{"id":2097,"date":"2016-03-28T23:15:52","date_gmt":"2016-03-28T23:15:52","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=2097"},"modified":"2024-08-21T15:05:35","modified_gmt":"2024-08-21T15:05:35","slug":"exercicios-de-vestibulares-sobre-tipos-de-transformacoes-gasosas","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/fisica-termica\/termodinamica\/tipos-de-transformacoes-gasosas\/exercicios-de-vestibulares-sobre-tipos-de-transformacoes-gasosas\/","title":{"rendered":"Tipos de transforma\u00e7\u00f5es gasosas"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares sobre<\/b><\/span><\/span><\/span><b> <\/b><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: large;\"><b>Tipos de transforma\u00e7\u00f5es gasosas<\/b><\/span><\/span><\/span><\/p>\n<p><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_10c16a9b.png\" alt=\"\" width=\"639\" height=\"129\" name=\"Imagem 133\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>02-(PUC-RS)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> De acordo com a Lei de Robert Boyle (1660), para proporcionar um aumento na press\u00e3o de uma determinada amostra gasosa numa transforma\u00e7\u00e3o isot\u00e9rmica, \u00e9 necess\u00e1rio:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) aumentar o seu volume. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) diminuir a sua massa. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) aumentar a sua temperatura.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) diminuir o seu volume. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) aumentar a sua massa<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>03-(UEBA-BA)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um bal\u00e3o-propaganda cheio de g\u00e1s h\u00e9lio, ao n\u00edvel do mar, ocupa um volume de 250 L. <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_18a471f1.jpg\" alt=\"\" width=\"469\" height=\"147\" name=\"Imagem 21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Seu volume ap\u00f3s lan\u00e7amento, numa altitude de 3000 m ser\u00e1: (obs.: admitindo-se que a temperatura tenha se mantido constante)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) menor, pois a press\u00e3o externa aumenta com a altitude. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) maior, pois a press\u00e3o externa diminui com a altitude. <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) permanecer\u00e1 constante, pois a press\u00e3o n\u00e3o varia com a altitude. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) permanecer\u00e1 constante, pois a temperatura se manteve constante.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) maior, pois a press\u00e3o externa aumenta com a altitude.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>04-(PUC-BA)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Duas amostras de igual massa de um mesmo g\u00e1s foram submetidas ao seguinte teste, \u00e0 temperatura constante:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_4eafd4aa.jpg\" alt=\"\" width=\"423\" height=\"163\" name=\"Imagem 22\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>os dados obtidos para a press\u00e3o e volume das amostras comprovam a lei de:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Boyle \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Gay-Lussac \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Avogadro\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Proust \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) Lavoisier<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>05- (PUC-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A figura ao lado representa um g\u00e1s contido em um cilindro cuja parte superior \u00e9 vedada por um \u00eambolo que pode deslizar, sem atrito, para cima e para baixo, ao longo das paredes do cilindro.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_99e7dcba.jpg\" alt=\"\" width=\"331\" height=\"166\" name=\"Imagem 23\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sobre o \u00eambolo est\u00e1 um objeto de massa constante. Se esse sistema for aquecido lentamente, a transforma\u00e7\u00e3o a que ele ser\u00e1 submetido \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) adiab\u00e1tica \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) isob\u00e1rica\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) isot\u00e9rmica\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) isoc\u00f3rica\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) isost\u00e1tica<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>06-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Se a press\u00e3o de um g\u00e1s confinado \u00e9 duplicada a temperatura constante, a grandeza do g\u00e1s que duplicar\u00e1 ser\u00e1:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a massa\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a massa espec\u00edfica\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) o volume\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) o peso\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) a energia cin\u00e9tica<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>07- (UFAC-AC)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Considere o gr\u00e1fico a seguir:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_56d3180e.jpg\" alt=\"\" width=\"513\" height=\"201\" name=\"Imagem 24\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O gr\u00e1fico acima representa um comportamento t\u00edpico de um g\u00e1s submetido \u00e0 lei de Boyle \u2013 Mariotte (P.V=K). Com rela\u00e7\u00e3o \u00e0 curva, pode-se afirmar que:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) \u00c9 uma isoc\u00f3rica e o valor de K \u00e9 igual a 2,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) \u00c9 uma isoterma e o valor de K \u00e9 igual a 12,0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) \u00c9 uma isoc\u00f3rica e o valor de K \u00e9 igual a 12,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) \u00c9 uma isoterma e o valor de K \u00e9 igual a 2,0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) \u00c9 uma isob\u00e1rica e o valor de K \u00e9 igual a 2,0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>08-(CESGRANRIO-RJ)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Voc\u00ea brincou de encher, com ar, um bal\u00e3o de g\u00e1s, na beira da praia, at\u00e9 um volume de 1 L e o fechou.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_c371a283.jpg\" alt=\"\" width=\"458\" height=\"153\" name=\"Imagem 25\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em seguida, subiu uma encosta pr\u00f3xima carregando o bal\u00e3o, at\u00e9 uma altitude de 900m, onde a press\u00e3o atmosf\u00e9rica \u00e9 10% menor que a press\u00e3o ao n\u00edvel do mar. Considerando que a temperatura na praia e na encosta seja mesma, o volume de ar no bal\u00e3o ap\u00f3s a subida, ser\u00e1 de:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_96d74e09.png\" alt=\"\" width=\"753\" height=\"20\" name=\"Imagem 134\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>09-(UFRJ-RJ)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um bal\u00e3o, contendo um g\u00e1s ideal, \u00e9 usado para levantar cargas subaqu\u00e1ticas. A uma certa profundidade, o g\u00e1s nele<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_f181fb3.jpg\" alt=\"\" width=\"571\" height=\"153\" name=\"Imagem 26\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>contido est\u00e1 em equil\u00edbrio t\u00e9rmico com a \u00e1gua a uma temperatura absoluta T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e a uma press\u00e3o P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Quando o bal\u00e3o sai da \u00e1gua, depois de levantar a carga, o g\u00e1s nele contido entra em equil\u00edbrio t\u00e9rmico com o ambiente a uma temperatura absoluta T e a uma press\u00e3o P.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Supondo que o g\u00e1s no interior do bal\u00e3o seja ideal e sabendo que P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\/P = 3\/2 e T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\/T = 0,93, calcule a raz\u00e3o V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\/V entre o volume V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do g\u00e1s quando o bal\u00e3o est\u00e1 submerso e o volume V do mesmo g\u00e1s quando o bal\u00e3o est\u00e1 fora d&#8217;\u00e1gua.