{"id":2514,"date":"2016-10-18T19:37:40","date_gmt":"2016-10-18T19:37:40","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2514"},"modified":"2024-08-21T14:27:49","modified_gmt":"2024-08-21T14:27:49","slug":"resolucao-comentada-dos-exercicios-de-vestibulares-sobre-teoria-da-relatividade","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/fisica-moderna\/introducao-a-teoria-da-relatividade\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-teoria-da-relatividade\/","title":{"rendered":"Teoria da Relatividade – Resolu\u00e7\u00e3o"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre <\/b><\/span><\/span><\/span><\/p>\n

Teoria da Relatividade<\/b><\/span><\/span><\/span><\/p>\n

01-<\/b><\/span><\/span><\/span> <\/b>R- A\u00a0<\/b><\/span><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

02-<\/b><\/span><\/span><\/span> <\/b>R- D<\/b><\/span><\/span><\/span><\/p>\n

03-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>A velocidade da luz \u00e9 constante independente da velocidade da fonte emissora\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0R- B<\/b><\/span><\/span><\/span><\/p>\n

04-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>A velocidade da luz (ondas eletromagn\u00e9ticas) \u00e9 de 3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>m\/s independentemente de a fonte emissora estar em repouso ou em movimento\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>R- D<\/b><\/span><\/span><\/span><\/p>\n

05-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>I. Correta\u00a0 —\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

III. Correta\u00a0 —\u00a0 O primeiro postulado afirma que n\u00e3o existe sistema de refer\u00eancia inercial preferencial no estudo de qualquer fen\u00f4meno f\u00edsico.<\/b><\/span><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/span><\/p>\n

06-<\/b><\/span><\/span><\/span> <\/b>R- D<\/b><\/span><\/span><\/span>\u00a0 —\u00a0 veja teoria \u00a0<\/b><\/span><\/span><\/span><\/p>\n

07-<\/b><\/span><\/span><\/span> <\/b>R- D<\/b><\/span><\/span><\/span>\u00a0 —\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

08-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u0394t=\u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\/\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 lembre-se de que na Terra o intervalo de tempo \u00e9 sempre maior e que \u0394t \u00e9 sempre maior que \u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 \u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>=12meses\u00a0 —\u00a0 \u0394t=12\/\u221a1 \u2013 (0,8c)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394t=12\/\u221a1 \u2013 (0,64c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394t=12\/\u221a0,36\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>\u0394t=20 meses.<\/b><\/span><\/span><\/span><\/p>\n

09-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>a) O intervalo de tempo que sofre maior dilata\u00e7\u00e3o na express\u00e3o \u0394t=\u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\/\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0\u00e9 \u0394t e ele se dilata \u0394t= \u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\u00a0+ 0,5\/100.\u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\u00a0 — \u0394t=1,005.\u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\u00a0 — \u0394t=\u03bb.\u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\u00a0\u00a0 —\u00a0 procurando na tabela\u00a0 —\u00a0 quando \u03bb=1,005\u00a0 —\u00a0 v=0,100c\u00a0 —\u00a0 v=0,100.3,0.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>v=3,0.10<\/b><\/span><\/span><\/span>7<\/b><\/span><\/span><\/sup><\/span>m\/s<\/b><\/span><\/span><\/span>\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>observe que as velocidades no nosso cotidiano s\u00e3o insignificantes em rela\u00e7\u00e3o a 3.10<\/b><\/span><\/span><\/span>7<\/b><\/span><\/span><\/sup><\/span>=30.000.000m\/s.<\/b><\/span><\/span><\/span><\/p>\n

b) quando v=0,600c\u00a0 —\u00a0 \u03bb= 1,250c\u00a0 — \u0394t=\u03bb.\u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>=1,250.10min\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>\u0394t=12,5 min\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span>\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n

