{"id":2725,"date":"2017-02-07T03:51:05","date_gmt":"2017-02-07T03:51:05","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2725"},"modified":"2024-09-03T14:28:24","modified_gmt":"2024-09-03T14:28:24","slug":"resolucao-comentada-das-questoes-de-fisica-economia-da-fundacao-getulio-vargas-fgv-sp-2017","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2017\/fgv-2017\/resolucao-comentada-das-questoes-de-fisica-economia-da-fundacao-getulio-vargas-fgv-sp-2017\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00edsica (ECONOMIA) da Funda\u00e7\u00e3o Get\u00falio Vargas (FGV-SP) 2017"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00edsica (ECONOMIA) da <\/span><\/span><\/span><\/p>\n

Funda\u00e7\u00e3o Get\u00falio Vargas (FGV-SP) 2017<\/span><\/span><\/span><\/p>\n

01- <\/span><\/span><\/span>As alternativas (A) e (B) est\u00e3o erradas, pois o gr\u00e1fico <\/b><\/span><\/span><\/span>Sxt fornece apenas a posi\u00e7\u00e3o do m\u00f3vel em cada instante, <\/b><\/span><\/span><\/span>independente da trajet\u00f3ria <\/b><\/span><\/span><\/span>do mesmo. <\/b><\/span><\/span><\/span>\"\"<\/p>\n

Pelo enunciado o <\/b><\/span><\/span><\/span>trecho C n\u00e3o \u00e9 arco de par\u00e1bola (reta) <\/b><\/span><\/span><\/span>o que significa que <\/b><\/span><\/span><\/span>nesse trecho o m\u00f3vel est\u00e1 em repouso numa posi\u00e7\u00e3o qualquer, por exemplo X.<\/b><\/span><\/span><\/span><\/p>\n

Nos <\/b><\/span><\/span><\/span>trechos A, B e D <\/b><\/span><\/span><\/span>o movimento \u00e9 um <\/b><\/span><\/span><\/span>MUV de equa\u00e7\u00e3o S = S<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> + V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>t + \"\"<\/b><\/span><\/span><\/span> <\/b>onde <\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/span> \u00e9 a <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o<\/b><\/span><\/span><\/span> que \u00e9 <\/b><\/span><\/span><\/span>positiva com a concavidade da par\u00e1bola para cima e negativa com a concavidade para baixo.<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

02- <\/span><\/span><\/span><\/p>\n

Dilata\u00e7\u00e3o do tempo<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

03- \"\"<\/span><\/span><\/span><\/p>\n

R- A <\/b><\/span><\/span><\/span><\/p>\n

04- <\/span><\/span><\/span>Como <\/b><\/span><\/span><\/span>n\u00e3o houve interfer\u00eancias passivas <\/b><\/span><\/span><\/span>e, <\/b><\/span><\/span><\/span>durante o salto apenas a for\u00e7a peso (<\/b><\/span><\/span><\/span> <\/b>for\u00e7a conservativa) realiza trabalho, <\/b><\/span><\/span><\/span>voc\u00ea pode <\/b><\/span><\/span><\/span>aplicar o princ\u00edpio da conserva\u00e7\u00e3o da energia mec\u00e2nica, colocando o referencial no solo:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- A<\/b><\/span><\/span><\/span><\/p>\n

05- <\/span><\/span><\/span><\/p>\n

Se voc\u00ea n\u00e3o domina a teoria ela est\u00e1 a seguir:<\/b><\/span><\/span><\/span><\/p>\n

Segunda lei de Kepler (lei das \u00e1reas)<\/b><\/span><\/span><\/span><\/p>\n

\u201c\u00a0<\/span>O<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>segmento de reta imagin\u00e1rio<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>que une <\/b><\/span><\/span><\/span>o<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>centro do Sol ao centro do planeta varre \u00e1reas iguais em per\u00edodos de tempo iguais\u201d\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n

A figura abaixo representa um<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>planeta em \u00f3rbita el\u00edptica ao redor do Sol.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