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>10-(UNIFESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A figura ilustra duas transforma\u00e7\u00f5es de um g\u00e1s ideal contido num cilindro de paredes adiab\u00e1ticas. Em I, atrav\u00e9s de uma base diat\u00e9rmica (que permite a passagem do calor), o g\u00e1s recebe calor e faz o \u00eambolo, tamb\u00e9m constru\u00eddo de material adiab\u00e1tico, subir livremente, aumentando seu volume de V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a V, atingindo a temperatura T. Nesse estado, a fonte quente \u00e9 retirada e substitu\u00edda por um reservat\u00f3rio t\u00e9rmico \u00e0 mesma temperatura T do g\u00e1s. Em seguida, na transforma\u00e7\u00e3o II, colocam-se gr\u00e3os de areia sobre o \u00eambolo, lentamente, para que o g\u00e1s possa manter-se em equil\u00edbrio t\u00e9rmico com o reservat\u00f3rio. Nessas condi\u00e7\u00f5es, o \u00eambolo baixa at\u00e9 que o g\u00e1s volte a ocupar o mesmo volume V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do in\u00edcio.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_5659a6a5.jpg\" alt=\"\" width=\"610\" height=\"201\" name=\"Imagem 27\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere desprez\u00edveis as varia\u00e7\u00f5es da press\u00e3o atmosf\u00e9rica. O diagrama pV, que melhor representa essas duas transforma\u00e7\u00f5es, \u00e9 o da figura:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_2fc4c90b.jpg\" alt=\"\" width=\"778\" height=\"149\" name=\"Imagem 28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>11-(PUC-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um bal\u00e3o de anivers\u00e1rio, cheio de g\u00e1s H\u00e9lio, solta-se da m\u00e3o de uma crian\u00e7a, subindo at\u00e9 grandes altitudes.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_3340e90b.jpg\" alt=\"\" width=\"358\" height=\"161\" name=\"Imagem 29\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Durante a subida, \u00e9 CORRETO afirmar:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) O volume do bal\u00e3o diminui.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) A press\u00e3o do g\u00e1s no interior do bal\u00e3o aumenta.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) O volume do bal\u00e3o aumenta.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) O volume do bal\u00e3o permanece constante.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>12-(UEPG-GO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 A respeito do funcionamento da panela de press\u00e3o, assinale o que for correto.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_8d4962b4.jpg\" alt=\"\" width=\"377\" height=\"167\" name=\"Imagem 30\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>01) De acordo com a lei dos gases, as vari\u00e1veis envolvidas no processo s\u00e3o press\u00e3o, volume e temperatura.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>02) O aumento da press\u00e3o no interior da panela afeta o ponto de ebuli\u00e7\u00e3o da \u00e1gua.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>04) A quantidade de calor doado ao sistema deve ser constante, para evitar que a panela venha a explodir.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>08) O tempo de cozimento dos alimentos dentro de uma panela de press\u00e3o \u00e9 menor porque eles ficam submetidos a temperaturas superiores a 100 \u00b0C.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b><br \/>\n<\/b><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>13-(UFSC-SC)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0Como funciona a panela de press\u00e3o?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dona Maria, uma ex\u00edmia cozinheira, ficou intrigada ao sair de uma das aulas de Ci\u00eancias sobre o funcionamento da panela de<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_26aed4d7.jpg\" alt=\"\" width=\"263\" height=\"165\" name=\"Imagem 31\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>press\u00e3o, a qual utiliza diariamente em sua casa. Na primeira pesquisa efetuada em um site na Internet, ela encontrou o seguinte fragmento:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>&#8220;A panela de press\u00e3o foi inventada pelo f\u00edsico franc\u00eas Denis Papin, que publicou em 1861 uma descri\u00e7\u00e3o do equipamento, denominando-o digestor. Numa reuni\u00e3o de cientistas da Royal Society, Papin demonstrou que o seu invento era capaz de reduzir ossos a gelatina comest\u00edvel.&#8221;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dispon\u00edvel em:\u00a0 &lt;http:\/\/br.geocities.com\/saladefisica7\/funciona\/panela.htm&gt;. Acesso em: 22 out. 2007<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Alunos do ensino m\u00e9dio, no intuito de ajudar Dona Maria, enviaram os gr\u00e1ficos (I), (II), (III) e (IV) que representam o comportamento da temperatura de ebuli\u00e7\u00e3o da \u00e1gua (T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>) em fun\u00e7\u00e3o da press\u00e3o m\u00e1xima de vapor de \u00e1gua (P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>max<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>) no interior de quatro panelas de press\u00e3o (a, b, c e d), com press\u00f5es m\u00e1ximas diferentes P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e\u00a0 P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, respectivamente.<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_fd7d04e7.jpg\" alt=\"\" width=\"785\" height=\"154\" name=\"Imagem 32\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Escolha o gr\u00e1fico que melhor representa o comportamento da temperatura de ebuli\u00e7\u00e3o da \u00e1gua (Te) em fun\u00e7\u00e3o da press\u00e3o m\u00e1xima do vapor de \u00e1gua (P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>max<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>), indique-o na sua resposta, fa\u00e7a uma an\u00e1lise matem\u00e1tica da rela\u00e7\u00e3o entre as vari\u00e1veis referidas, explicando o princ\u00edpio de funcionamento da panela de press\u00e3o.<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>14-(UFMG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Gabriela segura um bal\u00e3o com g\u00e1s h\u00e9lio durante uma viagem do Rio de Janeiro at\u00e9 o pico das Agulhas Negras. <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_8790c732.jpg\" alt=\"\" width=\"522\" height=\"146\" name=\"Imagem 33\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>No Rio de Janeiro, o volume do bal\u00e3o era V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, e o g\u00e1s estava \u00e0 press\u00e3o p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e \u00e0 temperatura T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, medida em kelvin. Ao chegar ao pico, por\u00e9m, Gabriela observa que o volume do bal\u00e3o passa a ser 6\/5 V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e a temperatura do g\u00e1s, 9\/10 T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b><br \/>\nCom base nessas informa\u00e7\u00f5es, \u00e9 correto afirmar que, no pico das Agulhas Negras, a press\u00e3o do g\u00e1s, no interior do bal\u00e3o, \u00e9:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_b80a8c6d.png\" alt=\"\" width=\"765\" height=\"23\" name=\"Imagem 135\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>15- (FMTM-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Nas li\u00e7\u00f5es iniciais de um curso de mergulho com equipamento aut\u00f4nomo \u2013 <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_f3b83fbc.jpg\" alt=\"\" width=\"375\" height=\"143\" name=\"graphics31\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>cilindro de ar comprimido \u2013 os alunos s\u00e3o instru\u00eddos a voltarem lentamente \u00e0 superf\u00edcie, sem prender sua respira\u00e7\u00e3o em hip\u00f3tese alguma, a fim de permitir que ocorra a gradativa descompress\u00e3o. O aprisionamento do ar nos pulm\u00f5es pode ser fatal para o mergulhador durante a subida, pois, nesse caso, a transforma\u00e7\u00e3o sofrida pelo ar nos pulm\u00f5es \u00e9<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) isob\u00e1rica, com redu\u00e7\u00e3o do volume do ar.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) isob\u00e1rica, com aumento da temperatura do ar.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) isot\u00e9rmica, com aumento da press\u00e3o do ar.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) isot\u00e9rmica, com aumento do volume do ar.