{"id":1185,"date":"2015-08-25T12:03:35","date_gmt":"2015-08-25T12:03:35","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1185"},"modified":"2024-08-23T13:42:36","modified_gmt":"2024-08-23T13:42:36","slug":"exercicios-de-vestibulares-com-resolucoes-comentadas-sobre-polias-e-roldanas","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/polias-e-roldanas\/exercicios-de-vestibulares-com-resolucoes-comentadas-sobre-polias-e-roldanas\/","title":{"rendered":"Polias e Roldanas &#8211; Exerc\u00edcios"},"content":{"rendered":"<p align=\"CENTER\"><span style=\"color: #0000cc;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Exerc\u00edcios de vestibulares com resolu\u00e7\u00f5es comentadas sobre<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><span style=\"color: #c00000;\"><span style=\"font-family: 'Arial Black', serif;\"><span style=\"font-size: large;\"><b>Polias e Roldanas<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>01-(UFU-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Na figura abaixo despreze as for\u00e7as dissipativas e calcule o valor da carga Q, sabendo que o rapaz exerce uma for\u00e7a de 25N para mant\u00ea-la em equil\u00edbrio.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_fa7b275b.jpg\" alt=\"\" width=\"112\" height=\"242\" name=\"Imagem 25\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>02-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere o esquema representado na figura abaixo. As roldanas e a corda s\u00e3o ideais. O corpo suspenso da<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_5eadcee9.jpg\" alt=\"\" width=\"89\" height=\"235\" name=\"Imagem 26\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>roldana m\u00f3vel tem peso de 550N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Qual o m\u00f3dulo da for\u00e7a vertical (para baixo) que o homem deve exercer sobre a corda, para equilibrar o sistema?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Para cada 1 metro de corda que o homem puxa, de quanto se eleva o corpo suspenso?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>03-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><b> <\/b><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Disp\u00f5e-se de um conjunto de fios e polias ideais para um determinado experimento. Quatro dessas polias s\u00e3o associadas conforme a ilustra\u00e7\u00e3o abaixo, sendo tr\u00eas m\u00f3veis e uma fixa.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_6b6af747.jpg\" alt=\"\" width=\"184\" height=\"255\" name=\"Imagem 27\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>No fio que passa pela polia fixa, suspende-se o corpo de massa m e o conjunto \u00e9 mantido em repouso por estar preso ao solo, por meio de fios e de um dinam\u00f4metro (d) de massa desprez\u00edvel, que registra 400N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Qual \u00e9 o valor da massa do corpo?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>04.(UFABC-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um mec\u00e2nico afirma ao seu assistente que \u00e9 poss\u00edvel erguer e manter um carro no alto e em equil\u00edbrio est\u00e1tico, usando-se um contrapeso mais leve do que o carro. A figura mostra, fora de escala, o esquema sugerido pelo mec\u00e2nico para obter o seu intento.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_4d87746.jpg\" alt=\"\" width=\"221\" height=\"244\" name=\"Imagem 28\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considerando as polias e os cabos como ideais e, ainda, os cabos convenientemente presos ao carro para que n\u00e3o haja movimento de rota\u00e7\u00e3o, determine a massa m\u00ednima do contrapeso e o valor da for\u00e7a que o cabo central exerce sobre o carro, com massa de 700 kg, quando esse se encontra suspenso e em equil\u00edbrio est\u00e1tico.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Dado: Adote g = 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>05-(CESGRANRIO-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um corpo de peso P encontra-se em equil\u00edbrio devido \u00e0 a\u00e7\u00e3o da for\u00e7a de inteensidade F aplicada pelo homem da figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_d5ab2587.jpg\" alt=\"\" width=\"338\" height=\"236\" name=\"Imagem 29\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Os pontos A, B e C s\u00e3o os pontos de contato entre os fios e a superf\u00edcie. A for\u00e7a que a superf\u00ede exerce sobre os fios nos pontos A, B e C s\u00e3o respectivamente.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) P\/8, P\/4, P\/2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) P\/8, P\/2, P\/4\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) P\/2, P\/4, P\/8\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) P, P\/2, P\/4\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) iguais a P<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>06-(CEFET-SP)<\/b><\/span><\/span><\/span><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Embora abrigue toda uma floresta, o solo amaz\u00f4nico constitui uma fina camada f\u00e9rtil. Ap\u00f3s uma temporada de chuvas, um caminh\u00e3o ficou atolado no solo desmatado. Rapidamente, providenciaram alguns cabos de a\u00e7o e quatro roldanas.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Aproveitando-se da enorme in\u00e9rcia de uma colheitadeira, montaram a m\u00e1quina simples da figura.