{"id":1322,"date":"2015-09-15T15:11:27","date_gmt":"2015-09-15T15:11:27","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1322"},"modified":"2024-08-23T13:44:22","modified_gmt":"2024-08-23T13:44:22","slug":"exercicios-de-vestibulares-com-resolucao-comentada-sobre-potencia-de-uma-forca","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/potencia-de-uma-forca\/exercicios-de-vestibulares-com-resolucao-comentada-sobre-potencia-de-uma-forca\/","title":{"rendered":"Pot\u00eancia de uma for\u00e7a &#8211; Exerc\u00edcios"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Pot\u00eancia de uma for\u00e7a<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>01-(UFSM-RS)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Leia a informa\u00e7\u00e3o a seguir.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A constru\u00e7\u00e3o de usinas geradoras de eletricidade causa impacto para o meio ambiente, mas pode proporcionar uma melhor qualidade de vida, trazendo conforto em resid\u00eancias.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Observe a figura:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_55963a94.jpg\" alt=\"\" width=\"493\" height=\"176\" name=\"Imagem 5\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Essa figura representa a pot\u00eancia em W consumida numa resid\u00eancia alimentada por uma tens\u00e3o de 220V ao longo de um dia. A energia consumida no per\u00edodo de maior consumo, em kWh, \u00e9 de:<\/b><\/span><\/span><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_a2765f99.png\" alt=\"\" width=\"775\" height=\"19\" name=\"Imagem 4564\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>02-(UFPE-PE)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Uma caixa d&#8217;\u00e1gua de 66 kg precisa ser i\u00e7ada at\u00e9 o telhado de um pequeno edif\u00edcio de altura igual a 18 m. A caixa \u00e9 i\u00e7ada com velocidade constante, em 2,0 min. Calcule a pot\u00eancia mec\u00e2nica m\u00ednima necess\u00e1ria para realizar essa tarefa, em watts. Despreze o efeito do atrito e considere g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>03-(PUC-RS)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Considere a figura a seguir, que representa uma parte dos degraus de uma escada, com suas medidas.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_af17f748.jpg\" alt=\"\" width=\"297\" height=\"155\" name=\"Imagem 6\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma pessoa de 80,0kg sobe 60 degraus dessa escada em 120s num local onde a acelera\u00e7\u00e3o da gravidade \u00e9 de 10,0m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. Desprezando eventuais perdas por atrito, o trabalho realizado ao subir esses 60 degraus e a pot\u00eancia m\u00e9dia durante a subida s\u00e3o, respectivamente,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 7,20kJ e 60,0W\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 0,720kJ e 6,00W\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 14,4kJ e 60,0W\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 1,44kJ e 12,0W\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 14,4kJ e 120W<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>04-(FGV-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Procurando um par\u00e2metro para assimilar o significado da informa\u00e7\u00e3o impressa na embalagem de um p\u00e3o de forma &#8211; valor energ\u00e9tico de duas fatias (50 g) = 100 kcal &#8211; , um rapaz calcula o tempo que uma l\u00e2mpada de 60 W permaneceria acesa utilizando essa energia, concluindo que esse tempo seria, aproximadamente,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dado: 1 cal = 4,2 J<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 100 minutos.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 110 minutos.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 120 minutos.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 140 minutos.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 180 minutos.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>05-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Em um terminal de cargas, uma esteira rolante \u00e9 utilizada para transportar caixas iguais, de massa M = 80 kg, com centros igualmente espa\u00e7ados de 1 m. Quando a velocidade da esteira \u00e9 1,5 m\/s, a pot\u00eancia dos motores para mant\u00ea-la em movimento \u00e9 P<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. Em um trecho de seu percurso, \u00e9 necess\u00e1rio planejar uma inclina\u00e7\u00e3o para que a esteira eleve a carga a uma altura de 5 m, como indicado. Para acrescentar essa rampa e manter a velocidade da esteira, os motores devem passar a fornecer uma pot\u00eancia adicional aproximada de<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_bd2c03b2.jpg\" alt=\"\" width=\"516\" height=\"168\" name=\"Imagem 7\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_ae9ea17b.png\" alt=\"\" width=\"774\" height=\"18\" name=\"Imagem 4565\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>06-(FATEC-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Em um apartamento, h\u00e1 um chuveiro el\u00e9trico que dissipa 6000W de pot\u00eancia quando usado com o seletor de temperatura na posi\u00e7\u00e3o inverno e 4000W quando usado com o seletor de temperatura na posi\u00e7\u00e3o ver\u00e3o. O casal que reside nesse apartamento utiliza o chuveiro em m\u00e9dia 30 minutos por dia,sempre com o seletor na posi\u00e7\u00e3o inverno.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_2e95368.jpg\" alt=\"\" width=\"284\" height=\"176\" name=\"Imagem 8\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Assustado com o alto valor da conta de luz, o marido informa a sua esposa que, a partir do dia seguinte, o chuveiro passar\u00e1 a ser utilizado apenas com o seletor na posi\u00e7\u00e3o ver\u00e3o. Com esse procedimento, num m\u00eas de 30 dias, a economia de energia el\u00e9trica, em quilowatts-hora, ser\u00e1 de:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_96e372ef.png\" alt=\"\" width=\"774\" height=\"19\" name=\"Imagem 4566\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>07-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Pedro mant\u00e9m uma dieta de 3 000 kcal di\u00e1rias e toda essa energia \u00e9 consumida por seu organismo a cada dia. Assim, ao final de um m\u00eas (30 dias), seu organismo pode ser considerado como equivalente a um aparelho el\u00e9trico que, nesse m\u00eas, tenha consumido<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>a) 50 kW.h\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>b) 80 kW.h\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>c) 100 kW.h\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 175 kW.h\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 225 kW.h<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Obs: 1 kW.h \u00e9 a energia consumida em 1 hora por um equipamento que desenvolve uma pot\u00eancia de 1 kW<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1 cal = 4 J<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>08-(ITA-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Projetado para subir com velocidade m\u00e9dia constante a uma altura de 32 m em 40 s, um elevador consome a pot\u00eancia de 8,5 kW de seu motor. Considere que seja de 370 kg a massa do elevador vazio e a acelera\u00e7\u00e3o da gravidade g = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. Nessas condi\u00e7\u00f5es, o n\u00famero m\u00e1ximo de passageiros, de 70 kg cada um, a ser transportado pelo elevador \u00e9<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_5f347259.png\" alt=\"\" width=\"774\" height=\"22\" name=\"Imagem 4567\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>09-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Em v\u00e1rios pa\u00edses no mundo, os recursos h\u00eddricos s\u00e3o utilizados como fonte de energia el\u00e9trica.