V<\/b><\/span><\/span><\/span>12<\/b><\/span><\/span><\/sub><\/span>\u00a0<\/b><\/span><\/span><\/span>> V<\/b><\/span><\/span><\/span>34<\/b><\/span><\/span><\/sub><\/span><\/p>\n

Essa<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>constante K depende do planeta<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>e recebe o nome de<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>velocidade areolar (velocidade escalar orbital)..<\/b><\/span><\/span><\/span><\/p>\n

Observa\u00e7\u00e3o importante: <\/b><\/span><\/span><\/span>Observe que, quando<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>A<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0<\/b><\/span><\/span><\/span>= A<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00a0\"\"\u00a0<\/b><\/span><\/span><\/span>\u2206t<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0<\/b><\/span><\/span><\/span>=\u00a0\u2206t<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>,<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>ou seja, para o<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>arco maior (1,2),<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>ser percorrido no<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>mesmo intervalo de tempo que o arco menor (3,4)<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span>a <\/b><\/span><\/span><\/span>velocidade em (1,2)<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>(<\/b><\/span><\/span><\/span>mais perto do Sol,<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>peri\u00e9lio<\/b><\/span><\/span><\/span>)<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>deve ser maior que a velocidade em (3,4) <\/b><\/span><\/span><\/span>(<\/b><\/span><\/span>mais afastado do Sol,<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>af\u00e9lio<\/b><\/span><\/span><\/span>).<\/b><\/span><\/span><\/p>\n

Ent\u00e3o, V<\/b><\/span><\/span><\/span>12<\/b><\/span><\/span><\/sub><\/span>\u00a0<\/b><\/span><\/span><\/span>> V<\/b><\/span><\/span><\/span>34<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Portanto<\/b><\/span><\/span><\/span>\u00a0os<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>planetas aceleram do af\u00e9lio para o peri\u00e9lio e retardam do peri\u00e9lio para o af\u00e9lio.<\/b><\/span><\/span><\/span><\/p>\n

Ainda, de<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>acordo com essa lei<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span>se as<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u00f3rbitas forem circulares<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>velocidade de transla\u00e7\u00e3o ser\u00e1<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>constante<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>e se a \u00f3rbita do planeta tiver<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>raio R<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>e seu\u00a0<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>per\u00edodo de transla\u00e7\u00e3o for T<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span>sua<\/b><\/span><\/span><\/span> <\/b>velocidade<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>areolar<\/b><\/span><\/span><\/span> <\/b>(velocidade escalar orbital)<\/b><\/span><\/span><\/span> <\/b>ser\u00e1 constante <\/b><\/span><\/span><\/span>e dada por: <\/b><\/span><\/span><\/span>K = V = A\/\u2206t = \u03c0R<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> \/T.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

06- \"\"<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Pot\u00eancia = \"\"<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>60 000 = \"\"<\/b><\/span><\/span><\/span> \"\" \"\"= 6, 666 s<\/b><\/span><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

07- <\/span><\/span><\/span><\/p>\n

Capacidade t\u00e9rmica (C) \u2013 Calor espec\u00edfico (c)<\/b><\/span><\/span><\/span><\/p>\n

\u00a0Define-se\u00a0<\/b><\/span><\/span><\/span>capacidade t\u00e9rmica (C) ou capacidade calor\u00edfica\u00a0<\/b><\/span><\/span><\/span>de um corpo como sendo o <\/b><\/span><\/span><\/span>produto da massa desse corpo pelo calor espec\u00edfico da subst\u00e2ncia de que ele \u00e9 constitu\u00eddo, <\/b><\/span><\/span><\/span>ou seja\u00a0\u00a0\"\"\u00a0\u00a0 <\/b><\/span><\/span><\/span>C = m.c\u00a0\u00a0\"\"\u00a0 como Q = m.c.\u0394\u03b8\u00a0\u00a0\"\"\u00a0\u00a0Q = C.\u0394\u03b8\u00a0\u00a0\"\"\u00a0 ou\u00a0Q = C.(\u03b8 \u2013 \u03b8<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>).<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