10-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>O intervalo de tempo que sofre maior dilata\u00e7\u00e3o na express\u00e3o \u0394t=\u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\/\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0\u00e9 \u0394t<\/b><\/span><\/span><\/span>Andr\u00e9<\/b><\/span><\/span><\/sub><\/span>\u00a0e ele se dilata \u0394t<\/b><\/span><\/span><\/span>Andr\u00e9<\/b><\/span><\/span><\/sub><\/span>=2\u0394t<\/b><\/span><\/span><\/span>Regina<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 \u0394t<\/b><\/span><\/span><\/span>Andr\u00e9<\/b><\/span><\/span><\/sub><\/span>=\u0394t<\/b><\/span><\/span><\/span>Regina<\/b><\/span><\/span><\/sub><\/span>\/\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 — 2\u0394t<\/b><\/span><\/span><\/span>Regina<\/b><\/span><\/span><\/sub><\/span>=\u0394t<\/b><\/span><\/span><\/span>Regina<\/b><\/span><\/span><\/sub><\/span>\/\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 2=1\/\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=1\/2\u00a0 —\u00a0 1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=1\/4\u00a0 —\u00a0 1 \u2013 1\/4=\u00a0 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 4V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=3c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 V=\u221a3\/4.c\u00a0 —\u00a0 V=0,87c\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0R- B<\/b><\/span><\/span><\/span>
\n<\/b><\/span><\/span><\/span><\/p>\n

11-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Eles ir\u00e3o retornar mais velhos, ou seja, \u0394t \u00e9 maior que \u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 \u0394t= \u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\/\u221a(1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\u00a0 —\u00a0 \u0394t= 6\/\u221a(1 \u2013 (0,8)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\u00a0 —\u00a0 \u0394t= \u0394t<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\/\u221a(1 \u2013 0,64c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\u00a0 —\u00a0 \u0394t= 6\/0,6\u00a0 —\u00a0 \u0394t= 10 anos\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>R- B<\/b><\/span><\/span><\/span><\/p>\n

12-<\/b><\/span><\/span><\/span> <\/b>A velocidade do sinal \u00e9 igual a c, qualquer que seja o referencial adotado, esteja ele em repouso ou em movimento<\/b><\/span><\/span><\/span>..<\/b><\/span><\/span><\/span><\/p>\n

13-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>A velocidade da luz \u00e9 constante e igual a c=3,0.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>m\/s=300.000.000m\/s, qualquer que seja o referencial adotado, esteja ele em repouso ou em movimento\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>R- B<\/b><\/span><\/span><\/span><\/p>\n

14-<\/b><\/span><\/span><\/span> <\/b>R- B\u00a0<\/b><\/span><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

15-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>\u0394t=\u0394t\u2019\/\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394t=18\/\u221a1 \u2013 0,64c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394t=18\/0,6\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>\u0394t=30 anos<\/b><\/span><\/span><\/span><\/p>\n

16-<\/b><\/span><\/span><\/span> <\/b>R- D\u00a0<\/b><\/span><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

17-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>As contra\u00e7\u00f5es ocorrem apenas na dire\u00e7\u00e3o do movimento, no caso, horizontal\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>R- A<\/b><\/span><\/span><\/span><\/p>\n

18-<\/b><\/span><\/span><\/span> <\/b>R-C\u00a0<\/b><\/span><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

19-<\/b><\/span><\/span><\/span> <\/b>R- E\u00a0<\/b><\/span><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

20-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Se d for a aresta da nave, medida pelo astronauta\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>=d.d.d\u00a0 —\u00a0 V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>=d<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 o observador em repouso no referencial S observar\u00e1 uma contra\u00e7\u00e3o da aresta da nave na dire\u00e7\u00e3o do eixo x, onde ela se move\u00a0 —\u00a0 nova aresta d\u2019\u00a0 —\u00a0 d\u2019=d.\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 d\u2019=d.\u221a1 \u2013 0,64c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 d\u2019=0,6d\u00a0 —\u00a0 V=d.d.d\u2019\u00a0 —\u00a0 V=d.d.0,6d\u00a0 —\u00a0 V=0,6.d.d.d\u00a0 —\u00a0<\/b><\/span><\/span><\/span>V=0,6V<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span><\/p>\n

