{"id":1213,"date":"2015-08-26T00:07:44","date_gmt":"2015-08-26T00:07:44","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1213"},"modified":"2024-06-24T15:05:36","modified_gmt":"2024-06-24T15:05:36","slug":"plano-inclinado-sem-atrito","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/plano-inclinado-sem-atrito\/","title":{"rendered":"Plano Inclinado sem Atrito"},"content":{"rendered":"

Plano inclinado sem atrito<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

C\u00e1lculo <\/b><\/span><\/span><\/span>da intensidade de P<\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/sub><\/span> e P<\/b><\/span><\/span><\/span>N<\/b><\/span><\/span><\/sub><\/span> <\/b>utilizando o <\/b><\/span><\/span><\/span>tri\u00e2ngulo ret\u00e2ngulo <\/b><\/span><\/span><\/span>da figura abaixo:<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

\u00a0<\/span><\/p>\n

\"\"<\/p>\n

Como n\u00e3o existe atrito,<\/b><\/span><\/span><\/span> o <\/b><\/span><\/span><\/span>bloco desce<\/b><\/span><\/span><\/span> com <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o de intensidade <\/b><\/span><\/span><\/span>a<\/b><\/span><\/span><\/span>, <\/b><\/span><\/span><\/span>tal que <\/b><\/span><\/span><\/span>F<\/b><\/span><\/span><\/span>R <\/b><\/span><\/span><\/sub><\/span>= m.a<\/b><\/span><\/span><\/span>\u00a0 \"\" \u00a0\u00a0P<\/b><\/span><\/span><\/span>P <\/b><\/span><\/span><\/sub><\/span>= m.a\u00a0\"\" \u00a0 <\/b><\/span><\/span><\/span>m,g.sen\u03b1 = m.a<\/b><\/span><\/span><\/span>\u00a0 \"\"\u00a0\u00a0<\/b><\/span><\/span><\/span>a = g.sen\u03b1<\/b><\/span><\/span><\/span> <\/b>(acelera\u00e7\u00e3o de descida do bloco de massa m).<\/b><\/span><\/span><\/span><\/p>\n

Se o <\/b><\/span><\/span><\/span>bloco estiver em equil\u00edbrio (est\u00e1tico ou din\u00e2mico)<\/b><\/span><\/span><\/span>, a <\/b><\/span><\/span><\/span>for\u00e7a resultante sobre ele seria nula<\/b><\/span><\/span><\/span> e, nesse caso <\/b><\/span><\/span><\/span>haveria ou uma for\u00e7a de atrito (F<\/b><\/span><\/span><\/span>at<\/b><\/span><\/span><\/sub><\/span>) ou uma for\u00e7a externa (F) anulando P<\/b><\/span><\/span><\/span>P<\/b><\/span><\/span><\/sub><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

O que voc\u00ea deve saber, informa\u00e7\u00f5es e dicas<\/b><\/span><\/span><\/span><\/p>\n

\"\" Num <\/b><\/span><\/span><\/span>plano inclinado<\/b><\/span><\/span><\/span>, se <\/b><\/span><\/span><\/span>n\u00e3o houver atrito<\/b><\/span><\/span><\/span> e nem <\/b><\/span><\/span><\/span>for\u00e7a externa<\/b><\/span><\/span><\/span>, o bloco desce com <\/b><\/span><\/span><\/span>acelera\u00e7\u00e3o<\/b><\/span><\/span><\/span> de<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

intensidade<\/b><\/span><\/span><\/span> <\/b>a<\/b><\/span><\/span><\/span>,<\/b><\/span><\/span><\/span> tal que F<\/b><\/span><\/span><\/span>R<\/b><\/span><\/span><\/sub><\/span>=m.a\u00a0\"\"\u00a0\u00a0 P<\/b><\/span><\/span><\/span>P <\/b><\/span><\/span><\/sub><\/span>= m.a\u00a0 \"\" \u00a0m.g.sen\u03b1 = m.a\u00a0 \"\"\u00a0\u00a0 <\/b><\/span><\/span><\/span>a = g.sen\u03b1.<\/b><\/span><\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

\u00a0<\/span><\/p>\n

\"Plano<\/p>\n

\u00a0<\/span><\/p>\n

Confira os exerc\u00edcios com resolu\u00e7\u00f5es comentadas<\/span><\/a><\/h3>\n

 <\/p>\n

Clique aqui para ver sobre o tema!<\/a><\/p>\n

Confira as v\u00eddeo aulas!<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Plano inclinado sem atrito C\u00e1lculo da intensidade de PP e PN utilizando o tri\u00e2ngulo ret\u00e2ngulo da figura abaixo: \u00a0 Como n\u00e3o existe atrito, o bloco desce com acelera\u00e7\u00e3o de intensidade a, tal que FR = m.a\u00a0 \u00a0\u00a0PP = m.a\u00a0 \u00a0 m,g.sen\u03b1 = m.a\u00a0 \u00a0\u00a0a = g.sen\u03b1 (acelera\u00e7\u00e3o de descida do bloco de massa m). Se o bloco estiver em equil\u00edbrio<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":141,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1213","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1213","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1213"}],"version-history":[{"count":4,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1213\/revisions"}],"predecessor-version":[{"id":9705,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1213\/revisions\/9705"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/141"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1213"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}