{"id":2201,"date":"2016-05-14T23:31:44","date_gmt":"2016-05-14T23:31:44","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2201"},"modified":"2024-09-02T14:33:38","modified_gmt":"2024-09-02T14:33:38","slug":"reflexao-total-exercicios","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/optica\/optica-geometrica\/reflexao-total\/reflexao-total-exercicios\/","title":{"rendered":"Reflex\u00e3o Total &#8211; Exerc\u00edcios"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00f5es comentadas sobre <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Reflex\u00e3o Total<\/b><\/span><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01-(PUC-PR)<\/b><\/span><\/span><\/span><b> <\/b><\/p>\n<p><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_9d19e70a.png\" alt=\"\" width=\"333\" height=\"202\" name=\"Imagem 2\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura mostra um arranjo experimental. No fundo do vaso, uma fonte pontual emite um raio que se desloca na \u00e1gua e atinge a superf\u00edcie di\u00f3ptrica.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando o \u00e2ngulo \u03b8 como \u00e2ngulo limite, o raio emergente \u00e9 o raio:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) IV\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) I\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) II\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) III<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-(PUCCAMP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pesquisadores da Funda\u00e7\u00e3o Osvaldo Cruz desenvolveram um sensor a laser capaz de detectar bact\u00e9rias no ar em at\u00e9 5 horas, ou seja, 14 vezes mais r\u00e1pido do que o m\u00e9todo tradicional. O equipamento, que aponta a presen\u00e7a de microorganismos por meio de uma fibra \u00f3ptica, pode se tornar um grande aliado no combate \u00e0s infec\u00e7\u00f5es hospitalares.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(Adaptado de Karine Rodrigues. http:www.estad\u00e3o.com.br\/ci\u00eancia\/not\u00edcias\/20 4\/julho\/15)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A transmiss\u00e3o de raios laser atrav\u00e9s de uma fibra \u00f3ptica \u00e9 poss\u00edvel devido ao fen\u00f4meno da<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) refra\u00e7\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) difra\u00e7\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) polariza\u00e7\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) interfer\u00eancia.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) reflex\u00e3o total.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03-(Ufg-GO)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Deseja-se realizar uma experi\u00eancia de reflex\u00e3o total na interface entre dois l\u00edquidos <\/b><\/span><\/span><\/span><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_239fe1fb.png\" alt=\"\" width=\"534\" height=\"277\" name=\"Imagem 110\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>imisc\u00edveis, usando um feixe de luz monocrom\u00e1tica que incide de cima para baixo, como ilustrado na figura 1.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Disp\u00f5e-se dos seguintes l\u00edquidos, conforme figura 2:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com base nesses dados, pode-se concluir que os l\u00edquidos A e B s\u00e3o, respectivamente,<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 1 e 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 1 e 3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 2 e 3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 1 e 4\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 3 e 4<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>04-(UNIFAP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As fibras \u00f3pticas conectam v\u00e1rios continentes, conduzindo ondas eletromagn\u00e9ticas que transmitem um grande volume de informa\u00e7\u00e3o na forma de imagem, voz e dados.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabendo que a luz do laser \u00e9 usada para carregar a informa\u00e7\u00e3o \u201ccanalizada\u201d em uma fibra de vidro, obtenha o(s) valor(es) num\u00e9rico(s) associado(s) \u00e0(s) proposi\u00e7\u00e3o(\u00f5es) VERDADEIRA(S).<\/b><\/span><\/span><\/span><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_e0f30ff1.jpg\" alt=\"\" width=\"317\" height=\"172\" name=\"Imagem 40\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(01) O princ\u00edpio de Arquimedes explica o funcionamento das fibras \u00f3pticas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(02) A reflex\u00e3o interna total independe do \u00e2ngulo de incid\u00eancia do raio de luz no interior da fibra de vidro.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(04) O comprimento de onda da luz do laser, quando passa de um meio para outro meio, n\u00e3o varia.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(08) A lei da reflex\u00e3o interna total explica as reflex\u00f5es dos raios de luz no interior da fibra de vidro<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>05- (MACKENZIE-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um raio de luz monocrom\u00e1tica, que se propaga em um meio de \u00edndice de refra\u00e7\u00e3o 2, atinge a superf\u00edcie que separa esse meio do ar (\u00edndice de refra\u00e7\u00e3o = 1). O raio luminoso passar\u00e1 para o ar se o seu \u00e2ngulo de incid\u00eancia nessa superf\u00edcie for:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) igual a 45\u00b0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) maior que 30<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) menor que 30\u00b0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) maior que 60\u00b0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) menor que 60\u00b0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>06-(Ufrs-RS)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A figura a seguir representa um raio de luz monocrom\u00e1tica que incide sobre a superf\u00edcie de separa\u00e7\u00e3o de dois meios transparentes. Os \u00e2ngulos formados pelo raio incidente e pelo raio refratado com a normal \u00e0 superf\u00edcie s\u00e3o designados por \u03b1 e \u03b2, respectivamente.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_40642a2e.jpg\" alt=\"\" width=\"364\" height=\"125\" name=\"Imagem 41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Nesse caso, afirmar que o \u00e2ngulo-limite para a reflex\u00e3o total da luz entre os meios 1 e 2 \u00e9 de 48\u00b0 significa dizer que ocorrer\u00e1 reflex\u00e3o total se<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 48\u00b0 &lt; \u03b1 &lt; 90\u00b0.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 24\u00b0 &lt; \u03b1 &lt; 48\u00b0.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 0\u00b0 &lt; \u03b1 &lt; 24\u00b0. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d) 48\u00b0 &lt; \u03b2 &lt; 90\u00b0.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 0\u00b0 &lt; \u03b2 &lt; 48\u00b0.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>07-(Ufu-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um recipiente aberto, conforme a figura 1, cont\u00e9m um l\u00edquido de \u00edndice de refra\u00e7\u00e3o n(t), que varia com o tempo (t) de acordo com a express\u00e3o n(t) = n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> (1 + e<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-bt<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0), em que b \u00e9 uma constante positiva e n ar \u00e9 o \u00edndice de refra\u00e7\u00e3o do ar.