{"id":2939,"date":"2017-05-16T15:15:22","date_gmt":"2017-05-16T15:15:22","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2939"},"modified":"2024-09-03T17:35:42","modified_gmt":"2024-09-03T17:35:42","slug":"resolucao-comentada-das-questoes-de-fisica-da-unicap-pe-017","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2017\/unicap-2017\/resolucao-comentada-das-questoes-de-fisica-da-unicap-pe-017\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da UNICAP-PE-017"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da <\/b><\/span><\/span><\/span><\/p>\n

UNICAP-PE-017<\/b><\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span><\/span><\/span><\/p>\n

\"\" 0 \u2013 Falsa \"\"<\/b><\/span><\/span> V<\/b><\/span><\/span>m<\/b><\/span><\/sub><\/span> = 2V<\/b><\/span><\/span>1<\/b><\/span><\/sub><\/span>.V<\/b><\/span><\/span>2<\/b><\/span><\/sub><\/span>\/ (V<\/b><\/span><\/span>1<\/b><\/span><\/sub><\/span> + V<\/b><\/span><\/span>2<\/b><\/span><\/sub><\/span>)<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\" 1 \u2013 Correta<\/b><\/span><\/span> \"\"<\/span> \u2206S <\/b><\/span><\/span>= 2\"\"<\/b><\/span><\/span> <\/b>= \"\"m<\/b><\/span><\/span> \"\" <\/b><\/span><\/span>\u2206t = 2 s \"\" V = \"\"<\/b><\/span><\/span> = 5\"\"m\/s. <\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\" 2 \u2013 Correta \"\"<\/b><\/span><\/span><\/span> S<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 0 \"\" V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 10 m\/s \"\" a = 2 m\/s<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> \"\" t = 10 s.<\/b><\/span><\/span><\/span><\/p>\n

S = S<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> + V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>t + a t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 \"\" S = 0 + 10.10 + 2.10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/2 \"\" S = 200 m.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 3 – Falsa <\/b><\/span><\/span><\/span>\u2013 <\/b><\/span><\/span><\/span>Se ele <\/b><\/span><\/span><\/span>fosse lan\u00e7ado<\/b><\/span><\/span><\/span>, por exemplo, do <\/b><\/span><\/span><\/span>alto de um pr\u00e9dio, o tempo de subida seria diferente do tempo de descida.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 4 \u2013 Correta \"\" A <\/b><\/span><\/span><\/span>for\u00e7a m\u00e1xima <\/b><\/span><\/span><\/span>para <\/b><\/span><\/span><\/span>coloc\u00e1-lo em movimento<\/b><\/span><\/span><\/span> \u00e9 calculada pelo <\/b><\/span><\/span><\/span>coeficiente <\/b><\/span><\/span><\/span>de <\/b><\/span><\/span><\/span>atrito est\u00e1tico \"\"<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span> = 0,2 \"\"<\/b><\/span><\/span><\/span> <\/b>F<\/b><\/span><\/span><\/span>ate<\/b><\/span><\/span><\/sub><\/span> = \"\"<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span>.N <\/b><\/span><\/span><\/span>= \"\"<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span>.P = \"\"<\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/sub><\/span>.m.g = 0,2.10.10 <\/b><\/span><\/span><\/span>= 20 N.<\/b><\/span><\/span><\/span><\/p>\n

Est\u00e1 na <\/b><\/span><\/span><\/span>imin\u00eancia de se mover. S\u00f3 se mover\u00e1 se F > 20 N.<\/b><\/span><\/span><\/span><\/p>\n

02- <\/span><\/span><\/span> <\/b><\/p>\n

\"\" 0 – Correta \"\" <\/b><\/span><\/span><\/span>W<\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/sub><\/span> = mgh <\/b><\/span><\/span><\/span>= 10.10.10 <\/b><\/span><\/span><\/span>= 1000 J.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 1 \u2013 Correta \"\" Se o sistema \u00e9 <\/b><\/span><\/span><\/span>conservativo a energia mec\u00e2nica <\/b><\/span><\/span><\/span>(soma das duas) <\/b><\/span><\/span><\/span>\u00e9 constante. Uma delas deve aumentar para que a outra possa diminuir.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 2 \u2013 Falsa \"\" A <\/b><\/span><\/span><\/span>energia potencial el\u00e1stica <\/b><\/span><\/span><\/span>armazenada na mola \u00e9 fornecida por <\/b><\/span><\/span><\/span>E<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span> = \"\"<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>ou seja, \u00e9 <\/b><\/span><\/span><\/span>diretamente proporcional ao quadrado da deforma\u00e7\u00e3o x<\/b><\/span><\/span><\/span>, assim, se <\/b><\/span><\/span><\/span>x dobrar ela ficar\u00e1 4 vezes maior.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 3 \u2013 Correta \"\" <\/b><\/span><\/span><\/span>Lei da gravita\u00e7\u00e3o universal<\/b><\/span><\/span><\/span>: <\/b><\/span><\/span><\/span>Dois corpos <\/b><\/span><\/span><\/span>se atraem <\/b><\/span><\/span><\/span>gravitacionalmente <\/b><\/span><\/span><\/span>com <\/b><\/span><\/span><\/span>for\u00e7a cuja intensidade \u00e9 diretamente proporcional ao produto de suas massas <\/b><\/span><\/span><\/span>e<\/b><\/span><\/span><\/span> inversamente proporcional ao quadrado da dist\u00e2ncia <\/b><\/span><\/span><\/span>entre seus<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>centros de massa.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 4 \u2013 Falsa \"\" O <\/b><\/span><\/span><\/span>empuxo <\/b><\/span><\/span><\/span>\u00e9 explicado pelo <\/b><\/span><\/span><\/span>teorema de Arquimedes.<\/b><\/span><\/span><\/span><\/p>\n

