{"id":30,"date":"2014-11-14T21:07:45","date_gmt":"2014-11-14T21:07:45","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=30"},"modified":"2024-09-02T17:14:47","modified_gmt":"2024-09-02T17:14:47","slug":"resolucao-do-vestibular-da-unicentro-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-do-vestibular-da-unicentro\/resolucao-do-vestibular-da-unicentro-2015\/","title":{"rendered":"Resolu\u00e7\u00e3o do Vestibular da UNICENTRO 2015"},"content":{"rendered":"

Resolu\u00e7\u00f5es<\/b><\/span><\/span><\/span><\/p>\n

01- <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

02- <\/b><\/span><\/span><\/span>Veja na <\/b><\/span><\/span>sequ\u00eancia das figuras abaixo<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span>adi\u00e7\u00e3o vetorial<\/b><\/span><\/span><\/span> desses 4 vetores de for\u00e7a, pelo <\/b><\/span><\/span><\/span>m\u00e9todo da linha poligonal<\/b><\/span><\/span><\/span>, na sequ\u00eancia indicada.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Observe que o <\/b><\/span><\/span>vetor resultante final<\/b><\/span><\/span><\/span> ter\u00e1 <\/b><\/span><\/span>uma unidade<\/b><\/span><\/span><\/span> e est\u00e1 orientado no sentido positivo do eixo y.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

03- <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

04- <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

05- <\/b><\/span><\/span><\/span>Teorema de Varignon<\/b><\/span><\/span><\/span><\/p>\n

O <\/b><\/span><\/span><\/span>momento resultante<\/b><\/span><\/span><\/span> sobre um <\/b><\/span><\/span><\/span>sistema de for\u00e7as concorrentes<\/b><\/span><\/span><\/span> (aplicadas em um mesmo ponto)<\/b><\/span><\/span><\/span>\u00e9 igual \u00e0 soma dos momentos das for\u00e7as aplicadas<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

06- <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

07- <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

08- <\/b><\/span><\/span><\/span>a.<\/b><\/span><\/span>Falsa <\/b><\/span><\/span><\/span> — veja <\/b><\/span><\/span>figura abaixo<\/b><\/span><\/span><\/span>:<\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

b.<\/b><\/span><\/span>Falsa<\/b><\/span><\/span><\/span> — veja <\/b><\/span><\/span>figura acima:<\/b><\/span><\/span><\/span><\/p>\n

c.<\/b><\/span><\/span>Falsa <\/b><\/span><\/span><\/span> — observe <\/b><\/span><\/span>na figura <\/b><\/span><\/span><\/span>que, para cada <\/b><\/span><\/span>2 oscila\u00e7\u00f5es da onda1, a onda 2 efetua 1 oscila\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

d.<\/b><\/span><\/span>Falsa<\/b><\/span><\/span><\/span> — veja <\/b><\/span><\/span>figura abaixo:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

e. <\/b><\/span><\/span>Correta<\/b><\/span><\/span><\/span>— veja <\/b><\/span><\/span>figura acima:<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

09- <\/b><\/span><\/span><\/span>A <\/b><\/span><\/span><\/span>varia\u00e7\u00e3o da energia potencial gravitacional <\/b><\/span><\/span><\/span>das massas ao <\/b><\/span><\/span><\/span>subir e descer<\/b><\/span><\/span><\/span>movimenta os fios <\/b><\/span><\/span><\/span>que <\/b><\/span><\/span><\/span>giram o cilindro, provocando uma correspondente<\/b><\/span><\/span><\/span>varia\u00e7\u00e3o de energia cin\u00e9tica.<\/b><\/span><\/span><\/span><\/p>\n

A <\/b><\/span><\/span><\/span>energia cin\u00e9tica <\/b><\/span><\/span><\/span>devido ao movimento do cilindro giram as p\u00e1s no interior do recipiente e, esse giro provoca uma <\/b><\/span><\/span><\/span>agita\u00e7\u00e3o da \u00e1gua aumentando seu movimento vibrat\u00f3rio e consequentemente sua temperatura, <\/b><\/span><\/span><\/span>transformando energia cin\u00e9tica em energia t\u00e9rmica.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