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_ed891b34.jpg\" alt=\"\" width=\"337\" height=\"147\" name=\"Imagem 9\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O princ\u00edpio de funcionamento das hidrel\u00e9tricas est\u00e1 baseado no aproveitamento da energia potencial gravitacional da \u00e1gua, represada por uma barragem, para movimentar turbinas que convertem essa energia em energia el\u00e9trica. Considere que 700 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de \u00e1gua chegam por segundo a uma turbina situada 120 m abaixo do n\u00edvel da represa. Se a massa espec\u00edfica da \u00e1gua \u00e9 1000 kg\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e considerando g = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, calcule a pot\u00eancia fornecida pelo fluxo de \u00e1gua.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>10-(ENEM) <\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A efici\u00eancia de uma usina, do tipo da representada na figura, \u00e9 da ordem de 0,9, ou seja, 90% da energia da \u00e1gua no in\u00edcio do processo se transforma em energia el\u00e9trica.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_15046e1c.jpg\" alt=\"\" width=\"399\" height=\"177\" name=\"Imagem 10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A usina Ji-Paran\u00e1, do Estado de Rond\u00f4nia, tem pot\u00eancia instalada de 512 milh\u00f5es de watts, e a barragem tem altura de aproximadamente 120m. A vaz\u00e3o do Rio Ji-Paran\u00e1, em litros de \u00e1gua por segundo, deve ser da ordem de: (g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_6e0087e3.png\" alt=\"\" width=\"775\" height=\"18\" name=\"Imagem 4568\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>11-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> O teste Margaria de corrida em escada \u00e9 um meio r\u00e1pido de medida de pot\u00eancia anaer\u00f3bica de uma pessoa. Consiste em faz\u00ea-la subir uma escada de dois em dois degraus, cada um com 18 cm de altura, partindo com velocidade m\u00e1xima e constante de uma dist\u00e2ncia de alguns metros da escada. Quando pisa no 8<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. degrau, a pessoa aciona um cron\u00f4metro, que se desliga quando pisa no 12<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>degrau. Se o intervalo de tempo registrado para uma pessoa de 70 kg foi de 2,8 s e considerando a acelera\u00e7\u00e3o da gravidade igual a 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, a pot\u00eancia m\u00e9dia\u00a0 avaliada por este m\u00e9todo foi de<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_9e582e1f.png\" alt=\"\" width=\"775\" height=\"18\" name=\"Imagem 4569\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>12-(Uff-RJ<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>) O projeto de transposi\u00e7\u00e3o do rio S\u00e3o Francisco, ora em discuss\u00e3o, implicar\u00e1 a necessidade de se elevar 280 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de \u00e1gua por segundo at\u00e9 uma altura de 160 m. Sabe-se que a massa de um litro d&#8217;\u00e1gua \u00e9 um quilograma.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Determine o valor da pot\u00eancia necess\u00e1ria para esse fim, em watts.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>13-(Ufes)<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_315b50cb.jpg\" alt=\"\" width=\"580\" height=\"250\" name=\"Imagem 11\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O recalque das \u00e1guas do rio S\u00e3o Francisco ser\u00e1 feito atrav\u00e9s de quatro esta\u00e7\u00f5es elevat\u00f3rias, representadas na figura. Considerando que o fluxo de transposi\u00e7\u00e3o ser\u00e1 de 26 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de \u00e1gua por segundo, a pot\u00eancia m\u00ednima necess\u00e1ria para a transposi\u00e7\u00e3o ser\u00e1, aproximadamente, de:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_461d132d.png\" alt=\"\" width=\"774\" height=\"18\" name=\"Imagem 4570\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>14-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A usina hidrel\u00e9trica de Itaipu possui 20 turbinas, cada uma fornecendo uma pot\u00eancia el\u00e9trica \u00fatil de 680 MW, a partir de um desn\u00edvel de \u00e1gua de 120 m.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_ef193a85.jpg\" alt=\"\" width=\"353\" height=\"134\" name=\"Imagem 12\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>No complexo, constru\u00eddo no Rio Paran\u00e1, as \u00e1guas da represa passam em cada turbina com vaz\u00e3o de 600 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/s.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>) e d<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00e1gua<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>kg\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Estime o n\u00famero de domic\u00edlios, N, que deixariam de ser atendidos se, pela queda de um raio, uma dessas turbinas interrompesse sua opera\u00e7\u00e3o entre 17 h 30 min e 20 h 30 min, considerando que o consumo m\u00e9dio de energia, por domic\u00edlio, nesse per\u00edodo, seja de 4 kWh.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Estime a massa M, em kg, de \u00e1gua do rio que entra em cada turbina, a cada segundo.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Estime a pot\u00eancia mec\u00e2nica da \u00e1gua P, em MW, em cada turbina.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>NOTE E ADOTE:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Densidade da \u00e1gua = 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>kg\/m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1 MW = 1 megawatt = 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>6<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>W.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1 kWh = 1000 W . 3600 s = 3,6.10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>6<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>J<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Os valores mencionados foram aproximados para facilitar os c\u00e1lculos.