{"id":2986,"date":"2017-05-24T02:58:32","date_gmt":"2017-05-24T02:58:32","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2986"},"modified":"2024-09-03T17:25:14","modified_gmt":"2024-09-03T17:25:14","slug":"resolucao-comentada-das-questoes-de-fisica-da-universidade-estadual-de-ciencias-da-saude-de-alagoas-uncisal-2017","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2017\/uncisal-2017\/resolucao-comentada-das-questoes-de-fisica-da-universidade-estadual-de-ciencias-da-saude-de-alagoas-uncisal-2017\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da Universidade Estadual de Ci\u00eancias da Sa\u00fade de Alagoas – UNCISAL \u2013 2017"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da <\/span><\/span><\/span><\/p>\n

Universidade Estadual de Ci\u00eancias da Sa\u00fade de Alagoas – UNCISAL \u2013 2017<\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Observa\u00e7\u00e3o:<\/b><\/span><\/span><\/span> O <\/b><\/span><\/span>byte (B) <\/b><\/span><\/span><\/span>\u00e9 usado com <\/b><\/span><\/span><\/span>frequ\u00eancia para especificar o tamanho <\/b><\/span><\/span><\/span>ou <\/b><\/span><\/span><\/span>quantidade da<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>mem\u00f3ria<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>ou da<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>capacidade de armazenamento<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>de um certo dispositivo,<\/b><\/span><\/span><\/span> <\/b>independentemente do tipo de dados.<\/b><\/span><\/span><\/span><\/p>\n

02- \"\"<\/span><\/span><\/span><\/p>\n

Equa\u00e7\u00f5es:<\/b><\/span><\/span><\/span><\/span><\/p>\n

S = S<\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sub><\/span>\u00a0+ V<\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sub><\/span>.t + at<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/2\u00a0\"\"<\/b><\/span><\/span><\/span><\/span>\u00a0 <\/b><\/span><\/span><\/span><\/span>Y= 0 + 0.t + gt<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\/2\u00a0\"\"<\/b><\/span><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span><\/span>Y = g.\"\"<\/b><\/span><\/span><\/span><\/span><\/p>\n

V<\/b><\/span><\/span><\/span><\/span>y<\/b><\/span><\/span><\/span><\/sub><\/span>\u00a0= V<\/b><\/span><\/span><\/span><\/span>oy<\/b><\/span><\/span><\/span><\/sub><\/span>\u00a0+ a.t\u00a0\"\"<\/b><\/span><\/span><\/span><\/span>\u00a0 <\/b><\/span><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span><\/span>y<\/b><\/span><\/span><\/span><\/sub><\/span> = 0 + g.t\u00a0\"\"<\/b><\/span><\/span><\/span><\/span>\u00a0\u00a0<\/b><\/span><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span><\/span>y <\/b><\/span><\/span><\/span><\/sub><\/span>= g.t<\/b><\/span><\/span><\/span><\/span><\/p>\n

V<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span> =V<\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\u00a0+ 2.a.\u0394S\u00a0\"\"<\/b><\/span><\/span><\/span><\/span>\u00a0 <\/b><\/span><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span><\/span>y<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\u00a0= V<\/b><\/span><\/span><\/span><\/span>oy<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\u00a0+ 2.g.\u0394h\u00a0\"\"<\/b><\/span><\/span><\/span><\/span>\u00a0 <\/b><\/span><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span><\/span>y<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\u00a0= 0<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\u00a0+ 2.g.\u0394h\u00a0\"\"<\/b><\/span><\/span><\/span><\/span>\u00a0 <\/b><\/span><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span><\/span>y<\/b><\/span><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span>\u00a0= 2.g.\u0394h<\/b><\/span><\/span><\/span><\/span><\/p>\n

No<\/b><\/span><\/span><\/span> caso do <\/b><\/span><\/span><\/span>exerc\u00edcio,<\/b><\/span><\/span><\/span> calculando o <\/b><\/span><\/span><\/span>tempo de queda na vertical \"\"<\/b><\/span><\/span><\/span> <\/b>Y = g.\"\"<\/b><\/span><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span><\/span>10 = 10.\"\"<\/b><\/span><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span><\/span><\/p>\n

10 = 5t<\/b><\/span><\/span><\/span><\/span>2<\/b><\/span><\/span><\/span><\/sup><\/span> \"\" <\/b><\/span><\/span><\/span><\/span>t = \"\" s <\/b><\/span><\/span><\/span><\/span>(tempo que demora na queda vertical de 10 m).<\/b><\/span><\/span><\/span><\/span><\/p>\n

