{"id":1574,"date":"2015-11-28T03:41:58","date_gmt":"2015-11-28T03:41:58","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1574"},"modified":"2024-08-23T14:32:31","modified_gmt":"2024-08-23T14:32:31","slug":"exercicios-de-vestibulares-com-resolucao-comentada-sobre-principio-de-pascal-prensa-hidraulica","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/hidrostatica\/principio-de-pascal\/exercicios-de-vestibulares-com-resolucao-comentada-sobre-principio-de-pascal-prensa-hidraulica\/","title":{"rendered":"Princ\u00edpio de Pascal \u2013 Prensa hidr\u00e1ulica &#8211; Resolu\u00e7\u00e3o"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Princ\u00edpio de Pascal \u2013 Prensa hidr\u00e1ulica<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>01-(CPS-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>No in\u00edcio do s\u00e9culo XX, a ind\u00fastria e o com\u00e9rcio da cidade de S\u00e3o Paulo possibilitaram uma qualidade de vida melhor para seus habitantes. Um dos h\u00e1bitos saud\u00e1veis, ligados \u00e0 higieniza\u00e7\u00e3o bucal, foi a utiliza\u00e7\u00e3o de tubos de pasta dental e as respectivas escovas de dente.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_cd0f635f.jpg\" alt=\"\" width=\"369\" height=\"153\" name=\"Imagem 39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considerando um tubo contendo pasta dental de densidade homog\u00eanea, uma pessoa resolve apert\u00e1-lo. A press\u00e3o exercida sobre a pasta, dentro do tubo, ser\u00e1:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) maior no fundo do tubo, se apertar no fundo.\u00a0\u00a0\u00a0\u00a0\u00a0 b) menor no fundo do tubo, se apertar perto do bico de sa\u00edda.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) maior no meio do tubo, se apertar no meio.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) menor no fundo do tubo, se apertar no meio.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) igual em todos os pontos, qualquer que seja o local apertado.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>02-(CFT-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O sistema de freio hidr\u00e1ulico de um ve\u00edculo est\u00e1 baseado no princ\u00edpio<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_2223f34b.jpg\" alt=\"\" width=\"153\" height=\"150\" name=\"Imagem 40\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) de Pascal.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) de Arquimedes.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) da a\u00e7\u00e3o e rea\u00e7\u00e3o.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) da in\u00e9rcia.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>03-(UFSM-RS)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um bra\u00e7o mec\u00e2nico de um trator usado para fazer valetas tem um sistema hidr\u00e1ulico que se comp\u00f5e, basicamente, de dois cilindros conectados por uma mangueira resistente a altas press\u00f5es, todos preenchidos com \u00f3leo.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_a86c5271.jpg\" alt=\"\" width=\"343\" height=\"177\" name=\"Imagem 41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Se, no equil\u00edbrio, P \u00e9 a press\u00e3o num cilindro, a press\u00e3o no outro, que tem \u00e1rea 10 vezes maior, \u00e9<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_24b985c9.png\" alt=\"\" width=\"755\" height=\"17\" name=\"Imagem 66\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>04-(CFT-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A figura a seguir mostra, de maneira esquem\u00e1tica, como funciona o freio de um autom\u00f3vel. Ao pressionar o pedal 1 empurramos o \u00f3leo que se encontra no cilindro 2, que passa para o cilindro 3 onde aciona o freio 4, agindo sobre a roda 5.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_aba7195b.jpg\" alt=\"\" width=\"430\" height=\"142\" name=\"Imagem 42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Determine se o freio \u00e9 uma m\u00e1quina que amplia deslocamento ou for\u00e7a. Justifique.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>05-(UNIDERP-MS)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A figura mostra o funcionamento de uma prensa hidr\u00e1ulica para comprimir um fardo.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_6d6d7d3d.jpg\" alt=\"\" width=\"526\" height=\"181\" name=\"Imagem 43\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A rela\u00e7\u00e3o entre as intensidades das for\u00e7as F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0equivale a:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_8f1931ee.png\" alt=\"\" width=\"755\" height=\"21\" name=\"Imagem 67\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>06-(UFF-RJ) <\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma prensa hidr\u00e1ulica, sendo utilizada como elevador de uma carro de peso P, encontra-se em equil\u00edbrio, conforme a figura.