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) isovolum\u00e9trica, com diminui\u00e7\u00e3o da press\u00e3o do ar<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>16-(UNIFESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A figura reproduz o esquema da montagem feita por Robert Boyle para estabelecer a lei dos gases para transforma\u00e7\u00f5es isot\u00e9rmicas. Boyle colocou no tubo certa quantidade de merc\u00fario, at\u00e9 aprisionar um determinado volume de ar no ramo fechado, e igualou os n\u00edveis dos dois ramos. Em seguida, passou a acrescentar mais merc\u00fario no ramo aberto e a medir, no outro ramo, o volume do ar aprisionado (em unidades arbitr\u00e1rias) e a correspondente press\u00e3o pelo desn\u00edvel da coluna de merc\u00fario, em polegadas de merc\u00fario. Na tabela, est\u00e3o alguns dos dados por ele obtidos, de acordo com a sua publica\u00e7\u00e3o &#8220;New Experiments Physico-Mechanicall, Touching the Spring of Air, and its Effects&#8221;, de 1662.(<\/b><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b><a href=\"http:\/\/chemed.chem.purdue.edu\/gench%20m\/history\/\">http:\/\/chemed.chem.purdue.edu\/gench m\/history\/<\/a>)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_5d80a649.jpg\" alt=\"\" width=\"770\" height=\"237\" name=\"Imagem 35\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Todos os resultados obtidos por Boyle, com uma pequena aproxima\u00e7\u00e3o, confirmaram a sua lei. Que resultados foram esses? Justifique.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) De acordo com os dados da tabela, qual a press\u00e3o, em pascal, do ar aprisionado no tubo para o volume de 24 unidades arbitr\u00e1rias?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Utilize para este c\u00e1lculo:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>press\u00e3o atmosf\u00e9rica p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 1,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pascal; densidade do merc\u00fario d(Hg) = 14 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>kg\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>; g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>17-(UFAM-AM)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0Analise as seguintes afirmativas a respeito dos tipos de transforma\u00e7\u00f5es ou mudan\u00e7as de estado de um g\u00e1s.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I. em uma transforma\u00e7\u00e3o isoc\u00f3rica o volume do g\u00e1s permanece constante.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II. em uma transforma\u00e7\u00e3o isob\u00e1rica a press\u00e3o do g\u00e1s permanece constante.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III. em uma transforma\u00e7\u00e3o isot\u00e9rmica a temperatura do g\u00e1s permanece constante.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>IV. em uma transforma\u00e7\u00e3o adiab\u00e1tica variam o volume, a press\u00e3o e a temperatura.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com a rela\u00e7\u00e3o as quatro afirmativas acima, podemos dizer que:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) s\u00f3 I e III s\u00e3o verdadeiras.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) s\u00f3 II e III s\u00e3o verdadeiras.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) I, II, III e IV s\u00e3o verdadeiras.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) s\u00f3 I \u00e9 verdadeira.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) todas s\u00e3o falsas.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>18-(UFMG-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Regina estaciona seu carro, movido a g\u00e1s natural, ao Sol. Considere que o g\u00e1s no <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_857e4fb9.jpg\" alt=\"\" width=\"354\" height=\"172\" name=\"Imagem 36\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>reservat\u00f3rio do carro se comporta como um g\u00e1s ideal. Assinale a alternativa cujo gr\u00e1fico melhor representa a press\u00e3o em fun\u00e7\u00e3o da temperatura do g\u00e1s na situa\u00e7\u00e3o descrita.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_6afc4629.jpg\" alt=\"\" width=\"779\" height=\"169\" name=\"Imagem 37\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>19-(UNIFENAS-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um mol de um g\u00e1s ideal \u00e9 submetido a uma transforma\u00e7\u00e3o de estado c\u00edclico, como mostra o gr\u00e1fico a seguir:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_d3045bc2.jpg\" alt=\"\" width=\"427\" height=\"175\" name=\"Imagem 38\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pode-se afirmar que as transforma\u00e7\u00f5es A, B e C, s\u00e3o, respectivamente:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) isovolum\u00e9trica, isot\u00e9rmica, isovolum\u00e9trica \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) isob\u00e1rica, isot\u00e9rmica, isovolum\u00e9trica<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) isovolum\u00e9trica, isot\u00e9rmica, isob\u00e1rica \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) isot\u00e9rmica, isob\u00e1rica, isovolum\u00e9trica<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) isovolum\u00e9trica, isob\u00e1rica, isot\u00e9rmica<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>20-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Uma bola de futebol imperme\u00e1vel e murcha \u00e9 colocada sob uma camp\u00e2nula, num ambiente hermeticamente<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_20a8f49.jpg\" alt=\"\" width=\"212\" height=\"159\" name=\"Imagem 39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>fechado. A seguir, extrai-se lentamente o ar da camp\u00e2nula at\u00e9 que a bola acabe por readquirir sua forma esf\u00e9rica. Ao longo do processo, a temperatura \u00e9 mantida constante. Ao final do processo, tratando-se o ar como um g\u00e1s perfeito, podemos afirmar que:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a press\u00e3o do ar dentro da bola diminuiu.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a press\u00e3o do ar dentro da bola aumentou.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) a press\u00e3o do ar dentro da bola n\u00e3o mudou.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) a densidade do ar dentro da bola aumentou.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>21- (FGV-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Na Cor\u00e9ia do Sul, a ca\u00e7a submarina \u00e9 uma profiss\u00e3o feminina por tradi\u00e7\u00e3o. As <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Haenyeos s\u00e3o &#8220;mulheres-peixe&#8221; que ganham dinheiro mergulhando atr\u00e1s de frutos do mar e crust\u00e1ceos. O trabalho \u00e9 realizado com equipamentos prec\u00e1rios o que n\u00e3o impede a enorme resist\u00eancia dessas senhoras que conseguem submergir por dois minutos e descer at\u00e9 20 metros abaixo da superf\u00edcie.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(&#8220;Revista dos Curiosos&#8221;, 2003)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Supondo que o ar contido nos pulm\u00f5es de uma dessas mergulhadoras n\u00e3o sofresse varia\u00e7\u00e3o significativa de temperatura e se comportasse como um g\u00e1s ideal, e levando em conta que a <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>press\u00e3o exercida por uma coluna de \u00e1gua de 10m de altura equivale aproximadamente a 1atm, a rela\u00e7\u00e3o entre o volume do ar contido nos pulm\u00f5es, durante um desses mergulhos de 20m de profundidade, e o volume que esse ar ocuparia ao n\u00edvel do mar, se a estrutura \u00f3ssea e muscular do t\u00f3rax n\u00e3o oferecesse resist\u00eancia, corresponderia, aproximadamente, a<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_510678fa.jpg\" alt=\"\" width=\"301\" height=\"151\" name=\"Imagem 40\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dado: press\u00e3o na superf\u00edcie da \u00e1gua = 1 atm<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_62aae7e9.png\" alt=\"\" width=\"765\" height=\"20\" name=\"graphics32\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>22-<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>(CESGRANRIO-RJ)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Antes da largada e &#8220;na volta de apresenta\u00e7\u00e3o&#8221; de um Grande Pr\u00eamio de F\u00f3rmula 1, os pneus s\u00e3o pr\u00e9-aquecidos para melhorar o desempenho do carro. Supondo desprez\u00edvel varia\u00e7\u00e3o do volume do pneu durante a prova, qual dos gr\u00e1ficos a seguir representa a varia\u00e7\u00e3o da press\u00e3o do ar no interior do pneu em fun\u00e7\u00e3o da varia\u00e7\u00e3o de temperatura absoluta atingida pelo pneu na reta de chegada?