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Quando a luz passa do l\u00edquido para o ar, \u00e9 poss\u00edvel ocorrer o fen\u00f4meno de reflex\u00e3o total para um \u00e2ngulo de incid\u00eancia maior do que um certo \u00e2ngulo limite, \u2018limite (que \u00e9 medido em rela\u00e7\u00e3o \u00e0 normal). Assinale a alternativa que melhor descreve a varia\u00e7\u00e3o do seno do \u00e2ngulo limite (sen \u2018limite) em fun\u00e7\u00e3o do tempo.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_a382c3b7.jpg\" alt=\"\" width=\"771\" height=\"167\" name=\"Imagem 42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>08-(UNESP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um prisma de vidro imerso em \u00e1gua, com a face AB perpendicular \u00e0 face BC, e a face AC com uma inclina\u00e7\u00e3o de 45\u00b0 em rela\u00e7\u00e3o a AB, \u00e9 utilizado para desviar um feixe de luz monocrom\u00e1tico. O feixe penetra perpendicularmente \u00e0 face AB, incidindo na face AC com \u00e2ngulo de incid\u00eancia de 45\u00b0. O \u00e2ngulo limite para a ocorr\u00eancia de reflex\u00e3o total na face AC \u00e9 60\u00b0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_9b7d357a.jpg\" alt=\"\" width=\"282\" height=\"180\" name=\"Imagem 43\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considerando que o \u00edndice de refra\u00e7\u00e3o do vidro \u00e9 maior que o da \u00e1gua, a trajet\u00f3ria que melhor representa o raio emergente \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_6d36f3ff.png\" alt=\"\" width=\"774\" height=\"17\" name=\"Imagem 111\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>09-(UFU-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um raio de luz incide, de uma regi\u00e3o que cont\u00e9m ar (\u00edndice de refra\u00e7\u00e3o n = 1,0), em uma placa de vidro de \u00edndice de refra\u00e7\u00e3o n = 1,5, com um \u00e2ngulo de incid\u00eancia igual a 30\u00b0, atravessando-a e perfazendo a trajet\u00f3ria AB da figura a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_895b3535.jpg\" alt=\"\" width=\"404\" height=\"198\" name=\"Imagem 44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ap\u00f3s atravessar a placa de vidro, o raio passa por uma regi\u00e3o que cont\u00e9m um l\u00edquido sem sofrer desvio, seguindo a trajet\u00f3ria BC da figura acima, atingindo a superf\u00edcie de separa\u00e7\u00e3o do l\u00edquido com o ar (ponto C da figura).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dados:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Velocidade da luz no v\u00e1cuo: c = 3,0 \u00d7 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>8<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>sen19,5\u00b0 = 1\/3\u00a0\u00a0\u00a0\u00a0\u00a0 sen30\u00b0 =1\/2\u00a0\u00a0\u00a0\u00a0\u00a0 sen41,8\u00b0 = 2\/3\u00a0\u00a0\u00a0\u00a0\u00a0 sen70,5\u00b0 = 0,94<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>Determine:<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) o \u00edndice de refra\u00e7\u00e3o do l\u00edquido.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a velocidade da luz no interior do vidro (percurso AB).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) se o raio de luz emergir\u00e1 do l\u00edquido para o ar no ponto C, justificando sua resposta.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>10-(UNIFESP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um raio de luz monocrom\u00e1tica prov\u00e9m de um meio mais refringente e incide na superf\u00edcie de separa\u00e7\u00e3o com outro meio menos refringente. \u00b4<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sendo ambos os meios transparentes, pode-se afirmar que esse raio,<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) dependendo do \u00e2ngulo de incid\u00eancia, sempre sofre refra\u00e7\u00e3o, mas pode n\u00e3o sofrer reflex\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) dependendo do \u00e2ngulo de incid\u00eancia, sempre sofre reflex\u00e3o, mas pode n\u00e3o sofrer refra\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) qualquer que seja o \u00e2ngulo de incid\u00eancia, s\u00f3 pode sofrer refra\u00e7\u00e3o, nunca reflex\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) qualquer que seja o \u00e2ngulo de incid\u00eancia, s\u00f3 pode sofrer reflex\u00e3o, nunca refra\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) qualquer que seja o \u00e2ngulo de incid\u00eancia, sempre sofre refra\u00e7\u00e3o e reflex\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>11-(UEL-PR)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As fibras \u00f3pticas s\u00e3o largamente utilizadas nas telecomunica\u00e7\u00f5es para a transmiss\u00e3o de dados. Nesses materiais, os sinais s\u00e3o transmitidos de um ponto ao outro por meio de feixes de luz que se propagam no interior da fibra, acompanhando sua curvatura.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_138573e9.jpg\" alt=\"\" width=\"360\" height=\"187\" name=\"Imagem 45\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A raz\u00e3o pela qual a luz pode seguir uma trajet\u00f3ria n\u00e3o retil\u00ednea na fibra \u00f3ptica \u00e9 consequ\u00eancia do fen\u00f4meno que ocorre quando da passagem de um raio de luz de um meio, de \u00edndice de refra\u00e7\u00e3o maior, para outro meio, de \u00edndice de refra\u00e7\u00e3o menor. Com base no texto e nos conhecimento sobre o tema, assinale a alternativa que apresenta os conceitos \u00f3pticos necess\u00e1rios para o entendimento da propaga\u00e7\u00e3o &#8220;n\u00e3o retil\u00ednea&#8221; da luz em fibras \u00f3pticas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Difra\u00e7\u00e3o e foco.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Reflex\u00e3o total e \u00e2ngulo limite.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Interfer\u00eancia e difra\u00e7\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Polariza\u00e7\u00e3o e plano focal.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) Imagem virtual e foco.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>12-(UNIFESP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A fibra \u00f3ptica possibilita o transporte da luz ou de outra radia\u00e7\u00e3o eletromagn\u00e9tica, confinando esses raios, por meio da reflex\u00e3o total, entre o n\u00facleo e a casca da fibra. H\u00e1 v\u00e1rios tipos de fibras \u00f3pticas. A figura abaixo representa um deles.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_39d39e43.jpg\" alt=\"\" width=\"428\" height=\"179\" name=\"Imagem 46\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Tr\u00eas fatores s\u00e3o relevantes para o estudo desse tipo de fibra \u00f3ptica: o \u00e2ngulo de recep\u00e7\u00e3o (\u03b8) com que o raio de luz incide no n\u00facleo da fibra e que \u00e9 igual \u00e0 metade do \u00e2ngulo de capta\u00e7\u00e3o, o \u00edndice de refra\u00e7\u00e3o do n\u00facleo ( n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>n<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0) e o \u00edndice de refra\u00e7\u00e3o da casca ( n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0). Neste caso s\u00e3o dados:\u00a0\u00a0\u00a0q=48,6<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>,\u00a0 n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>n<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1,50\u00a0 e\u00a0 n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1,30<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Complete na figura abaixo a trajet\u00f3ria do raio de luz que incide na fibra dentro do cone de capta\u00e7\u00e3o, penetra no n\u00facleo da mesma e que se reflita pelo menos duas vezes na superf\u00edcie interior da casca com \u00e2ngulo de incid\u00eancia ( i\u2019 ) e de reflex\u00e3o ( i\u2019 ).