{"id":1363,"date":"2015-09-20T15:27:45","date_gmt":"2015-09-20T15:27:45","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1363"},"modified":"2024-08-23T13:57:26","modified_gmt":"2024-08-23T13:57:26","slug":"exercicios-de-vestibulares-com-resolucao-comentada-sobre-tipos-de-energia","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/tipos-de-energia\/exercicios-de-vestibulares-com-resolucao-comentada-sobre-tipos-de-energia\/","title":{"rendered":"Tipos de Energia &#8211; Resolu\u00e7\u00e3o"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Tipos de Energia<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>01-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um ve\u00edculo de massa 800kg est\u00e1 rodando \u00e0 velocidade de 36 km\/h numa estrada reta e horizontal, quando o motorista aciona o freio. Supondo que a velocidade do ve\u00edculo se reduz uniformemente \u00e0 raz\u00e3o de 4 m\/s em cada segundo a partir do momento em que o freio foi acionado, determine<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) o tempo decorrido entre o instante do acionamento do freio e o instante em que o ve\u00edculo p\u00e1ra.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) a dist\u00e2ncia percorrida pelo ve\u00edculo nesse intervalo de tempo.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) o trabalho realizado pela for\u00e7a (<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_7b6ed63a.jpg\" alt=\"\" width=\"17\" height=\"17\" name=\"Imagem 20\" align=\"BOTTOM\" border=\"0\" \/>) aplicada pelo freio nesse deslocamento<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>02-(PUC-PR)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um carrinho de brinquedo, de massa 2 kg, \u00e9 empurrado ao longo de uma trajet\u00f3ria retil\u00ednea e horizontal por uma for\u00e7a vari\u00e1vel, cuja dire\u00e7\u00e3o \u00e9 paralela \u00e0 trajet\u00f3ria do carrinho. O gr\u00e1fico adiante mostra a varia\u00e7\u00e3o do m\u00f3dulo da for\u00e7a aplicada, em fun\u00e7\u00e3o do deslocamento do carrinho.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\">\u00a0<img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_d8810858.jpg\" alt=\"\" width=\"299\" height=\"150\" name=\"Imagem 21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Sabendo que o carrinho partiu do repouso, calcule sua velocidade quando seu deslocamento for igual a 10m<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>03-(Ufpe)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um objeto com massa 1,0 kg, lan\u00e7ado sobre uma superf\u00edcie plana com velocidade inicial de 8,0 m\/s, se move em linha reta, at\u00e9 parar. O trabalho total realizado pela for\u00e7a de atrito sobre o objeto \u00e9, em J:<\/b><\/span><\/span><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_e83cd632.png\" alt=\"\" width=\"774\" height=\"18\" name=\"Imagem 2575\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>04-(UERJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Suponha que o cora\u00e7\u00e3o, em regime de baixa atividade f\u00edsica, consiga bombear 200 g de sangue, fazendo com que essa massa de sangue adquira uma velocidade de 0,3 m\/s e que, com o aumento da atividade f\u00edsica, a mesma quantidade de sangue atinja uma velocidade de 0,6 m\/s.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O trabalho realizado pelo cora\u00e7\u00e3o, decorrente desse aumento de atividade f\u00edsica, em joules, corresponde ao produto de 2,7 por:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_f644537.png\" alt=\"\" width=\"775\" height=\"19\" name=\"Imagem 2576\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>05-(Ufpe)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um objeto \u00e9 abandonado a partir do repouso, em t = 0, no topo de um plano inclinado. Desprezando o atrito, qual dos gr\u00e1ficos a seguir melhor representa a varia\u00e7\u00e3o da energia cin\u00e9tica do objeto em fun\u00e7\u00e3o do tempo?<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_8cdf6555.jpg\" alt=\"\" width=\"767\" height=\"113\" name=\"Imagem 22\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>06-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Deslocando-se por uma rodovia a 108km\/h (30m\/s), um motorista chega \u00e0 pra\u00e7a de ped\u00e1gio e passa a frear o carro a uma taxa constante, percorrendo 150m em trajet\u00f3ria retil\u00ednea, at\u00e9 a parada do ve\u00edculo. Considerando a massa total do ve\u00edculo como sendo 1.000kg, o m\u00f3dulo do trabalho realizado pelas for\u00e7as de atrito que agem sobre o carro, em joules, \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 30.000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 150.000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 450.000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 1.500.000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 4.500.000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>07-(Ufla-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O kevlar \u00e9 uma fibra constitu\u00edda de uma longa cadeia molecular de poly-paraphenylene teraphthalamide, que associa leveza, flexibilidade e, principalmente, alta resist\u00eancia \u00e0 ruptura. Entre as in\u00fameras aplica\u00e7\u00f5es dessa fibra, est\u00e1 a confec\u00e7\u00e3o de coletes \u00e0 prova de balas.