{"id":2388,"date":"2016-08-02T00:38:22","date_gmt":"2016-08-02T00:38:22","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2388"},"modified":"2024-08-23T14:41:02","modified_gmt":"2024-08-23T14:41:02","slug":"exercicios-de-vestibulares-com-resolucao-comentada-sobre-cordas-vibrantes-harmonicos","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/ondulatoria\/acustica\/cordas-vibrantes\/exercicios-de-vestibulares-com-resolucao-comentada-sobre-cordas-vibrantes-harmonicos\/","title":{"rendered":"Cordas Vibrantes &#8211; Harm\u00f4nicos"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>cordas vibrantes &#8211; Harm\u00f4nicos<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>01-(UFSCAR-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com o carro parado no congestionamento sobre o centro de um viaduto, um motorista p\u00f4de constatar que a estrutura deste estava oscilando intensa e uniformemente. Curioso, p\u00f4s-se a contar o n\u00famero de oscila\u00e7\u00f5es que estavam ocorrendo. Conseguiu contar 75 sobes e desces da estrutura no tempo de meio minuto, quando teve que abandonar a contagem devido ao rein\u00edcio lento do fluxo de carros.<\/b><\/span><\/span><\/span><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_ffb59a4c.png\" alt=\"\" width=\"445\" height=\"169\" name=\"Picture 17\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Mesmo em movimento, observou que conforme percorria lentamente a outra metade a ser transposta do viaduto, a amplitude das oscila\u00e7\u00f5es que havia inicialmente percebido gradativamente diminu\u00eda, embora mantida a mesma rela\u00e7\u00e3o com o tempo, at\u00e9 finalmente cessar na chegada em solo firme. Levando em conta essa medi\u00e7\u00e3o, pode-se concluir que a pr\u00f3xima forma estacion\u00e1ria de oscila\u00e7\u00e3o desse viaduto deve ocorrer para a freq\u00fc\u00eancia, em Hz, de<\/b><\/span><\/span><\/span><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_a3b8cadd.png\" alt=\"\" width=\"774\" height=\"21\" name=\"Picture 20\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-(PUC-PR)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Numa certa guitarra, o comprimento das cordas (entre suas extremidades fixas) \u00e9 de 0,6 m. Ao ser dedilhada, uma das cordas emite um som de freq\u00fc\u00eancia fundamental igual a 220 Hz.<\/b><\/span><\/span><\/span><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_e575b747.jpg\" alt=\"\" width=\"332\" height=\"127\" name=\"Picture 26\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Marque a proposi\u00e7\u00e3o verdadeira:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Se somente a tens\u00e3o aplicada na corda for alterada, a freq\u00fc\u00eancia fundamental n\u00e3o se altera.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) A dist\u00e2ncia entre dois n\u00f3s consecutivos \u00e9 igual ao comprimento de onda.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) O comprimento de onda do primeiro harm\u00f4nico \u00e9 de 0,6 m.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) A velocidade das ondas transversais na corda \u00e9 de 264 m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) As ondas que se formam na corda n\u00e3o s\u00e3o ondas estacion\u00e1rias.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03- (UNIFESP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura representa uma configura\u00e7\u00e3o de ondas estacion\u00e1rias produzida num laborat\u00f3rio did\u00e1tico com uma fonte oscilante.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"JUSTIFY\"><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Sendo d = 12 cm a dist\u00e2ncia entre dois n\u00f3s sucessivos, qual o comprimento de onda da onda que se propaga no fio?<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_4e1763d6.jpg\" alt=\"\" width=\"313\" height=\"175\" name=\"Picture 27\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) O conjunto P de cargas que traciona o fio tem massa m = 180 g. Sabe-se que a densidade linear do fio \u00e9\u00a0m\u00a0= 5,0.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>kg\/m. Determine a freq\u00fc\u00eancia de oscila\u00e7\u00e3o da fonte.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dados: velocidade de propaga\u00e7\u00e3o de uma onda numa corda: <\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>v = <img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_676d4ee6.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/><\/b><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>; g =10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>04-(UECE)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma corda de 90 cm \u00e9 presa por suas extremidades, em suportes fixos, como mostra a figura.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_2f4f2a71.jpg\" alt=\"\" width=\"290\" height=\"71\" name=\"Picture 28\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa que cont\u00e9m os tr\u00eas comprimentos de onda mais longos poss\u00edveis para as ondas estacion\u00e1rias nesta corda, em cent\u00edmetros.