\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_899e1575.jpg\" alt=\"\" width=\"779\" height=\"162\" name=\"Imagem 47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Determine o valor do \u00e2ngulo de refra\u00e7\u00e3o ( r ) no interior do n\u00facleo da fibra quando o raio de luz incidir na mesma com \u00e2ngulo\u00a0\u03b8=48,6<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, tal que sen\u03b8=0,75.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Qual \u00e9 o valor de i\u2019?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Explique o motivo de o raio de luz sofrer reflex\u00e3o total no interior da fibra considerando sen60<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=0,88603 e sen59=0,86666.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>13-(PUC-RS)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As fibras \u00f3ticas s\u00e3o muito utilizadas para guiar feixes de luz por um determinado trajeto. A estrutura b\u00e1sica dessas fibras \u00e9 constitu\u00edda por cilindros conc\u00eantricos com \u00edndices de refra\u00e7\u00e3o diferentes, para que ocorra o fen\u00f4meno da reflex\u00e3o interna total. O centro da fibra \u00e9 denominado de n\u00facleo, e a regi\u00e3o externa \u00e9 denominada de casca.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Para que ocorra o fen\u00f4meno da reflex\u00e3o interna total numa fibra \u00f3tica, o \u00e2ngulo cr\u00edtico de incid\u00eancia da luz em rela\u00e7\u00e3o \u00e0 dire\u00e7\u00e3o normal \u00e9 _________, e o \u00edndice de refra\u00e7\u00e3o do n\u00facleo deve ser _________ \u00edndice de refra\u00e7\u00e3o da casca.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A alternativa correta que preenche a afirmativa \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) menor do que 90\u00b0 &#8211; igual ao\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) menor do que 90\u00b0 &#8211; menor do que o\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) igual a 90\u00b0 &#8211; menor do que o<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) menor do que 90\u00b0 &#8211; maior do que o\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) igual a 90\u00b0 &#8211; maior do que o<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>14-(UFRJ-RJ) <\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma l\u00e2mina homog\u00eanea de faces paralelas \u00e9 constitu\u00edda de um material com \u00edndice de refra\u00e7\u00e3o n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 1,5. De um lado da l\u00e2mina, h\u00e1 um meio homog\u00eaneo de \u00edndice de refra\u00e7\u00e3o n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 2,0; do outro lado, h\u00e1 ar, cujo \u00edndice de refra\u00e7\u00e3o n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0consideramos igual a 1,0.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um raio luminoso proveniente do primeiro meio incide sobre a l\u00e2mina com \u00e2ngulo de incid\u00eancia \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, como indica a figura.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_e0a650a2.jpg\" alt=\"\" width=\"240\" height=\"124\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule o valor de \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0a partir do qual o raio que atravessa a l\u00e2mina sofre reflex\u00e3o total na interface com o ar.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>15-(UFV)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um enfeite de Natal \u00e9 constitu\u00eddo por cinco pequenas l\u00e2mpadas iguais e monocrom\u00e1ticas, ligadas em s\u00e9rie atrav\u00e9s de um fio esticado de comprimento 5L. Uma das pontas do fio est\u00e1 presa no centro de um disco de madeira, de raio R, que flutua na \u00e1gua de uma piscina. A outra ponta do fio est\u00e1 presa no fundo da piscina, juntamente com uma das l\u00e2mpadas, conforme representado na figura adiante.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Durante a noite, quando as l\u00e2mpadas s\u00e3o acesas, um observador fora da piscina v\u00ea o brilho de apenas tr\u00eas das cinco l\u00e2mpadas. Sabendo que o \u00edndice de refra\u00e7\u00e3o da \u00e1gua e o do ar s\u00e3o, respectivamente, n(H) e n(ar), pergunta-se:<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_6fac0998.jpg\" alt=\"\" width=\"400\" height=\"183\" name=\"Imagem 50\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Qual \u00e9 o fen\u00f4meno que impede a visualiza\u00e7\u00e3o das l\u00e2mpadas?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Qual par de l\u00e2mpadas n\u00e3o \u00e9 vis\u00edvel?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Qual \u00e9 a rela\u00e7\u00e3o entre R, L, n(H) e n(ar) para que duas das l\u00e2mpadas n\u00e3o sejam vis\u00edveis?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>16-(Ufg)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com a finalidade de obter um efeito visual, atrav\u00e9s da propaga\u00e7\u00e3o da luz em meios homog\u00eaneos, colocou-se dentro de um aqu\u00e1rio um prisma triangular feito de vidro crown, conforme mostra a figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_2b3e51ae.jpg\" alt=\"\" width=\"497\" height=\"276\" name=\"Imagem 51\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um feixe de luz violeta, ap\u00f3s refratar-se na parede do aqu\u00e1rio, incidiu perpendicularmente sobre a face A do prisma, atingindo a face B.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com base nesses dados e conhecidos os \u00edndices de refra\u00e7\u00e3o do prisma e do l\u00edquido, respectivamente, 1,52 e 1,33, conclui-se que o efeito obtido foi um feixe de luz emergindo da face<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) B, por causa da refra\u00e7\u00e3o em B\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b)\u00a0 C, por causa da reflex\u00e3o total em B\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) B, por causa da reflex\u00e3o total em B e em C.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) C, por causa da reflex\u00e3o em B e seguida de refra\u00e7\u00e3o em C\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) A, por causa das reflex\u00f5es em B e em C, e refra\u00e7\u00e3o em A<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>17-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um raio luminoso incide sobre um cubo de vidro, colocado no ar (n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1), como mostra a figura ao lado.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O \u00edndice de refra\u00e7\u00e3o do vidro, para que haja internamente reflex\u00e3o total na face A, deve ser:<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_ae00faf9.jpg\" alt=\"\" width=\"235\" height=\"172\" name=\"Imagem 52\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dado: sen 45<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0=\u00a0<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_bb472a70.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/> \/2<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) n\u00a0&gt;\u00a0<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_bb472a70.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) n&lt;\u00a0<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_c26018b8.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c)\u00a0 n&gt;<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_c26018b8.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) n&lt;\u00a0<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_261e45fe.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e)\u00a0 n&gt;<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_dceb3c27.