a que tiver maior raio ter\u00e1 menor velocidade<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>linear em um ponto perif\u00e9rico.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>D) P, pois as polias 1 e 2 giram com diferentes velocidades lineares em pontos perif\u00e9ricos e a que tiver menor raio ter\u00e1 maior frequ\u00eancia.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>E) Q, pois as polias 2 e 3 giram com diferentes velocidades lineares em pontos perif\u00e9ricos e a que tiver maior raio ter\u00e1 menor frequ\u00eancia<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>05-(AFA-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_40cd5583.jpg\" alt=\"\" width=\"480\" height=\"132\" name=\"Imagem 553\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura 1 abaixo apresenta um sistema formado por dois pares de polias coaxiais, AB e CD, acoplados por meio de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>uma correia ideal e inextens\u00edvel e que n\u00e3o desliza sobre as polias\u00a0 C e\u00a0 B, tendo respectivamente raios\u00a0 R<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1 m,\u00a0 R<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0=<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2 m , R<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 10 m e R<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>D<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 0,5 m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_3de5b6b0.jpg\" alt=\"\" width=\"546\" height=\"264\" name=\"Imagem 554\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A polia A tem a forma de um cilindro no qual est\u00e1 enrolado um fio ideal e inextens\u00edvel de comprimento\u00a0 L=10\u03c0 m em<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>uma \u00fanica camada, como mostra a figura 2.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_6d821e80.jpg\" alt=\"\" width=\"157\" height=\"157\" name=\"Imagem 555\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Num dado momento, a partir do repouso, o fio \u00e9 puxado pela ponta\u00a0 P, por uma for\u00e7a\u00a0 F constante que imprime uma<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>acelera\u00e7\u00e3o linear a, tamb\u00e9m constante, na periferia da polia A, at\u00e9 que o fio se solte por completo desta polia. A partir<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>desse momento, a polia C gira at\u00e9 parar ap\u00f3s n voltas, sob a a\u00e7\u00e3o de uma acelera\u00e7\u00e3o angular constante de tal forma que<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o gr\u00e1fico da velocidade angular da polia\u00a0 D em fun\u00e7\u00e3o do tempo \u00e9 apresentado na figura 3.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_575f63f8.jpg\" alt=\"\" width=\"329\" height=\"216\" name=\"Imagem 556\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nessas condi\u00e7\u00f5es, o n\u00famero total de voltas dadas pela polia A at\u00e9 parar e o m\u00f3dulo da acelera\u00e7\u00e3o a, em m\/s<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, s\u00e3o,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>respectivamente,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 5(n + 1), 5\u03c0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b) 5n, 5\u03c0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 2(n \u2013 1), 3\u03c0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 5n, \u03c0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>06-(PUCCAMP-SP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_4ad97d53.jpg\" alt=\"\" width=\"617\" height=\"126\" name=\"Imagem 557\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As\u00a0 rodas dentadas constituem\u00a0 engrenagens \u00fateis para a transmiss\u00e3o de movimento. Duas\u00a0 rodas<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_d98c85ef.jpg\" alt=\"\" width=\"247\" height=\"162\" name=\"Imagem 558\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dentadas perfeitamente ajustadas s\u00e3o denominadas A e B. Enquanto a roda A, de 144 dentes, gira em torno de seu eixo com velocidade angular de 0,21 rad\/s, a roda B, de 126 dentes, tem velocidade angular em torno de seu eixo, em rad\/s, de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 0,18. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(B) 0,21. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(C) 0,24. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(D) 0,28. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(E) 0,31.