21-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Est\u00e1 errada apenas a II, pois a contra\u00e7\u00e3o ocorre apenas na dire\u00e7\u00e3o do movimento\u00a0 —\u00a0<\/b><\/span><\/span><\/span>R- E<\/b><\/span><\/span><\/span><\/p>\n

22-<\/b><\/span><\/span><\/span> <\/b>R- E<\/b><\/span><\/span><\/span>\u00a0 —\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

23-<\/b><\/span><\/span><\/span> <\/b>R- D<\/b><\/span><\/span><\/span>\u00a0 —\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

24-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>L<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>=100m\u00a0 —\u00a0 V=0,8c\u00a0 —\u00a0 L<\/b><\/span><\/span><\/span>t<\/b><\/span><\/span><\/sub><\/span>=70m\u00a0 —\u00a0 para um observador em repouso externo ao trem, o\u00a0 comprimento do trem ser\u00e1 \u00a0\u00a0— L=L<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 L=100. \u221a1 \u2013 (0,8c)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 L=100.06\u00a0 —\u00a0 L=60m\u00a0 —\u00a0 como o comprimento do trem se reduz a 60m, ele ficar\u00e1 totalmente no interior do t\u00fanel de 70m\u00a0 —<\/b><\/span><\/span><\/span>\u00a0R- B<\/b><\/span><\/span><\/span><\/p>\n

25-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>A \u00fanica falsa \u00e9 a 22, pois, quando em movimento o corpo sofre contra\u00e7\u00e3o na dire\u00e7\u00e3o do movimento .<\/b><\/span><\/span><\/span><\/p>\n

R- \u00a000.V\u00a0\u00a0 11. V\u00a0\u00a0\u00a0 22.F\u00a0\u00a0\u00a0\u00a0\u00a0 33. V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 44. V<\/b><\/span><\/span><\/span><\/p>\n

26-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/\u221a1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/\u221a1 \u2013 (0,5c)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/\u221a\u00a00,75\u00a0 —\u00a0 m\/m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>=1\/\u221a\u00a00,75\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0R- A<\/b><\/span><\/span><\/span><\/p>\n

27<\/b><\/span><\/span><\/span>–\u00a0<\/b><\/span><\/span><\/span>E=m.c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 E=10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>.(3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 E=10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>.9.10<\/b><\/span><\/span><\/span>16<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 E=9.10<\/b><\/span><\/span><\/span>13<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 E= 10<\/b><\/span><\/span><\/span>14<\/b><\/span><\/span><\/sup><\/span>\u00a0 —<\/b><\/span><\/span><\/span>\u00a0 R- D<\/b><\/span><\/span><\/span><\/p>\n

28-<\/b><\/span><\/span><\/span> <\/b>R- C\u00a0<\/b><\/span><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

29-<\/b><\/span><\/span><\/span> <\/b>R- (01 +04 + 08) = 13<\/b><\/span><\/span><\/span><\/p>\n

30-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>V=0,6c\u00a0 —\u00a0 m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/\u221a(1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\u00a0 —\u00a0 m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/\u221a(1 \u2013 (0,6c)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\u00a0 —\u00a0 m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/0,8\u00a0 —\u00a0 m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\/8\u00a0 —\u00a0 m=1,25m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0R- C<\/b><\/span><\/span><\/span><\/p>\n

31-<\/b><\/span><\/span><\/span> <\/b>R- C\u00a0\u00a0<\/b><\/span><\/span><\/span>—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

