{"id":1994,"date":"2016-02-28T00:07:17","date_gmt":"2016-02-28T00:07:17","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1994"},"modified":"2024-08-21T17:11:47","modified_gmt":"2024-08-21T17:11:47","slug":"resolucao-comentada-dos-exercicios-de-vestibulares-sobre-termometria","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/fisica-termica\/termometria\/termometria-medida-de-temperatura\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-termometria\/","title":{"rendered":"Termometria – Resolu\u00e7\u00e3o"},"content":{"rendered":"

Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre<\/b><\/span><\/span><\/span> <\/b><\/p>\n

Termometria \u2013 Medida de temperatura \u2013 Escalas Termom\u00e9tricas<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span>01<\/b><\/span><\/span><\/span>–<\/b><\/span><\/span><\/span> I. subst\u00e2ncia termom\u00e9trica \u2013 g\u00e1s\u00a0 —\u00a0 grandeza termom\u00e9trica \u2013 volume do g\u00e1s.<\/b><\/span><\/span><\/p>\n

II. subst\u00e2ncia termom\u00e9trica \u2013 \u00e1lcool\u00a0 —\u00a0 grandeza termom\u00e9trica \u2013 volume do \u00e1lcool.<\/b><\/span><\/span><\/p>\n

III. subst\u00e2ncia termom\u00e9trica \u2013 merc\u00fario\u00a0 —\u00a0 grandeza termom\u00e9trica \u2013 volume do merc\u00fario.<\/b><\/span><\/span><\/p>\n

IV. subst\u00e2ncia termom\u00e9trica \u2013 ar\u00a0 —\u00a0 grandeza termom\u00e9trica \u2013 volume do ar.<\/b><\/span><\/span><\/p>\n

02<\/b><\/span><\/span><\/span>–<\/b><\/span><\/span><\/span> Para que o term\u00f4metro e a pessoa entrem em equil\u00edbrio t\u00e9rmico, ficando com a mesma temperatura. Assim, o term\u00f4metro indica a temperatura da pessoa.<\/b><\/span><\/span><\/p>\n

03-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>A temperatura \u00e9 a medida do grau de agita\u00e7\u00e3o molecular de um corpo, ou seja, quanto maior a temperatura, maior a velocidade m\u00e9dia das mol\u00e9culas de um corpo.<\/b><\/span><\/span><\/p>\n

04-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>I. Correta\u00a0 —\u00a0 calor \u00e9 energia em tr\u00e2nsito entre dois corpos que est\u00e3o \u00e0 temperaturas diferentes.<\/b><\/span><\/span><\/p>\n

II. Falsa\u00a0 —\u00a0 veja I.<\/b><\/span><\/span><\/p>\n

III. Correta\u00a0 —\u00a0 veja teoria<\/b><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/p>\n

05-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>0<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C e 273K correspondem \u00e0 mesma temperatura e consequentemente o n\u00edvel de vibra\u00e7\u00e3o das mol\u00e9culas \u00e9 o mesmo\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- B<\/b><\/span><\/span><\/p>\n

06-<\/b><\/span><\/span><\/span> R- B\u00a0<\/b><\/span><\/span>\u00a0—\u00a0 veja teoria<\/b><\/span><\/span><\/p>\n

07-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>A menor temperatura obtida \u00e9 o zero absoluto (0 K) que corresponde a -273<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0\u00a0<\/b><\/span><\/span>R-C<\/b><\/span><\/span><\/p>\n

08-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>Entre os dois pontos fixos as escalas Celsius e Kelvin possuem 100 unidades\u00a0 —\u00a0 assim, a cada varia\u00e7\u00e3o de 1<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C corresponde a uma varia\u00e7\u00e3o de 1K\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- A<\/b><\/span><\/span><\/p>\n

09-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>Cada varia\u00e7\u00e3o de 5<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C na escala Celsius corresponde uma varia\u00e7\u00e3o de 9<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F na escala Fahrenheit\u00a0 —\u00a0 regra de tr\u00eas\u00a0 —\u00a0 5<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C \u2013 9<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F\u00a0 —\u00a0 40<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C \u2013 X\u00a0<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F\u00a0 —\u00a0 5.X=40.9\u00a0 —\u00a0 X=360\/5\u00a0 —\u00a0\u00a0<\/b><\/span><\/span>X=72<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F<\/b><\/span><\/span><\/p>\n

10-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>A dist\u00e2ncia entre dois graus Celsius inteiros \u00e9 a mesma que entre dois graus Kelvin inteiros, pois a cada varia\u00e7\u00e3o de 1 grau na Celsius corresponde uma varia\u00e7\u00e3o tamb\u00e9m de 1 grau na Kelvin.<\/b><\/span><\/span><\/p>\n