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>07-(PUCCAMP-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_b14aa44b.jpg\" alt=\"\" width=\"738\" height=\"116\" name=\"Imagem 559\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A roda dentada acoplada aos pedais de uma bicicleta possui 49 dentes. Essa roda est\u00e1 ligada, por meio de uma corrente, a uma outra roda dentada, acoplada \u00e0 roda traseira da bicicleta, e que possui 21 dentes. Desconsiderando qualquer tipo<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_14fcc429.jpg\" alt=\"\" width=\"206\" height=\"131\" name=\"Imagem 560\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de deslizamento do pneu da bicicleta no ch\u00e3o e considerando apenas o movimento da bicicleta gerado pelas pedaladas, uma pessoa que pedalar o suficiente para que a roda dentada acoplada aos pedais gire 6 voltas completas, far\u00e1 com que a bicicleta, cujas rodas t\u00eam comprimento aproximado de 1,8 m, percorra a dist\u00e2ncia, em metros, de, aproximadamente,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A)\u00a0\u00a0 6. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(B) 15. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(C) 20. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(D) 25. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0(E) 32.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\">\u00a0<\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08-(UFV-MG-013)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_63ae5812.jpg\" alt=\"\" width=\"389\" height=\"140\" name=\"Imagem 561\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura ao lado ilustra um autom\u00f3vel parado num estacionamento, com sua frente voltada para o port\u00e3o de sa\u00edda, que funciona por controle remoto. O motorista, ao dar partida no ve\u00edculo, aciona no mesmo instante o controle remoto do port\u00e3o, que passa a abrir-se, girando em torno de seu eixo com velocidade angular constante W.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/vest_assunto\/cinematica\/Final_das_atualizac_o_es_html_e36c7a55.jpg\" alt=\"Cinem\u00e1tica\" width=\"321\" height=\"162\" name=\"Imagem 562\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O autom\u00f3vel, que se encontra \u00e0 dist\u00e2ncia D do port\u00e3o, move-se com acelera\u00e7\u00e3o constante de m\u00f3dulo a ap\u00f3s a partida, atingindo a sa\u00edda no mesmo instante em que o port\u00e3o atinge sua abertura total.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A partir dos dados e informa\u00e7\u00f5es acima, fa\u00e7a o que se pede:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Expresse, em termos de W, o tempo gasto pelo port\u00e3o para se abrir totalmente.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Expresse a acelera\u00e7\u00e3o do autom\u00f3vel em termos de W e D.<\/b><\/span><\/span><\/span><\/p>\n<h3 align=\"JUSTIFY\"><a title=\"Resolu\u00e7\u00f5es Cinem\u00e1tica \u2013 2013 \u2013 2014\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/resolucoes-cinematica-2013-2014\/\"><span style=\"color: #000080;\">Confira as resolu\u00e7\u00f5es comentadas<\/span><\/a><\/h3>\n<p>&nbsp;<\/p>\n<p><a href=\"https:\/\/fisicaevestibular.com.br\/novo\/vestibulares-recentes\/mecanica\/\">Clique aqui para ver sobre o tema!<\/a><\/p>\n<p><a href=\"https:\/\/www.youtube.com\/user\/fisicaevestibular\/playlists\">Confira as v\u00eddeo aulas!<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>2013 &#8211; 2014 Cinem\u00e1tica MOVIMENTO UNIFORME 01-(UEL-PR-014) Analise a figura a seguir. Os habitantes de\u00a0metr\u00f3poles\u00a0convivem com o problema dos\u00a0congestionamentos de autom\u00f3veis, que geram estresse, acidentes, polui\u00e7\u00e3o sonora, entre outras consequ\u00eancias. Uma solu\u00e7\u00e3o para o problema de mobilidade urbana \u00e9 o\u00a0transporte coletivo por linhas de metr\u00f4.\u00a0A\u00a0figura\u00a0mostra a regi\u00e3o central da cidade de Bras\u00edlia. Considere que um indiv\u00edduo se\u00a0desloca diariamente de carro<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3123,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3242","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3242","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3242"}],"version-history":[{"count":6,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3242\/revisions"}],"predecessor-version":[{"id":9884,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3242\/revisions\/9884"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3123"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3242"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}