{"id":3055,"date":"2017-05-30T03:17:03","date_gmt":"2017-05-30T03:17:03","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=3055"},"modified":"2024-09-03T17:42:49","modified_gmt":"2024-09-03T17:42:49","slug":"resolucao-comentada-das-questoes-de-fisica-da-unitau-geral-sp-2017","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2017\/unitau-geral-2017\/resolucao-comentada-das-questoes-de-fisica-da-unitau-geral-sp-2017\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da UNITAU GERAL \u2013 SP \u2013 2017"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da <\/span><\/span><\/span><\/p>\n

UNITAU GERAL \u2013 SP \u2013 2017<\/span><\/span><\/span><\/p>\n

01-<\/span><\/span><\/span><\/p>\n

a) Errado \"\" em t > 0 a <\/b><\/span><\/span><\/span>trajet\u00f3ria<\/b><\/span><\/span><\/span> \u00e9 uma <\/b><\/span><\/span><\/span>exponencial<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

b) Errado \"\" em <\/b><\/span><\/span><\/span>t = 0 <\/b><\/span><\/span><\/span>o objeto est\u00e1 a 10 m de <\/b><\/span><\/span><\/span>dist\u00e2ncia <\/b><\/span><\/span><\/span>do observador.<\/b><\/span><\/span><\/span><\/p>\n

c) Correto \"\" <\/b><\/span><\/span><\/span>O movimento <\/b><\/span><\/span><\/span>\u00e9 dado pela <\/b><\/span><\/span><\/span>fun\u00e7\u00e3o<\/b><\/span><\/span><\/span> x(t) = -10 + 4t +2t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>, dessa forma, o termo <\/b><\/span><\/span><\/span>quadr\u00e1tico<\/b><\/span><\/span><\/span> constante caracteriza um <\/b><\/span><\/span><\/span>movimento retil\u00edneo <\/b><\/span><\/span><\/span>uniformemente variado.<\/b><\/span><\/span><\/span><\/p>\n

d) Errado \"\" em t = 0 a <\/b><\/span><\/span><\/span>velocidade<\/b><\/span><\/span><\/span> igual a velocidade inicial do <\/b><\/span><\/span><\/span>objeto<\/b><\/span><\/span><\/span>, que vale 4 m\/s.<\/b><\/span><\/span><\/span><\/p>\n

e) Errado \"\" <\/b><\/span><\/span><\/span>quando t = 2 s <\/b><\/span><\/span><\/span>o objeto est\u00e1 a 6 m do <\/b><\/span><\/span><\/span>observador<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span><\/p>\n

\"\" \"\"<\/span><\/p>\n

R-<\/b><\/span><\/span> Portanto, a resposta correta \u00e9 a alternativa C.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

02-<\/span><\/span><\/span><\/p>\n

A <\/b><\/span><\/span><\/span>energia consumida <\/b><\/span><\/span><\/span>pode ser calculada atrav\u00e9s da <\/b><\/span><\/span><\/span>seguinte<\/b><\/span><\/span><\/span> express\u00e3o \"\" \"\"<\/b><\/span><\/span><\/span> \"\" \"\" \"\" \"\"<\/b><\/span><\/span><\/span><\/p>\n

Note que <\/b><\/span><\/span><\/span>a energia consumida n\u00e3o depende dos <\/b><\/span><\/span><\/span>valores<\/b><\/span><\/span><\/span> de tens\u00e3o de cada chuveiro, a voltagem s\u00f3 <\/b><\/span><\/span><\/span>influenciar\u00e1 <\/b><\/span><\/span><\/span>no valor da <\/b><\/span><\/span><\/span>corrente<\/b><\/span><\/span><\/span> que passa por eles. <\/b><\/span><\/span><\/span>Dessa forma<\/b><\/span><\/span><\/span>, os dois chuveiros <\/b><\/span><\/span><\/span>consomem<\/b><\/span><\/span><\/span> a mesma energia.<\/b><\/span><\/span><\/span><\/p>\n

R-<\/b><\/span><\/span> Portanto, a resposta correta \u00e9 a alternativa D.<\/b><\/span><\/span><\/span><\/span><\/span><\/p>\n

03-<\/span><\/span><\/span><\/p>\n

Neste problema<\/b><\/span><\/span><\/span>, o objeto varia sua posi\u00e7\u00e3o <\/b><\/span><\/span><\/span>de acordo <\/b><\/span><\/span><\/span>com a fun\u00e7\u00e3o hor\u00e1ria dada por \"\" \"\"<\/b><\/span><\/span><\/span> \"\" \"\"<\/b><\/span><\/span><\/span><\/p>\n

Dessa forma, <\/b><\/span><\/span><\/span>substituindo<\/b><\/span><\/span><\/span> os dados do <\/b><\/span><\/span><\/span>enunciado<\/b><\/span><\/span><\/span>, podemos calcular a altura do pr\u00e9dio \"\" \"\" \"\" \"\"<\/b><\/span><\/span><\/span><\/p>\n

R-<\/b><\/span><\/span><\/span> Portanto, a resposta correta \u00e9 a alternativa D.<\/b><\/span><\/span><\/span><\/p>\n

04-<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

<\/b>Podemos<\/b><\/span><\/span><\/span> calcular o \u00e2ngulo do <\/b><\/span><\/span><\/span>raio refratado <\/b><\/span><\/span><\/span>atrav\u00e9s da Lei de Snell-Descartes \"\" \"\"<\/b><\/span><\/span><\/span> \"\" \"\" \"\" \"\" \"\" \"\" \"\" <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R-<\/b><\/span><\/span><\/span> Portanto, a resposta correta \u00e9 a alternativa E.<\/b><\/span><\/span><\/span><\/p>\n

05-<\/span><\/span><\/span><\/p>\n

Como os <\/b><\/span><\/span><\/span>resistores<\/b><\/span><\/span><\/span> est\u00e3o em paralelo, a <\/b><\/span><\/span><\/span>tens\u00e3o sobre <\/b><\/span><\/span><\/span>cada um \u00e9 igual a V.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

<\/b>Podemos<\/b><\/span><\/span><\/span> calcular a pot\u00eancia <\/b><\/span><\/span><\/span>dissipada<\/b><\/span><\/span><\/span> em R<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> atrav\u00e9s das express\u00f5es \"\" \"\"<\/b><\/span><\/span><\/span> \"\" \"\" \"\" \"\" \"\" \"\"<\/b><\/span><\/span><\/span><\/p>\n

R-<\/b><\/span><\/span><\/span> Portanto, a resposta correta \u00e9 a alternativa B.<\/b><\/span><\/span><\/span><\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da UNITAU GERAL \u2013 SP \u2013 2017 01- a) Errado em t > 0 a trajet\u00f3ria \u00e9 uma exponencial. b) Errado em t = 0 o objeto est\u00e1 a 10 m de dist\u00e2ncia do observador. c) Correto O movimento \u00e9 dado pela fun\u00e7\u00e3o x(t) = -10 + 4t +2t2, dessa forma, o termo quadr\u00e1tico<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3053,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-3055","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3055","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=3055"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3055\/revisions"}],"predecessor-version":[{"id":3057,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3055\/revisions\/3057"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3053"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=3055"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}