{"id":2210,"date":"2016-05-14T23:45:45","date_gmt":"2016-05-14T23:45:45","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2210"},"modified":"2024-09-02T13:43:43","modified_gmt":"2024-09-02T13:43:43","slug":"dioptro-plano-exercicios","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/optica\/optica-geometrica\/dioptro-plano\/dioptro-plano-exercicios\/","title":{"rendered":"Dioptro Plano &#8211; Exerc\u00edcios"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00f5es comentadas sobre <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Dioptro Plano<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>01- (Ufg-GO)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um ponto luminoso, encontra-se imerso na \u00e1gua em uma piscina totalmente limpa, quando visto por um observador que esteja fora da piscina (no ar) e que olha com uma inclina\u00e7\u00e3o de<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>45<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>em rela\u00e7\u00e3o ao eixo normal da superf\u00edcie da \u00e1gua, \u00e9 CORRETO afirmar que<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) o ponto luminoso parecer\u00e1 mais afastado da superf\u00edcie da \u00e1gua do que realmente est\u00e1.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(B) o ponto luminoso parecer\u00e1 mais pr\u00f3ximo da superf\u00edcie da \u00e1gua do que realmente est\u00e1.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(C) o fato de a luz estar mudando de meio n\u00e3o interfere na percep\u00e7\u00e3o visual do observador.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(D) a luz n\u00e3o ir\u00e1 conseguir passar da \u00e1gua para o ar.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(E) o ponto luminoso n\u00e3o ser\u00e1 percebido pelo observador.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-. (UFC-CE)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Uma folha de papel, com um texto impresso, est\u00e1 protegida por uma espessa placa de vidro.<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b><br \/>\nO \u00edndice de refra\u00e7\u00e3o do ar \u00e9 1,0 e o do vidro 1,5. Se a placa tiver 3 cm de espessura, a dist\u00e2ncia do topo da placa \u00e0 imagem de uma letra do texto, quando observada na vertical, \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_193f9ac5.jpg\" alt=\"\" width=\"566\" height=\"189\" name=\"graphics39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_d21c2886.png\" alt=\"\" width=\"775\" height=\"17\" name=\"Imagem 24\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03- (UFMG-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Qual a alternativa que melhor explica porque a profundidade aparente de uma piscina \u00e9 menor do que a\u00a0real?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) A luz refletida na superf\u00edcie da \u00e1gua \u00e9 perturbada pela luz refletida pelo fundo da piscina\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) A luz refletida pela superf\u00edcie da \u00e1gua sofre refra\u00e7\u00e3o no ar.\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) A luz refletida pelo fundo da piscina sofre reflex\u00e3o total na superf\u00edcie da \u00e1gua.\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) A luz refletida pelo fundo da piscina sofre refra\u00e7\u00e3o ao passar da \u00e1gua para o ar.\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) A luz \u00e9 refratada ao passar do ar para a \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>04- MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> De acordo com o desenho a seguir, consideremos para um determinado instante a seguinte situa\u00e7\u00e3o:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_30cb3ce6.jpg\" alt=\"\" width=\"425\" height=\"188\" name=\"graphics40\" align=\"BOTTOM\" border=\"0\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Admitindo-se que:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1) A seja uma andorinha que se encontra a 10m da superf\u00edcie livre do l\u00edquido;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2) P seja um peixe que se encontra a uma profundidade h da superf\u00edcie S;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3) n = 1,3 seja o \u00edndice de refra\u00e7\u00e3o absoluto da \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Podemos afirmar que:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) o peixe ver\u00e1 a andorinha s\u00f3 se estiver a 10m de profundidade;\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) o peixe ver\u00e1 a andorinha a uma altura aparente de 5,0m;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) o peixe ver\u00e1 a andorinha a uma altura aparente de 13m acima da superf\u00edcie da \u00e1gua;\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) o peixe n\u00e3o ver\u00e1 a andorinha, pois a luz n\u00e3o se propaga de um meio mais refringente para outro de\u00a0menor\u00a0refring\u00eancia\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) o peixe ver\u00e1 a andorinha a uma altura aparente de 26m<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>05-\u00a0(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um p\u00e1ssaro sobrevoa