11-<\/b><\/span><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>a) C=F=P\u00a0 —\u00a0 (P \u2013 0)\/(100 \u2013 0) = (P \u2013 32)\/(212 \u2013 32)\u00a0 —\u00a0 P\/5 = (F \u2013 32)\/9\u00a0 —\u00a0 9P=5F \u2013 160\u00a0 —\u00a0 4P= -160\u00a0 —\u00a0 P=- 40\u00a0 —<\/b><\/span><\/span><\/span><\/p>\n

P=F=C=\u00a0<\/b><\/span><\/span>-40<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C,<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F<\/b><\/span><\/span>\u00a0(quando a escala Celsius indicar -40<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C, a escala Fahrenheit indicar\u00e1 -40<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F)<\/b><\/span><\/span><\/p>\n

b) Cada varia\u00e7\u00e3o de 1\u00a0<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C corresponde a uma varia\u00e7\u00e3o de 1<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F e , como os pontos fixos dessas escalas s\u00e3o diferentes, elas\u00a0<\/b><\/span><\/span>jamais indicar\u00e3o o mesmo n\u00famero.<\/b><\/span><\/span><\/p>\n

12-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>(92- 0)\/(100 \u2013 0) = (F \u2013 32)\/(212 \u2013 32)\u00a0 —\u00a0 92\/5 = (F \u2013 32)\/9\u00a0 — 5F \u2013 160 = 828\u00a0 —\u00a0 F=988\/5\u00a0 —\u00a0\u00a0<\/b><\/span><\/span>F=197,6<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F<\/b><\/span><\/span><\/p>\n

13-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>Quando a Celsius marca\u00a0 \u201370<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 -70\/5 = (F \u2013 32)\/9\u00a0 —\u00a0 F=-94<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 quando a Celsius marca 40<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 — \u00a040\/5 = (F \u2013 32)\/9\u00a0 —\u00a0 F=104<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- A<\/b><\/span><\/span><\/p>\n

14-<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- A<\/b><\/span><\/span><\/p>\n

15-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>(C \u2013 0)\/(100 \u2013 0) = (SP \u2013 25)\/(54 \u2013 25)\u00a0 —\u00a0 C\/100 = (SP \u2013 25)\/29\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- C<\/b><\/span><\/span><\/p>\n

16-<\/b><\/span><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span><\/span>F=2C\u00a0 —\u00a0 (C \u2013 0)\/(100 \u2013 0)=(2C \u2013 32)\/(212 \u2013 32)\u00a0 —\u00a0 C\/5 = (2C \u2013 32)\/9\u00a0 —\u00a0 9C = 10C \u2013 160\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>C=160<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sup>C<\/b><\/span><\/span><\/span>\u00a0 — \u00a0F=2.160\u00a0 —\u00a0\u00a0<\/b><\/span><\/span><\/span>F=320<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/span><\/sup>F\u00a0 —\u00a0 R- A<\/b><\/span><\/span><\/span><\/p>\n

17-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>Deduzindo a equa\u00e7\u00e3o de convers\u00e3o\u00a0 —\u00a0 (W \u2013 (-40))\/(20 \u2013 (-40) = (C \u2013 0)\/(40 \u2013 0)\u00a0 —\u00a0 (W + 40)\/(20 + 40) = C\/40\u00a0 —\u00a0<\/b><\/span><\/span><\/p>\n

(W + 40)\/3 = C\/2\u00a0 —\u00a0 fus\u00e3o do gelo\u00a0 —\u00a0 C=0<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 (W + 40)\/3=0\/2\u00a0 —\u00a0<\/b><\/span><\/span>W=-40<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>W<\/b><\/span><\/span>\u00a0 —\u00a0 ebuli\u00e7\u00e3o da \u00e1gua\u00a0 —\u00a0 C=100<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0<\/b><\/span><\/span><\/p>\n

(W + 40)\/3=100\/2\u00a0 —\u00a0 W + 40 = 150\u00a0 —\u00a0\u00a0<\/b><\/span><\/span>W=110<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>W<\/b><\/span><\/span>\u00a0 —\u00a0\u00a0<\/b><\/span><\/span>R- B<\/b><\/span><\/span><\/p>\n

