{"id":1029,"date":"2015-07-15T03:29:45","date_gmt":"2015-07-15T03:29:45","guid":{"rendered":"http:\/\/fisicaevestibular.com.br\/novo\/?page_id=1029"},"modified":"2024-09-02T17:30:05","modified_gmt":"2024-09-02T17:30:05","slug":"resolucao-comentada-da-puc-go-2015","status":"publish","type":"page","link":"https:\/\/fisicaevestibular.com.br\/novo\/universidades-2015\/exercicios-resolvidos-da-puc-go-2015\/resolucao-comentada-da-puc-go-2015\/","title":{"rendered":"Resolu\u00e7\u00e3o comentada da PUC GO 2015"},"content":{"rendered":"

Resolu\u00e7\u00e3o dos exerc\u00edcios de F\u00edsica da PUC-GO-2015<\/b><\/span><\/span><\/span><\/p>\n

01- <\/b><\/span><\/span><\/span>Pelo enunciado, <\/b><\/span><\/span>cada 1 m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> de \u00e1rea recebe uma pot\u00eancia de 600 W.<\/b><\/span><\/span><\/span><\/p>\n

\u00c1rea do painel<\/b><\/span><\/span><\/span> \"\" <\/b><\/span><\/span>S<\/b><\/span><\/span><\/span> = 1,20×1,00 <\/b><\/span><\/span>= 1,2 m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span>.<\/b><\/span><\/span><\/span><\/p>\n

Pot\u00eancia incidente na \u00e1rea S = 1,2 m<\/b><\/span><\/span>2<\/b><\/span><\/span><\/sup> \"\" <\/b><\/span><\/span>regra de tr\u00eas \"\" 600 W \u2013 1 m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> \"\" P (W) \u2013 1,2 m<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> \"\" <\/b><\/span><\/span>P =<\/b><\/span><\/span><\/span> 600×1,2 <\/b><\/span><\/span>= 720 W.<\/b><\/span><\/span><\/span><\/p>\n

Apenas <\/b><\/span><\/span>40%<\/b><\/span><\/span><\/span> dessa pot\u00eancia \u00e9 transferida para a \u00e1gua \"\" <\/b><\/span><\/span>P\u2019<\/b><\/span><\/span><\/span> = 0,4×720 <\/b><\/span><\/span>= 288 W.<\/b><\/span><\/span><\/span><\/p>\n

Com essa pot\u00eancia recebida pela \u00e1gua em <\/b><\/span><\/span>t <\/b><\/span><\/span><\/span>= 20minx60 <\/b><\/span><\/span>= 1200 s<\/b><\/span><\/span><\/span> a <\/b><\/span><\/span>energia W<\/b><\/span><\/span><\/span> ser\u00e1:<\/b><\/span><\/span><\/p>\n

P = W\/t<\/b><\/span><\/span><\/span> \"\" 288 = W\/1200 \"\" <\/b><\/span><\/span>W<\/b><\/span><\/span><\/span> = 288×1200 <\/b><\/span><\/span>= 345600 J<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/p>\n

R – A<\/b><\/span><\/span><\/span><\/p>\n

02- <\/b><\/span><\/span><\/span>I. Falsa<\/b><\/span><\/span><\/span> \"\" <\/b><\/span>raios s\u00e3o uma <\/b><\/span><\/span>descarga el\u00e9trica<\/b><\/span><\/span><\/span> que ocorre entre as <\/b><\/span><\/span>nuvens e o solo (ou entre uma nuvem e outra)<\/b><\/span><\/span><\/span>, em decorr\u00eancia de sua polariza\u00e7\u00e3o, que ocorre ap\u00f3s, ou antes, uma tempestade.<\/b><\/span><\/span><\/p>\n

II. Correta<\/b><\/span><\/span><\/span> \"\" trata-se do poder das pontas.<\/b><\/span><\/span><\/p>\n

III. Correta<\/b><\/span><\/span><\/span><\/p>\n

IV. Falsa<\/b><\/span><\/span><\/span> \"\" o som dos estrondos \u00e9 ouvido depois da descarga el\u00e9trica, pois a <\/b><\/span><\/span>velocidade de propaga\u00e7\u00e3o do som \u00e9 menor que a da luz.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

03- <\/b><\/span><\/span><\/span>R- A<\/b><\/span><\/span><\/span><\/p>\n

04- <\/b><\/span><\/span><\/span>I. Falsa<\/b><\/span><\/span><\/span> \"\" F<\/b><\/span><\/span>R<\/b><\/span><\/span><\/sub> = ma \"\" <\/b><\/span><\/span>F \u2013 T = ma<\/b><\/span><\/span><\/span> \"\" 60 \u2013 T = 2.8 \"\" – T = 16 \u2013 60 \"\" <\/b><\/span><\/span>T = 44 N.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

Pelo <\/b><\/span><\/span>enunciado <\/b><\/span><\/span><\/span>a for\u00e7a de <\/b><\/span><\/span>tra\u00e7\u00e3o m\u00e1xima suportada linha \u00e9 de 50 N<\/b><\/span><\/span><\/span>, portanto a <\/b><\/span><\/span>linha n\u00e3o ser\u00e1 rompida.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