32-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.1\/\u221a(1 \u2013 V<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\u00a0 —\u00a0 m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.1\/\u221a(1 \u2013 0,25c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\u00a0 —\u00a0 m=m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>.1\/\u221a(0,75)\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0R- A<\/b><\/span><\/span><\/span><\/p>\n

33-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Como a velocidade \u00e9 vari\u00e1vel, o fen\u00f4meno \u00e9 explicado pela teria da relatividade especial.\u00a0<\/b><\/span><\/span><\/span><\/p>\n

34-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>De acordo com o postulado de Einstein (Teoria da Relatividade) a velocidade da luz \u00e9 constante, independentemente da velocidade do observador ou da fonte\u00a0 —\u00a0<\/b><\/span><\/span><\/span>R- A<\/b><\/span><\/span><\/span><\/p>\n

35-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>m = 2 g = 2.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>\u00a0kg; E<\/b><\/span><\/span><\/span>LB<\/b><\/span><\/span><\/sub><\/span>\u00a0= 60.10<\/b><\/span><\/span><\/span>12<\/b><\/span><\/span><\/sup><\/span>\u00a0J = 6.10<\/b><\/span><\/span><\/span>13<\/b><\/span><\/span><\/sup><\/span>\u00a0J; c=3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>\u00a0m\/s; 1 m\u00eas = 2,5.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>\u00a0s<\/b><\/span><\/span><\/span><\/p>\n

a) E = m c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0= 2.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>.(3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>)2 = 2.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>.9.10<\/b><\/span><\/span><\/span>16<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0E = 1,8.10<\/b><\/span><\/span><\/span>14<\/b><\/span><\/span><\/sup><\/span>\u00a0J.<\/b><\/span><\/span><\/span><\/p>\n

b) Sendo n a quantidade de bombas \u201cLittle Boy\u201d, temos\u00a0 —\u00a0 n=E\/E<\/b><\/span><\/span><\/span>LB<\/b><\/span><\/span><\/sub><\/span>=1,8.10<\/b><\/span><\/span><\/span>14<\/b><\/span><\/span><\/sup><\/span>\/6.10<\/b><\/span><\/span><\/span>13<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 n=3 (Little Boys)<\/b><\/span><\/span><\/span><\/p>\n

c) P=W\/\u0394t=E\/\u0394t\u00a0 —\u00a0 9.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>=1,8.10<\/b><\/span><\/span><\/span>14<\/b><\/span><\/span><\/sup><\/span>\/\u0394t\u00a0 —\u00a0 \u0394t=2.10<\/b><\/span><\/span><\/span>7<\/b><\/span><\/span><\/sup><\/span>s\u00a0 —\u00a0 \u0394t=2.10<\/b><\/span><\/span><\/span>7<\/b><\/span><\/span><\/sup><\/span>\/2,5.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394t=8 meses<\/b><\/span><\/span><\/span><\/p>\n

36-<\/b><\/span><\/span><\/span>\u00a0 <\/b><\/span><\/span><\/span>Para dois corpos deslocando-se em sentidos opostos, com velocidades de m\u00f3dulo u e v em rela\u00e7\u00e3o a um referencial inercial, a velocidade relativa (v\u2019) entre eles \u00e9 dada pela equa\u00e7\u00e3o de Einstein (veja teoria)\u00a0 —\u00a0 V\u2019=(u + V)\/1 + u.V\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 como, nesse exerc\u00edcio u=V=c2\u00a0 —\u00a0 V\u2019=(c\/2 + c\/2)\/ 1 + (c\/2.c\/2)\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 V\u2019=c\/(5\/4)\u00a0 —\u00a0 V\u2019=4c\/5\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0R- D<\/b><\/span><\/span><\/span><\/p>\n