18-<\/b><\/span><\/span><\/span> R- D<\/b><\/span><\/span><\/p>\n

19-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>Em \u0394t=(26-21)=5s houve um aumento de canto de (180 \u2013 120)=60 vezes por minuto\u00a0 —\u00a0 portanto a taxa de aumento \u00e9 constante e de 60\/5=12 vezes por minuto por cada\u00a0\u00a0<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 com os grilos cantando 156 vezes por minuto, em rela\u00e7\u00e3o \u00e0 situa\u00e7\u00e3o inicial voc\u00ea ter\u00e1 (156 \u2013 120)=36 vezes de aumento por minuto\u00a0 —\u00a0 regra de tr\u00eas\u00a0 —\u00a0 cada 12 vezes a mais \u2013 aumento de 1<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 cada 36 vezes a mais \u2013\u00a0 aumento de x<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 X=3<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 como a temperatura inicial era 21<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C e houve um aumento de 3<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C, a temperatura final ser\u00e1 (21 + 3)=24<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- D<\/b><\/span><\/span><\/p>\n

20-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>R- B\u00a0 —\u00a0 veja teoria<\/b><\/span><\/span><\/p>\n

21-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>C=K \u2013 273\u00a0 —\u00a0 C=243 \u2013 273\u00a0 —\u00a0 C= – 30<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 20% de -30<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C= -6<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- D<\/b><\/span><\/span><\/p>\n

22-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>C\/5=(172 \u2013 32)\/9\u00a0 —\u00a0 C=78<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- B<\/b><\/span><\/span>
\n<\/b><\/span><\/span><\/p>\n

23-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>C\/5=(172 \u2013 32)\/9\u00a0 —\u00a0 C=78<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- B<\/b><\/span><\/span>
\n<\/b><\/span><\/span><\/p>\n

24-<\/b><\/span><\/span><\/span> (01) Falsa\u00a0 —\u00a0 n\u00e3o deve variar arbitrariamente, mas sim linearmente com a temperatura.<\/b><\/span><\/span><\/p>\n

(02) Correta\u00a0 —\u00a0 est\u00e1 variando linearmente com a temperatura.<\/b><\/span><\/span><\/p>\n

(04) Falsa\u00a0 —\u00a0 \u00e9 a medida do n\u00edvel (grau) de vibra\u00e7\u00e3o das mol\u00e9culas do corpo.<\/b><\/span><\/span><\/p>\n

(08) Falsa\u00a0 —\u00a0 veja teoria.<\/b><\/span><\/span><\/p>\n

(16) Correta\u00a0 —\u00a0 tendem a atingir a temperatura de equil\u00edbrio t\u00e9rmico.<\/b><\/span><\/span><\/p>\n

25-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>Como a temperatura varia linearmente com a altura da coluna l\u00edquida, podemos escrever:<\/b><\/span><\/span><\/p>\n

\"\".<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/p>\n

R- E<\/b><\/span><\/span><\/p>\n

26-<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

R- B<\/b><\/span><\/span><\/p>\n

27-<\/b><\/span><\/span><\/span><\/p>\n

Observe as escalas abaixo:<\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

R- A<\/b><\/span><\/span><\/p>\n

28-<\/b><\/span><\/span><\/span><\/p>\n

Para melhor visualiza\u00e7\u00e3o, coloquemos os dados na figura a seguir.<\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

R- B<\/b><\/span><\/span><\/p>\n

29-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>A equa\u00e7\u00e3o de convers\u00e3o entre essas escalas \u00e9:<\/b><\/span><\/span><\/p>\n

\"\". Fazendo T<\/b><\/span><\/span>C<\/b><\/span><\/span><\/sub>\u00a0= T<\/b><\/span><\/span>F<\/b><\/span><\/span><\/sub>\u00a0= T, vem:\u00a0\"\"\u00a0\u00a0\u00de\u00a0\u00a0 9<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/sub>T = 5<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/sub>T \u2013 160\u00a0 \u00de\u00a0\u00a0 4<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/sub>T = \u2013<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/sub>160\u00a0 \u00de\u00a0\u00a0 T = \u2013<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/sub>40.<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/sub>\u00a0<\/b><\/span><\/span><\/p>\n

R- D<\/b><\/span><\/span><\/p>\n

30-<\/b><\/span><\/span><\/span>\u00a0Equa\u00e7\u00e3o de convers\u00e3o entre essas escalas\u00a0 — ( F \u2013 32)\/9 = C\/5 = (K \u2013 273)\/5\u00a0 —\u00a0 substituindo C= – 271,25\u00a0<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 (F \u2013 32)\/9 = – 271,25\/5\u00a0 —\u00a0 F=54,25×9 + 32\u00a0 —\u00a0 F= – 456<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F\u00a0 —\u00a0 K= – 271,25 + 273\u00a0 —\u00a0 K = 1,75 K\u00a0 —\u00a0<\/b><\/span><\/span>\u00a0R- B<\/b><\/span><\/span><\/p>\n

