{"id":2347,"date":"2016-08-01T23:34:26","date_gmt":"2016-08-01T23:34:26","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2347"},"modified":"2024-08-23T14:58:55","modified_gmt":"2024-08-23T14:58:55","slug":"exercicios-de-vestibulares-com-resolucoes-comentadas-sobre-tubos-sonoros","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/ondulatoria\/acustica\/tubos-sonoros\/exercicios-de-vestibulares-com-resolucoes-comentadas-sobre-tubos-sonoros\/","title":{"rendered":"Tubos Sonoros &#8211; Exerc\u00edcios"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00f5es comentadas sobre <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Tubos Sonoros<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>01-(UFPE)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura mostra uma onda estacion\u00e1ria em um tubo de comprimento L = 5 m, fechado em uma extremidade e aberto na outra.<\/b><\/span><\/span><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_213244be.jpg\" alt=\"\" width=\"366\" height=\"73\" name=\"Picture 68\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere que a velocidade do som no ar \u00e9 340 m\/s e determine a freq\u00fc\u00eancia do som emitido pelo tubo, em hertz.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-(UFG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As ondas eletromagn\u00e9ticas geradas pela fonte de um forno de microondas t\u00eam uma freq\u00fc\u00eancia bem caracter\u00edstica, e, ao serem refletidas pelas paredes internas do forno, criam um ambiente de ondas estacion\u00e1rias. O cozimento (ou esquentamento) ocorre devido ao fato de as mol\u00e9culas constituintes do alimento, sendo a de \u00e1gua a principal delas, absorverem energia dessas ondas e passarem a vibrar com a mesma freq\u00fc\u00eancia das ondas emitidas pelo tubo gerador do forno. O fen\u00f4meno f\u00edsico que explica o funcionamento do forno de microondas \u00e9 a<\/b><\/span><\/span><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_310414cd.png\" alt=\"\" width=\"774\" height=\"24\" name=\"Picture 10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03-(UFSCAR-SP<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>) No passado, quando os motoristas adentravam em um t\u00fanel, come\u00e7avam a buzinar em tom de brincadeira, pelo simples prazer de ouvir ecoar o grande ru\u00eddo produzido. Mais recentemente, engenheiros constataram que tais sons produzem ondas estacion\u00e1rias que podem afetar a estrutura dessas constru\u00e7\u00f5es.<\/b><\/span><\/span><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_f580547b.jpg\" alt=\"\" width=\"218\" height=\"140\" name=\"Picture 69\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O carro esquematizado est\u00e1 com sua buzina localizada exatamente no centro do arco que delimita o t\u00fanel, cujo di\u00e2metro \u00e9 10 m. Se a buzina emite o som da nota L\u00e1 (440 Hz), e se a velocidade de propaga\u00e7\u00e3o do som no ar \u00e9 340 m\/s, o n\u00famero de comprimentos de onda que o som percorrer\u00e1 at\u00e9 atingir o teto do t\u00fanel \u00e9, aproximadamente,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 2,5.\u00a0\u00a0\u00a0\u00a0\u00a0 b) 3,5.\u00a0\u00a0\u00a0\u00a0\u00a0 c) 4,5.\u00a0\u00a0\u00a0\u00a0\u00a0 d) 5,5.\u00a0\u00a0\u00a0\u00a0\u00a0 e) 6,5<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04-(UNICAMP-SP) <\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O ru\u00eddo sonoro nas proximidades de rodovias resulta, predominantemente, da compress\u00e3o do ar pelos pneus de ve\u00edculos que trafegam a altas velocidades. O uso de asfalto emborrachado pode reduzir significativamente esse ru\u00eddo. O gr\u00e1fico a seguir mostra duas curvas de intensidade do ru\u00eddo sonoro em fun\u00e7\u00e3o da freq\u00fc\u00eancia, uma para asfalto comum e outra para asfalto emborrachado.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) As intensidades da figura foram obtidas a uma dist\u00e2ncia r = 10 m da rodovia. Considere que a intensidade do ru\u00eddo sonoro \u00e9 dada por I = P\/4\u03c0.r<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, onde P \u00e1 a pot\u00eancia de emiss\u00e3o do ru\u00eddo.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_cce7f017.jpg\" alt=\"\" width=\"508\" height=\"202\" name=\"Picture 70\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule P na freq\u00fc\u00eancia de 1000 Hz para o caso do asfalto emborrachado.Considere\u00a0\u03c0=3<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Uma poss\u00edvel explica\u00e7\u00e3o para a origem do pico em torno de 1000 Hz \u00e9 que as ranhuras longitudinais dos pneus em contato com o solo funcionam como tubos sonoros abertos nas extremidades. O modo fundamental de vibra\u00e7\u00e3o em um tubo aberto ocorre quando o comprimento de onda \u00e9 igual ao dobro do comprimento do tubo. Considerando que a freq\u00fc\u00eancia fundamental de vibra\u00e7\u00e3o seja 1000 Hz, qual deve ser o comprimento do tubo? A velocidade de propaga\u00e7\u00e3o do som no ar \u00e9 v = 340 m\/s.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>05-(ITA-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dois tubos de \u00f3rg\u00e3o, A e B, tem o mesmo comprimento L, sendo que A \u00e9 fechado e B \u00e9 aberto. Sejam f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0as freq\u00fc\u00eancias fundamentais emitidas, respectivamente, por A e B. Designando por V a velocidade do som no ar, podemos afirmar que:<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_3d87914d.jpg\" alt=\"\" width=\"276\" height=\"146\" name=\"Picture 71\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=2 f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=V\/2L\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=V\/4L\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=4 f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) f<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=V\/4L<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>06-(UFRJ-RJ)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O grupo brasileiro Uakti constr\u00f3i seus pr\u00f3prios instrumentos musicais. Um deles consiste em v\u00e1rios canos de PVC de comprimentos variados.