{"id":1227,"date":"2015-08-26T00:23:39","date_gmt":"2015-08-26T00:23:39","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1227"},"modified":"2024-08-23T13:08:50","modified_gmt":"2024-08-23T13:08:50","slug":"exercicios-de-vestibulares-com-resolucao-comentada-sobre","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/forca-elastica-lei-de-hooke\/exercicios-de-vestibulares-com-resolucao-comentada-sobre\/","title":{"rendered":"Lei de Hooke e Associa\u00e7\u00e3o de molas"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Lei de Hooke e Associa\u00e7\u00e3o de molas<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>01-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A mola da figura varia seu comprimento de 10cm para 22cm quando penduramos em sua extremidade um corpo de 4N.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_9b1c4198.jpg\" alt=\"\" width=\"317\" height=\"206\" name=\"Imagem 36\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Determine o comprimento total dessa mola quando penduramos nela um corpo de 6N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>02- (UNIRIO)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O dinam\u00f4metro, ou balan\u00e7a de mola, \u00e9 um instrumento para medir for\u00e7a. Se graduado em newtons, ele indica o par de for\u00e7as que \u00e9 exercido sobre ele, distendendo a mola. Com a gradua\u00e7\u00e3o em quilogramas \u00e9 que ele se tornou conhecido no tempo do imp\u00e9rio como &#8220;balan\u00e7a de peixeiro&#8221;, pois o peixe era carregado em cestas sobre burros e comercializado pelas ruas. A figura a seguir mostra um dinam\u00f4metro de peso desprez\u00edvel, em cujas extremidades est\u00e3o aplicadas as for\u00e7as indicadas.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_84d9830e.jpg\" alt=\"\" width=\"613\" height=\"150\" name=\"Imagem 37\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa correta.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) A indica\u00e7\u00e3o do dinam\u00f4metro no primeiro caso \u00e9 zero.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) A leitura do dinam\u00f4metro no segundo caso \u00e9 300 N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) A resultante sobre o dinam\u00f4metro no primeiro caso \u00e9 100 N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) A indica\u00e7\u00e3o do dinam\u00f4metro no primeiro caso \u00e9 100 N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) A leitura do dinam\u00f4metro no segundo caso \u00e9 50 N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>03-(UFSM)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Durante os exerc\u00edcios de for\u00e7a realizados por um corredor, \u00e9 usada uma tira de borracha presa ao seu abdome. Nos arranques, o atleta obt\u00e9m os seguintes resultados:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_16c3d072.jpg\" alt=\"\" width=\"442\" height=\"97\" name=\"Imagem 38\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O m\u00e1ximo de for\u00e7a atingido pelo atleta, sabendo-se que a constante el\u00e1stica da tira \u00e9 de 300 N\/m e que obedece \u00e0 lei de Hooke, \u00e9, em N,<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_49239686.png\" alt=\"\" width=\"774\" height=\"18\" name=\"Imagem 3038\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>04-(Ufrrj-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um bloco de massa 5 kg est\u00e1 parado sobre um plano inclinado de um \u00e2ngulo de 30\u00b0 com a horizontal, preso a uma mola, de constante el\u00e1stica k = 100 N\/m, como mostra a figura. O atrito entre o bloco e o plano pode ser desprezado.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_b0b145f6.jpg\" alt=\"\" width=\"266\" height=\"143\" name=\"Imagem 39\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Represente as for\u00e7as que atuam na caixa e escreva quem exerce cada uma das for\u00e7as.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Calcule a deforma\u00e7\u00e3o da mola nessa situa\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>05-(UFB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A mola da figura est\u00e1:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_79087bbc.jpg\" alt=\"\" width=\"244\" height=\"237\" name=\"Imagem 40\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>&#8211; em (1) no seu tamanho natural<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>&#8211; em (2) tracionada por uma for\u00e7a de 10N<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>&#8211; em (3) tracionada por uma for\u00e7a de 25N<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Verifique, justificando, se ela obedece \u00e0 lei de Hooke<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>06-(UFB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Entre