Esse <\/b><\/span><\/span><\/span>tempo de queda <\/b><\/span><\/span><\/span>\u00e9 o <\/b><\/span><\/span><\/span>mesmo que ele deve demorar a percorrer<\/b><\/span><\/span><\/span> na <\/b><\/span><\/span><\/span>horizontal<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span><\/span>dist\u00e2ncia de x = 20 m <\/b><\/span><\/span><\/span>fornecido por <\/b><\/span><\/span><\/span>x = V<\/b><\/span><\/span><\/span>o.<\/b><\/span><\/span><\/sub><\/span>t \"\"<\/b><\/span><\/span><\/span> 20 = V<\/b><\/span><\/span><\/span>o\"\"<\/b><\/span><\/span><\/sub><\/span> \"\" <\/b><\/span><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sub><\/span> = \"\"<\/b><\/span><\/span><\/span><\/span> \"\" V<\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sub><\/span> <\/b>= 20.\"\"\/\"\" \"\" V<\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sub><\/span> = \"\"<\/b><\/span><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sub><\/span> = 10\"\" m\/s.<\/b><\/span><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

03- <\/span><\/span><\/span>Centrifuga\u00e7\u00e3o:<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00e9 um <\/b><\/span><\/span><\/span>processo de\u00a0<\/b><\/span><\/span><\/span>separa\u00e7\u00e3o de misturas<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>utilizado para <\/b><\/span><\/span><\/span>acelerar <\/b><\/span><\/span><\/span>a <\/b><\/span><\/span><\/span>decanta\u00e7\u00e3o <\/b><\/span><\/span><\/span>ou <\/b><\/span><\/span><\/span>sedimenta\u00e7\u00e3o<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>onde o <\/b><\/span><\/span><\/span>corpo mais denso da mistura \u00f3leo-\u00e1gua deposita-se <\/b><\/span><\/span><\/span>no <\/b><\/span><\/span><\/span>fundo do recipiente devido \u00e0 a\u00e7\u00e3o da gravidade (maior peso).<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span><\/p>\n

Este <\/b><\/span><\/span><\/span>processo \u00e9 ocorrido <\/b><\/span><\/span><\/span>em um aparelho chamado\u00a0<\/b><\/span><\/span><\/span>centr\u00edfuga,<\/b><\/span><\/span><\/span> que <\/b><\/span><\/span><\/span>gira em alta velocidade, <\/b><\/span><\/span><\/span>fazendo<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

com que a <\/b><\/span><\/span><\/span>subst\u00e2ncia mais densa seja \u201cfor\u00e7ada\u201d a sedimentar (decantar) <\/b><\/span><\/span><\/span>devido \u00e0 <\/b><\/span><\/span><\/span>a\u00e7\u00e3o da\u00a0<\/b><\/span><\/span><\/span>for\u00e7a <\/b><\/span><\/span><\/span>centr\u00edfuga<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

D<\/b><\/span><\/span><\/span>estila\u00e7\u00e3o<\/b><\/span><\/span><\/span>:\u00a0<\/b><\/span><\/span><\/span>\u00e9 um <\/b><\/span><\/span><\/span>processo que permite separar um l\u00edquido de um s\u00f3lido ou de outro l\u00edquido, <\/b><\/span><\/span><\/span>devido \u00e0 <\/b><\/span><\/span><\/span>diferen\u00e7a na temperatura de ebuli\u00e7\u00e3o dos componentes. <\/b><\/span><\/span><\/span><\/p>\n

Na\u00a0<\/b><\/span><\/span><\/span>destila\u00e7\u00e3o <\/b><\/span><\/span><\/span>simples, o <\/b><\/span><\/span><\/span>componente de menor temperatura de ebuli\u00e7\u00e3o contido no recipiente <\/b><\/span><\/span><\/span>se <\/b><\/span><\/span><\/span>vaporiza ao sofrer aquecimento e acaba passando para o condensador.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Uma vez <\/b><\/span><\/span><\/span>nesse recipiente<\/b><\/span><\/span><\/span>, ele entra em <\/b><\/span><\/span><\/span>contato com a superf\u00edcie fria da c\u00e2mara do instrumento <\/b><\/span><\/span><\/span>e retorna ao <\/b><\/span><\/span><\/span>estado l\u00edquido, passando, assim, para outro recipiente, na extremidade do condensador. <\/b><\/span><\/span><\/span>Ao <\/b><\/span><\/span><\/span>final<\/b><\/span><\/span><\/span>, os <\/b><\/span><\/span><\/span>l\u00edquidos de maior e de menor temperatura de ebuli\u00e7\u00e3o ficam separados em recipientes diferentes.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