<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_60a53388.jpg\" alt=\"\" width=\"781\" height=\"148\" name=\"Imagem 41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>23-(UFRN-RN)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> O departamento de F\u00edsica da UFRN possui um laborat\u00f3rio de pesquisa em criogenia, ci\u00eancia que estuda a produ\u00e7\u00e3o e manuten\u00e7\u00e3o de temperaturas muito baixas, contribuindo para o entendimento das propriedades f\u00edsicas e qu\u00edmicas de sistemas nessas temperaturas pouco comuns. Nesse laborat\u00f3rio, uma m\u00e1quina retira o g\u00e1s nitrog\u00eanio do ar e o liquefaz a uma temperatura de 77,0 kelvin (K), que corresponde a -196 graus celsius (\u00b0C). Nessa temperatura o nitrog\u00eanio \u00e9 usado cotidianamente pelos departamentos de F\u00edsica, Qu\u00edmica e Biologia da UFRN, como tamb\u00e9m por pecuaristas no congelamento de s\u00eamen para reprodu\u00e7\u00e3o animal.<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_f7909e6e.jpg\" alt=\"\" width=\"777\" height=\"156\" name=\"Imagem 42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>O nitrog\u00eanio l\u00edquido, em virtude de suas caracter\u00edsticas, necessita ser manuseado adequadamente, pois pessoas n\u00e3o habilitadas poder\u00e3o sofrer acidentes e serem v\u00edtimas de explos\u00f5es. Imagine uma pessoa desavisada transportando, num dia quente de ver\u00e3o, uma por\u00e7\u00e3o de nitrog\u00eanio l\u00edquido numa garrafa pl\u00e1stica fechada. Como o nitrog\u00eanio l\u00edquido tende a entrar em equil\u00edbrio t\u00e9rmico com o ambiente, mudar\u00e1 de estado f\u00edsico, transformando-se em um g\u00e1s. A tend\u00eancia desse g\u00e1s \u00e9 se expandir, podendo provocar uma explos\u00e3o.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Admita que<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>I) o nitrog\u00eanio rapidamente se transforma em g\u00e1s ideal, ou seja, obedece \u00e0 equa\u00e7\u00e3o PV = nRT. Em que R \u00e9 a constante universal dos gases e P, V, T, n s\u00e3o, respectivamente: a press\u00e3o, o volume, a temperatura e o n\u00famero de moles do g\u00e1s;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>II) a press\u00e3o interna e a temperatura iniciais desse g\u00e1s s\u00e3o, respectivamente, 2,0.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>pascal (P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>) e 78,0 K;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>III) a garrafa utilizada pode suportar uma press\u00e3o m\u00e1xima de 4,0.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e o volume dessa garrafa n\u00e3o varia at\u00e9 que a explos\u00e3o ocorra.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Diante dessas considera\u00e7\u00f5es, \u00e9 correto dizer que a temperatura limite (do g\u00e1s nitrog\u00eanio) que a garrafa suporta sem explodir \u00e9<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_1f4d0ea0.png\" alt=\"\" width=\"765\" height=\"19\" name=\"graphics33\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>24-(ITA-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A press\u00e3o total do ar no interior de um pneu era de 2,30 atm, quando a temperatura do pneu era de 27<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C. Depois de ter rodado um certo tempo com este pneu, mediu-se novamente sua press\u00e3o e verificou-se que este agora era de 2,53 atm. Supondo varia\u00e7\u00e3o de volume desprez\u00edvel do pneu, determine sua nova temperatura.\u00a0 <\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>25-(UNIFESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Voc\u00ea j\u00e1 deve ter notado como \u00e9 dif\u00edcil abrir a porta de um freezer logo ap\u00f3s t\u00ea-la fechado, sendo necess\u00e1rio aguardar alguns segundos para abri-la novamente. Considere um freezer vertical cuja porta tenha 0,60 m de largura por 1,0 m de<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>altura, volume interno de 150 L e que esteja a uma temperatura interna de &#8211; 18\u00baC, num dia em que a <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_9d42d05d.jpg\" alt=\"\" width=\"413\" height=\"181\" name=\"Imagem 43\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>temperatura externa seja de 27\u00baC temperatura interna de\u00a0 e a press\u00e3o, 1,0 x 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<br \/>\na) Com base em conceitos f\u00edsicos, explique a raz\u00e3o de ser dif\u00edcil abrir a porta do freezer logo ap\u00f3s t\u00ea-la fechado e por que \u00e9 necess\u00e1rio aguardar alguns instantes para conseguir abri-la novamente.<br \/>\nb) Suponha que voc\u00ea tenha aberto a porta do freezer por tempo suficiente para que todo o ar frio do seu interior fosse substitu\u00eddo por ar a 27\u00baC e que, fechando a porta do freezer, quisesse abri-la novamente logo em seguida. Considere que, nesse curt\u00edssimo intervalo de tempo, a temperatura m\u00e9dia do ar no interior do -3\u00baC. Determine a intensidade da for\u00e7a resultante sobre a porta do freezer.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>26-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Certa massa de g\u00e1s ideal, inicialmente \u00e0 press\u00e3o P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, volume V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e temperatura T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, \u00e9 submetida \u00e0 seguinte seq\u00fc\u00eancia de transforma\u00e7\u00f5es:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1. \u00c9 aquecida \u00e0 press\u00e3o constante at\u00e9 que a temperatura atinja o valor 2T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2. \u00c9 resfriada a volume constante at\u00e9 que a temperatura atinja o valor inicial T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3. \u00c9 comprimida \u00e0 temperatura constante at\u00e9 que atinja a press\u00e3o inicial P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Calcule os valores da press\u00e3o, temperatura e volume final de cada transforma\u00e7\u00e3o.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Represente as transforma\u00e7\u00f5es num diagrama press\u00e3o x volume.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>27-(UFRN-RN)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um mergulhador que faz manuten\u00e7\u00e3o numa plataforma de explora\u00e7\u00e3o de petr\u00f3leo est\u00e1 a uma profundidade de 15 m quando uma pequena bolha de ar, de volume V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>i<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, \u00e9 liberada e sobe at\u00e9 a superf\u00edcie, onde a press\u00e3o \u00e9 a press\u00e3o atmosf\u00e9rica (1,0 atm). Para efeito deste problema, considere que: a temperatura dentro da bolha permanece constante enquanto esta existir; a <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>press\u00e3o aumenta cerca de 1,0 atm a cada 10 m de profundidade; o ar da bolha \u00e9 um g\u00e1s ideal e obedece \u00e0 rela\u00e7\u00e3o PV\/T= constante, em que P, V e T s\u00e3o respectivamente, a press\u00e3o, o volume e a <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>temperatura do ar dentro da bolha. Na situa\u00e7\u00e3o apresentada, o volume da bolha quando ela estiver prestes a chegar \u00e0 superf\u00edcie ser\u00e1 aproximadamente:<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_ec2bc6f5.jpg\" alt=\"\" width=\"281\" height=\"174\" name=\"Imagem 44\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_f3deb1b0.png\" alt=\"\" width=\"678\" height=\"21\" name=\"graphics34\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>28-(UFLA-MG)<\/b><\/span><\/span><\/span><b> <\/b><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Quando abrimos uma geladeira com boa veda\u00e7\u00e3o e voltamos a fech\u00e1-la, \u00e9 dif\u00edcil abri-la novamente em seguida.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Como podemos explicar esse fen\u00f4meno com base no comportamento termodin\u00e2mico dos gases?