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_e784a50.jpg\" alt=\"\" width=\"127\" height=\"146\" name=\"graphics17\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_ff137907.jpg\" alt=\"\" width=\"112\" height=\"146\" name=\"Imagem 24\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere um proj\u00e9til de massa 50g com velocidade de 200m\/s que se choca com essa fibra e penetra 0,5cm. Pode-se afirmar que o kevlar apresentou uma for\u00e7a de resist\u00eancia m\u00e9dia de:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_e3a2529a.png\" alt=\"\" width=\"775\" height=\"16\" name=\"Imagem 2577\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>08-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um esquiador, com todos seus apetrechos, tem massa de 80kg e chega ao final de uma encosta, deslizando na neve, com velocidade de 108km\/h. Suponha-se que ele consiga parar exclusivamente com o aux\u00edlio da pr\u00f3pria neve, colocando os<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_d56df1fd.jpg\" alt=\"\" width=\"342\" height=\"126\" name=\"Imagem 25\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>esquis em oposi\u00e7\u00e3o ao movimento. Nesse caso, o m\u00f3dulo do trabalho realizado pela neve sobre o esquiador, em joules, \u00e9 de:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_fc325c2.png\" alt=\"\" width=\"775\" height=\"17\" name=\"Imagem 2578\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>09-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um proj\u00e9til de 20 gramas, com velocidade de 240m\/s, atinge o tronco de uma \u00e1rvore e nele penetra uma certa dist\u00e2ncia at\u00e9 parar.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Determine a energia cin\u00e9tica E, do proj\u00e9til, antes de colidir com o tronco e o trabalho realizado sobre o proj\u00e9til na sua trajet\u00f3ria no interior do tronco, at\u00e9 parar.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Sabendo que o proj\u00e9til penetrou 18cm no tronco da \u00e1rvore, determine o valor m\u00e9dio F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>m<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>da for\u00e7a de resist\u00eancia que o tronco ofereceu \u00e0 penetra\u00e7\u00e3o do proj\u00e9til.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>10-(Ufg)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O bloco A da figura desliza sobre uma superf\u00edcie horizontal sem atrito puxado pelo bloco B. O fio e a polia s\u00e3o ideais.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O gr\u00e1fico que representa qualitativamente a energia cin\u00e9tica do sistema em fun\u00e7\u00e3o do tempo a partir do instante em que o bloco A atinge o ponto P \u00e9<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_b2e7dfb0.jpg\" alt=\"\" width=\"545\" height=\"198\" name=\"Imagem 26\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Energia potencial gravitacional<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>11- (UFV-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma pessoa pode subir do n\u00edvel A para o n\u00edvel B por tr\u00eas caminhos: uma rampa, uma corda e uma escada.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_90e9241b.jpg\" alt=\"\" width=\"381\" height=\"161\" name=\"graphics18\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Ao mudar de n\u00edvel, a varia\u00e7\u00e3o da energia potencial da pessoa \u00e9 :<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a mesma, pelos tr\u00eas caminhos. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) menor, pela rampa. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) maior, pela escada. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) maior pela corda.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) maior pela rampa<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>12- (UFB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma pessoa de massa 70kg sobe um lance de escada de 5 degraus, cada um com 30cm de altura. Determine, considerando g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_d6dbfe72.jpg\" alt=\"\" width=\"357\" height=\"129\" name=\"Imagem 28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) A energia potencial gravitacional adquirida pela pessoa em rela\u00e7\u00e3o ao pavimento.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) O trabalho realizado pelo peso da pessoa neste deslocamento.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Se a pessoa tivesse subido pela trajet\u00f3ria da direita, o trabalho da for\u00e7a peso da pessoa seria diferente? Justifique.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>13-(Ufrj-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dois jovens, cada um com 50 kg de massa, sobem quatro andares de um edif\u00edcio. A primeira jovem, Helo\u00edsa, sobe de elevador, enquanto o segundo, Abelardo, vai pela escada, que tem dois lances por andar, cada um com 2,0 m de altura.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Denotando por W(A) o trabalho realizado pelo peso de Abelardo e por W(H) o trabalho realizado pelo peso de Helo\u00edsa, determine a raz\u00e3o W(A) \/ W(H).<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Supondo que s\u00e3o nulas suas velocidades inicial e final, calcule a varia\u00e7\u00e3o de energia mec\u00e2nica de cada jovem ao realizar o deslocamento indicado.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>14-(Uepg)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A respeito de energia, assinale o que for correto.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(01) Energia potencial \u00e9 aquela que se encontra armazenada num determinado sistema e pode ser utilizada a qualquer momento para realizar trabalho.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(02) No sistema conservativo, o decr\u00e9scimo da energia potencial \u00e9 compensado por um acr\u00e9scimo da energia cin\u00e9tica.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(04) A energia est\u00e1 relacionada com a capacidade de produzir movimento.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(08) A energia pode ser transformada ou transferida, mas nunca criada ou destru\u00edda.