{"id":1194,"date":"2015-08-25T23:46:33","date_gmt":"2015-08-25T23:46:33","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1194"},"modified":"2024-08-23T13:27:44","modified_gmt":"2024-08-23T13:27:44","slug":"peso-e-massa","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/peso-e-massa-conceitos-e-definicoes\/peso-e-massa\/","title":{"rendered":"Peso e Massa"},"content":{"rendered":"<p><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><span lang=\"pt-PT\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre <\/b><\/span><\/span><\/span><\/span><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><span lang=\"pt-PT\"><b>Peso e Massa<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>1-(UFB)<\/b><\/span><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>\u00a0<\/b><\/span><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>A massa de um corpo na Terra \u00e9 X. No planeta Kripton \u00e9 Y. Qual a rela\u00e7\u00e3o entre X e Y?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>02-(UERJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>\u00a0<\/b><\/span><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>Leia atentamente os quadrinhos a seguir.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_c21f62a2.jpg\" alt=\"\" width=\"582\" height=\"179\" name=\"Imagem 2\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>A solu\u00e7\u00e3o pensada pelo gato Garfield para atender \u00e0 ordem recebida de seu dono est\u00e1 fisicamente correta? Justifique sua resposta.<\/b><\/span><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>03-(PUC-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Suponha que sua massa seja de 55 kg. Quando voc\u00ea sobe em uma balan\u00e7a de farm\u00e1cia para saber seu peso, o ponteiro indicar\u00e1: (considere g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_2c5d7931.png\" alt=\"\" width=\"775\" height=\"16\" name=\"Imagem 44\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>04-(ENEM)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O peso de um corpo \u00e9 uma grandeza f\u00edsica:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) que n\u00e3o varia com o local onde o corpo se encontra\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) cuja unidade \u00e9 medida em quilograma\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) caracterizada pela quantidade de mat\u00e9ria que o corpo encerra\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) que mede a intensidade da for\u00e7a de rea\u00e7\u00e3o de apoio\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) cuja intensidade \u00e9 o produto da massa do corpo pela acelera\u00e7\u00e3o da gravidade local.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>05-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma for\u00e7a de 1newton (1N) tem a ordem de grandeza do peso de:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) um homem adulto<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) uma crian\u00e7a rec\u00e9m-nascida<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) um litro de leite<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) uma xicrinha cheia de caf\u00e9<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) uma moeda<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>06-(Unitins-TO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Assinale a proposi\u00e7\u00e3o correta:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) a massa de um corpo na Terra \u00e9 menor do que na Lua<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) o peso mede a in\u00e9rcia de um corpo<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Peso e massa s\u00e3o sin\u00f4nimos<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) A massa de um corpo na Terra \u00e9 maior do que na Lua<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) O sistema de propuls\u00e3o a jato funciona baseado no princ\u00edpio da a\u00e7\u00e3o e rea\u00e7\u00e3o.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>07-(FMIt-MG)<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um corpo de massa igual a 100kg \u00e9 atra\u00eddo pela Terra, que provoca no mesmo uma acelera\u00e7\u00e3o. Este corpo, por sua vez, tamb\u00e9m exerce uma for\u00e7a sobre a Terra, comunicando-lhe uma acelera\u00e7\u00e3o. Sabendo-se que a massa da Terra tem a ordem de grandeza de 10<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>34<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>kg, calcular o m\u00f3dulo da acelera\u00e7\u00e3o que a Terra adquire, como conseq\u00fc\u00eancia da intera\u00e7\u00e3o com o referido corpo.(considere g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>08-(FCC-BA)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O peso de um corpo, pr\u00f3ximo \u00e0 superf\u00edcie da Terra onde g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00e9 de 40N.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual \u00e9 o seu peso na Lua, sabendo que g<\/b><\/span><\/span><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>L<\/b><\/span><\/span><\/sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>=g\/6?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Qual \u00e9 a sua massa em Marte?