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Considere uma geladeira com volume interno de 1.000 L, temperatura interna -5\u00b0C e \u00e1rea da porta 2m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Num dia cuja temperatura ambiente \u00e9 25\u00b0C, abrimos a porta da geladeira e a fechamos. Supondo que todo o ar frio no interior da geladeira seja substitu\u00eddo por ar \u00e0 temperatura ambiente. <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_a3c44ae2.jpg\" alt=\"\" width=\"193\" height=\"137\" name=\"graphics35\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Qual ser\u00e1 a for\u00e7a m\u00e9dia necess\u00e1ria para abrir a porta depois de restabelecido o equil\u00edbrio termodin\u00e2mico no interior da geladeira?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(Dado: 1 atm \u2248 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>29-(UFA-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Nos manuais de autom\u00f3veis, na se\u00e7\u00e3o que trata da calibragem dos pneus, junto \u00e0 press\u00e3o recomendada, encontramos a seguinte instru\u00e7\u00e3o: \u201cos pneus devem ser calibrados enquanto frios\u201d. Qual o motivo da recomenda\u00e7\u00e3o?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Se calibrarmos os pneus quentes com a press\u00e3o recomendada, ao esfriarem a press\u00e3o cair\u00e1 a valores mais baixos que o recomendado.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Se calibrarmos os pneus quentes com ar \u00e0 temperatura ambiente, podemos provocar rachaduras nas rodas.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Se calibrarmos os pneus ainda quentes, podemos levar a vazamentos de ar, porque a borracha estar\u00e1 dilatada.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) Se calibrarmos os pneus quentes com a press\u00e3o recomendada, quando os pneus esfriarem a press\u00e3o ficar\u00e1 muito acima da recomendada, por causa da contra\u00e7\u00e3o da borracha.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_6ccf55ed.jpg\" alt=\"\" width=\"286\" height=\"172\" name=\"Imagem 46\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) Se calibrarmos os pneus a frio, gastaremos menos ar para ench\u00ea-los.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_a9c9f0e1.png\" alt=\"\" width=\"765\" height=\"170\" name=\"Imagem 10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>31-(UFPB-PB)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Antes de iniciar uma viagem, um motorista cuidadoso calibra os pneus de seu carro, que est\u00e3o \u00e0 temperatura<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_4f74e87c.jpg\" alt=\"\" width=\"286\" height=\"154\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>ambiente de 27\u00b0C, com uma press\u00e3o de 30 lb\/pol<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Ao final da viagem, para determinar a temperatura dos pneus, o motorista mede a press\u00e3o dos mesmos e descobre que esta aumentou para 32 lb\/pol<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Se o volume dos pneus permanece inalterado e se o g\u00e1s no interior \u00e9 ideal, o motorista determinou a temperatura dos pneus como sendo:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_32b3844c.png\" alt=\"\" width=\"766\" height=\"18\" name=\"Imagem 11\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>32-(FUVEST)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> O gas\u00f4metro G, utilizado para o armazenamento de ar, \u00e9 um recipiente cil\u00edndrico, met\u00e1lico, com paredes laterais de pequena espessura. G \u00e9 fechado na sua parte superior, aberto na inferior que permanece imersa em \u00e1gua e pode se mover na dire\u00e7\u00e3o vertical. G cont\u00e9m ar, inicialmente \u00e0 temperatura de 300K e o n\u00edvel da \u00e1gua no seu interior se encontra 2,0m abaixo do n\u00edvel externo da \u00e1gua. Nessas condi\u00e7\u00f5es, a tampa de G est\u00e1 9,0m acima do n\u00edvel externo da \u00e1gua como mostra a figura a seguir.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Aquecendo-se o g\u00e1s, o sistema se estabiliza numa nova altura de equil\u00edbrio, com a tampa superior a uma altura H, em rela\u00e7\u00e3o ao n\u00edvel externo da \u00e1gua, e com a temperatura do g\u00e1s a 360K. Supondo que o ar se comporte como um g\u00e1s ideal, a nova altura H ser\u00e1, aproximadamente, igual a:<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_47dd1ae1.jpg\" alt=\"\" width=\"347\" height=\"167\" name=\"Imagem 49\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_7dc7305b.png\" alt=\"\" width=\"749\" height=\"22\" name=\"graphics36\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>33-(UFRJ-RJ)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um recipiente de volume interno total igual a V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>est\u00e1 dividido em dois compartimentos estanques por meio de uma parede fina que pode se mover sem atrito na dire\u00e7\u00e3o horizontal, como indica a figura a seguir.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A parede \u00e9 diat\u00e9rmica, isto \u00e9, perme\u00e1vel ao calor. O compartimento da direita cont\u00e9m dois moles de um g\u00e1s ideal, enquanto o da esquerda cont\u00e9m um mol de um outro g\u00e1s, tamb\u00e9m ideal.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Sabendo que os gases est\u00e3o em equil\u00edbrio t\u00e9rmico entre si e que a parede se encontra em repouso, calcule o volume de cada g\u00e1s em fun\u00e7\u00e3o de V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_c5b7897e.jpg\" alt=\"\" width=\"397\" height=\"171\" name=\"Imagem 50\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>34-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Em algumas situa\u00e7\u00f5es de resgate, bombeiros utilizam cilindros de ar comprimido <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_f2d94672.jpg\" alt=\"\" width=\"379\" height=\"160\" name=\"Imagem 51\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>para garantir condi\u00e7\u00f5es normais de respira\u00e7\u00e3o em ambientes com gases t\u00f3xicos. Esses cilindros, cujas caracter\u00edsticas est\u00e3o indicadas e seguir, alimentam m\u00e1scaras que se acoplam ao nariz. Quando acionados, os cilindros fornecem para a respira\u00e7\u00e3o, a cada minuto, cerca de 40 litros de ar, a press\u00e3o atmosf\u00e9rica e temperatura ambiente. Nesse caso, a dura\u00e7\u00e3o do ar de um desses cilindros seria de aproximadamente:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_52c5663e.jpg\" alt=\"\" width=\"410\" height=\"144\" name=\"Imagem 52\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A temperatura durante todo o processo permanece constante.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 20 minutos.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 30 minutos.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 45 minutos. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 60 minutos.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 90 minutos.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>35-(Inatel-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um recipiente cil\u00edndrico tem seu volume V dividido em duas partes por uma membrana r\u00edgida. <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_dbe5969.jpg\" alt=\"\" width=\"414\" height=\"160\" name=\"Imagem 53\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Em uma das partes tem-se g\u00e1s ideal \u00e0 press\u00e3o P e temperatura T. Admita que essa parte tenha 1\/3 do volume do cilindro. Na outra parte fez-se o v\u00e1cuo. As paredes do cilindro n\u00e3o permitem que o g\u00e1s troque calor com o meio externo. A membrana \u00e9 removida sem que haja troca de calor. Depois que o g\u00e1s entra em equil\u00edbrio, a press\u00e3o e temperatura s\u00e3o, respectivamente:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_79064772.png\" alt=\"\" width=\"766\" height=\"21\" name=\"graphics37\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>36-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> A figura mostra uma bomba de encher pneu de bicicleta. Quando o \u00eambolo est\u00e1 todo puxado, a uma dist\u00e2ncia de 30cm da base, a press\u00e3o dentro da bomba \u00e9 igual \u00e0 press\u00e3o atmosf\u00e9rica normal. A \u00e1rea da se\u00e7\u00e3o transversal do pist\u00e3o da bomba \u00e9 de 24cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Um ciclista quer encher ainda mais o pneu da bicicleta que tem volume de 2,4 litros e j\u00e1 est\u00e1 com uma press\u00e3o interna de 3atm. Ele empurra o \u00eambolo da bomba at\u00e9 o final de seu curso. Suponha que o volume do pneu permane\u00e7a constante, que o processo possa ser considerado isot\u00e9rmico e que o volume