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>As sec\u00e7\u00f5es retas dos pist\u00f5es s\u00e3o indicadas por S<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e S<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, tendo-se S<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=4S<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_ab7e3bab.jpg\" alt=\"\" width=\"416\" height=\"161\" name=\"Imagem 44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A for\u00e7a exercida sobre o fluido tem intensidade F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e a for\u00e7a exercida pelo fluido tem intensidade F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. A situa\u00e7\u00e3o descrita obedece:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) ao Princ\u00edpio de Arquimedes e, pelas leis de Newton, conclui-se que F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=P;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) ao Princ\u00edpio de Pascal e, pelas leis de a\u00e7\u00e3o e rea\u00e7\u00e3o e de conserva\u00e7\u00e3o da emergia mec\u00e2nica, conclui-se que F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=4F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=P;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) ao Princ\u00edpio de Pascal e, pela lei da conserva\u00e7\u00e3o da energia, conclui-se que F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=4F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1\u00a0<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u2260 P;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) apenas \u00e0s leis de Newton e F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=P;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) apenas \u00e0 lei de conserva\u00e7\u00e3o de energia<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>07-(CEFET-RS)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A figura representa um elevador hidr\u00e1ulico de um posto de lavagem de autom\u00f3veis.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_64c98077.jpg\" alt=\"\" width=\"433\" height=\"172\" name=\"Imagem 45\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Ele \u00e9 acionado atrav\u00e9s de um cilindro de \u00e1rea 3.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-5<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. O autom\u00f3vel a ser elevado tem massa 3.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>kg e est\u00e1 sobre o \u00eambolo de \u00e1rea 6.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. Considere acelera\u00e7\u00e3o da gravidade como sendo g= 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/sub><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual deve ser a press\u00e3o exercida pelo cilindro (acima da atmosf\u00e9rica) para equilibrar o autom\u00f3vel (imin\u00eancia de iniciar a subida)?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Qual ser\u00e1 o deslocamento do cilindro para elevar o autom\u00f3vel de 20cm?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>08-(FGV-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O macaco hidr\u00e1ulico consta de dois \u00eambolos: um estreito, que comprime o \u00f3leo, e outro largo, que suspende a carga. Um sistema de v\u00e1lvulas permite que uma nova quantidade de \u00f3leo entre no mecanismo sem que haja retorno do \u00f3leo j\u00e1 comprimido. Para multiplicar a for\u00e7a empregada, uma alavanca \u00e9 conectada ao corpo do macaco.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_7faeb608.jpg\" alt=\"\" width=\"523\" height=\"152\" name=\"Imagem 46\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Tendo perdido a alavanca do macaco, um caminhoneiro de massa 80 kg, usando seu peso para pressionar o \u00eambolo pequeno com o p\u00e9, considerando que o sistema de v\u00e1lvulas n\u00e3o interfira significativamente sobre a pressuriza\u00e7\u00e3o do \u00f3leo, poder\u00e1 suspender uma carga m\u00e1xima, em kg, de<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dados: di\u00e2metro do \u00eambolo menor = 1,0 cm; di\u00e2metro do \u00eambolo maior = 6,0 cm; acelera\u00e7\u00e3o da gravidade = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_67707ea6.png\" alt=\"\" width=\"756\" height=\"16\" name=\"Imagem 68\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>09-(UFJF-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um grupo de alunos resolveu montar um guindaste hidr\u00e1ulico para uma feira de ci\u00eancias (veja figura).<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_f4d9a880.jpg\" alt=\"\" width=\"547\" height=\"213\" name=\"Imagem 47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Para isso resolveram utilizar duas seringas. Uma seringa tem di\u00e2metro D<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=2cm e a outra D<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=1cm. Sabendo que o m\u00f3dulo da for\u00e7a m\u00e1xima que o motor permite produzir \u00e9 de 2N, qual o valor m\u00e1ximo da massa M que o guindaste poder\u00e1 erguer? (g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_89665c53.png\" alt=\"\" width=\"756\" height=\"19\" name=\"Imagem 69\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>10-(UFMG-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um sistema hidr\u00e1ulico tem tr\u00eas \u00eambolos m\u00f3veis L, M e N com \u00e1rea A, 2A e 3A, como mostra a figura.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_8c55edfe.jpg\" alt=\"\" width=\"482\" height=\"135\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Quantidades diferentes de blocos s\u00e3o colocadas sobre cada \u00eambolo.