{"id":1856,"date":"2016-01-25T01:04:18","date_gmt":"2016-01-25T01:04:18","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1856"},"modified":"2024-11-08T13:14:32","modified_gmt":"2024-11-08T13:14:32","slug":"resolucao-comentada-dos-exercicios-de-vestibulares-sobre-galvanometro-como-amperimetro-e-como-voltimetro-ponte-de-wheatstone","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/eletricidade\/eletrodinamica\/galvanometro-como-amperimetro-e-como-voltimetro-ponte-de-wheatstone\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-galvanometro-como-amperimetro-e-como-voltimetro-ponte-de-wheatstone\/","title":{"rendered":"Ponte de Wheatstone – Resolu\u00e7\u00e3o EN"},"content":{"rendered":"

WHEATSTONE BRIDGE \u2013 RESOLUTION<\/span><\/h1>\n
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Commented resolution of entrance exam exercises on<\/span><\/b>\u00a0\u00a0<\/b><\/p>\n

Galvanometer as Ammeter and as\u00a0<\/span>\u00a0Voltmeter<\/span><\/span><\/a>\u00a0\u2013 Wheatstone Bridge<\/span><\/b><\/p>\n

01-<\/span><\/b>\u00a0\u00a0The full-scale current (i\u00a0<\/span><\/b>G<\/span><\/b><\/sub>\u00a0) of the galvanometer remains the same \u2014 what changes is the full-scale current (I) of the system (galvanometer + shunt resistance in parallel with it), which works as an ammeter, indicating a current greater than i\u00a0<\/span><\/b>G<\/span><\/b><\/sub>\u00a0\u00a0 \u2014\u00a0\u00a0\u00a0<\/span><\/b>R- B<\/span><\/b><\/p>\n

02-<\/span><\/b>\u00a0\u00a0Observe the figure below \u2014 U=U\u00a0<\/span><\/b>G<\/span><\/b><\/sub>\u00a0( 1 + R\u00a0<\/span><\/b>M<\/span><\/b><\/sub>\u00a0\/R\u00a0<\/span><\/b>G<\/span><\/b><\/sub>\u00a0) \u2014 10=1(1 + R\u00a0<\/span><\/b>M<\/span><\/b><\/sub>\u00a0\/10) \u2014\u00a0\u00a0\u00a0<\/span><\/b>R\u00a0<\/span><\/b>M<\/span><\/b><\/sub>\u00a0=90\u03a9<\/span><\/b><\/p>\n

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Of course the multiplication factor is 10 (a full scale voltage of 1V should indicate 10V) \u2014\u00a0\u00a0\u00a0<\/span><\/b>R- A<\/span><\/b><\/p>\n

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