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_af8fd285.jpg\" alt=\"\" width=\"294\" height=\"214\" name=\"Picture 72\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma das pontas dos canos \u00e9 mantida fechada por uma membrana que emite sons caracter\u00edsticos ao ser percutida pelos artistas, enquanto a outra \u00e9 mantida aberta. Sabendo-se que o m\u00f3dulo da velocidade do som no ar vale 340 m\/s, \u00e9 correto afirmar que as duas freq\u00fc\u00eancias mais baixas emitidas por um desses tubos, de comprimento igual a 50 cm, s\u00e3o:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 170 Hz e 340 Hz\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 170 Hz e 510 Hz.\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 200 Hz e 510 Hz.\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 340 Hz e 510 Hz.\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 200 Hz e 340 Hz.<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>07-(UERJ-RJ)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O som do apito do transatl\u00e2ntico \u00e9 produzido por um tubo aberto de comprimento L igual a 7,0 m. Considere que o som no interior desse tubo propaga-se \u00e0 velocidade de 340 m\/s e que as ondas estacion\u00e1rias produzidas no tubo, quando o apito \u00e9 acionado, t\u00eam a forma representada pela figura a seguir.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Determine a freq\u00fc\u00eancia de vibra\u00e7\u00e3o das ondas sonoras no interior do tubo.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_7a4eabcf.jpg\" alt=\"\" width=\"304\" height=\"111\" name=\"Picture 73\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Admita que o navio se afaste perpendicularmente ao cais do porto onde esteve ancorado, com velocidade constante e igual a 10 n\u00f3s.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule o tempo que as ondas sonoras levam para atingir esse porto quando o tubo do apito se encontra a 9.045 m de dist\u00e2ncia.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dado: 1 n\u00f3 = 0,5 m\/s<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>08-(UNIFESP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Quando colocamos uma concha junto ao ouvido, ouvimos um &#8220;ru\u00eddo de mar&#8221;, como muita gente diz, talvez imaginando que a concha pudesse ser um gravador natural. Na verdade, esse som \u00e9 produzido por qualquer cavidade colocada junto ao ouvido &#8211; a nossa pr\u00f3pria m\u00e3o em forma de concha ou um canudo, por exemplo.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Qual a verdadeira origem desse som? Justifique.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Se a cavidade for um canudo de 0,30 m aberto nas duas extremidades, qual a freq\u00fc\u00eancia predominante desse som?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dados:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>velocidade do som no ar: v = 330 m\/s;<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>09-(UFJF-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando que a velocidade do som no ar \u00e9 igual a 340 m\/s e que o canal auditivo humano pode ser comparado a um tubo de \u00f3rg\u00e3o com uma extremidade aberta e a outra fechada, qual deveria ser o comprimento do canal auditivo para que a freq\u00fc\u00eancia fundamental de uma onda sonora estacion\u00e1ria nele produzida seja de 3400 Hz?<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_71a92874.png\" alt=\"\" width=\"774\" height=\"20\" name=\"Picture 13\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>10-(UERJ-RJ)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A press\u00e3o no ouvido interno de uma pessoa, no in\u00edcio de uma viagem subindo uma montanha, \u00e9 igual a 1,010 x 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0Pa. Admita que essa press\u00e3o n\u00e3o varie durante a viagem e que a press\u00e3o atmosf\u00e9rica no topo da montanha seja igual a 0,998 x 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0Pa.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere o t\u00edmpano como uma membrana circular com raio 0,4 cm e o canal auditivo como um tubo cil\u00edndrico de 2,8 cm de comprimento, aberto em uma extremidade e fechado, na outra, pelo t\u00edmpano.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em rela\u00e7\u00e3o ao instante de chegada dessa pessoa ao topo da montanha, quando ainda n\u00e3o foi alcan\u00e7ado novo equil\u00edbrio entre a press\u00e3o interna do ouvido e a press\u00e3o externa, calcule: (velocidade do som no ar = 340m\/s)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a for\u00e7a resultante em cada t\u00edmpano;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a freq\u00fc\u00eancia fundamental do som no interior do canal auditivo<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>11-(ITA-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um tubo sonoro de comprimento l, fechado numa das extremidades, entra em resson\u00e2ncia, no seu modo fundamental, com o som emitido por um fio, fixado nos extremos, que tamb\u00e9m vibra no modo fundamental. Sendo L o comprimento do fio, m sua massa e c, a velocidade do som no ar, pode-se determinar a tens\u00e3o a que est\u00e1 sendo submetido o fio.