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/><\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>18-(UERJ-RJ)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um raio de luz, deslocando-se no ar, incide em um dos extremos de uma fibra \u00f3ptica F de \u00edndice de refra\u00e7\u00e3o n=<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_bb472a70.gif\" alt=\"\" align=\"ABSMIDDLE\" hspace=\"8\" \/>, a um \u00e2ngulo de incid\u00eancia\u00a0\u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0e penetra na fibra a um \u00e2ngulo\u00a0\u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=30<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, conforme figura. (n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1).<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_e442523f.jpg\" alt=\"\" width=\"577\" height=\"151\" name=\"Imagem 53\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) calcule o \u00e2ngulo de incid\u00eancia\u00a0\u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"> <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Prove que o raio de luz, por reflex\u00e3o total, permanece completamente no interior da fibra.\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>19- (UNICAMP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ao vermos miragens, somos levados a pensar que h\u00e1 \u00e1gua no ch\u00e3o de estradas. O que vemos \u00e9, na verdade, a reflex\u00e3o da luz do c\u00e9u por uma camada de ar quente pr\u00f3xima ao solo. Isso pode ser explicado por um modelo simplificado como o da figura abaixo, onde n representa o \u00edndice de refra\u00e7\u00e3o. Numa camada pr\u00f3xima ao solo, o ar \u00e9 aquecido, diminuindo assim seu \u00edndice de refra\u00e7\u00e3o n.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere a situa\u00e7\u00e3o na qual o \u00e2ngulo de incid\u00eancia \u00e9 de 84\u00b0. Adote n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 1,010 e use a aproxima\u00e7\u00e3o sen 84\u00b0 = 0,995.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Qual deve ser o m\u00e1ximo valor de n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0para que a miragem seja vista? D\u00ea a resposta com tr\u00eas casas decimais.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_30e457ae.jpg\" alt=\"\" width=\"505\" height=\"89\" name=\"Imagem 54\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Em qual das camadas (1 ou 2) a velocidade da luz \u00e9 maior?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>20-(UNIUBE-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em dias de muito calor, nas estradas, temos a impress\u00e3o de que ela se\u00a0 apresenta molhada, devido ao fen\u00f4meno de:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) reflex\u00e3o total, pois a camada de ar junto ao leito da estrada, estando mais quente que as camadas superiores apresentam \u00edndice de refra\u00e7\u00e3o maior.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) ) reflex\u00e3o total, pois a camada de ar junto ao leito da estrada, estando mais quente que as camadas superiores apresentam \u00edndice de refra\u00e7\u00e3o menor.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) reflex\u00e3o total, pois a camada de ar junto ao leito da estrada, estando mais quente que as camadas superiores tornam-se mais densas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) refra\u00e7\u00e3o total, pois a camada de ar junto ao leito da estrada, estando mais quente que as camadas superiores tornam-se mais refringentes.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) refra\u00e7\u00e3o total, pois a camada de ar junto ao leito da estrada, estando mais quente que as camadas superiores tornam-se menos refringentes.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>21-(UFF-RJ)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em meados do s\u00e9culo XX, pesquisadores come\u00e7aram a sugerir a utiliza\u00e7\u00e3o de guias para conduzir a luz. Em 1970, isso foi conseguido\u00a0com um fio muito fino de fibra de vidro (n\u00facleo) revestido por outro material, escolhido de modo a permitir\u00a0 que a luz fosse totalmente refletida ao longo do fio. Dessa forma, obteve-se o que atualmente \u00e9 conhecido como fibra \u00f3ptica.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Suponha que um feixe laser penetre no n\u00facleo de uma fibra \u00f3ptica a partir do ar, fazendo um \u00e2ngulo\u00a0\u03b8\u00a0com o eixo, conforme indicado na figura.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_86c9904.jpg\" alt=\"\" width=\"413\" height=\"168\" name=\"Imagem 55\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0 <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dados:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00cdndice de refra\u00e7\u00e3o do revestimento = 1,52\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00cdndice de refra\u00e7\u00e3o do vidro = 1,60\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00cdndice de refra\u00e7\u00e3o do ar = 1,00<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule o maior valor de\u00a0q\u00a0que possibilita a propaga\u00e7\u00e3o do feixe ao longo da fibra.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>22-(PUC-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O fato de um brilhante (diamante lapidado)\u00a0 apresentar maior brilho do que sua imita\u00e7\u00e3o, feita de vidro, \u00e9 devido:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0\u00a0ao \u00e2ngulo limite do diamante ser maior que o do vidro.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b)\u00a0ao comprimento de onda da luz no vidro ser menor que no diamante.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c)\u00a0ao \u00edndice de refra\u00e7\u00e3o do diamante ser maior do que o do vidro<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d)\u00a0ao vidro n\u00e3o oferecer bom polimento<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e)\u00a0a n\u00e3o se poder lapidar um vidro com a mesma geometria permitida pelo diamante<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>23-(UNIFESP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dois raios de luz, um vermelho (v) e outro azul (a), incidem perpendicularmente em pontos diferentes da face AB de um prisma transparente imerso no ar. No interior do prisma, o \u00e2ngulo limite de incid\u00eancia na face AC \u00e9 44\u00b0 para o raio azul e 46\u00b0 para o vermelho. A figura que mostra corretamente as trajet\u00f3rias desses dois raios \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_94c868f2.jpg\" alt=\"\" width=\"775\" height=\"169\" name=\"Imagem 56\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>24- (ENEM-MEC)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_6ec6e37b.jpg\" alt=\"\" width=\"155\" height=\"101\" name=\"Imagem 57\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As ondas eletromagn\u00e9ticas, como a luz vis\u00edvel e as ondas de r\u00e1dio, viajam em linha reta em um meio homog\u00eaneo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ent\u00e3o, as ondas de r\u00e1dio emitidas na regi\u00e3o litor\u00e2nea do Brasil n\u00e3o alcan\u00e7ariam a regi\u00e3o amaz\u00f4nica do Brasil por causa da curvatura da Terra. Entretanto sabemos que \u00e9 poss\u00edvel transmitir ondas de r\u00e1dio entre essas localidades devido \u00e0 ionosfera.