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 90, 60 e 30<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 180, 90 e 60<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 120, 90 e 60<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 120, 60 e 30<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>05-(UFPB)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura a seguir mostra uma corda de densidade linear igual a 1 g\/m, que passa por uma roldana. A sua extremidade esquerda est\u00e1 presa a um vibrador e, na extremidade direita, pendura-se um corpo de massa M<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nessa situa\u00e7\u00e3o, quando a dist\u00e2ncia L, entre o vibrador e a roldana, for 0,5 m e a vibra\u00e7\u00e3o estiver na freq\u00fc\u00eancia de 200 Hz, a corda vibrar\u00e1 no modo fundamental. Com base nesses dados, o valor de M deve ser igual a: ( g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_a995382b.jpg\" alt=\"\" width=\"341\" height=\"179\" name=\"Picture 29\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>a) 3 kg\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>b) 4 kg\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>c) 5 kg\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>d) 6 kg\u00a0\u00a0\u00a0 \u00a0\u00a0<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 7 kg<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>06-(UFPB)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma das cordas de uma harpa tem comprimento igual a 50 cm.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_ff2b66cd.jpg\" alt=\"\" width=\"119\" height=\"179\" name=\"Picture 30\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O maior comprimento de onda estacion\u00e1ria que um m\u00fasico pode estabelecer nessa corda, em cm, \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 12,5\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 25\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 50\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 100\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 200<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>07- (UFMG-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Bruna afina a corda mi de seu violino, para que ela vibre com uma freq\u00fc\u00eancia m\u00ednima de 680 Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A parte vibrante das cordas do violino de Bruna mede 35 cm de comprimento, como mostrado nesta figura:Considerando essas informa\u00e7\u00f5es,<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_aa046263.jpg\" alt=\"\" width=\"268\" height=\"156\" name=\"Picture 31\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) CALCULE a velocidade de propaga\u00e7\u00e3o de uma onda na corda mi desse violino.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Considere que a corda mi esteja vibrando com uma freq\u00fc\u00eancia de 680 Hz. DETERMINE o comprimento de onda, no ar, da onda sonora produzida por essa corda.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Velocidade do som no ar = 340 m\/s<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>08-(UFPA)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>No trabalho de restaura\u00e7\u00e3o de um antigo piano, um m\u00fasico observa que se faz necess\u00e1rio substituir uma de suas cordas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ao efetuar a troca, fixando rigidamente a corda pelas duas extremidades ao piano, ele verifica que as freq\u00fc\u00eancias de 840 Hz, 1050 Hz e 1260 Hz s\u00e3o tr\u00eas freq\u00fc\u00eancias de resson\u00e2ncias sucessivas dos harm\u00f4nicos gerados na corda. Se a velocidade de propaga\u00e7\u00e3o de uma onda transversal na corda for 210 m\/s, pode-se afirmar que o comprimento da corda, colocada no piano, em cm, \u00e9<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_7313c9b5.jpg\" alt=\"\" width=\"205\" height=\"214\" name=\"Picture 32\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 100\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 90\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c)\u00a0 30\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 50\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"> <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 30<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>09-(UFU-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma corda de um viol\u00e3o emite uma freq\u00fc\u00eancia fundamental de 440,0 Hz ao vibrar livremente, quando tocada na regi\u00e3o da boca, como mostra Figura 1.