37<\/b><\/span><\/span><\/span>–<\/b><\/span><\/span><\/span> <\/b>a) Dados: R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\u00a0= 6,4.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>\u00a0m; c = 3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>\u00a0m\/s; t<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>\u00a0= 1 dia = 86.400 s\u00a0 —\u00a0 express\u00f5es fornecidas\u00a0 —\u00a0 \u0394t\/T<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>= \u0394U\/m.c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0(I)\u00a0 —\u00a0\u0394U=m.g.R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>.(1 \u2013 R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>r) (II)\u00a0 —\u00a0 (II) em (I)\u00a0 —\u00a0 \u0394tT<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>=m.g.R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\/(m.c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>).(1 \u2013 R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\/r)\u00a0 —\u00a0 r=4R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 \u0394tT<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>=m.g.R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\/(m.c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>).(1 \u2013 R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\/4R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>)\u00a0 —\u00a0 \u0394t=(T<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>).g.R<\/b><\/span><\/span><\/span>T<\/b><\/span><\/span><\/sub><\/span>\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.3\/4\u00a0 —\u00a0 substituindo os valores num\u00e9ricos\u00a0 —\u00a0 \u0394t=86.400.(10.6,4.10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>)\/(3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0\u0394t=4,6.10<\/b><\/span><\/span><\/span>-5<\/b><\/span><\/span><\/sup><\/span>s<\/b><\/span><\/span><\/span><\/p>\n

b) \u00c9 dado que \u0394t\/t<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>=10<\/b><\/span><\/span><\/span>-16<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394t\/t<\/b><\/span><\/span><\/span>Terra<\/b><\/span><\/span><\/sub><\/span>= \u0394U\/m.c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 na vizinhan\u00e7a terrestre\u00a0 —\u00a0 \u0394U=m.g.h\u00a0 —\u00a0 10<\/b><\/span><\/span><\/span>-16<\/b><\/span><\/span><\/sup><\/span>=g.h\/c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0<\/b><\/span><\/span><\/span><\/p>\n

h=10<\/b><\/span><\/span><\/span>-16<\/b><\/span><\/span><\/sup><\/span>.9.10<\/b><\/span><\/span><\/span>16<\/b><\/span><\/span><\/sup><\/span>\/10\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0h=0,9m<\/b><\/span><\/span><\/span><\/p>\n

38-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>a) Dados: c = 300.000 km\/s; v = 0,998 c = 299.400 km\/s; Dt = 2 ms = 2.10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span>\u00a0s\u00a0 —\u00a0 mec\u00e2nica cl\u00e1ssica\u00a0 —\u00a0 V=\u0394S\/\u0394t\u00a0 —\u00a0 0,998.3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>= \u0394S\/2.10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 2,994.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>=\u0394S\/2.10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 \u0394S=5,988.10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>\u0394S=598,8m<\/b><\/span><\/span><\/span><\/p>\n

b) Pela dilata\u00e7\u00e3o do tempo (mec\u00e2nica relativ\u00edstica)\u00a0 —\u00a0 \u0394t= \u0394<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\/1\/\u221a(1 \u2013 0,998<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>)\u00a0 —\u00a0 \u0394t= 2.10<\/b><\/span><\/span><\/span>-6<\/b><\/span><\/span><\/sup><\/span>\/15\u00a0 —\u00a0 \u0394t=3.10<\/b><\/span><\/span><\/span>-5<\/b><\/span><\/span><\/sup><\/span>s\u00a0 —\u00a0 V= \u0394S\/\u0394t\u00a0 —\u00a0 299.400.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>= \u0394S\/3.10<\/b><\/span><\/span><\/span>-5<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0\u0394S=8.982m<\/b><\/span><\/span><\/span><\/p>\n

c) No referencial do m\u00faon, h\u00e1 contra\u00e7\u00e3o do espa\u00e7o, tal que uma dist\u00e2ncia de 8.982 m no referencial de um observador no solo para o m\u00faon \u00e9 de apenas 598,8 m.<\/b><\/span><\/span><\/span><\/p>\n

