{"id":1783,"date":"2016-01-11T22:19:35","date_gmt":"2016-01-11T22:19:35","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1783"},"modified":"2024-08-19T14:11:03","modified_gmt":"2024-08-19T14:11:03","slug":"serie-paralelo-caracteristicas","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/eletricidade\/eletrodinamica\/serie-paralelo-caracteristicas\/","title":{"rendered":"S\u00e9rie, paralelo, caracter\u00edsticas."},"content":{"rendered":"

Caracter\u00edsticas das associa\u00e7\u00f5es s\u00e9rie e paralelo<\/b><\/span><\/span><\/span><\/p>\n

Para se <\/b><\/span><\/span><\/span>resolver qualquer tipo de circuito <\/b><\/span><\/span><\/span>\u00e9 preciso conhecer as <\/b><\/span><\/span><\/span>principais caracter\u00edsticas das associa\u00e7\u00f5es\u00a0 s\u00e9rie e paralelo:<\/b><\/span><\/span><\/span><\/p>\n

Caracter\u00edsticas da associa\u00e7\u00e3o s\u00e9rie<\/b><\/span><\/span><\/span><\/p>\n

\"\" Todos<\/b><\/span><\/span><\/span> os resistores s\u00e3o <\/b><\/span><\/span><\/span>ligados um em seguida ao outro.\u00a0<\/b><\/span><\/span><\/span><\/p>\n

\"\" A <\/b><\/span><\/span><\/span>intensidade da\u00a0corrente el\u00e9trica i \u00e9 a mesma em todos os resistores<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0A <\/b><\/span><\/span><\/span>tens\u00e3o U nos terminais da associa\u00e7\u00e3o<\/b><\/span><\/span><\/span> (entre A e B) \u00e9 <\/b><\/span><\/span><\/span>igual \u00e0 soma das tens\u00f5es<\/b><\/span><\/span><\/span> em <\/b><\/span><\/span><\/span>cada resistor, ou seja,\u00a0U= U<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>+ U<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0+ U<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span><\/p>\n

\"\"\u00a0A <\/b><\/span><\/span><\/span>resist\u00eancia equivalente (R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span>) \u00e9 igual \u00e0 soma das resist\u00eancias parciais<\/b><\/span><\/span><\/span>\u00a0 \"\"\u00a0\u00a0<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/span>eq <\/b><\/span><\/span><\/sub><\/span>= R<\/b><\/span><\/span><\/span>1 <\/b><\/span><\/span><\/sub><\/span>+ R<\/b><\/span><\/span><\/span>2 <\/b><\/span><\/span><\/sub><\/span>+ R<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span><\/p>\n

\"\" Como a intensidade da corrente\u00a0i\u00a0\u00e9 a mesma em cada resistor, a pot\u00eancia<\/b><\/span><\/span><\/span> <\/b>el\u00e9trica total dissipada<\/b><\/span><\/span><\/span> ser\u00e1 <\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>t<\/b><\/span><\/span><\/sub><\/span>\u00a0= P<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0+ P<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0+ P<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>\u00a0= R<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>.i<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0+ R<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>.i<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0+ R<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>.i<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 \"\"\u00a0 P<\/b><\/span><\/span><\/span>t <\/b><\/span><\/span><\/sub><\/span>= (R<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0+ R<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0+ R<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span>).i<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>\u00a0 \"\"\u00a0<\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/span>t <\/b><\/span><\/span><\/sub><\/span>= R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span>.i<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n

F\u00f3rmulas v\u00e1lidas para a associa\u00e7\u00e3o s\u00e9rie<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

O que voc\u00ea deve saber, informa\u00e7\u00f5es e dicas<\/b><\/span><\/span><\/span><\/p>\n

\"\" Memorizar as caracter\u00edsticas acima sobre a associa\u00e7\u00e3o s\u00e9rie.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0\"\"<\/span> Procure entender esta explica\u00e7\u00e3o:<\/b><\/span><\/span><\/span> <\/b>Uma <\/b><\/span><\/span><\/span>situa\u00e7\u00e3o pr\u00e1tica<\/b><\/span><\/span><\/span> <\/b>bastante comum<\/b><\/span><\/span><\/span> nas <\/b><\/span><\/span><\/span>resid\u00eancias<\/b><\/span><\/span><\/span> e <\/b><\/span><\/span><\/span>nos hot\u00e9is<\/b><\/span><\/span><\/span> \u00e9 o chamado <\/b><\/span><\/span><\/span>\u201cinterruptor paralelo\u201d,<\/b><\/span><\/span><\/span> onde, <\/b><\/span><\/span><\/span>na realidade a liga\u00e7\u00e3o \u00e9 em s\u00e9rie<\/b><\/span><\/span><\/span>, na qual <\/b><\/span><\/span><\/span>\u00e9 poss\u00edvel ligar ou desligar uma determinada l\u00e2mpada, de forma independente, estando no ponto mais alto ou mais baixo de uma escada, da maneira indicada nas seq\u00fc\u00eancias abaixo.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\u00a0<\/span><\/p>\n

