{"id":1250,"date":"2015-08-26T00:57:02","date_gmt":"2015-08-26T00:57:02","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1250"},"modified":"2024-08-23T13:19:07","modified_gmt":"2024-08-23T13:19:07","slug":"exercicios-de-vestibulares-com-resolucao-comentada-sobre-funcao-horaria-da-velocidade-e-da-aceleracao-do-mhs","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/mhs\/funcao-horaria-da-velocidade-e-da-aceleracao-do-mhs\/exercicios-de-vestibulares-com-resolucao-comentada-sobre-funcao-horaria-da-velocidade-e-da-aceleracao-do-mhs\/","title":{"rendered":"Fun\u00e7\u00e3o hor\u00e1ria da velocidade e da acelera\u00e7\u00e3o do MHS"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Fun\u00e7\u00e3o hor\u00e1ria da velocidade e da acelera\u00e7\u00e3o do MHS<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1-(UFB)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 A fun\u00e7\u00e3o hor\u00e1ria da elonga\u00e7\u00e3o de uma part\u00edcula em MHS \u00e9 x = 4.cos(p<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>+<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>pt) SI.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a fun\u00e7\u00e3o hor\u00e1ria da velocidade<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) a velocidade m\u00e1xima e a velocidade m\u00ednima<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) o gr\u00e1fico da velocidade em fun\u00e7\u00e3o do tempo<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) a fun\u00e7\u00e3o hor\u00e1ria da acelera\u00e7\u00e3o<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) a acelera\u00e7\u00e3o m\u00e1xima e a acelera\u00e7\u00e3o m\u00ednima<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>f) o gr\u00e1fico da acelera\u00e7\u00e3o em fun\u00e7\u00e3o do tempo<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>g) o gr\u00e1fico da acelera\u00e7\u00e3o a em fun\u00e7\u00e3o da elonga\u00e7\u00e3o x<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2-(UFCE)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A figura a seguir mostra uma part\u00edcula P, em movimento circular uniforme, em um c\u00edrculo de raio r, com velocidade angular constante w, no tempo t = 0.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_4f81dea0.gif\" alt=\"\" width=\"377\" height=\"253\" name=\"Imagem 5\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A proje\u00e7\u00e3o da part\u00edcula no eixo x executa um movimento tal que a fun\u00e7\u00e3o hor\u00e1ria vf(t), de sua velocidade, e expressa por:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) vf(t) = w r<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) ) vf(t) = w r cos (wt +\u00a0<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>j)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) vf(t) = &#8211; w r cos (wt +\u00a0<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>j)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>d) vf(t) = &#8211; w r sen (wt +\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>\u00a0<\/b><\/span><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>j<\/b><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) ) vf(t) =\u00a0 w r sen (wt +\u00a0<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>j)<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3-(UFPB)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Uma part\u00edcula material executa um movimento harm\u00f4nico simples (MHS) em torno do ponto x = 0. Sua acelera\u00e7\u00e3o, em fun\u00e7\u00e3o da posi\u00e7\u00e3o, \u00e9 descrita pelo gr\u00e1fico a seguir.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_e04ee4c8.gif\" alt=\"\" width=\"403\" height=\"251\" name=\"Imagem 6\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Nessas condi\u00e7\u00f5es, a freq\u00fc\u00eancia angular do MHS \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>a) 4 rad\/s<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>b) 3 rad\/s<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>c) 2 rad\/s<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 1 rad\/s<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 0,5 rad\/s<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>4-(UFF-RJ)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Medidores de tempo s\u00e3o, em geral, baseados em osciladores peri\u00f3dicos. Um exemplo mec\u00e2nico simples de um desses osciladores \u00e9 obtido com um carrinho, preso a duas molas ideais, que oscila, sem atrito, entre as posi\u00e7\u00f5es x =<\/b><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sup><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00b1<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>L em torno da sua posi\u00e7\u00e3o de equil\u00edbrio x = 0, conforme ilustrado na figura 1.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Assinale o gr\u00e1fico que melhor representa a acelera\u00e7\u00e3o do carrinho em fun\u00e7\u00e3o da sua posi\u00e7\u00e3o x.