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>15-(UFSCAR-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Quino, criador da personagem Mafalda, \u00e9 tamb\u00e9m conhecido por seus quadrinhos repletos de humor chocante. Aqui, o executivo do alto escal\u00e3o est\u00e1 prestes a cair em uma armadilha fatal.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_5feee6ac.jpg\" alt=\"\" width=\"248\" height=\"196\" name=\"graphics19\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere que:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>&#8211; o centro de massa do tubo suspenso, relativamente \u00e0 parte inferior do tubo, est\u00e1 localizado a uma dist\u00e2ncia igual \u00e0 altura da cartola do executivo;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>&#8211; a dist\u00e2ncia do centro de massa do tubo at\u00e9 o topo da cartola \u00e9 3,2 m;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>&#8211; a vertical que passa pelo centro de massa do tubo passa tamb\u00e9m pela cabe\u00e7a do executivo;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>&#8211; o tubo tem massa de 450 kg e, durante uma queda, n\u00e3o sofreria a\u00e7\u00e3o significativa da resist\u00eancia do ar, descendo com acelera\u00e7\u00e3o de 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>&#8211; comparativamente \u00e0 massa do tubo, a corda tem massa que se pode considerar desprez\u00edvel.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Para preparar a armadilha, o tubo foi i\u00e7ado a 5,5 m do ch\u00e3o pela pr\u00f3pria corda que posteriormente o sustentou. Determine o trabalho, em J, realizado pela for\u00e7a peso na ascens\u00e3o do tubo.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>16-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A rela\u00e7\u00e3o entre calor e outras formas de energia foi objeto de intensos estudos durante a Revolu\u00e7\u00e3o Industrial, e uma experi\u00eancia realizada por James P. Joule foi imortalizada. Com ela, ficou demonstrado que o trabalho mec\u00e2nico e o calor s\u00e3o duas formas diferentes de energia e que o trabalho mec\u00e2nico poderia ser convertido em energia t\u00e9rmica. A figura apresenta uma vers\u00e3o atualizada da m\u00e1quina de Joule. Um corpo de massa 2 kg \u00e9 suspenso por um fio cuidadosamente enrolado em um carretel, ligado ao eixo de um gerador.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_b89591fa.jpg\" alt=\"\" width=\"313\" height=\"195\" name=\"graphics20\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O gerador converte a energia mec\u00e2nica do corpo em el\u00e9trica e alimenta um resistor imerso em um recipiente com \u00e1gua. Suponha que, at\u00e9 que o corpo chegue ao solo, depois de abandonado a partir do repouso, sejam transferidos para a \u00e1gua 24 J de energia t\u00e9rmica. Sabendo que esse valor corresponde a 80% da energia mec\u00e2nica, de qual altura em rela\u00e7\u00e3o ao solo o corpo foi abandonado? Adote g = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>17-(PUC-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma pessoa de massa 80kg sobe todo o v\u00e3o de uma escada de de 5m de altura. Considere g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e assinale a afirmativa CORRETA<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_787d8fd8.jpg\" alt=\"\" width=\"273\" height=\"188\" name=\"graphics21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Ao subir todo o v\u00e3o da escada, a pessoa realiza um trabalho de 1600J.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Para que houvesse realiza\u00e7\u00e3o de trabalho pela pessoa, seria necess\u00e1rio que ela subisse com movimento acelerado.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) O trabalho realizado pela pessoa depende da acelera\u00e7\u00e3o da gravidade.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) Ao subir a escada, n\u00e3o h\u00e1 realiza\u00e7\u00e3o de trabalho, independentemente de o movimento ser uniforme ou acelerado.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>18-(UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Como \u00e9 mencionado no texto 6 da colet\u00e2nea apresentada, a disponibilidade de \u00e1gua \u00e9 essencial para a agricultura. Um projeto do governo brasileiro, que pretende aumentar a irriga\u00e7\u00e3o na regi\u00e3o Nordeste, planeja a transposi\u00e7\u00e3o das \u00e1guas do Rio S\u00e3o Francisco.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_59572841.jpg\" alt=\"\" width=\"284\" height=\"200\" name=\"graphics22\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O projeto \u00e9 dividido em duas partes: Eixo Norte e Eixo Leste. Em seu Eixo Norte, ser\u00e3o bombeados cerca de 50m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/s de \u00e1gua do rio at\u00e9 uma altura de 160m, para posterior utiliza\u00e7\u00e3o pelas popula\u00e7\u00f5es locais. Considere g = 10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e a densidade da \u00e1gua igual a 1,0g\/cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual ser\u00e1 a massa de \u00e1gua bombeada em cada segundo no Eixo Norte?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Qual ser\u00e1 o aumento de energia potencial gravitacional dessa massa?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Conhecendo a quantidade de \u00e1gua bombeada em cada segundo e o correspondente aumento da energia potencial gravitacional, o engenheiro pode determinar a pot\u00eancia do sistema de bombeamento, que \u00e9 um dado crucial do projeto dos Eixos. No Eixo Leste, planeja-se gastar cerca de 4,2 .10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>9<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>J em um minuto de bombeamento da \u00e1gua. Determine a pot\u00eancia do sistema do Eixo Leste.