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A solu\u00e7\u00e3o encontrada permite que uma for\u00e7a resistente F<\/b><\/span><\/span><\/span><span style=\"color: #292526;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>R<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_f2863f31.gif\" alt=\"\" width=\"477\" height=\"196\" name=\"Imagem 30\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #292526;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>seja vencida por uma for\u00e7a potente F<\/b><\/span><\/span><\/span><span style=\"color: #292526;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>P<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(A) duas vezes menor.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(B) quatro vezes menor.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(C) seis vezes menor.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(D) oito vezes menor.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #292526;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(E) dezesseis vezes menor.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>07-(FUVEST-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>As figuras mostram dois arranjos (A e B) de polias constru\u00eddos para erguer um corpo de massa M=8kg. As polias e os fios s\u00e3o ideais. Calcule as for\u00e7as F<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e F<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>B<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, em Newton,necess\u00e1ria para manter o corpo suspenso e em repouso nos dois casos. (Considere g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>).<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_a70c02d.jpg\" alt=\"\" width=\"167\" height=\"233\" name=\"Imagem 31\" align=\"BOTTOM\" border=\"0\" \/><span style=\"color: #000000;\"> <img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_5bbbcbfa.jpg\" alt=\"\" width=\"143\" height=\"233\" name=\"Imagem 32\" align=\"BOTTOM\" border=\"0\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>08-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Admita que sua massa seja 60kg e que voc\u00ea esteja sobre uma balan\u00e7a, dentro da cabine de um elevador.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_dfe57bab.jpg\" alt=\"\" width=\"145\" height=\"181\" name=\"Imagem 33\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Sendo g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e a balan\u00e7a calibrada em newtons, a indica\u00e7\u00e3o por ela fornecida, quando a cabine desce com acelera\u00e7\u00e3o constante de 3m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, \u00e9:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_188e57e7.png\" alt=\"\" width=\"774\" height=\"20\" name=\"Imagem 2\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>09-(UFB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um elevador de massa 1.000kg est\u00e1 subindo e acelerando com a=3m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>. No interior de sua cabine h\u00e1 uma pessoa de massa 70kg que se encontra sobre uma balan\u00e7a calibrada em newtons. Consi dere g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e despreze os atritos:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_96d25c34.jpg\" alt=\"\" width=\"154\" height=\"185\" name=\"Imagem 34\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) Calcule a indica\u00e7\u00e3o da balan\u00e7a<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) Determine a intensidade da for\u00e7a de tra\u00e7\u00e3o em cada um dos tr\u00eas cabos do elevador da figura acima?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) Se o elevador cair em queda livre (a=g), ent\u00e3o n\u00e3o haver\u00e1 compress\u00e3o entre a balan\u00e7a e a pessoa e a mesma ter\u00e1 a impress\u00e3o de \u201cter perdido peso\u201d. Normalmente \u00e9 usada em elevadores especiais ou em avi\u00f5es em queda livre para acostumar os astronautas com a \u201caus\u00eancia da gravidade\u201d.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Pense e responda: O que aconteceria se o elevador cair com acelera\u00e7\u00e3o a, tal que a&gt;g?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>10-(UFMG-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Qual \u00e9 o peso aparente de um corpo de massa 10kg que est\u00e1 dentro de um elevador que tem uma acelera\u00e7\u00e3o de 5m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>, dirigida para baixo? (g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>11-(UFPA)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um corpo de peso 2,0N pende de um dinam\u00f4metro que est\u00e1 fixo no teto de um elevador em movimento. Verifica-se que a leitura do dinam\u00f4metro \u00e9 de 2,5N. Podemos afirmar que o elevador est\u00e1:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_dfca738a.jpg\" alt=\"\" width=\"166\" height=\"177\" name=\"Imagem 35\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) em repouso\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) subindo com velocidade constante\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) descendo com velocidade constante\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) subindo com velocidade crescente\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) descendo com velocidade crescente.