10- <\/b><\/span><\/span><\/span>Se voc\u00ea n\u00e3o domina a teoria leia as informa\u00e7\u00f5es a seguir:<\/b><\/span><\/span><\/span><\/p>\n

Fibras \u00f3pticas <\/b><\/span><\/span><\/span>\u2013 Usadas como meio de transmiss\u00e3o de ondas eletromagn\u00e9ticas (como a luz). Feitas <\/b><\/span><\/span><\/span>de pl\u00e1stico ou de vidro<\/b><\/span><\/span><\/span> e tem di\u00e2metros vari\u00e1veis (mais finos que um fio de cabelo at\u00e9 v\u00e1rios mil\u00edmetros). Em rela\u00e7\u00e3o aos <\/b><\/span><\/span><\/span>cabos met\u00e1licos de cobre <\/b><\/span><\/span><\/span>tem a vantagem de serem <\/b><\/span><\/span><\/span>imunes \u00e0s interfer\u00eancias eletromagn\u00e9ticas al\u00e9m de n\u00e3o serem afetados com problemas decorrentes\u00a0da eletricidade.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

A luz se <\/b><\/span><\/span><\/span>propaga no interior do n\u00facleo num caminho totalmente espelha<\/b><\/span><\/span><\/span>do devido ao <\/b><\/span><\/span><\/span>fen\u00f4meno da reflex\u00e3o total <\/b><\/span><\/span><\/span>que ocorrer\u00e1 no <\/b><\/span><\/span><\/span>interior do n\u00facleo <\/b><\/span><\/span><\/span>desde que o \u00edndice de refra\u00e7\u00e3o do n\u00facleo (n<\/b><\/span><\/span><\/span>n<\/b><\/span><\/span><\/sub><\/span>) seja maior que o \u00edndice de refra\u00e7\u00e3o da casca (n<\/b><\/span><\/span><\/span>c<\/b><\/span><\/span><\/sub><\/span>) e que\u00a0o \u00e2ngulo de incid\u00eancia em rela\u00e7\u00e3o \u00e0 normal ao incidir na casca seja maior que o \u00e2ngulo limite L.<\/b><\/span><\/span><\/span><\/p>\n

Utilizados em <\/b><\/span><\/span><\/span>comunica\u00e7\u00f5es (rede telef\u00f4nica, televis\u00e3o por cabo, distribui\u00e7\u00e3o de energia el\u00e9trica), em medicina (sistemas de monitora\u00e7\u00e3o interna do corpo humano e instrumenta\u00e7\u00e3o cir\u00fargica), etc<\/b><\/span><\/span><\/span>. N\u00e3o importa a dist\u00e2ncia, levam a informa\u00e7\u00e3o quase instantaneamente, ou seja, \u00e0 <\/b><\/span><\/span><\/span>velocidade pr\u00f3xima \u00e0 da luz.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

11- <\/b><\/span><\/span><\/span>Observe na <\/b><\/span><\/span>figura abaixo<\/b><\/span><\/span><\/span> que a condi\u00e7\u00e3o para que cada esfera continue em <\/b><\/span><\/span>equil\u00edbrio<\/b><\/span><\/span><\/span> \u00e9 que a <\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

for\u00e7a resultante sobre cada uma deve <\/b><\/span><\/span><\/span>ser nula<\/b><\/span><\/span><\/span> e, para que isso ocorra as <\/b><\/span><\/span>for\u00e7as sobre <\/b><\/span><\/span><\/span>cada esfera<\/b><\/span><\/span><\/span> devem ter <\/b><\/span><\/span><\/span>mesma dire\u00e7\u00e3o mas sentidos contr\u00e1rios.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

12- <\/b><\/span><\/span><\/span>Algumas informa\u00e7\u00f5es sobre o fen\u00f4meno ondulat\u00f3rio da <\/b><\/span><\/span><\/span>difra\u00e7\u00e3o:<\/b><\/span><\/span><\/span><\/p>\n