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_dd4fc8eb.gif\" alt=\"\" width=\"808\" height=\"350\" name=\"Imagem 7\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>5- (MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um disco de 20cm de di\u00e2metro gira uniformemente em torno de um eixo O, sobre um plano horizontal executando 60rpm. Perpendicularmente ao plano do disco, existe um anteparo, conforme figura.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_88e82745.jpg\" alt=\"\" width=\"389\" height=\"214\" name=\"Imagem 8\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Ao fixarmos um objeto cil\u00edndrico de pequeno di\u00e2metro. Perpendicularmente ao disco, num ponto de sua periferia, o mesmo passa a descrever um \u00a0MCU de freq\u00fc\u00eancia igual a do disco Pede-se a m\u00e1xima velocidade da sombra do objeto.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>6-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Uma part\u00edcula em MHS tem velocidade m\u00e1xima 2,0pm\/s. Se a amplitude do movimento \u00e9 20cm, seu per\u00edodo \u00e9 de:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_24bc601a.png\" alt=\"\" width=\"775\" height=\"18\" name=\"graphics42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>7-(PUC-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A figura abaixo representa uma sen\u00f3ide para t&gt;0, indicando a velocidade do ponto P m\u00f3vel na trajet\u00f3ria (0,x), em fun\u00e7\u00e3o do tempo.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_38baa61.jpg\" alt=\"\" width=\"437\" height=\"190\" name=\"Imagem 9\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) sua velocidade inicial e sua fase inicial<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) sua pulsa\u00e7\u00e3o (velocidade angular) e sua amplitude<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) a maior dist\u00e2ncia que ele alcan\u00e7a da origem<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) a acelera\u00e7\u00e3o m\u00e1xima por ele adquirida<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>8-(UFCE)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um carrinho desloca-se com velocidade constante, v<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, sobre uma superf\u00edcie horizontal sem atrito, conforme figura.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_a34e4294.jpg\" alt=\"\" width=\"327\" height=\"126\" name=\"Imagem 10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O carrinho choca-se contra uma mola de massa desprez\u00edvel, ficando preso a ela. O sistema mola+carrinho come\u00e7a ent\u00e3o a oscilar em movimento harm\u00f4nico simples, com amplitude de valor A. Determine o per\u00edodo de oscila\u00e7\u00e3o do sistema.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>9<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-(<\/b><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Fuvest &#8211; SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Dois corpos, A e B, ligados por um fio, encontram-se presos \u00e0 extremidade de uma mola e em repouso. Parte-se o fio que liga os corpos, e o corpo<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_d5b62c0e.gif\" alt=\"\" width=\"12\" height=\"13\" name=\"Imagem 11\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0passa a executar um movimento oscilat\u00f3rio, descrito pelo gr\u00e1fico abaixo:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_b4373957.gif\" alt=\"\" width=\"361\" height=\"284\" name=\"Imagem 12\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Determine a frequ\u00eancia, a amplitude e a pulsa\u00e7\u00e3o do movimento de A.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Escreva a equa\u00e7\u00e3o hor\u00e1ria das posi\u00e7\u00f5es Y do corpo A, conforme o gr\u00e1fico.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>10-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Um\u00a0m\u00f3vel com\u00a0MHS obedece \u00e0 fun\u00e7\u00e3o hor\u00e1ria x=7.cos(p\/2.t), onde x \u00e9 medido em cent\u00edmetros e<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_99176a33.gif\" alt=\"\" width=\"6\" height=\"12\" name=\"Imagem 13\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>em segundos. Calcule:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) O tempo necess\u00e1rio para que este m\u00f3vel v\u00e1 da posi\u00e7\u00e3o de equil\u00edbrio para a posi\u00e7\u00e3o de elonga\u00e7\u00e3o m\u00e1xima.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) A velocidade m\u00e1xima e a acelera\u00e7\u00e3o m\u00e1xima<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>11-(UFMS)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A figura 1 representa um sistema mec\u00e2nico que ilustra o funcionamento de um motor a combust\u00e3o, simplificado, com apenas tr\u00eas pe\u00e7as: virabrequim, biela e pist\u00e3o. Essas tr\u00eas pe\u00e7as est\u00e3o acopladas entre si, atrav\u00e9s de eixos articulados. Enquanto o virabrequim gira com velocidade angular constante, no sentido hor\u00e1rio, a biela faz o pist\u00e3o subir e descer num movimento oscilat\u00f3rio. A posi\u00e7\u00e3o do pist\u00e3o no eixo vertical y, \u00e9 dada pela proje\u00e7\u00e3o do ponto de articula\u00e7\u00e3o entre a biela e o pist\u00e3o sobre esse eixo.