dois blocos 1 e 2 de massas m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=12kg e m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=8kg existe uma mola ideal A. Os dois blocos est\u00e3o apoiados sobre<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_fa5783c9.jpg\" alt=\"\" width=\"605\" height=\"90\" name=\"Imagem 41\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>um plano horizontal sem atrito. O bloco 1 \u00e9 puxado por uma for\u00e7a<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_1a369bf7.jpg\" alt=\"\" width=\"13\" height=\"16\" name=\"Imagem 42\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, constante, horizontal e paralela ao plano por meio de outra mola ideal B, id\u00eantica \u00e0 mola A. Calcule a rela\u00e7\u00e3o x<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/x<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>entre as deforma\u00e7\u00f5es das molas A e B, depois que o sistema entrou em movimento com acelera\u00e7\u00e3o constante<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_de289265.jpg\" alt=\"\" width=\"14\" height=\"20\" name=\"Imagem 43\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>07-(UFRJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma mola de constante el\u00e1stica k e comprimento natural L est\u00e1 presa, por uma de suas extremidades, ao teto de um elevador e, pela outra extremidade, a um balde vazio de massa M que pende na vertical. Suponha que a mola seja ideal, isto \u00e9, que tenha massa desprez\u00edvel e satisfa\u00e7a \u00e0 lei de Hooke.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_1bacd66c.jpg\" alt=\"\" width=\"370\" height=\"198\" name=\"Imagem 44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Calcule a elonga\u00e7\u00e3o x<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>da mola supondo que tanto o elevador quanto o balde estejam em repouso, situa\u00e7\u00e3o ilustrada na figura 1, em fun\u00e7\u00e3o de M, k e do m\u00f3dulo g da acelera\u00e7\u00e3o da gravidade.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Considere, agora, uma situa\u00e7\u00e3o na qual o elevador se mova com acelera\u00e7\u00e3o constante para cima e o balde esteja em repouso relativamente ao elevador. Verifica-se que a elonga\u00e7\u00e3o da mola \u00e9 maior do que a anterior por um valor d, como ilustra a figura 2. Calcule o m\u00f3dulo da acelera\u00e7\u00e3o do balde em termos de k, M e d.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>08-(UFG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>No sistema representado na figura abaixo, as duas molas s\u00e3o iguais, t\u00eam 1 m de comprimento e est\u00e3o relaxadas. Quando o fio \u00e9 cortado, a esfera de massa 5,1 kg desce 1 m at\u00e9 parar momentaneamente.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_d1cfa428.jpg\" alt=\"\" width=\"275\" height=\"173\" name=\"Imagem 45\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dados:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u221a<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2 = 1,41<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Calcule o valor da constante el\u00e1stica k das molas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>09-(UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Sensores de dimens\u00f5es muito pequenas t\u00eam sido acoplados a circuitos microeletr\u00f4nicos. Um exemplo \u00e9 um medidor de acelera\u00e7\u00e3o que consiste de uma massa m presa a uma micromola de constante el\u00e1stica k. Quando o conjunto \u00e9 submetido a uma acelera\u00e7\u00e3o<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, a micromola se deforma, aplicando uma for\u00e7a F na massa (ver diagrama a seguir). O gr\u00e1fico a seguir do diagrama mostra o m\u00f3dulo da for\u00e7a aplicada versus a deforma\u00e7\u00e3o de uma micromola utilizada num medidor de acelera\u00e7\u00e3o.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_d33aaa34.jpg\" alt=\"\" width=\"469\" height=\"171\" name=\"Imagem 46\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual \u00e9 a constante el\u00e1stica k da micromola?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) O medidor de acelera\u00e7\u00e3o foi dimensionado de forma que essa micromola sofra uma deforma\u00e7\u00e3o de 0,50<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>mm quando a massa tem uma acelera\u00e7\u00e3o de m\u00f3dulo igual a 25 vezes o da acelera\u00e7\u00e3o da gravidade. Qual \u00e9 o valor da massa m ligada \u00e0 micromola?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #231f20;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>10-(UNICAMP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Nas cenas dos filmes e nas ilustra\u00e7\u00f5es gr\u00e1ficas do Homem-aranha, a espessura do cabo de teia de aranha que seria necess\u00e1rio para sustent\u00e1- lo \u00e9 normalmente exagerada.