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_144a6cd.jpg\" alt=\"\" width=\"334\" height=\"238\" name=\"Imagem 58\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com a ajuda da ionosfera, a transmiss\u00e3o de ondas planas entre o litoral do Brasil e a regi\u00e3o amaz\u00f4nica \u00e9 poss\u00edvel\u00a0\u00a0 por meio da<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) reflex\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) refra\u00e7\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) difra\u00e7\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) polariza\u00e7\u00e3o\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) interfer\u00eancia<\/b><\/span><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>25-(UFV-MG)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_2926f791.jpg\" alt=\"\" width=\"743\" height=\"124\" name=\"Imagem 59\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Analise as afirmativas a seguir:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I. Em virtude da refra\u00e7\u00e3o na atmosfera terrestre, um observador na Terra pode ver o Sol mesmo quando esse est\u00e1 totalmente abaixo da linha do horizonte.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II. Quando a luz passa do ar para a \u00e1gua, existe um \u00e2ngulo de incid\u00eancia para o qual ocorre a reflex\u00e3o total.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III. Quando uma onda sonora de frequ\u00eancia f passa do ar para a \u00e1gua, a sua frequ\u00eancia se altera.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Est\u00e1 CORRETO o que se afirma em:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) I, II e III.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) II, apenas.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) II e III, apenas.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) I, apenas.\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>26-(MACKENZIE-SP)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_eec0f108.jpg\" alt=\"\" width=\"281\" height=\"77\" name=\"Imagem 60\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um estudante, ao fazer a experi\u00eancia em que um feixe de luz monocrom\u00e1tico vai da \u00e1gua, de \u00edndice de refra\u00e7\u00e3o 1,3, para o ar, de \u00edndice de refra\u00e7\u00e3o 1,0, pode concluir que, para essa onda,<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_8e328c2d.jpg\" alt=\"\" width=\"281\" height=\"193\" name=\"Imagem 61\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) o comprimento de onda diminui e a velocidade aumenta.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) o comprimento de onda e a frequ\u00eancia da luz diminuem.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) a frequ\u00eancia aumenta, mas o comprimento de onda diminui.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) a frequ\u00eancia n\u00e3o se altera e o comprimento de onda diminui.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) a frequ\u00eancia n\u00e3o se altera e o comprimento de onda aumenta.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>27-(UNICAMP-SP)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_ca33b4ae.jpg\" alt=\"\" width=\"179\" height=\"104\" name=\"Imagem 62\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>H\u00e1 atualmente um grande interesse no desenvolvimento de materiais artificiais, conhecidos como metamateriais, que t\u00eam propriedades f\u00edsicas n\u00e3o convencionais. Este \u00e9 o caso de metamateriais que apresentam \u00edndice de refra\u00e7\u00e3o negativo, em contraste com materiais convencionais que t\u00eam \u00edndice de refra\u00e7\u00e3o positivo. Essa propriedade n\u00e3o usual pode ser aplicada na camuflagem de objetos e no desenvolvimento de lentes especiais.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_ab530204.jpg\" alt=\"\" width=\"185\" height=\"155\" name=\"Imagem 63\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_4218ce1.jpg\" alt=\"\" width=\"125\" height=\"153\" name=\"Imagem 64\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Na figura a seguir \u00e9 representado um raio de luz A que se propaga em um material convencional (Meio 1) com \u00edndice de refra\u00e7\u00e3o n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 1,8 e incide no Meio 2 formando um \u00e2ngulo \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 30\u00b0 com a normal. Um dos raios B, C, D ou E apresenta uma trajet\u00f3ria que n\u00e3o seria poss\u00edvel em um material convencional e que ocorre quando o Meio 2 \u00e9 um metamaterial com \u00edndice de refra\u00e7\u00e3o negativo. Identifique este raio e calcule o m\u00f3dulo do \u00edndice de refra\u00e7\u00e3o do Meio 2, n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, neste caso, utilizando a lei de Snell na forma \u2502n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u2502.sen\u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0= \u2502n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u2502.sen\u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Se necess\u00e1rio use \u221a2=1,4 e \u221a3=1,7.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_8771ccc3.jpg\" alt=\"\" width=\"371\" height=\"203\" name=\"Imagem 65\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) O \u00edndice de refra\u00e7\u00e3o de um meio material, n, \u00e9 definido pela raz\u00e3o entre as velocidades da luz no v\u00e1cuo e no meio. A velocidade da luz em um material \u00e9 dada por<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_edad058a.png\" alt=\"\" width=\"69\" height=\"46\" name=\"Imagem 137\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, em que \u03b5 \u00e9 a permissividade el\u00e9trica e \u03bc \u00e9 a permeabilidade magn\u00e9tica do material. Calcule o \u00edndice de refra\u00e7\u00e3o de um material que tenha:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_6b7d372b.png\" alt=\"\" width=\"294\" height=\"48\" name=\"Imagem 139\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A velocidade da luz no v\u00e1cuo \u00e9 c = 3,0\u00d710<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>8<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0m\/s.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>28-(PUC-RJ)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_d654f288.jpg\" alt=\"\" width=\"136\" height=\"111\" name=\"Imagem 68\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma onda eletromagn\u00e9tica se propaga no v\u00e1cuo e incide sobre uma superf\u00edcie de um cristal fazendo um \u00e2ngulo de \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 60<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0com a dire\u00e7\u00e3o normal a superf\u00edcie. Considerando a velocidade de propaga\u00e7\u00e3o da onda no v\u00e1cuo como c = 3 x 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>8<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0m\/s e sabendo que a onda refratada faz um \u00e2ngulo de \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 30<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0com a dire\u00e7\u00e3o normal, podemos dizer que a velocidade de propaga\u00e7\u00e3o da onda no cristal em m\/s \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 1 \u00d7 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>8<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) \u221a2\u00d7 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>8<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) \u221a3\u00d7 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>8<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) \u221a4\u00d7 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>8<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) \u221a5\u00d7 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>8<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>29-(UFPR-PR)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_c5c47a77.jpg\" alt=\"\" width=\"170\" height=\"110\" name=\"Imagem 69\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_5b0326b0.jpg\" alt=\"\" width=\"197\" height=\"111\" name=\"Imagem 70\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Descartes desenvolveu uma teoria para explicar a forma\u00e7\u00e3o do arco-\u00edris com base nos conceitos da \u00f3ptica geom\u00e9trica.