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>15-(ITA-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Calcule a \u00e1rea \u00fatil das placas de energia solar de um sistema de aquecimento de \u00e1gua, para uma resid\u00eancia com quatro moradores, visando manter um acr\u00e9scimo m\u00e9dio de 30,0\u00b0 C em rela\u00e7\u00e3o \u00e0 temperatura ambiente.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_adcbc744.jpg\" alt=\"\" width=\"412\" height=\"150\" name=\"Imagem 13\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere que cada pessoa gasta 30,0 litros de \u00e1gua quente por dia e que, na latitude geogr\u00e1fica da resid\u00eancia, a convers\u00e3o m\u00e9dia mensal de energia \u00e9 de 60,0 kWh\/m\u00eas por metro quadrado de superf\u00edcie coletora. Considere ainda que o reservat\u00f3rio de \u00e1gua quente com capacidade para 200 litros apresente uma perda de energia de 0,30 kWh por m\u00eas para cada litro. \u00c9 dado o calor espec\u00edfico da \u00e1gua c = 4,19 J\/g\u00b0C e a densidade da \u00e1gua 1kg\/L.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>Gr\u00e1fico da pot\u00eancia em fun\u00e7\u00e3o do tempo<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>16-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A pot\u00eancia de uma m\u00e1quina em fun\u00e7\u00e3o do tempo variou da maneira indicada pelo gr\u00e1fico.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_d8628f7f.jpg\" alt=\"\" width=\"398\" height=\"178\" name=\"Imagem 14\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Qual o trabalho realizado pela m\u00e1quina desde zero segundo a 150 segundos?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>Rela\u00e7\u00e3o entre pot\u00eancia m\u00e9dia (P<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>m<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>) e velocidade m\u00e9dia (V<\/b><\/span><\/span><\/span><span style=\"color: #0000cc;\"><sub><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>m<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>17-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> No sistema da figura, o motor estacion\u00e1rio M, puxa um bloco de massa m=500kg com velocidade constante V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=0,50m\/s sobre uma superf\u00edcie horizontal, cujo coeficiente de atrito \u00e9 0,10. (g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_b401767.jpg\" alt=\"\" width=\"453\" height=\"111\" name=\"Imagem 15\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Qual deve ser a pot\u00eancia do motor?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>18- (UNIFESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Avalia-se que um atleta de 60kg, numa prova de 10000m rasos, desenvolve uma pot\u00eancia m\u00e9dia de 300W.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual o consumo m\u00e9dio de calorias desse atleta, sabendo que o tempo dessa prova \u00e9 de cerca de 0,50h?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dado: 1 cal = 4,2 J.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Admita que a velocidade do atleta \u00e9 constante. Qual a intensidade m\u00e9dia da for\u00e7a exercida sobre o atleta durante a corrida?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>19-(Ufsm-RS<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>) Um caminh\u00e3o transporta 30 toneladas de soja numa estrada retil\u00ednea e plana, em MRU, com velocidade de m\u00f3dulo igual a 72km\/h.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_46162386.jpg\" alt=\"\" width=\"298\" height=\"141\" name=\"Imagem 16\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Se 200 kW da pot\u00eancia do motor do caminh\u00e3o est\u00e3o sendo usados para vencer a for\u00e7a de resist\u00eancia do ar, o m\u00f3dulo dessa for\u00e7a \u00e9, em N,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 10000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 60000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 480000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 6000000\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 14400000<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>20- (Ufpe-PE)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um autom\u00f3vel se desloca em uma estrada plana e reta com velocidade constante v = 80 km\/h.,<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_220a326.jpg\" alt=\"\" width=\"235\" height=\"109\" name=\"Imagem 17\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A pot\u00eancia do motor do autom\u00f3vel \u00e9 P = 25 kW. Supondo que todas as for\u00e7as que atuam no autom\u00f3vel s\u00e3o constantes, calcule o m\u00f3dulo da for\u00e7a de atrito total, em newtons.<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_2a03f1d7.png\" alt=\"\" width=\"774\" height=\"20\" name=\"Imagem 4571\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>21- (FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Nos manuais de autom\u00f3veis, a caracteriza\u00e7\u00e3o dos motores \u00e9 feita em CV (cavalo-vapor). Essa unidade, proposta no tempo das primeiras m\u00e1quinas a vapor, correspondia \u00e0 capacidade de um cavalo t\u00edpico, que conseguia erguer, na vertical, com aux\u00edlio de uma roldana, um bloco de 75 kg, \u00e0 velocidade de 1 m\/s.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_b56553cf.jpg\" alt=\"\" width=\"356\" height=\"121\" name=\"Imagem 18\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Para subir uma ladeira, inclinada como na figura, um carro de 1000 kg, mantendo uma velocidade constante de 15 m\/s (54 km\/h), desenvolve uma pot\u00eancia \u00fatil que, em CV, \u00e9, aproximadamente, de: (g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_20971d49.png\" alt=\"\" width=\"774\" height=\"16\" name=\"Imagem 4572\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>22- (FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um elevador de carga, com massa M = 5 000 kg, \u00e9 suspenso por um cabo na parte externa de um edif\u00edcio em constru\u00e7\u00e3o. Nas condi\u00e7\u00f5es das quest\u00f5es a seguir, considere que o motor fornece a pot\u00eancia P = 150 kW. (g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_e64c15f4.jpg\" alt=\"\" width=\"164\" height=\"169\" name=\"Imagem 19\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Determine a for\u00e7a F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, em N, que o cabo exerce sobre o elevador, quando ele \u00e9 puxado com velocidade constante.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Determine a for\u00e7a F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>em N, que o cabo exerce sobre o elevador, no instante em que ele est\u00e1 subindo com uma acelera\u00e7\u00e3o para cima de m\u00f3dulo a = 5 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Levando em conta a pot\u00eancia P do motor, determine a velocidade V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>em m\/s, com que o elevador estar\u00e1 subindo, nas condi\u00e7\u00f5es do item (b) (a = 5 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) Determine a velocidade m\u00e1xima V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>M<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, em m\/s, com que o elevador pode subir quando puxado pelo motor.