\u00a0 Todos os blocos t\u00eam o mesmo peso. Para que, em equil\u00edbrio, os \u00eambolos continuem na mesma altura, o n\u00famero de blocos colocados sobre os \u00eambolos L, M e N podem ser, respectivamente:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 1, 2 e 3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 1,4 e 9\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 3,2 e 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 9,4 e 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 8,2 e 1<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>11-(UFPE-PE)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma for\u00e7a vertical de intensidade F, atuando sobre o \u00eambolo menor de uma prensa hidr\u00e1ulica, mant\u00e9m elevado um peso P = 400 N, como mostra a figura.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_4931fcf.jpg\" alt=\"\" width=\"370\" height=\"138\" name=\"Imagem 49\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Sabendo que a \u00e1rea do \u00eambolo maior \u00e9 8 vezes a \u00e1rea menor, determine o valor de F, em newtons.<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #0000cc;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>12-(FUVEST-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere o arranjo da figura, onde um l\u00edquido est\u00e1 confinado na regi\u00e3o delimitada pelos \u00eambolos A e B, de \u00e1reas a=80cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e b=20cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, respectivamente.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_1a072f04.jpg\" alt=\"\" width=\"456\" height=\"143\" name=\"Imagem 50\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O sistema est\u00e1 em equil\u00edbrio. Despreze os pesos dos \u00eambolos e os atritos. Se m<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=4,0 kg, qual o valor de m<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>?<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_d0bebb67.png\" alt=\"\" width=\"756\" height=\"18\" name=\"Imagem 70\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>13-(UFRGS)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa que preenche corretamente as lacunas do texto que segue, na ordem em que aparecem.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A figura a seguir representa uma prensa hidr\u00e1ulica composta por dois pist\u00f5es, de di\u00e2metros d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. O motor aplica uma for\u00e7a axial de intensidade F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 100 N no pist\u00e3o de di\u00e2metro d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 0,05 m. Para que se possa obter uma for\u00e7a de intensidade F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 10.000 N no pist\u00e3o de di\u00e2metro d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, esse di\u00e2metro deve ser igual a ___________, e a press\u00e3o transmitida ser\u00e1 de ____________.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_6c61ea76.jpg\" alt=\"\" width=\"533\" height=\"164\" name=\"Imagem 51\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 0,25 m; 50,9 kPa\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 0,50 m; 12,7 kPa\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 0,50 m; 509 Pa\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 0,12 m; 50,9 Pa<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 0,12 m; 12,7 Pa<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>14-(UNESP-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>As \u00e1reas dos pist\u00f5es do dispositivo hidr\u00e1ulico da figura mant\u00eam a rela\u00e7\u00e3o 50:2. Verifica-se que um peso p, quando colocado sobre o pist\u00e3o maior, \u00e9 equilibrado por uma for\u00e7a de 30N no pist\u00e3o menor, sem que o n\u00edvel do fluido nas duas se altere.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_e366ed20.jpg\" alt=\"\" width=\"354\" height=\"181\" name=\"Imagem 52\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O peso p vale:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_24148481.png\" alt=\"\" width=\"756\" height=\"21\" name=\"Imagem 71\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>15-(PUC-RJ)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_196df90f.jpg\" alt=\"\" width=\"332\" height=\"131\" name=\"Imagem 53\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um bloco de massa m = 9000 kg \u00e9 colocado sobre um elevador hidr\u00e1ulico como mostra a figura anterior. A raz\u00e3o entre o di\u00e2metro do pist\u00e3o (d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>P<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>) que segura a base do elevador e o di\u00e2metro (d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>) onde deve-se aplicar a for\u00e7a F \u00e9 de d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>P<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\/ d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 30. Encontre a for\u00e7a necess\u00e1ria para se levantar o bloco com velocidade constante. Considere g = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e despreze os atritos.