No caso do exerc\u00edcio \"\"<\/b><\/span><\/span><\/span> Q = C<\/b><\/span><\/span><\/span>.\"\"<\/b><\/span><\/span><\/span> \"\" \"\"<\/b><\/span><\/span><\/span> = \"\" (I).<\/b><\/span><\/span><\/span><\/p>\n

A <\/b><\/span><\/span><\/span>dilata\u00e7\u00e3o t\u00e9rmica (varia\u00e7\u00e3o de volume \u2206V) <\/b><\/span><\/span><\/span>sofrida pelo bloco \u00e9 <\/b><\/span><\/span><\/span>fornecida por \u2206V = V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>. \"\".\"\"<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>onde o <\/b><\/span><\/span><\/span>coeficiente de dilata\u00e7\u00e3o volum\u00e9trica \"\" vale 3.\"\" <\/b><\/span><\/span><\/span>sendo \"\"<\/b><\/span><\/span><\/span> o coeficiente de dilata\u00e7\u00e3o linear do bloco \"\" <\/b><\/span><\/span><\/span>\u2206V = V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>. \"\".\"\"<\/b><\/span><\/span><\/span> (II).<\/b><\/span><\/span><\/span><\/p>\n

Substituindo <\/b><\/span><\/span><\/span>(I) em (II) \"\"<\/b><\/span><\/span><\/span> <\/b>\u2206V = V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>. \"\".\"\"<\/b><\/span><\/span><\/span> .<\/b><\/span><\/span><\/span><\/p>\n

Portanto, a <\/b><\/span><\/span><\/span>varia\u00e7\u00e3o de volume <\/b><\/span><\/span><\/span>\u2206V<\/b><\/span><\/span><\/span> do bloco \u00e9 diretamente proporcional a V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>, \"\" e inversamente proporcional a C.<\/b><\/span><\/span><\/span><\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

08- <\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

09- <\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

10- <\/span><\/span><\/span><\/p>\n

Veja um resumo da teoria:<\/span><\/span><\/span><\/p>\n

O\u00a0<\/b><\/span><\/span>ponto P fica em refor\u00e7o\u00a0<\/b><\/span><\/span><\/span>(interfer\u00eancia construtiva), o que\u00a0<\/b><\/span><\/span><\/span>ocorre quando, no mesmo instante, duas cristas ou dois vales est\u00e3o se superpondo.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

C\u00e1lculo do <\/b><\/span><\/span><\/span>comprimento de onda \"\"<\/b><\/span><\/span><\/span> dessas ondas que possuem <\/b><\/span><\/span><\/span>frequ\u00eancia de f = 4,0 Hz <\/b><\/span><\/span><\/span>e se <\/b><\/span><\/span><\/span>propagam<\/b><\/span><\/span><\/span> com <\/b><\/span><\/span><\/span>velocidade de V = 2,0 m\/s \"\" V = \"\"<\/b><\/span><\/span><\/span>.f \"\" <\/b><\/span><\/span><\/span>2 = \"\"<\/b><\/span><\/span><\/span><\/p>\n

D<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> = D \"\" d<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = 2, 8 m \"\" \"\"\"\"\"\"<\/b><\/span><\/span><\/span>para que D seja m\u00ednimo n = 1 \"\" d<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span> \u2013 d<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span> = (2n).<\/b><\/span><\/span><\/span><\/p>\n

\"\" \"\" <\/span>D \u2013 2,8 = (2.1).\"\"<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>D = 2,8 + 2.0,25 \"\"<\/b><\/span><\/span><\/span> D = 3,3 m<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

11- <\/span><\/span><\/span><\/p>\n

Equa\u00e7\u00e3o Fotoel\u00e9trica de Einstein<\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n


\n<\/b><\/span><\/span>\"\"<\/p>\n

Da equa\u00e7\u00e3o W = h.f \u00a0\"\" \u00a0f<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\u00a0= W\/h\u00a0\"\"\u00a0 f<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00e9 a frequ\u00eancia m\u00ednima (frequ\u00eancia de corte) a partir da qual os el\u00e9trons s\u00e3o extra\u00eddos do metal.<\/b><\/span><\/span><\/span><\/p>\n

