{"id":1482,"date":"2015-11-02T21:55:15","date_gmt":"2015-11-02T21:55:15","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1482"},"modified":"2024-08-23T14:17:15","modified_gmt":"2024-08-23T14:17:15","slug":"exercicios-de-vestibulares-com-resolucao-comentada-sobre-estatica-de-um-ponto-material","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/estatica\/estatica-de-um-ponto-material\/exercicios-de-vestibulares-com-resolucao-comentada-sobre-estatica-de-um-ponto-material\/","title":{"rendered":"Est\u00e1tica de um Ponto Material &#8211; Exerc\u00edcios"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Est\u00e1tica de um Ponto Material<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>01-(Ufrrj-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A figura a seguir mostra um atleta de gin\u00e1stica ol\u00edmpica no aparelho de argolas. O ginasta encontra-se parado na posi\u00e7\u00e3o mostrada.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Assinale qual dentre as alternativas a seguir a que melhor representa as for\u00e7as que atuam sobre ele, desprezando-se as for\u00e7as do ar.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"LEFT\"><span style=\"color: #4f81bd;\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_ae6f835e.png\" alt=\"\" width=\"775\" height=\"146\" name=\"Imagem 98\" align=\"BOTTOM\" border=\"0\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>02- (PUC-PR)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Duas esferas r\u00edgidas 1 e 2, de mesmo di\u00e2metro, est\u00e3o em equil\u00edbrio dentro de uma caixa, como mostra a figura a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_af9ea23c.jpg\" alt=\"\" width=\"762\" height=\"137\" name=\"Imagem 2\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considerando nulo o atrito entre todas as superf\u00edcies, assinale o diagrama que representa corretamente as for\u00e7as de contato que agem sobre a esfera 2 nos pontos A, B e C.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>03-(CFT-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> As figuras 1 e 2 a seguir representam, respectivamente, todas as for\u00e7as, constantes e coplanares, que atuam sobre uma part\u00edcula e o diagrama da soma vetorial destas for\u00e7as.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_4885238e.jpg\" alt=\"\" width=\"346\" height=\"154\" name=\"Imagem 3\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Com base nestas informa\u00e7\u00f5es, pode-se afirmar que a part\u00edcula certamente estar\u00e1 em<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) repouso.\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) movimento retil\u00edneo uniforme.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) equil\u00edbrio.\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) movimento circular uniforme.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>04-(PUC-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um corpo est\u00e1 sujeito a um sistema de tr\u00eas for\u00e7as concorrentes. As intensidades de duas delas s\u00e3o 5N e 20N. Quanto a intensidade da terceira for\u00e7a f, para que haja equil\u00edbrio deve satisfazer \u00e0 desigualdade:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_d8fb0f99.jpg\" alt=\"\" width=\"734\" height=\"27\" name=\"Imagem 4\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>05-(Cesgranrio)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um corpo de peso P encontra-se em equil\u00edbrio, devido \u00e0 a\u00e7\u00e3o da for\u00e7a F, como indica a figura a seguir<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_834f4b53.jpg\" alt=\"\" width=\"274\" height=\"189\" name=\"graphics20\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Os pontos A, B e C s\u00e3o os pontos de contato entre os fios e a superf\u00edcie. A for\u00e7a que a superf\u00edcie exerce sobre os fios nos pontos A, B e C s\u00e3o, respectivamente:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_7a780091.png\" alt=\"\" width=\"774\" height=\"21\" name=\"Imagem 6\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>06-(UFMG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Dois \u00edm\u00e3s, presos nas extremidades de dois fios finos, est\u00e3o em equil\u00edbrio, alinhados verticalmente, como mostrado nesta figura:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_d238d08f.jpg\" alt=\"\" width=\"280\" height=\"173\" name=\"graphics21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Nessas condi\u00e7\u00f5es, o m\u00f3dulo da tens\u00e3o no fio que est\u00e1 preso no \u00edm\u00e3 de cima \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) igual ao m\u00f3dulo da tens\u00e3o no fio de baixo.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) igual ao m\u00f3dulo do peso desse \u00edm\u00e3.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) maior que o m\u00f3dulo do peso desse \u00edm\u00e3.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) menor que o m\u00f3dulo da tens\u00e3o no fio de baixo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) nada se pode afirmar.