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 100 N\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 300 N\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 600 N\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 900 N\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 1000 N<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>16-(UNB-DF)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Temos dois tubos cil\u00edndricos A e B de di\u00e2metro D e D\/4, respectivamente.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_42f3863f.jpg\" alt=\"\" width=\"302\" height=\"133\" name=\"Imagem 54\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Os cilindros formam um sistema de macaco hidr\u00e1ulico e os \u00eambolos s\u00e3o m\u00f3veis. Considerando o sistema em equil\u00edbrio e desprezando o peso dos \u00eambolos, ache a raz\u00e3o entre as intensidades \u00a0das for\u00e7as F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>17-(UERJ-RJ)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um adestrador quer saber o peso de um elefante.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_d5c0fe91.jpg\" alt=\"\" width=\"333\" height=\"143\" name=\"Imagem 55\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Utilizando uma prensa hidr\u00e1ulica, consegue equilibrar o elefante sobre um pist\u00e3o de 2000cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de \u00e1rea, exercendo uma for\u00e7a vertical F equivalente a 200N, de cima para baixo, sobre o outro pist\u00e3o da prensa, cuja \u00e1rea \u00e9 igual a 25cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. Calcule o peso do elefante.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>18-(UFRS-RS)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A figura mostra tr\u00eas tubos cil\u00edndricos interligados entre si e contendo um l\u00edquido em equil\u00edbrio est\u00e1tico. Cada tubo possui um \u00eambolo, sendo a \u00e1rea da sec\u00e7\u00e3o reta do tubo 1 a metade da \u00e1rea da sec\u00e7\u00e3o reta do tubo 2 e da do tubo 3; os \u00eambolos se encontram todos no mesmo n\u00edvel (conforme a figura a seguir). O l\u00edquido faz uma for\u00e7a de 200N no \u00eambolo 1.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>As for\u00e7as que os \u00eambolos 2 e 3, respectivamente, fazem no l\u00edquido valem<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_95de5ce0.jpg\" alt=\"\" width=\"417\" height=\"158\" name=\"Imagem 56\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 200 N e 200 N. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 400 N e 400 N. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 100 N e 100 N. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 800 N e 800 N. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 800 N e 400 N.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>19-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O diagrama da figura mostra o principio do sistema hidr\u00e1ulico do freio de um autom\u00f3vel.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_77022b6b.jpg\" alt=\"\" width=\"409\" height=\"215\" name=\"Imagem 57\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Quando uma for\u00e7a de 50N \u00e9 exercida no pedal, qual a for\u00e7a aplicada pelo \u00eambolo de 80mm\u00b2 de \u00e1rea?<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_c0923681.png\" alt=\"\" width=\"755\" height=\"19\" name=\"Imagem 72\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>20-(FATEC-SP) <\/b><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um esquema simplificado de uma prensa hidr\u00e1ulica est\u00e1 mostrado na figura a seguir. Pode-se fazer uso de uma alavanca para transmitir uma for\u00e7a aplicada \u00e0 sua extremidade, amplificando seu efeito v\u00e1rias vezes.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_761909c.jpg\" alt=\"\" width=\"414\" height=\"152\" name=\"Imagem 58\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Supondo que se aplique uma for\u00e7a de 10N \u00e1 extremidade A da alavanca e sabendo que a raz\u00e3o entre a \u00e1rea do \u00eambolo maior pela \u00e1rea do \u00eambolo menor \u00e9 de 5, o m\u00f3dulo da for\u00e7a\u00a0<\/b><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>que o \u00eambolo maior aplicar\u00e1 sobre a carga ser\u00e1 de:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 4 N \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 20 N \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 50 N \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 100 N \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 200 N<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>21-(CFT-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Analise a situa\u00e7\u00e3o a seguir representada.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_e3796f74.jpg\" alt=\"\" width=\"506\" height=\"159\" name=\"Imagem 59\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O aumento de press\u00e3o em todas as partes do fluido armazenado no recipiente est\u00e1 relacionado ao princ\u00edpio de<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_e2aac5a6.png\" alt=\"\" width=\"756\" height=\"16\" name=\"Imagem 73\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>22-(CFT-MG)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O esquema seguinte ilustra o funcionamento de uma espingarda de ar comprimido.