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>12-(ITA-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um tubo sonoro aberto em uma das extremidades e fechado na outra apresenta uma freq\u00fc\u00eancia fundamental de 200Hz. Sabendo-se que o intervalo de freq\u00fc\u00eancias aud\u00edveis \u00e9 aproximadamente de 20Hz a 16.000Hz, pode-se afirmar que\u00a0 o n\u00famero de freq\u00fc\u00eancias aud\u00edveis emitidas pelo tubo \u00e9, aproximadamente:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_dbf0c5e2.png\" alt=\"\" width=\"775\" height=\"21\" name=\"Picture 4\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>13-(CESGRANRIO-RJ)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O maior tubo do \u00f3rg\u00e3o de uma catedral tem comprimento de 10m; o tubo menor tem comprimento de 2cm. Os tubos s\u00e3o abertos, a velocidade do som no ar \u00e9 340m\/s. Quais s\u00e3o os valores extremos de freq\u00fc\u00eancias sonoras que o \u00f3rg\u00e3o pode emitir, sabendo-se que os tubos ressoam no fundamental?<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_73eb508a.jpg\" alt=\"\" width=\"331\" height=\"197\" name=\"Picture 74\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Menor freq\u00fc\u00eancia\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Maior frequ\u00eancia<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 17Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 8,5.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Hz<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 14Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a06,8.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Hz<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 17Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 3,4.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Hz<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 2,0Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 8,5.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Hz<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 2,0Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1,0.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Hz<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>14-(Funrei-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura abaixo representa tr\u00eas tubos ac\u00fasticos de comprimento D.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_12b6d82c.jpg\" alt=\"\" width=\"201\" height=\"61\" name=\"Picture 75\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_73b9b81c.jpg\" alt=\"\" width=\"191\" height=\"57\" name=\"Picture 76\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_dda54b66.jpg\" alt=\"\" width=\"229\" height=\"59\" name=\"Picture 77\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com rela\u00e7\u00e3o \u00e0s freq\u00fc\u00eancias de seus modos de vibra\u00e7\u00e3o fundamentais, \u00e9 correto afirmar que:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I =\u00a0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II =\u00a0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/sub><\/p>\n<p><sub>\u00a0<\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I =<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a02F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 4 F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 2F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/sub><\/p>\n<p><sub>\u00a0<\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 2 F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II\u00a0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=4 F<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I<\/b><\/span><\/span><\/sub><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>15-(FUVEST-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um m\u00fasico sopra a extremidade aberta de um tubo de 25cm de comprimento, fechado na outra extremidade, emitindo um som na freq\u00fc\u00eancia f=1.700Hz. A velocidade do som no ar nas condi\u00e7\u00f5es do experimento \u00e9 V=340m\/s. Dos diagramas abaixo, aquele que melhor representa a amplitude de deslocamento da onda sonora estacion\u00e1ria no tubo pelo sopro do m\u00fasico, \u00e9:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_a7462aa6.jpg\" alt=\"\" width=\"769\" height=\"193\" name=\"Picture 78\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>16-(UEA-AM)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para medir a freq\u00fc\u00eancia de uma onda sonora, utiliza-se um tubo de se\u00e7\u00e3o reta circular,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>provido de um \u00eambolo, contendo part\u00edculas leves que acompanham as vibra\u00e7\u00f5es das ondas, indicando a forma\u00e7\u00e3o de ventres e n\u00f3s. A figura abaixo mostra a situa\u00e7\u00e3o em que a posi\u00e7\u00e3o do \u00eambolo permite a forma\u00e7\u00e3o de ondas estacion\u00e1rias no interior do tubo. Considerando a velocidade do som no ar, dentro do tubo, 340m\/s e o comprimento efetivo do tubo 60cm, determine a freq\u00fc\u00eancia do som.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_620ca5cb.jpg\" alt=\"\" width=\"577\" height=\"156\" name=\"Picture 14\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>17-(UFPE)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um \u00eambolo executa um movimento oscilat\u00f3rio com pequena amplitude, ao longo de um tubo cil\u00edndrico fechado contendo ar \u00e0 press\u00e3o atmosf\u00e9rica. Qual deve ser a freq\u00fc\u00eancia de oscila\u00e7\u00e3o <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_dfff05da.jpg\" alt=\"\" width=\"466\" height=\"167\" name=\"Picture 15\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do \u00eambolo, em Hz, para que n\u00e3o haja sa\u00edda ou entrada de ar, atrav\u00e9s de dois orif\u00edcios feitos nas posi\u00e7\u00f5es indicadas na figura?