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pressiona-se ent\u00e3o a corda a L\/3 de dist\u00e2ncia da pestana, como mostra Figura 2<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_4ec2dcf1.jpg\" alt=\"\" width=\"586\" height=\"166\" name=\"Picture 33\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A freq\u00fc\u00eancia fundamental emitida pela corda pressionada, quando tocada na regi\u00e3o da boca, ser\u00e1 de:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 660,0 Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 146,6 Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 880,0 Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 293,3 Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>10-(ITA-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>S\u00e3o de 100 Hz e 125 Hz, respectivamente, as freq\u00fc\u00eancias de duas harm\u00f4nicas adjacentes de uma onda estacion\u00e1ria no trecho horizontal de um cabo esticado, de comprimento L = 2 m e densidade linear de massa igual a 10 g\/m (veja figura).<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_ad2d4e8e.jpg\" alt=\"\" width=\"192\" height=\"141\" name=\"Picture 34\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando a acelera\u00e7\u00e3o da gravidade g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, a massa do bloco suspenso deve ser de<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>a) 10 kg\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>b) 16 kg\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>c) 60 kg\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>d) 10<\/b><\/span><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>2<\/b><\/span><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0kg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0kg<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>11-(UFRN)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Afinar a corda de um instrumento musical \u00e9 ajustar a tens\u00e3o dessa corda at\u00e9 que a freq\u00fc\u00eancia de seu modo fundamental de vibra\u00e7\u00e3o coincida com uma freq\u00fc\u00eancia predeterminada. Uma forma usual de se afinar um viol\u00e3o consiste em afinar uma das \u00faltimas cordas (valendo-se de mem\u00f3ria musical ou da compara\u00e7\u00e3o com algum som padr\u00e3o, obtido por meio de um diapas\u00e3o, piano, flauta, etc.) e usar tal corda para afinar as outras que ficam abaixo dela. (A figura seguinte ilustra em detalhe o bra\u00e7o de um viol\u00e3o).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Flavita, acostumada a afinar seu viol\u00e3o, afina inicialmente a corda n\u00famero 5. Assim, para afinar a corda n\u00famero 4, ela pressiona a corda 5 entre o quarto e o quinto traste, percute-a, observa se a corda 4 vibra e o qu\u00e3o intensamente vibra em conseq\u00fc\u00eancia desse procedimento. Flavita vai ajustando a tens\u00e3o na corda 4 e repetindo tal procedimento at\u00e9 que ela vibre com a maior amplitude poss\u00edvel. Quando isso ocorre, essa corda est\u00e1 afinada.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_539bef6b.jpg\" alt=\"\" width=\"514\" height=\"158\" name=\"Picture 35\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com base no que foi exposto no enunciado, atenda \u00e0s solicita\u00e7\u00f5es seguintes.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) D\u00ea o nome do fen\u00f4meno f\u00edsico que fundamenta esse processo de afina\u00e7\u00e3o do viol\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Com base em seus conhecimentos de ac\u00fastica, explique como esse fen\u00f4meno ocorre no processo de afina\u00e7\u00e3o do viol\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>12-(UFG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Na experi\u00eancia de resson\u00e2ncia em cordas representada na figura, dois fios de densidades diferentes est\u00e3o tensionados, atrav\u00e9s de roldanas ideais, por um bloco que pende deles dois. As extremidades esquerdas de ambos est\u00e3o ligadas a uma fonte que produz pequenas vibra\u00e7\u00f5es com freq\u00fc\u00eancia conhecida. A dist\u00e2ncia entre a fonte e as roldanas \u00e9 L. Verifica-se que, quando a freq\u00fc\u00eancia da fonte atinge o valor f, ambos os fios entram em resson\u00e2ncia, o mais denso no terceiro harm\u00f4nico e o outro, na freq\u00fc\u00eancia fundamental. Dados: v =\u00a0\u00d6T\/m\u00a0&#8211; velocidade da onda na corda.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_6212498b.jpg\" alt=\"\" width=\"437\" height=\"243\" name=\"Picture 36\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Conhecendo a densidade linear de massa\u00a0m\u00a0do fio mais denso, determine a densidade linear de massa do outro fio;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>13-(UECE) Na figura as cordas A e B, de mesmo comprimento, t\u00eam densidades\u00a0m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e\u00a0m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, respectivamente, (m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt;\u00a0m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>) e est\u00e3o presas a um bloco como mostra a figura.