Caracter\u00edsticas da associa\u00e7\u00e3o paralelo<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

\"\" \u00a0Os <\/b><\/span><\/span><\/span>resistores s\u00e3o associados pelos seus terminais<\/b><\/span><\/span><\/span>, ou seja, <\/b><\/span><\/span><\/span>todos saem de um mesmo ponto e todos chegam a um mesmo ponto.<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0A <\/b><\/span><\/span><\/span>diferen\u00e7a de potencial (tens\u00e3o) U<\/b><\/span><\/span><\/span> de <\/b><\/span><\/span><\/span>toda a associa\u00e7\u00e3o (entre A e B) \u00e9 a mesma <\/b><\/span><\/span><\/span>para todos os resistores<\/b><\/span><\/span><\/span><\/p>\n

\"\" \u00a0A <\/b><\/span><\/span><\/span>corrente total i<\/b><\/span><\/span><\/span> \u00e9 a <\/b><\/span><\/span><\/span>soma das correntes parciais<\/b><\/span><\/span><\/span>, ou seja,\u00a0i = i<\/b><\/span><\/span><\/span>1<\/b><\/span><\/span><\/sub><\/span>\u00a0+ i<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sub><\/span>\u00a0+ i<\/b><\/span><\/span><\/span>3<\/b><\/span><\/span><\/sub><\/span><\/p>\n

F\u00f3rmulas v\u00e1lidas para a associa\u00e7\u00e3o paralelo<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

\"\" \u00a0C\u00e1lculo da <\/b><\/span><\/span><\/span>resist\u00eancia (Req) do resistor equivalente<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span><\/span>tr\u00eas processos:<\/b><\/span><\/span><\/span><\/p>\n

Tr\u00eas processos:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

3<\/b><\/span><\/span><\/span>o<\/b><\/span><\/span><\/sup><\/span>\u00a0\u2013<\/b><\/span><\/span><\/span>\u00a0Regra pr\u00e1tica:<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0quando <\/b><\/span><\/span><\/span>um<\/b><\/span><\/span><\/span> \u00e9 o <\/b><\/span><\/span><\/span>dobro <\/b><\/span><\/span><\/span>do outro, voc\u00ea <\/b><\/span><\/span><\/span>pega o maior e divide por tr\u00eas;<\/b><\/span><\/span><\/span><\/p>\n

\u00a0 quando <\/b><\/span><\/span><\/span>um <\/b><\/span><\/span><\/span>\u00e9 o <\/b><\/span><\/span><\/span>triplo<\/b><\/span><\/span><\/span> do outro, voc\u00ea <\/b><\/span><\/span><\/span>pega o maior e divide por quatro, <\/b><\/span><\/span><\/span>e assim por diante.<\/b><\/span><\/span><\/span><\/p>\n

\"\"\u00a0<\/span>dois resistores iguais<\/b><\/span><\/span><\/span>, voc\u00ea <\/b><\/span><\/span><\/span>divide o valor de um deles por dois;<\/b><\/span><\/span><\/span><\/p>\n

\u00a0\u00a0 <\/span>tr\u00eas resistores iguais<\/b><\/span><\/span><\/span>, voc\u00ea <\/b><\/span><\/span><\/span>divide o valor de um deles por tr\u00eas, <\/b><\/span><\/span><\/span>e assim por diante.\u00a0<\/b><\/span><\/span><\/span><\/p>\n

Em alguns casos essa regra pr\u00e1tica, quando o <\/b><\/span><\/span><\/span>n\u00famero n\u00e3o der exato<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>pode ser substitu\u00edda<\/b><\/span><\/span><\/span> por <\/b><\/span><\/span><\/span>uma das duas acima.<\/b><\/span><\/span><\/span><\/p>\n

O que voc\u00ea deve saber, informa\u00e7\u00f5es e dicas<\/b><\/span><\/span><\/span><\/p>\n