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>09-(UNIMEP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um astronauta com o traje completo tem uma massa de 120 kg. Ao ser levado para a<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_b12956dc.jpg\" alt=\"\" width=\"219\" height=\"165\" name=\"graphics13\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Lua, onde a acelera\u00e7\u00e3o Da gravidade \u00e9 igual a 1,6m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, a sua massa e seu peso ser\u00e3o, respectivamente:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 75kg e 120N<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 120kg e 192N<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 192kg e 192N<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 120kg e 120N<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 75kg e 192N<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>10-(FATEC-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um p\u00e1ra-quedista desce com velocidade constante de 4m\/s. Sendo a massa do conjunto de 80kg, e a acelera\u00e7\u00e3o<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_33153bee.jpg\" alt=\"\" width=\"218\" height=\"182\" name=\"Imagem 4\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>da gravidade de 10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, a for\u00e7a de resist\u00eancia do ar \u00e9 de:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_fcb9a6dc.png\" alt=\"\" width=\"774\" height=\"18\" name=\"Imagem 45\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>11-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um corpo de massa igual a 20kg, partindo do repouso, cai em queda livre de uma altura igual a 2m em rela\u00e7\u00e3o ao solo (g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>). Qual \u00e9 o m\u00f3dulo, em newtons, da for\u00e7a de atra\u00e7\u00e3o que a Terra exerce sobre o corpo?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>12-(UFB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma pedra de massa 10kg foi transportada da Terra para uma regi\u00e3o (R) afastada da influ\u00eancia de qualquer corpo celeste, fora da atra\u00e7\u00e3o gravitacional deles. Assim:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual \u00e9 a massa da pedra na regi\u00e3o R?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Qual \u00e9 o peso da pedra na regi\u00e3o R?<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) A in\u00e9rcia da pedra na regi\u00e3o R seria a mesma que ela possu\u00eda na Terra?<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>13-(UNESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Observe a tira abaixo:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_26de7646.jpg\" alt=\"\" width=\"484\" height=\"179\" name=\"Imagem 5\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A forma encontrada por Garfield para perder peso \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) correta, uma\u00a0 vez que, em um planeta de gravidade menor, seu peso ser\u00e1 realmente menor, por\u00e9m com a mesma massa.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) errada, pois em um planeta de gravidade menor sua massa ser\u00e1 maior, por\u00e9m com o mesmo peso.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) correta, pois em um planeta de gravidade menor sua massa ser\u00e1 menor, por\u00e9m seu peso ser\u00e1 maior.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) correta, pois em um planeta de gravidade menor sua massa e seu peso ser\u00e3o maiores.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) correta, pois em um planeta de gravidade menor sua massa e seu peso ser\u00e3o menores.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>14-(UFV-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um astronauta leva uma caixa da Terra at\u00e9 a Lua. Podemos dizer que o esfor\u00e7o que ele far\u00e1 para carregar a caixa na Lua ser\u00e1:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) maior que na Terra, j\u00e1 que a massa da caixa diminuir\u00e1 e seu peso aumentar\u00e1.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) maior que na Terra, j\u00e1 que a massa da caixa permanecer\u00e1 constante e seu peso aumentar\u00e1.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) menor que na Terra, j\u00e1 que a massa da caixa diminuir\u00e1 e seu peso permanecer\u00e1 constante.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) menor que na Terra, j\u00e1 que a massa da caixa aumentar\u00e1 e seu peso diminuir\u00e1.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) menor que na Terra, j\u00e1 que a massa da caixa permanecer\u00e1 constante e seu peso diminuir\u00e1.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>15-(Unifei-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma crian\u00e7a arremessa uma bola, cuja massa \u00e9 20g, verticalmente para cima. Desprezando-se a resist\u00eancia do ar, determine o m\u00f3dulo, a dire\u00e7\u00e3o e o sentido da for\u00e7a resultante que atua sobre a bola nos seguintes casos: (considere g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) na subida, ap\u00f3s ter deixado a m\u00e3o da crian\u00e7a.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) no ponto mais alto da trajet\u00f3ria.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) na descida, antes de tocar o solo.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>16-(PUC-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A massa de um determinado indiv\u00edduo \u00e9 de 60kg. Ele sobe em uma balan\u00e7a e o ponteiro indica seu peso.