*\u00a0<\/b><\/span><\/span>Difra\u00e7\u00e3o<\/b><\/span><\/span>\u00a0\u2013 fen\u00f4meno que permite com que uma <\/b><\/span><\/span>onda atravesse fendas ou contorne obst\u00e1culos<\/b><\/span><\/span><\/span>, atingindo regi\u00f5es onde, segundo a propaga\u00e7\u00e3o retil\u00ednea da luz, n\u00e3o conseguiria chegar.<\/b><\/span><\/span><\/p>\n

* A <\/b><\/span><\/span>difra\u00e7\u00e3o \u00e9 explicada pelo Princ\u00edpio de Huygens<\/b><\/span><\/span><\/span> que afirma que: <\/b><\/span><\/span>quando os pontos de uma abertura ou de um obst\u00e1culo s\u00e3o atingidos pela frente de onda eles tornam-se fontes de ondas secund\u00e1rias que mudam a dire\u00e7\u00e3o de propaga\u00e7\u00e3o da onda principal, atravessando a abertura e contornando o obst\u00e1culo<\/b><\/span><\/span><\/span><\/p>\n

* As <\/b><\/span><\/span>ondas (sonoras ou luminosas) s\u00e3o fortemente difratadas<\/b><\/span><\/span><\/span>\u00a0 quando o <\/b><\/span><\/span>comprimento de onda\u00a0\u00a0\u03b3\u00a0tem aproximadamente o mesmo tamanho do objeto (obst\u00e1culo ou fenda).<\/b><\/span><\/span><\/span><\/p>\n

* Se a <\/b><\/span><\/span>fonte \u00e9 a mesma<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span>frequ\u00eancia da onda n\u00e3o se altera antes e depois da difra\u00e7\u00e3o<\/b><\/span><\/span><\/span>. Se, ap\u00f3s a barreira, o <\/b><\/span><\/span>meio for o mesmo, a velocidade de propaga\u00e7\u00e3o da onda tamb\u00e9m ser\u00e1 a mesma.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Assim, <\/b><\/span><\/span>o comprimento de onda tamb\u00e9m permanece o mesmo<\/b><\/span><\/span><\/span>, mas, a onda, ap\u00f3s sofrer difra\u00e7\u00e3o chega a regi\u00f5es que n\u00e3o seriam atingidas caso se considerasse apenas a propaga\u00e7\u00e3o retil\u00ednea da luz<\/b><\/span><\/span>.<\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

13- <\/b><\/span><\/span><\/span>Como eles possuem a <\/b><\/span><\/span><\/span>mesma resist\u00eancia el\u00e9trica <\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>, a corrente el\u00e9trica i<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> =i que percorre R<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>=R ao passar por R<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>=R e R<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>=R se <\/b><\/span><\/span><\/span>divide pela metade , passando i<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>=i\/2 por R<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>=R e i<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>=i\/2 por R<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

14- <\/b><\/span><\/span><\/span>Se voc\u00ea n\u00e3o domina a teoria, ela est\u00e1 a seguir:<\/b><\/span><\/span><\/span><\/p>\n

Associa\u00e7\u00e3o de capacitores<\/b><\/span><\/span><\/p>\n

\"\"\u00a0Associa\u00e7\u00e3o s\u00e9rie<\/b><\/span><\/span><\/span>\u00a0\u2013 Os capacitores da figura est\u00e3o associados em s\u00e9rie onde a <\/b><\/span><\/span>armadura positiva de cada capacitor est\u00e1 ligada \u00e0 armadura negativa do outro e assim por diante.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

No processo de carga, quando os capacitores em s\u00e9rie estiverem ligados ao gerador de tens\u00e3o U, as cargas que saem de uma armadura ser\u00e3o deslocadas para a seguinte at\u00e9 que <\/b><\/span><\/span>as cargas de todas as<\/b><\/span><\/span><\/span> <\/b>armaduras tenham o mesmo m\u00f3dulo, ou seja, Q<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>=Q<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>=Q<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>=Q.<\/b><\/span><\/span><\/span> Observe que, se as cargas s\u00e3o iguais e as capacit\u00e2ncias s\u00e3o diferentes, a <\/b><\/span><\/span>diferen\u00e7a de potencial (tens\u00e3o) tamb\u00e9m ser\u00e1 diferente<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/p>\n