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>07- UNIFOR-CE)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Com 6 peda\u00e7os iguais de corda e tr\u00eas corpos de mesma massa e mesmo formato, um estudante fez as montagens representadas abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_fbcfe8d1.jpg\" alt=\"\" width=\"445\" height=\"130\" name=\"graphics22\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Nos peda\u00e7os de corda a intensidade da for\u00e7a de tra\u00e7\u00e3o \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(A) a mesma nas montagens 1, 2 e 3.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(B) maior na montagem 3 que na 2.\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(C) maior na montagem 2 que na 3.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(D) a mesma nas montagens 2 e 3 e menor que na 1.\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(E) a mesma nas montagens 2 e 3 e maior que na 1.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>08-(AFA)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Na figura abaixo, o \u00e2ngulo \u03b8 vale 30<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, e a rela\u00e7\u00e3o entre as massas m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0tem valor 3\/2.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_fdca0619.jpg\" alt=\"\" width=\"281\" height=\"179\" name=\"graphics23\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Qual deve ser o valor do coeficiente de atrito entre o bloco 2 e o plano, para que o sistema permane\u00e7a em equil\u00edbrio?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>09-(CFT-CE)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um quadro de massa m = 6,0 kg se encontra em equil\u00edbrio pendurado ao teto pelos fios 1 e 2, que fazem com a horizontal os \u00e2ngulos\u00a0 \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 60\u00b0 e\u00a0 \u03b8<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0= 30\u00b0, conforme a figura.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_93da35e.jpg\" alt=\"\" width=\"217\" height=\"177\" name=\"Imagem 9\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Adotando g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, calcule as tra\u00e7\u00f5es nos fios 1 e 2.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dados: sen30\u00b0 = cos60\u00b0 = 1\/2\u00a0 &#8212;\u00a0 cos30\u00b0 = sen60\u00b0 =\u00a0 (\u221a3)\/2<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>10-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um bloco de peso P \u00e9 suspenso por dois fios de massa desprez\u00edvel, presos a paredes em A e B, como mostra a figura adiante.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_9cc1b319.jpg\" alt=\"\" width=\"196\" height=\"160\" name=\"graphics24\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Pode-se afirmar que o m\u00f3dulo da for\u00e7a que tenciona o fio preso em B, vale:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_6bf8d275.png\" alt=\"\" width=\"774\" height=\"19\" name=\"graphics25\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>11-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Os garotos A e B da figura puxam, por meio de cordas, uma caixa de 40kg, que repousa sobre uma superf\u00edcie horizontal, aplicando for\u00e7as paralelas a essa superf\u00edcie e perpendiculares entre si, de intensidades, 160N e 120N, respectivamente. \u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_58ee664.jpg\" alt=\"\" width=\"384\" height=\"171\" name=\"Imagem 11\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O garoto C, para impedir que a caixa se desloque,aplica outra for\u00e7a horizontal, em determinada dire\u00e7\u00e3o e sentido. Desprezando o atrito entre a caixa e a superf\u00edcie de apoio, a for\u00e7a aplicada pelo garoto C tem intensidade de:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_a44c0e0a.png\" alt=\"\" width=\"774\" height=\"19\" name=\"graphics26\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>12-(UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Uma das modalidades de gin\u00e1stica ol\u00edmpica \u00e9 a das argolas. Nessa modalidade, os m\u00fasculos mais solicitados s\u00e3o os dos bra\u00e7os, que suportam as cargas horizontais, e os da regi\u00e3o dorsal, que suportam os esfor\u00e7os verticais. Considerando um atleta cuja massa \u00e9 de 60 kg e sendo os comprimentos indicados na figura H = 3,0 m; L = 1,5 m e d = 0,5 m, responda:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_61e22694.jpg\" alt=\"\" width=\"348\" height=\"190\" name=\"graphics27\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual a tens\u00e3o em cada corda quando o atleta se encontra pendurado no in\u00edcio do exerc\u00edcio com os bra\u00e7os na vertical?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Quando o atleta abre os bra\u00e7os na horizontal, qual a componente horizontal da tens\u00e3o em cada corda?