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_da0852eb.jpg\" alt=\"\" width=\"631\" height=\"145\" name=\"Imagem 60\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O pist\u00e3o dessa espingarda, de \u00e1rea de se\u00e7\u00e3o igual a 10 \u03c0cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, ao ser empurrado por uma forca constante de 4000 N, comprime o ar no cilindro e impulsiona, atrav\u00e9s do cano de 1,00 m de comprimento dessa arma, um proj\u00e9til, conhecido como chumbinho, de massa igual a 1,0 g e \u00e1rea de se\u00e7\u00e3o igual a 0,05 \u03c0cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Admitindo que perdas de press\u00e3o e o atrito entre o chumbinho e o cano sejam desprez\u00edveis, a velocidade do proj\u00e9til, em m\/s, imediatamente ap\u00f3s ser expelido dessa arma, e igual a<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_c77c9cc9.png\" alt=\"\" width=\"755\" height=\"19\" name=\"Imagem 74\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>23-(UFSC-SC)<\/b><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> \u2013 Quest\u00e3o discursiva.<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_2bb7e96.jpg\" alt=\"\" width=\"654\" height=\"121\" name=\"Imagem 61\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_351781df.jpg\" alt=\"\" width=\"775\" height=\"274\" name=\"Imagem 62\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual o tipo de alavanca que o pedal de freio representa, na forma como \u00e9 aqui apresentado?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Enuncie o Princ\u00edpio de Pascal.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Com base em princ\u00edpios de f\u00edsica e explicitando o racioc\u00ednio matem\u00e1tico, determine a for\u00e7a que o pist\u00e3o 2 exerce sobre a pastilha de freio, supondo que o motorista empurrou o pedal at\u00e9 o fundo e para isto aplicou uma for\u00e7a (<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_bdb86b3c.jpg\" alt=\"\" width=\"12\" height=\"21\" name=\"Imagem 63\" align=\"BOTTOM\" border=\"0\" \/>) de intensidade 100 N.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>24-(UFRN-RN)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_4652a77.jpg\" alt=\"\" width=\"653\" height=\"129\" name=\"Imagem 64\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Do ponto de vista da F\u00edsica, o sistema de freios dos carros atuais \u00e9 formado por uma alavanca e por uma prensa hidr\u00e1ulica. Enquanto a alavanca tem a capacidade\u00a0 de amplia\u00e7\u00e3o da for\u00e7a aplicada por um fator igual \u00e0 raz\u00e3o direta de seus bra\u00e7os, a prensa hidr\u00e1ulica amplia a for\u00e7a da alavanca na raz\u00e3o direta de suas \u00e1reas. Finalmente, a for\u00e7a resultante aciona os freios, conforme mostrado na Figura, fazendo o ve\u00edculo parar.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hidrostatica\/pascal\/i_6707d860d5005463_html_832e23d2.jpg\" alt=\"\" width=\"523\" height=\"170\" name=\"Imagem 65\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere que a alavanca tem bra\u00e7o maior,\u00a0 L, igual a 40cm e bra\u00e7o menor , l, igual a 10cm, e a prensa hidr\u00e1ulica apresenta \u00eambolos com \u00e1rea maior, A, oito vezes maior que a \u00e1rea menor, a. Levando em considera\u00e7\u00e3o as caracter\u00edsticas descritas\u00a0 acima, tal sistema de freios \u00e9 capaz de fazer a for\u00e7a exercida no pedal dos freios, pelo motorista, aumentar<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A) 32 vezes. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B) 12 vezes\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>C) 24 vezes. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>D) 16 vezes.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><span style=\"color: #000080;\"><a style=\"color: #000080;\" title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Princ\u00edpio de Pascal e Prensa hidr\u00e1ulica\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/mecanica\/hidrostatica\/principio-de-pascal\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-principio-de-pascal-e-prensa-hidraulica\/\">Confira a resolu\u00e7\u00e3o comentada dos exerc\u00edcios<\/a><\/span><\/h3>\n<p><span style=\"color: #000080;\">\u00a0<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre Princ\u00edpio de Pascal \u2013 Prensa hidr\u00e1ulica 01-(CPS-SP) No in\u00edcio do s\u00e9culo XX, a ind\u00fastria e o com\u00e9rcio da cidade de S\u00e3o Paulo possibilitaram uma qualidade de vida melhor para seus habitantes. Um dos h\u00e1bitos saud\u00e1veis, ligados \u00e0 higieniza\u00e7\u00e3o bucal, foi a utiliza\u00e7\u00e3o de tubos de pasta dental e as respectivas escovas de dente.<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1572,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1574","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1574","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1574"}],"version-history":[{"count":4,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1574\/revisions"}],"predecessor-version":[{"id":10891,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1574\/revisions\/10891"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1572"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1574"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}