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Energia potencial el\u00e1stica<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>19-(Uerj-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma mola, que apresenta uma determinada constante el\u00e1stica, est\u00e1 fixada verticalmente por uma de suas extremidades, conforme figura 1.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Ao acloparmos a extremidade livre a um corpo de massa M, o comprimento da mola foi acrescido de um valor X, e ela passou a armazenar uma energia el\u00e1stica E, conforme figura 2.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Em fun\u00e7\u00e3o de X<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, o gr\u00e1fico que melhor representa E est\u00e1 indicado em:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_893f93a2.jpg\" alt=\"\" width=\"501\" height=\"180\" name=\"graphics23\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>20- (UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Num conjunto arco e flecha, a energia potencial el\u00e1stica \u00e9 transformada em energia cin\u00e9tica da flecha durante o lan\u00e7amento. A for\u00e7a da corda sobre a flecha \u00e9 proporcional ao deslocamento x, como ilustrado na figura.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_98f22cb.jpg\" alt=\"\" width=\"162\" height=\"196\" name=\"graphics24\" align=\"BOTTOM\" border=\"0\" \/> <img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_8f2a45b2.jpg\" alt=\"\" width=\"317\" height=\"191\" name=\"graphics25\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Quando a corda \u00e9 solta, o deslocamento \u00e9 x = 0,6 m e a for\u00e7a \u00e9 de 300 N. Qual a energia potencial el\u00e1stica nesse instante?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>21-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma mola de constante el\u00e1stica igual a 10N\/m \u00e9 esticada desde sua posi\u00e7\u00e3o de equil\u00edbrio at\u00e9 uma posi\u00e7\u00e3o em que seu comprimento aumentou 20cm. A energia potencial da mola esticada \u00e9:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_9f94a131.png\" alt=\"\" width=\"774\" height=\"17\" name=\"Imagem 2579\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>22-(UNIFESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Numa mola atua uma for\u00e7a el\u00e1stica do tipo F=K.x, em que K=150,0N\/m e x \u00e9 a deforma\u00e7\u00e3o que ela provoca. O comprimento da mola passa ent\u00e3o de 2,500cm para 2,000cm. Por efeito dessa deforma\u00e7\u00e3o, o aumento de energia potencial, em joules, acumulada na mola \u00e9,<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_2fd9ab34.png\" alt=\"\" width=\"774\" height=\"22\" name=\"Imagem 2580\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><sup>\u00a0<\/sup><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>23-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um praticante de esporte radical, amarrado a uma corda el\u00e1stica, cai de uma plataforma, a partir do repouso, seguindo uma trajet\u00f3ria vertical. A outra extremidade da corda est\u00e1 presa na plataforma.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_ccee12e3.jpg\" alt=\"\" width=\"165\" height=\"239\" name=\"graphics26\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A figura mostra dois gr\u00e1ficos que foram tra\u00e7ados desprezando-se o atrito do ar em toda a trajet\u00f3ria. O primeiro \u00e9 o da energia potencial gravitacional, U<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>gravitacional<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, do praticante em fun\u00e7\u00e3o da dist\u00e2ncia y entre ele e a plataforma, onde o potencial zero foi escolhido em y=30m. Nessa posi\u00e7\u00e3o, o praticante atinge o maior afastamento da plataforma, quando sua velocidade se reduz, momentaneamente, a zero. O segundo \u00e9 o gr\u00e1fico da energia armazenada na corda, U<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>el\u00e1stica<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, em fun\u00e7\u00e3o da dist\u00e2ncia entre suas extremidades.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_b01de34a.jpg\" alt=\"\" width=\"426\" height=\"182\" name=\"graphics27\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Determine:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) o peso P do praticante e o comprimento L<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>da corda.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) a constante el\u00e1stica K da corda<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>24-(UEPG-PR)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 No que respeita \u00e0 energia e suas transforma\u00e7\u00f5es, assinale o que for correto.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>01) O trabalho n\u00e3o \u00e9 uma forma de energia, mas uma maneira de transferir energia de um lugar para outro, ou de transformar uma forma de energia em outra.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>02) A energia cin\u00e9tica de um corpo a 80 km\/h \u00e9 16 vezes maior que a do mesmo corpo a 20 km\/h.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>04) A energia potencial gravitacional de um corpo depende da posi\u00e7\u00e3o em rela\u00e7\u00e3o a um ponto de refer\u00eancia.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>08) A quantidade de energia utiliz\u00e1vel diminui a cada transforma\u00e7\u00e3o sofrida at\u00e9 que dela nada reste.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>16) A energia cin\u00e9tica de um sistema \u00e9 energia em tr\u00e2nsito ou em transforma\u00e7\u00e3o.