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_a4d2a188.png\" alt=\"\" width=\"184\" height=\"181\" name=\"Picture 21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As duas cordas s\u00e3o perturbadas de tal modo que cada uma vibra em sua respectiva freq\u00fc\u00eancia fundamental. Em rela\u00e7\u00e3o \u00e0s velocidades e freq\u00fc\u00eancias nas cordas (v \u00e9 a velocidade de propaga\u00e7\u00e3o da onda e f \u00e9 a freq\u00fc\u00eancia fundamental), podemos afirmar, corretamente:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&gt;<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt;<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt;<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 e f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt;f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0&gt;V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&gt;<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt;<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e \u00a0f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&gt;f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=V<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>14- (UNIFEI-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma corda de viol\u00e3o de 64cm de comprimento emite uma nota Sol (f=392Hz) quando tocada.. Que comprimento deve ter essa mesma corda para que emita uma nota L\u00e1(f=440Hz)?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>15-(UFPE)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma corda de viol\u00e3o de 1,0m de comprimento tem massa de 20g.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando que a velocidade (V) de uma onda na corda, a tens\u00e3o (T) e a densidade linear de massa da corda (m) est\u00e3o relacionadas por <\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>v = <img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_676d4ee6.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/><\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, calcule a tens\u00e3o, em unidades de 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N, que deve ser aplicada na corda, para afina-la em d\u00f3 m\u00e9dio(260Hz), de modo que o comprimento da corda seja igual a meio comprimento de onda.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_c41c3284.jpg\" alt=\"\" width=\"336\" height=\"153\" name=\"Picture 38\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>16-(CESGRANRIO-RJ)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pit\u00e1goras j\u00e1 havia observado que duas cordas cujos comprimentos estivessem na raz\u00e3o de 1 para 2<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Soariam em un\u00edssono. Hoje sabemos que a raz\u00e3o das freq\u00fc\u00eancias dos sons emitidos por essas cordas \u00e9 igual \u00e0 raz\u00e3o inversa dos seus comprimentos. A freq\u00fc\u00eancia da nota l\u00e1-padr\u00e3o (o l\u00e1 central do piano) \u00e9 440Hz., e a freq\u00fc\u00eancia do l\u00e1 seguinte, mais agudo \u00e9 880Hz. A escala crom\u00e1tica (ou bem temperada), usada na m\u00fasica ocidental de J. S. Bach (s\u00e9culo XVIII)\u00a0 para c\u00e1, divide esse intervalo (dito de oitava) em doze semitons iguais, isto \u00e9,\u00a0 tais que a raz\u00e3o das freq\u00fc\u00eancias de notas consecutivas \u00e9 constante. Essas notas e suas respectivas freq\u00fc\u00eancias (em Hz e aproximadas para inteiros) est\u00e3o na tabela a seguir.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_f976363d.jpg\" alt=\"\" width=\"531\" height=\"209\" name=\"Picture 39\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_b184b34c.jpg\" alt=\"\" width=\"187\" height=\"104\" name=\"Picture 40\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A corda mi de um violino usado em um conjunto de m\u00fasica renascentista est\u00e1 afinada para a freq\u00fc\u00eancia de 660Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para tocar a nota l\u00e1, de freq\u00fc\u00eancia 880Hz, prende-se a corda com um dedo, de modo a utilizar apenas uma fra\u00e7\u00e3o da corda.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Que fra\u00e7\u00e3o \u00e9 essa?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>17-(UNICAMP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para a afina\u00e7\u00e3o de um piano usa-se um diapas\u00e3o com frequ\u00eancia fundamental igual a 440Hz, que \u00e9 a frequ\u00eancia\u00a0 da nota L\u00e1.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) A nota L\u00e1 de certo piano est\u00e1 desafinada e o seu harm\u00f4nico fundamental est\u00e1 representado na curva tracejada do gr\u00e1fico.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_b84ab747.jpg\" alt=\"\" width=\"401\" height=\"142\" name=\"Picture 41\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Obtenha a freq\u00fc\u00eancia da nota L\u00e1 desafinada.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) O comprimento dessa corda do piano \u00e9 igual a 1m e sua densidade linear \u00e9 igual a 5,0.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>g\/cm. Calcule o\u00a0 aumento\u00a0 de tens\u00e3o na corda necess\u00e1rio para que a nota L\u00e1 seja afinada.