39-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>a) m=2g + 2g=4.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>kg\u00a0 —\u00a0 E=m.c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=4.10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>.(3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0E=3,6.10<\/b><\/span><\/span><\/span>14<\/b><\/span><\/span><\/sup><\/span>J<\/b><\/span><\/span><\/span><\/p>\n

b) Energia consumida pela cidade em um m\u00eas\u00a0 —\u00a0 E=1milh\u00e3o.100kWh=10<\/b><\/span><\/span><\/span>6<\/b><\/span><\/span><\/sup><\/span>.100.10<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sup><\/span>.3.600=36.10<\/b><\/span><\/span><\/span>13<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 E=3,6.10<\/b><\/span><\/span><\/span>14<\/b><\/span><\/span><\/sup><\/span>J\u00a0 —<\/b><\/span><\/span><\/span><\/p>\n

\u00a0R- 1 m\u00eas<\/b><\/span><\/span><\/span><\/p>\n

40-<\/b><\/span><\/span><\/span> <\/b>R- D<\/b><\/span><\/span><\/span>\u00a0 —\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

41-<\/b><\/span><\/span><\/span> <\/b>R- E\u00a0<\/b><\/span><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

42-<\/b><\/span><\/span><\/span> <\/b>R- D\u00a0<\/b><\/span><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

43-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>A energia cin\u00e9tica relativ\u00edstica do corpo corresponde \u00e0 diferen\u00e7a entre a energia pr\u00f3pria (E) e a energia do repouso (E<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>)\u00a0 — E<\/b><\/span><\/span><\/span>c<\/b><\/span><\/span><\/sub><\/span>=E \u2013 E<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 E<\/b><\/span><\/span><\/span>c<\/b><\/span><\/span><\/sub><\/span>=mc<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0\u2013 m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 E<\/b><\/span><\/span><\/span>c<\/b><\/span><\/span><\/sub><\/span>=(m \u2013 m<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sub><\/span>).c<\/b><\/span><\/span><\/span>\u00a0 —\u00a0<\/b><\/span><\/span><\/span>como c \u00e9 constante, se E<\/b><\/span><\/span><\/span>c<\/b><\/span><\/span><\/sub><\/span>\u00a0diminuir ocorrer\u00e1 uma correspondente diminui\u00e7\u00e3o de massa do corpo\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>R- E<\/b><\/span><\/span><\/span><\/p>\n

44-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>m=1g=10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>kg\u00a0 —\u00a0 E=m.c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>.(3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=10<\/b><\/span><\/span><\/span>-3<\/b><\/span><\/span><\/sup><\/span>.9.10<\/b><\/span><\/span><\/span>16<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 m=9.10<\/b><\/span><\/span><\/span>13<\/b><\/span><\/span><\/sup><\/span>J\u00a0 —\u00a0<\/b><\/span><\/span><\/span>\u00a0R- A<\/b><\/span><\/span><\/span><\/p>\n

45-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>Dados\u00a0 —\u00a0\u00a0 m<\/b><\/span><\/span><\/span>p<\/b><\/span><\/span><\/sub><\/span>\u00a0= 1,673.10<\/b><\/span><\/span><\/span>-27<\/b><\/span><\/span><\/sup><\/span>\u00a0kg\u00a0 —\u00a0 m<\/b><\/span><\/span><\/span>H<\/b><\/span><\/span><\/sub><\/span>\u00a0= 6,645.10<\/b><\/span><\/span><\/span>-27<\/b><\/span><\/span><\/sup><\/span>\u00a0kg\u00a0 —\u00a0\u00a0 c = 3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>\u00a0m\/s\u00a0 —\u00a0 \u00a0diferen\u00e7a entre a massa de 4 pr\u00f3tons e a massa do n\u00facleo de h\u00e9lio \u00e9 a massa transformada em energia —\u00a0\u00a0 \u2502\u2206m\u2502=4m<\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/sub><\/span>\u00a0\u2013 m<\/b><\/span><\/span><\/span>H\u00a0<\/b><\/span><\/span><\/sub><\/span>= (4.1,673 \u2013 6,645).10<\/b><\/span><\/span><\/span>-27<\/b><\/span><\/span><\/sup><\/span>\u00a0 — \u2502\u2206m\u2502= 4,7.10<\/b><\/span><\/span><\/span>-29\u00a0<\/b><\/span><\/span><\/sup><\/span>kg\u00a0 — rela\u00e7\u00e3o massa-energia de Einstein\u00a0 —\u00a0 E=\u2502\u2206m\u2502.c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=(4,7.10<\/b><\/span><\/span><\/span>-29<\/b><\/span><\/span><\/sup><\/span>).(3.10<\/b><\/span><\/span><\/span>8<\/b><\/span><\/span><\/sup><\/span>)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>E=4,23.10<\/b><\/span><\/span><\/span>-12<\/b><\/span><\/span><\/sup><\/span>J<\/b><\/span><\/span><\/span><\/p>\n