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ele sup\u00f4s uma gota de \u00e1gua com forma esf\u00e9rica e a incid\u00eancia de luz branca conforme mostrado de modo simplificado na figura.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_f30bd4d7.jpg\" alt=\"\" width=\"241\" height=\"135\" name=\"Imagem 71\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_71da266b.jpg\" alt=\"\" width=\"277\" height=\"136\" name=\"Imagem 72\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O raio incidente sofre refra\u00e7\u00e3o ao entrar na gota (ponto A) e apresenta uma decomposi\u00e7\u00e3o de cores. Em seguida, esses raios sofrem reflex\u00e3o interna dentro da gota (regi\u00e3o B) e saem para o ar ap\u00f3s passar por uma segunda refra\u00e7\u00e3o (regi\u00e3o C).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Posteriormente, com a experi\u00eancia de Newton com prismas, foi poss\u00edvel explicar corretamente a decomposi\u00e7\u00e3o das cores da luz branca. A figura n\u00e3o est\u00e1 desenhada em escala e, por simplicidade, est\u00e3o representados apenas os raios violeta e vermelho, mas deve-se considerar que entre eles est\u00e3o os raios das outras cores do espectro vis\u00edvel.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sobre esse assunto, avalie as seguintes afirmativas:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1. O fen\u00f4meno da separa\u00e7\u00e3o de cores quando a luz sofre refra\u00e7\u00e3o ao passar de um meio para outro \u00e9 chamado de dispers\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2. Ao sofrer reflex\u00e3o interna, cada raio apresenta \u00e2ngulo de reflex\u00e3o igual ao seu \u00e2ngulo de incid\u00eancia, ambos medidos em rela\u00e7\u00e3o \u00e0 reta normal no ponto de incid\u00eancia.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3. Ao refratar na entrada da gota (ponto A na figura), o violeta apresenta menor desvio, significando que o \u00edndice de refra\u00e7\u00e3o da \u00e1gua para o violeta \u00e9 menor que para o vermelho.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa correta.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Somente a afirmativa 1 \u00e9 verdadeira.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Somente a afirmativa 2 \u00e9 verdadeira.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Somente as afirmativas 1 e 2 s\u00e3o verdadeiras.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Somente as afirmativas 1 e 3 s\u00e3o verdadeiras.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) Somente as afirmativas 2 e 3 s\u00e3o verdadeiras. \u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>30-(UFG-GO)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_e57f484c.jpg\" alt=\"\" width=\"164\" height=\"123\" name=\"Imagem 73\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um raio de luz monocrom\u00e1tico incide perpendicularmente na face A de um prisma e sofre reflex\u00f5es internas totais com toda luz emergindo pela face C, como ilustra a figura a seguir. Considerando o <\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_6519e394.jpg\" alt=\"\" width=\"479\" height=\"178\" name=\"Imagem 74\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ex\u00adposto e sabendo que o meio externo \u00e9 o ar\u00a0(n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>,\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>calcule o \u00edndice de refra\u00e7\u00e3o m\u00ednimo do prisma.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>31-(ITA-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_bd62afb1.jpg\" alt=\"\" width=\"249\" height=\"95\" name=\"Imagem 75\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um tarugo de vidro de \u00edndice de refra\u00e7\u00e3o n = 3\/2 e se\u00e7\u00e3o transversal retangular \u00e9 moldado na forma de uma ferradura, como ilustra a figura.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_1ea9b6f.jpg\" alt=\"\" width=\"331\" height=\"182\" name=\"Imagem 76\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um feixe de luz incide perpendicularmente sobre a superf\u00edcie plana P. Determine o valor m\u00ednimo da raz\u00e3o R\/d para o qual toda a luz que penetra pela superf\u00edcie P emerja do vidro pela superf\u00edcie Q.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>32-(UFF-RJ)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_eeeebffc.jpg\" alt=\"\" width=\"180\" height=\"105\" name=\"Imagem 77\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O fen\u00f4meno da miragem, comum em desertos, ocorre em locais onde a temperatura do solo \u00e9 alta. Raios luminosos chegam aos olhos de um observador por dois caminhos distintos, um dos quais parece proveniente de uma imagem especular do objeto observado, como se esse estivesse ao lado de um espelho d\u2019\u00e1gua (semelhante ao da superf\u00edcie de um lago).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um modelo simplificado para a explica\u00e7\u00e3o desse fen\u00f4meno \u00e9 mostrado na figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_ca2870c8.jpg\" alt=\"\" width=\"773\" height=\"172\" name=\"Imagem 78\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O raio que parece provir da imagem especular sofre refra\u00e7\u00f5es sucessivas em diferentes camadas de ar pr\u00f3ximas ao solo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Esse modelo reflete um racioc\u00ednio que envolve a temperatura, densidade e \u00edndice de refra\u00e7\u00e3o de cada uma das camadas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O texto a seguir, preenchidas suas lacunas, exp\u00f5e esse racioc\u00ednio.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u201c<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A temperatura do ar ___________________ com a altura da camada, provocando _________________ da densidade e _________________ do \u00edndice de refra\u00e7\u00e3o; por isso, as refra\u00e7\u00f5es sucessivas do raio descendente fazem o \u00e2ngulo de refra\u00e7\u00e3o ______________ at\u00e9 que o raio sofra reflex\u00e3o total, acontecendo o inverso em sua trajet\u00f3ria ascendente at\u00e9 o olho do observador\u201d.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa que completa corretamente as lacunas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) aumenta \u2013 diminui\u00e7\u00e3o \u2013 aumento \u2013 diminuir\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) aumenta \u2013 diminui\u00e7\u00e3o \u2013 diminui\u00e7\u00e3o \u2013 diminuir\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) diminui \u2013 aumento \u2013 aumento \u2013 aumentar\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) diminui \u2013 aumento \u2013 diminui\u00e7\u00e3o \u2013 aumentar\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) n\u00e3o varia \u2013 diminui\u00e7\u00e3o \u2013 diminui\u00e7\u00e3o \u2013 aumentar\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>33-(UFES-ES)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_d1b4c29d.jpg\" alt=\"\" width=\"237\" height=\"109\" name=\"Imagem 79\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\">\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_8375e79c.jpg\" alt=\"\" width=\"167\" height=\"101\" name=\"Imagem 80\" align=\"BOTTOM\" border=\"0\" \/>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_8142d4e2.jpg\" alt=\"\" width=\"177\" height=\"98\" name=\"Imagem 81\" align=\"BOTTOM\" border=\"0\" \/>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_b2999f39.jpg\" alt=\"\" width=\"176\" height=\"99\" name=\"Imagem 82\" align=\"BOTTOM\" border=\"0\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um raio de luz monocrom\u00e1tico com \u03bb=500 nm se propaga no ar com velocidade de 300.000 km\/s. Esse raio atinge com incid\u00eancia normal a superf\u00edcie (1) de um prisma de cristal, que flutua na superf\u00edcie de um l\u00edquido, penetrando em seu interior, conforme mostra a figura. Os \u00edndices de refra\u00e7\u00e3o do cristal e do ar s\u00e3o, n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cristal<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=2 e n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ar<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1, respectivamente.