\u00a0\"\"<\/span> Memorizar as caracter\u00edsticas acima sobre a associa\u00e7\u00e3o paralelo.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\" \u00a0<\/span>Aten\u00e7\u00e3o para esse detalhe:<\/b><\/span><\/span><\/span> As <\/b><\/span><\/span><\/span>intensidades das correntes nos ramos<\/b><\/span><\/span><\/span> se <\/b><\/span><\/span><\/span>repartem <\/b><\/span><\/span><\/span>de modo que <\/b><\/span><\/span><\/span>sejam inversamente<\/b><\/span><\/span><\/span> <\/b>proporcionais \u00e0s respectivas resist\u00eancias<\/b><\/span><\/span><\/span>, isto \u00e9, no <\/b><\/span><\/span><\/span>ramo de menor resist\u00eancia h\u00e1 corrente<\/b><\/span><\/span><\/span> de <\/b><\/span><\/span><\/span>intensidade m\u00e1xima<\/b><\/span><\/span><\/span> e no ramo de <\/b><\/span><\/span><\/span>maior resist\u00eancia h\u00e1 corrente de intensidade m\u00ednima,<\/b><\/span><\/span><\/span> de modo que a <\/b><\/span><\/span><\/span>soma das correntes parciais seja\u00a0 igual \u00e0 corrente total<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Observe na <\/b><\/span><\/span><\/span>figura acima<\/b><\/span><\/span><\/span> que, como uma <\/b><\/span><\/span><\/span>resist\u00eancia \u00e9 o dobro da outra<\/b><\/span><\/span><\/span>, o <\/b><\/span><\/span><\/span>mesmo acontece com as correntes de modo que uma seja o dobro da outra e sua soma deve fornecer a corrente total.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

\"\" \u00a0Em <\/b><\/span><\/span><\/span>toda associa\u00e7\u00e3o paralelo,<\/b><\/span><\/span><\/span> o <\/b><\/span><\/span><\/span>valor da resist\u00eancia do resistor equivalente<\/b><\/span><\/span><\/span> \u00e9 <\/b><\/span><\/span><\/span>sempre menor<\/b><\/span><\/span><\/span> que <\/b><\/span><\/span><\/span>a de qualquer resistor da associa\u00e7\u00e3o<\/b><\/span><\/span><\/span>, pois na<\/b><\/span><\/span><\/span>resist\u00eancia equivalente passa a maior corrente e conseq\u00fcentemente ter\u00e1 a menor resist\u00eancia, pois nela, U \u00e9 constante..<\/b><\/span><\/span><\/span><\/p>\n

\"\" \u00a0Numa <\/b><\/span><\/span><\/span>associa\u00e7\u00e3o paralelo<\/b><\/span><\/span><\/span>, \u00e0 <\/b><\/span><\/span><\/span>medida que voc\u00ea for acrescentando resistores<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span><\/span>resist\u00eancia equivalente (R<\/b><\/span><\/span><\/span>eq<\/b><\/span><\/span><\/sub><\/span>) vai diminuindo e a corrente total vai aumentando.<\/b><\/span><\/span><\/span><\/b><\/p>\n

Por <\/b><\/span><\/span><\/span>esse motivo, nas resid\u00eancias, pr\u00e9dios, empresas, etc.,<\/b><\/span><\/span><\/span> existem <\/b><\/span><\/span><\/span>disjuntores <\/b><\/span><\/span><\/span>que <\/b><\/span><\/span><\/span>desligam o<\/b><\/span><\/span><\/span> <\/b>circuito quando muitos dispositivos el\u00e9tricos s\u00e3o ligados simultaneamente, evitando sobrecarga el\u00e9trica que pode causar inc\u00eandios.<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Confira os exerc\u00edcios com resolu\u00e7\u00f5es comentadas!<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

Caracter\u00edsticas das associa\u00e7\u00f5es s\u00e9rie e paralelo Para se resolver qualquer tipo de circuito \u00e9 preciso conhecer as principais caracter\u00edsticas das associa\u00e7\u00f5es\u00a0 s\u00e9rie e paralelo: Caracter\u00edsticas da associa\u00e7\u00e3o s\u00e9rie Todos os resistores s\u00e3o ligados um em seguida ao outro.\u00a0 A intensidade da\u00a0corrente el\u00e9trica i \u00e9 a mesma em todos os resistores \u00a0A tens\u00e3o U nos terminais da associa\u00e7\u00e3o (entre A e<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1676,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1783","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1783","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1783"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1783\/revisions"}],"predecessor-version":[{"id":10517,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1783\/revisions\/10517"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1676"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1783"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}