em linha reta e a baixa altitude uma piscina em cujo fundo se encontra\u00a0uma\u00a0pedra. Podemos afirmar que:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) com a piscina cheia o p\u00e1ssaro poder\u00e1 ver a pedra durante um intervalo de tempo maior do que se a piscina\u00a0estivesse vazia;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) com a piscina cheia ou vazia o p\u00e1ssaro poder\u00e1 ver a pedra durante o mesmo intervalo de tempo;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) o p\u00e1ssaro somente poder\u00e1 ver a pedra enquanto estiver voando sobre a superf\u00edcie da \u00e1gua;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) o p\u00e1ssaro, ao passar sobre a piscina, ver\u00e1 a pedra numa posi\u00e7\u00e3o mais profunda do que aquela em\u00a0que ela\u00a0realmente se encontra;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) o p\u00e1ssaro nunca poder\u00e1 ver a pedra.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>06-(UNIFESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Na figura, P representa um peixinho no interior de um aqu\u00e1rio a 13 cm de profundidade em rela\u00e7\u00e3o \u00e0 superf\u00edcie da \u00e1gua. Um garoto v\u00ea esse peixinho atrav\u00e9s da superf\u00edcie livre do aqu\u00e1rio, olhando de duas posi\u00e7\u00f5es O<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e O<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_40b77b2d.jpg\" alt=\"\" width=\"536\" height=\"205\" name=\"graphics41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sendo n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e1gua<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1,3 o \u00edndice de refra\u00e7\u00e3o da \u00e1gua e d<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1,0 o \u00edndice de refra\u00e7\u00e3o do ar, pode-se afirmar que o garoto v\u00ea o peixinho a uma profundidade de:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 10 cm, de ambas as posi\u00e7\u00f5es\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 17 cm, de ambas as posi\u00e7\u00f5es\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 10 cm em O<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e 17 cm em O<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 10 cm em O<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e a uma profundidade maior que 10 cm em O<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 10cm em O<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e a uma profundidade menor que 10cm em O<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>07-(ITA-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um pescador deixa cair uma lanterna acesa em um lago a 10.0m de profundidade.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_6be5c0d9.jpg\" alt=\"\" width=\"464\" height=\"174\" name=\"graphics42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>No fundo do lago, a lanterna emite um feixe luminoso formando um pequeno \u00e2ngulo<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>q<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>com a vertical. Considere o \u00edndice de refra\u00e7\u00e3o da \u00e1gua como 1,33 e determine a profundidade aparente h vista pelo pescador.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_e84807ca.png\" alt=\"\" width=\"775\" height=\"20\" name=\"Imagem 25\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>08-(UFU-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A profundidade de uma piscina \u00e9 tal que sua parede, revestida com azulejos quadrados de 12 cm de lado, cont\u00e9m 12 azulejos justapostos verticalmente.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um banhista, na borda da piscina, cheia de \u00e1gua (n\u00e1gua=4\/3), olhando quase perpendicularmente, ver\u00e1 a parede da piscina formada por:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 12 azulejos de 9cm de lado vertical\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 9 azulejos de 16cm de lado vertical\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 16 azulejos de 9cm de lado vertical<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 12 azulejos de 12cm de lado vertical\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 9 azulejos de 12cm de lado vertical<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>09-(UFRJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Temos dificuldade de enxergar com nitidez debaixo da \u00e1gua porque os \u00edndices de refra\u00e7\u00e3o da c\u00f3rnea e das demais estruturas do olho s\u00e3o muito pr\u00f3ximos do \u00edndice de refra\u00e7\u00e3o da \u00e1gua (n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00e1gua<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=4\/3). Por isso usamos m\u00e1scaras de mergulho, o que interp\u00f5e uma pequena camada de ar (n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1) entre a \u00e1gua e o olho.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_11767db6.jpg\" alt=\"\" width=\"536\" height=\"165\" name=\"Imagem 6\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um peixe est\u00e1 a uma dist\u00e2ncia de 2,0m de um mergulhador. Suponha o vidro da m\u00e1scara plano e de espessura desprez\u00edvel. Calcule a que dist\u00e2ncia o mergulhador v\u00ea a imagem do peixe.