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_5bdd957f.jpg\" alt=\"\" width=\"129\" height=\"246\" name=\"Imagem 47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>De fato, os fios de seda da teia de aranha s\u00e3o materiais extremamente resistentes e el\u00e1sticos. Para deforma\u00e7\u00f5es \u0394L relativamente pequenas, um cabo feito de teia de aranha pode ser aproximado por uma mola de constante el\u00e1stica<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>k<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>dada pela f\u00f3rmula (K=10<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>10<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A\/L),\u00a0 onde<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>L<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00e9 o comprimento inicial e<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>A<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a \u00e1rea da se\u00e7\u00e3o<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>transversal do cabo. Para os c\u00e1lculos abaixo, considere a massa do Homem-aranha<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>M<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 70 kg.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Calcule a \u00e1rea<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>A<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><i><b>\u00a0<\/b><\/i><\/span><\/span><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>da se\u00e7\u00e3o transversal do cabo de teia de aranha que suportaria o peso do Homem-aranha com uma deforma\u00e7\u00e3o de 1,0 % do comprimento inicial do cabo. (g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #231f20;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #231f20;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>11-(UFRJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O sistema representado na figura (carrinhos de mesma massa ligados a molas id\u00eanticas) est\u00e1 inicialmente em repouso, podendo mover-se com atrito desprez\u00edvel sobre trilhos horizontais:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_22a550fe.jpg\" alt=\"\" width=\"311\" height=\"105\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Aplica-se \u00e0 extremidade livre da mola 3, uma for\u00e7a constante, paralela aos trilhos e orientada para a direita. Depois de as oscila\u00e7\u00f5es iniciais terem sido amortecidas, o conjunto desloca-se em bloco para a direita. Nessa situa\u00e7\u00e3o, sendo l<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, l<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e l<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>os comprimentos respectivos das molas 1, 2 e 3, assinale a alternativa correta:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_bb5cabcb.jpg\" alt=\"\" width=\"686\" height=\"36\" name=\"Imagem 49\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: medium;\"><b>Associa\u00e7\u00e3o de molas<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>12-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma mola helicoidal de massa desprez\u00edvel est\u00e1 presa pela extremidade A, a uma parede r\u00edgida e, na extremidade B, encontra-se preso um corpo de massa m, conforme mostra a figura 1. Quando o conjunto oscila livremente na dire\u00e7\u00e3o da reta horizontal AB, perpendicular \u00e0 parede, constitui-se um oscilador harm\u00f4nico de per\u00edodo T. Se dispusermos de duas molas id\u00eanticas \u00e0 anterior e as fixarmos conforme a figura 2, ao constituirmos um oscilador harm\u00f4nico, com a oscila\u00e7\u00e3o do mesmo corpo de massa m, segundo a mesma dire\u00e7\u00e3o AB, seu respectivo per\u00edodo ser\u00e1:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_5a97986e.jpg\" alt=\"\" width=\"237\" height=\"124\" name=\"Imagem 50\" align=\"BOTTOM\" border=\"0\" \/><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_58baa81b.jpg\" alt=\"\" width=\"220\" height=\"130\" name=\"Imagem 51\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Figura 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 figura 2<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_9b966ec4.png\" alt=\"\" width=\"774\" height=\"19\" name=\"Imagem 3039\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>13-(UFB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma massa M=(20\/9)kg, encontra-se suspensa ao conjunto de molas ilustrado na figura abaixo,<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Suas constantes el\u00e1sticas s\u00e3o k<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= k<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=30N\/m.