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>NOTE E ADOTE:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A pot\u00eancia P, desenvolvida por uma for\u00e7a F, \u00e9 igual ao produto da for\u00e7a pela velocidade V do corpo em que atua, quando V tem a dire\u00e7\u00e3o e o sentido da for\u00e7a.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>23-(Fuvest-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um carro de corrida de massa m=800kg, percorre uma pista de prova plana com velocidade constante V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=60m\/s \u00a0Nessa situa\u00e7\u00e3o, observa-se que a pot\u00eancia desenvolvida pelo motor P<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=120kW, \u00e9 praticamente utilizada para vencer a resist\u00eancia do ar Situa\u00e7\u00e3o 1, pista horizontal).<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Prosseguindo com os testes, faz-se o carro descer uma ladeira, com o motor desligado, de forma que mantenha a mesma velocidade V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e que enfrente a mesma resist\u00eancia do ar (situa\u00e7\u00e3o 2, inclina\u00e7\u00e3o<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a)<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_74279fdf.jpg\" alt=\"\" width=\"618\" height=\"118\" name=\"Imagem 20\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Finalmente, faz-se o carro subir uma ladeira, com a mesma velocidade V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, sujeito \u00e0 mesma resist\u00eancia do ar (situa\u00e7\u00e3o 3, inclina\u00e7\u00e3o<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>q)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Estime, para a situa\u00e7\u00e3o 1, o valor da for\u00e7a de resist\u00eancia do ar F<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>R<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, em newtons, que age sobre o carro no sentido oposto a seu movimento.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Estime, para a situa\u00e7\u00e3o 2, o seno do \u00e2ngulo de inclina\u00e7\u00e3o da ladeira, sem<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a, para que o carro des\u00e7a a ladeira com velocidade=60m\/s, constante.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Estime, para a Situa\u00e7\u00e3o 3, a pot\u00eancia P<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>do motor, em kW, para que o carro suba uma ladeira de inclina\u00e7\u00e3o dada por senq=0,3, mantendo a velocidade V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=60m\/s.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>24-(Ufpe)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um elevador de massa m<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 200 kg tem capacidade m\u00e1xima para 6 pessoas, cada uma com massa m<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>p<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 70 kg.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_1de28bb1.jpg\" alt=\"\" width=\"387\" height=\"158\" name=\"Imagem 21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Como forma de economizar energia, h\u00e1 um contra-peso de massa m<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>cp<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 220 kg. Calcule a pot\u00eancia m\u00ednima que o motor deve desenvolver para fazer com que o elevador possa subir com a carga m\u00e1xima e velocidade constante v = 0,5 m\/s. Expresse o resultado em kW. \u00a0Considere g = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>25-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A figura a seguir representa esquematicamente um elevador E com massa de 800kg e um contrapeso B, tamb\u00e9m de 800kg, acionados por um motor M.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_c41269b8.jpg\" alt=\"\" width=\"346\" height=\"199\" name=\"Imagem 22\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A carga interna do elevador \u00e9 de 500kg.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual a pot\u00eancia fornecida pelo motor com o elevador subindo com velocidade constante de 1m\/s?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Qual a for\u00e7a aplicada pelo motor atrav\u00e9s do cabo, para acelerar o elevador em ascens\u00e3o, a raz\u00e3o de 0,5m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>?<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>26- (Ufal)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um pedra \u00e9 arremessada horizontalmente por uma pessoa que lhe aplica uma for\u00e7a de intensidade F que varia com a velocidade v da pedra segundo o gr\u00e1fico.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_6d40cfb1.png\" alt=\"\" width=\"298\" height=\"181\" name=\"Imagem 4573\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A pot\u00eancia instant\u00e2nea da for\u00e7a F quando a velocidade da pedra \u00e9 de 20 m\/s \u00e9, em W,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 8,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 6,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 4,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 2,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 1,0 \u00d7 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p>&nbsp;<\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>Rendimento<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>27-(PUC-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um dispositivo consome 1.000W realizando um trabalho de 3.200J em 4s. Seu rendimento vale:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_56658e9a.png\" alt=\"\" width=\"774\" height=\"21\" name=\"Imagem 4574\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>28-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um motor recebe durante 1 minuto a pot\u00eancia de 200W, realizando um trabalho de 8.640J. Calcule o rendimento do motor.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>29-(ITA-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Uma escada rolante transporta passageiros do andar t\u00e9rreo A ao andar superior B, com velocidade constante.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_38fca1cf.jpg\" alt=\"\" width=\"127\" height=\"199\" name=\"Imagem 24\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A escada tem comprimento total igual a 15m, degraus em n\u00famero de 75 e inclina\u00e7\u00e3o igual a 30<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. Dados: sen30<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=0,5 e g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. Determine:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) o trabalho da for\u00e7a motora necess\u00e1rio para elevar um passageiro de 80kg de A at\u00e9 B.