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>18-(FUVEST-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere uma corda de viol\u00e3o com 50cm de comprimento que est\u00e1 afinada para vibrar com frequ\u00eancia de 500Hz.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_42b5c855.jpg\" alt=\"\" width=\"275\" height=\"139\" name=\"Picture 42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Qual a velocidade de propaga\u00e7\u00e3o da onda nessa corda?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Se o comprimento da corda for reduzido \u00e0 metade, qual a nova freq\u00fc\u00eancia do som emitido?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>19-(UFPE)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ondas estacion\u00e1rias se formam numa corda de comprimento L, cujas extremidades est\u00e3o fixas. Determine a raz\u00e3o f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>n+1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\/f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>n<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, entre as freq\u00fc\u00eancias de vibra\u00e7\u00e3o de dois harm\u00f4nicos consecutivos.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>20-(CESGRANRIO-RJ)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma corda de viol\u00e3o \u00e9 mantida tensionada quando presa entre dois suportes fixos no laborat\u00f3rio. Posta a vibrar, verifica-se que a mais baixa freq\u00fc\u00eancia em que se consegue estabelecer uma onda estacion\u00e1ria na corda \u00e9 f<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=100Hz. Assim, qual das op\u00e7\u00f5es a seguir apresenta a sucess\u00e3o completa das quatro pr\u00f3ximas freq\u00fc\u00eancias poss\u00edveis para ondas estacion\u00e1rias na mesma corda, em Hz?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 150, 200, 250, 300\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 150, 250, 350, 450\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 200, 300, 400, 500\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 200, 400, 600, 800\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"> <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 300, 500,700, 900<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>21-(UFC-CE)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_2cd9eca.jpg\" alt=\"\" width=\"188\" height=\"95\" name=\"Picture 43\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Duas cordas de di\u00e2metros iguais foram constru\u00eddas de um mesmo material, uma de comprimento L<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=60cm e outra de comprimento L<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=40cm. A primeira \u00e9 submetida a uma tens\u00e3o T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=40N e a segunda, a uma tens\u00e3o T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=90N. Quando postas em<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_1835eb0e.jpg\" alt=\"\" width=\"406\" height=\"124\" name=\"Picture 44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>oscila\u00e7\u00e3o, verifica-se que a de comprimento L<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0tem frequ\u00eancia fundamental de 36Hz. A partir desses dados, determine, em Hz, para a corda L<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0a sua frequ\u00eancia fundamental.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>22-(UNIFAL-MG)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_dc459ca9.jpg\" alt=\"\" width=\"130\" height=\"98\" name=\"Picture 45\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\">\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_df26bfaf.jpg\" alt=\"\" width=\"118\" height=\"102\" name=\"Picture 46\" align=\"BOTTOM\" border=\"0\" \/>\u00a0\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_7e7c3c51.jpg\" alt=\"\" width=\"165\" height=\"105\" name=\"Picture 47\" align=\"BOTTOM\" border=\"0\" \/>\u00a0\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_3cbc53c7.jpg\" alt=\"\" width=\"152\" height=\"105\" name=\"Picture 48\" align=\"BOTTOM\" border=\"0\" \/>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_5203fceb.jpg\" alt=\"\" width=\"165\" height=\"106\" name=\"Picture 49\" align=\"BOTTOM\" border=\"0\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma corda vibrante de 50,0 cm de comprimento com densidade igual a 2,4.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0kg\/m, presa em suas<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>extremidades, e formada uma onda estacionaria apresentando um \u00fanico ventre, quando excitada por uma fonte de 1000 Hz.\u00a0Assinale a alternativa correta.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) A velocidade de propaga\u00e7\u00e3o da onda na corda e de 1000 m\/s quando a corda est\u00e1 sob uma tens\u00e3o de 240 N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) A frequ\u00eancia de vibra\u00e7\u00e3o \u00e9 diretamente proporcional ao comprimento de onda.