46-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>a) Observe a figura abaixo\u00a0 —\u00a0 n\u00e3o havendo for\u00e7as externas a quantidade de movimento do sistema \u00e9 conservada\u00a0 —\u00a0 a quantidade de movimento inicial \u00e9 nula ( a part\u00edcula que decai estava em repouso)\u00a0 —\u00a0\u00a0\"\"=0\u00a0 —\u00a0 quantidade de movimento final\u00a0 —\u00a0\u00a0\"\"igualando os m\u00f3dulos da quantidade de movimento inicial com a final\u00a0 —\u00a0 0= – m.0,8c + m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>0,6c\u00a0 —\u00a0 m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>=(4\/3)m\u00a0 —\u00a0 como em uma abordagem n\u00e3o relativ\u00edstica a massa \u00e9 conservada\u00a0 —\u00a0 M= m<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0+ m<\/b><\/span><\/span><\/span>2\u00a0<\/b><\/span><\/span><\/sub><\/span>= m + (4\/3)m\u00a0 —\u00a0<\/b><\/span><\/span><\/span>M=7m\/3<\/b><\/span><\/span><\/span>\"\"<\/p>\n

b) Conserva\u00e7\u00e3o da quantidade de movimento do ponto de vista relativ\u00edstico\u00a0 —\u00a0 0=m<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>v<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0+ m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>v<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 0=- m.0,8c\/\u221a{1 \u2013 (0,8c\/c)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>} +<\/b><\/span><\/span><\/span><\/p>\n

m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.0,6c\/\u221a{1 \u2013 (0,6c\/c)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>} —\u00a0 0,8m\/\u221a(1 \u2013 0,64) = 0,6m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\/\u221a(1 \u2013 0,36)\u00a0 —\u00a0 m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>=64\/36\u00a0 —\u00a0 m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>=16\/9\u00a0 —\u00a0 pela conserva\u00e7\u00e3o da energia relativ\u00edstica\u00a0 —\u00a0 E<\/b><\/span><\/span><\/span>inicial<\/b><\/span><\/span><\/sub><\/span>=E<\/b><\/span><\/span><\/span>final<\/b><\/span><\/span><\/sub><\/span>\u00a0 —\u00a0 Mc<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>=mc<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0+ m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>c<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 —\u00a0 Mc<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>= m\/\u221a{1 \u2013 (0,8c\/c)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>} + \u221a{1 \u2013 (0,6c\/c)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>}\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>M=35\/9m<\/b><\/span><\/span><\/span><\/p>\n

47-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>01. Correta\u00a0 — \u00a0Um corpo negro ideal \u00e9 considerado um corpo, onde seu poder absorvente \u00e9 igual a 1, ou seja, toda energia incidente \u00e9 absorvida e consequentemente emitida, ou seja, ele \u00e9 considerado uma fonte ideal de radia\u00e7\u00e3o t\u00e9rmica.<\/b><\/span><\/span><\/span><\/p>\n