do tubo que liga a bomba ao pneu seja desprez\u00edvel. A press\u00e3o final do pneu ser\u00e1, ent\u00e3o, de aproximadamente:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 1,0 atm\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_eda54d80.jpg\" alt=\"\" width=\"148\" height=\"170\" name=\"Imagem 54\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 3,0 atm\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 3,3 atm\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 3,9 atm\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 4,0 atm<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>37-(UFRGS-RS)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Na figura abaixo est\u00e3o representados dois bal\u00f5es de vidro, A e B, com capacidades \u00a0de 3 litros e de 1 litro, respectivamente. Os bal\u00f5es est\u00e3o conectados entre si\u00a0 por um tubo fino munido da torneira T, que se encontra fechada. O bal\u00e3o A cont\u00e9m hidrog\u00eanio \u00e0 press\u00e3o de 1,6 atmosferas. O bal\u00e3o B foi completamente esvaziado. Abre-se, ent\u00e3o, a torneira T, pondo os bal\u00f5es em comunica\u00e7\u00e3o, e faz-se tamb\u00e9m\u00a0 com que a temperatura dos bal\u00f5es e do g\u00e1s retorne ao seu valor inicial, (considere 1 atm igual a 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_bef2dca.jpg\" alt=\"\" width=\"334\" height=\"133\" name=\"Imagem 55\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Qual \u00e9, em N\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, o valor aproximado\u00a0 da press\u00e3o a que fica submetido o hidrog\u00eanio?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>38-(Unifor-CE)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Dois recipientes r\u00edgidos de mesmo volume cont\u00e9m gases perfeitos \u00e0s press\u00f5es de 5,0 atm e 18,0 atm, na mesma temperatura. Os dois recipientes est\u00e3o ligados por um tubo provido de torneira que, inicialmente, est\u00e1 fechada. Abrindo-se a torneira, os gases se misturam sem reagir, e a temperatura diminui. Aguardando-se algum tempo para que a temperatura volte ao valor inicial, a press\u00e3o comum nos dois botij\u00f5es, em atm, \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 10,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) 11,5\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) 13,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) 23,0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) 26,0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>39-(UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> As baleias s\u00e3o mam\u00edferos aqu\u00e1ticos dotados de um sistema respirat\u00f3rio altamente eficiente que dispensa um ac\u00famulo muito elevado de ar nos pulm\u00f5es, o que prejudicaria sua capacidade de submergir. A massa de certa baleia \u00e9 de 1,50 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>kg e o seu volume, quando os pulm\u00f5es est\u00e3o vazios, \u00e9 igual a 1,35 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Calcule o volume m\u00e1ximo da baleia ap\u00f3s encher os pulm\u00f5es de ar, acima do qual a baleia n\u00e3o conseguiria submergir sem esfor\u00e7o. Despreze o peso do ar nos pulm\u00f5es e considere a densidade da \u00e1gua do mar igual a 1,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>kg\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Qual \u00e9 a varia\u00e7\u00e3o percentual do volume da baleia ao encher os pulm\u00f5es de ar at\u00e9 atingir o volume m\u00e1ximo calculado no item a? Considere que inicialmente os pulm\u00f5es estavam vazios.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Suponha que uma baleia encha rapidamente seus pulm\u00f5es em um local onde o ar se encontra inicialmente a uma temperatura de 7<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00b0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C e a uma press\u00e3o de 1,0 atm (1,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>). Calcule a press\u00e3o do ar no interior dos pulm\u00f5es da baleia, ap\u00f3s atingir o equil\u00edbrio t\u00e9rmico com o corpo do animal, que est\u00e1 a 37<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00b0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C. Despreze qualquer varia\u00e7\u00e3o da temperatura do ar no seu caminho at\u00e9 os pulm\u00f5es e considere o ar um g\u00e1s ideal.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_5c96a204.jpg\" alt=\"\" width=\"350\" height=\"199\" name=\"Imagem 56\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>40-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Um cilindro com comprimento de 1,5m, cuja base inferior \u00e9 constitu\u00edda por um bom condutor de calor, permanece semi-imerso em um grande tanque industrial, ao n\u00edvel do mar, podendo ser utilizado como term\u00f4metro. Para isso, dentro do cilindro, h\u00e1 um pist\u00e3o, de massa desprez\u00edvel e isolante t\u00e9rmico, que pode mover-se sem atrito.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Inicialmente, com o ar e o l\u00edquido do tanque \u00e0 temperatura ambiente de 27\u00baC, o cilindro est\u00e1 aberto e o pist\u00e3o encontra-se na posi\u00e7\u00e3o indicada na figura 1. O cilindro \u00e9, ent\u00e3o fechado e, a seguir, o l\u00edquido do tanque \u00e9 aquecido, fazendo com que o pist\u00e3o atinja uma nova posi\u00e7\u00e3o, indicada na figura 2.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_6c7dfe1c.png\" alt=\"\" width=\"765\" height=\"246\" name=\"graphics38\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Supondo que a temperatura da c\u00e2mara superior A permane\u00e7a sempre igual a 27\u00baC, determine:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) A press\u00e3o final P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, em Pa, na c\u00e2mara superior A.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) A temperatura final T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do l\u00edquido no tanque, em \u00baC ou em K.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>41-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um grande cilindro, com ar inicialmente \u00e0 press\u00e3o P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e temperatura ambiente (T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 300 K), quando aquecido, pode provocar a eleva\u00e7\u00e3o de uma plataforma A, que funciona como um pist\u00e3o, at\u00e9 uma posi\u00e7\u00e3o mais alta. Tal processo exemplifica a transforma\u00e7\u00e3o de calor em trabalho, que ocorre nas m\u00e1quinas t\u00e9rmicas, \u00e0 press\u00e3o constante. Em uma dessas situa\u00e7\u00f5es, o ar contido em um cilindro, cuja \u00e1rea da base S \u00e9 igual a 0,16 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, sustenta uma plataforma de massa M<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>=160 kg a uma altura H<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 4,0 m do ch\u00e3o (situa\u00e7\u00e3o I). Ao ser aquecido, a partir da queima de um combust\u00edvel, o ar passa a uma temperatura T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, expandindo-se e empurrando a plataforma at\u00e9 uma nova altura H<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 6,0 m (situa\u00e7\u00e3o II). Para verificar em que medida esse \u00e9 um processo eficiente, estime:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_82e6de15.jpg\" alt=\"\" width=\"447\" height=\"262\" name=\"Imagem 58\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) A press\u00e3o P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do ar dentro do cilindro, em pascals, durante a opera\u00e7\u00e3o.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) A temperatura T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>do ar no cilindro, em kelvins, na situa\u00e7\u00e3o II.