III. Correta<\/b><\/span><\/span><\/span> \"\" 20 \u2013 T = 10.(-3) \"\" – T = -30 \u2013 20 \"\" T = 50 N.<\/b><\/span><\/span><\/p>\n

IV. Falsa<\/b><\/span><\/span><\/span> \"\" F \u2013 T = ma \"\" – T = ma \u2013 F \"\" T = F \u2013 ma \u2013 sendo F e m constantes, quanto maior for a, menor ser\u00e1 T.<\/b><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

05- <\/b><\/span><\/span><\/span>C\u00e1lculo do <\/b><\/span><\/span>\u00e2ngulo de incid\u00eancia i na figura 1<\/b><\/span><\/span><\/span> \"\" aplicando <\/b><\/span><\/span>Pit\u00e1goras<\/b><\/span><\/span><\/span> no tri\u00e2ngulo ret\u00e2ngulo \"\" <\/b><\/span><\/span>h<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 20<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> + (16,04)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 400 + 257,2816 \"\" h = \u221a(657,2816) \"\" <\/b><\/span><\/span>h = 25,627 cm<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/p>\n

sen i = 20\/25,627 \"\" <\/b><\/span><\/span>sen i = 0,78.<\/b><\/span><\/span><\/span><\/p>\n

\"\"<\/p>\n

C\u00e1lculo do <\/b><\/span><\/span>\u00e2ngulo de refra\u00e7\u00e3o r na figura 2<\/b><\/span><\/span><\/span> \"\" aplicando <\/b><\/span><\/span>Pit\u00e1goras<\/b><\/span><\/span><\/span> no tri\u00e2ngulo ret\u00e2ngulo \"\" <\/b><\/span><\/span>h<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> =<\/b><\/span><\/span><\/span><\/p>\n

10<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> + (16,04)<\/b><\/span><\/span><\/span>2<\/b><\/span><\/span><\/sup><\/span> = 100 + 257,2816 \"\" h = \u221a(357,2816) \"\" <\/b><\/span><\/span>h = 18,9 cm<\/b><\/span><\/span><\/span>.<\/b><\/span><\/span><\/p>\n

sen r = 10\/18,9 \"\" <\/b><\/span><\/span>sen r = 0,53.<\/b><\/span><\/span><\/span><\/p>\n

Aplicando a lei de <\/b><\/span><\/span>Snell-Descartes<\/b><\/span><\/span><\/span> na interface ar-glicerina l\u00edquida \"\" <\/b><\/span><\/span>n<\/b><\/span><\/span><\/span>ar<\/b><\/span><\/span><\/sub><\/span>.seni = n<\/b><\/span><\/span><\/span>glic<\/b><\/span><\/span><\/sub><\/span>.senr<\/b><\/span><\/span><\/span> \"\" 1.0,78 =<\/b><\/span><\/span><\/p>\n

n<\/b><\/span><\/span>glic<\/b><\/span><\/span><\/sub>.0,53 \"\" <\/b><\/span><\/span>n<\/b><\/span><\/span><\/span>glic<\/b><\/span><\/span><\/sub><\/span> = 0,78\/0,53 <\/b><\/span><\/span>= 1,47.<\/b><\/span><\/span><\/span><\/p>\n

R – B<\/b><\/span><\/span><\/span><\/p>\n

06- <\/b><\/span><\/span><\/span>I.Correta<\/b><\/span><\/span><\/span> \"\" \u00e9 <\/b><\/span><\/span>caracter\u00edstica de colis\u00e3o perfeitamente el\u00e1stica<\/b><\/span><\/span><\/span>, quando os corpos <\/b><\/span><\/span>s\u00e3o id\u00eanticos, de mesma massa, eles trocam suas velocidades, como conseq\u00fc\u00eancia de tanto o momento (quantidade de movimento) quanto a energia cin\u00e9tica do sistema se conservarem.<\/b><\/span><\/span><\/span><\/p>\n

III. Correta \"\" Veja I.<\/b><\/span><\/span><\/span><\/p>\n

R- C<\/b><\/span><\/span><\/span><\/p>\n

 <\/p>\n

Voltar para os Exerc\u00edcios<\/span><\/a><\/h2>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

Resolu\u00e7\u00e3o dos exerc\u00edcios de F\u00edsica da PUC-GO-2015 01- Pelo enunciado, cada 1 m2 de \u00e1rea recebe uma pot\u00eancia de 600 W. \u00c1rea do painel S = 1,20×1,00 = 1,2 m2. Pot\u00eancia incidente na \u00e1rea S = 1,2 m2 regra de tr\u00eas 600 W \u2013 1 m2 P (W) \u2013 1,2 m2 P = 600×1,2 = 720 W. Apenas 40% dessa<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":1027,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-1029","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1029","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/comments?post=1029"}],"version-history":[{"count":2,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1029\/revisions"}],"predecessor-version":[{"id":1031,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1029\/revisions\/1031"}],"up":[{"embeddable":true,"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/pages\/1027"}],"wp:attachment":[{"href":"https:\/\/fisicaevestibular.com.br\/novo\/wp-json\/wp\/v2\/media?parent=1029"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}