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) a pot\u00eancia correspondente ao item anterior empregada pelo motor que aciona o mecanismo efetuando o transporte em 30s.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) o rendimento do motor, sabendo-se que a pot\u00eancia total \u00e9 de 400W.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>30-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um motor de pot\u00eancia \u00fatil igual a 125W, funcionando como elevador, eleva a 10m de altura, com velocidade<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_c1589445.jpg\" alt=\"\" width=\"204\" height=\"172\" name=\"Imagem 25\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>constante, um corpo de peso igual a 50N, no tempo de:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_a24c310a.png\" alt=\"\" width=\"775\" height=\"20\" name=\"Imagem 4575\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>31-(Inatel-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Rendimento de uma m\u00e1quina \u00e9 a sua:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) capacidade de realiza\u00e7\u00e3o de trabalho\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) taxa temporal de realiza\u00e7\u00e3o de trabalho\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c)capacidade de ampliar as for\u00e7as aplicadas nela\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) taxa de transforma\u00e7\u00e3o de trabalho em calor\u00a0\u00a0\u00a0\u00a0\u00a0 e) taxa de transforma\u00e7\u00e3o da energia dispon\u00edvel em trabalho<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>32-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um autom\u00f3vel de massa 800kg partiu do repouso em uma estrada retil\u00ednea e horizontal, devido \u00e0 a\u00e7\u00e3o de uma for\u00e7a constante de 1.800N, paralela \u00e0 estrada e aplicada pelo seu motor, de rendimento 45 %. Ao percorrer 400m, sob a a\u00e7\u00e3o exclusiva dessa for\u00e7a, o consumo de energia proveniente do combust\u00edvel foi, no m\u00ednimo, igual a:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_db4155f8.png\" alt=\"\" width=\"775\" height=\"22\" name=\"Imagem 4576\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>33- (UNIFESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Ap\u00f3s algumas informa\u00e7\u00f5es sobre o carro, sa\u00edmos em dire\u00e7\u00e3o ao trecho off-road. Na primeira acelerada j\u00e1 deu para perceber a for\u00e7a do modelo.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_2708a8cd.jpg\" alt=\"\" width=\"226\" height=\"142\" name=\"Imagem 26\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>De acordo com n\u00fameros do fabricante, s\u00e3o 299 cavalos de pot\u00eancia [&#8230;] e os 100 km\/h iniciais s\u00e3o conquistados em satisfat\u00f3rios 7,5 segundos, gra\u00e7as \u00e0 boa rela\u00e7\u00e3o peso\/pot\u00eancia, j\u00e1 que o carro vem com v\u00e1rios componentes de alum\u00ednio.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(http:\/\/carsale.uol.com.br\/opapoecarro\/testes\/aval_050404discovery.shtml 5)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O texto descreve um teste de avalia\u00e7\u00e3o de um ve\u00edculo importado, lan\u00e7ado neste ano no mercado brasileiro. Sabendo que a massa desse carro \u00e9 de 2 400 kg, e admitindo 1 cv = 740 W e 100 km\/h = 28 m\/s, pode-se afirmar que, para atingir os 100 km\/h iniciais, a pot\u00eancia \u00fatil m\u00e9dia desenvolvida durante o teste, em rela\u00e7\u00e3o \u00e0 pot\u00eancia total do carro, foi, aproximadamente de<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_a30b2f33.png\" alt=\"\" width=\"774\" height=\"19\" name=\"Imagem 4577\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>34- (Ufg)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Nas usinas hidroel\u00e9tricas, a energia potencial gravitacional de um reservat\u00f3rio de \u00e1gua \u00e9 convertida em energia el\u00e9trica atrav\u00e9s de turbinas. Uma usina de pequeno porte possui vaz\u00e3o de \u00e1gua de 400 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/s, queda de 9 m, efici\u00eancia de 90% e \u00e9 utilizada<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_888eaba3.jpg\" alt=\"\" width=\"308\" height=\"155\" name=\"Imagem 27\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>para o abastecimento de energia el\u00e9trica de uma comunidade cujo consumo per capita mensal \u00e9 igual a 360 kWh.(g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>). Calcule:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a pot\u00eancia el\u00e9trica gerada pela usina;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) o n\u00famero de habitantes que ela pode atender.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>35-(FUVEST-SP<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)\u00a0 O que consome mais energia ao longo de um m\u00eas, uma resid\u00eancia ou um carro?<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_4000fed4.jpg\" alt=\"\" width=\"333\" height=\"159\" name=\"Imagem 28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Suponha que o consumo mensal de energia el\u00e9trica residencial de uma fam\u00edlia, E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>R<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, seja 300 kWh (300 quilowatts . hora) e que, nesse per\u00edodo, o carro da fam\u00edlia tenha consumido uma energia E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>C<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, fornecida por 180 litros de gasolina. Assim, a raz\u00e3o E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>C<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/E<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>R<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>ser\u00e1, aproximadamente:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Calor de combust\u00e3o da gasolina \u2248 30 000 kJ\/litro\u00a0 &#8212;\u00a0 1 kJ = 1 000 J<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_af88201d.png\" alt=\"\" width=\"775\" height=\"16\" name=\"Imagem 4578\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>36-(UNICAMP-SP<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>) A tra\u00e7\u00e3o animal pode ter sido a primeira fonte externa de energia usada pelo homem e representa um aspecto marcante da sua rela\u00e7\u00e3o com os animais.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) O gr\u00e1fico mostra a for\u00e7a de tra\u00e7\u00e3o exercida por um cavalo como fun\u00e7\u00e3o do deslocamento de uma carro\u00e7a. O trabalho realizado<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_3a3d51ac.jpg\" alt=\"\" width=\"321\" height=\"160\" name=\"Imagem 29\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>pela for\u00e7a \u00e9 dado pela \u00e1rea sob a curva Fxd. Calcule o trabalho realizado pela for\u00e7a de tra\u00e7\u00e3o do cavalo na regi\u00e3o em que ela \u00e9 constante.