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>25-(UFMS-MS)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Uma semente de massa m cai do galho de uma \u00e1rvore, de uma altura h do ch\u00e3o e, devido \u00e0 forma da semente que possui uma pequena asa, o ar produz um efeito pelo qual, logo ap\u00f3s a queda, a semente cai verticalmente com velocidade de transla\u00e7\u00e3o constante e, ao mesmo tempo, girando com uma velocidade angular W constante em torno de um eixo vertical que passa pelo seu centro de massa. Com fundamentos na mec\u00e2nica, assinale a(s) proposi\u00e7\u00e3o(\u00f5es) correta(s).<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_408bccc.jpg\" alt=\"\" width=\"504\" height=\"170\" name=\"Imagem 38\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>01) O trabalho realizado pelo campo gravitacional sobre a semente, desde a altura h at\u00e9 o ch\u00e3o, \u00e9 maior que mgh porque a semente cai girando com energia de rota\u00e7\u00e3o.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>02) O m\u00f3dulo da for\u00e7a que o ar exerce na semente \u00e9 igual ao m\u00f3dulo da for\u00e7a peso da semente.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>04) Enquanto a semente est\u00e1 caindo, a energia cin\u00e9tica de transla\u00e7\u00e3o e a energia cin\u00e9tica de rota\u00e7\u00e3o permanecem constantes.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>08) Enquanto a semente est\u00e1 caindo, o torque realizado pela for\u00e7a peso da semente \u00e9 nulo.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>16) A energia mec\u00e2nica da semente permanece constante.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>26-(UFG-GO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Uma das competi\u00e7\u00f5es dos X-games s\u00e3o as manobras dos esqueitistas em uma rampa em U. Um atleta parte do repouso do topo da rampa e atrav\u00e9s do movimento do seu corpo, de peso 800 N, consegue ganhar 600 J a cada ida e vinda na rampa, conforme ilustra\u00e7\u00e3o a seguir.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_71b145d1.jpg\" alt=\"\" width=\"328\" height=\"162\" name=\"Imagem 39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Desprezando as perdas de energia e o peso do skate, o n\u00famero m\u00ednimo de idas e vindas que o atleta deve realizar para atingir uma altura (h) de 3 m acima do topo da rampa \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 2\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 3\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 4\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 6\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 8\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>27-(UERJ-RJ)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Durante a Segunda Guerra Mundial, era comum o ataque com bombardeiros a alvos inimigos por meio de uma t\u00e9cnica denominada mergulho, cujo esquema pode ser observado a seguir.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_c8eafda4.jpg\" alt=\"\" width=\"334\" height=\"278\" name=\"Imagem 40\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O mergulho do avi\u00e3o iniciava-se a 5 000 m de altura, e a bomba era lan\u00e7ada sobre o alvo de uma altura de 500 m.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere a energia gravitacional do avi\u00e3o em rela\u00e7\u00e3o ao solo, no ponto inicial do ataque, igual a E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e, no ponto de onde a bomba \u00e9 lan\u00e7ada, igual a E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. Calcule E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>28-(UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Em 1948 Casimir prop\u00f4s que, quando duas placas met\u00e1licas, no v\u00e1cuo, s\u00e3o colocadas muito pr\u00f3ximas,<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_b1a4894f.jpg\" alt=\"\" width=\"440\" height=\"166\" name=\"Imagem 41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>surge uma for\u00e7a atrativa entre elas, de natureza eletromagn\u00e9tica, mesmo que as placas estejam descarregadas. Essa for\u00e7a \u00e9 muitas vezes relevante no desenvolvimento de mecanismos nanom\u00e9tricos.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) A for\u00e7a de Casimir \u00e9 inversamente proporcional \u00e0 quarta pot\u00eancia da dist\u00e2ncia entre as placas. Essa for\u00e7a pode ser medida utilizando-se microscopia de for\u00e7a at\u00f4mica atrav\u00e9s da deflex\u00e3o de uma alavanca, como mostra a figura a seguir.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_c498409.jpg\" alt=\"\" width=\"473\" height=\"140\" name=\"Imagem 42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A for\u00e7a de deflex\u00e3o da alavanca se comporta como a for\u00e7a el\u00e1stica de uma mola. No experimento ilustrado na figura, o equil\u00edbrio entre a for\u00e7a el\u00e1stica e a for\u00e7a atrativa de Casimir ocorre quando a alavanca sofre uma deflex\u00e3o de \u0394x = 6,4 nm. Determine a constante el\u00e1stica da alavanca, sabendo que neste caso o m\u00f3dulo da for\u00e7a de Casimir \u00e9 dado por F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=b\/d<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, em que b = 9,6\u00d710<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-39<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>N.m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e d \u00e9 a dist\u00e2ncia entre as placas. Despreze o peso da placa.