Assim, nenhum el\u00e9tron \u00e9 emitido pelo metal enquanto a frequ\u00eancia da luz (f\u00f3tons) incidente n\u00e3o ultrapassar um certo limite de frequ\u00eancia, denominada frequ\u00eancia de corte (f<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>).<\/b><\/span><\/span><\/span><\/p>\n

f<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\u00a0= \"\"<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> =<\/b><\/span><\/span><\/span> \"\"<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>f<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = 1,49 H<\/b><\/span><\/span><\/span>z<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

12- <\/span><\/span><\/span>A lupa \u00e9 uma lente convergente e todos os raios de luz que incidem paralelamente ao eixo principal (caso do sol a pino) emergem da lente convergindo para o foco f. Assim, no caso do exerc\u00edcio, f = h.<\/b><\/span><\/span><\/span><\/p>\n

Veja <\/b><\/span><\/span><\/span>a constru\u00e7\u00e3o geom\u00e9trica da imagem <\/b><\/span><\/span><\/span>em uma lupa <\/b><\/span><\/span><\/span>(lente convergente) em que o objeto tem que estar entre f<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span> = f = h e O. <\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Natureza\u00a0\"\"\u00a0Virtual\u00a0<\/b><\/span><\/span><\/span>(obtida no\u00a0<\/b><\/span><\/span><\/span>cruzamento dos prolongamentos\u00a0<\/b><\/span><\/span><\/span>dos raios luminosos).<\/b><\/span><\/span><\/span><\/p>\n

Localiza\u00e7\u00e3o\u00a0\"\"\u00a0Antes de fo<\/b><\/span><\/span><\/span><\/p>\n

Tamanho e orienta\u00e7\u00e3o\u00a0\"\"\u00a0maior\u00a0que o objeto e\u00a0direita\u00a0em rela\u00e7\u00e3o a ele.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- D<\/b><\/span><\/span><\/span><\/p>\n

13- <\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- B<\/b><\/span><\/span><\/span><\/p>\n

14- <\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

No\u00a0<\/b><\/span><\/span><\/span>interior do solenoide\u00a0<\/b><\/span><\/span><\/span>o\u00a0<\/b><\/span><\/span><\/span>campo magn\u00e9tico \u00e9 praticamente uniforme\u00a0<\/b><\/span><\/span><\/span>e\u00a0<\/b><\/span><\/span><\/span>sua intensidade \u00e9 constante e vale:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\u00a0A\u00a0<\/b><\/span><\/span><\/span>express\u00e3o acima \u00e9 v\u00e1lida para solenoides sem n\u00facleo e,<\/b><\/span><\/span><\/span>\u00a0se voc\u00ea colocar no\u00a0<\/b><\/span><\/span><\/span>interior\u00a0<\/b><\/span><\/span><\/span>do <\/b><\/span><\/span><\/span>solenoide<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

um\u00a0<\/b><\/span><\/span><\/span>n\u00facleo de material ferromagn\u00e9tico,\u00a0<\/b><\/span><\/span><\/span>a\u00a0<\/b><\/span><\/span><\/span>intensidade do campo magn\u00e9tico\u00a0<\/b><\/span><\/span><\/span>gerado fica\u00a0<\/b><\/span><\/span><\/span>muito aumentada ele ser\u00e1 um eletro\u00edm\u00e3 (im\u00e3 muito possante). \u00a0<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R – B<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada das quest\u00f5es de F\u00edsica (ECONOMIA) da Funda\u00e7\u00e3o Get\u00falio Vargas (FGV-SP) 2017 01- As alternativas (A) e (B) est\u00e3o erradas, pois o gr\u00e1fico Sxt fornece apenas a posi\u00e7\u00e3o do m\u00f3vel em cada instante, independente da trajet\u00f3ria do mesmo. Pelo enunciado o trecho C n\u00e3o \u00e9 arco de par\u00e1bola (reta) o que significa que nesse trecho o m\u00f3vel est\u00e1 em<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2723,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2725","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2725","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2725"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2725\/revisions"}],"predecessor-version":[{"id":2726,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2725\/revisions\/2726"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2723"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2725"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}