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>10- (UFBA-BA) Um objeto pontual P encontra-se na base de um recipiente que cont\u00e9m duas camadas de l\u00edquidos, A e B,\u00a0 com espessuras e<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=28cm e e<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=39cm. Os l\u00edquidos s\u00e3o homog\u00eaneos,\u00a0 transparentes e imisc\u00edveis. Considere o \u00edndice de<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_f2a2f7e7.png\" alt=\"\" width=\"299\" height=\"268\" name=\"Imagem 36\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>refra\u00e7\u00e3o do ar igual a 1 e os dos l\u00edquidos A e B iguais\u00a0 a 1,4 e 1,3, respectivamente. Determine a altura aparente de P, vista por um observador, olhando numa dire\u00e7\u00e3o aproximadamente perpendicular \u00e0 base do recipiente.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>11-(UFMS)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A figura mostra um jacar\u00e9, imerso na \u00e1gua, o qual avan\u00e7a lentamente com velocidade constante e horizontal, para abocanhar um pato que flutua em repouso na superf\u00edcie de um lago. Os olhos do jacar\u00e9 est\u00e3o no ponto O atr\u00e1s do ponto N que corresponde ao nariz dele. Enquanto que os olhos do pato est\u00e3o no ponto P. Considere todos esses pontos contidos no plano da p\u00e1gina. Os tr\u00eas caminhos a, b, e c, mostrados na figura, representam raios de luz que saem do ponto N (nariz do jacar\u00e9) e chegam at\u00e9 o ponto P (olhos do pato). Considere a \u00e1gua transparente, parada e mais refringente que o ar. Com rela\u00e7\u00e3o \u00e0 propaga\u00e7\u00e3o retil\u00ednea da luz, \u00e9 correto afirmar:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_22b7aa1d.jpg\" alt=\"\" width=\"672\" height=\"210\" name=\"graphics43\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(01) O caminho (c) pode representar um raio de luz que sai de N e chega at\u00e9 o ponto P.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(02) O pato v\u00ea a imagem do ponto N, mais pr\u00f3ximo que a dist\u00e2ncia real que esse ponto se encontra do dele.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(04) Como as patas do pato est\u00e3o imersas na \u00e1gua, a posi\u00e7\u00e3o da imagem das patas, vista pelo jacar\u00e9, coincide com a posi\u00e7\u00e3o real das patas na \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(08) A velocidade da luz na \u00e1gua \u00e9 maior que a velocidade da luz no ar.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(16) Para acontecer a reflex\u00e3o total de um raio de luz que sai do ponto N, e esse ponto tornar-se invis\u00edvel para o pato, o jacar\u00e9 dever\u00e1 aproximar-se do pato.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>12-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Certa m\u00e1quina fotogr\u00e1fica \u00e9 fixada a uma dist\u00e2ncia D<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>da superf\u00edcie de uma mesa, montada de tal forma a fotografar, com nitidez, um desenho em uma folha de papel que est\u00e1 sobre a mesa.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_4cbf1a39.jpg\" alt=\"\" width=\"361\" height=\"150\" name=\"Imagem 8\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_26e9225f.jpg\" alt=\"\" width=\"383\" height=\"155\" name=\"Imagem 9\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Desejando manter a folha esticada, \u00e9 colocada uma placa de vidro, com 5 cm de espessura,\u00a0 sobre a mesma.. Nessa nova situa\u00e7\u00e3o, pode-se fazer com que a fotografia continue igualmente n\u00edtida<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) aumentando D<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de menos de 5 cm\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) aumentando D<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de mais de 5 cm\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) reduzindo D<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de menos de 5 cm\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) reduzindo D<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de 5 cm\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) reduzindo D<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>de mais de 5 cm.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>13-(UFRN-RN)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um observador, quando colocado numa posi\u00e7\u00e3o adequada, pode ver o canto do recipiente como representado na figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_20773126.jpg\" alt=\"\" width=\"283\" height=\"233\" name=\"Imagem 10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Enchendo o recipiente com um l\u00edquido, o observador passa a ver a moeda que est\u00e1 colocada no centro. Qual o \u00edndice de refra\u00e7\u00e3o do l\u00edquido? Dados: sen45<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=\u221a2\/2; \u00edndice de refra\u00e7\u00e3o do ar=1,0)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_83fab28e.png\" alt=\"\" width=\"775\" height=\"18\" name=\"Imagem 