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>13-(UEL-PR)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> As placas I, II, III, IV e V est\u00e3o submetidas a for\u00e7as cujas dire\u00e7\u00f5es est\u00e3o indicadas no esquema e suas respectivas intensidades devem ser ajustadas para que a resultante seja nula e as placas fiquem em equil\u00edbrio est\u00e1tico.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_99ee859c.jpg\" alt=\"\" width=\"760\" height=\"140\" name=\"Imagem 13\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Em uma das placas, o acerto das intensidades das for\u00e7as para obter o equil\u00edbrio est\u00e1tico \u00e9 imposs\u00edvel. Essa placa \u00e9 a<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_be77bb10.png\" alt=\"\" width=\"774\" height=\"22\" name=\"graphics28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>14-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Para vencer o atrito e deslocar um grande cont\u00eainer C, na dire\u00e7\u00e3o indicada, \u00e9 necess\u00e1ria uma for\u00e7a F = 500N. Na tentativa de mov\u00ea-lo, blocos de massa m = 15kg s\u00e3o pendurados em um fio, que \u00e9 esticado entre o cont\u00eainer e o ponto P na parede, como na figura.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_8082fc11.jpg\" alt=\"\" width=\"363\" height=\"158\" name=\"Imagem 14\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Para movimentar o cont\u00eainer, \u00e9 preciso pendurar no fio, no m\u00ednimo,<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_f21096f0.png\" alt=\"\" width=\"775\" height=\"36\" name=\"graphics29\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>15-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um sem\u00e1foro pesando 100 N est\u00e1 pendurado por tr\u00eas cabos conforme ilustra a figura. Os cabos 1 e 2 fazem um \u00e2ngulo \u03b1 e \u03b2 com a horizontal, respectivamente.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_2e0a49b2.jpg\" alt=\"\" width=\"195\" height=\"193\" name=\"graphics30\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Em qual situa\u00e7\u00e3o as tens\u00f5es nos fios 1 e 2 ser\u00e3o iguais?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Considerando o caso em que \u03b1 = 30\u00b0 e \u03b2 = 60\u00b0, determine as tens\u00f5es nos cabos 1, 2 e 3.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dados: sen 30\u00b0 = 1\/2 e sen 60\u00b0 = \u221a3\/2<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>16-(Uerj-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Em uma sess\u00e3o de fisioterapia, a perna de um paciente acidentado \u00e9 submetida a uma for\u00e7a de tra\u00e7\u00e3o que depende do \u00e2ngulo \u03b1, como indica a figura a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_6a6d82f0.jpg\" alt=\"\" width=\"501\" height=\"214\" name=\"Imagem 16\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O \u00e2ngulo \u03b1 varia deslocando-se a roldana R sobre a horizontal. Se, para um mesmo peso P, o fisioterapeuta muda \u03b1 de 60\u00b0 para 45\u00b0, o valor da tra\u00e7\u00e3o na perna fica multiplicado por:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_ea51d8a8.png\" alt=\"\" width=\"774\" height=\"20\" name=\"graphics31\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>17- (UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Quando um homem est\u00e1 deitado numa rede (de massa desprez\u00edvel), as for\u00e7as que esta aplica na parede formam um \u00e2ngulo de 30\u00b0 com a horizontal, e a intensidade de cada uma \u00e9 de 60 kgf (ver figura adiante)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_d25dcff6.jpg\" alt=\"\" width=\"502\" height=\"166\" name=\"Imagem 17\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual \u00e9 o peso do homem?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) O gancho da parede foi mal instalado e resiste apenas at\u00e9 130 kgf. Quantas crian\u00e7as de 30 kgf a rede suporta? (suponha que o \u00e2ngulo n\u00e3o mude).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>18-(ACAFE-SC)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> No sistema representado na figura abaixo, as massas dos blocos s\u00e3o, respectivamente, m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=5,0kg, m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=10kg e m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>P<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=15kg. Suponha que o bloco P esteja em equil\u00edbrio e que n\u00e3o haja atrito entre ele e a superf\u00edcie. Pode-se afirmar ent\u00e3o, que o valor da for\u00e7a normal, em newtons, que atua sobre o bloco P \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_7bbff6be.jpg\" alt=\"\" width=\"414\" height=\"199\" name=\"Imagem 18\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_6c26ecc4.png\" alt=\"\" width=\"774\" height=\"36\" name=\"graphics32\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>19-(UFPE-PE)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um bloco de massa m = 20 kg \u00e9 escorado contra o teto de uma edifica\u00e7\u00e3o, atrav\u00e9s da aplica\u00e7\u00e3o de uma for\u00e7a obl\u00edqua F, como indicado na figura adiante.