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_5051fec.jpg\" alt=\"\" width=\"171\" height=\"202\" name=\"Imagem 52\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Calcule a constante el\u00e1stica total equivalente do conjunto.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>14-(ITA-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um sistema massa-molas \u00e9 constitu\u00eddo por molas de constantes k<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e k<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, respectivamente, barras de massas desprez\u00edveis e um corpo de massa m, como mostrado na figura.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_beda7bc2.jpg\" alt=\"\" width=\"358\" height=\"213\" name=\"Imagem 53\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Determine a freq\u00fc\u00eancia desse sistema.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>15-(UFB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A mola helicoidal (figura 1), de constante el\u00e1stica k=12N\/m, foi partida em 3 partes iguais. Em seguida, essas 3 partes foram associadas em paralelo (figura 2) e em s\u00e9rie (figura 3).\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_acf5a84.png\" alt=\"\" width=\"449\" height=\"231\" name=\"Imagem 3041\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>As massas das figuras 2 e 3 s\u00e3o iguais e valem 100g. Adote g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e determine:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a constante el\u00e1stica de cada parte.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) o per\u00edodo de oscila\u00e7\u00e3o do conjunto quando as tr\u00eas molas est\u00e3o associadas em paralelo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) o per\u00edodo de oscila\u00e7\u00e3o do conjunto quando as tr\u00eas molas est\u00e3o associadas em s\u00e9rie.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>16-(PUC-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Na figura abaixo, as tr\u00eas molas ideais 1, 2 e 3 s\u00e3o id\u00eanticas\u00a0 e possuem a mesma constante el\u00e1stica de valor 0,1N\/cm e as massas tamb\u00e9m s\u00e3o id\u00eanticas e de mesmo valor (10g).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Inicialmente, o conjunto est\u00e1 em equil\u00edbrio e as molas est\u00e3o em seu comprimento natural (20cm cada uma). Em seguida, retira-se o suporte S e cada mola se distende at\u00e9 que o conjunto adquira novamente o equil\u00edbrio.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_5610b790.jpg\" alt=\"\" width=\"85\" height=\"185\" name=\"Imagem 57\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Ap\u00f3s o novo equil\u00edbrio, determine: (g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) deforma\u00e7\u00e3o de cada mola.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) o comprimento de cada mola<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) a deforma\u00e7\u00e3o total do conjunto<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>17- (UFMS)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere um sistema constitu\u00eddo de duas molas de constantes el\u00e1sticas K<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e K<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. \u00c9 correto afirmar que<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(01) a constante el\u00e1stica do sistema \u00e9 maior quando as molas s\u00e3o associadas em s\u00e9rie.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(02) a constante el\u00e1stica do sistema \u00e9 menor quando as molas s\u00e3o associadas em paralelo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(04) a elonga\u00e7\u00e3o das molas \u00e9 a mesma quando elas s\u00e3o associadas em paralelo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(08) a constante el\u00e1stica do sistema \u00e9 K<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>+ K<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>quando elas s\u00e3o associadas em paralelo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(16) a for\u00e7a de elonga\u00e7\u00e3o das molas \u00e9 a mesma quando elas s\u00e3o associadas em paralelo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>18-(UFMS-MS)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 A figura a seguir mostra duas massas iguais a m, presas nas extremidades de uma mola de constante el\u00e1stica K e que obedece \u00e0 lei de Hooke. Um fio mant\u00e9m esse sistema suspenso em um teto. Todo o sistema est\u00e1 em equil\u00edbrio, at\u00e9 que uma tesoura corta o fio que mant\u00e9m o sistema suspenso. Considere a massa da mola desprez\u00edvel, a acelera\u00e7\u00e3o da gravidade uniforme e igual a g no local e assinale a(s) proposi\u00e7\u00e3o(\u00f5es) CORRETA(S).