31-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>Equa\u00e7\u00e3o de convers\u00e3o entre as escalas mencionadas\u00a0 —\u00a0 C\/5 = (F \u2013 32)\/9\u00a0 —\u00a0 C=5.(10,8 \u2013 32)\/9= – 108\/9\u00a0 —\u00a0 C= – 12<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0<\/b><\/span><\/span><\/p>\n

R- A<\/b><\/span><\/span><\/p>\n

32-<\/b><\/span><\/span><\/span>\u00a0<\/b><\/span><\/span>C\/5 = (F -32)\/9\u00a0 —\u00a0 C<\/b><\/span><\/span>1<\/b><\/span><\/span><\/sub>\/5= (-32 -32)\/9 \u00a0—\u00a0 C<\/b><\/span><\/span>1<\/b><\/span><\/span><\/sub>= – 35,6<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0 C\/5 = (F -32)\/9\u00a0 —\u00a0 C<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sub>\/5 = (23 \u2013 32)\/9\u00a0 —\u00a0 C<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sub>= – 5<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0\u00a0<\/b><\/span><\/span>R- A<\/b><\/span><\/span><\/p>\n

33-<\/b><\/span><\/span><\/span>\u00a070\/5 = (F \u2013 32)\/9\u00a0 —\u00a0 F=9.(-14) + 32\u00a0 —\u00a0 F= -94<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>F\u00a0 —\u00a0\u00a0<\/b><\/span><\/span>R- E\u00a0<\/b><\/span><\/span>\u00a0<\/b><\/span><\/span><\/p>\n

 <\/p>\n

34-<\/b><\/span><\/span><\/span>\u00a0O fato de o ouro met\u00e1lico se depositar sob o material s\u00f3lido ocorre devido \u00e0 sua maior\u00a0densidade\u00a0\u00a0—\u00a0 quando o am\u00e1lgama (mistura de ouro e merc\u00fario) \u00e9 aquecido com o ma\u00e7arico, o merc\u00fario se vaporiza, separando-se do ouro\u00a0 — isso ocorre porque\u00a0temperatura de ebuli\u00e7\u00e3o\u00a0do merc\u00fario \u00e9 menor que a do ouro\u00a0 —\u00a0 posteriormente esse merc\u00fario gasoso volta a transformar em merc\u00fario l\u00edquido devido \u00e0 sua baixatemperatura de liquefa\u00e7\u00e3o\u00a0 —\u00a0\u00a0R- D<\/b><\/span><\/span><\/p>\n

 <\/p>\n

35- <\/b><\/span><\/span><\/span>A partir dos dados fornecidos e como o enunciado afirma que a varia\u00e7\u00e3o \u00e9 linear,voc\u00ea pode <\/b><\/span><\/span><\/p>\n

\"\"<\/p>\n

construir o gr\u00e1fico temperatura (<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C) em fun\u00e7\u00e3o do tempo (ano)\u00a0 —\u00a0 (t \u2013 13,8)\/(2012 \u2013 2010) = (13,8 \u2013 13,35)\/(2010 \u2013 1995)\u00a0 —\u00a0<\/b><\/span><\/span><\/p>\n

(t \u2013 13,8)\/2 = 0,45\/15\u00a0 —\u00a0 t \u2013 13,8 = 0,03\u00a0 —\u00a0 t=13,86\u00a0<\/b><\/span><\/span>o<\/b><\/span><\/span><\/sup>C\u00a0 —\u00a0\u00a0<\/b><\/span><\/span>R- B<\/b><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os exerc\u00edcios<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Termometria \u2013 Medida de temperatura \u2013 Escalas Termom\u00e9tricas \u00a001– I. subst\u00e2ncia termom\u00e9trica \u2013 g\u00e1s\u00a0 —\u00a0 grandeza termom\u00e9trica \u2013 volume do g\u00e1s. II. subst\u00e2ncia termom\u00e9trica \u2013 \u00e1lcool\u00a0 —\u00a0 grandeza termom\u00e9trica \u2013 volume do \u00e1lcool. III. subst\u00e2ncia termom\u00e9trica \u2013 merc\u00fario\u00a0 —\u00a0 grandeza termom\u00e9trica \u2013 volume do merc\u00fario. IV. subst\u00e2ncia termom\u00e9trica \u2013 ar\u00a0 —\u00a0 grandeza termom\u00e9trica<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1991,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1994","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1994","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1994"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1994\/revisions"}],"predecessor-version":[{"id":10759,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1994\/revisions\/10759"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1991"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1994"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}