Q<\/b><\/span><\/span>1<\/b><\/span><\/span><\/sub>=Q<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sub>=Q<\/b><\/span><\/span>3<\/b><\/span><\/span><\/sub>=Q\u00a0 — U=U<\/b><\/span><\/span>1<\/b><\/span><\/span><\/sub>\u00a0+ U<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sub>\u00a0+ U<\/b><\/span><\/span>3<\/b><\/span><\/span><\/sub>.<\/b><\/span><\/span><\/p>\n

\"\"\u00a0Associa\u00e7\u00e3o paralelo<\/b><\/span><\/span><\/span>\u00a0\u2013 todas as <\/b><\/span><\/span>placas positivas est\u00e3o ligadas ao polo positivo da bateria e o mesmo acontece com as placas negativas (veja figura abaixo).<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

\"\"<\/p>\n

Como est\u00e3o associadas em paralelo, a diferen\u00e7a de potencial U \u00e9 a mesma para todos os capacitores e <\/b><\/span><\/span>a carga\u00a0 total Q, do capacitor equivalente \u00e9 a soma das cargas de cada capacitor, ou seja, Q= Q<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0+ Q<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0+ Q<\/b><\/span><\/span><\/span>3\u00a0<\/b><\/span><\/span><\/sub><\/span>\u00a0—\u00a0 C.U= C<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>.U + C<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.U + C<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>.U\u00a0 —\u00a0 <\/b><\/span><\/span><\/span>C<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span>=C<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0+ C<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0+ C<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

15- <\/b><\/span><\/span>A <\/b><\/span><\/span>dire\u00e7\u00e3o e sentido de \"\"\u00a0 <\/b><\/span><\/span><\/span>\u00e9 fornecida pela <\/b><\/span><\/span>regra da m\u00e3o esquerda<\/b><\/span><\/span><\/span> (veja figura) onde o <\/b><\/span><\/span>dedo <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

m\u00e9dio<\/b><\/span><\/span><\/span> indica o <\/b><\/span><\/span>sentido da corrente el\u00e9trica i,<\/b><\/span><\/span><\/span> o <\/b><\/span><\/span>polegar<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span>for\u00e7a magn\u00e9tica<\/b><\/span><\/span><\/span> \"\" e o i<\/b><\/span><\/span>ndicador<\/b><\/span><\/span><\/span> o <\/b><\/span><\/span>campo magn\u00e9tico \"\".<\/b><\/span><\/span><\/span><\/p>\n

Adapte sua m\u00e3o esquerda na alternativa <\/b><\/span><\/span>(a)<\/b><\/span><\/span><\/span> com o <\/b><\/span><\/span>indicador <\/b><\/span><\/span><\/span>(\"\") entrando na folha, o <\/b><\/span><\/span><\/span>m\u00e9dio<\/b><\/span><\/span><\/span> (i) para baixo e verificar\u00e1 que o <\/b><\/span><\/span><\/span>polegar<\/b><\/span><\/span><\/span> (\"\") estar\u00e1 orientado para a direita.<\/b><\/span><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

Confira os Exerc\u00edcios<\/strong><\/a><\/span><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00f5es 01- 02- Veja na sequ\u00eancia das figuras abaixo a adi\u00e7\u00e3o vetorial desses 4 vetores de for\u00e7a, pelo m\u00e9todo da linha poligonal, na sequ\u00eancia indicada. Observe que o vetor resultante final ter\u00e1 uma unidade e est\u00e1 orientado no sentido positivo do eixo y. R- D 03- 04- 05- Teorema de Varignon O momento resultante sobre um sistema de for\u00e7as concorrentes<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":28,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-30","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/30","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=30"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/30\/revisions"}],"predecessor-version":[{"id":32,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/30\/revisions\/32"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/28"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=30"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}