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_27874ad8.jpg\" alt=\"\" width=\"364\" height=\"151\" name=\"Imagem 30\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) No sistema internacional, a unidade de pot\u00eancia \u00e9 o watt (W) = 1 J\/s. O uso de tra\u00e7\u00e3o animal era t\u00e3o difundido no passado que James Watt, aprimorador da m\u00e1quina a vapor, definiu uma unidade de pot\u00eancia tomando os cavalos como refer\u00eancia. O cavalo \u2013<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_91b661a.jpg\" alt=\"\" width=\"377\" height=\"162\" name=\"Imagem 31\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>vapor (CV), definido a partir da id\u00e9ia de Watt, vale aproximadamente 740 W. Suponha que um cavalo, transportando uma pessoa ao longo do dia, realize um trabalho total de 444.000 J. Sabendo que o motor de uma moto, operando na pot\u00eancia m\u00e1xima, executa esse mesmo trabalho em 40 s, calcule a pot\u00eancia m\u00e1xima do motor da moto em CV.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>37-(FGV-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Conhecido como parafuso de Arquimedes, este dispositivo foi utilizado pelos eg\u00edpcios para retirar \u00e1gua do Nilo. Um modelo simples pode ser constru\u00eddo com uma mangueira enrolada em uma haste reta. Quando a haste \u00e9 girada no sentido conveniente, a extremidade inferior da mangueira entra e sai da \u00e1gua, aprisionando uma por\u00e7\u00e3o desta no interior da mangueira. Enquanto o parafuso gira, a \u00e1gua capturada \u00e9 obrigada a subir at\u00e9 o outro extremo da mangueira, onde \u00e9 despejada.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_f1a5a60.jpg\" alt=\"\" width=\"450\" height=\"177\" name=\"Imagem 32\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Com um desses dispositivos, elevou-se \u00e1gua proveniente de um rio at\u00e9 um reservat\u00f3rio, localizado a 2,0 m de altura em rela\u00e7\u00e3o ao n\u00edvel de \u00e1gua desse rio. O parafuso de Arquimedes utilizado tinha 100 voltas completas de uma mangueira de borracha, sendo que cada anel podia transportar 1,0 cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de \u00e1gua. Desconsiderando atritos e supondo uma rota\u00e7\u00e3o uniforme, admitindo que o tempo necess\u00e1rio para que o parafuso girasse 360\u00ba em torno de seu eixo era de 2,0 s, a pot\u00eancia \u00fatil da fonte do movimento de rota\u00e7\u00e3o, em W, era de: Dado: densidade da \u00e1gua = 1,0 g\/cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>; acelera\u00e7\u00e3o da gravidade = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_6e57998e.png\" alt=\"\" width=\"775\" height=\"20\" name=\"Imagem 4579\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>38-(PUC-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Na leitura da placa de identifica\u00e7\u00e3o de um chuveiro el\u00e9trico, constatam-se os seguintes<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_59ab8952.jpg\" alt=\"\" width=\"251\" height=\"139\" name=\"Imagem 33\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>valores: 127 V &#8211; 4800W. \u00c9 CORRETO afirmar:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Esse equipamento consome uma energia de 4800 J a cada segundo de funcionamento.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) A corrente el\u00e9trica correta para o funcionamento desse chuveiro \u00e9 de no m\u00e1ximo 127 V.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) A tens\u00e3o adequada para o seu funcionamento n\u00e3o pode ser superior a 4800 W.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) N\u00e3o \u00e9 poss\u00edvel determinar o valor correto da corrente el\u00e9trica com as informa\u00e7\u00f5es dispon\u00edveis.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>39-(UFOP-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Normalmente, para elevar as camas em hospitais, as enfermeiras utilizam o sistema rosca-manivela.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_4471938c.jpg\" alt=\"\" width=\"377\" height=\"150\" name=\"Imagem 34\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere que o bra\u00e7o de uma manivela \u00e9 de 0,2 m e que uma enfermeira, ao gir\u00e1-lo com uma velocidade constante, gasta 20 s para dar 10 voltas completas, elevando, assim, um peso de 450 N a uma altura de 0,5 m. Desprezando as perdas com atrito, calcule:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a velocidade angular da manivela;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) o trabalho realizado pela enfermeira;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) a pot\u00eancia desenvolvida pela enfermeira.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>40-(UFG-GO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Um trabalhador da constru\u00e7\u00e3o civil usa uma polia e uma corda para transportar telhas<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_7dcb4a42.jpg\" alt=\"\" width=\"218\" height=\"194\" name=\"Imagem 35\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>at\u00e9 a cobertura de uma\u00a0resid\u00eancia, a 3 m de altura. Se o trabalhador transporta 20 telhas por vez durante duas horas, \u00e0 velocidade m\u00e9dia de 0,1 m\/s, calcule:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a quantidade de calorias a mais que deve ser ingerida pelo trabalhador, sabendo-se que apenas 15% dessa energia ser\u00e1 transformada em energia mec\u00e2nica pelo corpo humano;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) o n\u00famero total de telhas transportadas nesse intervalo de duas horas.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>41-(UFSC-SC)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Para que o trabalho na agricultura tenha maior produtividade e seja menos penoso, os<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_71e0d5bd.jpg\" alt=\"\" width=\"244\" height=\"134\" name=\"Imagem 36\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>agricultores contam com a possibilidade de uso de instrumentos e maquin\u00e1rios desde os mais simples aos mais sofisticados. Na tarefa de arar a terra pode ser empregada a tra\u00e7\u00e3o animal e ou a mec\u00e2nica, como os tratores. \u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Para medir o trabalho realizado por uma for\u00e7a, de acordo com o tempo gasto para que ele seja realizado, utiliza-se uma grandeza escalar chamada pot\u00eancia.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Com rela\u00e7\u00e3o a esse tema, \u00e9 correto afirmar que:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) o\u00a0 tempo necess\u00e1rio para arar uma \u00e1rea de 20.000 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>do mesmo tipo de solo, utilizando um trator de 65 cv, \u00e9 menor do que se for utilizado um trator de 130 cv.