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_5280fe82.jpg\" alt=\"\" width=\"425\" height=\"141\" name=\"Imagem 19\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Sabendo-se que este escoramento deve suportar o peso p = 8,8 x 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>N, devido ao teto, calcule o valor m\u00ednimo de F, em unidades de 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>20-(Ufpel-RS)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Para garantir o sono tranq\u00fcilo de Chico Bento, Rosinha segura a rede, exercendo sobre ela uma for\u00e7a inclinada de 37\u00ba em rela\u00e7\u00e3o \u00e0 horizontal, como mostra a figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_c937b706.jpg\" alt=\"\" width=\"410\" height=\"198\" name=\"graphics33\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Desprezando o peso da rede e sabendo que Chico Bento pesa 280 N, observamos que Rosinha ter\u00e1 grande dificuldade para permanecer segurando a rede, pois precisa exercer sobre ela uma for\u00e7a de:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_7728126.png\" alt=\"\" width=\"774\" height=\"33\" name=\"graphics34\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>21-(UFPB-PB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Conforme a figura a seguir, um barco, puxado por dois tratores, navega contra a corrente de um trecho retil\u00edneo de um rio.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_e22a7fff.jpg\" alt=\"\" width=\"414\" height=\"163\" name=\"Imagem 21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Os tratores exercem, sobre o barco, for\u00e7as de mesmo m\u00f3dulo (F<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0= F<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>), enquanto a corrente atua com uma for\u00e7a , cujo m\u00f3dulo \u00e9 1,92 . 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0N. Sabendo que o barco e os tratores movem-se com velocidades constantes, que sen \u03b8 = 0,80 e cos \u03b8 = 0,60, ent\u00e3o o valor de F<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00e9:\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 1,20 . 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0N.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 1,60 . 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0N.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 1,92 . 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0N.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 2,40 . 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 3,84 . 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0N.\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>22-<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>(UFPE)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Uma barra horizontal de massa desprez\u00edvel possui uma de suas extremidades articulada em uma parede vertical. A outra extremidade est\u00e1 presa \u00e0 parede por um fio que faz um \u00e2ngulo de 45\u00b0 com a horizontal e possui um corpo de 55 N pendurado.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_6e90af19.jpg\" alt=\"\" width=\"289\" height=\"188\" name=\"graphics35\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Qual o m\u00f3dulo da for\u00e7a normal \u00e0 parede, em newtons, que a articula\u00e7\u00e3o exerce sobre a barra?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>23-(UFRJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Sejam tr\u00eas cartazes id\u00eanticos em tamanho e massa, pendurados, como mostra a figura. Os cabos t\u00eam massas desprez\u00edveis. As tens\u00f5es nas cordas s\u00e3o, respectivamente, T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_81a87bc1.jpg\" alt=\"\" width=\"450\" height=\"166\" name=\"graphics36\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Compare as intensidades das tens\u00f5es T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e ordene-as de maneira crescente. Justifique sua resposta.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>24-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um mesmo pacote pode ser carregado com cordas amarradas\u00a0 de v\u00e1rias maneiras. A situa\u00e7\u00e3o, dentre as apresentadas, em que as cordas est\u00e3o sujeitas \u00e0 maior tens\u00e3o \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_74acbe18.jpg\" alt=\"\" width=\"759\" height=\"177\" name=\"Imagem 24\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>25-(PUC-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Para tentar desencalhar um carro, seu motorista prende a extremidade de uma corda inextens\u00edvel e de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_c86d67db.jpg\" alt=\"\" width=\"445\" height=\"130\" name=\"Imagem 25\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>peso desprez\u00edvel\u00a0ao p\u00e1ra choque e a outra extremidade a uma \u00e1rvore, de modo que a corda fique disposta horizontalmente com um comprimento livre de 10m. No meio da corda \u00e9 suspenso um corpo de 20N de peso. Nessas condi\u00e7\u00f5es, observa-se que o ponto m\u00e9dio da corda desce