<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_4a0ed5b3.jpg\" alt=\"\" width=\"231\" height=\"175\" name=\"Imagem 58\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>01) Imediatamente ap\u00f3s cortar o fio, a for\u00e7a resultante na massa superior ser\u00e1 de 2 mg.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>02) Imediatamente ap\u00f3s cortar o fio, as duas massas cair\u00e3o com acelera\u00e7\u00e3o da gravidade.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>04) Enquanto o sistema estiver em equil\u00edbrio e suspenso pelo fio ao teto, a for\u00e7a aplicada pela mola ser\u00e1 igual a 2 mg.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>08) Imediatamente ap\u00f3s cortar o fio, a acelera\u00e7\u00e3o resultante na massa superior ser\u00e1 maior que a acelera\u00e7\u00e3o resultante da massa inferior.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>16) Depois de cortar o fio e enquanto o sistema cai, o centro de massa do sistema oscilar\u00e1 enquanto cai em queda livre.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>19-(PUC-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> O corpo A da figura, de peso 10N e volume 400cm<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, \u00e9 erguido 10cm, com velocidade<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_bb5ba6f6.jpg\" alt=\"\" width=\"191\" height=\"238\" name=\"Imagem 59\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>constante, por meio de um fio ideal no qual \u00e9 aplicada uma for\u00e7a de tra\u00e7\u00e3o.Considerando que o corpo permanece o tempo todo completamente imerso na \u00e1gua (d=10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>kg\/m<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>), o trabalho, em joules, realizado pela for\u00e7a de tra\u00e7\u00e3o indicada no dinam\u00f4metro D \u00e9 de (considere g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_7a5a8f63.png\" alt=\"\" width=\"774\" height=\"16\" name=\"Imagem 3042\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>20-(PUC-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 A viol\u00eancia urbana, tanto contra a pessoa quanto aquela realizada contra o patrim\u00f4nio, tem feito com que a popula\u00e7\u00e3o procure as mais variadas formas de prote\u00e7\u00e3o. Carros blindados, contrata\u00e7\u00e3o de empresas privadas de seguran\u00e7a e eletrifica\u00e7\u00e3o de muros e cercas est\u00e3o entre as mais comuns.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O Arame Espetante \u00e9 um produto que oferece uma boa prote\u00e7\u00e3o para o seu patrim\u00f4nio, contra vandalismo e roubo. Ele pode ser utilizado em empresas, resid\u00eancias, edif\u00edcios e condom\u00ednios.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_39184d24.jpg\" alt=\"\" width=\"482\" height=\"158\" name=\"Imagem 60\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O que \u00e9 o Arame Espetante? \u00c9 um arame de a\u00e7o, com dois tratamentos contra ferrugem, encapado por uma l\u00e2mina de a\u00e7o, com pontas perfurantes e inflex\u00edveis. Ele pode ser facilmente instalado sobre: muro de alvenaria, alambrado, grade, marquise ou direto no solo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Em formato de h\u00e9lice cil\u00edndrica (ou helicoidal), travado em dois cabos de a\u00e7o, forma uma barreira contra invas\u00e3o por v\u00e2ndalos e ladr\u00f5es.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A id\u00e9ia de um construtor \u00e9 instalar, nos 20 m de comprimento de um muro frontal de uma resid\u00eancia, arame espetante de bitola (di\u00e2metro do fio) 8 mm. Para isso, ele utilizar\u00e1 arame com formato helicoidal, cuja sec\u00e7\u00e3o transversal apresenta di\u00e2metro de 40 cm, e com an\u00e9is separados por 10 cm de dist\u00e2ncia.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Instru\u00e7\u00f5es:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Nas respostas, lembre-se de deixar os processos de resolu\u00e7\u00e3o claramente expostos. N\u00e3o basta escrever apenas o resultado final. \u00c9 necess\u00e1rio registrar os c\u00e1lculos e\/ou o racioc\u00ednio utilizado.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Admitindo que esse produto seja vendido em caixas c\u00fabicas de 40 cm de arestas, desprezando as eventuais folgas entre os an\u00e9is e supondo que eles fiquem justos na caixa, calcule o n\u00famero m\u00ednimo de caixas que dever\u00e3o ser compradas para montar uma cerca nesse muro. Considere em sua resolu\u00e7\u00e3o que as extremidades do arame est\u00e3o fixadas no topo do muro, em seu in\u00edcio e final, n\u00e3o ocorrendo sobreposi\u00e7\u00e3o nas emendas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Antes de sua fixa\u00e7\u00e3o no topo do muro, que for\u00e7a deve ser feita sobre o arame espetante de cada caixa para estic\u00e1-lo, separando os an\u00e9is conforme o planejado? Considere que ele se comporta como uma mola helicoidal, de constante el\u00e1stica 5 N\/m, que obedece \u00e0 lei de Hooke.