38\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>14-(UNIMAR-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um observador deseja saber qual a profundidade\u00a0 em que se encontra um peixe flutuando na \u00e1gua de um tanque. Sabe-se que esse observador\u00a0 est\u00e1 olhando exatamente na posi\u00e7\u00e3o vertical, que o \u00edndice de refra\u00e7\u00e3o da \u00e1gua \u00e9 1,33, e que a dist\u00e2ncia aparente \u00e9 de 3 metros. Dentre as alternativas a seguir, assinale a correta:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a dist\u00e2ncia real \u00e9 menor que a dist\u00e2ncia aparente e vale 2,25 metros;\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a dist\u00e2ncia real \u00e9 maior e a dist\u00e2ncia aparente e vale 4,0 metros\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) a dist\u00e2ncia real \u00e9 menor que a dist\u00e2ncia aparente e vale 2,5m;\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) a dist\u00e2ncia real \u00e9 maior que a dist\u00e2ncia aparente e vale 2,5m\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) a dist\u00e2ncia real \u00e9 maior que a dist\u00e2ncia aparente e vale 4,0m\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>15-(UFSCAR)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Um canh\u00e3o de luz foi montado no fundo de um laguinho artificial. Quando o lago se encontra vazio, o feixe produzido corresponde ao representado na figura.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Quando cheio de \u00e1gua, uma vez que o \u00edndice de refra\u00e7\u00e3o da luz na \u00e1gua \u00e9 maior que no ar, o esquema que melhor representa o caminho a ser seguido pelo feixe de luz \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_30d2abc6.jpg\" alt=\"\" width=\"785\" height=\"206\" name=\"Imagem 11\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>16-(UNIRIO-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um c\u00e3o est\u00e1 diante de uma mesa, observando um peixinho dentro do aqu\u00e1rio, conforme\u00a0 representado na figura. Ao mesmo tempo, o peixinho tamb\u00e9m observa o c\u00e3o. Em rela\u00e7\u00e3o \u00e0 parede P do aqu\u00e1rio e \u00e0s dist\u00e2ncias reais, podemos afirmar que as imagens observadas por cada um dos animais obedecem \u00e0s seguintes rela\u00e7\u00f5es:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_7e9fff1f.jpg\" alt=\"\" width=\"329\" height=\"187\" name=\"Imagem 12\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) O c\u00e3o observa o olho do peixinho mais pr\u00f3ximo da parede P, enquanto o peixinho observa o olho do c\u00e3o mais distante do aqu\u00e1rio.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) O c\u00e3o observa o olho do peixinho mais distante da parede P, enquanto o peixinho observa o olho do c\u00e3o mais pr\u00f3ximo do aqu\u00e1rio.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) O c\u00e3o observa o olho do peixinho mais pr\u00f3ximo da parede P, enquanto o peixinho observa o olho do c\u00e3o mais pr\u00f3ximo do aqu\u00e1rio.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) O c\u00e3o observa o olho do peixinho mais distante da parede P, enquanto o peixinho observa o olho do c\u00e3o tamb\u00e9m mais distante do aqu\u00e1rio.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) O c\u00e3o e o peixinho observam o olho um do outro, em rela\u00e7\u00e3o \u00e0 parede P, em dist\u00e2ncias iguais \u00e0s dist\u00e2ncias reais que eles ocupam na figura.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>17-(UFSC-SC)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A m\u00e3e zelosa de um candidato, preocupada com o nervosismo do filho antes do<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>vestibular, prepara uma receita caseira de &#8220;\u00e1gua com a\u00e7\u00facar&#8221; para acalm\u00e1-lo. Sem querer, a m\u00e3e faz o filho relembrar alguns conceitos relacionados \u00e0 luz, quando o mesmo observa a colher no copo com \u00e1gua, como mostrado na figura a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sobre o fen\u00f4meno apresentado na figura acima, \u00e9 CORRETO afirmar que:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(01) a luz tem um comportamento somente de part\u00edcula.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(02) a velocidade da luz independe do meio em que se propaga.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(04) a colher parece quebrada, pois a dire\u00e7\u00e3o da propaga\u00e7\u00e3o da luz muda ao se propagar do ar para a \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_38f295b.jpg\" alt=\"\" width=\"255\" height=\"165\" name=\"Imagem 13\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(08) a velocidade da luz na \u00e1gua e no ar \u00e9 a mesma.