de 0,2m. A intensidade da for\u00e7a transmitida ao carro \u00e9, aproximadamente de:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_13443552.png\" alt=\"\" width=\"774\" height=\"19\" name=\"graphics37\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>26-(MACKENZIE-SP) <\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um quadro, pesando 36,0 N, \u00e9 suspenso por um fio ideal preso \u00e0s suas extremidades. Esse fio se apoia em um prego fixo \u00e0 parede, como mostra a figura. Desprezados os atritos, a for\u00e7a de tra\u00e7\u00e3o no fio tem intensidade de:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_2099381c.jpg\" alt=\"\" width=\"206\" height=\"210\" name=\"Imagem 26\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_8672d04c.png\" alt=\"\" width=\"774\" height=\"18\" name=\"graphics38\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>27-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Um professor de f\u00edsica pendurou uma pequena esfera, pelo seu centro de gravidade, ao teto da sala de aula, conforme a figura:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_7bd36d7b.jpg\" alt=\"\" width=\"371\" height=\"149\" name=\"Imagem 27\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_52ee033b.jpg\" alt=\"\" width=\"136\" height=\"148\" name=\"Imagem 28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Em um dos fios que sustentava a esfera ele acoplou um dinam\u00f4metro e verificou que, com o sistema em equil\u00edbrio, ele marcava 10 N. O peso, em newtons, da esfera pendurada \u00e9 de<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_2900f187.jpg\" alt=\"\" width=\"774\" height=\"34\" name=\"Imagem 29\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>28-(UFPR-PR)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Uma corrente composta por cinco elos est\u00e1 presa ao teto por meio de um barbante, conforme mostra a figura. \u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_a18131bb.jpg\" alt=\"\" width=\"220\" height=\"203\" name=\"graphics39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A massa de cada elo \u00e9 de 200 g.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Fa\u00e7a um diagrama de for\u00e7as para o terceiro elo, identificando cada uma das for\u00e7as que atuam sobre ele.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Calcule o m\u00f3dulo de todas as for\u00e7as que est\u00e3o atuando nesse terceiro elo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>29-(PUC-RS)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Dois oper\u00e1rios suspendem um balde por meio de cordas, conforme mostra o esquema a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_df72002d.jpg\" alt=\"\" width=\"381\" height=\"204\" name=\"graphics40\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\uf020<\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>cos30\u00ba =\u221a3\/2. <\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Symbol, serif;\"><span style=\"font-size: medium;\"><b>\uf020<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1\/2 e \u00a0sen60\u00ba = <\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Symbol, serif;\"><span style=\"font-size: medium;\"><b>\uf020<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> =<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Symbol, serif;\"><span style=\"font-size: medium;\"><b>\uf020<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>S\u00e3o dados: sen30\u00ba = cos60\u00ba<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Sabe-se que o balde, com seu conte\u00fado, tem peso 50N, e que o \u00e2ngulo formado entre as partes da corda no ponto de suspens\u00e3o \u00e9 60<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. A corda pode ser considerada como ideal (inextens\u00edvel e de massa desprez\u00edvel).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Quando o balde est\u00e1 suspenso no ar, em equil\u00edbrio, a for\u00e7a exercida por um oper\u00e1rio, medida em newtons, vale:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_274565cb.png\" alt=\"\" width=\"774\" height=\"16\" name=\"graphics41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>30-(UFLA-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Um corpo de massa 10 kg \u00e9 preso a uma mola, produzindo, assim, um alongamento de 5 cm (Figura A). Coloca-se, agora, esse conjunto mola-corpo sobre um plano inclinado \u03b8 isento de atrito (Figura B). Considere a acelera\u00e7\u00e3o da gravidade g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, cos \u03b8 = 0,8 e sen \u03b8 = 0,6.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_e58a06d8.jpg\" alt=\"\" width=\"460\" height=\"163\" name=\"Imagem 32\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00c9 CORRETO afirmar que no plano inclinado a mola sofre um alongamento de<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 0,6 cm.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 0,8 cm.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 4 cm.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 3 cm.