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_c8ad73a4.jpg\" alt=\"\" width=\"110\" height=\"193\" name=\"graphics14\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Qual \u00e9 a indica\u00e7\u00e3o correta que a balan\u00e7a deve oferecer? (considere 1 quilograma-for\u00e7a \u201c1 kgf\u201d como sendo 10N e g=10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 60kg<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 60kgf<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 60N<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 6N<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 0,6kgf<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>17-(FEI-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um quilograma padr\u00e3o pesa cerca de 10N na Terra. Em um planeta X, o mesmo quilograma padr\u00e3o pesa 35N. Qual \u00e9 a acelera\u00e7\u00e3o da gravidade no planeta X? (1kgf=10N)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 3,5m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 35m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 0,3m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 0,7m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>18-(UF-MT)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A ordem de grandeza de uma for\u00e7a de 1.000N \u00e9 compar\u00e1vel ao peso de:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) um lutador de boxe<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) um tanque de guerra<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) um navio quebra-gelo<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) uma bola de futebol<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) uma bolinha de pingue-pongue<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>19-(Udesc)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A afirmativa seguinte \u00e9 feita por uma pessoa que nunca estudou f\u00edsica: \u201cPara suspender este corpo, tive que exercer nele uma for\u00e7a de 15kg\u201d<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Com base no enunciado, podemos afirmar:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>I. kg \u00e9 unidade de massa.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>II. Nesse caso, o corpo pesa 15N.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>III. Peso \u00e9 uma for\u00e7a e pode ser expresso em kgf ou N.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>IV. Nesse caso, o corpo pesa 150kgf.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>S\u00e3o verdadeiras, somente:<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_4a459b60.png\" alt=\"\" width=\"774\" height=\"21\" name=\"Imagem 46\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>20-(UFMG-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um astronauta, de p\u00e9 sobre a superf\u00edcie da Lua, arremessa uma pedra,<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_e51c1f89.jpg\" alt=\"\" width=\"160\" height=\"176\" name=\"graphics15\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>horizontalmente, a partir de uma altura \u00a0 de 1,25 m, e verifica que ela atinge o solo a uma dist\u00e2ncia de 15 m.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere que a acelera\u00e7\u00e3o da gravidade na sua superf\u00edcie vale 1,6 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Com base nessas informa\u00e7\u00f5es, CALCULE o m\u00f3dulo da velocidade com que o astronauta arremessou a pedra.<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>21-(UERJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Embora sua realiza\u00e7\u00e3o seja imposs\u00edvel, imagine a constru\u00e7\u00e3o de um t\u00fanel entre os dois p\u00f3los geogr\u00e1ficos da Terra, e que uma pessoa, em um dos p\u00f3los, caia pelo t\u00fanel, que tem 12.800 km de extens\u00e3o, como ilustra a figura a seguir.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_d117ea01.jpg\" alt=\"\" width=\"278\" height=\"199\" name=\"graphics16\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Admitindo que a Terra apresente uma constitui\u00e7\u00e3o homog\u00eanea e que a resist\u00eancia do ar seja desprez\u00edvel, a acelera\u00e7\u00e3o da gravidade e a velocidade da queda da pessoa, respectivamente, s\u00e3o nulas nos pontos indicados pelas seguintes letras:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>a) Y \u2013 W\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>b) W \u2013 X\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>c) X \u2013 Z\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>d) Z &#8211;\u00a0Y<\/b><\/span><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>22- (PUC-RS)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Vamos supor que voc\u00ea esteja em um supermercado, aguardando a pesagem de uma quantidade de ma\u00e7\u00e3s em uma<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_ef47437c.jpg\" alt=\"\" width=\"295\" height=\"164\" name=\"graphics17\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>balan\u00e7a de molas cuja unidade de medida \u00e9 o quilograma-for\u00e7a.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A leitura da balan\u00e7a corresponde:\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) ao m\u00f3dulo da for\u00e7a normal, pois essa \u00e9 a for\u00e7a de intera\u00e7\u00e3o entre as ma\u00e7\u00e3s e a balan\u00e7a, cujo valor \u00e9 supostamente igual ao do m\u00f3dulo do peso das ma\u00e7\u00e3s.