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) A frequ\u00eancia fundamental da corda \u00e9 de 2000 Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) A velocidade de propaga\u00e7\u00e3o da onda na corda \u00e9 de 1000 m\/s e \u00e9 inversamente proporcional a tens\u00e3o na corda.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) O segundo harm\u00f4nico possui uma frequ\u00eancia de 500 Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>23-(UPE-PE)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_b55c91d9.jpg\" alt=\"\" width=\"187\" height=\"81\" name=\"Picture 50\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um pulso ondulat\u00f3rio senoidal \u00e9 produzido em uma extremidade de uma corda longa e se propaga por toda a sua extens\u00e3o.\u00a0A onda possui uma frequ\u00eancia de 50 Hz e comprimento de onda 0,5 m. O tempo que a onda leva para percorrer uma dist\u00e2ncia de 10m na corda vale em segundos:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_ae56a87c.png\" alt=\"\" width=\"775\" height=\"22\" name=\"Picture 22\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>24-(FGV-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_17b29321.jpg\" alt=\"\" width=\"449\" height=\"134\" name=\"Picture 51\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A nota l\u00e1 da escala crom\u00e1tica musical \u00e9 tida como refer\u00eancia na afina\u00e7\u00e3o dos instrumentos. No viol\u00e3o comum de 6 cordas, a quinta<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_5198f2fc.jpg\" alt=\"\" width=\"179\" height=\"174\" name=\"Picture 52\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>corda (segunda de cima para baixo), devidamente afinada, emite a nota l\u00e1 vibrando com frequ\u00eancia de 220 Hz. Se o instrumentista colocar seu dedo num traste localizado a meia dist\u00e2ncia dos extremos desta corda e percuti-la, ele ouvir\u00e1 a nota l\u00e1 vibrando com frequ\u00eancia de<\/b><\/span><\/span><\/span><\/p>\n<p><a name=\"_GoBack\"><\/a> <span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 440 Hz, mantida a velocidade de propaga\u00e7\u00e3o da onda formada.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(B) 110 Hz, mantida a velocidade de propaga\u00e7\u00e3o da onda formada.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(C) 440 Hz, com velocidade de propaga\u00e7\u00e3o da onda dobrada.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(D) 110 Hz, com velocidade de propaga\u00e7\u00e3o da onda dobrada.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(E) 440 Hz, com velocidade de propaga\u00e7\u00e3o da onda reduzida \u00e0 metade.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>25-(PUC-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um homem mant\u00e9m em equil\u00edbrio est\u00e1tico um bloco preso a uma corda de densidade linear igual a 0,01kg\/m, conforme a figura. Determine a massa M do bloco, sabendo que as frequ\u00eancias de duas harm\u00f4nicas consecutivas de uma onda estacion\u00e1ria no trecho<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/cordas\/i_469b94010b66ffa8_html_954c6c50.jpg\" alt=\"\" width=\"264\" height=\"167\" name=\"Picture 79\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>vertical de 2m da corda correspondem a 150Hz e 175Hz.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>g\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>g\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>g\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0g\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>6\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>g<\/b><\/span><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Cordas vibrantes \u2013 Harm\u00f4nicos\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/ondulatoria\/acustica\/cordas-vibrantes\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-cordas-vibrantes-harmonicos\/\"><span style=\"color: #000080;\">Confira as resolu\u00e7\u00f5es comentadas<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre cordas vibrantes &#8211; Harm\u00f4nicos \u00a0 01-(UFSCAR-SP) Com o carro parado no congestionamento sobre o centro de um viaduto, um motorista p\u00f4de constatar que a estrutura deste estava oscilando intensa e uniformemente. Curioso, p\u00f4s-se a contar o n\u00famero de oscila\u00e7\u00f5es que estavam ocorrendo. Conseguiu contar 75 sobes e desces da estrutura no tempo de<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2386,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2388","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2388","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2388"}],"version-history":[{"count":4,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2388\/revisions"}],"predecessor-version":[{"id":10898,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2388\/revisions\/10898"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2386"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2388"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}