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) A efici\u00eancia do processo, indicada pela raz\u00e3o R = \u2206Ep\/Q, onde \u2206Ep \u00e9 a varia\u00e7\u00e3o da energia potencial da plataforma, quando ela se desloca da altura H<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>para a altura H<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, e Q, a quantidade de calor recebida pelo ar do cilindro durante o aquecime<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>NOTE E ADOTE:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>PV = nRT; P(atmosf\u00e9rica) = P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>= 1,0&#215;10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pa; 1 Pa = 1 N\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 &#8212;\u00a0 Calor espec\u00edfico do ar a press\u00e3o constante Cp \u2248 1,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J\/(kg.K)\u00a0 &#8212;\u00a0 Densidade do ar a 300 K \u2248 1,1 kg\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>42-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Uma massa de certo g\u00e1s ideal est\u00e1 confinada em um reservat\u00f3rio, cuja dilata\u00e7\u00e3o t\u00e9rmica \u00e9 desprez\u00edvel no intervalo de temperatura considerado. Esse reservat\u00f3rio possui na parte superior, um \u00eambolo que pode se deslocar livremente, conforme ilustra a figura. Observando-se o gr\u00e1fico a seguir, destaca-se que, no estado A, o volume ocupado pelo g\u00e1s \u00e9 V e a sua press\u00e3o \u00e9 P. Em seguida, esse g\u00e1s passa por duas transforma\u00e7\u00f5es sucessivas e &#8220;chega&#8221; ao estado C, com temperatura e press\u00e3o, respectivamente iguais a:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 450 K e 3P\/2\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_a5d34da7.jpg\" alt=\"\" width=\"506\" height=\"199\" name=\"Imagem 59\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 450 K e 4P\/3\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 600 K e 3P\/2\u00a0\u00a0 \u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 600 K e 4P\/3\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e) 600 K e 5P\/3\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>43-(UFOP-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Considere o gr\u00e1fico a seguir, que descreve o comportamento da press\u00e3o e do volume de certa massa de g\u00e1s ideal.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_843ee9e2.jpg\" alt=\"\" width=\"546\" height=\"230\" name=\"Imagem 60\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Com rela\u00e7\u00e3o \u00e0s transforma\u00e7\u00f5es mostradas acima, podemos afirmar que:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) a transforma\u00e7\u00e3o BC \u00e9 isob\u00e1rica.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) a transforma\u00e7\u00e3o AB \u00e9 isot\u00e9rmica.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) h\u00e1 uma mudan\u00e7a dr\u00e1stica do volume na transforma\u00e7\u00e3o BC.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) a temperatura no ponto A \u00e9 maior que no ponto C.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>44-(UDESC-SC)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um motorista, antes de iniciar sua viagem, calibrou os pneus de seu carro, deixando-os a uma press\u00e3o<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>manom\u00e9trica de 150,0&#215;10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pa. No momento da calibra\u00e7\u00e3o a temperatura ambiente e dos pneus era de 27,0<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00b0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C. Quando chegou ao destino de sua viagem, o motorista percebeu que a press\u00e3o manom\u00e9trica do ar (g\u00e1s) nos pneus aumentara para 160,0&#215;10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pa. Considere o ar dentro dos pneus como sendo um g\u00e1s ideal. Dada a constante de Boltzmann 1,38 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-23<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>J\/K.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Ao chegar ao destino, qual a temperatura do g\u00e1s nos pneus, sabendo que eles expandiram, aumentando seu volume interno em 5%.<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_61a35b20.jpg\" alt=\"\" width=\"342\" height=\"205\" name=\"Imagem 61\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Considerando as condi\u00e7\u00f5es iniciais da viagem e que os pneus suportem, no m\u00e1ximo, uma varia\u00e7\u00e3o de volume de 8%, calcule a press\u00e3o do g\u00e1s no interior dos pneus nessa condi\u00e7\u00e3o limite. Sabe-se ainda que a temperatura do g\u00e1s dentro dos pneus, na condi\u00e7\u00e3o limite, atinge aproximadamente 360 K.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\">\u00a0<span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>45-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Em um<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>freezer<\/b><\/i><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, muitas vezes, \u00e9 dif\u00edcil repetir a abertura da porta, pouco tempo ap\u00f3s ter sido fechado, devido \u00e0 diminui\u00e7\u00e3o da press\u00e3o interna. Essa diminui\u00e7\u00e3o ocorre porque o ar que entra, \u00e0 temperatura ambiente, \u00e9 rapidamente resfriado at\u00e9<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a temperatura de opera\u00e7\u00e3o, em torno de &#8211; 18<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00b0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C. Considerando um<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><i><b>freezer<\/b><\/i><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>dom\u00e9stico, de 280 l, bem vedado, em um ambiente a 27<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00b0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C e press\u00e3o atmosf\u00e9rica P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, a press\u00e3o interna poderia atingir o valor m\u00ednimo de:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere que todo o ar no interior do freezer, no instante em que a porta \u00e9 fechada, est\u00e1 \u00e0 temperatura do ambiente.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 35% de P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_b79b250b.jpg\" alt=\"\" width=\"248\" height=\"184\" name=\"Imagem 62\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 50% de P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 67% de P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 85% de P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 95% de P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\">\u00a0\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>46-(FGV-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Para garantir a dosagem precisa, um medicamento pedi\u00e1trico \u00e9 acompanhado de uma seringa. Depois de destampado o frasco de vidro que cont\u00e9m o rem\u00e9dio, a seringa \u00e9 nele encaixada com seu \u00eambolo completamente recolhido. Em seguida, o frasco \u00e9 posicionado de cabe\u00e7a para baixo e o rem\u00e9dio \u00e9 ent\u00e3o sugado para o interior da seringa, enquanto o \u00eambolo \u00e9 puxado para baixo. Como consequ\u00eancia da retirada do l\u00edquido, o ar que j\u00e1 se encontrava dentro do frasco, expande-se isotermicamente, preenchendo o volume antes ocupado pelo rem\u00e9dio.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Ao retirar-se uma dose de 40 mL de l\u00edquido do frasco, que continha um volume ocupado pelo ar de 100 mL, o \u00eambolo encontra certa resist\u00eancia, devido ao fato de a press\u00e3o no interior do frasco ter se tornado, aproximadamente, em Pa,<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_566ba339.jpg\" alt=\"\" width=\"338\" height=\"215\" name=\"Imagem 63\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Dados: Press\u00e3o atmosf\u00e9rica = 1,0&#215;10<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>5<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Pa\u00a0 &#8212;\u00a0 Suponha que o ar dentro do frasco se comporte como um g\u00e1s ideal\u00a0 &#8212;\u00a0 Considere desprez\u00edvel o atrito entre o \u00eambolo e a parede interna da seringa.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) 57 000.\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) 68 000.\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) 71 000.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>d) 83 000.\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e) 94 000.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>47-(PUC-RJ)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Seja um mol de um g\u00e1s ideal a uma temperatura de 400 K e \u00e0 press\u00e3o atmosf\u00e9rica p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Esse g\u00e1s passa por uma expans\u00e3o isob\u00e1rica at\u00e9 dobrar seu volume. Em seguida, esse g\u00e1s passa por uma compress\u00e3o isot\u00e9rmica at\u00e9 voltar a seu volume original. Qual a press\u00e3o ao final dos dois processos?