\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) tanto ao valor do m\u00f3dulo da for\u00e7a peso quanto ao do m\u00f3dulo da for\u00e7a normal, pois ambas constituem um par a\u00e7\u00e3o-rea\u00e7\u00e3o, segundo a terceira lei de Newton.\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) ao m\u00f3dulo do peso das ma\u00e7\u00e3s, pois essa \u00e9 a for\u00e7a de intera\u00e7\u00e3o entre as ma\u00e7\u00e3s e a balan\u00e7a.\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) ao m\u00f3dulo da for\u00e7a resultante sobre as ma\u00e7\u00e3s.\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) \u00e0 quantidade de mat\u00e9ria de ma\u00e7\u00e3s.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>23-(PUC-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> A massa de um ve\u00edculo em repouso \u00e9 900 kg. Esse ve\u00edculo entra em movimento numa<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_69c18016.jpg\" alt=\"\" width=\"553\" height=\"158\" name=\"Imagem 10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>estrada pavimentada e \u00e9\u00a0acelerado at\u00e9 sua velocidade atingir 100 km\/h. Considerando-se g = 10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, \u00e9 CORRETO afirmar:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) \u00c0 medida que a velocidade do ve\u00edculo aumenta, o seu peso diminui e, a 100 km\/h, seu peso \u00e9 m\u00ednimo.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) \u00c0 medida que a velocidade do ve\u00edculo aumenta, aumenta tamb\u00e9m sua ader\u00eancia ao solo fazendo com que seu peso aumente.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Pode-se considerar que, at\u00e9 a velocidade de 100 km\/h, o peso do ve\u00edculo n\u00e3o se altera, por\u00e9m, para velocidades muito maiores que 100 km\/h, o peso do ve\u00edculo vai se reduzindo de maneira muito acentuada.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) O peso do ve\u00edculo \u00e9 o mesmo, estando ele em repouso ou em alta velocidade.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>24-(ENEM-MEC<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)\u00a0 O \u00f4nibus espacial Atlantis foi lan\u00e7ado ao espa\u00e7o com cinco astronautas a bordo e uma c\u00e2mera nova, que iria substituir uma outra danificada por um curto-circuito no telesc\u00f3pio Hubble. Depois de entrarem em \u00f3rbita a 560 km de altura, os astronautas se aproximaram do Hubble. Dois astronautas sa\u00edram da Atlantis e se dirigiram ao telesc\u00f3pio.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Ao abrir a porta de acesso, um deles exclamou: \u201cEsse telesc\u00f3pio tem a massa grande, mas o peso \u00e9 pequeno.\u201d<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_ad73350f.jpg\" alt=\"\" width=\"326\" height=\"165\" name=\"Imagem 11\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considerando o texto e as leis de Kepler, pode-se afirmar que a frase dita pelo astronauta<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) se justifica porque o tamanho do telesc\u00f3pio determina a sua massa, enquanto seu pequeno peso decorre da falta de a\u00e7\u00e3o da acelera\u00e7\u00e3o da gravidade.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) se justifica ao verificar que a in\u00e9rcia do telesc\u00f3pio \u00e9 grande comparada \u00e0 dele pr\u00f3prio, e que o peso do telesc\u00f3pio \u00e9 pequeno porque a atra\u00e7\u00e3o gravitacional criada por sua massa era pequena.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) n\u00e3o se justifica, porque a avalia\u00e7\u00e3o da massa e do peso de objetos em \u00f3rbita tem por base as leis de Kepler, que n\u00e3o se aplicam a sat\u00e9lites artificiais.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) n\u00e3o se justifica, porque a for\u00e7a-peso \u00e9 a for\u00e7a exercida pela gravidade terrestre, neste caso, sobre o telesc\u00f3pio e \u00e9 a respons\u00e1vel por manter o pr\u00f3prio telesc\u00f3pio em \u00f3rbita. \u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) n\u00e3o se justifica, pois a a\u00e7\u00e3o da for\u00e7a-peso implica a a\u00e7\u00e3o de uma for\u00e7a de rea\u00e7\u00e3o contr\u00e1ria, que n\u00e3o existe naquele ambiente. A massa do telesc\u00f3pio poderia ser avaliada simplesmente pelo seu volume.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>25-(PUC-MG)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Um astronauta na Lua quer medir a massa e o peso de uma pedra. Para isso ele realiza as seguintes experi\u00eancias:<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_fd84eb05.jpg\" alt=\"\" width=\"278\" height=\"154\" name=\"Imagem 12\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>I &#8211; Para medir a massa, ele utiliza uma balan\u00e7a de bra\u00e7os iguais, colocando em um dos pratos a pedra e, no outro, massas de valor conhecido, at\u00e9 obter o equil\u00edbrio da balan\u00e7a.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>II &#8211; Para medir o peso, ele utiliza um dinam\u00f4metro na vertical, pendurando a pedra na extremidade e lendo seu peso na escala do aparelho.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>III &#8211; Para medir a massa, ele deixa a pedra cair de uma certa altura e mede o tempo de queda, comparando-o com o tempo de queda de um objeto de massa conhecida, solto da mesma altura; a rela\u00e7\u00e3o entre os tempos \u00e9 igual \u00e0 rela\u00e7\u00e3o entre as massas.