04- <\/span><\/span><\/span>S\u00e3o dados \"\"<\/b><\/span><\/span><\/span> <\/b>pot\u00eancia total, P<\/b><\/span><\/span><\/span>t<\/b><\/span><\/span><\/sub><\/span> <\/b>= 1,21 GW <\/b><\/span><\/span><\/span>= 1,21.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> W \"\"<\/b><\/span><\/span><\/span> <\/b>rendimento, \u03b7 = 50% \"\"<\/b><\/span><\/span><\/span> <\/b>m = 1210 kg<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 0 \"\"<\/b><\/span><\/span><\/span> <\/b>V =<\/b><\/span><\/span><\/span> 100 km\/h <\/b><\/span><\/span><\/span>\u2245<\/b><\/span><\/span><\/span> 27 m\/s.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

C\u00e1lculo da <\/b><\/span><\/span><\/span>energia adquirida <\/b><\/span><\/span><\/span>pelo carro <\/b><\/span><\/span><\/span>(trabalho W) <\/b><\/span><\/span><\/span>nesse deslocamento pelo <\/b><\/span><\/span><\/span>teorema da varia\u00e7\u00e3o de energia cin\u00e9tica \"\" W = E<\/b><\/span><\/span><\/span>cf<\/b><\/span><\/span><\/sub><\/span> \u2013 E<\/b><\/span><\/span><\/span>ci<\/b><\/span><\/span><\/sub><\/span> = m\"\"<\/b><\/span><\/span><\/span> – m.V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 <\/b><\/span><\/span><\/span>= <\/b><\/span><\/span><\/span>1210.\"\"<\/b><\/span><\/span><\/span> – <\/b><\/span><\/span><\/span>1210.\"\"<\/b><\/span><\/span><\/span> = 441045 \u2013 0 \"\" <\/b><\/span><\/span><\/span><\/p>\n

W = 441045 J.<\/b><\/span><\/span><\/span><\/p>\n

Pelo enunciado, a <\/b><\/span><\/span><\/span>pot\u00eancia \u00fatil (P<\/b><\/span><\/span><\/span>u<\/b><\/span><\/span><\/sub><\/span>) utilizada \u00e9 de 50% da pot\u00eancia total P<\/b><\/span><\/span><\/span>t<\/b><\/span><\/span><\/sub><\/span> = 1,21.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> J \"\"<\/b><\/span><\/span><\/span> <\/b>P<\/b><\/span><\/span><\/span>u<\/b><\/span><\/span><\/sub><\/span> = <\/b><\/span><\/span><\/span> 0,5×1,21.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> \"\" <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>u<\/b><\/span><\/span><\/sub><\/span> = 0,605.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> J.<\/b><\/span><\/span><\/span><\/p>\n

P<\/b><\/span><\/span><\/span>u<\/b><\/span><\/span><\/sub><\/span> = \"\"<\/b><\/span><\/span><\/span> \"\" 0,605.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> = \"\" \"\" t = \"\" \"\" <\/b><\/span><\/span><\/span>t =<\/b><\/span><\/span><\/span> 729000.10<\/b><\/span><\/span><\/span>9<\/b><\/span><\/span><\/sup><\/span> = 729.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span> <\/b>= 729 \u00b5s.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/span><\/span><\/span><\/p>\n

05-<\/span><\/span><\/span> Como a <\/b><\/span><\/span><\/span>velocidade do ciclista \u00e9 constante (n\u00e3o existe varia\u00e7\u00e3o de energia cin\u00e9tica) <\/b><\/span><\/span><\/span>e a <\/b><\/span><\/span><\/span>pista \u00e9 horizontal (n\u00e3o existe varia\u00e7\u00e3o de energia potencial gravitacional), <\/b><\/span><\/span><\/span>e como <\/b><\/span><\/span><\/span>pot\u00eancia = \"\" , essa pot\u00eancia mede <\/b><\/span><\/span><\/span> a <\/b><\/span><\/span><\/span>quantidade de energia do ciclista <\/b><\/span><\/span><\/span>transformada em <\/b><\/span><\/span><\/span>energia t\u00e9rmica pela resist\u00eancia do ar e pelo atrito, por unidade de tempo<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