03- <\/span><\/span><\/span><\/p>\n

\"\" 0 \u2013 Falsa \"\" Como as escalas <\/b><\/span><\/span><\/span>Celsius e Kelvin possuem o mesmo n\u00famero de unidades <\/b><\/span><\/span><\/span>elas <\/b><\/span><\/span><\/span>devem sofrer a mesma varia\u00e7\u00e3o de temperatura. <\/b><\/span><\/span><\/span><\/p>\n

\"\" 1 \u2013 Correta \"\" <\/b><\/span><\/span><\/span><\/p>\n

De <\/b><\/span><\/span><\/span>gelo a 0<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 \u00e1gua a 0<\/b><\/span><\/span><\/span>o <\/b><\/span><\/span><\/sup><\/span>C \"\"<\/b><\/span><\/span><\/span> <\/b>Q<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = m.L <\/b><\/span><\/span><\/span>= 1.80 <\/b><\/span><\/span><\/span>= 80 cal. <\/b><\/span><\/span><\/span><\/p>\n

De <\/b><\/span><\/span><\/span>\u00e1gua a 0<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 \u00e1gua a 100 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C \"\"<\/b><\/span><\/span><\/span> <\/b>Q<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = m.c.(t \u2013 t<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>) <\/b><\/span><\/span><\/span>= 1.1.100 <\/b><\/span><\/span><\/span>= 100 cal.<\/b><\/span><\/span><\/span><\/p>\n

De <\/b><\/span><\/span><\/span>\u00e1gua a 100 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C at\u00e9 vapor a 100 <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>C \"\"<\/b><\/span><\/span><\/span> <\/b>Q = m.L <\/b><\/span><\/span><\/span>= 1.538 <\/b><\/span><\/span><\/span>= 538 cal.<\/b><\/span><\/span><\/span><\/p>\n

Q<\/b><\/span><\/span><\/span>total<\/b><\/span><\/span><\/sub><\/span> <\/b>= 80 + 100 + 540 <\/b><\/span><\/span><\/span>= 718 cal.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 2 \u2013 Falsa \"\" <\/b><\/span><\/span><\/span>Capacidade t\u00e9rmica = massa x calor espec\u00edfico. <\/b><\/span><\/span><\/span>A <\/b><\/span><\/span><\/span>rela\u00e7\u00e3o <\/b><\/span><\/span><\/span>entre eles <\/b><\/span><\/span><\/span>depende da massa.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 3 \u2013 Falsa \"\" \"\"<\/b><\/span><\/span><\/span> = \"\" \"\"<\/b><\/span><\/span><\/span> \"\" = \"\"<\/b><\/span><\/span><\/span> \"\" T = 900 K.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 4 \u2013 Correta \"\" <\/b><\/span><\/span><\/span>absorve calor \"\" \u2206U > 0 \"\" \u2206U = Q \u2013 W.<\/b><\/span><\/span><\/span><\/p>\n

04- <\/span><\/span><\/span><\/p>\n

\"\" 0 \u2013 Falsa \"\"<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\" 1 \u2013 Falsa \"\"<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

\"\" 2 \"\" Correta \"\"<\/b><\/span><\/span><\/span><\/p>\n

O<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>ponto objeto (O)<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>e o<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>ponto imagem (i)<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>s\u00e3o<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>sim\u00e9tricos em rela\u00e7\u00e3o ao espelho,<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>ou seja,<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>a dist\u00e2ncia<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>do<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

objeto ao espelho \u00e9 a mesma que a dist\u00e2ncia da imagem ao espelho<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>e contidos numa<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span>mesma reta perpendicular ao plano do espelho.<\/b><\/span><\/span><\/span><\/span><\/p>\n

\"\" 3 \"\" Falsa \"\" 1<\/b><\/span><\/span><\/span>\/f = 1\/P + 1\/P\u2019 \"\"<\/b><\/span><\/span><\/span> 1\/10 = 1\/100 + 1\/P\u2019 \"\" 1\/ 10 – 1\/100 = 1\/P\u2019 \"\" 9\/100 = 1\/P\u2019 \"\"<\/b><\/span><\/span><\/span> P\u2019 = 100\/9 cm<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

i\/o = – P\u2019\/P<\/b><\/span><\/span><\/span> \"\" i\/5 = – (100\/9)\/100 \"\" <\/b><\/span><\/span><\/span>i<\/b><\/span><\/span><\/span> = – 5\/9 <\/b><\/span><\/span><\/span>= – 0,56 cm.<\/b><\/span><\/span><\/span><\/p>\n

\"\" 4 \"\" Correta \"\" <\/b><\/span><\/span><\/span>n = \"\"<\/b><\/span><\/span><\/span> <\/b>= \"\" \"\" <\/b><\/span><\/span><\/span>n = 2.<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00cdSICA da UNICAP-PE-017 01- 0 \u2013 Falsa Vm = 2V1.V2\/ (V1 + V2) 1 \u2013 Correta \u2206S = 2 = m \u2206t = 2 s V = = 5m\/s. 2 \u2013 Correta So = 0 Vo = 10 m\/s a = 2 m\/s2 t = 10 s. S = So + Vot + a t2\/2<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2937,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2939","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2939","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2939"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2939\/revisions"}],"predecessor-version":[{"id":2941,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2939\/revisions\/2941"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2937"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2939"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}