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>IV &#8211; Para medir o peso da pedra, o astronauta a prende na ponta de um fio que passa por uma roldana fixa vertical; na outra ponta do fio, ele pendura objetos de peso conhecido, um de cada vez, at\u00e9 que consiga o equil\u00edbrio, isto \u00e9, at\u00e9 que a roldana pare de girar.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>As experi\u00eancias CORRETAS s\u00e3o:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) I e II apenas.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b) III e IV apenas.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0c) I, II e IV apenas.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d) I, II, III e IV.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>26-(UECE-CE)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b> Ao cair de uma altura pr\u00f3xima \u00e0 superf\u00edcie da Terra, uma ma\u00e7\u00e3 de massa igual a 100g<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_2739806d.jpg\" alt=\"\" width=\"146\" height=\"158\" name=\"Imagem 13\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>causa no planeta uma acelera\u00e7\u00e3o aproximadamente igual a<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Zero.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 1 m\/s2.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 10 m\/s2.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 1 N.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>27-(UEG-GO)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Entre os poucos animais que desenvolveram o \u201cp\u00e1ra-quedismo\u201d est\u00e1 o sapo voador de Born\u00e9u \u2013 Rhacophorus dulitensis, apresentado na figura a seguir.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_8b8e7d0a.jpg\" alt=\"\" width=\"476\" height=\"185\" name=\"Imagem 14\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Na ilustra\u00e7\u00e3o,<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_72b5ab07.jpg\" alt=\"\" width=\"21\" height=\"24\" name=\"Imagem 15\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0e<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_f61c3a6e.jpg\" alt=\"\" width=\"27\" height=\"28\" name=\"Imagem 16\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0s\u00e3o, respectivamente, a for\u00e7a de resist\u00eancia do ar e a for\u00e7a peso.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considerando que esse animal tenha se atirado do alto de uma \u00e1rvore em dire\u00e7\u00e3o ao solo, o seu p\u00e1ra-quedas ser\u00e1 utilizado e, durante sua queda,<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) as suas membranas interdigitais nas patas favorecem o aumento da for\u00e7a de resist\u00eancia do ar, haja vista que elas aumentam a \u00e1rea de contato com o ar.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) a resultante das for\u00e7as que atuam sobre ele tender\u00e1 a se tornar nula, levando-o, necessariamente, ao repouso no ar.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) a sua velocidade tender\u00e1 a um valor limite, chamada de velocidade terminal, independentemente da resist\u00eancia do ar.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) a sua acelera\u00e7\u00e3o ser\u00e1 nula em todo o percurso, independentemente da resist\u00eancia do ar.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>28-(FATEC-SP)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Um explorador de cavernas utiliza-se da t\u00e9cnica de \u201crapel\u201d que consiste em descer abismos e canyons apenas<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_6c4e2a4f.jpg\" alt=\"\" width=\"230\" height=\"173\" name=\"Imagem 17\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>em uma corda e com velocidade praticamente constante. A massa total do explorador e de seus equipamentos \u00e9 de 80 kg.Considerando a acelera\u00e7\u00e3o da gravidade no local de 10m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, a for\u00e7a resultante de resist\u00eancia que atua sobre o explorador, durante a descida \u00e9, em N, de<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_ffb8a2db.png\" alt=\"\" width=\"774\" height=\"19\" name=\"Imagem 47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>29-(UNEMAT-MT)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 A figura abaixo representa um elevador em movimento com velocidade constante.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_be32e8d.jpg\" alt=\"\" width=\"359\" height=\"153\" name=\"Imagem 18\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A tra\u00e7\u00e3o (T) do cabo durante o movimento de subida \u00e9:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) maior que o peso do elevador.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) maior que durante o movimento de descida.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) igual durante o movimento de descida.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) menor que durante o movimento de descida.\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) menor que o peso do elevador.\u00a0<\/b><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>30-(UNEMAT-MT)<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0 Um \u00f4nibus de peso igual a 10.000 N est\u00e1 em movimento com velocidade de 15 m\/s.<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_584324f1.jpg\" alt=\"\" width=\"249\" height=\"145\" name=\"Imagem 19\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O motorista que dirige o \u00f4nibus avista na pista de rolamento um animal e aciona o freio. O \u00f4nibus percorre 9 metros durante a frenagem at\u00e9 parar completamente.