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>12-(PUC-BA)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um cabo de a\u00e7o utilizado para mover um elevador suporta um peso m\u00e1ximo igual ao peso de um corpo de massa igual a 1200kg. Se ele est\u00e1 sustentando um elevador\u00a0 de massa igual a 1000kg, qual pode ser a m\u00e1xima acelera\u00e7\u00e3o do elevador na subida? (g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>13-(UFB)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Num elevador h\u00e1 uma balan\u00e7a graduada em newtons. Uma pessoa de massa 80kg que est\u00e1 sobre a balan\u00e7a l\u00ea 960N quando o elevador sobe com certa acelera\u00e7\u00e3o e 640N quando o elevador desce com a mesma acelera\u00e7\u00e3o. Quais as intensidades das acelera\u00e7\u00f5es da gravidade e do elevador? O que estar\u00e1 acontecendo quando a balan\u00e7a registrar 800N? E quando registrar zero?<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>14-(UNIFESP-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00c0s vezes, as pessoas que est\u00e3o num elevador em movimento sentem uma sensa\u00e7\u00e3o de desconforto, em geral na regi\u00e3o do est\u00f4mago. Isso se deve \u00e0 in\u00e9rcia de nossos \u00f3rg\u00e3os internos localizados nessa regi\u00e3o, e pode ocorrer:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) quando o elevador sobe ou desce em movimento uniforme.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) apenas quando o elevador sobe em movimento uniforme<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) apenas quando o elevador desce em movimento uniforme.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) quando o elevador sobe ou desce em movimento variado.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) apenas quando o elevador sobe em movimento variado.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>15-(UFPE)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u201cUma pessoa comprou uma balan\u00e7a de ch\u00e3o e, ao chegar em casa, ansiosa para controlar o peso, resolve testa-la ainda no elevador. Ela concluiu que a\u00a0 balan\u00e7a estava com defeito ao notar um aumento de seu peso\u201d.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_32e8190a.jpg\" alt=\"\" width=\"186\" height=\"199\" name=\"Imagem 36\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considerando as informa\u00e7\u00f5es, identifique a op\u00e7\u00e3o correta.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) O aumento da indica\u00e7\u00e3o da balan\u00e7a pode ocorrer se o elevador est\u00e1 subindo com velocidade constante.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) O aumento da indica\u00e7\u00e3o da balan\u00e7a pode ocorrer se o elevador est\u00e1 descendo com velocidade constante<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) O aumento da indica\u00e7\u00e3o da balan\u00e7a pode ocorrer se o elevador est\u00e1 subindo com acelera\u00e7\u00e3o constante<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) O aumento da indica\u00e7\u00e3o da balan\u00e7a pode ocorrer se o elevador est\u00e1 descendo com acelera\u00e7\u00e3o constante<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) A balan\u00e7a est\u00e1 necessariamente com defeito e deve ser trocada\u00a0 em respeito aos direitos do consumidor.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>16-(MACKENZIE-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma mo\u00e7a entra em um elevador que est\u00e1 parado no 5<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>o<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>andar de um edif\u00edcio de 10 andares, carregando uma caixa de 800g, suspensa por um barbante que suporta, no m\u00e1ximo, a tra\u00e7\u00e3o de 9,6N, como mostra a figura abaixo.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_d8db335c.jpg\" alt=\"\" width=\"133\" height=\"186\" name=\"Imagem 37\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Estando a caixa em repouso em rela\u00e7\u00e3o ao elevador, o barbante arrebentar\u00e1 somente se o elevador (adote g=10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>):<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) descer com acelera\u00e7\u00e3o maior que 2,0m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) descer com acelera\u00e7\u00e3o maior que 1,2m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) subir com acelera\u00e7\u00e3o maior que 2,0m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) subir com acelera\u00e7\u00e3o maior que 1,2m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>e) subir ou descer com acelera\u00e7\u00e3o maior que 2,5m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>17-(UFSCAR-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O sistema esquematizado comp\u00f5e-se de um elevador de massa M e um homem de massa m. O elevador est\u00e1 suspenso por uma corda que passa por uma polia fixa e vem \u00e0s m\u00e3os do operador; a corda e a roldana s\u00e3o supostas ideais. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_3ad58509.jpg\" alt=\"\" width=\"168\" height=\"215\" name=\"Imagem 38\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O operador puxa a corda e sobe com acelera\u00e7\u00e3o constante a, juntamente com o elevador. S\u00e3o supostos conhecidos M, m, a e g. Determine a intensidade da for\u00e7a<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_a1d3e32b.jpg\" alt=\"\" width=\"14\" height=\"20\" name=\"Imagem 39\" align=\"BOTTOM\" border=\"0\" \/><\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0que traciona a corda.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>18-(UERJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Um passageiro est\u00e1 no interior de um elevador que desce verticalmente, com acelera\u00e7\u00e3o constante &#8220;a&#8221;.