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Um dos limites da medida da deflex\u00e3o da alavanca decorre de sua vibra\u00e7\u00e3o natural em raz\u00e3o da energia t\u00e9rmica fornecida pelo ambiente. Essa energia \u00e9 dada por E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>T<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= k<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>T , em que k<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=1, 4&#215;10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-23<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>J\/K e T \u00e9 a temperatura do ambiente na escala Kelvin. Considerando que toda a energia E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>T<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00e9 convertida em energia el\u00e1stica, determine a deflex\u00e3o \u0394x produzida na alavanca a T = 300 K se a constante el\u00e1stica vale k<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 0, 21 N\/m.<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>29-(UFAL-AL)\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A figura mostra um bloco de peso 10 N em equil\u00edbrio contraindo uma mola ideal de constante el\u00e1stica 100 N\/m. N\u00e3o existe atrito entre o bloco e o plano inclinado e sabe-se que sen\u03b8= 0,8 e cos\u03b8= 0,6. Considere que a energia potencial el\u00e1stica \u00e9 nula quando a mola n\u00e3o est\u00e1 nem contra\u00edda nem distendida, e que a energia potencial gravitacional \u00e9 nula no n\u00edvel do ponto P, situado a uma altura de 10 cm acima do centro de massa do bloco.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_1099c3b4.jpg\" alt=\"\" width=\"445\" height=\"174\" name=\"graphics28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Nesse contexto, pode-se afirmar que a soma das energias potenciais el\u00e1stica da mola e gravitacional do bloco na situa\u00e7\u00e3o da figura vale:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) \u22120,68 J\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) \u22120,32 J\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) zero\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 0,32 J\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 0,68 J\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>30-(UDESC-SC)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Tr\u00eas homens, Jo\u00e3o, Pedro e Paulo, correm com velocidades horizontais constantes de 1,0 m\/s, 1,0 m\/s e 2,0 m\/s respectivamente (em rela\u00e7\u00e3o a O, conforme mostra a figura).<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A massa de Jo\u00e3o \u00e9 50 Kg, a de Pedro \u00e9 50 kg e a de Paulo \u00e9 60 Kg.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_467bf519.jpg\" alt=\"\" width=\"483\" height=\"180\" name=\"Imagem 44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>As energias cin\u00e9ticas de Pedro e Paulo em rela\u00e7\u00e3o a um referencial localizado em Jo\u00e3o s\u00e3o:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 0 J e 30 J\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 25 J e 120 J\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 0 J e 0 J\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 100 J e 270 J\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 100 J e 120 J\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>31-(UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Em determinados meses do ano observa-se significativo aumento do n\u00famero de estrelas cadentes em certas regi\u00f5es do c\u00e9u, n\u00famero que chega a ser da ordem de uma centena de estrelas cadentes por hora. Esse fen\u00f4meno \u00e9 chamado de chuva de meteoros ou chuva de estrelas cadentes, e as mais importantes s\u00e3o as chuvas de Perseidas e de Le\u00f4nidas. Isso ocorre<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_121803f4.jpg\" alt=\"\" width=\"377\" height=\"192\" name=\"Imagem 45\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>quando a Terra cruza a \u00f3rbita de algum cometa que deixou uma nuvem de part\u00edculas no seu caminho. Na sua maioria, essas part\u00edculas s\u00e3o pequenas como gr\u00e3os de poeira, e, ao penetrarem na atmosfera da Terra, s\u00e3o aquecidas pelo atrito com o ar e produzem os rastros de luz observados.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Uma part\u00edcula entra na atmosfera terrestre e \u00e9 completamente freada pela for\u00e7a de atrito com o ar ap\u00f3s se deslocar por uma dist\u00e2ncia de 1,5 km. Se sua energia cin\u00e9tica inicial \u00e9 igual a E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 4,5 \u00d710<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>J , qual \u00e9 o m\u00f3dulo da for\u00e7a de atrito m\u00e9dia? Despreze o trabalho do peso nesse deslocamento.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Considere que uma part\u00edcula de massa m = 0,1 g sofre um aumento de temperatura de \u0394\u03b8 = 2400<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>C ap\u00f3s entrar na atmosfera. Calcule a quantidade de calor necess\u00e1ria para produzir essa eleva\u00e7\u00e3o de temperatura se o calor espec\u00edfico do material que comp\u00f5e a part\u00edcula \u00e9 c = 0,90J\/g<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>C.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>32-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um menino puxa, com uma corda, na dire\u00e7\u00e3o horizontal, um cachorro de brinquedo formado por duas partes, A e B, ligadas entre si por uma mola, como ilustra a figura abaixo. As partes A e B t\u00eam, respectivamente, massas m<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 0,5<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_f86e6fbb.jpg\" alt=\"\" width=\"368\" height=\"163\" name=\"Imagem 46\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>kg e m<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 1 kg, sendo \u03bc<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 0,3 o coeficiente de atrito cin\u00e9tico entre cada parte e o piso. A constante el\u00e1stica da mola \u00e9 k = 10 N\/m e, na posi\u00e7\u00e3o relaxada, seu comprimento \u00e9 x<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 10 cm. O conjunto se move com velocidade constante v = 0,1 m\/s. Nessascondi\u00e7\u00f5es, determine:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) O m\u00f3dulo T da for\u00e7a exercida pelo menino sobre a parte B.