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_a4385ce7.jpg\" alt=\"\" width=\"475\" height=\"281\" name=\"Imagem 83\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Calcule<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a frequ\u00eancia da onda de luz no ar;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) o comprimento de onda da luz dentro do prisma;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) o menor valor do \u00e2ngulo \u03b8 \u00a0para que a luz n\u00e3o se propague do cristal para o l\u00edquido atrav\u00e9s da superf\u00edcie (2), sabendo que o \u00edndice de refra\u00e7\u00e3o do l\u00edquido \u00e9 n<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>l\u00edquido<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=1;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) o menor \u00edndice de refra\u00e7\u00e3o do l\u00edquido para que a luz se propague do cristal para o l\u00edquido atrav\u00e9s da superf\u00edcie (2), sabendo que o \u00e2ngulo \u03b8=45<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>34-(UNEMAT-MT)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_34949ae3.jpg\" alt=\"\" width=\"293\" height=\"90\" name=\"Imagem 84\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As fibras \u00f3ticas representaram uma revolu\u00e7\u00e3o na forma de transmitir informa\u00e7\u00f5es. Com o sistema de fibra \u00f3tica, mais dados s\u00e3o enviados atrav\u00e9s de dist\u00e2ncias mais longas, com menor n\u00famero de fios, aus\u00eancia de interfer\u00eancias eletromagn\u00e9ticas, al\u00e9m de se tornar mais vantajosa economicamente. O uso da fibra \u00f3tica tem se popularizado cada dia mais, desde ilumina\u00e7\u00e3o de piscinas at\u00e9<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_824baf23.jpg\" alt=\"\" width=\"153\" height=\"122\" name=\"Imagem 85\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_29e6aa97.jpg\" alt=\"\" width=\"442\" height=\"123\" name=\"Imagem 86\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_86489c96.jpg\" alt=\"\" width=\"136\" height=\"122\" name=\"Imagem 87\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>exames para examinar o interior de uma art\u00e9ria de um paciente com a introdu\u00e7\u00e3o de feixes de fibra \u00f3tica. A comunica\u00e7\u00e3o por fibra se realiza atrav\u00e9s da propaga\u00e7\u00e3o do sinal, obedecendo a um importante fen\u00f4meno da \u00f3tica geom\u00e9trica:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) dispers\u00e3o interna total.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) dispers\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) absor\u00e7\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) absor\u00e7\u00e3o interna total.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) reflex\u00e3o interna total<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>35-(CEFET-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sobre a refra\u00e7\u00e3o, afirma-se:<\/b><\/span><\/span><\/span><\/p>\n<p><a name=\"OLE_LINK1\"><\/a><a name=\"OLE_LINK2\"><\/a> <span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I-\u00a0A imagem que se observa das estrelas encontra-se acima de sua real posi\u00e7\u00e3o, tomando-se como refer\u00eancia o horizonte.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II- A reflex\u00e3o interna total ocorre quando a luz proveniente de um meio de menor \u00edndice de refra\u00e7\u00e3o propaga-se em outro meio de maior \u00edndice.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III &#8211; Um raio de luz, no ar, ao atingir com \u00e2ngulo de incid\u00eancia igual a 30\u00b0 a superf\u00edcie de separa\u00e7\u00e3o de um meio mais refringente,<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>refrata e forma com a normal um \u00e2ngulo menor que 30\u00b0.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>IV- As miragens nos desertos e a imagem de um carro refletida no asfalto, em um dia quente e ensolarado, s\u00e3o virtuais e invertidas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>S\u00e3o corretos apenas os itens<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) I e II.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) I e III.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) III e IV.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) I, II e III.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) II, III e IV.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>36-(ITA-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_85aca74a.jpg\" alt=\"\" width=\"180\" height=\"120\" name=\"Imagem 88\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\">\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_8d09211c.jpg\" alt=\"\" width=\"168\" height=\"119\" name=\"Imagem 89\" align=\"BOTTOM\" border=\"0\" \/>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_3e3f42ea.jpg\" alt=\"\" width=\"180\" height=\"119\" name=\"Imagem 90\" align=\"BOTTOM\" border=\"0\" \/>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_60a80257.jpg\" alt=\"\" width=\"216\" height=\"119\" name=\"Imagem 91\" align=\"BOTTOM\" border=\"0\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um hemisf\u00e9rio de vidro maci\u00e7o de raio de 10 cm e \u00edndice de refra\u00e7\u00e3o n = 3\/2 tem sua face plana apoiada sobre uma parede, como<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_b9c56aa5.jpg\" alt=\"\" width=\"430\" height=\"257\" name=\"Imagem 92\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ilustra a figura. Um feixe colimado de luz de 1 cm de di\u00e2metro incide sobre a face esf\u00e9rica, centrado na dire\u00e7\u00e3o do eixo de simetria do hemisf\u00e9rio.Valendo-se das aproxima\u00e7\u00f5es de \u00e2ngulos pequenos, sen\u03b8 \u2248 \u03b8 e tg\u03b8 \u2248\u03b8 e, o di\u00e2metro do c\u00edrculo de luz que se forma sobre a superf\u00edcie da parede \u00e9 de<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 1 cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 2\/3 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 1\/2 cm\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 1\/3 cm\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 1\/10 cm<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>37-(UFBA-BA)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_a4186ba1.jpg\" alt=\"\" width=\"589\" height=\"145\" name=\"Imagem 93\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>As fibras \u00f3pticas s\u00e3o longos fios finos, fabricados com vidro ou materiais polim\u00e9ricos, com di\u00e2metros da ordem de micr\u00f4metros at\u00e9 v\u00e1rios mil\u00edmetros, que t\u00eam a capacidade de transmitir informa\u00e7\u00f5es digitais, na forma de pulsos de luz, ao longo de grandes dist\u00e2ncias, at\u00e9 mesmo ligando os continentes atrav\u00e9s dos oceanos.