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(16) a luz \u00e9 refratada ao se propagar do ar para a \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>18-(UFMS-MS)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um bi\u00f3logo, na tentativa de obter o comprimento de um tubar\u00e3o que est\u00e1 no interior de um grande aqu\u00e1rio de vidro, observa-o atentamente do lado externo. Em um dado instante, o tubar\u00e3o permanece em repouso na posi\u00e7\u00e3o horizontal, paralelo e a uma dist\u00e2ncia de 1 m de uma das paredes de vidro transparente do aqu\u00e1rio. Nesse momento, o bi\u00f3logo est\u00e1 a 2 m de dist\u00e2ncia dessa parede e em frente do ponto A que est\u00e1 na extremidade da barbatana caudal. O bi\u00f3logo permanece nessa mesma posi\u00e7\u00e3o e gira a cabe\u00e7a de um \u00e2ngulo de 30\u00b0 para a esquerda, e a nova linha de visada coincide com o ponto B que est\u00e1 na cabe\u00e7a do tubar\u00e3o, veja a figura. Considere o \u00edndice de refra\u00e7\u00e3o do ar e da \u00e1gua iguais a 1,0 e 1,33, respectivamente, e despreze a espessura e os efeitos de refra\u00e7\u00e3o do vidro. Com fundamentos nos fen\u00f4menos da propaga\u00e7\u00e3o da luz em meios diferentes, assinale a(s) proposi\u00e7\u00e3o(\u00f5es) CORRETA(S).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(Dados: sen 22\u00b0 = 0,37; cos 22\u00b0 = 0,93; sen 30\u00b0 = 0,50; cos 30\u00b0 = 0,87)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_b0c055c5.jpg\" alt=\"\" width=\"565\" height=\"215\" name=\"Imagem 14\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(01) A velocidade da luz vermelha \u00e9 menor que a velocidade da luz violeta na \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(02) Se o tubar\u00e3o for nadando lentamente para a esquerda e na horizontal, devido ao fen\u00f4meno de reflex\u00e3o total, a imagem da cabe\u00e7a dele, vista pelo bi\u00f3logo, desaparecer\u00e1 primeiro que a imagem da cauda dele vista pelo bi\u00f3logo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(04) O fen\u00f4meno de refra\u00e7\u00e3o da luz n\u00e3o acontece em meio dispersivo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(08) O \u00edndice de refra\u00e7\u00e3o na \u00e1gua, para a luz violeta, \u00e9 maior que o \u00edndice de refra\u00e7\u00e3o na \u00e1gua para a luz vermelha.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(16) O comprimento real do tubar\u00e3o \u00e9 menor que 1,60 m.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_71c0a917.png\" alt=\"\" width=\"774\" height=\"304\" name=\"graphics44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>20-(UDESC-SC)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_4a5e0271.jpg\" alt=\"\" width=\"228\" height=\"111\" name=\"Imagem 16\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\">\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_bbcf40a4.jpg\" alt=\"\" width=\"224\" height=\"112\" name=\"Imagem 17\" align=\"BOTTOM\" border=\"0\" \/>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_fffc9997.jpg\" alt=\"\" width=\"225\" height=\"113\" name=\"Imagem 18\" align=\"BOTTOM\" border=\"0\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um bast\u00e3o \u00e9 colocado sequencialmente em tr\u00eas recipientes com l\u00edquidos diferentes. Olhando-se o bast\u00e3o atrav\u00e9s de cada recipiente, observam-se as imagens I, II e III, conforme ilustra\u00e7\u00e3o a seguir, pois os l\u00edquidos s\u00e3o transparentes. Sendo n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>os \u00edndices de refra\u00e7\u00e3o do ar, do l\u00edquido em I, do l\u00edquido em II e do l\u00edquido em III, respectivamente, a rela\u00e7\u00e3o que est\u00e1 correta \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_28448ee.jpg\" alt=\"\" width=\"481\" height=\"154\" name=\"Imagem 19\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&gt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&gt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&gt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&gt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&lt; n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>21-(FUVEST-SP)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_cdf2bd1e.jpg\" alt=\"\" width=\"259\" height=\"66\" name=\"Imagem 20\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um jovem pesca em uma lagoa de \u00e1gua transparente, utilizando, para isto, uma lan\u00e7a. Ao enxergar um peixe, ele atira sua lan\u00e7a na dire\u00e7\u00e3o em que o observa. O jovem est\u00e1 fora da \u00e1gua e o peixe est\u00e1 1 m abaixo da superf\u00edcie. A lan\u00e7a atinge a \u00e1gua a uma<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_c379c12c.jpg\" alt=\"\" width=\"308\" height=\"184\" name=\"Imagem 21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dist\u00e2ncia x = 90 cm da dire\u00e7\u00e3o vertical em que o peixe se encontra, como ilustra a figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_1883718a.jpg\" alt=\"\" width=\"309\" height=\"193\" name=\"Imagem 22\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para essas condi\u00e7\u00f5es, determine:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) O \u00e2ngulo \u03b1, de incid\u00eancia na superf\u00edcie da \u00e1gua, da luz refletida pelo peixe.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) O \u00e2ngulo \u03b2 que a lan\u00e7a faz com a superf\u00edcie da \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) A dist\u00e2ncia y, da superf\u00edcie da \u00e1gua, em que o jovem enxerga o peixe.