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0\u00a0 0,5 p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b)\u00a0\u00a0\u00a0 1,0 p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0c)\u00a0\u00a0\u00a0 2,0 p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d)\u00a0\u00a0\u00a0 5,0 p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e)\u00a0 10,0 p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>48-(UFAL-AL)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um g\u00e1s ideal possui, inicialmente, volume V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e encontra-se sob uma press\u00e3o p<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. O g\u00e1s passa por uma transforma\u00e7\u00e3o isot\u00e9rmica, ao final da qual o seu volume torna-se igual a V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\/2. Em seguida, o g\u00e1s passa por uma transforma\u00e7\u00e3o isob\u00e1rica, ap\u00f3s a qual seu volume \u00e9 2V<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>. Denotando a temperatura absoluta inicial do g\u00e1s por T<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, a sua temperatura absoluta ao final das duas transforma\u00e7\u00f5es \u00e9 igual a:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_3571178e.png\" alt=\"\" width=\"774\" height=\"22\" name=\"graphics39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>49-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b> Um bal\u00e3o de ar quente \u00e9 constitu\u00eddo de um envelope (parte infl\u00e1vel), cesta para tr\u00eas passageiros, queimador e tanque de g\u00e1s. A massa total do bal\u00e3o, com tr\u00eas passageiros e com o envelope vazio, \u00e9 de 400 kg. O envelope totalmente inflado tem um volume de 1500m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>a) Que massa de ar M<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>caberia no interior do envelope, se totalmente inflado, com press\u00e3o igual \u00e0 press\u00e3o atmosf\u00e9rica local (P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>atm<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>) e temperatura T=27<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>b) Qual a massa total de ar M<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>, no interior do envelope, ap\u00f3s este ser totalmente inflado com ar quente a uma temperatura de 127<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C e press\u00e3o P<\/b><\/span><\/span><sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>atm<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>c) Qual a acelera\u00e7\u00e3o do bal\u00e3o, com os passageiros, ao ser lan\u00e7ado nas condi\u00e7\u00f5es dadas no item b) quando a temperatura externa \u00e9 T=27<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C ?<\/b><\/span><\/span><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_66ab58af.jpg\" alt=\"\" width=\"303\" height=\"175\" name=\"Imagem 65\" align=\"LEFT\" border=\"0\" hspace=\"12\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>NOTE E ADOTE:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Densidade do ar a 27<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C e \u00e0 press\u00e3o atmosf\u00e9rica local = 1,2 kg\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Acelera\u00e7\u00e3o da gravidade na Terra, g = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere todas as opera\u00e7\u00f5es realizadas ao n\u00edvel do mar.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Despreze o empuxo acarretado pelas partes s\u00f3lidas do bal\u00e3o.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>T (K) = T (<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>C) + 273<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Indique a resolu\u00e7\u00e3o da quest\u00e3o. N\u00e3o \u00e9 suficiente apenas escrever as respostas.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><b>50-(UERJ-RJ)\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>A bola utilizada em uma partida de futebol \u00e9 uma esfera de di\u00e2metro interno igual a 20 cm. <\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_aa53e3e0.jpg\" alt=\"\" width=\"165\" height=\"136\" name=\"Imagem 72\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Quando cheia, a bola apresenta, em\u00a0seu interior, ar sob press\u00e3o de 1,0 atm e temperatura de 27 \u00baC.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Considere \u03c0= 3, R = 0,080 atm.L.mol<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.k<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>e, para o ar, comportamento de g\u00e1s ideal e massa molar igual a 30 g.mol<\/b><\/span><\/span><sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>No interior da bola cheia, a massa de ar, em gramas, corresponde a:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_e896b119.png\" alt=\"\" width=\"774\" height=\"20\" name=\"graphics40\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: Arial Black,serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>51-(UNESP-SP)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_92b375f5.jpg\" alt=\"\" width=\"774\" height=\"137\" name=\"Imagem 73\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Os desodorantes do tipo aerossol cont\u00eam em sua formula\u00e7\u00e3o solventes e propelentes inflam\u00e1veis. Por essa raz\u00e3o, as embalagens utilizadas para a comercializa\u00e7\u00e3o do produto fornecem no r\u00f3tulo algumas instru\u00e7\u00f5es, tais como:<\/b><\/span><\/span><\/p>\n<p>\u2022 <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N\u00e3o expor a embalagem ao sol.<\/b><\/span><\/span><\/p>\n<p>\u2022 <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N\u00e3o usar pr\u00f3ximo a chamas.<\/b><\/span><\/span><\/p>\n<p>\u2022 <span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>N\u00e3o descartar em incinerador.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_5f296d40.jpg\" alt=\"\" width=\"330\" height=\"156\" name=\"Imagem 74\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>Uma lata desse tipo de desodorante foi lan\u00e7ada em um incinerador a 25 \u00baC e 1 atm. Quando a temperatura do sistema<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/termica\/transformacoes\/i_538253d2ddbd4bdd_html_40fb1c52.jpg\" alt=\"\" width=\"307\" height=\"154\" name=\"Imagem 75\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>atingiu 621 \u00baC, a lata explodiu. Considere que n\u00e3o houve deforma\u00e7\u00e3o durante o aquecimento. No momento da explos\u00e3o a press\u00e3o no interior da lata era<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(A) 1,0 atm.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(B) 2,5 atm.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(C) 3,0 atm.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(D) 24,8 atm.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial,serif;\"><span style=\"font-size: medium;\"><b>(E) 30,0 atm.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Tipos de transforma\u00e7\u00f5es gasosas\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/fisica-termica\/termodinamica\/tipos-de-transformacoes-gasosas\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-tipos-de-transformacoes-gasosas\/\"><span style=\"color: #000080;\">Confira a resolu\u00e7\u00e3o comentada e gabarito<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares sobre Tipos de transforma\u00e7\u00f5es gasosas 02-(PUC-RS) De acordo com a Lei de Robert Boyle (1660), para proporcionar um aumento na press\u00e3o de uma determinada amostra gasosa numa transforma\u00e7\u00e3o isot\u00e9rmica, \u00e9 necess\u00e1rio: a) aumentar o seu volume. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) diminuir a sua massa. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) aumentar a sua temperatura. d) diminuir o seu volume. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) aumentar a<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":2095,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-2097","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2097","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=2097"}],"version-history":[{"count":4,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2097\/revisions"}],"predecessor-version":[{"id":10748,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2097\/revisions\/10748"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/2095"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=2097"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}