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Essa posi\u00e7\u00e3o no eixo y, oscila entre as amplitudes +A e -A.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_1f8910a3.jpg\" alt=\"\" width=\"295\" height=\"206\" name=\"Imagem 14\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Chamemos de y, v<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>y<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e a<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>y<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, respectivamente, a posi\u00e7\u00e3o, a velocidade e a acelera\u00e7\u00e3o do ponto de articula\u00e7\u00e3o entre a biela e o pist\u00e3o.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Se iniciarmos a marca\u00e7\u00e3o do tempo t, quando a posi\u00e7\u00e3o do ponto de articula\u00e7\u00e3o entre a biela e o pist\u00e3o estiver na posi\u00e7\u00e3o y = 0, como mostra a figura 1, assinale a alternativa que apresenta corretamente os gr\u00e1ficos correspondentes \u00e0s posi\u00e7\u00f5es y, \u00e0s velocidades v<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>y<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e \u00e0s acelera\u00e7\u00f5es a<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>y<\/b><\/span><\/span><\/sub><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>em fun\u00e7\u00e3o do tempo.<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_4cc34284.jpg\" alt=\"\" width=\"295\" height=\"61\" name=\"Imagem 15\" align=\"BOTTOM\" border=\"0\" \/><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b><br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_ecbf571.jpg\" alt=\"\" width=\"289\" height=\"137\" name=\"Imagem 16\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_134fb452.jpg\" alt=\"\" width=\"420\" height=\"174\" name=\"Imagem 17\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>12-(UFPR-PR)\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A pe\u00e7a de uma m\u00e1quina est\u00e1 presa a uma mola e executa um movimento harm\u00f4nico simples, oscilando em uma dire\u00e7\u00e3o<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_c8c02.jpg\" alt=\"\" width=\"614\" height=\"85\" name=\"Imagem 19\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>horizontal. O gr\u00e1fico a seguir representa a posi\u00e7\u00e3o x da pe\u00e7a em fun\u00e7\u00e3o do tempo t, com a posi\u00e7\u00e3o de equil\u00edbrio em x = 0.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/mhs-2\/i_4ff9abaa23e9bc9d_html_ba46c3a0.jpg\" alt=\"\" width=\"431\" height=\"185\" name=\"Imagem 20\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Com base no gr\u00e1fico, determine:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) O per\u00edodo e a frequ\u00eancia do sistema pe\u00e7a-mola.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Os instantes em que a velocidade da pe\u00e7a \u00e9 nula. Justifique a sua resposta.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Os instantes em que a acelera\u00e7\u00e3o da pe\u00e7a \u00e9 m\u00e1xima. Justifique a sua resposta.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Fun\u00e7\u00e3o hor\u00e1ria da velocidade e da acelera\u00e7\u00e3o do MHS\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/mhs\/funcao-horaria-da-velocidade-e-da-aceleracao-do-mhs\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-funcao-horaria-da-velocidade-e-da-aceleracao-do-mhs\/\"><span style=\"color: #000080;\">Confira as resolu\u00e7\u00f5es comentadas<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre Fun\u00e7\u00e3o hor\u00e1ria da velocidade e da acelera\u00e7\u00e3o do MHS \u00a0 1-(UFB)\u00a0 A fun\u00e7\u00e3o hor\u00e1ria da elonga\u00e7\u00e3o de uma part\u00edcula em MHS \u00e9 x = 4.cos(p\u00a0+\u00a0pt) SI. a) a fun\u00e7\u00e3o hor\u00e1ria da velocidade b) a velocidade m\u00e1xima e a velocidade m\u00ednima c) o gr\u00e1fico da velocidade em fun\u00e7\u00e3o do tempo d) a fun\u00e7\u00e3o hor\u00e1ria<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1248,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1250","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1250","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1250"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1250\/revisions"}],"predecessor-version":[{"id":10837,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1250\/revisions\/10837"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1248"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1250"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}