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>31-(UECE-CE)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Na figura a seguir, o peso P<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00e9 de 500 N e a corda RS \u00e9 horizontal.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_a5466937.jpg\" alt=\"\" width=\"452\" height=\"163\" name=\"graphics42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Os valores das tens\u00f5es T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e T<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e o peso P<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, em Newton, s\u00e3o, respectivamente,<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_aa806603.jpg\" alt=\"\" width=\"773\" height=\"69\" name=\"Imagem 34\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>32-(UPE-PE)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_4bcd64df.jpg\" alt=\"\" width=\"491\" height=\"131\" name=\"Imagem 35\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A figura abaixo ilustra uma roda de raio R e massa m. Qual \u00e9 o m\u00f3dulo da for\u00e7a horizontal\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_3e30fb1b.jpg\" alt=\"\" width=\"12\" height=\"17\" name=\"graphics43\" align=\"BOTTOM\" border=\"0\" \/>, necess\u00e1ria para erguer<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_ffc93a26.jpg\" alt=\"\" width=\"270\" height=\"259\" name=\"Imagem 37\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a roda sobre um degrau de altura h = R\/2, quando aplicada no seu eixo?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere a acelera\u00e7\u00e3o da gravidade g.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_91c4a60e.png\" alt=\"\" width=\"775\" height=\"17\" name=\"graphics44\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>As quest\u00f5es <\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>33 <\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e <\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>34 <\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>devem ser respondidas com base na situa\u00e7\u00e3o f\u00edsica descrita a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_c50b1c48.jpg\" alt=\"\" width=\"456\" height=\"147\" name=\"graphics45\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>No esquema apresentado na figura abaixo, uma part\u00edcula de poeira c\u00f3smica, cuja massa \u00e9 igual a 2,0 g, move-se livremente de norte para o sul, com velocidade de m\u00f3dulo igual a 1,2 km\/s. No instante visualizado nesse esquema (t = 0), passam a atuar sobre essa part\u00edcula as for\u00e7as A, B e C nele representadas, sendo todas elas constantes.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_f152fbff.jpg\" alt=\"\" width=\"275\" height=\"244\" name=\"Imagem 39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere tamb\u00e9m que os valores num\u00e9ricos associados aos eixos \u201cnorte\u201d e \u201cleste\u201d referem-se \u00e0 unidade de for\u00e7a do Sistema Internacional: newton (N).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>33-(IFNMG-MG)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_db36f517.jpg\" alt=\"\" width=\"462\" height=\"137\" name=\"Imagem 40\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O m\u00f3dulo da velocidade da part\u00edcula no instante t = 1,0 s, expresso em km\/s, est\u00e1 corretamente apresentado na alternativa:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_cd6d4965.png\" alt=\"\" width=\"774\" height=\"19\" name=\"graphics46\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>34-(IFNMG-MG)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_7a2b1d1d.jpg\" alt=\"\" width=\"555\" height=\"134\" name=\"Imagem 41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>No instante t = 1,0 s, as for\u00e7as A, B e C deixam de atuar na part\u00edcula. Nessas condi\u00e7\u00f5es, a forma da trajet\u00f3ria da part\u00edcula, desde t = 0, est\u00e1 corretamente descrita na alternativa:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A) Retil\u00ednea, desde t = 0, e ainda retil\u00ednea, ap\u00f3s t = 1,0 s.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B) Inicialmente circular e, ap\u00f3s 1,0 s, retil\u00ednea.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>C) Inicialmente circular e, ap\u00f3s 1,0 s, parab\u00f3lica.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>D) Inicialmente parab\u00f3lica e, ap\u00f3s t = 1,0 s, retil\u00ednea.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>35-(UFPR-PR)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_b58bd69.jpg\" alt=\"\" width=\"556\" height=\"114\" name=\"Imagem 42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Tr\u00eas blocos de massas m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, respectivamente, est\u00e3o unidos por cordas de massa desprez\u00edvel, conforme mostrado na<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_48ae8b44.jpg\" alt=\"\" width=\"416\" height=\"201\" name=\"Imagem 43\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>figura. O sistema encontra-se em equil\u00edbrio est\u00e1tico. Considere que n\u00e3o h\u00e1 atrito no movimento da roldana e que o bloco de<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>massa m1 est\u00e1 sobre uma superf\u00edcie horizontal. Assinale a alternativa que apresenta corretamente (em fun\u00e7\u00e3o de m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o coeficiente de atrito est\u00e1tico entre o bloco de massa<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e a superf\u00edcie em que ele est\u00e1 apoiado.