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O m\u00f3dulo da for\u00e7a de frenagem \u00e9 igual a: (Dado: g = 10 m\/s<\/b><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) 15.000 N\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) 12.500 N\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) 11.250 N\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) 10.000 N\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) 9.000 N\u00a0<\/b><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>31-(FGV-SP)<\/b><\/span><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b> Durante a cerim\u00f4nia de formatura, o professor de f\u00edsica, teve seu pensamento absorvido pela pilha de duas camadas de estojos de diplomas, todos iguais, escorada de ambos os lados, por um copo contendo \u00e1gua.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_7da2346e.jpg\" alt=\"\" width=\"282\" height=\"152\" name=\"Imagem 20\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>O professor lembrava que sen 30<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>o<\/b><\/span><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>=cos 60<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>o<\/b><\/span><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>=1<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\/<\/b><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>2 e que sen 60<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>o<\/b><\/span><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>=cos 30<\/b><\/span><\/span><\/span><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>o<\/b><\/span><\/span><\/span><\/sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"pt-PT\"><b>=\u221a3\/2. Admitindo que cada estojo tivesse o mesmo peso de m\u00f3dulo P, determinou mentalmente a intensidade da for\u00e7a de contato exercida por um estojo da fila superior sobre um da fila inferior, for\u00e7a que, escrita em termos de P, \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_831c1d7d.png\" alt=\"\" width=\"774\" height=\"21\" name=\"Imagem 48\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>32-(FUVEST-SP)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_22b2f00b.jpg\" alt=\"\" width=\"559\" height=\"109\" name=\"Imagem 21\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O gr\u00e1fico abaixo representa a for\u00e7a F exercida pela musculatura eretora sobre a coluna vertebral, ao se \u00a0levantar um peso, em fun\u00e7\u00e3o do<\/b><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_2e46dd3.jpg\" alt=\"\" width=\"481\" height=\"142\" name=\"Imagem 22\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00e2ngulo \u03c6, entre a dire\u00e7\u00e3o da coluna e a horizontal. Ao se levantar pesos \u00a0com postura incorreta, essa for\u00e7a pode se tornar muito \u00a0grande, causando dores lombares e problemas na coluna.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Com base nas informa\u00e7\u00f5es dadas e no gr\u00e1fico acima, foram feitas as seguintes afirma\u00e7\u00f5es:<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>I. Quanto menor o valor de<\/b><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u03c6<\/b><\/span><\/span><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, maior o peso que se consegue levantar.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>II. Para evitar problemas na coluna, um halterofilista deve procurar levantar pesos adotando postura corporal cujo \u00e2ngulo \u03c6 seja grande.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>III. Quanto maior o valor de\u00a0 \u03c6, \u00a0menor a tens\u00e3o na musculatura eretora ao se levantar um peso.<\/b><\/span><\/span><\/p>\n<p><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Est\u00e1 correto apenas o que se afirma em<\/b><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/peso\/i_fee20cabeb7c0bd9_html_5807f7a3.png\" alt=\"\" width=\"774\" height=\"17\" name=\"graphics18\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Peso e Massa\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/peso-e-massa-conceitos-e-definicoes\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-peso-e-massa\/\"><span style=\"color: #000080;\">Confira a resolu\u00e7\u00e3o comentada<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00e3o comentada sobre Peso e Massa 1-(UFB)\u00a0A massa de um corpo na Terra \u00e9 X. No planeta Kripton \u00e9 Y. Qual a rela\u00e7\u00e3o entre X e Y? 02-(UERJ-RJ)\u00a0Leia atentamente os quadrinhos a seguir. A solu\u00e7\u00e3o pensada pelo gato Garfield para atender \u00e0 ordem recebida de seu dono est\u00e1 fisicamente correta? Justifique sua resposta. &nbsp; 03-(PUC-MG)\u00a0Suponha que<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1192,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1194","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1194","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1194"}],"version-history":[{"count":4,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1194\/revisions"}],"predecessor-version":[{"id":10846,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1194\/revisions\/10846"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1192"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1194"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}