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>21-(UFG-GO)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A saltadora brasileira Fabiana Murer terminou as olimp\u00edadas de Pequim em d\u00e9cimo lugar, ap\u00f3s descobrir, no meio da competi\u00e7\u00e3o, que o Comit\u00ea Organizador dos Jogos havia perdido uma de suas varas, a de flexibilidade 21.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_d0552e38.jpg\" alt=\"\" width=\"546\" height=\"336\" name=\"Imagem 61\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considerando que este tipo de vara se comporta com uma mola ideal, qual \u00e9 a constante em N\/m da mola ideal equivalente a uma vara de flexibilidade 21?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dado: g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 9,25.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-6<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 9,25.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>-4<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 1,081.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 1,081.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 1,081.10<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>22-(UFU-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> O tiro com arco \u00e9 um esporte ol\u00edmpico desde a realiza\u00e7\u00e3o da segunda olimp\u00edada em Paris, no ano de 1900. O arco \u00e9 um dispositivo que converte energia potencial el\u00e1stica, armazenada quando a corda do arco \u00e9 tensionada, em energia cin\u00e9tica, que \u00e9 transferida para a flecha.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_1bc3da45.jpg\" alt=\"\" width=\"397\" height=\"172\" name=\"Imagem 62\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Num experimento, medimos a for\u00e7a F necess\u00e1ria para tensionar o arco at\u00e9 uma certa dist\u00e2ncia x, obtendo os seguintes valores:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_4197d5b9.jpg\" alt=\"\" width=\"224\" height=\"53\" name=\"Imagem 63\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O valor e unidades da constante el\u00e1stica, k, do arco s\u00e3o:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_588c879c.png\" alt=\"\" width=\"774\" height=\"17\" name=\"Imagem 3043\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>23-(ITA-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Sobre uma mesa sem atrito, uma bola de massa M \u00e9 presa por duas molas alinhadas, de constante de mola k e comprimento natural \u2113<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, fixadas nas extremidades da mesa. Ent\u00e3o, a bola \u00e9 deslocada a uma dist\u00e2ncia x na dire\u00e7\u00e3o perpendicular \u00e0 linha inicial das molas, como mostra a figura, sendo solta a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_8264c382.jpg\" alt=\"\" width=\"289\" height=\"148\" name=\"Imagem 64\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Obtenha a acelera\u00e7\u00e3o da bola, usando a aproxima\u00e7\u00e3o (1 + a)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u03b1<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>_= 1 + a.\u03b1<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a = &#8211; kx\/M\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) a = &#8211; kx<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/2M \u2113<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) a = &#8211; kx<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/M \u2113<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) a = &#8211; kx<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/2M \u2113<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) a = &#8211; kx<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/M \u2113<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>24-(UPE-PE)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_5a21afbc.jpg\" alt=\"\" width=\"416\" height=\"130\" name=\"Imagem 65\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um corpo de massa m est\u00e1 suspenso por duas molas ideais, paralelas, com constantes el\u00e1sticas k e deformadas de d.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_703920fd.jpg\" alt=\"\" width=\"378\" height=\"172\" name=\"Imagem 66\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Sabendo que o sistema se encontra em equil\u00edbrio, assinale a alternativa que expressa k.