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_8438df8d.jpg\" alt=\"\" width=\"155\" height=\"164\" name=\"Imagem 40\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Se &#8220;a&#8221; vale 1\/5 da acelera\u00e7\u00e3o da gravidade, a raz\u00e3o entre a intensidade da for\u00e7a que o piso do elevador exerce sobre o passageiro e o peso do passageiro \u00e9 igual a:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_dd27121f.png\" alt=\"\" width=\"774\" height=\"18\" name=\"graphics7\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>19-(UFRJ-RJ)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Quando o cabo de um elevador se quebra, os freios de emerg\u00eancia s\u00e3o acionados contra trilhos laterais, de modo que esses passam a exercer, sobre o elevador, quatro for\u00e7as verticais constantes e iguais a f , como indicado na figura.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere g = 10m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_e07e8c1b.jpg\" alt=\"\" width=\"242\" height=\"187\" name=\"graphics8\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Suponha que, numa situa\u00e7\u00e3o como essa, a massa total do elevador seja M = 600kg e que o m\u00f3dulo de cada for\u00e7a f seja | f | = 1350N.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Calcule o m\u00f3dulo da acelera\u00e7\u00e3o com que o elevador desce sob a frenagem dessas for\u00e7as.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>20-(UFU-MG)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma pessoa de massa m est\u00e1 no interior de um elevador de massa M, que desce verticalmente, diminuindo sua velocidade com uma acelera\u00e7\u00e3o de m\u00f3dulo a.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Se a acelera\u00e7\u00e3o local da gravidade \u00e9 g, a for\u00e7a feita pelo cabo que sustenta o elevador \u00e9<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>a) (M+m)(g-a)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>b) (M+m)(g+a)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>c) (M+m)(a-g)\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>d) (M-m)(g+a)<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>21-(ITA-SP)<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Uma pilha de seis blocos iguais, de mesma massa m, repousa sobre o piso de um elevador, como mostra a figura.<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_9c2d0172.jpg\" alt=\"\" width=\"199\" height=\"165\" name=\"Imagem 42\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>O elevador est\u00e1 subindo em movimento uniformemente retardado com acelera\u00e7\u00e3o de m\u00f3dulo a. O m\u00f3dulo da for\u00e7a que o bloco 3 exerce sobre o bloco 2 \u00e9 dado por:<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_81dd7db3.png\" alt=\"\" width=\"774\" height=\"21\" name=\"graphics9\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(UFT-TO)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_2d3cbbc1.jpg\" alt=\"\" width=\"416\" height=\"125\" name=\"Imagem 43\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Leia o texto para responder \u00e0s quest\u00f5es 22, 23 e 24.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>A fim de conferir realismo \u00e0 grava\u00e7\u00e3o da cena de um filme que envolve um astronauta caindo na superf\u00edcie lunar, a equipe de<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>efeitos especiais de um est\u00fadio utilizou uma montagem com polias, um cabo de a\u00e7o e um contrapeso. A montagem consiste\u00a0 em um cabo de a\u00e7o com uma extremidade presa ao astronauta, passando por duas polias fixas sobre o teto do est\u00fadio e por uma polia m\u00f3vel (na qual o contrapeso est\u00e1 preso). A outra extremidade do cabo est\u00e1 fixada ao teto do est\u00fadio, conforme ilustrado na figura abaixo:<\/b><\/span><\/span><\/span><\/p>\n<p align=\"CENTER\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_9a70d0c9.jpg\" alt=\"\" width=\"344\" height=\"174\" name=\"graphics10\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Existem for\u00e7as de atrito que influenciam\u00a0 o movimento do astronauta e do contrapeso.\u00a0 Geralmente estas for\u00e7as\u00a0 s\u00e3o<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>desconsideradas em situa\u00e7\u00f5es\u00a0 envolvendo cabos e polias ideais. Cabos ideais s\u00e3o inextens\u00edveis (comprimento constante) e t\u00eam massa nula. Polias ideais n\u00e3o possuem atrito e t\u00eam massa nula.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Em uma situa\u00e7\u00e3o real podemos considerar os cabos e polias como ideais desde que:<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>1)\u00a0 a massa destes seja muito inferior\u00a0 \u00e0 dos demais elementos do sistema;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2)\u00a0 o comprimento do cabo\u00a0 seja aproximadamente constante;<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>3) o atrito na polia seja aproximadamente nulo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Para calcular a massa do contrapeso, de forma que o astronauta em queda esteja submetido a uma acelera\u00e7\u00e3o igual \u00e0 acelera\u00e7\u00e3o gravitacional lunar, a equipe de efeitos especiais considerou o cabo e as polias ideais, a massa total do astronauta (com equipamentos) igual a\u00a0 220 kg e a acelera\u00e7\u00e3o gravitacional lunar (g<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Lua<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>) igual a vinte por cento da acelera\u00e7\u00e3o gravitacional terrestre, g<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Terra<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>= 10 m\/s<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sup><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>2<\/b><\/span><\/span><\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>22-(UFT-TO)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_297d57cd.jpg\" alt=\"\" width=\"415\" height=\"128\" name=\"graphics11\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa que mais se aproxima da massa calculada para o contrapeso utilizado pela equipe de efeitos especiais do est\u00fadio.