\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>18-(UFES)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Na ilha Escalvada, em frente a Guarapari, existe um farol de aux\u00edlio \u00e0 navega\u00e7\u00e3o. Em um dia com muito vento, estando a porta da base e a janela do topo do farol abertas, observa-se a forma\u00e7\u00e3o de uma resson\u00e2ncia sonora com freq\u00fc\u00eancia de 30Hz no interior do farol.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_a52b81bb.jpg\" alt=\"\" width=\"217\" height=\"215\" name=\"Picture 81\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O farol pode ser considerado como um tubo ressonante de extremidades abertas. Sabendo-se que a velocidade do som no ar \u00e9 340m\/s e considerando-se que a onda estacion\u00e1ria tem tr\u00eas n\u00f3s de deslocamento, a altura do farol \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 12m\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 15m\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 17m\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 21m\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 34m<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>19- (UDESC-SC)\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dois tubos sonoros de um \u00f3rg\u00e3o t\u00eam o mesmo comprimento, um deles \u00e9 aberto e o outro fechado. O tubo \u00a0fechado emite o som<\/b><\/span><\/span><b> <\/b><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>fundamental de 500 Hz \u00e0 temperatura de 20<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C e \u00e0 press\u00e3o atmosf\u00e9rica. Dentre as frequ\u00eancias abaixo, indique a que esse tubo n\u00e3o \u00e9 capaz de emitir.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_687ffb18.jpg\" alt=\"\" width=\"287\" height=\"161\" name=\"Picture 83\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a01500 Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b)\u00a04500 Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><a name=\"_GoBack\"><\/a> <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c)\u00a01000 Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d)2500 Hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e)\u00a03500 Hz\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>20-(ITA-SP)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O tubo mais curto de um \u00f3rg\u00e3o t\u00edpico de tubos tem um comprimento de aproximadamente 7 cm. Qual \u00e9 o harm\u00f4nico mais alto na faixa aud\u00edvel, considerada como estando entre 20 Hz e 20.000 Hz, de um tubo deste comprimento aberto nas duas extremidades?<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_ba5d592f.jpg\" alt=\"\" width=\"539\" height=\"182\" name=\"Picture 85\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>21-(UNESP-SP)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_26591f23.jpg\" alt=\"\" width=\"253\" height=\"66\" name=\"Picture 86\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um aluno, com o intuito de produzir um equipamento para a feira de ci\u00eancias de sua escola, selecionou 3 tubos de PVC de cores e<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_2146f7a8.jpg\" alt=\"\" width=\"357\" height=\"244\" name=\"Picture 87\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>comprimentos diferentes, para a confec\u00e7\u00e3o de tubos sonoros. Ao bater com a m\u00e3o espalmada em uma das extremidades de cada um dos tubos, s\u00e3o produzidas ondas sonoras de diferentes frequ\u00eancias. A tabela a seguir associa a cor do tubo com a frequ\u00eancia sonora emitida por ele:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_5756c1e.jpg\" alt=\"\" width=\"408\" height=\"52\" name=\"Picture 88\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Podemos afirmar corretamente que, os comprimentos dos tubos vermelho (L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>vermelho<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>), azul (L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>azul<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>) e roxo (L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>roxo<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>), guardam a seguinte rela\u00e7\u00e3o entre si:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a<\/b><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>) L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>vermelho<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0&lt; L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>azul<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0&gt; L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>roxo<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>b) L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>vermelho<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0= L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>azul<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0= L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>roxo<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>c) L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>vermelho<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0&gt; L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>azul<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0= L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>roxo<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>. \u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>d) L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>vermelho<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0&gt; L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>azul<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0&gt; L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>roxo<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>e) L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>vermelho<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0&lt; L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>azul<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>\u00a0&lt; L<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: large;\"><b>roxo<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>22-(UNEMAT-MT)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_69ae0aea.jpg\" alt=\"\" width=\"317\" height=\"107\" name=\"Picture 89\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura abaixo representa uma onda estacion\u00e1ria que se forma em um tubo sonoro fechado.<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_45621930.jpg\" alt=\"\" width=\"776\" height=\"131\" name=\"Picture 90\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere a velocidade do som no ar igual a 340m\/s. Assinale a alternativa que representa a frequ\u00eancia do som emitido pelo tubo.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a. 680 hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b. 170 hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c. 212,5 hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d. 185,5 hz\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e. 92,5 hz<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>23-(UCB-DF)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_153eac07.jpg\" alt=\"\" width=\"697\" height=\"135\" name=\"Picture 91\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Os sons musicais podem ser produzidos pelas oscila\u00e7\u00f5es de cordas (viol\u00e3o, piano), membranas <\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_8e0d661f.jpg\" alt=\"\" width=\"766\" height=\"172\" name=\"Picture 92\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(t\u00edmpano, tambor),colunas de ar (flauta, tubos), blocos de madeira e outros corpos. Um estudante, na aula de m\u00fasica, percebeu que os ru\u00eddos de fundo de baixa intensidade da sala produziam ondas estacion\u00e1rias em um tubo de papel\u00e3o de comprimento<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>L = 50,0 cm com as duas extremidades abertas. Sendo a velocidade do som no ar dentro do tubo de 340 m\/s, qual \u00e9 a frequ\u00eancia fundamental,\u00a0 em hertz, do som produzido pelo tubo? Divida o resultado encontrado por 10 e marque na folha de respostas, desprezando, se houver, a parte decimal do resultado final.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>24-(UFPR-PR)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_5e7ebd76.jpg\" alt=\"\" width=\"552\" height=\"134\" name=\"Picture 93\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma cerca el\u00e9trica foi instalada em um muro onde existe um buraco de forma cil\u00edndrica e fechado na base, conforme representado na figura. Os fios condutores da cerca el\u00e9trica est\u00e3o fixos em ambas as extremidades e esticados sob uma tens\u00e3o de 80 N. Cada fio tem comprimento igual a 2,0 m e massa de 0,001 kg. Certo dia, algu\u00e9m tocou no fio da cerca mais pr\u00f3ximo do muro e esse fio ficou oscilando em sua frequ\u00eancia fundamental. Essa situa\u00e7\u00e3o fez com que a coluna de ar no buraco, por resson\u00e2ncia, vibrasse na mesma frequ\u00eancia do fio condutor. As paredes do buraco t\u00eam um revestimento adequado, de modo que ele age como um tubo sonoro fechado na base e aberto no topo. Considerando que a velocidade do som no ar seja de 330 m\/s e que o ar no buraco oscile no modo fundamental, assinale a alternativa que apresenta corretamente a profundidade do buraco.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/ondulatoria\/tubos\/i_466eafa41242a4a1_html_93384588.jpg\" alt=\"\" width=\"551\" height=\"196\" name=\"Picture 94\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 0,525 m.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 0,650 m.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 0,825 m.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 1,250 m.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 1,500 m.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Tubos Sonoros\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/ondulatoria\/acustica\/tubos-sonoros\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-tubos-sonoros\/\"><span style=\"color: #000080;\">Confira as resolu\u00e7\u00f5es comentadas<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00f5es comentadas sobre Tubos Sonoros \u00a0 01-(UFPE) A figura mostra uma onda estacion\u00e1ria em um tubo de comprimento L = 5 m, fechado em uma extremidade e aberto na outra. Considere que a velocidade do som no ar \u00e9 340 m\/s e determine a freq\u00fc\u00eancia do som emitido pelo tubo, em hertz. &nbsp; 02-(UFG) As ondas<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2345,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2347","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2347","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2347"}],"version-history":[{"count":5,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2347\/revisions"}],"predecessor-version":[{"id":10909,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2347\/revisions\/10909"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2345"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2347"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}