06- <\/span><\/span><\/span>Pelo <\/b><\/span><\/span><\/span>enunciado,<\/b><\/span><\/span><\/span> como o <\/b><\/span><\/span><\/span>volume \u00e9 constante <\/b><\/span><\/span><\/span>trata-se de uma <\/b><\/span><\/span><\/span>transforma\u00e7\u00e3o isom\u00e9trica (isoc\u00f3rica ou isovolum\u00e9trica) onde V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = V, <\/b><\/span><\/span><\/span>de <\/b><\/span><\/span><\/span>equa\u00e7\u00e3o P<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/T<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = P.V\/T \"\"<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> = \"\"<\/b><\/span><\/span><\/span> = constante, <\/b><\/span><\/span><\/span>assim \"\" \"\"<\/b><\/span><\/span><\/span> = \"\"<\/b><\/span><\/span><\/span> \"\" T.\u2206P = P. \u2206T \"\" <\/b><\/span><\/span><\/span>\u2206P = \"\"<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

07- <\/b><\/span><\/span><\/span>A trajet\u00f3ria da Lua <\/b><\/span><\/span><\/span>ao redor da Terra <\/b><\/span><\/span><\/span>n\u00e3o \u00e9 circular, \u00e9 el\u00edptica. <\/b><\/span><\/span><\/span><\/p>\n

Quando o <\/b><\/span><\/span><\/span>dia em que ocorre uma Lua Cheia coincide com o dia em que ela passa pelo perigeu <\/b><\/span><\/span><\/span>(mais pr\u00f3xima da Terra) <\/b><\/span><\/span><\/span>ela pode se apresentar at\u00e9 cerca de 30% mais brilhante que uma Lua Cheia no<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

apogeu<\/b><\/span><\/span><\/span> (mais afastada da Terra). <\/b><\/span><\/span><\/span><\/p>\n

Nesse caso, <\/b><\/span><\/span><\/span>ela aparenta ter um aumento de 14% em rela\u00e7\u00e3o ao seu tamanho real. <\/b><\/span><\/span><\/span><\/p>\n

Essa <\/b><\/span><\/span><\/span>Lua Cheia mais pr\u00f3xima da Terra <\/b><\/span><\/span><\/span>\u00e9 chamada de <\/b><\/span><\/span><\/span>Super Lua.
\n<\/b><\/span><\/span><\/span>R- E<\/b><\/span><\/span><\/span><\/p>\n

08- <\/span><\/span><\/span><\/p>\n

Michael Faraday, experimentalmente<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>observou que a<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>tens\u00e3o m\u00e9dia induzida<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>e consequentemente a<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>corrente el\u00e9trica induzida \u00e9 maior quanto mais r\u00e1pida for a varia\u00e7\u00e3o do fluxo magn\u00e9tico<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>no circuito. Lembrando que a essa<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>tens\u00e3o (ddp) m\u00e9dia induzida<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>d\u00e1-se o nome de<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>for\u00e7a eletromotriz induzida<\/b><\/span><\/span><\/span><\/p>\n

Assim, <\/b><\/span><\/span><\/span>a tens\u00e3o alternada e consequentemente a <\/b><\/span><\/span><\/span>corrente alternada do prim\u00e1rio gera no secund\u00e1rio um campo magn\u00e9tico de intensidade alternada,<\/b><\/span><\/span><\/span> que, por sua vez, <\/b><\/span><\/span><\/span>cria uma corrente el\u00e9trica e tamb\u00e9m <\/b><\/span><\/span><\/span>uma tens\u00e3o el\u00e9trica<\/b><\/span><\/span><\/span> alternada na bobina do secund\u00e1rio. <\/b><\/span><\/span><\/span> <\/b><\/p>\n

Se voc\u00ea n\u00e3o domina a teoria, ela se encontra em <\/b><\/span><\/span><\/span>fisicaevestibular.com.br \u2013 Eletricidade \u2013 Eletromagnetismo \u2013 For\u00e7a eletromotriz induzida \u2013 Transformadores.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da Universidade Estadual de Ci\u00eancias da Sa\u00fade de Alagoas – UNCISAL \u2013 2017 01- Observa\u00e7\u00e3o: O byte (B) \u00e9 usado com frequ\u00eancia para especificar o tamanho ou quantidade da\u00a0mem\u00f3ria\u00a0ou da\u00a0capacidade de armazenamento\u00a0de um certo dispositivo, independentemente do tipo de dados. 02- Equa\u00e7\u00f5es: S = So\u00a0+ Vo.t + at2\/2\u00a0\u00a0 Y= 0 + 0.t + gt2\/2\u00a0\u00a0Y<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2984,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2986","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2986","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2986"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2986\/revisions"}],"predecessor-version":[{"id":2988,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2986\/revisions\/2988"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2984"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2986"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}