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) O trabalho W realizado pela for\u00e7a que o menino faz para puxar o brinquedo por 2 minutos.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) O m\u00f3dulo F da for\u00e7a exercida pela mola sobre a parte A.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) O comprimento x da mola, com o brinquedo em movimento.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_7757f0e.jpg\" alt=\"\" width=\"297\" height=\"124\" name=\"Imagem 47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>33-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Trens de alta velocidade, chamados trens-bala, dever\u00e3o estar em funcionamento no<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_2892858b.jpg\" alt=\"\" width=\"361\" height=\"166\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Brasil nos pr\u00f3ximos anos. Caracter\u00edsticas t\u00edpicas desses trens s\u00e3o: velocidade m\u00e1xima de 300 km\/h, massa total (incluindo 500 passageiros) de 500 t e pot\u00eancia m\u00e1xima dos motores el\u00e9tricos igual a 8 MW. Nesses trens, as m\u00e1quinas el\u00e9tricas que atuam como motores tamb\u00e9m podem ser usadas como geradores, freando o movimento (freios regenerativos). Nas ferrovias, as curvas t\u00eam raio de curvatura de, no m\u00ednimo, 5 km. Considerando um trem e uma ferrovia com essas caracter\u00edsticas, determine:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) O tempo necess\u00e1rio para o trem atingir a velocidade de 288 km\/h, a partir do repouso, supondo que os motores forne\u00e7am a pot\u00eancia m\u00e1xima o tempo todo.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) A for\u00e7a m\u00e1xima na dire\u00e7\u00e3o horizontal, entre cada roda e o trilho, numa curva horizontal percorrida a 288 km\/h, supondo que o trem tenha 80 rodas e que as for\u00e7as entre cada uma delas e o trilho tenham a mesma intensidade.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) A acelera\u00e7\u00e3o do trem quando, na velocidade de 288 km\/h, as m\u00e1quinas el\u00e9tricas s\u00e3o acionadas como geradores de 8 MW de pot\u00eancia, freando o movimento.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_af81aeb4.jpg\" alt=\"\" width=\"492\" height=\"111\" name=\"Imagem 49\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>34-(UEPB-PB)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um estudante de f\u00edsica que morava numa resid\u00eancia universit\u00e1ria tinha tr\u00eas op\u00e7\u00f5es para subir ou descer do t\u00e9rreo para o 1\u00ba piso dessa resid\u00eancia: pela escada, pela corda ou por uma rampa , conforme ilustrado na figura:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_58238096.jpg\" alt=\"\" width=\"521\" height=\"189\" name=\"Imagem 50\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Ap\u00f3s algumas an\u00e1lises, o estudante estabeleceu as seguintes hip\u00f3teses:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>I &#8211; Ao mudar de n\u00edvel, a minha varia\u00e7\u00e3o da energia potencial \u00e9 menor pela rampa, uma vez que n\u00e3o me esfor\u00e7o tanto para subir ou descer.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>II &#8211; Ao mudar de n\u00edvel, a minha varia\u00e7\u00e3o da energia potencial \u00e9 maior pela escada, uma vez que o esfor\u00e7o \u00e9 maior.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>III &#8211; Ao mudar de n\u00edvel, a minha varia\u00e7\u00e3o da energia potencial \u00e9 a mesma pelos tr\u00eas caminhos.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>IV &#8211; Ao mudar de n\u00edvel, a minha varia\u00e7\u00e3o da energia potencial \u00e9 maior pela corda, uma vez que o esfor\u00e7o \u00e9 maior.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Das hip\u00f3teses apresentadas pelo estudante, \u00e9(s\u00e3o) verdadeira(s):<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) II, apenas. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) I e IV, apenas.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) III, apenas. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) I e II, apenas.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) I, apenas.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>35-(UFLA-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Dois corpos 1 e 2 est\u00e3o em movimento uniforme. Considerando que a massa m<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>do corpo 1 \u00e9 metade da massa M<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>do corpo 2, e que a velocidade v<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>do corpo 1 \u00e9 quatro vezes maior do que a velocidade v<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>do corpo 2, \u00e9 CORRETO afirmar que a energia cin\u00e9tica do corpo 1 \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(A) quatro vezes maior do que a energia cin\u00e9tica do corpo 2.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(B) metade da energia cin\u00e9tica do corpo 2.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(C) oito vezes maior do que a energia cin\u00e9tica do corpo 2.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(D) o dobro da energia cin\u00e9tica do corpo 2.