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) quanto menor for o tempo empregado por uma m\u00e1quina para realizar o trabalho de arar 20.000 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de terra, maior ser\u00e1 a sua pot\u00eancia.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) quanto maior for a pot\u00eancia de uma m\u00e1quina, mais lentamente ela realiza o trabalho.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) a rela\u00e7\u00e3o P = trabalho realizado pela for\u00e7a\/tempo decorrido na realiza\u00e7\u00e3o implica que a unidade de pot\u00eancia no Sistema<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Internacional de Unidades ser\u00e1 1 J\/h.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>P<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o <\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= W<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/\u0394t\u00a0 &#8212; \u00a0P<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o <\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= W<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>F<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/\u0394t\u00a0 &#8212;\u00a0 o tempo de realiza\u00e7\u00e3o de um trabalho \u00e9 inversamente proporcional \u00e0 pot\u00eancia empregada\u00a0 &#8212;\u00a0 isso significa que quanto menor \u00e9 o tempo, maior \u00e9 a pot\u00eancia\u00a0 &#8212;\u00a0<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>R- B<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>42-(ENEM-MEC)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Com o objetivo de se testar a efici\u00eancia de fornos de micro-ondas, planejou-se o<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_f1e27b87.jpg\" alt=\"\" width=\"417\" height=\"111\" name=\"Imagem 37\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>aquecimento em 10\u00b0C de\u00a0amostras de diferentes subst\u00e2ncias, cada uma com determinada massa, em cinco fornos de marcas distintas.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Nesse teste, cada forno operou \u00e0 pot\u00eancia m\u00e1xima.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O forno mais eficiente foi aquele que<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) forneceu a maior quantidade de energia \u00e0s amostras.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0b) cedeu energia \u00e0 amostra de maior massa em mais tempo.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) forneceu a maior quantidade de energia em menos tempo.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d) cedeu energia \u00e0 amostra de menor calor espec\u00edfico mais lentamente.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) forneceu a menor quantidade de energia \u00e0s amostras em menos tempo.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(UEG-GO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Texto para as quest\u00f5es de n\u00fameros 43 e 44.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A habilidade de uma pessoa em exercer uma atividade f\u00edsica depende de sua capacidade de consumir oxig\u00eanio. A forma f\u00edsica<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_df7b6397.jpg\" alt=\"\" width=\"555\" height=\"123\" name=\"Imagem 38\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de uma pessoa \u00e9 dada pela absor\u00e7\u00e3o m\u00e1xima de oxig\u00eanio por per\u00edodos relativamente longos.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere que uma pessoa, em boa forma f\u00edsica, consiga, por longos per\u00edodos, absorver at\u00e9 cerca de 50 mL de O<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>por minuto e por quilograma de sua massa, liberando 4,9 kcal por litro de O<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere 1 kcal = 4.200 J e g = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>43-(UEG-GO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 A energia liberada por uma pessoa que utiliza 2,5 litros de O<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>em sua respira\u00e7\u00e3o seria o suficiente para elevar um bloco de 400 kg a uma altura de, aproximadamente:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_9e0ee424.png\" alt=\"\" width=\"775\" height=\"15\" name=\"graphics2\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>44-(UEG-GO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Qual \u00e9 a pot\u00eancia (em watts) liberada, por cada kg de massa,\u00a0 por uma pessoa absorvendo 50 ml de O<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>?<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_870bc897.png\" alt=\"\" width=\"774\" height=\"21\" name=\"graphics3\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>45-(EsPCEx)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_6f8a76ff.jpg\" alt=\"\" width=\"411\" height=\"131\" name=\"Imagem 39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma for\u00e7a constante<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_18e596e3.jpg\" alt=\"\" width=\"10\" height=\"19\" name=\"graphics4\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de intensidade 25 N atua sobre um bloco e faz com que ele sofra um deslocamento horizontal. A dire\u00e7\u00e3o da for\u00e7a forma um \u00e2ngulo de 60\u00ba com a dire\u00e7\u00e3o do deslocamento.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_ecdd69ca.jpg\" alt=\"\" width=\"356\" height=\"138\" name=\"graphics5\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Desprezando todos os atritos, a for\u00e7a faz o bloco percorrer uma dist\u00e2ncia de 20 m em 5 s. A pot\u00eancia desenvolvida pela for\u00e7a \u00e9 de:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dados: sen 60\u00b0 = 0,87 e cos 60\u00ba = 0,50<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_3fd43bc1.png\" alt=\"\" width=\"775\" height=\"22\" name=\"graphics6\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>46-(ETEC-SP)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_afdfc07a.jpg\" alt=\"\" width=\"619\" height=\"117\" name=\"graphics7\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A hidroponia consiste em um m\u00e9todo de plantio fora do solo em que as plantas recebem seus nutrientes de uma solu\u00e7\u00e3o, que flui em canaletas, e \u00e9 absorvida pelas ra\u00edzes. Por meio de uma bomba hidr\u00e1ulica, em determinada horta hidrop\u00f4nica, a solu\u00e7\u00e3o \u00e9 elevada at\u00e9 uma altura de 80 cm, sendo vertida na canaleta onde est\u00e3o presas as mudas. Devido a uma ligeira inclina\u00e7\u00e3o da<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>canaleta, a solu\u00e7\u00e3o se move para o outro extremo, l\u00e1 sendo recolhida e direcionada ao reservat\u00f3rio do qual a bomba reimpulsiona o l\u00edquido, como mostra a figura.