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_989c4ce4.jpg\" alt=\"\" width=\"606\" height=\"165\" name=\"Imagem 23\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>22-(UFF-RJ-012)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_14d2d87f.jpg\" alt=\"\" width=\"552\" height=\"122\" name=\"graphics45\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O fen\u00f4meno de reflex\u00e3o interna pode ser usado para medir o \u00edndice de refra\u00e7\u00e3o da \u00e1gua de uma forma simples. A figura representa, esquematicamente, um rel\u00f3gio imerso em \u00e1gua. Com a luz de um laser incidindo perperdicularmente sobre a superf\u00edcie da \u00e1gua e variando-se o \u00e2ngulo \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, a partir do qual ocorre reflex\u00e3o total do raio na interface entre o vidro e o ar.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_97b2264b.jpg\" alt=\"\" width=\"453\" height=\"267\" name=\"graphics46\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Obtenha o \u00edndice de refra\u00e7\u00e3o da \u00e1gua em fun\u00e7\u00e3o de \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, considerando que o \u00edndice de refra\u00e7\u00e3o do ar \u00e9 aproximadamente igual a 1.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3.10 b) Calcule a velocidade da luz na \u00e1gua, sabendo que a velocidade da luz no v\u00e1cuo \u00e9 c \u2248<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>km\/s e que o \u00e2ngulo cr\u00edtico \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 48,6<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>23-\u00a0(ENEM-MEC)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_ce7bce35.jpg\" alt=\"\" width=\"257\" height=\"120\" name=\"graphics47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Alguns povos ind\u00edgenas ainda preservam suas tradi\u00e7\u00f5es realizando a pesca com lan\u00e7as, <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_932dfc40.jpg\" alt=\"\" width=\"418\" height=\"216\" name=\"graphics48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>demonstrando uma not\u00e1vel habilidade. Para fisgar um peixe em um lago com \u00e1guas tranquilas o \u00edndio deve mirar abaixo da posi\u00e7\u00e3o em que enxerga o peixe, Ele deve proceder dessa forma porque os raios de luz:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) refletidos pelo peixe n\u00e3o descrevem uma trajet\u00f3ria retil\u00ednea no interior da \u00e1gua.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) emitidos pelos olhos do \u00edndio desviam sua trajet\u00f3ria quando passam do ar para a \u00e1gua.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) espalhados pelo peixe s\u00e3o refletidos pela superf\u00edcie da \u00e1gua.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) emitidos pelos olhos s\u00e3o espalhados pela superf\u00edcie da \u00e1gua.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) refletidos pelo peixe desviam sua trajet\u00f3ria quando passam da \u00e1gua para o ar.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>24-(FUVEST-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_a1526dd0.png\" alt=\"\" width=\"474\" height=\"125\" name=\"Imagem 28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Numa folha de papel num plano horizontal, est\u00e1 desenhado um c\u00edrculo de centro C. Sobre a folha \u00e9 colocada uma placa grossa de vidro, cobrindo metade do c\u00edrculo. A figura a seguir mostra uma pessoa olhando para o c\u00edrculo, com seu olho no eixo vertical OC.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_4c41b9ae.png\" alt=\"\" width=\"531\" height=\"197\" name=\"Imagem 29\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A alternativa que melhor representa o que a pessoa enxerga \u00e9:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/dioptro\/i_f6760d5daed816fd_html_c927af4e.png\" alt=\"\" width=\"779\" height=\"251\" name=\"Imagem 30\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Dioptro Plano\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/optica\/optica-geometrica\/dioptro-plano\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-dioptro-plano\/\"><span style=\"color: #000080;\">Confira a resolu\u00e7\u00e3o comentada dos exerc\u00edcios e gabaritos<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00f5es comentadas sobre Dioptro Plano \u00a0 01- (Ufg-GO) Um ponto luminoso, encontra-se imerso na \u00e1gua em uma piscina totalmente limpa, quando visto por um observador que esteja fora da piscina (no ar) e que olha com uma inclina\u00e7\u00e3o de 45o\u00a0em rela\u00e7\u00e3o ao eixo normal da superf\u00edcie da \u00e1gua, \u00e9 CORRETO afirmar que (A) o ponto luminoso<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2208,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2210","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2210","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2210"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2210\/revisions"}],"predecessor-version":[{"id":10932,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2210\/revisions\/10932"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2208"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2210"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}