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>(A) 320kg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) 100kg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (C) 220kg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (D) 151kg\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (E) 352kg<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><span lang=\"en-US\"><b>23-(UFT-TO)<\/b><\/span><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_eae5c292.jpg\" alt=\"\" width=\"426\" height=\"126\" name=\"graphics12\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere a dist\u00e2ncia vertical inicial entre os centros de massa do astronauta e do contrapeso\u00a0 d = 9,0m e as velocidades iniciais do astronauta e do contrapeso iguais a zero.\u00a0<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa que mais se aproxima do menor intervalo de tempo necess\u00e1rio para que a dist\u00e2ncia vertical entre os centros de massa do astronauta e do contrapeso seja igual a 4,5m<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_fff981d.png\" alt=\"\" width=\"774\" height=\"21\" name=\"graphics13\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\">\u00a0<\/span><\/p>\n<p><span style=\"color: #c00000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>24-(UFT-TO)<\/b><\/span><\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/fisicaevestibular.com.br\/novo\/wp-content\/uploads\/migracao\/polias\/i_0ab260d6d4034b45_html_ec944f4b.jpg\" alt=\"\" width=\"415\" height=\"131\" name=\"Imagem 47\" align=\"BOTTOM\" border=\"0\" \/><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Considere o cabo utilizado no est\u00fadio como ideal e, agora, as polias com coeficiente de atrito diferente de zero, dissipando<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>energia, e possuindo massa nula. Considere tamb\u00e9m que exista o movimento.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Assinale a alternativa CORRETA.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(A) O m\u00f3dulo da acelera\u00e7\u00e3o do astronauta \u00e9 nulo enquanto o m\u00f3dulo da acelera\u00e7\u00e3o do contrapeso \u00e9 igual a\u00a0 0,2g<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Terra<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(B) Os m\u00f3dulos das acelera\u00e7\u00f5es do astronauta e do contrapeso s\u00e3o inferiores a\u00a0 0,2g<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Terra<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(C) Os m\u00f3dulos das acelera\u00e7\u00f5es do astronauta e do contrapeso s\u00e3o superiores a\u00a0 0,2g<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Terra<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(D) O m\u00f3dulo da acelera\u00e7\u00e3o do astronauta \u00e9 igual a 0,2g<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Terra<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>\u00a0<\/b><\/span><\/span><\/sub><\/span><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>enquanto o m\u00f3dulo da\u00a0 acelera\u00e7\u00e3o do contrapeso \u00e9 nulo.<\/b><\/span><\/span><\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>(E) Os m\u00f3dulos das acelera\u00e7\u00f5es do astronauta e do contrapeso s\u00e3o iguais a\u00a0 0,2g<\/b><\/span><\/span><\/span><span style=\"color: #000000;\"><sub><span style=\"font-family: Arial, serif;\"><span style=\"font-size: medium;\"><b>Terra<\/b><\/span><\/span><\/sub><\/span><\/p>\n<p>&nbsp;<\/p>\n<h3><a title=\"Resolu\u00e7\u00e3o comentada dos exerc\u00edcios de vestibulares sobre Polias ou Roldanas\" href=\"http:\/\/fisicaevestibular.com.br\/novo\/mecanica\/dinamica\/polias-e-roldanas\/resolucao-comentada-dos-exercicios-de-vestibulares-sobre-polias-ou-roldanas\/\"><span style=\"color: #000080;\">Confira a resolu\u00e7\u00e3o comentada<\/span><\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"<p>Exerc\u00edcios de vestibulares com resolu\u00e7\u00f5es comentadas sobre Polias e Roldanas 01-(UFU-MG)\u00a0Na figura abaixo despreze as for\u00e7as dissipativas e calcule o valor da carga Q, sabendo que o rapaz exerce uma for\u00e7a de 25N para mant\u00ea-la em equil\u00edbrio. \u00a0 02-(FUVEST-SP)\u00a0Considere o esquema representado na figura abaixo. As roldanas e a corda s\u00e3o ideais. O corpo suspenso da roldana m\u00f3vel tem peso<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1183,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1185","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1185","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1185"}],"version-history":[{"count":3,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1185\/revisions"}],"predecessor-version":[{"id":10852,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1185\/revisions\/10852"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1183"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1185"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}