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dado: Considere a acelera\u00e7\u00e3o da gravidade g.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A) 2mg\/d\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>B) mg\/d\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>C) mg\/2d\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>D) 2d\/mg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>E) mg<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>25-(UFES-ES)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_b21cb0bb.jpg\" alt=\"\" width=\"552\" height=\"124\" name=\"Imagem 67\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um bloco de massa 0,10 kg \u00e9 abandonado, a partir do repouso, de uma altura h de 1,2 m em rela\u00e7\u00e3o a uma mola ideal de constante el\u00e1stica 0,10 N\/cm. Como \u00e9 mostrado na figura rotulada como \u201cDepois\u201d,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_6c0886e.jpg\" alt=\"\" width=\"403\" height=\"221\" name=\"Imagem 68\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>ao lado, o bloco adere \u00e0 mola ap\u00f3s o choque. No desenho, A \u00e9 o ponto de abandono do bloco, B \u00e9 o ponto de equil\u00edbrio da mola, e C \u00e9 o ponto onde h\u00e1 maior compress\u00e3o da mola. Despreze perdas de energia por atrito.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A) Identifique, em um diagrama, as for\u00e7as que atuam no corpo, quando a deforma\u00e7\u00e3o da mola \u00e9 m\u00e1xima.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B) Determine a velocidade do bloco imediatamente antes de se chocar com a mola.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>C) Determine o trabalho realizado sobre o bloco pela for\u00e7a gravitacional entre os pontos A e B.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>D) Determine a deforma\u00e7\u00e3o m\u00e1xima sofrida pela mola.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>26-(UPE-PE)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_10b8025.jpg\" alt=\"\" width=\"488\" height=\"149\" name=\"Imagem 69\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_5720e465.jpg\" alt=\"\" width=\"773\" height=\"237\" name=\"Imagem 70\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>27-(UFG-GO)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_7384e4af.jpg\" alt=\"\" width=\"490\" height=\"119\" name=\"Imagem 71\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Para prote\u00e7\u00e3o e conforto, os t\u00eanis modernos s\u00e3o equipados com amortecedores constitu\u00eddos de molas. Um determinado modelo,<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_cb6a3b6b.jpg\" alt=\"\" width=\"133\" height=\"220\" name=\"Imagem 72\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>molas. Um determinado modelo, que possui tr\u00eas molas id\u00eanticas, sofre uma deforma\u00e7\u00e3o de 4 mm ao ser cal\u00e7ado por uma pessoa de 84 kg. Considerando-se que essa pessoa permane\u00e7a parada, a constante el\u00e1stica de uma das molas ser\u00e1, em kN\/m, de<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_b0a30789.jpg\" alt=\"\" width=\"82\" height=\"52\" name=\"Imagem 73\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/hooke\/i_f0932ed15524a52f_html_60398b28.png\" alt=\"\" width=\"774\" height=\"24\" name=\"Imagem 3044\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Lei de Hooke e Associa\u00e7\u00e3o de molas\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/forca-elastica-lei-de-hooke\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-lei-de-hooke-e-associacao-de-molas\/\"><span style=\"color: #000080;\">Confira as resolu\u00e7\u00f5es comentadas<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre Lei de Hooke e Associa\u00e7\u00e3o de molas 01-(MACKENZIE-SP)\u00a0A mola da figura varia seu comprimento de 10cm para 22cm quando penduramos em sua extremidade um corpo de 4N. Determine o comprimento total dessa mola quando penduramos nela um corpo de 6N. \u00a0 02- (UNIRIO)\u00a0O dinam\u00f4metro, ou balan\u00e7a de mola, \u00e9 um instrumento para medir<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1225,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1227","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1227","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1227"}],"version-history":[{"count":6,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1227\/revisions"}],"predecessor-version":[{"id":10828,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1227\/revisions\/10828"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1225"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1227"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}