<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_7bc5290c.jpg\" alt=\"\" width=\"767\" height=\"54\" name=\"Imagem 44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>36-(UFF-RJ)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_6a467340.jpg\" alt=\"\" width=\"588\" height=\"116\" name=\"Imagem 45\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00cdm\u00e3s s\u00e3o frequentemente utilizados para prender pequenos objetos\u00a0 em superf\u00edcies met\u00e1licas planas e verticais, como quadros de avisos e portas de geladeiras.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere que um \u00edm\u00e3, colado a um grampo, esteja em contato com a porta de uma geladeira . Suponha que a for\u00e7a magn\u00e9tica que o \u00edm\u00e3 faz sobre a superf\u00edcie da geladeira \u00e9 perpendicular a ela e tem m\u00f3dulo F<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>M<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. O conjunto im\u00e3\/grampo tem massa m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.O coeficiente de atrito est\u00e1tico entre a superf\u00edcie da geladeira e a do \u00edm\u00e3 \u00e9\u00a0 \u03bc<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.Uma massa M est\u00e1 pendurada no grampo por um fio de massa desprez\u00edvel, como mostra a figura.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_223dbd79.jpg\" alt=\"\" width=\"236\" height=\"263\" name=\"graphics47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Desenhe no diagrama as for\u00e7as que agem sobre o conjunto \u00edm\u00e3\/grampo (representado pelo ponto preto no<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>cruzamento dos eixos x e y na figura), identificando cada uma dessas for\u00e7as.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Qual o maior valor da massa\u00a0 M\u00a0 que pode ser pendurada no grampo sem que o conjunto caia?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>37-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_1967b754.jpg\" alt=\"\" width=\"508\" height=\"126\" name=\"Imagem 47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Certo corpo de massa 10,0 kg est\u00e1 suspenso por uma pequena argola, que pode deslizar, sem atrito, por um fio, supostamente ideal. Em<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/estatica\/pontomaterial\/i_5dfbadeb3efe8d3a_html_781527d6.jpg\" alt=\"\" width=\"504\" height=\"192\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>uma primeira situa\u00e7\u00e3o, o corpo encontra-se na posi\u00e7\u00e3o ilustrada na figura 1 e, depois de certo tempo, encontra-se na posi\u00e7\u00e3o ilustrada na<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>figura 2. O trabalho realizado pela for\u00e7a peso, entre a posi\u00e7\u00e3o 1 e a posi\u00e7\u00e3o 2, foi\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a)\u00a0 2,40. 10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 2,45.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 5,00.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 2,40J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 2,45J<\/b><\/span><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><span style=\"color: #000080;\"><a style=\"color: #000080;\" title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Est\u00e1tica de um Ponto Material\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/mecanica\/estatica\/estatica-de-um-ponto-material\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-estatica-de-um-ponto-material\/\">Confira a resolu\u00e7\u00e3o comentada dos exerc\u00edcios<\/a><\/span><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre Est\u00e1tica de um Ponto Material 01-(Ufrrj-RJ) A figura a seguir mostra um atleta de gin\u00e1stica ol\u00edmpica no aparelho de argolas. O ginasta encontra-se parado na posi\u00e7\u00e3o mostrada. Assinale qual dentre as alternativas a seguir a que melhor representa as for\u00e7as que atuam sobre ele, desprezando-se as for\u00e7as do ar. \u00a0 02- (PUC-PR) Duas<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1480,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1482","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1482","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1482"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1482\/revisions"}],"predecessor-version":[{"id":10874,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1482\/revisions\/10874"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1480"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1482"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}