02. Falsa\u00a0 — O efeito fotoel\u00e9trico s\u00f3 ocorre se a frequ\u00eancia da luz incidente sobre o metal for<\/b><\/span><\/span><\/span>inferior<\/b><\/span><\/span><\/span>\u00a0a um valor m\u00ednimo.<\/b><\/span><\/span><\/span><\/p>\n

04. Correta\u00a0 —\u00a0 veja teoria<\/b><\/span><\/span><\/span><\/p>\n

08. Falsa\u00a0 —\u00a0 \u00e9 a teoria da relatividade de Einstein<\/b><\/span><\/span><\/span><\/p>\n

16. Correta\u00a0 — \u00a0veja teoria<\/b><\/span><\/span><\/span><\/p>\n

32. Falsa\u00a0 —\u00a0 \u00e9 explicado pela f\u00edsica moderna<\/b><\/span><\/span><\/span><\/p>\n

64. Falsa\u00a0 —\u00a0 \u00e9 explicado apenas pela f\u00edsica moderna<\/b><\/span><\/span><\/span><\/p>\n

R- (01 + 04 + 16) = 21<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

48-<\/b><\/span><\/span><\/span> <\/b>A luz tem car\u00e1ter dual: os fen\u00f4menos de reflex\u00e3o, refra\u00e7\u00e3o, interfer\u00eancia, difra\u00e7\u00e3o e polariza\u00e7\u00e3o da luz podem ser explicados pela teoria ondulat\u00f3ria e os de emiss\u00e3o e absor\u00e7\u00e3o podem ser explicados pela teoria corpuscular.<\/b><\/span><\/span><\/span><\/p>\n

Difra\u00e7\u00e3o\u00a0 — fen\u00f4meno de caracteriza a natureza ondulat\u00f3ria da luz, que permite com que uma onda atravesse fendas ou contorne obst\u00e1culos, atingindo regi\u00f5es onde, segundo a propaga\u00e7\u00e3o retil\u00ednea da luz, n\u00e3o conseguiria chegar\u00a0 —\u00a0 efeito fotoel\u00e9trico\u00a0 — fen\u00f4meno que caracteriza a natureza corpuscular da luz que ocorre quando a luz\u00a0(onda eletromagn\u00e9tica, radia\u00e7\u00e3o eletromagn\u00e9tica) de freq\u00fc\u00eancia suficientemente alta incide sobre a superf\u00edcie de um metal, ela pode retirar el\u00e9trons do mesmo\u00a0 —\u00a0 esse fen\u00f4meno ficou conhecido como\u00a0efeito fotoel\u00e9trico\u00a0 —\u00a0 \u00a0polariza\u00e7\u00e3o\u00a0 —\u00a0 fen\u00f4meno que evidencia a natureza ondulat\u00f3ria da luz\u00a0 —\u00a0 polarizar uma onda significa transformar, atrav\u00e9s do polarizador, uma onda transversal\u00a0 n\u00e3o polarizada,que vibra em v\u00e1rias dire\u00e7\u00f5es, numa onda polarizada, que vibra numa \u00fanica dire\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Teoria da Relatividade 01- R- A\u00a0\u00a0—\u00a0 veja teoria 02- R- D 03-\u00a0A velocidade da luz \u00e9 constante independente da velocidade da fonte emissora\u00a0 —\u00a0\u00a0R- B 04-\u00a0A velocidade da luz (ondas eletromagn\u00e9ticas) \u00e9 de 3.108m\/s independentemente de a fonte emissora estar em repouso ou em movimento\u00a0 —\u00a0\u00a0R- D 05-\u00a0I. Correta\u00a0 —\u00a0 veja teoria III.<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2510,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2514","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2514","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2514"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2514\/revisions"}],"predecessor-version":[{"id":10729,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2514\/revisions\/10729"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2510"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2514"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}