<\/b><\/span><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_d9aa1f5f.jpg\" alt=\"\" width=\"282\" height=\"243\" name=\"Imagem 94\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um modo de transmiss\u00e3o da luz atrav\u00e9s da fibra ocorre pela incid\u00eancia de um feixe de luz, em uma das extremidades da fibra, que a percorre por meio de sucessivas reflex\u00f5es. As aplica\u00e7\u00f5es das fibras \u00f3pticas s\u00e3o bastante amplas nas telecomunica\u00e7\u00f5es e em outras \u00e1reas, como a medicina, por exemplo. Uma vantagem importante da fibra \u00f3ptica, em rela\u00e7\u00e3o aos fios de cobre, \u00e9 que nela n\u00e3o ocorre interfer\u00eancia eletromagn\u00e9tica.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Supondo que uma fibra \u00f3ptica encontra-se imersa no ar e que o \u00edndice de refra\u00e7\u00e3o da fibra \u00f3ptica \u00e9 igual a \u221a(3\/2) , calcule o maior \u00e2ngulo de incid\u00eancia de um raio de luz em rela\u00e7\u00e3o ao eixo da fibra, para que ele seja totalmente refletido pela parede cil\u00edndrica.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>38-(UFF-RJ)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_31ad3e6d.jpg\" alt=\"\" width=\"579\" height=\"133\" name=\"Imagem 95\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>que o mostrador do rel\u00f3gio faz com a mesma, observa-se que existe um \u00e2ngulo cr\u00edtico \u03b8 O fen\u00f4meno de reflex\u00e3o interna pode ser usado para medir o \u00edndice de refra\u00e7\u00e3o da \u00e1gua de uma forma simples. A figura representa, esquematicamente, um rel\u00f3gio imerso em \u00e1gua. Com a luz de um laser incidindo perperdicularmente sobre a superf\u00edcie da \u00e1gua e variando-se o \u00e2ngulo \u03b8\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, a partir do qual ocorre reflex\u00e3o total do raio na interface entre o vidro e o ar.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_b1d9a386.jpg\" alt=\"\" width=\"363\" height=\"247\" name=\"Imagem 96\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Obtenha o \u00edndice de refra\u00e7\u00e3o da \u00e1gua em fun\u00e7\u00e3o de \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, considerando que o \u00edndice de refra\u00e7\u00e3o do ar \u00e9 aproximadamente igual a 1.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3.10 b) Calcule a velocidade da luz na \u00e1gua, sabendo que a velocidade da luz no v\u00e1cuo \u00e9 c \u2248<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0km\/s e que o \u00e2ngulo cr\u00edtico \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 48,6<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>39-(UEPA-PA)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_560be51d.jpg\" alt=\"\" width=\"551\" height=\"139\" name=\"Imagem 97\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O conhecimento do \u00edndice de refra\u00e7\u00e3o de um meio \u00f3ptico \u00e9 um dado importante em v\u00e1rias aplica\u00e7\u00f5es tecnol\u00f3gicas usadas no dia-a-dia, tais como: constru\u00e7\u00e3o de lentes, de prismas usados em bin\u00f3culos e tamb\u00e9m de fibras \u00f3pticas. Na tabela abaixo s\u00e3o fornecidos os valores do \u00edndice de refra\u00e7\u00e3o absoluto de alguns meios \u00f3pticos.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_cb528366.jpg\" alt=\"\" width=\"777\" height=\"143\" name=\"Imagem 98\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A partir dessas informa\u00e7\u00f5es, afirma-se que:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I. Se a luz proveniente do ar incide em cada um dos meios, com o mesmo \u00e2ngulo de incid\u00eancia, o \u00e2ngulo de refra\u00e7\u00e3o ser\u00e1 maior na glicerina.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II. A velocidade com que a luz se propaga no diamante \u00e9 maior do que a velocidade com que a luz se propaga no acr\u00edlico.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III. O valor do \u00e2ngulo limite, quando a luz se propaga do acr\u00edlico para o ar, \u00e9 maior do que quando a luz se propaga do zirc\u00f4nio para o ar.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>IV. O \u00edndice de refra\u00e7\u00e3o de um meio \u00f3ptico \u00e9 uma caracter\u00edstica do meio, e n\u00e3o depende do tipo de radia\u00e7\u00e3o que nele incide.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>De acordo com as afirmativas acima, a<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>alternativa correta \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) I e II \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) I e III \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) II e III \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) II e IV \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) III e IV<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>40-(FUVEST-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_bd4d8f87.jpg\" alt=\"\" width=\"774\" height=\"125\" name=\"Imagem 99\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_f9e2e265.jpg\" alt=\"\" width=\"769\" height=\"131\" name=\"Imagem 100\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma fibra \u00f3tica \u00e9 um guia de luz, flex\u00edvel e transparente, cil\u00edndrico, feito de s\u00edlica ou pol\u00edmero, de di\u00e2metro n\u00e3o muito maior que o de um fio de cabelo, usado para transmitir sinais luminosos a grandes dist\u00e2ncias, com \u00a0baixas perdas de intensidade. A fibra \u00f3tica \u00e9 constitu\u00edda de um n\u00facleo, por onde a luz se propaga e de um revestimento, como esquematizado na figura acima (corte longitudinal). Sendo o \u00edndice de refra\u00e7\u00e3o do n\u00facleo 1,60 e o do revestimento, 1,45, o menor valor do \u00e2ngulo de incid\u00eancia \u03b8 do feixe luminoso, para que toda a luz incidente permane\u00e7a no n\u00facleo, \u00e9, aproximadamente,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_c64aa90a.jpg\" alt=\"\" width=\"419\" height=\"237\" name=\"Imagem 101\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/optica\/reflexao-total\/i_47a9531b4ec135e3_html_838d188e.png\" alt=\"\" width=\"775\" height=\"19\" name=\"Imagem 140\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<h3 align=\"CENTER\"><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Reflex\u00e3o Total\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/optica\/optica-geometrica\/reflexao-total\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-reflexao-total\/\"><span style=\"color: #000080;\">Confira as resolu\u00e7\u00f5es dos exerc\u00edcios e gabarito<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00f5es comentadas sobre Reflex\u00e3o Total &nbsp; 01-(PUC-PR) A figura mostra um arranjo experimental. No fundo do vaso, uma fonte pontual emite um raio que se desloca na \u00e1gua e atinge a superf\u00edcie di\u00f3ptrica. Considerando o \u00e2ngulo \u03b8 como \u00e2ngulo limite, o raio emergente \u00e9 o raio: a) IV\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) I\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) II\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) III<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2199,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2201","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2201","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2201"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2201\/revisions"}],"predecessor-version":[{"id":10957,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2201\/revisions\/10957"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2199"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2201"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}