<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_8d7ea750.jpg\" alt=\"\" width=\"751\" height=\"143\" name=\"graphics8\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Suponha que nessa horta hidrop\u00f4nica foi empregada uma bomba com pot\u00eancia de 20 W. Se toda a pot\u00eancia dessa bomba<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>pudesse ser empregada para elevar a \u00e1gua at\u00e9 a canaleta, a cada um segundo (1 s), o volume de \u00e1gua que fluiria seria, em litros,<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_8889e053.png\" alt=\"\" width=\"775\" height=\"23\" name=\"graphics9\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>47-(UFPA-PA)<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_afcaade1.jpg\" alt=\"\" width=\"541\" height=\"120\" name=\"Imagem 44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um\u00a0 painel\u00a0 de\u00a0 energia\u00a0 solar\u00a0 de\u00a0 \u00e1rea\u00a0 igual a\u00a0 1 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>produz cerca de 0,5 kW.h por dia.<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Pensando nisso, um consumidor interessado nessa fonte de energia resolveu avaliar sua necessidade de consumo di\u00e1rio, que est\u00e1 listada na tabela abaixo.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_eddedd78.jpg\" alt=\"\" width=\"591\" height=\"131\" name=\"Imagem 45\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A partir desses dados, o n\u00famero m\u00ednimo de pain\u00e9is solares que esse consumidor precisa adquirir para fazer frente \u00e0s suas necessidades de consumo di\u00e1rio de energia \u00e9<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_f5848775.png\" alt=\"\" width=\"775\" height=\"21\" name=\"graphics10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>48-(AFA)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_8da7c46e.jpg\" alt=\"\" width=\"210\" height=\"114\" name=\"Imagem 46\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O motor de um determinado ve\u00edculo consome 8,0 litros de combust\u00edvel em uma hora. Sabendo-se<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_c8761fcd.jpg\" alt=\"\" width=\"271\" height=\"152\" name=\"Imagem 47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>que o calor de combust\u00e3o desse combust\u00edvel \u00e9 de 10000 cal\/g, que sua densidade \u00e9 0,675g\/cm<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e que o motor desenvolve uma pot\u00eancia de 24 kW, o rendimento desse motor, em porcentagem, \u00e9 de (considere 1 cal = 4 J)<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_c400966f.png\" alt=\"\" width=\"775\" height=\"18\" name=\"graphics11\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>49-(FUVEST-SP)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_bd5e974c.jpg\" alt=\"\" width=\"514\" height=\"120\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A energia que um atleta gasta pode ser determinada pelo volume de oxig\u00eanio por ele consumido na respira\u00e7\u00e3o. Abaixo est\u00e1 apresentado o gr\u00e1fico do volume\u00a0 V de oxig\u00eanio, em litros por minuto, consumido por um atleta de massa corporal de 70 kg, em fun\u00e7\u00e3o de sua velocidade, quando ele anda ou corre.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_4c31439c.jpg\" alt=\"\" width=\"590\" height=\"207\" name=\"Imagem 49\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considerando que para cada litro de oxig\u00eanio consumido s\u00e3o gastas 5 kcal e usando as informa\u00e7\u00f5es do gr\u00e1fico, determine, para esse atleta,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a velocidade a partir da qual ele passa a gastar menos energia correndo do que andando;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) a quantidade de energia por ele gasta durante 12 horas de repouso (parado);<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) a pot\u00eancia dissipada, em watts, quando ele corre a 15 km\/h;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) quantos minutos ele deve andar, a 7 km\/h, para gastar a quantidade de energia armazenada com a ingest\u00e3o de uma barra de chocolate de 100 g, cujo conte\u00fado energ\u00e9tico \u00e9 560 kcal.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>50-(FUVEST-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_138bf8d2.jpg\" alt=\"\" width=\"588\" height=\"119\" name=\"graphics12\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um pequeno cata-vento do tipo Savonius, como o esquematizado na figura abaixo, acoplado a uma bomba d&#8217;\u00e1gua, \u00e9 utilizado em uma<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/potencia\/i_377af18932384684_html_4beff4da.jpg\" alt=\"\" width=\"486\" height=\"169\" name=\"Imagem 51\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>propriedade rural. A pot\u00eancia \u00fatil\u00a0 P (W) desse sistema para bombeamento de \u00e1gua pode ser obtida\u00a0 pela express\u00e3o P = 0,1xAxv<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, em que A (m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>) \u00e9 a \u00e1rea total das p\u00e1s do cata-vento e v (m\/s), a velocidade do vento. Considerando um cata-vento com \u00e1rea total das p\u00e1s de 2 m<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, velocidade do vento de 5 m\/s e a \u00e1gua sendo elevada de 7,5 m na vertical, calcule<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a pot\u00eancia \u00fatil P do sistema;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) a energia E necess\u00e1ria para elevar 1l de \u00e1gua;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) o volume V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de \u00e1gua bombeado por segundo;<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) o volume V<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>de \u00e1gua, bombeado por segundo, se a velocidade do vento cair pela metade.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Pot\u00eancia de uma for\u00e7a\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/potencia-de-uma-forca\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-potencia-de-uma-forca\/\"><span style=\"color: #000080;\">Confira o gabarito e a resolu\u00e7\u00e3o comentada<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre Pot\u00eancia de uma for\u00e7a 01-(UFSM-RS) Leia a informa\u00e7\u00e3o a seguir. A constru\u00e7\u00e3o de usinas geradoras de eletricidade causa impacto para o meio ambiente, mas pode proporcionar uma melhor qualidade de vida, trazendo conforto em resid\u00eancias. Observe a figura: Essa figura representa a pot\u00eancia em W consumida numa resid\u00eancia alimentada por uma tens\u00e3o de<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1320,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1322","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1322","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1322"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1322\/revisions"}],"predecessor-version":[{"id":10854,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1322\/revisions\/10854"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1320"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1322"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}