{"id":12189,"date":"2024-12-04T13:59:02","date_gmt":"2024-12-04T13:59:02","guid":{"rendered":"https:\/\/fisicaevestibular.com.br\/novo\/?page_id=12189"},"modified":"2024-12-04T13:59:02","modified_gmt":"2024-12-04T13:59:02","slug":"vectors-vector-kinematics-resolution-2","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/enem\/vetores-cinematica-vetorial\/vectors-vector-kinematics-resolution-2\/","title":{"rendered":"VECTORS \u2013 VECTOR KINEMATICS \u2013 RESOLUTION"},"content":{"rendered":"<p align=\"CENTER\">Commented Resolution<\/p>\n<p align=\"CENTER\">Vectors \u2013 Vector Kinematics<\/p>\n<p>01-\u00a0The graphic scale states that each centimeter of the map is equivalent to 250 kilometers of terrain,<\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"https:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/enem\/5\/ENEM5_html_d09a5e5.jpg\" alt=\"\" width=\"212\" height=\"234\" name=\"Imagem 26\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>which makes it easier to represent the path taken by the traveler in vector form and even to represent his vector displacement (in blue). In this way, he walked 1000 km to the South (an easy direction to identify, since the North is indicated on the map), leaving Cear\u00e1 and passing through Pernambuco and Bahia. In this state, he changed course and traveled 1,000 km to the West, arriving in Goi\u00e1s, from where he headed another 750 km to the South, arriving in the state of S\u00e3o Paulo. On this route, the traveler saw the ecosystems of the Caatinga, the Cerrado and the Atlantic Forest.<\/p>\n<p>R- And<\/p>\n<p>02- Observe the sequence below:<\/p>\n<p><img fetchpriority=\"high\" decoding=\"async\" src=\"https:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/enem\/5\/ENEM5_html_2f8cda88.png\" alt=\"\" width=\"783\" height=\"114\" name=\"Imagem 34\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>R-D<\/p>\n<p>03-\u00a0Adding all vectors using the polygonal line method<\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"https:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/enem\/5\/ENEM5_html_1e2fb0ef.jpg\" alt=\"\" width=\"395\" height=\"177\" name=\"Imagem 28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>S=4.0,50=2.0cm \u2014\u00a0\u00a0\u00a0R- E<\/p>\n<p>04-<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/enem\/5\/ENEM5_html_9273bb0e.jpg\" alt=\"\" width=\"783\" height=\"204\" name=\"Imagem 29\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>or even, adding the vectors using the polygonal line method \u2014 note that they are in the sequence 0,1,2, 3 and 4.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/enem\/5\/ENEM5_html_c539ab64.jpg\" alt=\"\" width=\"600\" height=\"155\" name=\"Imagem 30\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>R-D<\/p>\n<p>05- Since the distance between the two buoys does not vary, they are stationary in relation to each other. So, the boy must swim directly from one to the other \u2014\u00a0\u00a0\u00a0A- A<\/p>\n<p>06-\u00a0As the ocean liner moves in a straight line at constant speed, it is in dynamic equilibrium and behaves as if it were at rest (static equilibrium), not affecting the movement of the ball\u00a0\u00a0\u2014 R- D<\/p>\n<p>07-\u00a0Data: v\u00a0<sub>car<\/sub>\u00a0\u00a0= 80 km\/h; sen\u03b8 = 0.8 and cos\u03b8 = 0.6 \u2014 the figure below shows the car and the<\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/enem\/5\/ENEM5_html_dd38dc2e.jpg\" alt=\"\" width=\"623\" height=\"175\" name=\"Imagem 31\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>speeds of the car (\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/enem\/5\/ENEM5_html_75d4ea7c.jpg\" alt=\"\" width=\"39\" height=\"23\" name=\"Imagem 32\" align=\"BOTTOM\" border=\"0\" \/>) and the rain (\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/enem\/5\/ENEM5_html_c7dec55a.gif\" alt=\"\" width=\"19\" height=\"23\" name=\"Imagem 33\" align=\"BOTTOM\" border=\"0\" \/>), for the person standing on the side of the road. The vector diagram shows the composition of these speeds for the student \u2014 tan\u03b8 =V\u00a0<sub>car<\/sub>\u00a0\/V \u2014 sen\u03b8\/cos\u03b8=V\u00a0<sub>car<\/sub>\u00a0\/V \u2014 0.8\/0.6=80\/V\u00a0<sub>car<\/sub>\u00a0\u00a0 \u2014 V\u00a0<sub>car<\/sub>\u00a0=60km\/h \u2014\u00a0\u00a0\u00a0R- B<\/p>\n<p>&nbsp;<\/p>\n<p>08-\u00a0The crossing time depends only on the width of the river (L) and the speed of the boat in relation to the banks (u) \u2014 u=L\/t \u2014 t=L\/u \u2014 the higher the speed of the water, the greater the displacement of the boat to the right \u2014\u00a0\u00a0\u00a0R- B<\/p>\n<p>09-\u00a0When the car is moving to the right, the raindrops that would fall vertically if the car was stopped, are tilted to the left \u2014\u00a0\u00a0\u00a0R- B<\/p>\n<h3><a title=\"Vectors \u2013 Vector Kinematics\" href=\"https:\/\/fisicaevestibular.com.br\/novo\/enem\/vetores-cinematica-vetorial\/\">Back to exercises<\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Commented Resolution Vectors \u2013 Vector Kinematics 01-\u00a0The graphic scale states that each centimeter of the map is equivalent to 250 kilometers of terrain, which makes it easier to represent the path taken by the traveler in vector form and even to represent his vector displacement (in blue). In this way, he walked 1000 km to the South (an easy direction<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":3611,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-12189","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/12189","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=12189"}],"version-history":[{"count":1,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/12189\/revisions"}],"predecessor-version":[{"id":12208,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/12189\/revisions\/12208"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/3611"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=12189"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}