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>36-(UFAL-AL)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um estudante de peso 600 N salta de \u201cbungee jumping\u201d de uma ponte a uma dist\u00e2ncia<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_cf4115e1.jpg\" alt=\"\" width=\"410\" height=\"184\" name=\"Imagem 51\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>consider\u00e1vel do solo (ver figura).<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Inicialmente, a corda el\u00e1stica atada aos seus tornozelos est\u00e1 totalmente sem tens\u00e3o (energia potencial el\u00e1stica nula). O estudante cai, a partir do repouso, uma dist\u00e2ncia vertical m\u00e1xima de 40 m, em rela\u00e7\u00e3o ao seu ponto de partida. Desprezando-se as varia\u00e7\u00f5es de energia cin\u00e9tica e potencial da corda el\u00e1stica ideal, bem como as perdas de energia por dissipa\u00e7\u00e3o, qual a energia potencial el\u00e1stica armazenada na corda quando o estudante se encontra no ponto mais baixo da sua trajet\u00f3ria?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A) 12000 J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B) 24000 J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>C) 120000 J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>D) 240000 J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>E) 1200000 J<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>37-(UFG-GO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Em um edif\u00edcio de M andares moram N pessoas por andar. Cada andar possui altura h.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_6147d957.jpg\" alt=\"\" width=\"308\" height=\"173\" name=\"Imagem 52\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O elevador do edif\u00edcio possui um contrapeso e, por isso, quando se move vazio, o consumo de energia pode ser desprezado. Seja m a massa m\u00e9dia dos moradores que utilizam o elevador, individualmente, duas vezes por dia. Desprezando-se as perdas por atrito, a energia total<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>consumida pelo motor do elevador, em um dia, \u00e9<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(A) (1+M)MNmgh\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(B) (1+M)MNmgh\/2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(C) 2MNmgh\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(D) MNmgh\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(E) MNmgh\/2<\/b><\/span><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>38-(ENEM-MEC)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_58a7c039.jpg\" alt=\"\" width=\"183\" height=\"126\" name=\"Imagem 53\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um motor s\u00f3 poder\u00e1 realizar trabalho se receber uma quantidade de energia de outro sistema. No<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/tiposenergia\/i_653c434724845c73_html_8ef2966a.jpg\" alt=\"\" width=\"325\" height=\"193\" name=\"Imagem 54\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>caso, a energia armazenada no combust\u00edvel \u00e9, em parte, liberada durante a combust\u00e3o para que o aparelho possa funcionar.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Quando o motor funciona, parte da energia convertida ou transformada na combust\u00e3o n\u00e3o pode ser utilizada para a realiza\u00e7\u00e3o de trabalho. Isso significa dizer que h\u00e1 vazamento da energia em outra forma.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>CARVALHO, A. X. Z. F\u00edsica T\u00e9rmica. Belo Horizonte: Pax, 2009 (adaptado).<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>De acordo com o texto, as transforma\u00e7\u00f5es de energia que ocorrem durante o funcionamento do motor s\u00e3o decorrentes de a:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) libera\u00e7\u00e3o de calor dentro do motor ser imposs\u00edvel.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) realiza\u00e7\u00e3o de trabalho pelo motor ser incontrol\u00e1vel.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) convers\u00e3o integral de calor em trabalho ser imposs\u00edvel.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) transforma\u00e7\u00e3o de energia t\u00e9rmica em cin\u00e9tica ser imposs\u00edvel.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) utiliza\u00e7\u00e3o de energia potencial do combust\u00edvel ser incontrol\u00e1vel.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Tipos de Energia\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/tipos-de-energia\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-tipos-de-energia\/\"><span style=\"color: #000080;\">Confira o gabarito e\u00a0a resolu\u00e7\u00e3o comentada<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre Tipos de Energia 01-(UNESP-SP)\u00a0Um ve\u00edculo de massa 800kg est\u00e1 rodando \u00e0 velocidade de 36 km\/h numa estrada reta e horizontal, quando o motorista aciona o freio. Supondo que a velocidade do ve\u00edculo se reduz uniformemente \u00e0 raz\u00e3o de 4 m\/s em cada segundo a partir do momento em que o freio foi acionado,<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1361,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1363","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1363","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1363"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1363\/revisions"}],"predecessor-version":[{"id":10863,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1363\/revisions\/10863"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1361"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1363"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}